Two light spheres each of mass 2.0g are suspended by light strings 10cm in length. A uniform electric field |E| = 4.42 × 105N/C is applied in the horizontal direction. The charges on the spheres are equal and opposite. For what charge values will the spheres be in equilibrium at an angle θ = 10 degrees? *I believe the answer is supposed to be 5 x 10^-8 C but that's not what I'm getting.*

Answer:

The force is \(F =102.34 \  N \)

Explanation:

From the question we are told that

   The mass of the car is  \(m_c  =  1500\  kg\)  

   The top radius of the pipe is \(r_t =  24 \  cm  =0.24 \ m\)

    The bottom radius is  \(r_b  =  2 \ cm  =  0.02 \ m\)

 Generally the area of the small end of the pipe is  

      \(A_2 =  \pi  r_b^2\)

=>    \(A_2 =  3.142 * 0.02 ^2\)  

=>    \(A_2 =  0.00126\ m^2 \)  

Generally the pressure in the pipe is mathematically represented as

     \(P =  \frac{F}{A_1}\)

Here \(A_1\)  is the area of the larger opening of the pipe and this is mathematically represented as

     \(A_1  =  \pi  *  r^2_t\)

=>   \(A_1  = 3.142  * 0.24^2\)

=>   \(A_1  = 0.18098 \ m^2\)

Also  F is the force in the  at the larger opening(the top) of the pipe which mathematically evaluated as

        \(F =  m  *  g\)

=>      \(F =  1500 *  9.8\)

=>      \(F =  14700 \ N \)

So

    \(P =  \frac{14700}{0.18098}\)

     \(P = 81224.44 \ N / m^2\)

Generally the force at the smaller opening of the pipe is  

     \(F =  P  *  A_2\)

=>   \(F =  81224.44  *0.00126\)

=>   \(F =102.34 \  N \)

I believe the answer is Justine, correct me if I’m wrong.

The given statement "scientists are concerned about the decrease in ozone is allowing more ultraviolet" is true because ozone is a molecule made up of three oxygen atoms that exist in the Earth's atmosphere. It's a form of oxygen that absorbs almost all of the Sun's harmful ultraviolet light.

Ultraviolet rays are very harmful to humans, causing skin cancer, immune system breakdowns, and cataracts in the eyes. When the ozone layer is damaged or thinned, it can allow more ultraviolet rays to penetrate the atmosphere, which is why scientists are so concerned about ozone depletion.What are the impacts of ozone depletion?It is estimated that a 1% reduction in the ozone layer increases the incidence of non-melanoma skin cancer by 2%.A decrease of 10% in the ozone layer may result in a 20% increase in the incidence of skin cancer.The thinning of the ozone layer may result in a decrease in plant production, which may result in food supply shortages.A decrease in ozone may have an impact on phytoplankton, which play a crucial role in ocean food webs. These tiny creatures consume carbon dioxide and produce half of the world's oxygen. As phytoplankton numbers decline, ocean ecosystems may change, affecting everything from fish populations to weather patterns.

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Answer:

The North Pole.

Explanation:

According to the Lenz's law of electromagnetic induction, an induced elemagnetic force tends to give rise to the current. In reaction, this current's magnetic field try to oppose any replacement in the magnetic flux.

So,  as per the law of Lenz's electromagnetic induction, when the current passes in a coil in anti-clockwise direction, this will produce the opposite end of the coil in the north pole.

So, the correct answer is north pole.

The photon released during the transition has a wavelength of 219 nm, or \(2.19 * 10^-^7 m\)

The wavelength of the photon emitted during the transition can be calculated using the energy difference between the initial and final states of the electron. In this case, the electron transitions from the\(nX = 2, nY = 2, nZ = 1\) state to the \(nX = 1, nY = 1, nZ = 1\)state, which corresponds to an energy difference of ΔE = 9.08 × 10^-20 J.

The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Rearranging this equation, solve for λ:

λ = hc/ΔE

Plugging in the values for h, c, and ΔE, we get:

λ \(= (6.626 * 10^{-34} J s) * (3.00 * 10^8 m/s) / (9.08 * 10^{-20} J)\)

λ =\(2.19 * 10^-^7 m\)

Therefore, the wavelength of the photon emitted during the transition is \(2.19 * 10^-^7 m\), or 219 nm.

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The amount of radon 222 that would remain in the sample after 4 half-lives would be 0.28  grams , therefore the correct answer is option A.

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.

As given in problem ,the Environmental Protection Agency has been concerned about the levels of radon gas in homes. If a sample of gas taken from a basement contains 4.38 g of radon 222,

The amount of the radon remains after the first half-life = 4.38/2

The amount of the  radon remains after the second half-life = 2.19/2

The amount of the radon remains after the third half-life = 1.095/2

The amount of the radon  remain after the fourth half-life=0.5575/2

                                                                                              = 0.28 grams

Thus, the correct answer is option A.

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The acceleration of the proton by using Coulomb's law is 2.806 m/s²

The acceleration of a proton can be defined by using coulombs force and centripetal acceleration. The value of coulomb force is

Fc = k.q1.q2 / d²

where Fc is coulomb force, k is Coulomb's constant, q is charge and d is distance.

Centrifugal force will also same as coulomb force, which can be determined as

F = m.a

where F is centrifugal force, m is mass and a is acceleration.

From the question above, we know that:

q1 = q2 = e = 1.602176634×10‾¹⁹ C

k = 8.988×10⁹ N⋅m²⋅C‾²

m = 1.673 x 10‾²⁴ kg

d = 7 x 10‾³ m

By combining these equations, we get

F = Fc

m.a = k.q1.q2 / d²

a = k.e² / m.d²

Substitute the parameter

a = 8.988×10⁹ . (1.6×10‾¹⁹)² / ( 1.673 x 10‾²⁴ . ( 7 x 10‾³ )² )

a = 2.806 m/s²

Hence, the acceleration of the proton by using Coulomb's law is 2.806 m/s²

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When the temperature of the blocks is the same as the temperature of your hand, you feel neither hot nor cold to the touch. Hence, option ( 3) is correct.

Temperature is a unit used to describe hotness or coldness. It can be stated in terms of any number of arbitrary scales and shows the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature).

Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at a much higher temperature.

If you touch a block that is at higher than or  at lower than  the temperature of your hand, you feel hot or cold respectively. But,  when the temperature of the blocks is the same as the temperature of your hand, you feel neither hot nor cold to the touch.

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it tend to deflect if its velocity is in Westward direction.

An electric field that is supplied transverse to the route of the particles can be used to change the trajectory of a stream of charged particles, a process known as electrostatic deflection.

Deflection in physics is the modification of a moving object's velocity and, consequently, trajectory due to contact (collision) with a surface or the action of a non-contact force field.

When someone switches the subject in the middle of a discussion, that is one of the most prevalent instances of deflection. In particular, the deflector will refocus the discourse to center on something the other person did incorrectly if their behavior is questioned.

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Answer:

this conponent is a bulb

and is used to measure brightness

The landing velocity of the object is 31 m/s.

The given parameters;

height from which the object is released, h = 49 m

The landing velocity of the object is calculated by applying third equation of motion as shown below;

v² = u² + 2gh

where;

The landing velocity of the object is calculated as;

v² = 0 + 2(9.8)(49)

v² = 960.4

v = √960.4

v = 30.99 m/s

v ≈ 31 m/s

Thus, the landing velocity of the object is 31 m/s.

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Here, two metal spheres that are neutral to the outside world are in contact with others. A rod that is positively charged is brought close.

The overall charge will attempt to be split equally between two hemispheres of equal size. Positive charges reject one another and attempt to spread as far apart as they can. The similar behavior is shown by the negative charges.

Electrons can move freely between the spheres as they are formed of metal. So the electrons in the two will move as the rod carrying positive charge is moved close to the spheres.

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The internal resistance of the battery is 5.686ohms.

A battery's internal resistance (IR) is characterized as the resistance to current flow inside the battery. The internal resistance of a battery is primarily affected by two factors: electrical resistance.

The main causes of the increase in internal resistance with lead acid are sulfation and grid corrosion. Temperature has an impact on resistance as well; heat reduces it and cold increases it. An increase in runtime can be achieved by briefly lowering the internal resistance of the battery  

The formula below is used to determine the battery's internal resistance.

(V/R)r = V'

Make r the equation's subject.

r = V'R/V

Given:

V =  68.1  V

R = 20.6 ohms

V' = 18.8 V

r = (18.8×20.6)/68.1

r = 387.28/68.1

r = 5.686ohms.

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Answer and Explanation: The geosphere interacts with the cryosphere when glaciers and sheets of ice from the cryosphere erode the rocks located on the geosphere. This happens as ice passes over the land and carries eroded rocks to new locations. The cryosphere can also cause soil to become icy and take hold of greenhouse gases from the atmosphere. The geosphere is the part of the Earth that has rocks, minerals, sand, and lava. The cryosphere has frozen water, ice, and glaciers. The cryosphere also interacts frequently with the hydrosphere because it draws water from the hydrosphere and freezes it during cold temperatures. Warmer temperatures cause the cryosphere to melt and release water back to the hydrosphere.

Let's evaluate each statement one by one:1. If the amplitude is increased, the wavelength decreases increases stays the same.

False. The wavelength of a wave is inversely proportional to its frequency, not its amplitude. Increasing the amplitude of a wave does not have any effect on its wavelength.

2. If the oscillation frequency of the transmitting electron decreases, the oscillation frequency of the electron in the receiver is instantaneously affected.

False. The oscillation frequency of the transmitting electron does not instantaneously affect the oscillation frequency of the electron in the receiver. Changes in the transmitting electron's frequency take time to propagate to the receiver. Therefore, this statement is false.

3. The electron in the receiving antenna oscillates at a lower frequency than the electron in the transmitting antenna because of the distance between the antennas.

False. The frequency of oscillation of the electron in the receiving antenna is the same as the frequency of the transmitting antenna. The distance between the antennas does not affect the frequency of the oscillation. Therefore, this statement is false.

4. If the frequency of oscillation increases but the amplitude of the electron oscillation remains the same, then the electron in the transmitting antenna is experiencing larger accelerations.

False. The frequency of oscillation does not directly affect the acceleration experienced by the electron in the transmitting antenna. Acceleration depends on the amplitude of the oscillation, not the frequency. Therefore, this statement is false.

5. If the amplitude increases but frequency remains the same, the electron at the receiving antenna experiences larger peak forces but oscillates at the same frequency as before.

False. Increasing the amplitude of the electron oscillation in the transmitting antenna does not affect the peak forces experienced by the electron in the receiving antenna. The amplitude only determines the maximum displacement from the equilibrium position, not the forces involved. Therefore, this statement is false.

6. If the frequency of the transmitting electron decreases by a factor of two, it will now take longer for the electromagnetic signal to reach the receiving antenna.

True. The frequency of an electromagnetic wave is directly proportional to its speed. If the frequency decreases, the speed of the wave remains the same, but it takes longer for one complete cycle of the wave to occur. Therefore, it will take longer for the electromagnetic signal to reach the receiving antenna. Thus, this statement is true.

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Answer:

13 ms-1

Explanation:

Answer:

SE RESUELVE CON LA ECUACIÓN DE GALILEO GALILEI

Explanation:

v = 3 m/s + \(2 m/s^{2}\)(5 s) = 13 m/s

Answer: L

Explanation: L is the specific latent heat for a particular substance (kJ kg−1 or in BTU lb−1), either Lf for fusion, or Lv for vaporization.

The mechanical energy at top =Mechanical energy at bottom

\(\\ \tt\longmapsto M_{initial}=M_{Final}\)

\(\\ \tt\longmapsto KE=M_{initial}\)

\(\\ \tt\longmapsto KE=P.E_{(Top)}+K.E_{(Top)}\)

\(\\ \tt\longmapsto K.E=mgh+\dfrac{1}{2}mv^2\)

\(\\ \tt\longmapsto K.E=m\left(gh+\dfrac{v^2}{2}\right)\)

\(\\ \tt\longmapsto K.E=54\left((10)(51)+\dfrac{2.6^2}{2}\right)\)

\(\\ \tt\longmapsto K.E=54\left(510+\dfrac{6.76}{2}\right)\)

\(\\ \tt\longmapsto K .E=54(510+3.38)\)

\(\\ \tt\longmapsto K.E=54(513.38)\)

\(\\ \tt\longmapsto K.E=27722.52J\)

\(\\ \tt\longmapsto K.E=27.7KJ\)

Answer:

Ionic bonds are formed between cation and anions . A cation is formed when a metal ion loses valence electron while an anion is formed when a non-metal gains a valence electron.

Answer:

to find the weight, use the following formula

F= m x g

in Earth---> 45 x 9.8= 441 N

in Moon---> 45 x 1.6= 72 N

Explanation:

I HOPE THIS HELPS!!! :)

The change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.

Gravitational potential energy is defined as the energy possessed by or acquired by an object due to a change in its position when it is present in a gravitational field. This can be said that gravitational potential energy is the energy which is related to the gravitational force or gravitation.

Gravitational potential energy is expressed as

U=m g h

Where, U = gravitational potential energy

m = mass

g = gravitational field

h = height

For above given example,

The change in gravitational potential energy for Earth

mass= 45kg

Difference in height \((H_2-H_1)\)= 18-2= 16m

g= \(9.8m/s^2\)

U= 45*16*9.8 = 7056J or 7.056kJ

The change in gravitational potential energy for Moon

mass= 45kg

Difference in height \((H_2-H_1)\)= 18-2= 16m

g= \(1.6m/s^2\)

U= 45*16* 1.6= 1152J or 1.152kJ

Thus, the change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.

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Answer:The disturbance created by a source of sound in the medium travels through the medium and not the particles of the medium

Explanation:i hope this is right

The glasses that  increase pupil illumination is  Glasses do not increase pupil illumination.​

Pupil illumination refers to the amount of light entering the eye through the pupil. The size of the pupil determines the amount of light that enters the eye, with larger pupils allowing more light and smaller pupils allowing less light. The amount of light available in the environment also affects pupil illumination, with brighter environments causing the pupil to constrict and dimmer environments causing the pupil to dilate. Pupil illumination plays an important role in visual perception, as it affects the brightness and clarity of the visual image formed on the retina.

Pupil illumination is a function of the amount of light entering the eye, which is determined by the size of the pupil and the amount of light available in the environment. Glasses do not have a direct effect on the size of the pupil or the amount of light in the environment, so they cannot increase pupil illumination.

However, glasses can improve visual acuity and clarity by correcting refractive errors and enhancing contrast, which may indirectly improve the perception of brightness and illumination.

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To calculate the hours a bird can fly using the energy supplied by 4.00 grams of fat, we need to find the total energy content of the fat and then divide it by the bird's energy consumption rate.

Fat provides approximately 9 kcal of energy per gram. First, convert the energy content of the fat to watts:

4.00 grams of fat * 9 kcal/gram = 36 kcal

1 kcal = 4184 joules

36 kcal * 4184 joules/kcal = 150,624 joules

1 watt = 1 joule/second, so the bird consumes 3.70 joules per second.

Now, divide the total energy content of the fat by the bird's energy consumption rate:

150,624 joules / 3.70 joules/second = 40,704 seconds

Finally, convert the seconds to hours:

40,704 seconds / 3600 seconds/hour ≈ 11.31 hours

So, the bird can fly for approximately 11.31 hours using the energy supplied by 4.00 grams of fat.

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The first step is to calculate the energy that can be obtained from 4.00 grams of fat.

One gram of fat can provide approximately 9 calories of energy, which is equivalent to 37.656 joules. Therefore, 4.00 grams of fat can provide:

Energy = 4.00 grams x 9 calories/gram x 4.184 joules/calorie

Energy = 150.336 joules

Next, we can calculate the time that the bird can fly using this energy supply by using the formula:

Time = Energy / Power

where Power is the rate at which the bird consumes energy, which is 3.70 watts.

Time = 150.336 joules / 3.70 watts

Time = 40.62 seconds

Therefore, the bird can fly for approximately 40.62 seconds using the energy supply provided by 4.00 grams of fat.

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Answer:

C

Explanation:

i did the test too

In the case of charge q, one sphere is composed of metal and the other of plastic, thus the charge may be equally distributed throughout the metal sphere.

Electric charge is a property of matter that, when exposed to an electromagnetic field, causes the perception of force. Protons and electrons most typically carry positive and negative charges, which are the two forms of electric charges. Energy is created by charge movement.

Subatomic particles experience force while in an electric and magnetic field thanks to a property known as "electric charge." Protons and electrons are the most prevalent charge carriers for positive and negative electric charges, respectively.

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The resistivity of the material is 0.003925 ohm-meters.

We can use the formula for the resistance of a wire to solve this problem:

R = ρL/A

To find the resistivity (ρ) of the material, we can rearrange the formula:

ρ = RA/L

We are given the resistance (R) of the conductor as 0.1 ohms, the length (L) as 2.00 meters, and the diameter (d) as 1.00 mm. First, we need to calculate the cross-sectional area (A) of the conductor:

\(A = \pi (d/2)^2 \\A = \pi (0.5 mm)^2 \\A = 0.785 mm^2\)

Now we can plug in the values into the formula to find the resistivity:

\(\rho = (0.1 ohms)(0.785 mm^2) / 2.00 meters \\\rho = 0.003925 ohm-meters\)

Therefore, the resistivity of the material is 0.003925 ohm-meters.

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The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

The given parameters:

The vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.

Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

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Koko Head, Rabbit Island, Koko Crater, and Hanauma Bay are all geologically related to the Koko Crater Complex, which is a volcanic feature located on the island of Oahu, Hawaii.

They are all part of the same volcanic system and share similar geological origins. The Koko Crater Complex is characterized by tuff cone formations, which are created by explosive volcanic eruptions. These features have been shaped by volcanic activity and erosion over time, resulting in their distinct geological characteristics. The Koko Crater Complex is known for its tuff cone formations, which are created by explosive volcanic eruptions. These geological features have contributed to the unique landscape and characteristics of the area.

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