Two bodies, A and B, have equal kinetic energies. The mass of A is nine times that of B. The ratio of the momentum of A to that of B is:_______

a. 1:9
b. 1:3
c. 1:1
d. 3:1
e. 9:1

Answer:

The Cascadia Subduction Zone has not produced an earthquake since 1700 and is building up pressure where the Juan de Fuca Plate is subsiding underneath the North American plate.

Explanation:

At depths shallower than 30 km (19 mi) or so, the Cascadia zone is locked by friction while stress slowly builds up as the subduction forces act, until the fault's frictional strength is exceeded and the rocks slip past each other along the fault in a megathrust earthquake. Below 30 km (19 mi) the plate interface exhibits episodic tremor and slip .

Answer:

Explanation:

Period is : \(T=\frac{t}{n}=\frac{20}{100}=0.2\) s

Answer:fuafnshf dj en jz

Explanation:

Can. Nd I do j dj cdj an man Jaz jxn nah an b

Answer:

B

Explanation:

If you try the experiment yourself, You will see that a hot piece of metal has and sustains that thermal energy until that piece of metal eventually cools off.

On the other hand, it takes a while for the cold piece of metal to heat up. So, therefore, it does not contain thermal energy for that long period until it is thoroughly heated up.

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The nonmechanical energy or the loss of energy after the collision will be equal to  \(E=6\ J\)

The conservation of the momentum is defined as when two bodies collide with each other then the total energy of the masses will remain constant.

It is given in the question that

Mass of the body X is  \(M_X=4\ kg\)

The velocity of the body X is  =\(V_x=3 \ \frac{m}{s}\)

Mass of the body Y is   \(M_Y= 2\ kg\)

The velocity of body Y is \(V_y= 0\)

Now to find out the energy converted after the collision we will first find the final velocity of both the bodies.

Now from the conservation of the momentum

\(M_X V_X +M_YV_Y=(M_X+M_Y)V_F\)

\((4\times 3)+(2\times0)=(4+2)\times V_F\)

\(V_F= \dfrac{12}{6}\)

\(V_F = 2 \frac{m}{s}\)

Now to find the Change in the energy of the body

\(\Delta E=E_i-E_f\)

\(\Delta E=\dfrac{1}{2} M_XV_X^2+\dfrac{1}{2} M_YV_Y^2-\dfrac{1}{2} (M_X+M_Y)V_F^2\)

\(\Delta E=\dfrac{1}{2} (4)(3^2)+\dfrac{1}{2} (2)(0^2)-\dfrac{1}{2} ( 4+2) 2^2\)

\(\Delta E= 6\ J\)

Thus the nonmechanical energy or the loss of energy after the collision will be equal to  \(E=6\ J\)

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Set of equation which is true for the situation is

c) 2SA = SB  and 2BA=BB

Force applied perpendicular to the surface of an object per unit area is called pressure

SI unit of pressure is one newton per square meter (N/m2).

Given, length = 3 foot, width= 1 foot and height = 1 foot

1foot = 0.305m

Volume of tank A = 3*0.305*0.305*0.305

= 0.085

density of water= 1000kg/m^3

Pressure= 1000kg/m^3 *gravity * height

=1000kg/m^3 * 9.8 m/s^2* 0.305

=2989 N

Force exerted by water at bottom= P * A

                                                        = 2989*0.085

                                                         =254.065 Nm^2

similarly, for tank B

Given ,length = 6 foot, width =1 foot and height= 1foot

Volume of tank B = 6*0.305*0.305*0.305

                               =0.17

pressure= 1000kg/m^3 * 9.8m/s^2 * 0.305

               = 2989 N

Force exerted by water at bottom = P*A

                                                         = 2989 * 0.17

                                                          =508.13 Nm^2

Hence proved that pressure exerted by tank B is twice that of tank A.

And same goes for pressure exerted on the side of the tank.

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Answer:

Forwarded

Explanation:

Answer:

Hope this is helpful!

Explanation:

In every form of collision the momentum is conserved and it is the same before and after the collision, but in perfectly elastic collision, there is no loss of kinetic energy in the collision. In an inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision. Any macroscopic collision between objects will convert some of the kinetic energy into internal energy and other forms of energy.

Assuming the plane increases in speed steadily, the distance it travelled during the take-off is 7150ft

Given the data in the question.

Since the plane will start at rest,

Initial velocity; \(u = 0m/s\)

Final speed or velocity at take off; \(v = 150mph = 67.056 m/s\)

Time taken for the plane to reach the given speed; \(t = 65.0s\)

First, we need to find the acceleration of the plane using the first equation of motion;

\(v = u + at\)

We make "a" the subject of the formula

\(a = \frac{v - u}{t}\)

Now, substitute in our given values and solve for "a"

\(a = \frac{(67.056m/s) - (0m/s)}{65s}\)

\(a = 1.03163 m/s^2\)

Now, to get the distance travelled by the plane before take off, we use the second equation of motion;

\(s = ut + \frac{1}{2}at^2\)

We substitute in our values and solve for "s"

\(s = (0m/s * 65.0m/s) + ( \frac{1}{2}* 1.03163m/s^2 * (65.0s)^2)\)

\(s = \frac{1}{2} * (1.03163m/s^2) * (4225s^2)\)

\(s = 2179.318 m\)

We now convert our answer from unit of meters to feet

\(s = 7149.99ft \\s = 7150 ft\)

Therefore, distance travelled by the plane during the take-off is 7150ft

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The  engineering company must consider the speed of the train in the design.

The correct answer is option D.

To design a high speed train to transport passengers between Boston and Atlanta, the engineering company must include the following design criterion in the project:

Thus, the only statement in all the given options that considered speed of the train is option D.

"D. The train must be able to maintain a speed of 250 km/h."

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Answer:

The train must provide a smooth ride for passengers between bosten and atlanta

Explanation:

(a) The force is 12 N. (b) The normal force between the block and incline is  46.2 N. (c) The force of friction on the block is 12 N.

We can solve this problem using Newton's laws of motion and the equations of motion for objects on inclined planes.

(a) To find the force applied to the block, we can use the equation:

\(F_a_p_p_l_i_e_d = m * a\)

here,\(F_a_p_p_l_i_e_d\) is applied force,

m is mass of the block, and

a is acceleration of the block.

Reserving values:-

\(F_a_p_p_l_i_e_d = (5.2 kg) * (2.3 m/s^2) = 12 N\)

Therefore, the force applied on block is 12 N.

(b) To find the normal force between the block and the incline, we can use the component of the force of gravity that is perpendicular to the incline:-

\(F_n_o_r_m = m * g * cos\theta\)

here,

m is mass of the block,

g is acceleration due to gravity, and

theta is angle of the incline.

Reserving values:-

\(F_n_o_r_m = (5.2 kg) * (9.81 m/s^2) * cos25.0 = 46.2 N\)

Therefore, the normal force between the block and the incline is about 46.2 N.

(c) To find the force of friction on the block, we need to compare the applied force to the maximum frictional force that the surface can provide, which is given by:

\(F_f_r_i_c_t_i_o_n_,_m_a_x = mu * F_n_o_r_m\)

here, mu is coefficient of friction and

\(F_n_o_r_m\) is normal force.

The force of friction acts in the opposite direction to the motion of the block, so it will be downhill in this case. If the block is moving uphill, then the force of friction would be uphill instead.

Reserving values:-

\(F_f_r_i_c_t_i_o_n_,_m_a_x = (0.26) * (46.2 N) = 12.0 N\)

Since the applied force of 12 N is equal to the maximum frictional force, the block will slide with a constant velocity. Therefore, the force of friction on the block is 12 N.

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Explanation:

Sooooo, first,

Constant Speed means that the body isn't accelerating.

a= 0

Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.

The force that pulls the body downwards is given by,

F = mgsin40°

F= 18.898N

P -(F+Fr) = ma, but, a= 0

P = F + Fr

Fr = 26-18.898

= 7.102N

If the block must move down the incline, Q and Fr will act in the same direction.

Q + Fr = F

Q = 11.796N

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

Answer: answer C

Explanation:

Your welcome

Answer:Refraction

Explanation:

or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.

The tower's height would be around 143 m tall.

Solve for the length of the pendulum using the equation for the period of a simple pendulum.

T = 2π√(l/g)

where l = length of pendulum which is equal to height of tower because it touches the almost the floor

T = time, 24 seconds and

g = acceleration due to gravity 9.8 m/s².

Substitute the given values:

24s = 2π√(l/ 9.8 m/s²)

24/2π = √(l/ 9.8 m/s²)

l = (24/2π)² x 9.8 m/s²

l = (12/π)² x 9.8 m/s²

l = 14.59 x 9.8 m/s²

l = 142.982

Therefore, the height of the tower would be 143 m approximately.

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Answer:

Explanation:

The solar-powered reverse-osmosis (RO) water plant would likely fall under the category of "durable goods" or "capital goods."

Durable goods, also known as consumer durables, are goods that are expected to last for a period of three years or more. Capital goods, on the other hand, are goods used in the production of other goods and services and are expected to last for several years.

The characteristics of durable goods include:

Long-lasting and expected to last several years

High initial cost

Typically used for personal or household consumption

Often purchased infrequently

Can appreciate in value over time

The characteristics of capital goods include:

Long-lasting and expected to last several years

High initial cost

Used in the production of other goods and services

Often purchased by businesses or industries

Depreciate in value over time as they are used up in the production process.

Given that the solar-powered RO water plant is expected to last for several years, is used in the production of water for personal or household consumption, and has a high initial cost, it is likely to fall under the category of durable goods.

As we know larger the area of contact lesser the pressure. So, in order to reduce the pressure heavy vehicles have broad tyres to increase the area of contact with the ground. Heavy vehicles have broad tyres because broad tyres have large area of contact and less pressure on the ground.

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500 miles/hr West

Because it has magnitude and direction

Answer:

2.753*10^-11N

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

Hence the gravitational force between the asteroid is 2.753*10^-11N

With a current shunt, the current is obtained by measuring voltage across the current shunt and calculating using Ohm's Law.

A current shunt is a device that is used to measure electric current. It is a small resistor placed in parallel with the load (or the element being measured), that creates a known small voltage drop proportional to the current flowing through it.

By measuring this voltage drop and using Ohm's law, the current flowing through the shunt (and the load) can be calculated. Current shunts are commonly used in high-current applications, such as in power plants, electrical distribution systems, and electric vehicles.

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With a current shunt, the current is obtained by measuring the voltage drop across the current shunt and calculating using Ohm’s Law. A current shunt is a device that creates a low-resistance path for electric current, to allow it to pass around another point in the circuit. In current measuring, shunts allow the measurement of high current values by placing a resistor of low, known resistance in parallel with a voltmeter.

Answer:  1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.

2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.

3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.

4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.

5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.

Explanation:

I hope this helps!

Answer:

70m/s²

Explanation:

we will use the first equation of Dalton to find it

Answer:

When an object is thrown, the thrower pushes the object. This causes the object to move in a  

Explanation:

Answer:

Quadrupled

Explanation:

Kinetic energy = 1/2×mv^2

m= mass

v= velocity of object

Since mass is not changed

Kinetic energy is directly proportional to v^2

When v is doubled. v^2 is increased fourfold

[( v×2) ×(v× 2)] = v^2 ×4

So Kinetic energy is increased fourfold

Given,

The angle of projection, θ_D=35.0°

The time of flight, T=45.0 s

The height, h=3.30 km=3300 m

A.

The time of flight of a projectile is given by,

Where u is the initial velocity of the magma chunk and g is the acceleration due to gravity.

On substituting the known values,

Thus the initial speed of the magma chunk is 384.43 m/s

B. The horizontal distance of the flight of the magma chunk is given by,

Where u_x is the horizontal component of the initial velocity.

On substituting the known values,

Thus the horizontal distance of the magma is 14.17 km

Answer:

Gravitational force related to distance because when an object is closer to the center of the earth the stronger the gravitational force is the farther an objects it from the center of the earth the weaker the gravitational force is. For example if you are on the moon there is no gravity because the gravitational force of the moon to the center of the earth is father away then for example standing on earth.

The maximum height reached while running is calculated to be 0.75m.

The formula for the maximum height of the projectile motion is given by

H = u² (sin θ)²/2g

where, θ is the angle made with the horizontal

H is the maximum height reached

g is the acceleration due to gravity

u is the initial velocity

Given that, u = 6 m/s

g = 10 m/s²

θ = 40°

Substituting the above values, we have,

H = u² (sin θ)²/2g = 6² * (sin 40°)² / 2 * 10 = 36* 0.414/20 = 0.75 m

Thus, the maximum height reached while running is 0.75m.

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The mass of the bucket of water is 52.08kg whose kinetic energy is 15,000J with the speed of 24 m/s.

Kinetic energy is defined as the energy which is due to the motion of an object. When we want to accelerate an object, we must apply a force, thus by applying a force we need to do work. After the work is done, energy has been transferred to the object which will continue to move with a new constant speed.

The kinetic energy is given by

\(K.E.= \frac{1}{2} mass* velocity^2\)

For above given example,

K.E.= 15,000 J

velocity= 24m/s

\(15000= 1/2 mass *\) \((24)^2\)

\(\frac{15000* 2}{24*24} = Mass\)

\(Mass= \frac{30000}{576}\)

Mass= 52.08 kg

Thus, the mass of the bucket of water is 52.08kg whose kinetic energy is 15,000J with the speed of 24 m/s.

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