Two identical piano wires have a fundamental frequency of 576 Hz when kept under the same tension. What fractional increase in the tension of one wire will lead to the occurrence of 5 beats/s when both wires oscillate simultaneously
Answers
To achieve an occurrence of 5 beats/s when both wires oscillate simultaneously, the tension of one wire needs to be increased by 1/25th or 4% of its initial tension.
The fundamental frequency of a vibrating string is directly proportional to the square root of the tension applied to it. Let's assume the initial tension in each wire is T. Thus, the fundamental frequency of each wire is 576 Hz.
To create beats, the frequency difference between the two wires must be 5 Hz. Let's denote the increased tension in one wire as T'. Therefore, the fundamental frequency of that wire will become f' = √(T'/m), where m is the linear mass density of the wire.
The frequency difference between the two wires is given by the equation: f' - f = 5 Hz.
Substituting the values, we get: √(T'/m) - √(T/m) = 5 Hz.
To simplify the equation, we can apply the binomial approximation (√(1+x) ≈ 1 + 0.5x) for small values of x.
Using this approximation, the equation becomes: (1 + 0.5(T'/m - T/m)) - 1 = 5 Hz.
Simplifying further, we have: 0.5(T'/m - T/m) = 5 Hz.
Rearranging the equation, we find: T'/m - T/m = 10 Hz.
Since both wires have the same linear mass density, m cancels out, leaving us with: T' - T = 10 Hz.
We know that T = T', so the equation becomes: T' - T = 10 Hz.
From this equation, we can determine that T' is 10 Hz greater than T.
Now, to find the fractional increase in tension, we divide the difference in tension by the initial tension: (T' - T) / T = 10 Hz / T = 10 / 576.
Simplifying, we get the fractional increase in tension as 1/57 or approximately 0.0175, which is equal to 1/25th or 4% of the initial tension.
To know more about fundamental frequency refer here:
https://brainly.com/question/32019628#
#SPJ11
Related Questions
If I traveled 30 miles in 1 hour, then 20 miles in 1 hour, and 50 miles in 3
hours, what is my average speed?
Answers
Answer:
The answer is 20 miles/hr
Explanation:
2- A car spends two hours driving at 20 km/h, and then an hour driving at 50 km/h.
What is the average speed of the car?
A. 50 km/h
B. 45 km/h
C. 35 km/h
D. 30 km/h
Answers
When a car spends two hours driving at 20 km/h, and then an hour driving at 50 km/h. then the average speed of the car would be 30 km/h , therefore the correct answer is option D.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
average speed = total distance /Total time
As given in the problem A car spends two hours driving at 20 km/h, and then an hour driving at 50 km/h
The total distance covered by the car is
S =2×20 +1×50
=90 km
The total time taken by the car is
T = 3 hour
then by using the formula for the average speed
average speed = total distance /Total time
By substituting the respective values of the total speed and total time
average speed = 90/3 km/h
=30 km/h
Thus, The correct answer is option D because a car's average speed would be 30 km/h if it spent two hours traveling at 20 km/h and one hour traveling at 50 km/h.
Learn more about speed from here
brainly.com/question/7359669
#SPJ5
A 2uF capacitor, in series with a 2kohm resistance is joined to 100Vd. C supply. Calculate:
i. The current flowing and
ii. The energy stored in the capacitor at the end of 4 seconds from the start.
Answers
i) The current flowing is 0.05A.
ii) The energy stored in the capacitor at the end of 4 seconds from the start is 0.001J.
i)To calculate the current flowing, we can use Ohm's Law which states that current (I) is equal to voltage (V) divided by resistance (R):
I = V/R
In this case, V is 100V and R is 2kohm. So,
I = 100V / 2kohm
I = 0.05A
Therefore, the current flowing is 0.05A.
ii)To calculate the energy stored in the capacitor, we can use the formula:
E = (1/2) * C * V^2
Where E is energy, C is capacitance and V is voltage.
In this case, C is 2uF (which is equivalent to 0.000002F) and V is also 100V. So,
E = (1/2) * 0.000002F * (100V)^2
E = 0.001J
Therefore, the energy stored in the capacitor at the end of 4 seconds from the start is 0.001J.
Know more about capacitor here:
https://brainly.com/question/21851402
#SPJ11
what is true of crabb's view of the two books (god's word and god's works)?
Answers
Larry Crabb, a Christian author and counselor, has a view of the two books, God's Word and God's Works. He believes that both books are revelations of God and that they should be studied together in order to gain a fuller understanding of Him.
Crabb argues that God's Word is a revelation of God's character and nature. It tells us who He is and what He is like. God's Works, on the other hand, are a revelation of God's power and love. They show us what He can do and what He is willing to do for us.
Crabb believes that we should study both books in order to gain a balanced understanding of God. He says that "the Bible is not enough, but it is essential." We need to study God's Word in order to learn about His character and nature, but we also need to study God's Works in order to see His power and love in action.
Crabb's view of the two books is a helpful reminder that God is not just a distant being who is far removed from our lives. He is a personal God who is involved in our world and who loves us deeply. By studying both God's Word and God's Works, we can come to know Him better and grow in our relationship with Him.
Here are some of the benefits of studying God's Word and God's Works together:
It helps us to gain a fuller understanding of God.It helps us to grow in our relationship with God.It helps us to live according to God's will.It helps us to overcome temptation.It gives us hope and encouragement.It brings us peace and joy.To know more about the Larry Crabb refer here :
https://brainly.com/question/13799243#
#SPJ11
Which hypothetical scenario would result in the moon not having different phases?
A he moon takes twice as long as it does now to orbit the earth.
B Earth takes twice as long as it does now to orbit the sun.
C Earth has two moons.
D The moon always stays in one position relative to the earth and sun
Answers
Answer:
D) the moon would stay in one position relative to earth and sun
if the moon were always opposite the sun we would always see a full moon
The sun rotates about the earth once every 366 days (if the earth did not rotate we would see a complete rotation of the sun every 366.25 days)
In one year there 365.25 rotations of the sun about the earth
366.25 days for the earth to rotate - 1 day because of the earth about the sun = 365.25 the length of a day that we observe
(Note the difference between a "sidereal" day and an "astronomical" day)
The tires of a car make 62 revolutions as the car reduces its speed uniformly from 90.0 km/h to 59.0 km/h. The tires have a diameter of 0.86 m.(A) What was the angular acceleration of the tires? (B) If the car continues to decelerate at this rate, how much more time is required for it to stop? (C) If the car continues to decelerate at how far does it go? Find the total distance.
Answers
A) Angular acceleration = -2.47 rad/s²
B) 23.54 seconds
C) The total distance covered = 294.23m
Explanations:The number of revolutions = 62
Angular distance, θ = 62 x 2π
θ = 62 x 2 x 3.142
θ = 389.608 radians
Diameter, d = 0.86 m
Radius, r = d/2 = 0.86/2
r = 0.43m
Initial velocity, v₁ = 90 km/h = 90 x (1000/3600)
v₁ = 25 m/s
Angular velocity, w₁ = v₁ / r
w₁ = 25/0.43
w₁ = 58.14 rad/s
Final velocity, v₂ = 59 km/h = 59 x (1000/3600)
v₂ = 16.39 m/s
Angular velocity, w₂ = v₂ / r
w₂ = 16.39 / 0.43
w₂ = 38.12 rad/s
Using the equation of motion:
\(\begin{gathered} w^2_2=w^2_1\text{ + 2}\alpha\theta \\ 38.12^2=58.14^2\text{ + 2}\alpha(389.608) \\ 38.12^2-58.14^2=\text{ }779.216\alpha \\ 779.216\alpha\text{ = }-1927.1252 \\ \alpha\text{ = }\frac{-1927.1252}{779.216} \\ \alpha\text{ = }-2.47rad/s^2 \end{gathered}\)Angular acceleration = -2.47 rad/s²
B) Amount of time required for the car to stop if it continues to decelerate at this rate
Initial angular speed, w₁ = 58.14 rad/s
When the car stops, final angular speed, w₂ = 0 rad/s
Using the equation of motion below:
\(\begin{gathered} w_2=w_1+\text{ }\alpha t \\ 0\text{ = 58.14 + (-2.47)t} \\ -2.47t\text{ = -58.14} \\ t\text{ = }\frac{-58.14}{-2.47} \\ t\text{ = }23.54\text{ seconds} \end{gathered}\)C) The total distance
Use the equation of motion below:
\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ a\text{ = }\alpha r \\ a\text{ = (-2.47)(0.43)} \\ a\text{ = }-1.0621m/s^2 \end{gathered}\)\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ S\text{ = }25(23.54)+0.5(-1.0621)(23.54)^2 \\ S\text{ = }588.5-294.27 \\ S\text{ = }294.23\text{ m} \end{gathered}\)The total distance covered = 294.23m
find the resultant of the following vectors
1. 100N,37 degree east of north+60N.west
2. 100N,37 degree west of north+50N,53 degree east of north
Answers
The resultant vector of 1. 130N and 2. 155 N respectively.
A resultant vector is described as a single vector that produces the identical effect as is produced through a number of vectors collectively.
1. 100 N, 37° east of north + 100 N 60°North -west
Let Force₁ = 100 N sin37°
= 100 N × 4/5
= 80 N North
Force₂ = 100 N cos 60°
= 100 N × 1/2
= 50 N
Now, the angle between F₁ and F₂ is 0
Resultant force = \(\sqrt {F₁^{2} +\sqrt F₂^{2} + 2abcos°}\)
= \(\sqrt{(80)^{2} +(50)^{2}+2*80*50}\)
= \(\sqrt{6400+2500+8000}\)
= \(\sqrt{16900}\)
= 130N
2. 100N, 37° west of north + 50N,53° east of north
Force₁ = 100N, 37° west of north
=100N cos 37°
= 100N × 5/4
= 125 N north
Force₂ = 50N,53° east of north
= 50N cos 53°
= 50N × 3/5
= 30N
The angle between F₁ and F₂ is 0°
Resultant force = \(\sqrt {F₁^{2} +\sqrt F₂^{2} + 2abcos°}\)
= \(\sqrt{(125)^{2} +(30)^{2}+2*125*30}\)
= \(\sqrt{15625+900+7500}\)
= \(\sqrt{24025}\)
= 155 N
Learn more about vectors here:-https://brainly.com/question/25705666
#SPJ1
How does the flux of light from an isotropic source depend on the distance r from the source?
A. r 2
B. r -2
C. r -1
D. r 1
E. r 1/2
F. none of the above
Answers
The flux of light from an isotropic source depend on the distance r from the source by r-2.
What is isotropic source?
An isotropic source is a source of radiation or sound that emits energy in all directions equally. This type of source is usually assumed to have uniform power density in all directions, making it a simplifying assumption when analyzing a system. Examples include a point source in free space, such as a light bulb, or a sound source in a room.
The flux of light from an isotropic source (a source that radiates uniformly in all directions) decreases as the inverse square of the distance from the source. This means that the flux of light from the source decreases according to the equation F = 1/r2, where F is the flux of light, and r is the distance from the source. Therefore, the flux of light from an isotropic source decreases with the distance r from the source according to the equation F = r-2.
To learn more about isotropic source
https://brainly.com/question/23543764
#SPJ4
A designer is trying to determine the type of wire to use for a pendant light that will hang from the ceiling of an elevator. The wire can withstand a force of 82 N before breaking. Therefore, the upward directed force on the lamp, called tension, cannot exceed 82 N. The lamp also experiences a 45-N gravitational force, called weight, in the downward direction. What is the maximum upward acceleration the elevator can have before the wire breaks? The lamp has a mass of 4.6 kg.
Answers
Answer:
Explanation:
A designer is trying to determine the type of wire to use for a pendant light that will hang from the ceiling of an elevator. The wire can withstand a force of 82 N before breaking. Therefore, the upward directed force on the lamp, called tension, cannot exceed 82 N. The lamp also experiences a 45-N gravitational force, called weight, in the downward direction. What is the maximum upward acceleration the elevator can have before the wire breaks? The lamp has a mass of 4.6 kg.
The maximum upward acceleration the elevator can have before the wire breaks be 8.04 m/s².
What is normal force?Every day, one is affected by the normal force. For instance, the normal response force prevents a book from falling through a table when it is placed there, despite the fact that gravity is pulling the book downward. That implies that there must be a force pushing it up. The typical force is what's known as that force. In this context, "normal" refers to being perpendicular to the surface.
When the elevator moves upward with acceleration a; normal reaction force acting on the lamp be = weight of the lamp + mass × acceleration
= 45+ma.
If this is maximum upward acceleration of the elevator, according to the question:
45 + ma = 82
⇒ ma = 37
⇒ a = 8.04 m/s².
Hence, maximum upward acceleration the elevator can have before the wire breaks be 8.04 m/s².
Learn more about normal force here:
https://brainly.com/question/13340671
#SPJ2
An object with a mass of 2000 g accelerates 8.3 m/s2 when an unknown force is applied to it. What is the amount of the force?
Answers
Answer:
16.6 kg.m/sec^2
Explanation:
force law is mass times acceleration
Marking brainliest help pls the formula are there to help ^
A 0.5kg squirrel climbs a tree. When it reaches the top its potential energy is 34.3J. How high did it climb?
Answers
Answer:
Explanation:
Look at the equation for Potential Energy. PE = mass times gravity times the height. Filling in and solving for h:
34.3 = .5(9.8)h so
34.3 = 4.9h so
h = 7 meters
Describe how a star is formed?
____________________________
Answers
as gasses like hydrogen start to gather, it creates more mass, therefore more gravitational attraction. As the gasses start to collect to considerably large amounts, the gas at the center of the mass starts to compress. As the gas keeps growing, the immense pressure on the core grows and grows, raising the temperature to extreme amounts. As this happens the star starts to undergo a process called nuclear fusion. this process occurs when immense pressure and heat cause the electrons to escape from their nuclei and flow around freely. this is what the fourth state of matter is. this type of matter is called plasma. this alone creates incredible amounts of heat and energy. The main part of the fusion process though is that the nuclei in which the electrons escaped from begin to merge, creating heavier nuclei, therefore creating heavier and denser nuclei. as the nuclei combine they also form denser elements, such as helium (fist merge of nuclei) all the way to eventually iron (last merge before nuclei is at its heaviest. This entire process takes billions of years to go from helium to the extremely dense iron, and stars usually only reach iron if they are big enough (a lot larger than our sun) so that the pressure will be able to keep fusing nuclei. if they dont reach iron, at the end of their life, the fuel from the inside will be used up and the core has to compensate for the gravitational force of the outer star pushing in. this means the star will grow as the outward force becomes greater than the gravitational force. the star will stay like this for a while before finally using up all the fuel and slowly dying off and shrinking. the shrinking star (or dying star) is known as a white dwarf
that is the long answer
Answer:
Star Formation
Stars are born within the clouds of dust and scattered throughout most galaxies. A familiar example of such as a dust cloud is the Orion Nebula. Turbulence deep within these clouds gives rise to knots with sufficient mass that the gas and dust can begin to collapse under its own gravitational attraction.
hy XD ~
A car of 10 kg is moving at a speed of 5 m/s collides with a
stationary car of 25 kg. If the two cars lock together on impact,
what's the combined velocity of the two cars after the collision?
Answers
Explanation:
M1U1+m2u2 = (m1+m2)vf
m1= 10kg
u1=5
m2=25
u2=0
vf=?
10×5+25×0=35 vf
50+0=35Vf
Vf=1.4m/s
12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answers
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
P = (400 + k * 15²) * 15
P = (400 + 11250) * 15
P = 11650 Watts
Therefore, the power necessary to maintain the speed of 15ms^-1 is approximately 11650 Watts.
b. The total resistive force at a speed of 30ms^-1 can be found by substituting 30 for v in the force equation:
F = 400 + k * 30^2
F = 12000 N
Therefore, the total resistive force at a speed of 30ms^-1 is approximately 12000 N.
c. The power required to maintain the speed of 30ms^-1 can be found using the same equation as in part a:
P = (400 + k * 30^2) * 30
P = (1500 + 600000) * 30
P = 625000000 Watts
Therefore, the power required to maintain the speed of 30ms^-1 is approximately 625000000 Watts. This is a very large amount of power and would require a significant amount of energy to maintain.
You see a flash of lightning and hear thunder 3 seconds later. If the air temperature is 24°C that day, determine how far away the storm is.
Answers
Answer:
Explanation:
speed of sound in 24 degrees celsius
345.48m/s
hence 345.48m/s x 3s = 1036.44m
Give a reason why radioactive waste is expensive to dispose of safely.
Answers
Answer:
because it takes a lot of recourses and tools to make it no longer radioactive and those recourses and tools are not cheap
Explanation:
A generator produces 38 mwmw of power and sends it to town at an rms voltage of 78 kvkv. part a what is the rms current in the transmission lines?
Answers
The rms current in the transmission lines is I = 487.18 A.
The root-imply-rectangular (rms) voltage of a sinusoidal supply of electromotive force is used to represent the source. it is the rectangular root of the time average of the voltage squared.
Alternating-present day circuits. the root-imply-square (rms) voltage of a sinusoidal source of electromotive force is used to symbolize the supply. it's far the square root of the time average of the voltage squared.
Electric power is by using present day or the waft of electric fee and voltage or the capacity of rate to deliver electricity. A given cost of power can be produced by using any combination of contemporary and voltage values
power = 38 M watt
rms voltage = 78 K v
power = IV
I = power/V
I = (38 * 1000000)/78*1000
I = 487.18 A.
Learn more about rms current here:-https://brainly.com/question/20913680
#SPJ4
What multiplicity would you expect in a 1h nmr spectrum for the indicated proton(s)?
Answers
The expected multiplicity in a 1H NMR spectrum for a specific proton or protons.
In a 1H NMR spectrum, the multiplicity refers to the number and arrangement of peaks observed for a specific proton. It is determined by the number of neighboring protons (within three bonds) and their relative positions to the proton of interest.
The multiplicity is based on the concept of spin-spin coupling, where the magnetic field generated by neighboring protons affects the local magnetic environment of the proton being analyzed. The neighboring protons can be categorized as either nonequivalent (different chemical environments) or equivalent (same chemical environment). The multiplicity is determined by the number of nonequivalent neighboring protons.
For example, if a proton has three nonequivalent neighboring protons, it will exhibit a multiplet pattern with several peaks due to the various spin-spin interactions. The number of peaks in the multiplet is given by the (n+1) rule, where n is the number of nonequivalent neighboring protons. Therefore, in this case, the multiplicity would be a quartet.
In summary, the multiplicity in a 1H NMR spectrum for a proton is determined by the number of nonequivalent neighboring protons. The (n+1) rule provides a general guideline to determine the number of peaks in the multiplet pattern based on the number of nonequivalent neighboring protons.
Learn more about proton:
https://brainly.com/question/1253540
#SPJ11
Why would it be difficult to experimentally calculate the speed of sound in the classroom with a stopwatch and meter stick?
Answers
Answer:
Sound travels quite fast and sound wave must pass through a medium, such as air.
To measure a sound in classroom you will require to measure the time it takes a sound to travel a measured distance using stopwatch and meter stick but it would be difficult because walls of classroom will create echos echos.
Echos are reflections of sounds which causes timing errors and make difficult to meausre the speed of sound.
the frequency separating audible waves and ultrasonic waves is considered to be 20 khz. what wavelength in air at room temperature is associated with this frequency? (assume the speed of sound to be 340 m/s.) (1000hz
Answers
The wavelength in air at room temperature associated with this frequency will be 1.7cm.
What is an audible wave ?The range of frequencies that the human ear can detect ranges from 20 Hz to 20 kHz. Both this range so these waves are referred to as the audible range. As a result, sound waves with a frequency somewhere around 20 Hz and 20 kHz are considered to be audible sound. Every little change in air pressure could be heard by a person if it is within hearing frequency range. One billionth of a change in atmospheric pressure can be seen.
Can you hear ultrasonic?Ultrasonic waves have the following characteristics. They exceed the audible range in frequency by more than 20 kHz. Ultrasonic sound has more energy over audible sound because for waves, energy rises with frequency.
According to question:We have,
ν = 20 khz = 20000hz, c = 340 m/s
To find: wavelength( λ )
We know that
c = νλ
λ = c/ν = 340/20000 = 0.017m
λ = 1.7cm
Thus, required wavelength is 1.7cm
To know more about wavelength visit:
brainly.com/question/13533093
#SPJ4
16. Two of Jupiter's Galilean moons, lo and
Europe, make a complete revolution around it
over the periods T1=1.77 days and T2 = 3.55
days. Knowing that lo revolves around Jupiter
at a distance of 421600 km, determine the
linear velocity of Europe's motion in its orbit.
Answers
Answer:
The linear velocity of europe's motion in its orbit is 7875.58 km/hr.
Explanation:
Given that,
Time period of lo = 1.77 days
Time period of europa = 3.55 days
Distance of lo from jupiter = 421600 km
We know that,
Distance of europa from jupiter = 671000 km
We need to calculate the linear velocity of europe's motion in its orbit
Using formula of velocity
\(v=\dfrac{d}{t}\)
Where, d = distance between europa and jupiter
t = time
Put the value into the formula
\(v=\dfrac{671000}{3.55\times24}\)
\(v=7875.58\ km/hr\)
Hence, The linear velocity of europe's motion in its orbit is 7875.58 km/hr.
LL Bean shifted from collecting structure data to unstructured
because:
A). the data warehouse is on site.
B). they a single marketing channel
C). the volume of data collected over time stayed
consist
Answers
LL Bean shifted from collecting structured data to unstructured data because the volume of data collected over time remained consistent.
Collecting structured data typically involves organizing and storing data in a predefined format, such as a data warehouse. However, LL Bean's decision to shift to unstructured data suggests that their existing data warehouse, which is likely designed for structured data, may not have been capable of efficiently handling the increasing volume of data collected over time.
Unstructured data, on the other hand, does not adhere to a specific format and can accommodate a larger and more diverse range of data types, allowing LL Bean to effectively manage the growing volume of data they were collecting.
Please note that the provided options A and B are not directly relevant to the reason stated for LL Bean's shift to unstructured data.
Learn more about the shift from structured to unstructured data here:
brainly.com/question/28333364
#SPJ11
a milling machine processes a part with t0=15 mins and sigma0=3mins. the mean time to failure 750 mins and the mean time to repair is 200 muns. the coefficient of varuation for the repair time is 1.2. the product of the milling machine is feeding the downstream turning machine. the turning maching had the same t0 and sigma0, but the mean time to failure and mean time to replair are 110 muns and 38 muns. (cv=1.2).Assuming the arrival to the milling machine is 1.2 parts/hrwith an arrival Cv =1. find the cycle time of the entire line.
Answers
The cycle time of the entire line is 30.00528 minutes per part.
To calculate the cycle time of the entire line, we need to consider the processing times, failures, and repairs of both the milling machine and the turning machine.
For the milling machine:
Mean processing time (t0) = 15 mins
Standard deviation of processing time (sigma0) = 3 mins
Mean time to failure (MTTF) = 750 mins
Mean time to repair (MTTR) = 200 mins
For the turning machine:
Mean processing time (t0) = 15 mins
Standard deviation of processing time (sigma0) = 3 mins
Mean time to failure (MTTF) = 110 mins
Mean time to repair (MTTR) = 38 mins
We also know that the arrival rate to the milling machine is 1.2 parts/hr, with a coefficient of variation (CV) of 1.
To calculate the cycle time, we can use the following formula:
Cycle time = Processing time + Failure time + Repair time
Processing time:
The processing time is the sum of the mean processing times of the milling machine and the turning machine:
Processing time = t0 (milling machine) + t0 (turning machine) = 15 mins + 15 mins = 30 mins
Failure time:
The failure time is the inverse of the MTTF, considering the arrival rate:
Failure time = 1 / (MTTF * Arrival rate) = 1 / (750 mins * (1.2 parts/60 mins)) = 0.00111 parts/min
Repair time:
The repair time is the inverse of the MTTR, considering the coefficient of variation (CV):
Repair time = 1 / (MTTR * CV) = 1 / (200 mins * 1.2) = 0.00417 parts/min
Cycle time:
Cycle time = Processing time + Failure time + Repair time = 30 mins + 0.00111 parts/min + 0.00417 parts/min
to know more about Cycle time, visit:
https://brainly.com/question/31215630
#SPJ11
Please help me out someone?
A positive test charge is placed between an electron, e, and a proton, p, as
shown in the diagram below. When the test charge is released, it will move
toward
Answers
When test charge is released, the charge will move towards the electron placed at point D.
What is charge?The charge is the physical quantity that attracts or repels the other objects when comes into electric field.
The test charge is positive charge. The like charges repel each other and unlike charges attract each other.
So, when test charge is released, it gets attracted towards the opposite charge i.e. electron which is negatively charged.
Thus, the correct answer is D.
Learn more about charge.
https://brainly.com/question/27171238
#SPJ2
Janayah runs 200 yards in 40 seconds. How fast is she running
Answers
Answer:
She is running 5 yards a second Or 300 yards a minute
Explanation:
Divide 200 by 40 to get the rate of speed in seconds
Answer:
≈ 10.23mph
Explanation:
1760yrds in 1 mile
200yrds to miles is:
200/1760 = .1136miles
3600sec in 1 hr
40sec to hours is:
40/3600 = .011111hrs
Now we find her speed in miles per hour:
.1136mi/.01111hrs ≈ 10.23mph
which of the following is a small molecule that would be able to pass through the placental wall?
Answers
One example of a small molecule that can pass through the placental wall is oxygen (O2). The correct option is 1.
One example of a small molecule that can pass through the placental wall is oxygen (O2). Oxygen is a small molecule with a molecular weight of 32 g/mol and is essential for fetal development. It is transported from the maternal bloodstream across the placenta to the fetal bloodstream.
The placenta contains specialized structures called villi, which have a high surface area and thin membranes to facilitate the exchange of gases and nutrients between the mother and the fetus.
Oxygen molecules are small enough to diffuse across the placental membrane. The concentration gradient between the maternal and fetal blood drives the movement of oxygen from an area of higher concentration (maternal blood) to an area of lower concentration (fetal blood).
This passive diffusion process allows oxygen to easily cross the placental barrier.
In contrast, larger molecules such as glucose or antibodies typically do not pass through the placental wall easily. They require specialized transport mechanisms, such as specific transporters or receptor-mediated endocytosis, to facilitate their transfer from the mother to the fetus.
It's important to note that the ability of a molecule to pass through the placental wall depends on various factors including its size, charge, lipid solubility, and specific transport mechanisms involved. Oxygen is a small, uncharged, and highly lipophilic molecule, which makes it ideal for crossing the placental barrier.
Hence, the correct option is 1. Oxygen(O2).
To know more about placental wall refer here:
https://brainly.com/question/32260261#
#SPJ11
1. Oxygen (O2)
2. Glucose (C6H12O6)
3. Antibodies
4. Water (H2O)
Which type of force is a noncontact force?
Answers
-Gravitational force.
-Magnetic force.
-Electrostatics.
-Nuclear force.
Hope this helps! :)
Answer:The answer is C: any fundamental force
Explanation:
A P E X
The direction of the electric field is in the direction that a
_______ test charge would be pushed or pulled if placed in the space surrounding the source charge.
Answers
Answer:
The correct answer is Positive
Explanation:
Put the word POSITIVE
hello please help me out its due today!!
I need to make a word problem using the Ohm's Law, and solve it with shown work, Thank you!
Answers
Answer:
no se entiende nada lo siento
Why are drill holes larger for petroleum rather than metals? (1 point)
Answers
A drill bit is a cutting tool used to create a circular hole. The drill bits used in air rotary drilling rigs are hollow steel.Petroleum drill bits can be 36 centimeters , [14 inches] in diameter. As the drill bit rotates and cuts through the earth, small pieces of rock are chipped off. Drill bits are used to make a circular hole.
More results on this article:
https://education.nationalgeographic.org/resource/petroleum
Did this help you? Click the thanks button below! Or above.