Answer:
The larger number is \(1100\)
Step-by-step explanation:
Let larger number be \(x\)
We have
\(\frac{x}{700} =\frac{11}{7} \\\\x=100\times11\\\\=1100\)
Answer:
The larger number is 1100.
Step-by-step explanation:
Solution :
Let the,
>> Larger number be 11x. >> Smaller number be 7x.Now, According to the question :
\(\begin{gathered} \dashrightarrow\sf{Smaller \: number} = \tt{700} \end{gathered}\)
\(\begin{gathered} \dashrightarrow\sf{7x}= \tt{700} \end{gathered}\)
\(\begin{gathered} \dashrightarrow\sf{x}= \tt{700 \div 7} \end{gathered}\)
\(\begin{gathered} \dashrightarrow\sf{x}= \tt{ \dfrac{700}{7} } \end{gathered}\)
\(\begin{gathered} \dashrightarrow\sf{x}= \tt{\cancel{\dfrac{700}{7}}} \end{gathered}\)
\(\begin{gathered} \dashrightarrow \sf{x}= \tt{100} \end{gathered}\)
Hence, the value of x is 100.
Now, calculating the larger number :
\(\begin{gathered} \dashrightarrow\sf{Larger \: number} = \tt{11x} \end{gathered}\)
\(\begin{gathered} \dashrightarrow\sf{Larger \: number} = \tt{11 \times 100} \end{gathered}\)
\(\begin{gathered} \dashrightarrow\sf{Larger \: number} = \tt{1100} \end{gathered}\)
Hence, the larger number is 1100
\(\rule{300}{1.5}\)
How many ways can a committee of four students be selected from a 15-member club? a.15!44! b.15!11!×4! c.15×14×13 d.B and C
Answer:
B) 15! / (11! × 4!)------------------------
This is a combination of 4 out of 15.
Use combination formula:
nCr = n! / ((n - r)! × r!),where C - number of combinations, n- total number of objects, r - number of choosing from objects
Substitute 15 for n and 4 for r to get:
15C4 = 15! / ((15 - 4)! × 4!) = 15! / (11! × 4!)Correct choice is B.
A spinner with repeated colors numbered from 1 to 8 is shown. Sections 1 and 8 are purple. Sections 2 and 3 are yellow. Sections 4, 5, and 6 are blue. Section 7 is orange.
Determine P(not yellow) if the spinner is spun once.
75%
37.5%
25%
12.5%
The probability of the spinner is P(not yellow) = 37.5%.
What is the probability?
Probability is simply how likely something is to happen. Whenever we're unsure about the outcome of an event, we can talk about the probabilities of certain outcomes—how likely they are. The analysis of events governed by probability is called statistics.
If the spinner is spun once, the probability of not landing on yellow (sections 2 and 3) is equal to the probability of landing on purple (sections 1 and 8), blue (sections 4, 5, and 6), or orange (section 7).
The total probability of these sections is 1- (2/8) = 1-(1/4) = 3/4.
So P(not yellow) = 3/4 = 37.5%.
Hence, the probability of the spinner is P(not yellow) = 37.5%.
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A Cylinder has a radius of 10 feet and a height of 11.4 feet what is the approximate volume of the cylinder?
Answer:
3579.6 \(ft^{3}\)
Step-by-step explanation:
First, write out the equation used to find the volume of a cylinder and place the values in place of the variables. The equation is \(\pi\)\(r^{2}\)*h where r is the radius and h is the height. When we place the values of the variables into the equation we get: \(\pi\)\(10^{2}\)*11.4. Next, square 10 to get 100. This would give you 3.14*100*11.4. When you multiply this together you get 314 times 11.4 which gives you 3579.6 ft cubed.
I believe it's 3581.42 (if the answer needs be rounded to 2 decimal places.
Step-by-step explanation:
area of circle = r×r×π
area of circle × height = volume
10 × 10 × π = 314.16
314.16 × 11.4 = 3581.42
pls help will give brainliest
Chloe's new lunch box is only 5 centimeters in height, so it fits in her backpack along with all her books. The lunch box has 3 sections for different types of food. The length and width of the lunch box are 22 centimeters and 14 centimeters. What is the volume of Chloe's new lunch box?
Answer:
1,540
Step-by-step explanation:
length times width times height makes the volume
Hope this helps
BTW it's my birthday
1. Two trains, one traveling at 72 km/h and the other traveling at 144 km/h, are headed towards one another on a straight, level track. When the trains are 0.950 km apart, each engineer sees the other's train and applies the brakes. The brakes slow each train at a rate of 12960 km/h
2
. Do the trains collide? Hint: For a solution, determine how far each train would need to travel to come to a complete stop. Is the total distance less than 0.950 km ? a. A car sits at rest at a red light. The moment the light turns green, a truck passes the car with a constant speed of 10.0 m/s. At the same moment, the car begins to accelerate at 2.50 m/s
2
. Assuming the car continues with a constant acceleration, how long will it take for the car to catch up to the truck? How far will they travel? How fast will the car be traveling when it passes the truck? b. A rocket car accelerates from rest at a rate of 124 m/s
2
. (!!!) (a) How fast will the car be traveling at a time of 5.00 seconds? (b) How far will the car travel during its 5 th second of motion?
The distance travelled by the car during its 5th second of motion is 775 m.
Part A)
Given data:
Speed of train 1 = 72 km/h
Speed of train 2 = 144 km/h
The distance between the trains is 0.950 km
Braking acceleration of trains = -12960 km/h²
We have to determine if the two trains collide or not.
To solve this question, we first need to determine the distance each train will travel before coming to a stop.
Distance travelled by each train to come to rest is given by:
v² = u² + 2as
where, v = final velocity
u = initial velocity
a = acceleration of train
and s = distance travelled by train to come to rest
Train 1: u = 72 km/h
v = 0 km/h
a = -12960 km/h²
s₁ = (v² - u²) / 2a
s₁ = (0² - 72²) / 2(-12960) km
= 0.028 km
= 28 m
Train 2: u = 144 km/h
v = 0 km/h
a = -12960 km/h²
s₂ = (v² - u²) / 2a
s₂ = (0² - 144²) / 2(-12960) km = 0.111 km
= 111 m
The total distance travelled by both the trains before coming to rest = s₁ + s₂ = 28 + 111 = 139 m
Since 139 m is less than 950 m, therefore the trains collide.
Part B)
Given data:
Speed of truck = 10.0 m/s
Acceleration of car = 2.50 m/s²
The distance travelled by the car in the time t is given by:
s = ut + 1/2 at²
where,u = initial velocity of car
a = acceleration of car
and s = distance travelled by car
The car catches up with the truck when the distance covered by both of them is the same. Therefore, we can equate the above two equations.
vt = ut + 1/2 at²
t = (v - u) / a
t = (10 - 0) / 2.5 s
t = 4 s
Therefore, the time required for the car to catch up to the truck is 4 seconds.
Distance travelled by the car:
s = ut + 1/2 at²
s = 0 x 4 + 1/2 x 2.5 x 4²s = 20 m
Therefore, the distance travelled by the car is 20 m.
Speed of car when it passes the truck:
The velocity of the car when it passes the truck is given by:
v = u + at
v = 0 + 2.5 x 4
v = 10 m/s
Therefore, the speed of the car when it passes the truck is 10 m/s.
Part C)
Given data:
Acceleration of rocket car = 124 m/s²
The velocity of the car at a time t is given by:
v = u + at
where,v = velocity of car
u = initial velocity of car
a = acceleration of car
and t = time taken by the car
To find the speed of the car at a time of 5.00 seconds, we have to put t = 5 s in the above equation:
v = u + at
v = 0 + 124 x 5
v = 620 m/s
Therefore, the speed of the car at a time of 5.00 seconds is 620 m/s.
The distance travelled by the car during its 5th second of motion is given by:
s = u + 1/2 at² + (v - u)/2 x ta = 124 m/s²
t = 5 s
Initial velocity of car, u = 0
Therefore, s = 1/2 x 124 x 5² + (620 - 0)/2 x 5
s = 775 m
Therefore, the distance travelled by the car during its 5th second of motion is 775 m.
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Lynn's cable bill for watching television is a first rate of $50 per month plus $1.25 for every movie that she chooses to rent. After one month of service, she owed $66.2.
Answer:
$66.20=1.25x+50
Step-by-step explanation:
Be sure about the question. This problem is exactly the same to another one I did. So this should help.
Answer:
If the question is to reveal how many movies Lynn has watched, then...:
13 movies
Step-by-step explanation:
$50 is the monthly bill
$66.2 - $50 = $16.2 for movies
$16.2 / $1.25 = 12.96 movies .( or 13 movies)
assume that a plane is flying at a constant speed under unvarying wind conditions. traveling against a head wind, the plane takes 4 hours to travel 1540 miles. traveling with a tail wind, the plane flies 1365 miles in 3 hours. find the speed of the plane and the speed of the wind.
The speed of the plane is 410 mph and the speed of the wind is 45 mph.
To find the speed of the plane and the speed of the wind, we can use the following system of linear equations:
Let x = speed of the plane (in mph) and y = speed of the wind (in mph).
Equation 1: (x - y) * 4 = 1540 (traveling against headwind)
Equation 2: (x + y) * 3 = 1365 (traveling with tailwind)
Step 1: Simplify the equations:
Equation 1: 4x - 4y = 1540
Equation 2: 3x + 3y = 1365
Step 2: Solve for x in Equation 2:
x = (1365 - 3y) / 3
Step 3: Substitute x in Equation 1:
4((1365 - 3y) / 3) - 4y = 1540
Step 4: Solve for y:
y = 45 mph (speed of the wind)
Step 5: Substitute y in the x equation:
x = (1365 - 3(45)) / 3
Step 6: Solve for x:
x = 410 mph (speed of the plane)
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How do you know that 4/11 is a repeating decimal?
Answer:
Step-by-step explanation:
A repeating decimal or recurring decimal is decimal representation of a number whose digits are periodic (repeating its values at regular intervals) and the infinitely repeated portion is not zero.
For this case 4/11 are
0.36 36 36 36 36 36 36 36 36
it repeating 36 36
so 4/11 are repeating decimal
Answer:
\( \frac{4}{11} = 0.3636\)
Step-by-step explanation:
The remainders repeat in a pattern and the quotient also repeats in blocks of two. So, 4/11 = 0.3636, Which
36 repeats, In this case, 36 is the repeating pattern.
Easy 10 points to make by answering this question. Thank you!
Answer:
b). 18.3
Step-by-step explanation:
c² = a² + b² - 2bc (cos A)
= 12.4² + 9.9² - 2(12.4) (9.9) x cos(110)
= 153.76 + 98.01 - 245.52 x cos(110)
= 251.77 - 245.52 x -0.342
c² = 251.77 + 83.97
c² = 335.74
c = 18.3
please help me
i’m so stuck
Answer:
2 cm
Step-by-step explanation:
V=πr2h = 20π
-π -π
r2h = 20
h= 5
r2(5) = 20
/5 /5
r2=4
/2 /2
r=2cm
(my work is complicated, but trust me 2 cm is the answer)
What is the range of the following data set?
34 15 75 81 45 73 97 89 23
Answer: 45
Step-by-step explanation:
find the velocity and acceleration vectors in terms of and . r= 2cost and theta = 9t
So the velocity vector is v = (-2sin(t)) i + (2cos(t)) j, and the acceleration vector is a = (-2cos(t)) i + (-2sin(t)) j, both in terms of t.
Given
r= 2cost and theta = 9t
To Find
the velocity and acceleration vector
Solution
We can start by expressing the position vector r in terms of the Cartesian coordinates x and y:
x = r cos(theta) = 2cos(t)
y = r sin(theta) = 2sin(t)
To find the velocity vector, we can take the time derivative of the position vector:
v = (dx/dt) i + (dy/dt) j
where i and j are the unit vectors in the x and y directions, respectively.
Taking the derivatives:
dx/dt = -2sin(t)
dy/dt = 2cos(t)
Substituting these back into the velocity vector equation:
v = (-2sin(t)) i + (2cos(t)) j
To find the acceleration vector, we can take the time derivative of the velocity vector:
a = (d^2x/dt^2) i + (d^2y/dt^2) j
Taking the derivatives:
d^2x/dt^2 = -2cos(t)
d^2y/dt^2 = -2sin(t)
Substituting these back into the acceleration vector equation:
a = (-2cos(t)) i + (-2sin(t)) j
So the velocity vector is v = (-2sin(t)) i + (2cos(t)) j, and the acceleration vector is a = (-2cos(t)) i + (-2sin(t)) j, both in terms of t.
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In a survey given by camp counselors, campers were
asked if they like to swim and if they like to have a
cookout. The Venn diagram displays the campers'
preferences.
Camp Preferences
S
0.06
0.89
C
0.04
0.01
A camper is selected at random. Let S be the event that
the camper likes to swim and let C be the event that the
camper likes to have a cookout. What is the probability
that a randomly selected camper does not like to have a
cookout?
O 0.01
O 0.04
O 0.06
O 0.07
The probability is 0.96 that a randomly selected camper does not like to have a cookout, based on the given information and the complement rule of probability.
To determine the probability that a randomly selected camper does not like to have a cookout, we need to find the complement of the event C (the event that the camper likes to have a cookout).
Looking at the Venn diagram, we see that the probability of event C is 0.04 (represented by the intersection of circles C and A). Therefore, the probability of the complement of event C (not liking to have a cookout) is equal to 1 minus the probability of event C.
1 - 0.04 = 0.96
Hence, the probability that a randomly selected camper does not like to have a cookout is 0.96.
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The combined perimeter of an equilateral triangle and square is 13.
Find the dimensions of the triangle and square that produce a minimum total area.
The measurement of square on each side
The measurement of triangle on each side
Find the dimensions of the triangle and square that produce a maximum total area.
The measusrement of square on each side
The measurement of triangle on each side
To minimize the total area of an equilateral triangle and square, the side length of the square should be 2.167 and the side length of the triangle should be 3.833.
To find the dimensions that minimize the total area, we can set up equations based on the given information. Let's denote the side length of the square as 's' and the side length of the equilateral triangle as 't'. The perimeter of the square is 4s, and the perimeter of the equilateral triangle is 3t. Given that the combined perimeter is 13, we have the equation 4s + 3t = 13.
To minimize the total area, we need to consider the formulas for the areas of the square and equilateral triangle. The area of the square is given by A_square = \(s^2\), and the area of the equilateral triangle is given by A_triangle = (\(\sqrt{(3)}\)/4) *\(t^2\).
To find the values that minimize the total area, we can substitute s = (13 - 3t)/4 into the equation for A_square and solve for t. By finding the derivative of the total area with respect to t and setting it equal to zero, we can find the value of t that minimizes the area.
Similarly, to find the dimensions that maximize the total area, we follow the same process but this time maximize the total area by finding the value of t that maximizes the area.
Performing the calculations, we find that to minimize the total area, the side length of the square is approximately 2.167 and the side length of the triangle is approximately 3.833. To maximize the total area, the side length of the square is approximately 4.333 and the side length of the triangle is approximately 1.667.
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Find the exact length of the curve.y = 3 + 4x^3/2, 0 ≤ x ≤ 1
The exact length of the curve. y = 3 + 4x^3/2, 0 ≤ x ≤ 1 is L = ∫√(9+108x-144x^(5/2)) / √(9-16x^3) dx, from 0 to 1.
To find the length of the curve, we need to use the arc length formula:
L = ∫√(1+(dy/dx)^2) dx, where y = 3 + 4x^(3/2) and 0 ≤ x ≤ 1.
First, we need to find dy/dx:
dy/dx = (12x^(1/2))/2√(3 + 4x^(3/2))
dy/dx = 6x^(1/2)/√(3 + 4x^(3/2))
Now, we can substitute this into the arc length formula:
L = ∫√(1+(6x^(1/2)/√(3 + 4x^(3/2)))^2) dx, from 0 to 1.
Simplifying the inside of the square root, we get:
L = ∫√(1+(36x)/(3 + 4x^(3/2))) dx, from 0 to 1.
We can simplify this further by multiplying the numerator and denominator of the fraction by (3 - 4x^(3/2)):
L = ∫√(1+36x(3-4x^(3/2))/(9-16x^3)) dx, from 0 to 1.
Expanding the numerator, we get:
L = ∫√((9+108x-144x^(5/2))/(9-16x^3)) dx, from 0 to 1.
Simplifying the expression under the square root, we get:
L = ∫√(9+108x-144x^(5/2)) / √(9-16x^3) dx, from 0 to 1.
We can evaluate this integral using numerical methods, such as Simpson's rule or the trapezoidal rule, to get an approximation of the length of the curve. The exact length of the curve cannot be expressed in a finite number of terms, but it can be approximated to any desired degree of accuracy using numerical methods.
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Which system of equations is represented by the matrix below?
0 5 15
3 -2 9
A. -5y = 15
3x-2y = 9
B. 5y = 15
3x+2y=9
C. 5y = 15
3x-2y=9
Answer:
Step-by-step explanation:
Answer:
Answer:
Step-by-step explanation:
When making a matrix of two equations with the variables x and y, the result will be a matrix with three columns:
a column for the values of x in each equation
a column for the values of y in each equation
a column for the independent values of each equation
since our system of equations is:
we can see that the value for x in the first equation is 3 and in the second equation is 4, thus the first column will have the numbers 3 and 4:
Now for the values of y we have -5 in the first equation and -2 in the second equation, we update the matrix with another column with the values of -5 and -2:
Finally, the last column is the independent values of each equation (or the results) in the first equation that number is 12 and in the second equation is 15, thus the matrix is:
usually there is a line separating the columns for the values of x and y, and the independent values:
this is the matrix of the system of equations
A piece of green rope is being used to make a border around the outside of a sculpture that is in the shape of an equilateral triangle. One side of the equilateral triangle has a length of 3x + 3. Give TWO equivalent expressions that can be used to represent the length of the rope that is used to border all 3 sides.
Answer:
The equivalent expressions are;
9x + 9
and
9(x + 1)
Step-by-step explanation:
Mathematically, we should understand that an equilateral triangle has all of its sides equal
So if one side is 3x+ 3, the other sides too measures same
Therefore, the length of the rope represents the perimeter of the triangle
This is obtainable by adding all the side lengths together
This will be;
3x + 3 + 3x + 3 + 3x + 3 = 9x + 9
This is also same as 9(x + 1)
Answer:
sussi baker!!!
Step-by-step explanation:
26 In a bag there are only red counters, blue counters, green counters and pink counters.
A counter is going to be taken at random from the bag.
The table shows the probabilities of taking a red counter or a blue counter.
Colour
Probability
red
0.05
blue
1 -0.15 -0.05
0.8
0.15
green
There are 18 blue counters in the bag.
(b) Work out the total number of counters in the bag
The total number of counters in the bag is given as follows:
23 counters.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
The probability of taking a blue counter is of 0.8, while there are 18 blue counters in the bag, hence the total number of counters in the bag is obtained as follows:
0.8 = 18/n
0.8n = 18
n = 18/0.8
n = 23 counters. (rounding up).
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Compute the surface integral of f(x, y, z) = x + y + z along the surface S parametrized by r(u, v) = (u+u, u - v, 1+2u + v), for 0 ≤ u ≤ 2, 0 ≤ v ≤ 1.
the surface integral of f(x, y, z) = x + y + z along the surface S is 10√14.
To compute the surface integral of f(x, y, z) = x + y + z along the surface S parametrized by r(u, v) = (u+u, u - v, 1+2u + v), for 0 ≤ u ≤ 2, 0 ≤ v ≤ 1, we can use the surface integral formula:
∫∫f(x, y, z) dS = ∫∫f(r(u, v)) ||r_u × r_v|| du dv
where r_u and r_v are the partial derivatives of r with respect to u and v, respectively, and ||r_u × r_v|| is the magnitude of their cross product.
First, we need to compute the partial derivatives of r with respect to u and v:
r_u = (1, 1, 2)
r_v = (1, -1, 1)
Next, we can compute the cross product of r_u and r_v:
r_u × r_v = (3, 1, -2)
The magnitude of this cross product is:
||r_u × r_v|| = √(3^2 + 1^2 + (-2)^2) = √14
Now, we can write the integral as:
∫∫f(x, y, z) dS = ∫∫(u + u + u - v + 1 + 2u + v) √14 du dv
Using the limits of integration given, we have:
∫∫f(x, y, z) dS = ∫ from 0 to 1 ∫ from 0 to 2 (4u + 1) √14 du dv
Integrating with respect to u, we get:
∫∫f(x, y, z) dS = ∫ from 0 to 1 [(2u^2 + u) √14] evaluated at u=0 and u=2 dv
∫∫f(x, y, z) dS = ∫ from 0 to 1 (8√14 + 2√14) dv
Integrating with respect to v, we get:
∫∫f(x, y, z) dS = (8√14 + 2√14) v evaluated at v=0 and v=1
∫∫f(x, y, z) dS = 10√14
Therefore, the surface integral of f(x, y, z) = x + y + z along the surface S is 10√14.
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find the product of
\(63 \times 0 \times ( - 7)\)
Answer:
0
Step-by-step explanation:
63 * 0 is 0. 0 * (-7) is also 0.
Anything multiplied by 0 is 0, no matter how big the number is, or how many numbers there are.
Hope this helps :)
how do you solve d/3-9= -12?
Answer:
d=-9
Step-by-step explanation:
you simplify both side of the equation
d/3-9=-12
1/3d+-9=-12
add 9 both sides
1/3d-9+9=-12+9
1/3d=-3
then you multiply 3 both sides
3 x (1/3d)=(3) x(-3)
d=-9
Hopes this helps :)
Find the particular solution to the given differential equation that satisfies the given conditions. √x² + y² dy = 7(xdx + ydy); x = 16 when y=0 The particular solution is (Type an equation.)
The particular solution to the given differential equation \($\sqrt[4]{x^2+y^2} d y=7(x d x+y d y)$\) that satisfies the condition x = 16 when y = 0, is \($\frac{4}{5} \sqrt[4]{256^2+y^2} = 896$\).
The particular solution to the given differential equation that satisfies the condition x = 16 when y = 0 can be found by integrating the equation and applying the initial condition.
To begin, we rewrite the equation as:
\(\sqrt[4]{x^2+y^2}\) dy=7(x dx+y dy)
Now, we integrate both sides of the equation.
On the left-hand side, we substitute u = y and obtain:
\($\int \sqrt[4]{x^2+u^2} du=7 \int (x dx+u dy)$\)
Integrating the left-hand side requires a substitution.
We let v = \(x^2 + u^2\), and the integral becomes:
\($\frac{4}{5} v^{\frac{5}{4}} + C_1 = 7\left(\frac{x^2}{2} + uy\right) + C_2$\)
Simplifying and rearranging the terms, we have:
\($\frac{4}{5} v^{\frac{5}{4}} = 7\left(\frac{x^2}{2} + uy\right) + C$\)
Here, C is the constant of integration.
Next, we apply the initial condition x = 16 when y = 0.
Substituting these values into the equation, we get:
\($\frac{4}{5} (16^2 + 0^2)^{\frac{5}{4}} = 7\left(\frac{16^2}{2}\right) + C$\)
Simplifying further, we have:
\($\frac{4}{5} (256)^{\frac{5}{4}} = 7(128) + C$\)
Now, we can solve for C:
\($\frac{4}{5} (256)^{\frac{5}{4}} = 896 + C$\)
Finally, we can write the particular solution by substituting the value of C back into the equation:
\($\frac{4}{5} \sqrt[4]{256^2+y^2} = 896$\)
Therefore, the particular solution to the given differential equation that satisfies the condition x = 16 when y = 0 is \($\frac{4}{5} \sqrt[4]{256^2+y^2} = 896$\).
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The complete question is:
Find the particular solution to the given differential equation that satisfies the given conditions.
\($\sqrt[4]{x^2+y^2} d y=7(x d x+y d y)$\); x = 16 when y=0
The particular solution is (Type an equation).
Pls Help me I need the answer really fast A.S.A.P
Answer:
15 or 15.4!!!!!!!!!! I hope this helps
Answer:
15
Step-by-step explanation:
9.2 + 6.2 is 15.4
we are rounding to the nearest whole
15.4 goes to 15
compute the area enclosed by y = e^xy=e x , y = e^{−x}y=e −x , and y = 4.
The area enclosed by the curves can be found by integrating the difference between the upper and lower curves with respect to x within the given x-interval,
which is from -ln(4) to ln(4). To compute the area enclosed by the curves y = e^x, y = e^(-x), and y = 4, we need to find the x-values where these curves intersect.
Setting y = e^x and y = 4 equal to each other, we get:
e^x = 4
Taking the natural logarithm of both sides, we have:
x = ln(4)
Setting y = e^(-x) and y = 4 equal to each other, we get:
e^(-x) = 4
Taking the natural logarithm of both sides, we have:
-x = ln(4)
x = -ln(4)
The area enclosed by the curves can be found by integrating the difference between the upper and lower curves with respect to x within the given x-interval.
∫[ln(4), -ln(4)] (e^x - e^(-x) - 4) dx
Evaluating this integral will give us the area enclosed by the curves.
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Exercise 5<br />Part 1<br />Calculate by justifying the measurement of angles: CAD and CDA<br />B<br />45<br />432<br />35.35<br />Part 2<br />1) give the value of BD 92<br />2) show that AD = V50<br />3) show that AC = 50<br />3) calculate the exact value of CD<br />30<br />Part 3<br />Check that x is the difference between the perimeters of triangles ABC and ABD<br />Part 4<br />1) Give the exact value of the area of ABD then that of ACD<br />2) Complete with the exact value then approximate: area of ABD =<br />X area of ACD
what is the mean of the numbers??
If ST=17 and RT=41, find RS. Use the number line below.
The length of segment RS is given as follows:
RS = 24.
What does the angle addition postulate state?The angle addition postulate states that if two or more angles share a common vertex and a common angle, forming a combination, the measure of the larger angle will be given by the sum of the measures of each of the angles.
The segment RT is the combination of segments RS and ST, hence:
RT = RS + ST.
Hence the length of segment RS is given as follows:
41 = RS + 17
RS = 24.
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Solve the differential equation, such that the equation passes through the given point (x, y). (Remember to use absolute values where appropriate.) dy (1,16) dx x 11. [2.5/5 Points] DETAILS PREVIOUS ANSWERS LARCALCET7 5.7.046. MY NOTES ASK YOUR TEACHER Find the general solution of the differential equation (Remember to use absolute values where appropriate. Use C for the constant of integration.) sec?() tan(t) + 1 dr dt
The solution of the differential equation is given by y = (1/2) x²/11 + 359/22.
Given differential equation is dy/dx = x/11, and it should pass through (1, 16).We have to find the solution of the differential equation.
The given differential equation is,
dy/dx = x/11
Now, we will integrate both sides of the equation with respect to x. We will get\(,∫dy = ∫x/11dx\)On integrating, we get,
y = (1/2) x²/11 + C ------(1)
Where C is the constant of integration.
Now, the equation should pass through (1, 16).Hence, on substituting the value of x and y in equation (1), we get16
= (1/2) (1²)/11 + C16
= 1/22 + CC
= 359/22.
Therefore, the solution of the differential equation is
y = (1/2) x²/11 + 359/22.
Hence, we can write the answer as follows: The differential equation is given by dy/dx = x/11.
After solving the differential equation and using the given point (1,16), the solution of the differential equation is given by y = (1/2) x²/11 + 359/22.
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A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated from a sample of 49 apples randomly selected from a shipment indicated a mean weight of 122. 5 grams per apple. Calculate and interpret a 95% confidence interval for the mean weight per apple.
The average apple weight's 95% confidence interval is (119.14, 125.86).
According to one manufacturer, an apple weighs 120 grams on average with a 12-gram standard variation. According to statistics generated from a sample of 49 apples randomly selected from a shipment, the average weight per apple was 122. 5 grams.
Let,
n = 49
x = 122.5
σ = 12
To figure up and analyze a 95% confidence interval for the average apple weight;
The formula for a 95% confidence interval is
(x ± 1.96*σ√n)
(122.5 ± 1.96*12/√49)
(119.14, 125.86)
Consequently, a 95% confidence interval for the average apple weight is (119.14, 125.86).
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