Answer:
Kinetic energy and velocity are at zero when the magnets are held apart, and both increase rapidly when they are released and move together. Energy stored in the magnetic field decreases.
Explanation:
easy
The increase in the kinetic energy occurs when both magnets are released.
Change in energy occurs between two magnets
The kinetic energy and velocity are at zero when the magnets are held apart from one another at a certain distance but the kinetic energy increases when they are released and move together so we can conclude that the increase in the kinetic energy occurs when both magnets are released.
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A plane is flying horizontally with speed 171 m/s at a height 6520 m above the ground, when a package is dropped from the plane. The acceleration of gravity is 9.8 m/s 2 . Neglecting air resistance, when the package hits the ground, the plane will be 1. directly above the package. 2. ahead of the package. 3. behind the package.
Answer:
2. Ahead of the package
Explanation:
The plane is going straight without stopping while the package is going straight down.
why does a bowling ball and a father fall at the same speed while in a vacuum?
PLZ NEED HELP
Answer:
there is no drag in a vacuum (why is father in a vaccum)
Explanation:
there is nothing to hit and slow the object other than gravity like dust or air
A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 32. 6◦C. In an attempt to cool the liquid, which has a mass of 176 g, 135 g of ice at 0. 0◦C is added. At the time at which the temperature of the tea is 28. 4 ◦C, find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg ◦ C. Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g
The mass of the remaining ice in the jar is 79.6 g.
What is the mass of the remaining ice in grams?to calculate the mass in grams we need to know when the tea reaches an equilibrium temperature of 32.6°C, it means that the heat gained by the tea from the sunlight is equal to the heat lost by the tea to the surroundings.
Let's denote the initial temperature of the tea as T1 and the final temperature as T2. The heat gained or lost by an object can be calculated using the equation Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the tea has a mass of 176 g and the specific heat capacity of water is 4186 J/kg°C. The heat gained by the tea is equal to the heat lost by the ice. The mass of the ice is 135 g, and its temperature is 0.0°C. The final temperature of the tea is 28.4°C.
To find the mass of the remaining ice, we can set up the equation: (mass of tea) * (specific heat capacity of water) * (ΔT of tea) = (mass of ice) * (specific heat capacity of water) * (ΔT of ice). Plugging in the given values, we can solve for the mass of the remaining ice. The mass of the remaining ice in the jar is 79.6 g.
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40 POINTSS. Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fingertip. Note how much opposition to your push you feel. Repeat the steps, but this time push the piece of plastic or wood across a rug, carpet, or piece of fabric. If you’re using fabric, be sure to secure the fabric so it doesn’t move. How does the opposition to motion on the tabletop compare with that of the rug, carpet, or fabric? WILL MARK BRAINLIST IF RIGHT
Answer: If there is a higher friction, the opposition force is higher so that it can reduce our speed. So, a factor that affects friction is the roughness or smoothness of the surface of the object. In comparison of the table with the fabric, the fabric will have a more opposition force. As the surface of the fabric is usually rougher than the surface of a smooth table. As there is more friction on a fabric, we will feel more opposition force on our finger tip.
An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object
Answer:
\(\boxed {\boxed {\sf a=42.8 \ m/s^2}}\)
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
\(a=\frac{v-u}{t}\) (v is the final velocity, u is the initial velocity, t is the time).
The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:
\(v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s\)
Substitute the values into the formula.
\(a=\frac{236 \ m/s - 22 \ m/s}{5 \ s}\)
Subtract in the numerator.
236 m/s-22 m/s=214 m/s\(a=\frac{214 \ m/s}{5 \ s}\)
Divide.
\(a=42.8 \ m/s^2\)
The acceleration of the object is 42.8 meters per square second.
I need help with this can anybody help me
Explanation:
The problem here deals with relative dating of fossils in a stratigraphic column.
To solve this problem, we apply one of the rules of interpreting a session which is the principle of fossil and fauna succession:
"fossils and fauna in a geologic sequence succeed one another in a predictable way".
The oldest fossil is found in the oldest bed usually at the bottom of the sequence.
The youngest fossil is found at the top of the beds.
1. Oldest organism in the sequence;
Trilobite
2. Organism in the youngest layer;
Fern
3. Older organism between Crinoid and Ammonite;
Ammonite
The ammonite is below the crinoid in the sequence.
HELP If a skater has a mass of 55 kg and the maximum height the skater can reach is 10 m, then what will be the velocity of the skater if they skate down to a height of 5 m?
please if someone could explain this to me, that'd be appreciated :)
Hello, for this applicate formula:
Vf² = Vo² + 2gh
Data:
Vf = Final Velocity = ¿?
Vo = Initial veloctiy = 0 m/s
g = Gravity = 9,81 m/s²
h = Height = 5 m
Replacing according our data:
Vf² = 0 m/s² + 2(9,81 m/s²)(5 m)
Vf² = 98,1 m²/s²
Vf = √98,1 m²/s²
Vf = 9,9 m/s
The final velocity will be 9,9 meters per second.
The answer is 9.9 m/s
The image produced by a concave lens is always virtual. Is this true or false?
calculating magnitude of a resultant vector two forces of 19.8 pounds and 36.5 pounds act on a body with an angle of 61.4 degrees between them. on a coordinate plane, a vector on the x-axis is labeled 19.8 pounds. a vector labeled 36.5 pounds forms angle 61.4 degrees with the x-axis. choose the correct approximation for the magnitude of the resultant vector. 45.5 pounds 21.3 pounds 49.2 pounds 2416.2 pounds
The magnitude of the resultant vector of two forces of 19.8 pounds and 36.5 pounds act on a body is 49.2 pounds that is option C.
The resulting value of two or more vectors can be calculated using the resultant vector formula. By calculating the vectors based on their respective orientations to one another, this is achieved. The resultant vector formula has several uses in engineering and science. This is illustrated via the interaction of many force vectors on a body, where the resulting vector is calculated using this formula.
Depending on the orientation of the vectors, there are three different types of resulting vector formulas. These equations apply to vectors moving in the same direction, vectors moving in the opposite direction, and vectors moving at an angle to one another.
We have two forces as 19.8 pounds and 36.5 pounds
by using the resultant formula we have,
R² = f1² + f2² + 2(f1)(f2)cos(θ)
R² = 19.8² + 36.5² + 2(19.8 x 36.5) cos(61.4)
= 1724.29 + 1445.4 x 0.478
= 1724.29 + 691.9
= 2416.2
R = \(\sqrt{2416.2}\)
R = 49.2 pounds.
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Which substances are inorganic? Check all that apply.
C6H12O6
K2CO3
C4H10
C27H46O
Fe3O4
The major characteristic an organic compound has which an inorganic
compound doesn't have is the presence of carbon atoms in the molecule.
This helps us to differentiate the compounds into their respective divisions.
Inorganic compounds
K2CO3Fe3O4Organic compounds
C6H12O6C4H10C27H46OWe can observe that inorganic compounds lack carbon atoms which makes
the answer valid.
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Answer:
B and E because yk thats the asnwer
expert answer 1 month ago a) determine the distance of the spectrum. write the equation for the diffraction grating for the sodium and substitute the required values to determine the initial angular position of the sodium spectrum of the first order. write the equation for the diffraction grating for the sodium and substitute the required values to determine the final angular position of the sodium spectrum of the first order. determine the angular separation of both closely spaced yellow lines of sodium of the first order. -- b) write the equation for the diffraction grating for the sodium and substitute the required values to determine the initial angular position of the sodium spectrum of the second order. write the equation for the diffraction grating for the sodium and substitute the required values to determine the final angular position of the sodium spectrum of the second order. determine the angular separation of both closely spaced yellow lines of sodium of the second order. -- c) write the equation for the diffraction grating for the sodium and substitute the required values to determine the initial angular position of the sodium spectrum of the third order. write the equation for the diffraction grating for the sodium and substitute the required values to determine the final angular position of the sodium spectrum of the third order. determine the angular separation of both closely spaced yellow lines of sodium of the third order. like 0 the
Where θ 1 is the angle of the first line, and θ 2 is the angle of the second line.
What is angle?Angle is the measure of a turn or displacement between two intersecting lines. Angles are typically measured in degrees, with 360 degrees in a full circle. acute angles are smaller than 90 degrees, while obtuse angles are larger than 90 degrees. Straight angles are exactly 180 degrees, while reflex angles are greater than 180 degrees.
The equation for the diffraction grating for the sodium is:
nλ = d sinθ
Where n is the order of the spectrum, λ is the wavelength of the light, d is the distance of the spectrum, and θ is the angle of the light.
For the first order, the initial angular position is:
nλ = d sinθ
θ = sin-1 (λ/d)
For the first order, the final angular position is:
nλ = d sinθ
θ = sin-1 (λ/d)
The angular separation of the two closely spaced yellow lines of sodium is:
Δθ = θ 1 - θ 2
Where θ 1 is the angle of the first line, and θ 2 is the angle of the second line.
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Three resistors connected in parallel have individual values of 4.0, 6.0 and 10.0 Ohms respectively. This combination is connected in series with a 12.0 V battery and a 2.0-Ohm resistor.
(a) What is the current in the 10-Ohm resistor?
(b) What is the voltage on the 2-Ohm resistor?
(a) The current in the 10-Ohm resistor is 1.6 A.
(b) The voltage on the 2-Ohm resistor is 19.2 V.
To solve this question, the total resistance of the circuit must be calculated first. Using the formula for resistors in parallel, the total resistance of the circuit is 1.6 Ohms.
To calculate the current, Ohm's law (I=V/R) can be used. The total current is then found to be 12.0/1.6 = 7.5 A. To calculate the current in the 10-Ohm resistor, the current in the other two resistors must be calculated first. Using Ohm's Law, the current in the 4-Ohm and 6-Ohm resistors are found to be 4.0 and 6.0 A, respectively.
Therefore, the current in the 10-Ohm resistor is the total current minus the current in the other two resistors;
7.5 - 4.0 - 6.0 = 1.6 A.
To calculate the voltage on the 2-Ohm resistor, the voltage drop across each resistor in the circuit must be calculated first.
Using Ohm's Law, the voltage drop across the 4-Ohm and 6-Ohm resistors are found to be 16.0 and 36.0 V, respectively. Therefore, the voltage on the 2-Ohm resistor is the total voltage minus the voltage drop across the other two resistors;12.0 - 16.0 - 36.0 = 19.2 V.
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Electricity consumption in the United States totaled about ____________ kilowatthours (kWh) in 2015.
Answer:
3,900
Explanation:
G= 10m/s
A 50kg student jumps out of a window onto a pile of mattresses.
(a) Ignoring air resistance, what is her increase in speed each second?
B) What is her change of momentum each second?
The increase in velocity of the student per second is 10 m/s^2 and her change in momentum each second is 500 kgm/s^2.
What is the change in velocity per second for any object falling freely under gravity?The change in velocity of a moving object is known as acceleration.
For any object falling freely under gravity, the change in velocity per second or acceleration due to gravity is a constant and is equal to 10 metres per square second (10 m/s^2).
The change in momentum of a body is given as follows:
Momentum = mass × velocity Change in momentum = mv - muChange in momentum = m(v - u)acceleration = v - uwhere m is mass, v is final velocity and u is final velocity.
Mass of the student = 50 Kg
Change in momentum each second = 50 kg × 10 m/s^2 = 500 kgm/s^2
Therefore, the increase in velocity of the student per second is 10 m/s^2 and her change in momentum each second is 500 kgm/s^2.
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20. Q: How long will it take for an apple falling from a 29.4m-tall tree to hit the ground?
A: 1.56 s
B: 2.04 s
C: 2.45 s
D: 3.72 s
Answer:
2.45s
Explanation:
is explanation needed too?
À partir de tes connaissances et en utilisant les documents ci-dessous explique pourquoi réparer un interrupteur ou changer un prix électrique à la maison sont des gestes très dangereux rédiger un compte rendu en détaillant les étapes de ton raisonnement
Answer:
solo se que la respuesta esExplanation:
rosa melano!¡A skateboarder is skating along a level concrete path. Every so often, to keep himself going, he uses his foot to give himself a push. Discuss why the skateboarder needs to regularly push with a foot when skateboarding along a level surface.
In your answer, you should:
- describe the motion of the skateboarder during a push and between pushes
- identify the forces in action and explain whether they are balanced or unbalanced
- link the net force to the motion of the skateboarder.
The skateboarder needs to regularly push with their foot when skateboarding along a level surface because of the presence of frictional forces that oppose motion. When the skateboarder gives themselves a push, they increase their forward velocity.
The skateboarder needs to regularly push with their foot when skateboarding along a level surface because of the presence of frictional forces that oppose motion. When the skateboarder gives themselves a push, they increase their forward velocity. However, over time, the velocity decreases due to the force of friction between the skateboard's wheels and the ground, which acts in the opposite direction to the skateboard's motion. During a push, the skateboarder exerts a force on the skateboard that propels it forward. Between pushes, the skateboard moves at a constant velocity due to the balanced forces acting upon it. However, as frictional forces act on the skateboard, it slows down until the next push is required. The net force acting on the skateboarder is unbalanced, as the force of friction acting against the skateboard's motion is greater than the force of the skateboarder's push. The resulting net force causes the skateboarder to slow down over time. Thus, by pushing themselves, the skateboarder overcomes the force of friction and maintains their forward motion.
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A conjugate beam is drawn so that its and correspond to the slope and deflection of the real beam.
We can use the conjugate beam to determine the bending moment and shear force at any point along the real beam by calculating the corresponding bending moment and shear force in the conjugate beam.
A conjugate beam is an imaginary beam having similar properties to that of an actual beam. The conjugate beam theory is a significant tool for finding out the slope and deflection of a beam with the help of energy method or unit load method.
The conjugate beam is drawn so that its shear force and bending moment correspond to the slope and deflection of the real beam respectively. Additionally, the loads are reversed in the conjugate beam.
For example, if the real beam is subjected to a point load, the conjugate beam will have a moment at the same point instead of a concentrated load.
Therefore, we can use the conjugate beam to determine the bending moment and shear force at any point along the real beam by calculating the corresponding bending moment and shear force in the conjugate beam.
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how does loudness relate to the unit decibel? how does loudness relate to the unit decibel? the decibel is a unit of measurement of sound frequency. perceived loudness is determined by sound frequency and sound wavelength. the decibel is a unit of measurement of sound intensity. perceived loudness is determined completely by sound intensity. the decibel is a unit of measurement of sound intensity. perceived loudness depends on sound intensity and sound frequency. the decibel is a unit of measurement of sound frequency. perceived loudness depends on sound intensity and sound frequency.
The unit of measurement for loudness is the decibel (dB). Loudness is directly related to the intensity of sound, which is measured in decibels.
The higher the decibel level, the louder the sound. However, loudness is not solely determined by sound intensity. It also depends on the frequency and wavelength of the sound. Therefore, a sound with a higher decibel level may not necessarily be perceived as louder if its frequency is outside the range of human hearing. In summary, loudness is related to the unit decibel, which measures sound intensity, but also depends on the frequency and wavelength of the sound.
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Can you take your phone in a tanning bed?
No, you cannot take your phone in a tanning bed. Tanning beds use ultraviolet (UV) light to help people achieve a dark, even tan. However, this light can damage electronic devices, such as cell phones.
The heat generated by the bulbs and the strong UV radiation can damage the phone’s internal components and cause the phone to overheat. This can lead to short circuits and permanent damage to the phone.
In addition to the damage caused by UV light, the high temperatures of the tanning bed may cause the phone to overheat, leading to further damage, such as battery failure. Overheating may also cause the phone to shut down or restart unexpectedly, resulting in data loss and further damage.
Finally, taking your phone into a tanning bed may be a distraction. Tanning beds require the user to remain still and relaxed in order to achieve optimal results. Having your phone in the bed may disrupt this process and lead to a less effective tanning session.
For all of these reasons, it is not recommended to take your phone into a tanning bed. Doing so may cause irreparable damage to the device and may disrupt the tanning process.
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Nfpa 70e, standard for electrical safety in the workplace, consists of ? chapters; 18 informative annexes; the foreword to nfpa 70e; and article 90, introduction. chapter 1 is divided into ? articles.
NFPA 70e consist of 3 chapters and the chapter 1 is divided into 5 articles.
What is NFPA?The National Fire Protection Association is abbreviated as NFPA (NFPA). It has three chapters and seventeen annexes that contain standard electrical safety guidelines.
The NFPA 70E code covers safety management systems, equipment maintenance, and more specific requirements for specific equipment.
The goal of NFPA 70E®, Standard for Electrical Safety in the Workplace®, is to provide employees with a safe working environment free of unacceptable risk associated with the use of electricity in the workplace.
The first chapter of NFPA 70E discusses the parameters of an electrical safety program, whether used alone or as part of a comprehensive safety management system.
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35.On a cold winter day the sections of a bridge will...Select one:a. expand.b. contract.c. remain the same.d. none of the above.
We know that substances expand with high temperatures and contract with low temperatures, therefore, the bridge will contract and the answer is b.
A 6.00 kg bowling ball with speed 9.00 m/s strikes a 0.750 kg pin. This slows the ball to
7.00 m/s. Find the force exerted on the pin due to the impact if the collision last for 0.030 s.
(a) Find the change in momentum of the bowling ball
(b) Find the impulse imparted on the pin
(c) Find the resulting speed of the pin after the collision
(d) Find the force exerted on the pin during the collision
For a 6.00 kg bowling ball:
(a) change in momentum of the bowling ball is −12.0 kg m/s
(b) impulse imparted on the pin is −12.0 kg m/s.
(c) resulting speed of the pin after the collision is 8.00 m/s
(d) force exerted on the pin during the collision −400 N
How to solve for collision?(a) The change in momentum of the bowling ball is given by
Δp = m(vf − vi) = (6.00 kg)(7.00 m/s−9.00 m/s) =−12.0 kg m/s
(b) The impulse imparted on the pin is equal to the change in momentum of the bowling ball, so the impulse is −12.0 kg m/s.
(c) The resulting speed of the pin after the collision can be found using conservation of momentum. The total momentum after the collision is the sum of the momentum of the bowling ball and the momentum of the pin. So,
mbvi = mbvf+ mpvp
where vp = speed of the pin after the collision.
Solving for vp,
vp = mb(vi− vf)/mp = (6.00 kg)(9.00 m/s−7.00 m/s) / 0.750 kg = 8.00 m/s
(d) The force exerted on the pin during the collision is given by
F = Δp/Δt = − 12.0 kg m/s/0.030 s = −400 N
The negative sign indicates that the force is in the opposite direction of the initial velocity of the bowling ball.
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_______ assisted Anton Raphael Mengs with the iconography of his ceiling fresco, Parnasus, in the Villa Albani.
A) Johann Winckelmann
B) Cardinal Albani
C) Jacques Louis David
D) Joshua Reynolds
Answer:A
Explanation:
PLS ANSWER FAST WILL GIVE BRAINLY!!!!!!
.What are some observations we can make to determine if something has energy?
Answer:
if somthing is warm or if somthing moves it usally has energy
A rubber band has an un-stretched length of 0. 10m. If someone picks up a paper clip that has a mass of 10g (0. 010kg) and pulls back on it with a rubber band to a distance of. 25 m. With what speed would the paper clip be launched horizontally? The spring constant of the rubber band is 15 N/m
The speed at which the paper clip be launched horizontally, given that the paper clip has a mass of 0.01 Kg is 5.81 m/s
How do I determine the speed?We'll begin by obtaining the energy stored in the stored in rubber. This is shown below:
Initial length = 0.10 mNew length = 0.25 mExtension (e) = 0.25 - 0.10 = 0.15 mSpring constant (K) = 15 N/mEnergy stored (E) =?E = ½Ke²
E = ½ × 15× 0.15²
E = 7.5 × 0.0225
E = 0.16875 J
Finally, we shall determine the speed. Details below:
Mass (m) = 0.01 KgEnergy (E) = 0.16875 JSpeed (v) = ?KE = ½mv²
0.16875 = ½ × 0.01 × v²
0.16875 = 0.005 × v²
Divide both side by 0.005
v² = 0.16875 / 0.005
Take the square root of both side
v = √(0.16875 / 0.005)
v = 5.81 m/s
Thus, the speed is 5.81 m/s
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Can somebody please explain how a compass can be used to find North?
if the pointy thingy in your compass is pointing north, that means it's being (pulled toward) something near Earth's north pole
From the top of a tall cliff of height y, a soccer ball is kicked horizontally so that it leaves the cliff with a velocity v. Assuming air friction is negligible, the speed of the ball just before it hits the ground is:
Answer:
\(\sqrt{v^{2} + 2\, g\, y}\).
Explanation:
Apply the SUVAT equation \({v_{1}}^{2} - {v_{0}}^{2} = 2\, a\, x\) to the vertical component of the soccer ball's motion to find the vertical velocity right before the ball lands. In this equation:
\(v_{1}\) represents the vertical velocity of the ball right before it lands (needs to be found);\(v_{0}\) represents the initial vertical velocity of the soccer ball (\(0\) in this question since the ball was initially travelling horizontally); \(a\) represents the acceleration (equal to \(g\) since air friction is negligible);\(x\) represents the vertical displacement of this ball (in this question, this vertical displacement is equal \(y\), the height of the cliff.)Rearrange this equation to find an expression for the vertical velocity \(v_{1}\) in terms of \(y\) and \(g\):
\(\begin{aligned}v_{1} &= \sqrt{{v_{0}}^{2} + 2\, a\, x} \\ &= \sqrt{2\, g\, y}\end{aligned}\).
Since air friction is negligible, the horizontal velocity of the ball would stay unchanged. Thus, the horizontal velocity of the ball would still be \(v\) right before the ball lands.
Notice that these two components of velocity are perpendicular to one another. Thus, find the combined velocity of the ball right before landing could be found using Pythagorean's Theorem:
\(\sqrt{v^{2} + {v_{1}}^{2}} = \sqrt{v^{2} + 2\, g\, y}\).
light reflecting from a smooth surface undergoes a change in
Light reflecting from a smooth surface undergoes a change in its direction, but not in its speed.
This phenomenon is referred to as specular reflection. When a light ray comes into contact with a smooth surface, such as a mirror, it is reflected back at an angle that is equal to the angle of incidence.
This is because the smooth surface reflects light uniformly, and the angle of incidence is always equal to the angle of reflection.
There are two types of reflection: specular and diffuse. Specular reflection is when light reflects from a smooth surface, such as a mirror or a pool of water, while diffuse reflection is when light reflects off a rough or irregular surface, such as a wall or a sheet of paper.
This is because the light rays that come into contact with the surface are scattered in many directions, making it difficult to see a clear image of the light source.
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Determine the kinetic energy of a 1000 kg roller coaster car that is moving with speed of 40.0 m/s
Answer:
KE=800,000
Explanation:
The formula for kinetic energy is KE=1/2mv^2 or Kinetic Energy= 0.5*mass*velocity^2
so 1000 is the mass and 40 is the velocity
KE=0.5*1000*40^2
KE=0.5*1,000*1,600
KE=800,000 Joules