Answer:
The ants would just carry it and fight for the way home, so if the other ant loses the cake would just be on that same spot till the ants get more ants from their home.
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A person pushes a 11.5KG lawn mower with an applied force of 70.0N along the 45.0-degree-handle. if the lawn mower moves at a constant velocity
Determine the net force on the mower:
Fnet=__N
Determine the horizontal component of applied force on the mower:
Fx=__N (round to 3 digits)
Determine the horizontal frictional force acting on the mower
Ff=__N (Round to 3 digits)
Calculate the applied force the person must exert on the mower for it to accelerate at a rate of 1.00m/s^2
F=__N (round to 3 digits)
Force is a vector quantity hence it can be resolved into a vertical and a horizontal components.
1) The horizontal component of the applied force is given by;
Fnet = F cos θ
Fnet = 70.0N × cos (45.0)
Fnet = 49.5 N
2) The horizontal component of the frictional force is;
F = -Ff + mgsinθ
F = applied force
Ff =mgsinθ - F
Ff = (11 × 10 × sin 45) - 49.5
Ff = 28.3 N
Horizontal component of Ff
28.3 N cos 45 = 19.9 N
3) The applied force is given by;
F = 11 Kg × 1.00m/s^2 = 11.0 N
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Two balls are rolling using the same force. Which law explains why the bowling ball will roll a shorter distance than a soccer ball ?
1. Newton's 1st law
2. Newton's 2nd law
3. Newton's 3rd law
Answer:
newton's 2nd law
Explanation:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
PLEASE HELP! I WILL MARK BRAINLIEST! tight guitar string has a frequency of 560 Hz as its third harmonic. What will be its fundamental frequency if it is fingered at a length of only 60% of its original length?
Answer:
Original fundamental frequency = 311.111 Hz (Approx)
Explanation:
Given:
Frequency (f) = 560 Hz
3rd harmonic
Used length = 60%
Find:
Original fundamental frequency.
Computation:
Fundamental frequency = Frequency (f) / 3rd harmonic
Fundamental frequency = 560 / 3
Original fundamental frequency = 560 / 3(60%)
Original fundamental frequency = 560 / 1.8
Original fundamental frequency = 311.111 Hz (Approx)
Dr. Suarez walks 2.8 km north to get to an observation post, then walks 5.1 km south back to her outpost. Determine her distance.
A.) 2.3 km, north
B.) 7.9 km, south
C.) 7.9 km
D.) 2.3 km
Answer:
C.) 7.9 km
Explanation:
Distance and Displacement
An object who constantly travels for some distances at defined periods of time has a total distance as the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.
Dr. Suarez walks 2.8 km north and then 5.1 km south. The total distance is simply the sum of both distances: 2.8 km + 5.1 km = 7.9 km.
Note the distance does not have any direction (north or south), it's just the number.
Answer: C.) 7.9 km
Josie walks 15 meters north down the freshman hallway. She then walks 25 meters east. Lastly, she walks 15 meters south. What is Josie's displacement? *
Answer:
the answer is yours a calculated
which other team sport basketball is the most like.
hi
Answer: mmm... If you mean most like Basketball it's net ball but i don't know much about Basket ball teams
Explanation:
Please help me with this!
A student has a mineral sample with a mass of 35g. She then puts 20
mL of water into a graduated cylinder. When she puts the sample
into the cylinder, the water level rises to 30 mL. She then compares
the results to the following:
Augite 3.5 g/cm3
Galena 7.5 g/cm3
Pyrite 5.0 g/cm3
Sphalerite 4.0 g/cm3
Which substance did she find the density for?
The student finds the density for Augite = 3.5 g/cm³
Mass of the metal = 35g
Volume of water in the graduated cylinder = 20 mL
When the metal is placed in the cylinder filled with water, the water level rises to 30 mL.
So, the volume of the metal = 30 - 20 = 10 mL
1 mL = 1cm³
∴ 10 mL = 10 cm³
Now, we know that,
\(Density = \frac{Mass}{Volume}\)
\(Density = \frac{35g}{10 cm^{3} }\)
\(Density = 3.5 g/cm^{3}\)
Therefore, the student finds the density for Augite = 3.5 g/cm³
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a spoon can appear broken in a glass of water due to the wave interaction known as
The wave interaction that can cause a spoon to appear broken in a glass of water is called refraction.
Refraction occurs when a wave, such as light, passes from one medium to another with a different density or refractive index. When light waves travel from air into water, for example, they undergo a change in direction due to the change in speed caused by the difference in optical properties between the two mediums.
In the case of the spoon in a glass of water, the light waves coming from the spoon encounter the air-water interface. As they pass from air into water, they undergo refraction, causing a change in their direction. This change in direction can create an optical illusion where the spoon appears to be bent or broken at the water's surface.
This phenomenon is a result of the bending of light rays as they pass through different mediums with different refractive indices, and it is a common example of how refraction can distort the perception of objects when viewed through different mediums.
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A system consists of electrons, protons, and neutrons . It contains 250 neutrons and 150 protons. If the total charge of the system is -35e, what is the mass of system?
Answer:
250 - 35e = 215e
150 - 35e = 115e
Explanation:
I did it mentally
A cart of mass m is moving with negligible friction along a track with known speed y, to the right. It
collides with and sticks to a cart of mass 4m moving with known speed y, to the right. Which of the two
principles, conservation of momentum and conservation of mechanical energy, must be applied to determine
the final speed of the carts, and why?
The principle of conservation of momentum must be applied to determine the final speed of the carts. Conservation of momentum states that the total momentum of a system remains constant if no external forces act on it.
In this scenario, the collision between the two carts is an isolated system, meaning no external forces are involved. Therefore, the initial momentum of the system before the collision should be equal to the final momentum after the collision. Since the carts stick together after the collision, they move as a single combined mass. The initial momentum of the system is given by the sum of the individual momenta of the two carts. After the collision, the combined mass moves with a final velocity, which is the same for both carts since they are now connected.
On the other hand, the principle of conservation of mechanical energy cannot be directly applied in this scenario. Conservation of mechanical energy states that the total mechanical energy of a system remains constant if no external non-conservative forces (such as friction or air resistance) act on it. However, in this case, the collision is not perfectly elastic, and there is a change in the mechanical energy due to the deformation of the carts and the conversion of kinetic energy into other forms of energy, such as heat or sound. Therefore, conservation of mechanical energy cannot be used to determine the final speed of the carts.
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what would be the noontime altitude of the sun at the time of the summer solstice?
The highest angle, which is 23.5°, occurs at the summer solstice. The greatest altitude angle at midday is therefore 90° 40° + 23.5° Equals 73.5°.
What is the summer solstice's noon sun angle?On the solstice, the sun's angle at noon lowers by 1 degree for every point of latitude that is moved away from 23.5o. On the summer, the sun's angle at noon lowers by 1 degree for every point of latitude that is moved away from 23.5o.
What is the summertime sun's altitude?Every day of the year, including the solstices, is the same duration of 12 hours. arcs of the solstices as seen from 20° latitude. The Sun reaches its highest point at 46.56° in the winter and 93.44° in the summer.
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A projectile is fired horizontally off the top of a cliff with an initial velocity of 30 m/s. It hits the ground 2.0 seconds later. How far from the base of the cliff does the projectile land?
Answer:
The horizontal distance traveled by the projectile is 60 m
Explanation:
Given;
initial horizontal velocity of the projectile, Vₓ = 30 m/s
time of the motion of the projectile, t = 2 s
The horizontal distance traveled by the projectile is given by the range of the projection;
X = Vₓt
X = 30 x 2
X = 60 m
Therefore, the horizontal distance traveled by the projectile is 60 m
Therefoe
A rod of length 2d0 and mass 2m0 is at rest on a flat, horizontal surface. One end of the rod is connected to a pivot that the rod will rotate around if acted upon by a net torque. A sphere of mass m0 is launched horizontally toward the free end of the rod with velocity v0, as shown in the figure. After the sphere collides with the rod, the sphere sticks to the rod and both objects rotate around the pivot with a common angular velocity. Which of the following predictions is correct about angular momentum and rotational kinetic energy of the sphere-rod system immediately before the collision and immediately after the collision?.
The angular momentum immediately before and after the collision is equal. The rotational kinetic energy before the collision is greater than the rotational kinetic energy after the collision.
What are rotational kinetic energy and angular momentum?When a body is rotating in a plane about a center, the energy possessed by the body is known as rotational kinetic energy.
Angular momentum is the momentum of a body having circular motion.
According to the law of conservation of angular momentum, the momentum remains conserved before and after the collision.
In the given sphere rod system, after the sphere (m0) sticks to the rod(2m0), the mass increases to 3m0 due to which the moment of inertia is increased but the speed is decreased.
Rotational Kinetic Energy =\(\frac{1}{2}\)Iω²
Thus, the angular momentum immediately before and after the collision is equal. The rotational kinetic energy before the collision is greater than the rotational kinetic energy after the collision.
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A positive test charge of 6.45 × 10^−5 C is placed in an electric field of 50.99 N/C intensity. What is the strength of the force exerted on the test charge?
Answer in units of N.
The electric force is 3.3 * 10-3 N.
What is the magnitude of the force?Electric field intensity is a measure of the electric force acting on a charged particle in an electric field. It is defined as the force per unit charge that acts on a test charge placed in an electric field. The formula for electric field intensity (E) is given by:
E = F / q
where F is the force acting on a test charge of magnitude q in the electric field.
We haver that;
E = F/q
E = electric field intensity
F = force
q = magnitude of charge
Then;
F = Eq
F = 50.99 N/C * 6.45 × 10^−5 C
F = 3.3 * 10-3 N
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an undamped 1.21 kg1.21 kg horizontal spring oscillator has a spring constant of 26.1 n/m.26.1 n/m. while oscillating, it is found to have a speed of 2.31 m/s2.31 m/s as it passes through its equilibrium position. what is its amplitude ????a of oscillation?
The kinetic energy in the spring is equal to the mechanical work done by the spring
The kinetic energy in then spring is
E = 1 / 2 kA2
The mechanical work done by the spring is,
E= 1 / 2 mv2
Compare the above two equations to find the amplitude of oscillation:
1 / 1 kA2 = 1 / 2 mv2
A = v√ m/k
(3.58 m/s) √ 1.12 kg / 32.3 N/m
= 0.66m
The mechanical work done by the spring is,
E = 1/2 mv2
= 1 / 2 (1.12 kg) (3.58 m/s)2
= 7.17 J
Work modifications the quantity of mechanical and internal energy possessed by gadgets. Whole work is achieved on a machine or item, energy is introduced to it.
The character of work achieved can be categorised in three classes. they are +ve work, -ve work and zero work. The character of work relies upon on the perspective among pressure and displacement.
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Una botella vacía tiene una masa de 24.25g y de 86.55g completamente llena de agua, se vacia el agua y se llena nuevamente con 123.95g de solvente tetracloruro de carbono, ¿cual es la densidad del solvente?
Answer:
La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.
Explanation:
La masa de agua contenida dentro de la botella es igual a la diferencia entre la masa pesada totalmente llena y la masa pesada totalmente vacía, es decir:
\(m_{w} = 86.55\,g-24.25\,g\)
\(m_{w} = 62.3\,g\)
Ahora, de acuerdo con la definición de densidad, la masa es directamente proporcional a la densidad, entonces, podemos calcular la densidad del solvente mediante la siguiente relación:
\(\frac{m_{x}}{m_{w}} = \frac{\rho_{x}}{\rho_{w}}\) (1)
Donde:
\(m_{x}\) - Masa del tetracloruro de carbono, en gramos.
\(m_{w}\) - Masa del agua, en gramos.
\(\rho_{x}\) - Densidad del tetracloruro de carbono, en gramos por centímetro cúbico.
\(\rho_{w}\) - Densidad del agua, en gramos por centímetro cúbico.
Si sabemos que \(m_{x} = 123.95\,g\), \(m_{w} = 62.3\,g\) y \(\rho_{w} = 1\,\frac{g}{cm^{3}}\), entonces la densidad del tetracloruro de carbono es:
\(\rho_{x} = \left(\frac{m_{x}}{m_{w}} \right)\cdot \rho_{w}\)
\(\rho_{x} = 1.990\,\frac{g}{cm^{3}}\)
La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.
when looking at a motion with constant acceleration the velocity , how to determine if increasing or decreasing
Answer:
a = (v2 - v1) / t
For constant acceleration (positive) v2 (final velocity) must be greater than v1 (initial velocity)
Note that velocity is a vector quantity in this equation
For instance in the case of a freely falling body one might have v1 as 9.8 m/s and v2 as 29.4 m/s in 3 sec giving
a = (-29.4 - (-9.8)) / 3 = -19.6 m/s^2 where the positive direction was chosen as upwards and the acceleration is negative or downwards
Which of the following does not need to be considered when selecting a bow?
A. Is the bow made by hand?
B. Will you shoot right or left handed?
C. Will the bow be used for target shooting, hunting or both?
D. Can the bow be held without straining?
Answer:
A. Is the bow made by hand?
Explanation:
Hope this helps.
A ball was thrown from the ground at an angle 0 with a velocity v. The ball reached a maximum height of 8 m and a maximum range of 15 m. Calculate the value of 0. Let g=1 m/s²
Answer:
θ ≈ 65°
Explanation:
From the question given above, the following data were obtained:
Maximum height (H) = 8 m
Range (R) = 15 m
Initial velocity (u) = v
Angle θ =?
H = u²Sine²θ / 2g
8 = v²Sine²θ / 2g
Cross multiply
8 × 2g = v²Sine²θ
16g = v²Sine²θ
Divide both side by Sine²θ
v² = 16g / Sine²θ.... (1)
R = u²Sine2θ / g
15 = v²Sine2θ / g
Cross multiply
15 × g = v²Sine2θ
15g = v²Sine2θ
Divide both side by Sine2θ
v² = 15g / Sine 2θ... (2)
Summary:
v² = 16g / Sine²θ.... (1)
v² = 15g / Sine 2θ... (2)
Equate equation 1 and 2
16g / Sine²θ = 15g / Sine 2θ
16 / Sine²θ = 15 / Sine 2θ
Recall:
Sine²θ = SineθSineθ
Sine 2θ = 2SineθCosθ
16 / Sine²θ = 15 / Sine 2θ
16 / SineθSineθ = 15 / 2SineθCosθ
16 / Sineθ = 15 / 2Cosθ
Cross multiply
15 × Sineθ = 16 × 2Cosθ
15Sineθ = 32Cosθ
Divide both side by Cosθ
15Sineθ / Cosθ = 32
Divide both side by 15
Sineθ / Cosθ = 32/15
Recall:
Sineθ / Cosθ = Tanθ
Sineθ / Cosθ = 32/15
Tanθ = 32/15
Tanθ = 2.1333
Take the inverse of Tan
θ = Tan¯¹ 2.1333
θ ≈ 65°
calculate the mass of air in a room if the floor dimensions are 10m × 12m and height is 400 cm the density of air is 1 .26 kg/M³ 3
Explanation:
first find the volume of room --->
\(v \: = 10 \times 12 \times (400 \times {10}^{ - 2} ) \times = 480 \: {m}^{3} \)
then find the mass
\(mass \: = \: density \: \times \: volume \: = 480 \times 1.26 = 604.8 \: kg\)
according to the sine-wave generated by three phase power, what is the measured separation of each phase?
Three sine waves separated by 120 degrees make up three-phase power. An AC generator with three separate windings that are each precisely 120 degrees apart generates this type of electricity.
What is three phase power ?To supply electricity to data centers, as well as to commercial and industrial buildings that house power-hungry machinery, three-phase alternating current (AC) power is frequently used. This is for good reason, as 3-phase AC power is more efficient and capable of delivering more power than single-phase AC power.
Three-phase power sources are more effective than single-phase power sources when compared. While just requiring one more wire, a three-phase power supply can transmit three times as much power as a single-phase power supply (that is, three wires instead of two).
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How much force is needed to accelerate a 2500 kg car at a rate of 4m/s²?
10,000 N
8,400 N
625 N
7,500 N
Answer:
Momentum (p) is equal to the product of an object's mass (m) and its change in velocity (v).
Change in velocity (v) results in change in momentum (p), which is equal to impulse. Impulse (J) is also equal to an applied force (F) over a period of time (t).
Combining p=mv and J=F t together:
m (v final - v initial) = F t
(2,500 kg) (70 m/s - 30 m/s) = F (10 s)
Explanation:
Solving for F we get:
10,000 N of force
F=ma
F=2500 x 4
F = 10,000 N
a 90 kg fullback running east with a speed of 5.00 m/s is tackled by a 95.0 kg opponent running north with a speed of 3 m/s. if the collision is perfectly inelastic, calculate the speed and direction of the players just after the tackle and determine the mechanical energy lost as results of the collision. account of the missing energy
two twins make a round-trip journey from earth to a star that is 12 light-years distant. alice travels at a speed of 0.6c. bob departs 10 years after alice and travels at a speed of 0.8c. (a) show that the two twins arrive back on earth at the same time. (b) which twin is the younger when they return?
A)To show that the two twins arrive back on earth at the same time, we can use the time dilation formula: t' = t / sqrt(1 - v^2/c^2).
B) Alice is older than Bob when they return to Earth.
Let's use Earth as the observer at rest, and assume that the journey takes 24 years (12 years to the star and 12 years back). Then, Alice travels at a speed of 0.6c for the entire journey, so her time is dilated by a factor of:
t'_Alice = t / sqrt(1 - 0.6^2)
t'_Alice = 24 / sqrt(1 - 0.6^2)
t'_Alice = 40 years
Bob departs 10 years after Alice, so his journey takes 22 years (10 years to the star and 12 years back). He travels at a speed of 0.8c for the entire journey, so his time is dilated by a factor of:
t'_Bob = t / sqrt(1 - 0.8^2)
t'_Bob = 22 / sqrt(1 - 0.8^2)
t'_Bob = 40 years
Let's use Earth as the observer at rest again. For Alice, we have:
t_Alice = t'_Alice * sqrt(1 - 0.6^2)
t_Alice = 40 * sqrt(1 - 0.6^2)
t_Alice = 32 years
For Bob, we have:
t_Bob = t'_Bob * sqrt(1 - 0.8^2)
t_Bob = 40 * sqrt(1 - 0.8^2)
t_Bob = 15 years
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suppose you lift a stone that has a mass of 5.9 kilograms off the floor onto a shelf that is 0.5 meters high. how much work have you done?
Work done to lift the stone of mass 5.9 kg is 28.91 J.
The work done through pressure is made of the displacement and the component of the carried-out force of the object inside the direction of displacement. whilst we push a block with a few pressure ' F ' the body movements with a few accelerations, paintings are carried out. paintings executed is written as W = F.
The paintings executed by using pressure are defined to be manufactured from the aspect of the force in the path of the displacement and the significance of this displacement. formula. work can be calculated by multiplying pressure and Distance within the course of force as follows. W = F × d.
Work is achieved whenever a pressure actions something over a distance. you can calculate the strength transferred, or work carried out, by multiplying the pressure via the space moved in the route of the pressure.
Calculation:-
mass = 5.9
g = 9.8 m/s
f = 0.5 m
work done = mgh
= 5.9 × 9.8 × 0.5 J
= 28.91 J
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A drone traveling horizontally at 100 m/s over flat ground at an elevation of 3000 meters must drop an emergency package on a target on the ground. The trajectory of the package is given by x=100t , y=−4.9t2+3000 ,t≥0 where the origin is the point on the ground directly beneath the drone at the moment of release. How many horizontal meters before the target should the package be released in order to hit the target? Round to the nearest meter.
Answer:
The package should be dropped 244.7 meters before the target
Explanation:
We need to find how long the package will take to hit the ground then solve for position.
y=0
-4.9t^2=-3000
t= sqrt (3000/4.9)
t= 24.74 seconds.
x= 247.4 meters.
a material that is not a mixture; it has the same properties all the way through is called. Its 9 letters long and the second letter is u and the eighth letter is c. Its a crossword clue by the way
Answer: The material that is not a mixture; it has the same properties all the way through is called a substance.
Explanation:
A pure substance is a form of matter that has a constant composition and properties that are constant throughout the sample. Hence, it cannot be separated by physical means. Example: Gold
Mixture is a substance which has two or more components which do not combine chemically and do not have any fixed ratio in which they are present. They can be separated by physical means as well. Example: Air
Thus the material that is not a mixture; it has the same properties all the way through is called a substance.
Convert 3.8 kg to Lbs
Answer:
8.37757
Explanation:
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A bottle of soda always has a space between the cape and the top of the liquid. Explain
Answer:
All soft drinks contain water. When soft drink bottles are chilled in sub-zero temperatures, the water on account of its anomalous expansion expands. Thus, to provide space for expanding water, soft drink bottles are not completely filled as otherwise they will burst.
Explanation:
Answer:
Soft drink bottles are filled leaving some space between the lid/cap and the liquid level.
Explanation:
The reason is that the soft drinks are cooled below room temperature. Sometimes they are kept in the hot Sun and weather. They are subject to a big temperature variation. Also, there are gases like CO2 mixed in the drink. So the gases come out of the liquid and expand due to heat. That creates high pressure.
Water expands when it is cooled to 4 deg. C. But the bottle (glass) contracts when it is cooled. So if there is no air gap, then volume of water (cool drink) will become more than the inside volume of the bottle. Then the bottle will break due to pressure from water expansion around 8 deg. to 4 deg.C.
When a bottle is opened, due to pressure difference, and temperature difference, the gases come out of drink in the form of bubbles. So cold drink overflows out.
Also, the soft drink bottles are capped tightly. When an opener is used to open it using some force upwards, the pulling force also moves the soft drink bottle upwards. So just after the lid comes off, the top part of the drink comes out due to the pull. So some drink spills on people who open or, it falls outside.
In order to prevent these problems, some gap is left open between the surface of the soft drink and the top of the bottle.
If a car travels 20 km at a speed of 20km/h, what will the speed be for the remaining 20km if the average speed of the journey is 24km/h?
Answer:
12
Explanation:
avarage speed = total distance/total time
our total distance is 40km
the first 20km speed was 20km/h, so the time os 1 hour here
for the next 20km, we dont have the time, so let the time here be = x
so total time is x+1 km/h
and total distance is 40km
and the avarage is 24km/h
so =>
\( \frac{40}{1 + x} = 24\)
solve for x to find the time in the second 20km
so x=0.6
then find the speed of the second 20km by diving the distance on time =>
\( \frac{20}{0.6} = 12\)
so the speed in the second 20km is 12km/h