Two identical flasks of equal volume are kept at the same temperature. Flask A contains argon (Ar) and flask B contains krypton (Kr). If the pressure inside both flasks is measured to be the same and we assume the gases behave as ideal gases, which answer correctly completes the following statements: (i) The average kinetic energy of the atoms in flask A is _______ the average kinetic energy of the atoms in flask B. (ii) On average, the atoms in flask A are moving _______ than the atoms in flask B.O less than, slower than O greater than, faster than O equal to, the same speed as O equal to, faster than O less than, the same speed

Answer: 42.0%

Explanation: %Sb = 23.6 g/ 56.2 g x 100% = 42.0% Sb

The percent composition of fluorine is 58.0%.

Percent composition = mass of compound ÷ molecular mass × 100

Mass of Compound = 32.6g
Molecular Mass = 56.2g

∴ percent composition = 32.6 ÷ 56.2 × 100

= 0.580× 100

= 58.0%

The percent composition of fluorine is 58.0%.

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Answer:

40 litres

Explanation:

using Boyle's law V1P1=V2P2

V1=20 l

P1= 60atm

P2= 30 atm V2=?

substituting we will have that

20×60=V2×30

V2={20×60}/30

V2=40 l

Answer:

the volume of the gas will decrease

Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

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Answer:

methanide

Explanation:

not sure

Answer:

Domain

Explanation:

This is because Linnaeus taxonomy is a system of classification which was invented by a swedish Botanist called Carl Linnaeus and it is refered to hierarchy of grouping organisms called taxa. It involve 7 system of classifications and they include Kingdom, Phylum, Class, Order, Family, Genus, and Species.

Answer:

Water is weird because in solid state The molecules are combine then in liquid state they are wide apart.

The concentration of Zn²⁺ ions at the cathode of the concentration cell is 0.646 M.

The concentration of the Zn²⁺ ions at the cathode of the concentration cell is determined as follows:

At the anode, oxidation half-reaction: Zn(s) ---> Zn²⁺ (aq) + 2 e⁻ [Zn⁺] = 0.100 M

At the cathode, reduction half-reaction: Zn²⁺ (aq) + 2 e⁻ ----> Zn (s)  [Zn⁺] =  x

The Ecell = 24.0 mV or 0.024 V

Using the Nernst equation:

Ecell = E°cell - 0.0592/n * log([Zn⁺]anode/[Zn⁺]cathode)

E°cell of a concentration cell = 0

where;

n is the number of moles of ions = 2

0.024 =  0 - 0.0592/2 * log (0.1/x)

y = 0.646 M

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The mass (in kilograms) of Cryolite, Na₃AlF₆ produced, given that 10.3 Kg of Al₂O₃, 55.4 Kg of NaOH, and 55.4 Kg of HF react completely is 42.4 Kg

The mass of Na₃AlF₆ produced from the reaction can be obtained as follow:

Al₂O₃(s) + 6NaOH(l) + 12HF(g) ⟶ 2Na₃AlF₆ + 9H₂O(g

From the balanced equation above,

0.102 Kg of Al₂O₃ reacted to produce 0.420 Kg of Na₃AlF₆

Therefore,

10.3 Kg of Al₂O₃ will react to produce = (10.3 × 0.420) / 0.102 = 42.4 Kg of Na₃AlF₆

Thus, from the above calculation, it is evident that the mass of Na₃AlF₆ produced is 42.4 Kg

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It is an amine, and it has less polar nitrogen-hydrogen and oxygen-hydrogen bonds.

A compound's boiling point is a physical characteristic. These intramolecular linkages between the molecules that make up a chemical affect these physical characteristics.

Alcohols and amino acids have the same kind of intermolecular linkages. The hydrogen bond is the name of this kind of bond.

The electrical attraction between a hydrogen atom from one molecule and an electronegative atom from a nearby molecule is known as a hydrogen bond.

The strength of the bond is in the following order: H.....F > H.....O > H......N

The H....N hydrogen bonds exist in amines, whereas the H....O hydrogen bonds exist in alcohols.

Consequently, the alcohol's hydrogen bonds are stronger and it will impart a higher boiling point on the compound.

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Answer:uses world like

Explanation:

The ionization of the following acids can be represented as:

Tetraoxosulphate (VI) Acid (\(H_{2}SO_{4}\)) ionizes as H+ and SO4^2- ions.

Trioxonitrate (V) Acid (\(HNO_{3}\)) ionizes as H+ and \(NO_{3-}\) ions.

Ethanoic Acid (\(CH_{3}COOH\)) ionizes as H+ and \(CH_{3}COO^{-}\) ions.

Tetraoxosulphate (VI) Acid, also known as sulfuric acid (\(H_{2}SO_{4}\)), ionizes as follows:

\(H_{2}SO_{4}\) → \(H+\) + \(SO_{4}^{2-}\)

In this reaction, sulfuric acid donates two hydrogen ions (H+) to the solution, forming sulfate ions (\(SO_{4}^{2-}\)).

Trioxonitrate (V) Acid, commonly known as nitric acid (\(HNO_{3}\)), ionizes as follows:

\(HNO_{3}\) → \(H+_{}\) + \(NO_{3-}\)

Nitric acid dissociates to release one hydrogen ion (\(H+\)) and a nitrate ion  (\(NO_{3-}\)).

Ethanoic Acid, also known as acetic acid (\(CH_{3}COOH\)), ionizes as follows:

\(CH_{3}COOH\) → H+ + \(CH_{3}COO^{-}\)

Acetic acid donates a hydrogen ion (H+) to the solution, forming an acetate ion (\(CH_{3}COO^{-}\)).

In all cases, the acids dissociate in water, producing hydrogen ions (H+) as positively charged ions and their corresponding anions. The hydrogen ions are responsible for the acidic properties of these substances, while the anions contribute to the overall charge balance in the solution. The ionization of acids allows them to conduct electricity in aqueous solutions and react with other substances.

The question was incomplete. find the full content below:

Indicate the ionization of the following acids,

Tetraoxosulphate (VI) Acid

Trioxonitrate (V) Acid

Ethanoic Acid.​

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Answer:

Explanation:

Given that:

number of moles of super cooled liquid water = 1

Melting enthalpy of ice = 6020 J/mol

Freezing point =0 °C = (0 + 273 K)= 273 K

The decrease in entropy of the system during freezing for 1 mol (i.e during transformation from liquid water to solid ice )  = - 6020 J/mol × 1 mol /273 K = -22.051 J/K

Entropy change during further cooling from 0 °C (273 K) to -10 °C (263 K)

\(\Delta \ S = \int\limits^{T_2}_{T_1}\dfrac{nC_p(s)dT}{T}\)

\(\Delta \ S = {nC_p(s)In \dfrac{T_2}{T_1}\)

\(\Delta \ S = {(1*37.7)In \dfrac{263}{273}\)

Δ S = -1.4 J/K

Total entropy change of the system = - 22.05 J/K - 1.4 J/K = - 23.45 J/K

Entropy change of universe = entropy change of the system+ entropy change of the surrounding

According to the second law of thermodynamics

Entropy change of universe  >0

SO,

Entropy change of the system + entropy change in the surrounding > 0

Entropy change in the surrounding > - entropy change of the system

Entropy change in the surrounding > - (- 23.53 J/K)

Entropy change in the surrounding > 23.53 J/K

b) Make some comments on entropy changes from the obtained data.

From the data obtained; we will realize that the entropy of the system decreases as cooling takes place when water is be convert to ice , randomness of these molecules reduces and as cooling proceeds , hence, entropy reduces more as well and the liberated heat will go into the surrounding due to this entropy of the surrounding increasing.

The half-life of a reaction is the time it takes for the concentration of a reactant to decrease to half its initial value. In a first-order reaction, the rate of the reaction is directly proportional to the concentration of the reactant. This means that the rate of the reaction depends on the concentration of compound A.

To calculate the half-life of compound A, you can use the equation:

half-life = (ln(2)) / k

where k is the rate constant for the reaction.

Plugging in the values given in the question, we get:

half-life = (ln(2)) / 0.45

This simplifies to:

half-life = 1.44 / 0.45

Which gives us a final result of:

half-life = 3.2 hours

So the half-life of compound A at 250°C is approximately 3.2 hours.

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Answer:1. metyletevinyl

4. (Z)-3-hydroxypropenal

Explanation:

Erosion by water during the rainy season can be a significant natural phenomenon. When it rains, water flows over the land, picking up soil particles and carrying them along with it.

Water is a clear, colorless, odorless, and tasteless liquid that is essential for life. It is a chemical compound made up of two hydrogen atoms and one oxygen atom, with the chemical formula H2O. Water is the most abundant substance on Earth, covering approximately 71% of its surface.

Water is a unique substance because of its molecular structure, which allows it to exist in all three physical states - solid, liquid, and gas - at temperatures and pressures commonly found on Earth. It has a high heat capacity, meaning it can absorb and release large amounts of heat without changing temperature significantly. This property is important for regulating the Earth's climate and for maintaining the temperature of living organisms.

Water is essential for many biological processes, such as hydration, digestion, and metabolism. It also plays a crucial role in the Earth's water cycle, where it evaporates from bodies of water and plants, condenses into clouds, and falls back to the surface as precipitation.

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Answer:

\(molar \: mass \: of \: copper(ii)nitrate = 64 + (14 + 48) \times 3 \\ = 250 \: g \\ 64 \: g \: of \: copper \: produces \: 250 \: g \: of \: copper \: nitrate \\ 10.36 \: g \: of \: copper \: will \: produce \: ( \frac{10.36 \times 250}{64} ) \: g \\ = 40.7 \: g\)

Answer:

640 g

Explanation:

Step 1: Given and required data

Step 2: Calculate the moles of oxygen gas

We will use the ideal gas equation

P × V = n × R × T

n = P × V / R × T

n = 25 atm × 20 L / (0.082 atm.L/mol.K) × 300 K = 20 mol

Step 3: Calculate the mass corresponding to 20 moles of oxygen

The molar mass of oxygen is 32.00 g/mol.

20 mol × 32.00 g/mol = 640 g

Density for 98% = 1.84 g/mL

V M = # mol

0.1 L x 1 M = 0.1 mol

0.1 mol x 98 g/mol = 9.8 g

m =%CDV

9.8 g = 0.98 x 1.84V

V = 5.43 mL

take this volume and carefully (acid to ater) dilute till 100 mL

A) The chemical symbol for the ion is Fe+

B) It has 20 electrons in total, and there are 6 3p electrons in the ion.

C) There are 6 electrons present in the 3p orbital.

The atomic cation with the given electron configuration is represented by the chemical symbol Fe+.

To determine the number of electrons in the ion, we need to count the electrons present in the electron configuration. In the given configuration, we can see that the 1s orbital has 2 electrons, the 2s orbital has 2 electrons, the 2p orbital has 6 electrons, the 3s orbital has 2 electrons, the 3p orbital has 6 electrons, the 3d orbital has 1 electron, and the 4s orbital has 1 electron. Adding up these numbers, we have:

2 + 2 + 6 + 2 + 6 + 1 + 1 = 20

Therefore, the ion has 20 electrons.

To determine the number of 3p electrons in the ion, we look at the 3p orbital. In this case, there are 6 electrons present in the 3p orbital.

In summary, the chemical symbol for the ion is Fe+, it has 20 electrons in total, and there are 6 3p electrons in the ion.

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Answer:

B

Explanation:

I did the question before and got it right.

Given that, an experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter; the heat of the reaction in the whole system is calculated to be 2218.34 kJ

Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.

The formula used to calculate the heat of the reaction can be expressed as follows:

Q = mcΔT

where:

From the information given:

∴

The change in temperature i.e. ΔT = T₂ - T₁

ΔT = 91.5° C - 25° C

ΔT = 66.5° C

The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³

\(\mathbf{= (1 \times \dfrac{50}{1000})\ moles}\)

= 0.05 moles

Then;

Using the relation:

\(\mathbf{number \ of \ moles = \dfrac{mass}{molar \ mass}}}\)

By crossing multiplying;

mass of CuSO₄ = number of moles of CuSO₄ ×  molar mass of CuSO₄

mass of CuSO₄ = 0.05 moles  × 159.609 g/moles

mass of CuSO₄ = 7.9805 grams

∴

Using the formula from above:

Q = mcΔT

Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C

Q = 2218.34 kJ

Therefore, we can conclude that the heat of the reaction is 2218.34 kJ

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A water bath can be used to keep the temperature of the conical flask and its contents at a temperature .

This is a laboratory equipment which contains a heated source and  is used to incubate samples in water at a constant temperature over a period of time.

This is why water bath will be best used to keep the temperature of the conical flask and its contents at a temperature of 45 °C throughout the reaction.

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The functional group within the compound is ketone.

Ketones are a common functional group in organic chemistry. Ketones have important physiological properties.

Ketones can be named using either the common system or the IUPAC system. In the common system, ketones names are created by naming the groups attached to the carbonyl carbon and then adding the word ketone.

In ketones, the carbonyl group has two hydrocarbon groups attached to it. These can be either aromatic rings or alkyl groups. Ketone does not have a hydrogen atom attached to the carbonyl group.

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For trace analysis, X-ray spectrography is more suitable as it is more sensitive technique and gives finer emission spectrum.

Emission spectrum is defined as a spectrum of a chemical compound or substance composed of frequencies of electromagnetic radiation. Radiations which are emitted while electron make transition from higher to lower energy level.

Energy of photon is equal to the difference between the two energy states . There are many possible electronic transitions in an atom and every transition has a specific wavelength.

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So, we're given the following equation:

We're asked to find how many moles of H2O can we produce from 2 moles of H2SO4. For this, we need to look at the coefficients of each compound in the reaction.

As you can see, we have 1 mol of H2SO4 and 2 moles of water according to the reaction. This tells us that for each 1 mol of H2SO4, we can produce 2 moles of water, so there's a 1:2 ratio.

So, if we have 2 moles of H2SO4:

Therefore, the answer is 4 moles of H2O.

Answer:

The answer is as follow:

Explanation:

In general, the compounds which discharge proton (H+) in aqueous solution or donate H+ to other compound or receive electrons from other molecules/ions tend to be acidic. Example: HCl, H2SO4, AlCl3 etc.

Again,

In general, the compounds which discharge OH-  in aqueous solution or receive H+ from other compound tend to be basic. And the bases with hydroxides and are soluble in water tend to be alkaline. Example: NaOH, KOH etc.

The final temperature of the copper and water in the calorimeter given the data is 30.3 °C

Heat loss = Heat gain

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – M꜀)

95 × 0.385 (77.9 – Tₑ) = 42 × 4.184(Tₑ – 20.4)

36.575(77.9 – Tₑ) = 175.728(Tₑ – 20.4)

Clear bracket

2849.1925 – 36.575Tₑ = 175.728Tₑ – 3584.8512

Collect like terms

2849.1925 + 3584.8512 = 175.728Tₑ + 36.575Tₑ

6434.0437 = 212.303Tₑ

Divide both side by 212.303

Tₑ = 6434.0437 / 212.303

Tₑ = 30.3 °C

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Answer:Because the Earth is round and not flat, the Sun's rays don't fall evenly on the land and oceans. The Sun shines more directly near the equator bringing these areas more warmth. However, the polar regions are at such an angle to the Sun that they get little or no sunlight during the winter, causing colder temperatures.

Explanation:

The volume of the gas is 27 ml

The calculation can be done as follows

The first step is to convert the pressure to atm

convert 2280 tors to atm

760 tors= 1 atm

= 2280/780

= 3 atm

The formula is

PV= nRT

The next step is to write out the parameters

Pressure= 3 atm

Temperature= 21 °C

no of moles= 32.1 mole

volume= ?

(r)constant= 8.314

3 × v= 32.1×8.314×21

3v= 81.080

V= 81.080/3

V= 27 ml

Hence the volume of the gas is 27 ml

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