tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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She does 818J work, which is the transfer of energy to or from an item by the application of force along a displacement.

Work is the energy that is transferred when a force acts on an item and moves it. The sum of the force's magnitude, the displacement's magnitude, and the angle's cosine determines the work that a force produces on an item.

Work is force transferred across a distance. Examples of labor include pushing a car up a hill, drawing a captive helium balloon down, and raising an object against the gravitational attraction of the Earth. The mechanical expression of energy is work. The

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A refrigerator that accepts heat from a low-temperature reservoir also rejects heat to the same reservoir.

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Answer:

Forwarded

Explanation:

As vₙ<v, no photoelectron is emitted, thus no extraction work is required.

The minimum frequency of incident radiation below which photoelectric emission or electron emission is not feasible is referred to as the threshold frequency.

The frequency of light at which an electron will be forced to leave a metal surface is referred to as the threshold frequency.

The wavelength of incident radiation is λ = 180nm = 1800A = 1800 * 10⁻¹⁰ m.

Therefore, the frequency of incident radiation is

v = c / λ

v = 3 * 10⁸ / 1800 * 10⁻¹⁰

v = 0.166 * 10¹⁶ Hz

Therefore, threshold frequency is

v₀ = c/λₙ

vₙ = 3 * 10⁸ / 275 * 10⁻¹⁰

vₙ = = 1.09 * 10¹⁶ Hz

As vₙ<v, no photoelectron is emitted.

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Answer:

I AM SO SORRY

but here is the answer

Explanation:

20 j

Explanation:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in

Answer:

The Correct Answer Is b.

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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Answer:

0.33m/\(s^{2}\) East.

Hope this helps you. Do mark me as brainliest.

Answer:  ~Y/n here~ Your answer I believe would be:

A. kinetic energy before the collision equals kinetic energy after the collision.

(Hope this helps!)

(a) The minimum angle above the ground is approximately 16.4°. (B) The initial speed required for the ball to just clear the bar when kicked at 46.0° above the horizontal is approximately 17.4 m/s.

The initial potential energy of the ball equal to the kinetic energy,

mgh = (1/2)mv^2

where m is the mass of the ball, g is acceleration due to gravity, h is the height of the bar above the ground, v is the velocity of the ball.

m(9.81 m/s²)(3.048 m) = (1/2)m v^2

v = √(2g(3.048 m)) = 7.67 m/s

The corresponding launch angle,

θ = sin⁻¹(h/d)

where d is the horizontal distance between the ball and the bar.

θ = sin⁻¹(3.048 m / 10.973 m) = 16.4°

B) The ball has kinetic energy and potential energy,

mgh + (1/2)mv₀² = (1/2)mv²

where v₀ is the initial velocity of the ball, and v is the velocity of the ball just as it clears the bar.

v₀ = √(v² - 2gh)

v₀ = √[(7.67 m/s)² - 2(9.81 m/s²)(3.048 m / sin(46.0°))]

v₀ = 17.4 m/s (to three significant figures)

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Answer:

Yes

Explanation:

Yes. The momentum is the same when the speed of the tennis ball is 18 times greater than the speed of the basketball and the velocities of both objects are in the same direction.

Answer:

speed /wavelength = frequency

f = 3×10*8 /6.5×10*7

f = 4.62

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

eating an apple

Explanation:

Eating food gives your body the nutrients and energy it needs.

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s, Speed it will have when it slides back down to its starting point is 2.36 m/s

The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab). The electromagnetic attraction between charged particles in two contacting surfaces, according to scientists, is what causes it.

using work energy theorem ,

change in kinetic energy = work done by frictional force

\(\frac{1}{2}\) m(\(x^{2}\)-\(y^{2}\)) =  μmghcos30°

where mass is m=200g

x is speed with which it slides back

y is speed at top of metal ramp=3.8 m/s

μ is coefficient of kinetic friction=0.3

g is gravity = 9.8m/\(s^{2}\)

h is height to which hockey puck is reached on metal ramp=1.18m

Substituting the values and solving for speed x,

x=2.36m/s

speed  it will have when it slides back down to its starting point is 2.36m/s

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The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Answer:

27 degrees Fahrenheit is -2.78°c

\( \Large {\underline { \sf {Required \; Solution :}}}\)

We have ―

We've been asked to calculate acceleration.

\(\qquad \implies\boxed{\red{\sf{ a = \dfrac{v-u}{t} }}}\\\)

\( \twoheadrightarrow \quad \sf {a = \dfrac{30-18}{3} \; ms^{-2} } \\ \)

\( \twoheadrightarrow \quad \sf {a =\cancel{ \dfrac{12}{3} \; ms^{-2} }} \\ \)

\(\twoheadrightarrow \quad \boxed{\red{\sf{ a = 4 \; ms^{-2} }}}\\\)

Therefore, acceleration of the car is 4 m/s².

Answer:

it builds muscle cells

Explanation:

took test

Given,

the heights,

h₀ =142 m

hA=17 m

hB=62 m

hC=122 m

When the roller coaster is at the top of the hill at rest, it will have maximum potential energy and minimum, that is zero, kinetic energy. As it rolls down, it gradually loses the potential energy and gains kinetic energy.

From the law of conservation of energy, the potential energy so lost will be equal to the kinetic energy gained by the cart at any given height.

That is,

Where m is the mass of the cart and Δh is the difference in the height.

On rearranging the above equation,

Thus the speed at point A can be calculated as,

On substituting the known values,

Thus the speed of the cart at point A will be 49.5 m/s

The speed of the cart at point B is,

Thus the speed of the cart at point B is 39.6 m/s

The speed of the cart at point C is,

Therefore the speed of the cart at point C is 19.8 m/s

Answer:

The answer is "\(4,500 - 225 \ V\)".

Explanation:

Using formula for calculating the Voltage:

\(M_1=12.5\\\\M_2=250\\\\V_1=4,500 \\\\\bold{\text{Formula: }}\\\\\to \bold{\frac{m_1}{m_2}=\frac{V_2}{V_1}}\\\\\to \frac{12.5}{250}=\frac{V_2}{4,500}\\\\\to 0.05=\frac{v_2}{4,500}\\\\\to 0.05\times 4,500= V_2\\\\\to V_2=225\\\\\)

Hence the range of accelerating in voltage is \(4,500 - 225 \ V\)

Answer:

a)14.17V

b)32.8 x \(10^-^1^2\)J

c)96.9x \(10^-^1^2\)J

d) -64x \(10^-^1^2\)J

Explanation:

Given:

Area 'A'=7.10cm² =>7.1 x \(10^-^4\)m²

voltage '\(V_o\)'=4.8 volt

\(d_o\) = 2.20mm => 2.2 x \(10^-^3\)m

\(d_1\) = 6.50mm => 6.5 x \(10^-^3\)m

a) Capacitance \(C_o\) before push is given by:

\(C_o\) = εA/\(d_o\) =>\(\frac{(8.85*10^-^1^2)(7.1*10^-^4)}{2.2*10^-^3}\)

\(C_o\) =   2.85 x \(10^-^1^2\) F

\(q_o\)=\(C_o\)\(V_o\)=> 2.85 x \(10^-^1^2\) x 4.8

\(q_o\)=1.37 x \(10^-^1^1\) C

Capacitance \(C_1\) after push is given by:

\(C_1\) = εA/\(d_1\) =>\(\frac{(8.85*10^-^1^2)(7.1*10^-^4)}{6.5*10^-^3}\)

\(C_1\) =   9.66 x \(10^-^1^3\)F

\(q_o\)=\(q_1\)

\(q_1\)=\(C_1\)\(V_1\)

Therefore, the potential difference between the plates

\(V_1\) = 1.37 x \(10^-^1^1\) / 9.66 x \(10^-^1^3\) =>14.17V

b) \(U_i=\frac{1}{2}C_oV_o^2 => \frac{1}{2} (2.85*10^-^1^2)(4.8^2)\)

\(U_i=\) 32.8 x \(10^-^1^2\)J

c)\(U_f=\frac{1}{2}C_1V_1^2 => \frac{1}{2} (9.66*10^-^1^3)(14.17^2)\)

\(U_f\)= 96.9x \(10^-^1^2\)J

d) the work required to separate the plates is given by:

workdone=  \(U_i\)-\(U_f\)=> 32.8 x \(10^-^1^2\)J- 96.9x \(10^-^1^2\)J

W≈ -64x \(10^-^1^2\)J

Answer:

A. pushing a car that isn't moving

It is advisable that Jeff should begin to save about 5% of his income to serve as his retirement plan.

Retirement refers to such a time when one is no longer involved in actual work. It is important that a person ought to save up some money for use via a retirement plan.

It is advisable that Jeff should begin to save about 5% of his income to serve as his retirement plan since he still has many years of work ahead of him.

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The gravitational potential energies are 300 kJ and 400 kJ respectively

Gravitational potential energy is a form of potential energy that an object possesses due to its position relative to a reference point in a gravitational field. It is defined as the amount of work that must be done to move an object from its current position to a reference point, without changing its speed or direction.

The gravitational potential energy of an object can be calculated using the formula:

For the first case;

Note that the mass of  2500 L is 2500 Kg

With respect to the floor;

2500 Kg * 10 * 12 = 300 kJ

With respect to the basement;

2500 * 10 * 16 = 400 kJ

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PHYSICS

*not sure about the answer but here we go*

Mass = 425 kg

distance = 614.4 m

acceleration = 1.8 m/s²

Answer :

Count Force first.

\(f \: = m \: \times a\)

F = 425 × 1,8

F = 765 N ✅

Now let's count Work.

\(w \: = \: f \: \times s\)

W = 765 × 614.4

W = 470016 J ✅