Answers
We are given that two protons are 7.1818 fm apart. To determine the electric force between them we need to use the following formula:
\(F=k\frac{q_1q_2}{r^2}\)Where:
\(\begin{gathered} k=\text{ electric constant} \\ q_1,q_2=\text{ charges} \\ r=\text{ distance between charges} \end{gathered}\)The charge of a proton is:
\(q_p=1.606\times10^{-19}C\)Now, we plug in the values:
\(F=(9\times10^9\frac{Nm^2}{C^2})\frac{(1.606\times10^{-19}C)(1.606\times10^{-19}C)}{(1\times10^{-15}m)^2}\)Solving the operations:
\(F=232.13N\)Now, we need to determine the gravitational force. We will use the following formula:
\(F_g=G\frac{m_1m_2}{r^2}\)Where;
\(\begin{gathered} G=\text{ gravitational constant} \\ m_1,m_2=\text{ masses} \\ r=\text{ distance between masses} \end{gathered}\)The mass of a proton is given by:
\(m_p=1.67\times10^{-27}kg\)Now, we plug in the values:
\(F_g=(6.67\times10^{-11}\frac{Nm^2}{kg^2})\frac{(1.67\times10^{-27}kg)(1.67\times10^{-27}kg)}{(1\times10^{-15}m)^2}\)Solving the operations:
\(F_g=1.86\times10^{-34}N\)Now, we determine the ratio between the forces:
\(\frac{F}{F_g}=\frac{232.13N}{1.86\times10^{-34}N}=1.25\times10^{36}\)This means that the electric force is 1.25 by ten to the 36th times larger than the gravitational force.
Related Questions
34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again.
Answers
Answer and Explaination:
To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.
1. Gravitational force:
The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.
2. Force exerted by the spring:
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Given:
Mass (m) = 5.0 kg
Compression of the spring (x) = 20.0 cm = 0.20 m
Angle of the inclined plane (θ) = 30°
First, let's find the force exerted by the spring (F_spring):
F_spring = -kx
To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.
Next, let's calculate the gravitational force components:
Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ
Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ
Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.
At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).
Therefore, we have:
F_perpendicular = F_spring
mg * cosθ = -kx
Now, let's substitute the known values and solve for k:
(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m
49.0 N * 0.866 = -k * 0.20 m
42.426 N = -0.20 k
k = -42.426 N / (-0.20 m)
k = 212.13 N/m
Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:
PE_spring = (1/2) * k * x^2
PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2
PE_spring = 4.243 J
The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.
KE_max = PE_spring = 4.243 J
Next, we can calculate the height (h) the mass reaches on the inclined plane:
KE_max = m * g * h
4.243 J = 5.0 kg * 9.8 m/s^2 * h
h = 4.243 J / (5.0 kg * 9.8 m/s^2)
h = 0.086 m
The height the mass reaches on the inclined plane is 0.086 m.
Now, we can calculate the distance traveled.
A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.
Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.For more questions on the spring constant
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How does technology help science?
a)Technology teaches scientists how to do math.
b)Technology helps scientists study things that are very small, far away, or hard to reach.
c)New inventions are based on scientific principles.
d)Computers figure out answers so scientists don’t have to think.
Answers
Answer:
the answer to this is letter b
Answer:
B) Technology helps scientists study things that are very small, far away, or hard to reach.
In the United States, about _________ % of females and ________ % of males smoke.
a. 15; 30
b. 18; 24
c. 26; 21
d. 30; 30
Answers
Approximately 18% of girls and 24% of males in the United States smoke as of 2019, according to the Centers for Disease Control and Prevention (CDC).
Do both men and women smoke in the US?In general, men are more likely than women to use any type of tobacco product. 15.6% of adult females and 16.7% of adult males smoked cigarettes in 2015. These variations could be attributed to a mix of biological (especially ovarian hormones), cultural, and behavioural elements.
In India, how many males smoke?India is the nation with the second-highest number of tobacco smokers in the world with 267 million users (behind China). There are about 100 million smokers in the world today who are over the age of 15. (cigarettes and bidis).
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Question:
"In the United States, about what percentage of females and what percentage of males smoke?
a. 15%; 30%
b. 18%; 24%
c. 26%; 21%
d. 30%; 30%"
Which quantity describes the gravitational force between two objects?(1 point)
Responses
A the sum of the masses of the two objects divided by the distance between them
B the product of the masses of the two objects divided by the distance between them
C the product of the masses of the two objects divided by the square of the distance between them
D the sum of the masses of the two objects divided by the square of the distance between them
Answers
The quantity that describes the gravitational force between two objects is as follows: the product of the masses of the two objects divided by the square of the distance between them (option C).
What is gravitational force?Gravitational force is a very long-range, but relatively weak fundamental force of attraction that acts between all particles that have mass; believed to be mediated by gravitons.
It is called the gravitational force attraction because it always tries to pull masses together, it never pushes them apart.
The gravitational force of an object can be calculated using the following formula:
F = Gm1m2/r²
Where;
F = gravitational forceG = gravitational constantm1 and m2 = masses of objectr = distance between objectsTherefore, the product of the masses divided by the square of the distance is how gravitational force is calculated.
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If a bullet with a mass of 0.005kg is fired from a
gun at a speed of 1000 m/s, what is its
momentum?
what’s the v?
Answers
Answer:
5kgm/s
Explanation:
Given parameters:
Mass of bullet = 0.005kg
Speed = 1000m/s
Unknown:
Momentum = ?
Solution:
Momentum is the amount of motion a body possesses.
Mathematically;
Momentum = mass x velocity
Now insert the parameters and solve;
Momentum = 0.005 x 1000 = 5kgm/s
mention the device which could be used to carry a heavy load onto onto a truck.
Answers
Answer:
A crane is a type of machine, generally equipped with a hoist rope, wire ropes or chains, and sheaves, that can be used both to lift and lower materials and to move them horizontally. It is mainly used for lifting heavy things and transporting them to other places.
Explanation:
Answer:
A crane
Explanation:
Cranes are used move heavy items
the law of conservation of energy also states that energy can be transformed ________
what will be there?
Answers
A wave travels through a rope at a speed of 2.1 m/s and has a wavelength of 0.15 m. The wave then passes into a spring where it
travels at a speed of 5.0 m/s. The wave's wavelength in the spring is
m.
Answers
The wavelength of the wave in the spring is 0.357 m.
What is wavelenth?Wavelength is the length of a complete revolution of a wave.
To calculate the wavelength of the wave in the spring, we use the formula below
Formula:
v'/λ' = v/λ........................ Equation 1Where:
v' = Speed of the wave in the ropeλ' = Wavelength of the wave in the ropev = Speed of the wave in the springλ = Wavelength of the wave in the springFrom the question,
Given:
v' = 2.1 m/sλ' = 0.15 mv = 5.0 m/sSubstitute these values into equation 1 and solve for λ
2.1/0.15 = 5.0/λλ = (5×0.15)/2.1λ = 0.357 mHence, the wavelength is 0.357 m.
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Lower frequencies (red) move _____ in a glass prism than higher frequencies.
Answers
Lower frequencies (red) move faster in a glass prism than higher frequencies.
Light of all colors moves at the same speed in a vacuum. However, light travels at different speeds in many media, including water.
Red light moves through glass at the fastest speed, whereas violet light moves at the slowest speed.
Red light bends the least of all the colors because it moves at the fastest speed, whereas violet light moves at the slowest speed and bends the most.
Wavelength and speed are directly proportional. Speed also rises with increasing wavelength. Light that has a maximal wavelength therefore moves at its fastest.
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A wheel has moment of inertia 5x 10-3 kg-m² and is making 20 revolutions per second. The magnitude of torque needed to stop it in 10 s is:
A 4.5xx 10-2 N-m
B.2.5xx 10-2 N-m
C. 2x 10-2 N-m
D. 4xx 10-2 N-m
Answers
Answer:
Answer:
F = M a Newton's second law
Γ = I α Corresponding law for circular motion
α = 20 * 2 π rad / sec / 10 sec = 4 π rad / sec^2
α = 12.6 /sec^2 (rad not an actual unit)
Γ = 5E-3 * 12.6E1 = .63 kg-m^2 / sec^2
(5E-3 / 12.6 = 4E-4 = 4xxE-2 seems like a mistake made in arithmetic)
Note: kg-m^2 * 1 / sec^2 = kg-m^2 / sec^2 = N-m
One needs to "multiply" inertia * rad/sec^2 to get required units of torque
In order to train astronauts to get used to the accelerations they experience during space shuttle launches, they must ride around in a centrifuge to experience accelerations of up to 100 m/s2. If a centrifuge measures 20 m in radius, what is the rotational velocity of a centrifuge during testing?
Answers
The rotational velocity of the centrifuge is \(\sqrt{5}\) rad/s.
What is Centripetal force ?
Centripetal force is defined as the force that acts on a body moving in circular path which is directed towards the centre of the circular path.
Here,
The rotational acceleration attained by the astronauts, a' = 100 m/s²
The radius of the centrifuge, r = 20 m
From the equation of circular motion,
a' = rω²
So, ω² = a'/r
ω² = 100/20
ω² = 5
Rotational velocity, ω = \(\sqrt{5}\) rad/s
Hence,
The rotational velocity of the centrifuge, ω is \(\sqrt{5}\) rad/s
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hi i need help withMaria has already written Two-fifths of her 1,000 word essay. If she continues writing at the same pace of 6One-half words per minute, which expression shows the amount of time it will take her to write the rest of the essay?
Answers
ANSWER:
STEP-BY-STEP EXPLANATION:
Given:
\(undefined\)statics and strength of materials
Answers
The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.
What is the force P?The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;
Take moment about the joint to determine the magnitude of the force along part BC.
120 kN x 750 mm = F x 1000 mm
F = ( 120 kN x 750 mm ) / ( 1000 mm )
F = 90 kN
Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.
Stress in AB = 2 times stress in BC
P/A₁ = 2F/A₂
where;
A₁ is the area of segment ABA₂ is the area of segment BCA₁ = πd²/4 = π(50 x 10⁻³)²/4
A₁ = 1.96 x 10⁻⁵ m²
A₂ = πd²/4 = π(75 x 10⁻³)²/4
A₂ = 4.42 x 10⁻³ m²
P/A₁ = 2F/A₂
P = (2F x A₁) / (A₂)
P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = 798.2 N
P = 0.798 kN
P ≈ 0.8 kN
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I need help with the first question please
Answers
Work done on an object depends on the distance and force but independent of time.
What is Work ?Work is the product of force and the distance move in the direction of the force. It is measured in Joule.
If you use more force to move an object, there will be more amount of work because Work done = force x distance.
More force will give more about of work.
If you lift a 20 N object faster, you will experience the same amount of work because work is independent of time.
If you raise an object a shorter height, there will be less work done since work depends on the distance move in the direction of the force.
If you move a lighter object, you will experience a less work done because the weight of the object will reduce the work done
If you move an object farther, there will be more work to be done because of the increase in distance.
Therefore, Work done on an object depends on the distance and force but independent of time.
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The scientific symbol are matched with their respective unit of measurement as follows:
Force (F or Fw) = 30 Newton (N).Work done (W or E) = 90 Joules (J).Mechanical advantage (MA) = 10 (unitless).Momentum (p) = 24 kgm/s.Distance (d) = 25 meters (m).Power (P) = 8 watts (w).The amount of work that is required for each situation is given by:
More: You use more force to move an object.The same: You lift a 20 N object faster.Less: You raise an object a shorter height.Less: You move a lighter object.More: You move an object farther. What is a force?A force (F) can be defined as a push or pull of an object, which typically causes a change of motion (acceleration), especially due to the interaction of the object with another. Also, force (F) is measured in Newton (N).
What is work done?The work done (W) by an object is calculated by multiplying the force acting on it by the perpendicular distance covered by the object. Thus, work done (W) and energy (E) have the same unit i.e Joules (J).
In this exercise, you're required to match the scientific symbol with their respective unit of measurement and this is represented as follows:
Force (F or Fw) = 30 Newton (N).Work done (W or E) = 90 Joules (J).Mechanical advantage (MA) = 10 (unitless).Momentum (p) = 24 kgm/s.Distance (d) = 25 meters (m).Power (P) = 8 watts (w).Part B.The amount of work that is required for each situation is given by:
More: You use more force to move an object.The same: You lift a 20 N object faster.Less: You raise an object a shorter height.Less: You move a lighter object.More: You move an object farther.Read more on work done here: https://brainly.com/question/25573309
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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
Answers
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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an ice skater is moving across a flat and level skating rink and is speeding up. which one of the following statement is true of the ice skater
a) its potential energy is constant
b) its potential energy is increasing
c) its potential energy is decreasing
Answers
Answer:
A
Explanation:
The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point:
d
→
L
d
t
=
0
or
→
L
=
→
l
1
+
→
l
2
+
⋯
+
→
l
N
=
constant
.
Note that the total angular momentum
→
L
is conserved. Any of the individual angular momenta can change as long as their sum remains constant. This law is analogous to linear momentum being conserved when the external force on a system is zero.
Find the increase in volume of 34.1 in.3 of mercury when the mercury is heated from 2.35°F to 105°F.
Answers
Answer:
The answer is 0.351 in
Explanation:
A pelican flying along a horizontal path drops a fish from a height of 5.4 m. The fish travels 8.0 m horizontally before it hits the water below. What is the pelican’s speed?
Answers
Answer:
Speed, Vfx = 7.619 m/s
Explanation:
Vertical distance, Dx = 5.4m
Horizontal distance, Dy = 8m
Acceleration due to gravity, g = 9.8m/s²
Initial speed, Vix = 0m/s²
To find the speed, we would use the second equation of motion to find the time, t;
Dx = Vixt + ½gt²
Substituting into the equation, we have;
5.4 = 0(t) + ½(9.8)*t²
5.4 = 0 + 4.9t²
Rearranging the equation, we have;
4.9t² = 5.4
t² = 5.4/4.9
t² = 1.1020
Taking the square root of both sides;
t = 1.050 secs.
For the speed;
Dy = Vfxt
Vfx = Dy/t
Vfx = 8/1.050
Vfx = 7.619 m/s
Therefore, the speed of the pelican is 7.619 m/s
A uniform electric field has a magnitude of 10 N/C and is directed upward. A charge brought into the field experiences a force of 50 N downward. The charge must be:_______.
Answers
Answer:
q = 5 C
Explanation:
The electric field is defined as the force experienced by a unit charge when it is brought into the field. Hence, the formula used to find the electrical field is given as follows:
E = F/q
where,
E = Electric Field Magnitude = 10 N/C
F = Force Experienced by the test charge = 50 N
q = Magnitude of the Charge = ?
Therefore,
10 N/C = 50 N/q
q = 50 N/(10 N/C)
Therefore,
q = 5 C
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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A stone is dropped from the roof of a high building. A second stone is dropped 1.04 s later.
How far apart are the stones when the second one has reached a speed of 14.7 m/s?
Express your answer to three significant figures and include the appropriate units.
Answers
Explanation:
Let the initial speed of 2nd stone is u2 and final speed of it be v2.
Using the equation
v= u + at for the 2nd stone
We get
14.7=u2 + 10t (a=g, acceleration due to gravity)
14.7=0 +10t
Or, t= 1.47s
This is the time taken by 2nd stone to reach 14.7m/s
Now,
Total time for 1st stone=1.04 + 1.47= 2.51s
Using the equation
\(s = ut + \frac{1}{2} at {}^{2} \)
for distance travelled by 1st stone
s1=u2t + 1/2at²
u2=0 (initially it was also at rest)
\(s1 = \frac{1}{2} \times 10 \times 2.51 {}^{2} \)
therefore S = 31. 5005m
Distance travelled by 2nd stone
\(s2 = u2 + \frac{1}{2} at {}^{2} \)
\(s2 = \frac{1}{2} \times 10 \times 1.47 {}^{2} \)
therefore S2 = 10.8m
Therefore,
Distance between the stones is= s1 - s2 = 31.5005–10.8 = 20.7005
Ans:- 20.7m
Which shows evidence of active transport?
A scientist places four identical cells into four different
liquids, each with different concentrations of magnesiuni.
Celll
w
Description of Liquid
Slightly more magnesium than the
cell
The least amount of magnesium
O
O
O
O
cells W and Z
cell W only
cell Y only
cells X and Y
Result
Took in
magnesium
Took in
magnesium
Took in
magnesium
Took in
magnesium
Slightly less magnesium than the
cell
The most amount of magnesium
Answers
Answer: D
X and Y
Explanation:
X The least amount of magnesium Took in magnesium
Y Slightly less magnesium than the cell Took in magnesium
Because active transport occurs when ions or molecules move from less concentration region to high concentration region through semi membrane with the help of some energy.
Answer:
Cells X and Y
Explanation:
Active transport occurs when a substance moves across a membrane against its concentration gradient.
Cells W and Z were placed in a liquid containing more magnesium than the cells. Magnesium therefore, diffuses passively down it's concentration gradient into the cells.
However, cells X and Y were placed in a solution containing less magnesium than the cells, yet these cells took in magnesium against this concentration gradient. This, shows that active transport had taken place.
Jerry ran 21m East then 5m North in 24s. Find
a. Jerry's speed
b. Jerry's velocity
Answers
If Jerry ran 21m East then 5m North in 24s, his speed is 1.06m/s and velocity is 0.9m/s.
What is Speed?Speed ia defined as the ratio of distance to the time.
Speed = distance/time
Given,
distance = 21 + 5 = 26m
time = 24s
Speed = 26/24
= 1.06m/s
What is velocity?Velocity is defined as the ratio of displacement to the time.
Velocity = displacement/time
Given,
displacement = √(441 +25) = √466 = 21.6m
Time = 24s
Velocity = 21.6/24
= 0.9m/s
Thus, we concluded that if Jerry ran 21m East then 5m North in 24s, his speed is 1.06m/s and velocity is 0.9m/s.
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the fastest tennis service by a man is 246,2 km.hr-1 by Andy Roddick of the United States of America during a match in London in 2004. Calculate the ball's momentum if it has a mass of 58 g?
Answers
Answer:
Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).
Explanation:
Convert velocity to the standard units (meters per second):
\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).
Convert mass to standard units (kilograms):
\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).
When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:
\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).
25. You lift a book from the floor to a bookshelf 1.0 m above the ground. How much power is used if the
upward force is 15.0 N and you do the work in 2.0 ?
Answers
Explanation:
P=E/T
E=15N
T=2s
P=15/2
P=7.5
An automobile engine has an efficiency of 22.0% and produces 2510 J of work. How much heat is rejected by the engine
Answers
Answer:
If efficiency is .22 then W = .22 * Q where Q is the heat input
Heat Input Q = 2510 / .22 = 11,400 J
Heat rejected = 11.400 - 2510 = 8900 J of heat wasted
Also, 8900 J / (4.19 J / cal) = 2120 cal
An efficiency is the measure of productivity of an engine. The heat rejected by the engine is 8900 Joules.
What is efficiency?An efficiency of a heat engine is the ratio of the work done and heat supplied.
Given is the automobile engine has the efficiency 22% and Work done is 2510 Joules.
The efficiency is written as,
η= W / Qs.
The work done is W= Qs - Qr, where Qr is the rejected heat.
The heat rejected can be represented as
Qr = W ( 1/η -1)
Substituting the value into the equation, we get the rejected heat.
Qr = 2510 (1/0.22 -1)
Qr = 8900 Joules.
Thus, the heat rejected by the engine is 8900 Joules.
Learn more about efficiency.
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The circuit to the right consists of a battery (0=1.50 V) and five resistors (1=511 Ω, 2=182 Ω, 3=663 Ω, 4=234 Ω, and 5=565 Ω). Determine the current point passing through each of the specified points.
The battery V subscript 0 is connected in series via its positive terminal with resistor R subscript 1. R sub 1 is connected in series with the parallel combination of resistors R subscript 2, R subscript 3, R subscript 4, and R subscript 5. The parallel resistor combination is connected to the negative terminal of the battery.
The parallel resistor combination is configured as a rectangle with a total of four vertical branches. Each vertical branch contains a resistor. The resistors are in numerical order, with R sub 2 on the leftmost branch and R sub 5 on the rightmost branch. Resistor R sub 1 connects to the parallel combination at the midpoint of the upper horizontal leg, between the central parallel branches containing R sub 3 and R sub 4.
The circuit contains eight points labeled A through H. Point A is located on the upper horizontal leg between the parallel branches containing R sub 2 and R sub 3. Point B is located on the upper horizontal leg between the central parallel branches containing R sub 3 and R sub 4, and is to the left of the junction leading to R sub 1. Point C is located on the same horizontal leg as point B, but is to the right of the junction. Point D is located on the upper horizontal leg between the parallel branches containing R sub 4 and R sub 5. Point H is located on the lower horizontal leg between the parallel branches containing R sub 4 and R sub 5, and is opposite point D. Point G is located on the lower horizontal leg between the central parallel branches containing R sub 3 and R sub 4, opposite the junction leading to R sub 1. Point F is located on the lower horizontal leg between the parallel branches containing R sub 2 and R sub 3, opposite point A. Point E is located between the parallel resistor combination and the negative terminal of the battery.
D=
mA
G=
mA
F=
mA
Answers
Answer:
D: 0.346 mAG: 1.182 mAF: 1.478 mAExplanation:
You want the current in various circuit branches of a series-parallel circuit with a battery voltage V0 = 1.5V, a series resistor of R1 = 511 Ω, and four parallel resistors, R2–R5 = 182, 663, 234, and 565 Ω, respectively.
SolutionThere are a number of ways to solve the circuit. The one shown in the second attachment finds the combination of the parallel resistors, then determines how the total current is split among them. The values of interest include the current through R5 (node D), the sum of currents through R5 and R4 (node G), and the sum of currents through R5, R4, and R3 (node F).
If Rx is the effective resistance of the parallel combination of R2–R5, then the battery current is
I = V/R = (1.50)/(511 +Rx) ≈ 2.55254 mA
The current in any resistor Rn is this value multiplied by the fraction Rx/Rn for n=2 to 5.
Mesh CurrentsPerhaps more directly, we can write "mesh current" equations for the circuit. Letting I1–I4 represent the currents through nodes D, G, F, and E, respectively, we can write the equations ...
I1(0.565 +0.234) -I2(0.234) = 0I1(-0.234) +I2(0.234 +0.663) -I3(0.663) = 0I2(-0.663) +I3(0.663 +0.182) -I4(0.182) = 0I3(-0.182) +I4(0.511 +0.182) = 1.50The solution to these equations is shown in the first attachment. Resistances are given in kΩ so currents will be in mA.
The currents in the listed nodes are ...
D: 0.346 mAG: 1.182 mAF: 1.478 mA__
Additional comment
The third attachment shows the circuit as we understand it. The currents labeled I1–I4 are within the local loop. The "mesh current" equations match Kirchoff's Voltage Law: the sum of voltage differences around any closed loop is zero. Where a resistor is shared between loops, the voltage across it will be the (signed) sum of the two loop currents times that resistance.
a certain volume of dry air at NTP is allowed to expand five times of it original volume under adiabatic condition.calculate the final pressure.(air=1.4)
Answers
Answer:
Final pressure 0.105atm
Explanation:
Let V1 represent the initial volume of dry air at NTP.
under adiabatic condition: no heat is lost or gained by the system. This does not implies that the constant temperature throughout the system , but rather that no heat gained or loss by the system.
Adiabatic expansion:
\(\frac{T_1}{T_2} =(\frac{V_1}{V_2} )^{\gamma -1}\)
273/T2=(5V1/V1)^(1.4−1)
273/T2=5^0.4
Final temperature T2=143.41 K
Also
P1/P2=(V2/V1)^γ
1/P2=(5V1/V1)^1.4
Final pressure P2=0.105atm
A car traveled a distance of 30 km in 20 minutes (1/3 hours). What was the
speed of the car?
A. 90 km/hr
OB. 60 km/hr
O C. 30 km/hr
D. 10 km/hr
Answers
The angular velocity (in rpm) of the blade of a blender is given in. If θ=0rad at t=0s, what is the blade's angular position at t=20s?
Answers
Answer:
θ = 20.9 rad
Explanation:
In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship
w = θ / t
θ = w t
if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians
suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system
w = 10 rpm \((\frac{2\pi rad}{1 rev}) ( \frac{1 min}{60 s} )\)
= 1,047 rads
let's calculate
θ = 1,047 20
θ = 20.9 rad