Two charges 2uc and 3 uc are placed at 2 corners of an equilateral triangle of side 20 cm in freee space

The tension force being supplied by the rope is 245 N.

The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;

T = mg

where;

T = 25 x 9.8

T = 245 N

Thus, the tension force being supplied by the rope is 245 N.

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The final temperature of the water is approximately 19.8°C.First, we need to calculate the heat lost by the water as it cools down from 80°C to the final temperature.

We can use the formula: Q = m × c × ΔT where Q is the heat lost, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

The mass of water in the calorimeter is:

90 ml = 90 g

The heat lost by the water is:

Q1 = 90 g × 4.18 J/g°C × (80°C - T)

Q = m × Lf + m × c × ΔT

The mass of ice added to the water is 10 g. The heat gained by the ice is:

Q2 = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

where 334 J/g is the heat of fusion of water.

Since the calorimeter is insulated, we know that the heat lost by the water must equal the heat gained by the ice. Therefore:

Q1 = Q2

90 g × 4.18 J/g°C × (80°C - T) = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

Simplifying and solving for T, we get:

T = 19.8°C

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The required acceleration of the car, when the driver hits the brake, is \(-5 m/s^2\), the negative sign indicates that the car is slowing down.

From the question we can see that the:

initial velocity(u) is + 100 m/s (to the right)

Final velocity (v) is 0 since the car comes to stop

Time (t) is 20 s

We can use the formula

a= (v-u)/t to find the acceleration(a) of the car.

Now Substituting the values in the formula given above we get:

a=(0-100)/20

a= \(-5m/s^2\)

Therefore, the acceleration of the car is \(-5 m/s^2\). The negative sign in the answer indicates that the acceleration is in the opposite direction to the initial velocity, which means that the car is slowing down or decelerating.

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Answer:

Explanation:

Please please please what

The arrows are drawn in the figure which shows gravitational forces on each person on earth.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

This is analogous with coulomb's law which gives force between two charges.

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Answer:

True.

Explanation:

If the sum of the external forces on an object is zero, then the sum of the external torques on it  must also be zero.

The net external force and the net external torque acting on the object have to be zero for an object to be in mechanical equilibrium.

Hence, the given statement is true.

The apparatus that can used to measure the mass of the wooden block​ by the student is called beam balance.

A beam balance, often referred to as a double-pan balance, is a straightforward tool for determining an object's weight. Two pans or trays are hung from either end of a horizontal beam that is suspended from a pivot point in the middle.

The thing to be weighed is put on one tray, and then the second tray is filled with standard weights until it balances, showing the weight of the object. From little ones used in laboratories to larger ones used in enterprises, beam balances can be found in a variety of shapes and sizes. Because they are precise and operate without electricity or batteries, they are widely used.

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Element molecules consist of a single type of atom and are held together by covalent bonds. The model would have uniform-colored balls connected by sticks representing these bonds.

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The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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Answer:

Textbook

Explanation:

Pretty obvious thi :v

Answer:

OA

Explanation:

Text books are often reviewed by experts hence, is likely to be biased.

At a divergent boundary, heat and pressure can cause metamorphism, magma can solidify to form igneous rocks, and sediments can accumulate and lithify to form sedimentary rocks. These three processes contribute to the formation of various types of rocks.

At a divergent boundary, three main processes occur that can lead to the formation of metamorphic, igneous, and sedimentary rocks:

1. Metamorphic rocks: Heat and pressure from the divergent boundary can cause existing rocks to be metamorphosed, or transformed, into new rocks with different textures and mineral compositions. This process is called metamorphism.

2. Igneous rocks: Magma, which is molten rock, can rise to the surface at a divergent boundary and cool and solidify to form igneous rocks. This process is called solidification or crystallization.

3. Sedimentary rocks: Sediments, such as sand and mud, can accumulate in the low-lying areas near a divergent boundary, such as in rift valleys or on the continental shelf. Over time, these sediments can be compacted and cemented together to form sedimentary rocks. This process is called lithification.

Hence, Heat and pressure at a divergent boundary can produce metamorphism, solidify magma to create igneous rocks, and accumulate and lithify sediment to create sedimentary rocks. Different sorts of rocks are formed as a result of these three processes.

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The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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Answer:

Thus, the average velocity is 9.73 m/s.

Explanation:

The velocity is given by the rate of change of position.  

initial position, A = (9.2, 3.1) m

final position, B = (72.2, 77.2) m

time, t = 10 s

The velocity is given by

\(\overrightarrow{v} =\frac{\overrightarrow{B}-\overrightarrow{A}}{t}\\\overrightarrow{v}=\frac{(72.2-9.2)\widehat{i} - (77.2-3.1)\widehat{j}}{10}\\\overrightarrow{v}=\frac{63 \widehat{i} - 74.1\widehat{j}}{10}\overrightarrow{v} =6.3 \widehat{i} - 7.41 \widehat{j}\\v =\sqrt{6.3^{2}+7.41^{2}}v = 9.73 m/s\)

The maximum height to which block 1 rises after the collision   is 0.56m

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A block of mass m1 = 5.00kg is released from A. It makes a head-on elastic collision at B with a block of mass m2= 10.0 kg that is initially at rest.

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

Kinetic energy before collision = Potential energy after collision

1/2 mu² =mgh

The velocity at the bottom, when the height h = 5m, is

u= √2gh

u = √2x 9.81 x5

u = 9.9 m/s

For elastic head on collision, final velocity of block 1 after collision is

v₁ = (m₁ -m₂)/ (m₁ +m₂) x u

Putting the values, we get

v₁ = -3.3 m/s

The final velocity of block 2 after collision is

v₂ = 2m₁ / (m₁ +m₂) x u

Putting the values, we get

v₂ =6.6 m/s

For block 1, after collision kinetic energy is converted to potential energy, then the maximum height rises

h' = v₁²/2g

h' = (-3.3)²/(2x9.81)

h' = 0.56 m

Thus, the height gained by the block after collision is 0.56 m.

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Answer:

in the water cycle evaporation occurs when the sunlight warms the surface of the water the heat from the sun makes the water molecules move faster and faster until they move so fast they can escape as a gas once evaporated a molecule from water that vapor spends about 10 days in the air

Answer:

Pretty sure its D.

radiation, chemotherapy, and bone marrow transplant

Explanation:

Radiation, chemotherapy, and bone marrow transplant are the typical treatment for Hodgkin's disease. Therefore, option (D) is correct.

Hodgkin lymphoma can be described as a type of lymphoma, in which cancer forms from a specific type of white blood cell known as lymphocytes, where multinucleated Reed-Sternberg cells are present in the lymph nodes.

The most common symptom of Hodgkin's lymphoma is the painless enlargement of lymph nodes. Hodgkin lymphoma can be treated with radiation therapy, chemotherapy, and stem cell transplantation. The treatment generally depends on how advanced cancer has favorable features.

Radiation and chemotherapy drugs increase the risk of other cancers, lung disease, or heart disease over the subsequent decades.

Hodgkin lymphoma can be distinguished from non-cancerous causes of lymph node swelling and from other cancer. Definitive diagnosis is by lymph node biopsy. Blood tests are performed to assess the function of major organs and safety for chemotherapy.

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Answer: put them in the microwave

Explanation:

Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.

Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:

1200 m / 8 m per hPa = 150 hPa

Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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We can see here that the statement that is correct will be: B. The rock display with larger holes shows petroleum drilling, which is deep underground.

A geologist is a scientist who focuses on the solid components of the Earth, such as minerals and rocks, as well as the processes that shape the planet's surface.

Geologists study the make-up, structure, and past of the Earth's crust in order to comprehend geological processes including mountain creation, earthquake and volcanic activity, and the exploitation of natural resources. They frequently perform fieldwork, gathering samples, running surveys, and researching geological formations.

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The complete question is that:

Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? (1 point)

A. The rock display with smaller holes shows copper drilling, which is deep underground.

B. The rock display with larger holes shows petroleum drilling, which is deep underground.

C. The rock display with smaller holes shows petroleum drilling, which is closer to the surface.

D. The rock display with larger holes shows copper drilling, which is closer to the surface.

Answer:

Slope measures the rate of change in the dependent variable as the independent variable changes.

Explanation:

Answer:

(Question) Which type of wave needs a medium to travel?

(Answer) sound waves, because they travel by oscillating molecules

(Question) What do both sound and light waves transfer?

(Answer) energy

(Question) How does an increase in amplitude affect sound and light waves?

(Answer) louder sound and brighter light

(Question) What happens to the wavelength when the frequency increases?

(Answer) The wavelength decreases.

(Question) Which of the following is true about sound waves?

(Answer) Sound moves faster in the ocean than in the air.

Explanation:

i just finished the quick check UwU

Answer:

if its adding its 9 if its multiplying its 18 if its division its 2

The magnitude of the electric field along the positive z axis is kqz/√(z^2+a^2)^3/2 , the angular frequency of these oscillations is √(kqq0/ma^3)

1. Given that a uniformly charged ring in the xy plane, centered at the origin.

Radius of the ring(r) = a

positive charge distributed evenly along its circumference = q

k= 1/4piepsion

The electric field can be described as, E = kq/r^2

The force exerted on an electric charge by a charge is F = q0E

Any vector can be projected along the z = A(z)=Acosθ

We know that ∑F =ma

Acceleration along z axis = a =d^2z/dt^2

The equation of motion for a simple harmonic oscillation along z is d^2z/dt^2 = -ω^2z

Here,  ω is the cosine function in a right-angled triangle is cosθ = z/√(z^2+a^2)

dE(z)=dEcosθ we know that E = kq/z^2+a^2

To calculate the magnitude of the electric field caused by complete rings, integrate dE(z)=dEcosθ

E(z) = Ecosθ = kq/(z^2+a^2) x  z/√(z^2+a^2)

E(z) = kqz/(z^2+a^2)^3/2

2. We know that F= q0E = kqq0z/(z^2+a^2)^3/2

Given The ball will oscillate along the z axis between z=d and z=-d in simple harmonic motion. Let z =d

F = kqq0d/(d^2+a^2)^3/2 = kqq0d/a^3

Force at any point along z = - kqq0z/a^3

We know F = ma =  

- kqq0z/a^3 = md^2z/dt^2

d^2z/dt^2= - kqq0z/ma^3

This equation of motion can be compared with the equation of motion for simple harmonic motions to find the angular frequency.

ω =√(kqq0/ma^3)

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The distance that the bullet penetrates is 0.03m.

Given data:

The mass of the bullet is

m = 25 g = 0.025 kg

The bullet's initial velocity is

u = 350 m/s

The final velocity of the bullet is

v = 0

The average force opposing the motion is

F = 50000N

From Newton's second law, the acceleration derived as,

F = m. a.

a = F. m..........(1)

Substituting values in equation (1), we get:

a = 50000 N / 0.025 kg = 2×106 m/s 2

The equation of motion is,

v 2=u 2−2 a S

2 a S=u 2−v 2

S = u 2−v 2/2 a.......(2)

Substituting values in equation (2), we get:

S = (350 m/s)2−0/2(2×106 m/s 2)

 =12.25×104 m/s 4×106 m/s 2=0.03m

here, the distance that bullet penetrates is 0.03m.

Kinetic energy has the following formula: K.E. = 1/2 m v 2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kg/m per second squared if the mass is measured in kg and the velocity is measured in meters per second.

Radiant, thermal, electrical, and mechanical kinetic energies are the basic categories.

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Answer:

my friend give options .............

Answer:

(a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be \(723.91>SSD>620.2\)

(c), The SSD will be 910.5 ft.

Explanation:

Given that,

Speed = 70 mph

Suppose, a perception reaction time of 2.5 sec and the coefficient of friction is 0.35

We need to calculate the stopping sight distance

Using formula of SSD

\(SSD=1.47\times v\times t+\dfrac{v^2}{30\times(f\pm g)}\)

Where, v = speed of vehicle

t = perception reaction time

f = coefficient of friction

g = gradient of road

(a). If the gradient of road is zero.

Then, the stopping sight distance will be

\(SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35)}\)

\(SSD=723.9\ ft\)

(b-1). If the gradient of road is 0.1

Then, the stopping sight distance will be

\(SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35+0.1)}\)

\(SSD=620.2\ ft\)

(b-2). If the grade continuously decrease then the SSD will be increase.

But if the grade is increase then the SSD will be decrease and for flat grade the SSD will be more.

So, The SSD will be \(723.91>SSD>620.2\)

(c). When the vehicle is traveling downhill on a roadway of constant grade then the vehicle take will be more SSD

So, The SSD will be

\(SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35-0.1)}\)

\(SSD=910.5\ ft\)

Hence, (a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be \(723.91>SSD>620.2\)

(c), The SSD will be 910.5 ft.

Answer:

Fc=mv2/r v=√(Fcr/m) v=√[(3.6 N)(0.38 m)/(0.0012kg)] v=33.76388603 m/s v=38 m/s

Explanation:

Answer:

v = 6.89 [m/s]

velocity = 0

Explanation:

To solve this problem we must use the definition of speed which is defined by the following expression of physics, such as the relationship between distance and time.

v = x/t

where:

v = speed [m/s]

x = distance = 400 [m]

t = time = 58 [s]

v = 400/58

v = 6.89 [m/s]

The velocity is a vector, since the racing car moves in circles IE its movement started where it ended, its velocity is zero.