two monkeys were swinging on vines together. One monkey got stuck hanging from a branch unable to move. the other monkey, who was very smart,knew that to move he needed to have a net force in the direction he wanted to go

Answers

Answer 1

Answer:

Hi, what is the question here?

Explanation:

Happy to help if I'm able to


Related Questions

How much current is drawn by a 30.0-W satellite dish that has a resistance of 480 Ω?

Answers

Answer:

Below

Explanation:

Power = I^2 R

 30.0 = i^2 * 480

30/480 = I^2

I = .25 Amps

The gradual change in a species over time is called
a.
mutation.
b.
evolution.
c.
migration.
d.
variation.
PLZ HURRY WILL GIVE BRAINLIEST

Answers

Answer: B. Evolution

Explanation:

As species grow older over time they will gradually evolve through natural selection and evolution.

The gradual change in a species over time is known as evolution (b).

The process of evolution occurs through several mechanisms, including mutation, migration, and natural selection.

Mutation (a) is the spontaneous change in the genetic material of an organism. These changes can result in new traits that may be advantageous, disadvantageous, or neutral for survival. When mutations occur, they can introduce genetic variation within a population, which serves as the raw material for evolution.

Natural selection is a crucial factor driving evolution. Individuals with advantageous traits that better suit their environment are more likely to survive and reproduce, passing on these advantageous traits to their offspring. Over generations, the frequency of beneficial traits increases in the population, leading to the adaptation and evolution of the species.

Variation (d) encompasses the differences in physical traits and genetic makeup among individuals within a population. This variation is essential for evolution to occur since it provides the raw material for natural selection to act upon.

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if you were to walk at a constant speed 20m/s for 30 seconds, how far would you walk?

Answers

Answer:

600m

Explanation:

30×20 at a constant speed is 600m.

The time period of a simple pendulum on a planet is 5 seconds and the effective length is 5 meters. How long should it be made to make 20 oscillation in 30 seconds?
(A) 1 m
(B) 0.90 m
(C) 0.45 m
(D) 2 m

Answers

The length of the pendulum that will make 20 oscillations in 30 seconds is approximately 14.26 meters. None of the given options (A, B, C, D) matches the calculated length.

To find the length of the pendulum that will make 20 oscillations in 30 seconds, we can use the formula:

Time period (T) = (2π√(L/g))

Given that the time period on the planet is 5 seconds and the effective length is 5 meters, we can substitute these values into the formula and solve for the acceleration due to gravity (g).

5 = (2π√(5/g))

Simplifying the equation, we get:

g = (4π^2)/25

Now, we can use this value of g along with the desired time period of 30 seconds and the formula to find the length (L) of the pendulum that will give us 20 oscillations.

30 = (2π√(L/((4π^2)/25)))

Simplifying the equation, we get:

L = ((4π^2)/25) * (30/2π)^2

L = ((4π^2)/25) * (15^2)

L = (4π^2)/25 * 225

L = (4π^2 * 9)/25

L = (36π^2)/25

Calculating this value, we find that L is approximately 14.26 meters.

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Position vs Time
Based on the information presented in the graph, what
is the velocity of the object?
15
m/s
12
Position (m)
3
0
1
2
3
4
5
Time (s)
) Intro
Done

Answers

Answer:

3

Explanation:

just did it

A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the
ground. How long will it take, in seconds, for the ball to hit the ground?

Answers

Answer:

0.73 s

Explanation:

The time taken can be found by using the formula

\( t = \frac{d}{v} \\ \)

d is the distance

v is the velocity

From the question we have

\(t = \frac{3.5}{4.8} \\ = 0.72916...\)

We have the final answer as

0.73 s

Hope this helps you

You have accepted a summer internship at NASA working on a proposed rover for the moon. Your group is tasked with evaluating a design for a device that will be housed inside of the rover. The device will be used for massing small rocks by measuring the rate of oscillation. You have to determine if the device can damage the housing The rover is designed to retrieve a rock from the surface of the moon and then place it into a nearly massless chamber connected to a spring. Once the rock is loaded in the chamber and positioned at the spring's equilibrium point, a small mallet strikes it and sets it in simple harmonic motion. The motion takes place on a horizontal plane with respect to the moon's ground. Depending on how the chamber oscillatos, you may determine the mass of the rock. The device's specifications are for a 200 gram rock, when struck, will move initially at 14 cm/s and execute simple harmonic motion with a frequency of 0.30 Hz.


Required:

a. Estimate the maximum kinetic energy of the chamber with a 200 gram rock.

b. Estimate the maximum acceleration of the chamber with a 200 gram rock.

c. Develop a representation of the motion for a 200 gram rock as a function in time, x(t).

d. Does this seem like a lot of force inside of the rover? Why or why not?

Answers

A. The estimated maximum kinetic energy of the chamber with a 200 gram rock is approximately 0.00196 Joules. B. the estimated maximum acceleration of the chamber with a 200 gram rock is approximately 1.131 m/s².

C. The representation of the motion for a 200 gram rock as a function of time is x(t) = 0.1 × cos(2π × 0.30 Hz × t). D. It does not seem like a lot of force inside the rover.

How did we get these values?

To evaluate the design and determine if the device can damage the housing, go through the required steps:

a. The maximum kinetic energy of the chamber can be calculated using the formula:

K_max = (1/2) × m × v²

where K_max is the maximum kinetic energy, m is the mass of the rock, and v is the velocity of the rock.

Given:

Mass of the rock (m) = 200 grams = 0.2 kg

Velocity of the rock (v) = 14 cm/s = 0.14 m/s

Using the formula, we can calculate:

K_max = (1/2) × 0.2 kg × (0.14 m/s)²

K_max ≈ 0.00196 Joules

Therefore, the estimated maximum kinetic energy of the chamber with a 200 gram rock is approximately 0.00196 Joules.

b. The maximum acceleration of the chamber can be determined using the formula:

a_max = ω² × A

where a_max is the maximum acceleration, ω is the angular frequency, and A is the amplitude of the oscillation.

Given:

Angular frequency (ω) = 2π × frequency

Frequency = 0.30 Hz

Using the formula, we have:

ω = 2π × 0.30 Hz

Now, let's assume the amplitude of the oscillation is A = 0.1 meters.

a_max = (2π × 0.30 Hz)² × 0.1 meters

a_max ≈ 1.131 m/s²

Therefore, the estimated maximum acceleration of the chamber with a 200 gram rock is approximately 1.131 m/s².

c. The motion of the rock in simple harmonic motion can be described by the equation:

x(t) = A × cos(ω × t)

where x(t) represents the displacement of the rock at time t, A is the amplitude, ω is the angular frequency.

Using the values from earlier:

Amplitude (A) = 0.1 meters

Angular frequency (ω) = 2π × 0.30 Hz

The representation of the motion for a 200 gram rock as a function of time is:

x(t) = 0.1 × cos(2π × 0.30 Hz × t)

d. Based on the given information, the maximum kinetic energy of the chamber with a 200 gram rock is approximately 0.00196 Joules. This is a relatively small amount of energy.

The maximum acceleration of the chamber with a 200 gram rock is approximately 1.131 m/s². This acceleration is also relatively small.

Considering these values, it does not seem like a lot of force inside the rover. The energy and acceleration involved are relatively low, suggesting that the device should not cause significant damage to the housing. However, it is always essential to ensure that the design and materials used in the housing can withstand the expected forces and vibrations to ensure the rover's durability and functionality.

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A long distance runner running a 5.0km track is pacing himself by running 4.5km at 9.0km/h and the rest at 12.5km/h. What is his average speed?

Answers

Answer:

9.26 km/h

Explanation:

Applying,

V' = D'/t'............... Equation 1

Where V' = Average speed, D' = Total distance, t' = total time.

Given: D' = 5 km

But,

v = d/t............ Equation 2

Where v = speed , d = distance, t = time

t = d/v............ Equation 3

Given: d = 4.5 km, v = 9 km/h, and d = 0.5 km, v = 12.5 km/h

Therefore,

t₁ = 4.5/9 = 0.5 hours

t₂ = 0.5/12.5

t₂ = 0.04 hours

Therefore,

V' = 5/(0.5+0.04)

V' = 5/0.54

V' = 9.26 km/h

"Radioactive decay is a random process but we can still make predictions about it" Explain this statement​

Answers

Answer:

Radioactive decay is determined by quantum mechanics — which is inherently probabilistic. So it's impossible to work out when any particular atom will decay, but we can make predictions based on the statistical behaviour of large numbers of atoms.

pls mark me brainliest

There is no ability to make a specific prediction on the decay of a certain atom. However, when referring to gathered data from a wider perspective of a larger quantity of atoms, we can conjure predictions from typical atomic actions.

If the moon crosses in front of the sun while the moon is at apogee,
A.a total solar eclipse is seen everywhere on Earth.
B.a total solar eclipse is seen in the umbra portion of the moon's shadow.
C.a partial eclipse is seen in the umbra portion of the moon's shadow.
D.no eclipse occurs.
E.an annular eclipse occurs.

Answers

If the moon crosses in front of the sun while the moon is at apogee, a partial eclipse is seen in the umbra portion of the moon's shadow. The correct option is C.

When the moon crosses in front of the sun, it can create various types of solar eclipses depending on the alignment of the Earth, moon, and sun. In this scenario, where the moon is at apogee (farthest from Earth) during the eclipse, the following events occur:

1. The moon's position at apogee means that it is relatively far from Earth. As a result, the moon appears smaller in the sky compared to the sun.

2. During the eclipse, the moon passes directly in front of the sun, blocking a portion of its light.

3. The shadow cast by the moon consists of two parts: the umbra, which is the central region of complete shadow, and the penumbra, which is the outer region of partial shadow.

4. Since the moon is at apogee, its smaller size results in the umbra of the moon's shadow not reaching the Earth's surface completely. Instead, the umbra only covers a portion of the Earth, creating a partial eclipse in the umbra region.

5. Observers located within the umbra portion of the moon's shadow will experience a partial solar eclipse, where the moon covers a part of the sun, but not its entire disk.

Therefore, if the moon crosses in front of the sun while it is at apogee, a partial eclipse is seen in the umbra portion of the moon's shadow, as the moon's smaller size does not allow for a total solar eclipse to occur. Option C is the correct answer.

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how do animal weather rocks

Answers

Answer:

Burrowing animals can cause weathering. By digging for food or making space to live in the animal may break apart rock. The growing roots of a tree can also break apart rock.

Animals weather rocks depending on the rocks temperature, if it’s cool then it’s cold and if it warm it’s hot.

space shuttle travels at 17,500 mph if venus is 25 million miles from earth,how many hours will it take shuttle to get to venus

Answers

It will take approximately 1,428.57 hours, or about 59.5 days, for the space shuttle to travel from Earth to Venus

To calculate the time it takes for the space shuttle to travel from Earth to Venus:

Time = Distance / Speed

Where distance is the distance between Earth and Venus, and speed is the speed of the space shuttle.

Plugging in the given values, we get:

Time = 25,000,000 miles / 17,500 miles per hour

Simplifying the equation, we get:

Time = 1,428.57 hours

Therefore, it will take approximately 1,428.57 hours, or about 59.5 days, for the space shuttle to travel from Earth to Venus at a speed of 17,500 miles per hour.

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1. Hearing is also known as
?

Answers

I’m not sure what your quite asking for, but some people say auditory perception instead of hearing

the combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, what source strength is required to simulate flow around the body?

Answers

The combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, The source strength is required to simulate flow around the body is (m)= 94.2 kg.

What is force?

Force is a physical appearance that happen on a object of some amount of masses and then it changes it form and move a bit that called the force. It is a vector quantity. It can be measured in Newton, Dyne.

How can we calculate the source strength is required to simulate flow around the body?

To calculate the source strength is required to simulate flow around the body we are using the formula here is,

v= m/2*π*b

Or, m= 2*π*b*v

Here we are given,

b=  The thickness of a certain body has the shape of a half-body = 2*r = 2* 0.5 = 1 m

v = The velocity of the object. = 15 m/s.

We have to calculate the values of the source strength is required to simulate flow around the body = m kg

Now we put the values in above equation we get,

m= 2*π*b*v

Or, m= 2*π*1*15

Or, m= 94.2 kg

so we can say that , The source strength is required to simulate flow around the body is (m)= 94.2 kg

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Two blocks, of mass m and 2m, are initially at rest on a horizontal frictionless surface. A force F is exerted individually on each block, as shown above. The graph shows how F varies with time t. Which block has the greatest average power provided to it between t = 0 s and t = 3 s?

Answers

The block has the greatest average power provided is bock m.

What is instantaneous power?This is the product of force and velocity exerted on an object.

Mathematically instantaneous power is calculated as;

P = Fv

where;

F is the applied forcev is the velocity

Both blocks (m and 2m) will experience the same force but different velocity.

The smaller block (m) will experience greater velocity.

Thus, the block has the greatest average power provided is bock m.

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WILL GIVE BRAINLEST How far will a cheetah travel if it runs at 30 m/s for 60s?

Group of answer choices

2 m

1800 m

60 m

5 m

Answers

Answer:

2m

Explanation:

An incident ray that passes through the vertex of a convex lens:
F
F
c
A. refracts inward, at an angle equal to the angle of incidence,
B. continues in a straight line without refracting.
C. refracts parallel to the axis of the lens,
D. refracts outward, at an angle equal to the angle of incidence.

Answers

the answer is refracts parallel to the axis of the lens

Correctly label the following anatomical features of the semicircular ducts. Cupula Supporting tells Vestibular braneh CN Hair cells Crista ampullaris BEDRE Endolymph

Answers

Cupula: The cupula is a gelatinous structure that is attached to the sensory hair cells in the semicircular ducts.
Supporting tells: The supporting tells are the structures that support and anchor the cupula in the semicircular ducts.
Vestibular braneh: The vestibular branch is a branch of the vestibulocochlear nerve (CN VIII) that carries sensory information from the semicircular ducts to the brain.
CN: CN stands for cranial nerve, which is a group of nerves that originate in the brain and innervate various parts of the head and neck. In this context, CN VIII refers to the vestibulocochlear nerve.
Hair cells: Hair cells are sensory cells that are located in the semicircular ducts and are responsible for detecting changes in angular acceleration.
Crista ampullaris: The crista ampullaris is a ridge of sensory hair cells that is located in the ampulla of the semicircular ducts.
BEDRE: It is not clear what "BEDRE" refers to in this context. Please provide more context or clarify the term.
Endolymph: Endolymph is a fluid that is found within the inner ear and is responsible for transmitting sound and movement information to the brain. It is located within the semicircular ducts and other parts of the inner ear.

Predict how long it would take for an object to travel 5 m, if it is traveling at an average velocity of 2 m/s.

Answers

Answer:

-24650580. maybe I think

At 13:20 on the last Friday in September, 1989 a frantic call was received at the local police station. There had been a serious automobile accident at the intersection of Main Street and State Street with injuries involved. Lt. John Henry arrived at the scene ten minutes after the phone call and found that two cars had collided at the intersection. In one car, the driver was unconscious and in the other car, both the driver and one passenger were injured.
After the emergency vehicles transported the injured to the hospital, Lt. Henry's responsibility is to investigate the accident in order to determine whether one of the drivers (or both) are responsible. With the severity of injury in this accident, the investigation is critical because there may be a fatality involved.

1. What questions does John Henry have to answer in this investigation? What measurements does he need to take? What data should he collect? What other information does he need to record in order to aid the investigation? What physics principles will John Henry need to use in order to help analyze the data and answer his questions?
2. If two cars moving at right angles to each other collide, in what direction do you expect the cars to be moving after the collision?
3. What factors will influence the direction and distance traveled after impact?

Answers

The kinematics and conservation of momentum relationships allow to find the results for the questions about the measurements and conditions to know the accident conditions are:

     1) The principles of conservation of momentum  and kinematics.

     2)  \(\theta = tan^{-1} \frac{P_{01}}{p_{02}}\)

     3) The factors that influence the direction and distance traveled are:

         The initial speed of the vehicles

         The mass of the vehicles

         Pavement conditions: dry, wet, humid, with dirt or loose sand.

1) Kinematics studies the movement of bodies, they look for relationships between position, speed and acceleration.

To analyze the accident, you must answer a question such as what speed the vehicles had before the accident, this is the initial speed of each one and their directions.

When reviewing the kinematics relationships we have.

        \(v^2 = v_o^2 - 2 a x\)  

Where the acceleration is given by Newton's second law.

        fr = m a

The friction force is given by the expression.

       fr = μ N  

       fr = μ mg

       

Let's Substitute.

         μ m g = m a

         a = μ g

The friction coefficient is tabulated, for different types of rubber, pavement and wet,  dry conditions, etc.

Therefore, the researcher must measure the braking distance of the vehicles, which can be taken from the mark of the tires on the road and note the condition of the pavement if it is dry or wet and the visibility of the day.

This is the speed of the vehicles just after the impact, using the law of conservation of momentum you can find the speed of the vehicles before the impact

        \(p_o = p_f\) \f

         

Where this is a vector expression, which in general is solved with the components of each directional.

Consequently to answer the questions you must use the principles of conservation of momentum  and kinematics.

2) If the vehicles travel at right angles and their masses are similar, the direction after the collision  in each direction.

           \(tan \theta = \frac{p_{01}}{p_{02}}\)  

           \(\theta = tan ^{-1} \frac{p_{01}}{p_{02}}\)  

3) The factors that influence the direction and distance traveled are:

     The initial speed of the vehicles

     The mass of the vehicles

     Pavement conditions: dry, wet, humid, with dirt or loose sand.

In conclusion, using the kinematics and conservation of momentum relationships, we can find the answers to the question about measurements and conditions to know the accident conditions are:

      1) The principles of conservation of momentum  and kinematics.

     2)  \(\theta = tan^{-1} \frac{P_{01}}{p_{02}}\)

     3) The factors that influence the direction and distance traveled are:

         The initial speed of the vehicles

         The mass of the vehicles

         Pavement conditions: dry, wet, humid, with dirt or loose sand.

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say something random cuz i already answered my own question

Answers

Answer:

The experimental setup, with car 1 is at the top of a ramp and car 2 at the bottom of the ramp  is explained below in details.

Explanation:

The meter pole should be located at the opening location of car second at the bottom of the ramp so that it regulates the portion of car second that will finish up the most distant away from the bottom of the ramp.

So, I think now you got your answer which is absolutely correct and it will help you.

Answer:

hello my good friend

Explanation:

E. O 1.318 m/s²6. An object of mass 32 kg is being pulled on a friction lesshorizontal surface by means of two strings. One of the stringsis pulling forward, has a tension of 120 N and makesan angle of 30 degree with the horizontal-right. The other string ispulling backwards horizontally and has a tension of 10 N.Calculate the acceleration of the object. (1 point)A. 02.935 m/s²B.O2.506m/s2C. 05.172 m/sD. 03.816 m/s ²E. O4.308 m/s²

E. O 1.318 m/s6. An object of mass 32 kg is being pulled on a friction lesshorizontal surface by means

Answers

We first determine the total force ni he horizontal axis, that is:

\(\sum F_x=120cos(30)N-10N\Rightarrow\sum F_x=(60\sqrt{3}-10)N\)

Now, we determine the acceleration:

\(\begin{gathered} (60\sqrt{3}-10)N=(32kg)a\Rightarrow a=\frac{(60\sqrt{3}-10)N}{32kg} \\ \\ \Rightarrow a=\frac{30\sqrt{3}-5}{16}m/s^2\Rightarrow a\approx2.935m/s^2 \end{gathered}\)

So, the acceleration is approximately 2.935 m/s^2.

TRUE or FALSE: Most Electromagnetic waves are blocked by the atmosphere.
True
False

Answers

True because the atmosphere is in the way

The apple is on the tree and it is not moving. What are the two types of forces acting
on the apple?

Answers

Answer:

An apple hanging on a tree is acted upon by two basic forces: 1) the downward force exerted by the gravity force and, 2) the upward force exerted by the tree limb. The downward gravity force is also know as "weight".

The two types of forces acting on the apple on the tree are gravitational force and pressure by the wind. The gravitational force acting on it experiences as its own weight.

What is force?

Force is an external agent acting on a body to change its motion or to deform it. There are various kinds of force such as gravitational force, magnetic force, nuclear force etc.

Gravitational force is the force by which an object attracts other object into its center of mass. Earth gravitationally pull all objects in its surface to the ground.

The apple on the tree will experience a force of gravitation by the earth as well as the force exerted by the air currents passing through the region.

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Approximately how long does it take the uterus lining to build up again after menstruation

Answers

The uterus lining is rebuilt by the end of the menstrual period. The rebuilding of the uterus lining starts after menstruation and the lining is typically completely rebuilt by day 14 of the menstrual cycle, which is when ovulation occurs and the uterus is preparing to potentially receive a fertilized egg.

The endometrium is the inner lining of the uterus, and it thickens every month to prepare for pregnancy. After menstruation, the endometrium grows and thickens to prepare for the implantation of a fertilized egg. The cells in the lining multiply and enlarge, and the glands in the lining begin to secrete mucus and other substances that help support the fertilized egg and promote its growth.

The rebuilding of the endometrium usually takes about two weeks after menstruation. This process is closely regulated by hormones such as estrogen and progesterone, which are produced by the ovaries and other parts of the body. These hormones help control the growth and development of the endometrium and other reproductive tissues.

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(I) A centrifuge accelerates uniformly from rest to 15,000 rpm in 240 s. Through how many revolutions did it turn in this time

Answers

Answer:

θ = ω0 t + 1/2 ω t^2 = 1/2 α t^2          since it starts from rest

α = (15000 / 60) / 240 = 250 / 240 = 1.04 rev/sec^2

Note that α is in rev/sec^2

T(otal)  = 1/2 * 1.04 * 240^2 = 30,000 revolutions

Check:

Average RPM = (15000/2) = 7500 rev/min = 125 / sec

125 / sec * 240 sec = 30,000 rev

A sample of 6.90 g of solid calcium hydroxide is added to 37.5 mL of 0.440 M aqueous hydrochloric acid. Write the balanced chemical equation for the reaction. Physical states are optional.

Answers

Balanced chemical equation is : Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

The balanced chemical equation represents the reaction between solid calcium hydroxide (Ca(OH)₂) and aqueous hydrochloric acid (HCl). The equation shows that one mole of calcium hydroxide reacts with two moles of hydrochloric acid to produce one mole of calcium chloride (CaCl₂) and two moles of water (H₂O).

In the equation, the subscripts indicate the number of atoms present in each molecule. Calcium hydroxide consists of one calcium (Ca) atom, two oxygen (O) atoms, and two hydrogen (H) atoms. Hydrochloric acid contains one hydrogen (H) atom and one chlorine (Cl) atom. Calcium chloride is composed of one calcium (Ca) atom and two chlorine (Cl) atoms. Water consists of two hydrogen (H) atoms and one oxygen (O) atom.

The coefficients in the balanced equation indicate the relative amounts of each compound involved in the reaction. In this case, one mole of calcium hydroxide reacts with two moles of hydrochloric acid to produce one mole of calcium chloride and two moles of water.

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If his arms are capable of exerting a force of 1800 N on the vine, what is the maximum speed he can tolerate at the lowest point of his swing

Answers

The maximum speed that the person can tolerate at the lowest point of their swing is approximately 0.627 m/s.

To determine the maximum speed a person can tolerate at the lowest point of their swing, we need to consider the forces acting on them. At the lowest point, the person experiences two forces: the tension in the vine and the person's weight. The tension in the vine provides the centripetal force required for circular motion, while the person's weight acts downward.

First, we calculate the tension in the vine using the centripetal force equation: \(Fc = mv^2/r\), where Fc is the centripetal force, m is the mass, v is the velocity, and r is the radius (half the length of the vine). Rearranging the equation, we have\(v = \sqrt(Fc * r / m)\).

Substituting the given values, the centripetal force (Fc) is 1800 N, the radius (r) is 7.0 mm (converted to meters, 0.007 m), and the mass (m) is 90 kg. Calculating the velocity (v), we find \(v = \sqrt(1800 * 0.007 / 90) = 0.627 m/s.\)

Therefore, the maximum speed that the person can tolerate at the lowest point of their swing is approximately 0.627 m/s.

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The complete question is:

If his arms are capable of exerting a force of 1800 N on the vine, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 90 kg, and the vine is 7.0 mm long.

define the relationship between the ecg and the pulse wave. explain why the timing of the qrs complex in the ecg and the start of the pulse wave do not coincide.

Answers

The ECG (electrocardiogram) records the electrical activity of the heart, while the pulse wave is the physical manifestation of this activity that can be felt at the wrist or neck.

The timing of the QRS complex in the ECG and the start of the pulse wave do not coincide because the electrical activity propagates through the heart before the mechanical contraction of the heart muscle.

The QRS complex in the ECG corresponds to the depolarization of the ventricles, which is the electrical signal that triggers the mechanical contraction of the heart muscle.

The ECG records the electrical activity of the heart, which is faster than the mechanical contraction of the heart muscle. The pulse wave is the physical manifestation of the mechanical contraction of the heart muscle, which can be felt at the wrist or neck.

The pulse wave travels through the blood vessels to the surface of the skin, which takes some time. Therefore, the timing of the QRS complex in the ECG, which represents the electrical activity, and the start of the pulse wave, which represents the mechanical contraction, do not coincide.

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For a skateboard with a negative acceleration, which of the following statements is always true?

1. The initial velocity of the skateboard will be greater than it’s final velocity.
2. The skateboard will have a negative displacement.
3. The final velocity of the skateboard will be positive.
4. The final velocity of the skateboard will be negative
5. The skateboard is losing speed

Answers

With a negative acceleration, the skateboard's beginning velocity will be higher than its end velocity.

The correcty answer is 1

How do you calculate beginning velocity in the absence of time?

Based on the assumption that the object's energy is conserved, its velocity equals the square root of twice square product of the its acceleration or the distance it travels. This relationship also depends on the object's initial velocity.

What are starting and final velocities?

When gravity first exerts force on an object, its initial velocity indicates how quickly it moves. The final velocity, on the other hand, is a vector quantity that determines the rate and direction of the a moving body when it has reached its maximum velocity.

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