Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? 50 cm 45.8 cm 9.12 cm 91.2 cm 4.58 cm

Answer:

Hold down the shift key if your on windows, mac or chromebooks.

Explanation:

Computer Technician

Answer:

Press the "caps lock" button and then press which letter u want to be in cap

Answer:a

Explanation:because you might not know if each object would attract each other because we already know that a soup can and a spoon and also the pencil will not attract to each other but the paper clip will attract to the magnet  

Answer:

This is the answer.

Explanation:

We divide the total distance travelled by the period of time to determine the average speed. By dividing the displacement by the time interval, we can determine the average velocity.

Average speed was measured by dividing the overall distances you travelled by the total time, whereas average velocity is determined by dividing your movement (a vectors pointing from the initial position toward your end position) by the whole time.

For instance, someone travelling at an average speed over 40 miles split by 10 mins, meaning 1 mile per minute, is travelling twenty miles to the north and afterwards 20 miles south (60 mph).

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Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.

In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.

Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.

Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.

We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.

This gives us a resultant vector of -3.1 km east and 2.4 km north.

Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)

Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.

Therefore, option A) 3.9 km is the correct answer.

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Answer:

6656 N force

Explanation:

Hope it helps<3333333

Answer:

Pe= 2822.4

Explanation:

Use Pe=mgh and g=9.8

So, Pe=24kg(9.8)(12m) = 2822.4

The original two light bulbs will appear brighter when the third resistor is added in parallel.

When a third resistor is added in parallel to the other two resistors in a circuit, it will have an impact on the overall brightness of the original two light bulbs.

In a parallel circuit, each resistor has its own branch connected to the power source. The current flowing through each branch is inversely proportional to the resistance of that branch. Adding a third resistor in parallel means an additional path for current to flow.

The introduction of the third resistor reduces the total resistance of the circuit. As a result, the total current drawn from the power source increases, as per Ohm's Law (I = V/R). The increased current is distributed among the parallel branches, including the original two light bulbs.

Since the current through the bulbs is now greater, their brightness will also increase. This is because the brightness of an incandescent light bulb is directly proportional to the current passing through it.

It's worth noting that the specific effect on brightness depends on the resistance values of the resistors and the characteristics of the light bulbs. However, in general, adding a resistor in parallel reduces the overall resistance, increases the current, and subsequently enhances the brightness of the light bulbs in the circuit.

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Answer:sometimes it commits to how it will happen

Explanation:

Answer:

Atmospheric pressure increases density

Explanation:

Atmospheric pressure decreases the volume of space, since volume is inversely proportional to density, density will increase.

B. The normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

Fₙ = mg + mv²/r

where;

Fₙ = (2,000 x 9.8) + (2,000 x 18²)/24

Fₙ = 46,600 N

Fₙ =  4.7 x 10⁴ N

Thus, the normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

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Answer:

Energy in carriage (Potential energy) = 4,116 J

Explanation:

Given:

Mass of baby = 20 kg

Height = 21 m

Find:

Energy in carriage (Potential energy)

Computation:

The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.

In carriage accumulated energy is potential energy.

Energy in carriage (Potential energy) = mgh

Energy in carriage (Potential energy) = (20)(9.8)(21)

Energy in carriage (Potential energy) = 4,116 J

Answer:

16 meters

Explanation:

When the rope is suddenly cut the object moving tangent at the circle. In that moment the gravity act in the object making it falls.

First we need to find how much time de object take to reach at the ground.

g=acceleration of gravity=10m/s²

v= vertical velocity =0m/s

h=vertical altitude =20m

We will find t such that h(t)=0

\(0=20-5t^{2} \\\\5t^{2} =20\\\\t^{2} =4\\\\t=2s\)

v=horizontal velocity

D(t=2) is the horizontal distancetravelled by the object:

\(D(2)=8*2\\\\D(2)=16m\)

The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².

What is the moment of inertia?

This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².

From the question:

Mass,M =4.2kg

Radius, R=32Cm

The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:

moment of inertia, I =1/2MR²

I =\(\frac{1}{2}\) * 4.2 * 32²

  =2,150.4 kgm²

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Given data

*The given mass of the rocket is m = 3 kg

*The given momentum is p = 90 kg.m/s

The formula for the velocity of the rocket is given by the momentum formula as

Substitute the known values in the above expression as

Hence, the velocity of the rocket is v = 30 m/s

Answer:

Frequency = 25 / 10 = 2.5 Hz

Explanation:

If the wave oscillates up and down 25 times in 10 seconds, then the frequency can be calculated as follows:

Frequency = Number of oscillations / Time

In this case, the number of oscillations is 25, and the time is 10 seconds. Therefore, the frequency is:

Frequency = 25 / 10 = 2.5 Hz

So the frequency of the wave is 2.5 Hertz, which means it completes 2.5 cycles or oscillations in one second.

Answer: the answer is (C)

Explanation: Bar graphs show comparisons using number comparisons

Answer:

a) wind power system, turbines powered, solar power system

b) the possibility of creating jobs for the local workforce and of maintaining the environment without damaging it.

Explanation:

In a grassland system it may not have great changes in height or mountain system where it is easy to represent a river, therefore a hydroelectric power system is not very feasible.

a) You can have several alternative energy systems.

* If there is a fairly constant air current, a wind power system could be implemented.

* If there is a river with an acceptable flow, a generation system can be implemented with turbines powered by the river flow.

* Another system is a solar power system

b) To select any of the possible systems proposed, the current and future energy requirements of the region must be analyzed.

The amount of energy that each proposal can supply

Analyze the installation costs and the economic benefits of a given system.

Study the possible problems for the maintenance of each system.

A great advantage of these systems is the possibility of creating jobs for the local workforce and of maintaining the environment without damaging it.

The most plausible renewable energy source in a grassland is wind energy.

Renewable energy refers to energy that is obtained from wind, water biomass or underground heat. All of these sources of energy are inexhaustible and hold great prospect to solving the current energy deficit is many parts of the world.

In grasslands, the most plausible renewable source of energy is wind. Winds are abundant in grasslands . It is more plausible than hydroelectric power because it does not create any adverse environmental impact. It is the cleanest energy source.

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The electric potential energy would be 0.5  * 10 ∧-8 volts

Using the formula

E = 1/2 * C * V²

Where

E = electric potential energy

C = capacitance = charge

V = voltage applied

Substitute values into formula

E = 1/2  * 1.0x 10∧-10  *  100.0

E = 1/2 * 1.0x 10∧-8

E = 0.5  * 10 ∧-8 volts

Hence, the electric potential energy is 0.5 * 10 ∧-8 volts

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It reasonable to expect that anyone would be able to make good sense of a filing system as it reduces the overall storage space occupied by the records.

This is the process of keeping document safely and being able to easily retrieve them.

The new filing system is based on their volume which is why the space is reduced thereby reducing the ambiguity.

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8.27 x 1013 meres is the orbital radius.

Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution

The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.

6.67 x 10⁻¹¹ N/m²kg

2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7

The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.

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Answer:

When the tides are especially weak, it is called a NEAP tide.

Explanation:

Hope this helps :)

Answer:

Neap

Explanation:

Answered!

The coefficient of friction is 1.39.

Potential energy is a form of energy that an object possesses due to its position or configuration. It is the energy that is stored in an object as a result of its position or shape, and is potentially available to do work when released. The amount of potential energy an object has depends on its mass, height, and its distance from a reference point where the potential energy is considered to be zero. The most common example of potential energy is gravitational potential energy, which is the energy an object has due to its position above the ground. Other examples of potential energy include elastic potential energy, chemical potential energy, and nuclear potential energy. Potential energy can be converted into other forms of energy, such as kinetic energy or thermal energy, through various processes such as falling, stretching, or chemical reactions.

First, let's find the spring potential energy when it is compressed by 10.0 cm:

U_spring = (1/2)kx² = (1/2)(25.0 N/m)(0.1 m)² = 0.125 J

When the object is released, all of this potential energy is converted to kinetic energy:

K = U_spring = 0.125 J

The initial velocity of the object can be found using the conservation of energy:

K = (1/2)mv²

v = √(2K/m) = √(2(0.125 J)/(0.0200 kg)) = 2.50 m/s

Since the object slides a distance of 1.15 m, the average frictional force acting on it is:

F_friction = (1/2)mv²/d1 = (1/2)(0.0200 kg)(2.50 m/s)²/1.15 m = 0.272 N

The gravitational potential energy of the object when it is at a height h = 1.00 m above the floor is:

U_gravity = mgh = (0.0200 kg)(9.81 m/s²)(1.00 m) = 0.196 J

When the object falls to the floor, this potential energy is converted to kinetic energy:

K = U_gravity = 0.196 J

The final velocity of the object just before it hits the floor can be found using the conservation of energy:

K = (1/2)mv²

v = √(2K/m) = √(2(0.196 J)/(0.0200 kg)) = 3.14 m/s

The horizontal distance the object travels while falling can be found using the time it takes to fall:

t = √(2h/g) = √(2(1.00 m)/(9.81 m/s²)) = 0.452 s

d_fall = v*t = (3.14 m/s)(0.452 s) = 1.42 m

The total horizontal distance the object travels is:

d_total = d1 + d_fall = 1.15 m + 1.42 m = 2.57 m

The coefficient of friction can be found using the relationship:

F_friction = μN

where N is the normal force acting on the object. Since the object is not accelerating vertically, we know that:

N = mg

The normal force is also equal in magnitude to the force that the tabletop exerts on the object perpendicular to the surface:

N = F_tabletop

Therefore, the coefficient of friction is:

μ = F_friction/F_tabletop = F_friction/mg = (0.272 N)/(0.0200 kg)(9.81 m/s²) = 1.39

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Answer:

It takes approximately 0.625 seconds for the person to be stopped by the airbag.

Explanation:

We can use the formula for average acceleration to solve this problem:

a = (v_f - v_i) / t

where:

a = average acceleration

v_f = final velocity (0 m/s)

v_i = initial velocity (15 m/s)

t = time

We know that the airbag provides a stopping force of 1200 N, which is equal to the net force on the person-car system. We can use Newton's second law of motion to find the acceleration of the person:

F_net = ma

where:

F_net = net force (1200 N)

m = mass of person (50 kg)

a = acceleration

Solving for a, we get:

a = F_net / m

a = 1200 N / 50 kg

a = 24 m/s^2

Now we can substitute the values of a, v_f, and v_i into the formula for average acceleration and solve for t:

a = (v_f - v_i) / t

24 m/s^2 = (0 m/s - 15 m/s) / t

t = -15 m/s / 24 m/s^2

t = 0.625 s

Therefore, it takes approximately 0.625 seconds for the person to be stopped by the airbag.

Explanation:

Recall the equation for time is distance divided by speed. Here you can use that to solve for "t".

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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The length at which the restoring force is 2F is given by the following expression:

\(x = (-2F + F / (13 cm - 10 cm) * 10 cm) / (F / (13 cm - 10 cm))\)

The restoring force of a spring is proportional to its displacement from its unstretched length, according to Hooke's law:

F = -kx

where F is the restoring force, k is the spring constant, and x is the displacement from the unstretched length.

If we know the restoring force F when the spring is stretched to a length of 13 cm, we can find the spring constant k:

\(F = -k * (13 cm - 10 cm)\\k = F / (13 cm - 10 cm)\)

Next, we can find the displacement that gives a restoring force of 3F:

\(3F = -k * (x - 10 cm)\\3F = -k * x + k * 10 cm\\-3F = k * x - k * 10 cm\\-3F + k * 10 cm = k * x\\x = (-3F + k * 10 cm) / k\)

Substituting the value of k, we get:

\(x = (-3F + F / (13 cm - 10 cm) * 10 cm) / (F / (13 cm - 10 cm))\)

So, the length of the spring for which its restoring force is 3F is given by the above expression.

b. To find the length at which the restoring force is 2F, we can use the same method as above and replace 3F with 2F:

\(2F = -k * (x - 10 cm)x = (-2F + k * 10 cm) / k\)

Substituting the value of k, we get:

\(x = (-2F + F / (13 cm - 10 cm) * 10 cm) / (F / (13 cm - 10 cm))\)

So, the length at which the restoring force is 2F is given by the above expression.

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I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

Answer:

Explanation:

To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.

Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.

Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.

It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.

It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.