M will experience a net downward force, which will cause it to accelerate downhill, while M will experience a net upward force, which will cause it to accelerate upward.
As the same string is attached to both the blocks, it applies the same upward force = tension in the string.
Hence the length of the upward arrows should be the same.
Secondly, the weight of m is lesser than M. Hence, the arrow below m will be smaller than that below M.
This also means that the net force on M will be downwards, and hence, it will accelerate downwards and that on m will be upwards and hence it will accelerate upwards.
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What observation did this geocentric model of the solar system help to explai
Answer:
Geocentric model of the solar system helped to explain RETROGRADE MOTIONS OF PLANETS.
Explanation:
Geocentric model of planets was proposed by Ptolemy. It stated that all sun, planets and stars revolve round the earth in circular orbits.
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(◍•ᴗ•◍)
find the rms speed of a sample of oxygen at 30° C and having a molar mass of 16 g/mol.
At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.
The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:
vrms = √(3kT/m)
Where:
vrms is the rms speed
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
m is the molar mass of the gas in kilograms
To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:
m = 16 g/mol = 0.016 kg/mol
Substituting the values into the formula, we have:
vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))
Calculating this expression yields the rms speed of the oxygen sample:
vrms ≈ 482.34 m/s
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1.How are elements arranged on the periodic table in terms of valence electrons?
2. Show some evidence using data tables
3. Explain how the evidence supports your claim. Explain how the evidence from your data table shows the trends for valence electrons for both groups and periods on the periodic table.
Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.
1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.
2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:
Element | Electron Configuration | Group | Period |
--------------------------------------------
Hydrogen | 1s^1 | 1 | 1 |
Lithium | [He] 2s^1 | 1 | 2 |
Carbon | [He] 2s^2 2p^2 | 14 | 2 |
Oxygen | [He] 2s^2 2p^4 | 16 | 2 |
Neon | [He] 2s^2 2p^6 | 18 | 2 |
--------------------------------------------
3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.
- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.
- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.
By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.
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An object accelerates from rest, with a constant acceleration of 6.4 m/s2, what will its velocity be after 7s?
I also need the Formula
Hi there!
The formula for velocity given acceleration:
v = at
Plug in given values:
v = 6.4(7) = 44.8 m/s
a 85-kg person is riding in a car moving at 19.5 m/s (assume this is the positive direction) when the car runs into a bridge abutment. this problem will illustrate why the invention of the airbag dramatically improved the safety of automobiles.
The invention of the airbag greatly improved the safety of automobiles because, without airbags, the 85-kg person would experience a large force upon impact with the abutment.
What is invention?Invention is the process of creating something new, or discovering a solution to a problem that has never been solved before. It is the art of making something out of nothing and turning it into a reality. Invention is the driving force behind human progress, and has enabled us to develop to the point where we are today.
Without the airbag, this force would be equal to the person's mass multiplied by the acceleration due to the sudden stop of the car, which is equal to -19.5 m/s^2.
This means that the person would experience a force of 1,671.25 N upon impact. This force is potentially enough to cause serious injury or death.
However, when airbags are present, the airbag will absorb some of the force of the impact, reducing it to a much lower level. This is because the airbag will quickly inflate, which will help to reduce the acceleration of the person upon impact. The force experienced by the person will be much lower, potentially saving the person from serious injury or death.
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A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Positive x-axis, 5 m, then goes back, 6 m. What is his total displacement from his original position? Displacement is a vector quantity whilst, distance is a scalar quantity.
His total displacement from his original position is -1 m
We know that total displacement of an object from a position x to a position x', d = final position - initial position.
d = x' - x
If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.
Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.
His final position, x" after moving back 6 m is gotten from
x" - x' = -6 m
x" = -6 + x'
x" = -6 + 5
x" = -1 m
Thus, his total displacement from his original position is
d = final position - initial position
d = x" - x
d = -1 m - 0 m
d = -1 m
So, his total displacement from his original position is -1 m
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The figure shows the cross-section of a hollow cylinder of inner radius a = 5.0 cm and
outer radius b = 7.0 cm. A uniform current density of 1.0 A/cm2 flows through the
cylinder parallel to its axis. Calculate the magnitude of the magnetic field at a distance
of d = 10 cm from the axis of the cylinder. (µ0 = 4π × 10−7 T.m/A)
The magnetic field of a hollow cylinder can be calculated by the Biot-Savart law which can be represented as:`\(d\vec{B} = \frac{\mu_0}{4\pi} \frac{Id\vec{l} \times \vec{r}}{r^2}\)
Where:• I is the current through the wire• dℓ is an infinitesimal segment of the wire• r is the distance from the wire to the point of interest• μ₀ is the permeability of free space Biot-Savart's law can be used to determine the magnetic field produced by any current distribution.
Furthermore, this law is a consequence of the equation describing how a magnetic field induces an electric field and vice versa.
In this case, the cylinder's magnetic field at a distance of d = 10 cm from the axis of the cylinder can be calculated as follows:Given; Inner radius a = 5.0 cm
Radius of cylinder b = 10 cmµ
0 = 4π × 10−7 T.m/A
Formula to be used;`
B= (µ0 * I * a^2)/2 * (d^2 + a^2)^(3/2)`
Here, a = 5 cm
and d = 10 cm.
Substituting the values;
`B = (4 * π * 10^−7 * I * (5*10^−2)^2)/(2 * (10*10^−2^2 + (5*10^−2)^2)^(3/2))`
On solving the above equation, we get;`B = 1.33 × 10^-9 * I T`
Therefore, the magnitude of the magnetic field at a distance of d = 10 cm from the axis of the cylinder is `1.33 × 10^-9 * I T`.
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A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift is performed in three stages, each requiring a vertical distance of 5.90 m: (a) the initially stationary spelunker is accelerated to a speed of 2.30 m/s; (b) he is then lifted at the constant speed of 2.30 m/s; (c) finally he is decelerated to zero speed. How much work is done on the 69.0 kg rescue by the force lifting him during each stage
Answer:
W₃ = 3310.49 J , W3 = 3310.49 J
Explanation:
We can solve this exercise in parts, the first with acceleration, the second with constant speed and the third with deceleration. Therefore it is work we calculate it in these three sections
We start with the part with acceleration, the distance traveled is y = 5.90 m and the final speed is v = 2.30 m / s. Let's calculate the acceleration with kinematics
v2 = v₀² + 2 a₁ y
as they rest part of the rest the ricial speed is zero
v² = 2 a₁ y
a₁ = v² / 2y
a₁ = 2.3² / (2 5.90)
a₁ = 0.448 m / s²
with this acceleration we can calculate the applied force, using Newton's second law
F -W = m a₁
F = m a₁ + m g
F = m (a₁ + g)
F = 69 (0.448 + 9.8)
F = 707.1 N
Work is defined by
W₁ = F.y = F and cos tea
As the force lifts the man, this and the displacement are parallel, therefore the angle is zero
W₁ = 707.1 5.9
W₁ = 4171.89 J W3 = 3310.49 J
Let's calculate for the second part
the speed is constant, therefore they relate it to zero
F - W = 0
F = W
F = m g
F = 60 9.8
F = 588 A
the job is
W² = 588 5.9
W2 = 3469.2 J
finally the third part
in this case the initial speed is 2.3 m / s and the final speed is zero
v² = v₀² + 2 a₂ y
0 = vo2₀² + 2 a₂ y
a₂ = -v₀² / 2 y
a₂ = - 2.3²/2 5.9
a2 = - 0.448 m / s²
we calculate the force
F - W = m a₂
F = m (g + a₂)
F = 60 (9.8 - 0.448)
F = 561.1 N
we calculate the work
W3 = F and
W3 = 561.1 5.9
W3 = 3310.49 J
total work
W_total = W1 + W2 + W3
W_total = 4171.89 +3469.2 + 3310.49
w_total = 10951.58 J
A torque of 36.5 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result of a directed force combined with a friction force. As a result of the applied torque the angular speed of the wheel increases from 0 to 10.3 rad/s. After 6.10 s the directed force is removed, and the wheel comes to rest 60.6 s later.
(a) What is the wheel's moment of inertia (in kg m2)? kg m
(b) What is the magnitude of the torque caused by friction (in N m)? N m
(c) From the time the directed force is initially applied, how many revolutions does the wheel go through?
______ revolutions
Answer:
\(21.6\ \text{kg m}^2\)
\(3.672\ \text{Nm}\)
\(54.66\ \text{revolutions}\)
Explanation:
\(\tau\) = Torque = 36.5 Nm
\(\omega_i\) = Initial angular velocity = 0
\(\omega_f\) = Final angular velocity = 10.3 rad/s
t = Time = 6.1 s
I = Moment of inertia
From the kinematic equations of linear motion we have
\(\omega_f=\omega_i+\alpha_1 t\\\Rightarrow \alpha_1=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha_1=\dfrac{10.3-0}{6.1}\\\Rightarrow \alpha_1=1.69\ \text{rad/s}^2\)
Torque is given by
\(\tau=I\alpha_1\\\Rightarrow I=\dfrac{\tau}{\alpha_1}\\\Rightarrow I=\dfrac{36.5}{1.69}\\\Rightarrow I=21.6\ \text{kg m}^2\)
The wheel's moment of inertia is \(21.6\ \text{kg m}^2\)
t = 60.6 s
\(\omega_i\) = 10.3 rad/s
\(\omega_f\) = 0
\(\alpha_2=\dfrac{0-10.3}{60.6}\\\Rightarrow \alpha_1=-0.17\ \text{rad/s}^2\)
Frictional torque is given by
\(\tau_f=I\alpha_2\\\Rightarrow \tau_f=21.6\times -0.17\\\Rightarrow \tau=-3.672\ \text{Nm}\)
The magnitude of the torque caused by friction is \(3.672\ \text{Nm}\)
Speeding up
\(\theta_1=0\times t+\dfrac{1}{2}\times 1.69\times 6.1^2\\\Rightarrow \theta_1=31.44\ \text{rad}\)
Slowing down
\(\theta_2=10.3\times 60.6+\dfrac{1}{2}\times (-0.17)\times 60.6^2\\\Rightarrow \theta_2=312.03\ \text{rad}\)
Total number of revolutions
\(\theta=\theta_1+\theta_2\\\Rightarrow \theta=31.44+312.03=343.47\ \text{rad}\)
\(\dfrac{343.47}{2\pi}=54.66\ \text{revolutions}\)
The total number of revolutions the wheel goes through is \(54.66\ \text{revolutions}\).
If you were to pour 4 different liquids into a glass and the liquids separated into 4 layers, which liquid would have the highest density?
A. the layer at the bottom of the glass
B. the third layer from the bottom of the glass
C. the layer at the top of the glass
D. the second layer from the bottom of the glass
Answer:
A.
Explanation:
The liquid with the higher density will be found at the bottom of the glass because is the heaviest of all. The liquids which have a lower density than the liquid at the bottom of the glass will be found at the top of the glass. We assume that the liquids are not soluble in each other because otherwise they will be mixed.
Assume you are going to race the three objects (hollow sphere, disk and ring used in Experiment 8.2) by releasing them from rest at the top of an inclined plane.Which object do you expect to reach the bottom of the inclined plan first? Why?
Answer:
a. The disk
b. Because it has the smallest rotational inertia
Explanation:
a. Which object do you expect to reach the bottom of the inclined plan first?
I would expect the disk to reach the bottom first.
b. Why?
This is because the disk has the smallest rotational inertia.
The rotational inertial of the hollow sphere, disk and ring are 2/3MR², 1/2MR² and MR² respectively.
Since the three objects are rolling from the same height, they have the same mechanical energy.
But, since the disk has the smallest rotational inertia, it would have the smallest rotational kinetic energy and largest translational kinetic energy. The disk's smaller rotational kinetic energy will cause to rotate less but translate more than the other objects and thus reach the bottom first.
The object which is expected to reach the bottom of the inclined plan first is the disk, as it has the lowest rotational inertia.
What is a moment of inertia?Moment of inertia is the force which acts in the opposite direction of the force of angular acceleration acting on the body.
There are three objects, hollow sphere, disk and ring.
The moment of inertia of the hollow sphere object is given as,\(I=\dfrac{2}{3}mr^2\)
The moment of inertia of the ring is,\(I=mr^2\)
The moment of inertia of the disk is,\(I=\dfrac{1}{2}mr^2\)Here, (m) is the mass and (r) is the radius of the object.
These three objects are going to race by releasing from rest at the top of an inclined plane to the bottom of the plane.
As moment of inertia is the force which acts in the opposite direction of the force of angular acceleration acting on the body.
Thus the less the value of inertia will result in less the time required to reach at the bottom of the inclined plane.
Hence, the object which is expected to reach the bottom of the inclined plan first is the disk, as it has the lowest rotational inertia.
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A capacitor is formed from two square plates of edge length a and separation d, with d <
Answer:
A capacitor is formed from two square plates of edge length a and separation d, with d <
Explanation:
A capacitor is formed from two square plates of edge length a and separation d, with d <
H3C------CH------CH3 | | CH2------CH3The branched alkane contains____carbons in the parent chain and_____substituent group(s).
The parent chain is the chain containing large amount of carbon atom.
Thus,
CH3-CH-CH3 is the parent chain.
Thus, the number of carbon atoms in this chain is three.
The substituent group is the another group of chain attached to the parent chain containing less carbon atoms. The substitutent group is attached to the second carbon of the parent chain.
Thus, the substitutent group is 2-ethane (CH2-CH3).
what is the terminal velocity of blood
Answer:
25.1
Explanation:
Find the measure of arc CD (round to the nearest degree).
1.31 m
0.5 m
The measure of arc CD is
The measure of arc CD (round to the nearest degree) is 150 degress
How do i determine the measure of arc CD to the nearest degree?The following data were obtained from the question:
Radius (r) = 0.5 cmLength of arc CD = 1.31 mMeasure of arc CD (θ) =?Length of arc = 2πr × (θ / 360)
Inputting the given parameters, we can obtain the measure of arc CD as follow:
1.31 = (2 × 3.14 × 0.5) × (θ / 360)
1.31 = (3.14 × θ) / 360
Cross multiply
3.14 × θ = 1.31 × 360
3.14 × θ = 471.6
Divide both sides by 3.14
θ = 471.6 / 3.14
θ = 150 °
Thus, we can conclude that the measure of arc CD is 150 °
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Complete question:
See attached photo
I need help fast please help
How do nutritional needs change when a person increases their activity level to gain muscle mass?
When a person increases their activity level to gain muscle mass, their nutritional needs change.
How utritional needs change when a person increases their activity level to gain muscle mass?The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.
Individual variations exist, so seeking personalized guidance from a professional is recommended.
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the container is filled with liquid. the depth of liquid is 60 cm. if it is exerting the pressure of 2000pa. calculate the density of it
Answer:
\(\rho=333.33\ kg/m^3\)
Explanation:
Given that,
A container is filled with liquid. At a depth of 60 cm it exerts a pressure of 2000 Pa.
We need to find the density of the liquid.
The pressure exerted by liquid at a depth is given by the formula as follows :
\(P=\rho gh\)
h = 60 cm = 0.6 m
g is acceleration due to gravity
Putting all the values,
\(\rho=\dfrac{P}{gh}\\\\\rho=\dfrac{2000}{10\times 0.6}\\\\=333.33\ kg/m^3\)
So, the density of the liquid is \(333.33\ kg/m^3\).
A boy starts working front point A and walks a love fowards north and stops at point Now, he furns 136. to his right and walks loleme to reach a point c. what is distance betweee A & C ?
Answer:
Without knowing the actual distances involved, it's difficult to give a specific answer. However, we can use the information given in the question to determine the distance between points A and C using the Pythagorean theorem.
Let's assume that the boy walked a distance of x units from point A to point B, and a distance of y units from point B to point C. Then we can use the following diagram:
C
|
y |
| | x
|-----------B
|
|
A
According to the problem, the boy first walked a certain distance x in a direction that is not specified (we only know that it's forward and north). Then he turned 136 degrees to his right and walked a distance y to reach point C. Since the turn was to the right, the boy turned towards the east, so we can draw a line from point B towards the right to represent this change in direction.
Now we can apply the Pythagorean theorem to find the distance between points A and C:
AC² = AB² + BC²
We know that AB = x, and we need to find BC. To do so, we can use trigonometry. Since the boy turned 136 degrees to his right, he ended up facing 180 - 136 = 44 degrees east of north. This means that the angle between BC and AB is 90 - 44 = 46 degrees.
Using trigonometry, we can express BC in terms of y and the tangent of the angle 46 degrees:
tan(46) = BC / y
BC = y tan(46)
Substituting this expression for BC into the Pythagorean theorem equation, we get:
AC² = x² + (y tan(46))²
Simplifying:
AC² = x² + y² tan²(46)
We can calculate tan²(46) using a calculator or a table of trigonometric functions. Let's assume that tan²(46) is equal to 1.470. Then we have:
AC² = x² + 1.470y²
To find the distance between A and C, we need to take the square root of both sides of the equation:
AC = sqrt(x² + 1.470y²)
Without more information about the distances involved, we cannot compute the actual numerical value of AC.
explain why the insulting layer of fleece is good at reducing the rate of energy transfr
The insulating layer of fleece is effective at reducing the rate of energy transfer due to its unique properties and structure. Fleece is made of synthetic fibers or natural fibers such as wool, which have excellent insulating properties.
One key factor is the structure of fleece. Fleece fabric consists of many small air pockets trapped within the fibers. Air is a poor conductor of heat, so these air pockets act as a barrier to prevent the transfer of thermal energy. The trapped air creates a layer of insulation that helps to slow down the transfer of heat between the body and the environment.
Furthermore, fleece has a high loft, meaning it is thick and fluffy. The loft creates additional air space and increases the insulation capacity. The thickness of the fleece allows for more air to be trapped, providing a thicker barrier for heat transfer. The fibers themselves also have natural crimps and curls, which further enhance the insulation by creating more air pockets.
Additionally, fleece is hydrophobic, meaning it repels moisture. Moisture has a higher thermal conductivity than air, so by repelling moisture, fleece maintains its insulating properties even in damp conditions. This is particularly advantageous in outdoor activities or during physical exertion when the body may produce sweat.
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Explain what you understand by Millennial Generation
Answer:
refers to the generation of people born between the early 1980s and 1990s
A particle with mass
m = 3.80 kg
accelerates according to
a = (−3.40i + 1.70j) m/s2.
(a) What is the net force acting on the particle? (Express your answer in vector form.)
(b) What is the magnitude of this force?
The net force acting on the particle would be and the magnitude of the force would be -12.92i + 6.49j and the magnitude of the force would be 14.46 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The net force on the particle = mass of the particle × acceleration
=3.80*(−3.40i + 1.70j)
= -12.92i + 6.49j
Thus, the magnitude of the net force on the particle would be 14.46 Newtons.
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What is the linear diameter (in meters) of an object that has an angular diameter of 110 arcseconds and a distance of 25,000 m?
Answer:
Explanation:
angle θ = 110 arcsec
= 110 /60 arcmin
= 1.8333 arcmin
= 1.8333 / 60 degree
= .030555 degree
= .030555 x π / 180 radian
= 5.33 x 10⁻⁴ radian .
linear diameter = angular diameter in radian x distance
= 5.33 x 10⁻⁴ x 25000
= 13.325 m
linear diameter of object = 13.325 m .
A spring of spring constant k = 200 N m−1 is slowly extended from an extension of 3.0 cm to an extension of 5.0 cm. Calculate the work done by the extending force. 60
Answer:
31
Explanation:
No need
Calculate the heat change involved when 2,000 g of water is heated from 20 °C to 99.7°C in an electric kettle.
Which of these will have the same units if acceleration is multiplied by time? Force Time velocity Pressure
Answer:
Velocity
Explanation:
Velocity equals the original velocity... Plus
the acceleration is multiplied by time.
If the acceleration is multiplied by time then we get velocity as a result, therefore velocity has the same unit.
What is pressure?Pressure is measured as the amount of force applied in the one-meter of area. Pascal is used as the SI unit of it. The amount of pressure can be calculated by dividing the amount of force by the area of force applied. In relation to atmospheric pressure, the pressure is measured. Pressure does not represent any direction, so it comes under a scalar quantity. Many scientific and day-to-day life equipment use pressure principles like gauge meter thermometers in designing cars, ships, and every mechanical part.
We know that acceleration has an SI unit of m /\(s^{2}\) So if we multiply the time with an acceleration whose unit is second we will get m / s which is the unit of velocity.
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I need help with questions b and d, that’s all.
Thank you.
b). The power depends on the RATE at which work is done.
Power = (Work or Energy) / (time)
So to calculate it, you have to know how much work is done AND how much time that takes.
In part (a), you calculated the amount of work it takes to lift the car from the ground to Point-A. But the question doesn't tell us anywhere how much time that takes. So there's NO WAY to calculate the power needed to do it.
The more power is used, the faster the car is lifted. The less power is used, the slower the car creeps up the first hill. If the people in the car have a lot of time to sit and wait, the car can be dragged from the ground up to Point-A with a very very very small power ... you could do it with a hamster on a treadmill. That would just take a long time, but it could be done if the power is small enough.
Without knowing the time, we can't calculate the power.
...
d). Kinetic energy = (1/2) · (mass) · (speed squared)
On the way up, the car stops when it reaches point-A.
On the way down, the car leaves point-A from "rest".
WHILE it's at point-A, it has no speed. So it has no (zero) kinetic energy.
Unbeknownst to most students, every time the school floors are waxed, the physics teachers get together to have a barrel of phun doing friction experiments in their socks (uhm - they do have clothes on; its just that they don't have any shoes on their feet). On one occasion, Mr. London applies a horizontal force to accelerate Mr. Schneider (mass of 84 kg) rightward at a rate of 1.2 m/s/s. If the coefficient of friction between Mr. Schneider 's socks and the freshly waxed floors is 0.35, then with what force (in Newtons) must Mr. London be pulling?
The frictional force is taken away from the net force. Mr. London will pull with a force of 388.9 N
What is Force ?Force can simply be defined as a pull or push. It is a product of mass and acceleration. It is a vector quantity.
Given that Mr. London applies a horizontal force to accelerate Mr. Schneider (mass of 84 kg) rightward at a rate of 1.2 m/s/s. If the coefficient of friction between Mr. Schneider 's socks and the freshly waxed floors is 0.35, then the force F in which Mr. London is pulling will be;
F - Fr = ma
Where
F = ?m = 84 kga = 1.2 m/s²N = ?μ = 0.35N = mg
N = 84 × 9.8
N = 823.2 N
Fr = μN
Fr = 0.35 × 823.2
Fr = 288.12 N
F - 288.12 = 84 × 1.2
F - 288.12 = 100.8
F = 100.8 + 288.12
F = 388.92 N
Therefore, Mr. London must be pulling with a force of 388.9 N
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an inclinded plane makes work easier by increasing the distance and blank the force
Hi! I believe your answer is decreasing. An inclined plane makes work easier by decreasing the amount of effort force needed, but increases the distance. I hope this helps you! Good luck and have a great day. ❤️✨
In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O
is shown.
Through which point will this ray pass, after refraction by the lens?
The point through which this ray will pass, after refraction by the lens is point D.
What is refraction of light?The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.
From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.
Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.
So point D is the correct answer.
Learn more about refraction here: https://brainly.com/question/1360744
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