TRUE/FALSE. for a power system modeled by its positive squence network both bus addmittance matrix and bus impedance matrix are symmetric

The velocity of the car after 6.9 s if its acceleration is 1.5 m/s² due south would be  10.35 meters / seconds.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

Note that these equations are only valid for a uniform acceleration.

As given in the problem we have to find the velocity of the car we have to find the velocity of the car  after 6.9 s if its acceleration is 1.5 m/s² due south,

The acceleration of the car = 1.5 m/s²

The time taken by the car = 6.9 seconds

By using the first equation of the motion,

v = u + at

v = 0 + 1.5*6.9

v = 10.35 meters / seconds

Thus, the velocity of the car after 6.9 s, if its acceleration is 1.5 m/s² due south, would be  10.35 meters / seconds.

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Answer:

deformation : elastic deformation is reversed when the force is removed. inelastic deformation is not fully reversed when the force is removed – there is a permanent change in shape.

Explanation:

tysm

Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

The kinematics of the uniform motion and the addition of vectors allow finding the results are:

Vectors are quantities that have modulus and direction, so they must be added using vector algebra.

A simple method to perform this addition in the algebraic method which has several parts:

 Indicate that Barry's velocity is constant, let's find using the uniform motion thatthe distance traveled in ad case

              v = \(\frac{\Delta d}{t}\)

              Δd = v t

Where  v is the average velocity, Δd the displacement and t the time

We look for the first distance traveled at speed v₁ = 600 m / s for a time

          t₁ = 2 min = 120 s

          Δd₁ = v₁ t₁

          Δd₁ = 600 120

          Δd₁ = 72 10³ m

Now we look for the second distance traveled for the velocity v₂ = 400 m/s    

  time t₂ = 1 min = 60 s

          Δd₂ = v₂ t₂

          Δd₂ = 400 60

          Δd₂ = 24 103 m

In the attached we can see a diagram of the different Barry trajectories and the coordinate system for the decomposition,

We must be careful all the angles must be measured counterclockwise from the positive side of the axis ax (East)

Let's use trigonometry for each distance

Route 1

          cos (180 -35) = \(\frac{x_1}{\Delta d_1}\)

          sin 145 = \(\frac{y_1}{\Delta d1}\)

          x₁ = Δd₁ cos 125

          y₁ = Δd₁ sin 125

          x₁ = 72 103 are 145 = -58.98 103 m

          y₁ = 72 103 sin 155 = 41.30 10³ m

Route 2

          cos (90+ 30) = \(\frac{x_2}{\Delta d_2}\)

          sin (120) = \(\frac{y_2}{\Delta d_2}\)

          x₂ = Δd₂ cos 120

          y₂ = Δd₂ sin 120

          x₂ = 24 103 cos 120 = -12 10³ m

           y₂ = 24 103 sin 120 = 20,78 10³ m

The component of the resultant vector are

              Rₓ = x₁ + x₂

              R_y = y₁ + y₂

              Rx = - (58.98 + 12) 10³ = -70.98 10³ m

              Ry = (41.30 + 20.78) 10³ m = 62.08 10³ m

We construct the resulting vector

Let's use the Pythagoras' Theorem for the module

             R = \(\sqrt{R_x^2 +R_y^2}\)

             R = \(\sqrt{70.98^2 + 62.08^2}\)   10³

             R = 94.30 10³ m

We use trigonometry for the angle

             tan θ ’= \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{62.08}{70.98}\)

             θ ’= 41.2º

Since the offset in the x axis is negative and the displacement in the y axis is positive, this vector is in the second quadrant, to be written with respect to the positive side of the x axis in a counterclockwise direction

            θ = 180 - θ'

            θ = 180 -41.2

            θ = 138.8º

Finally, let's calculate the speed for the way back, since the total of the trajectory must be 5 min and on the outward trip I spend 3 min, for the return there is a time of t₃ = 2 min = 120 s.

The average speed of the trip should be

             v = \(\frac{\Delta R}{t_3}\)  

             v = \(\frac{94.30}{120} \ 10^3\)

              v = 785.9 m / s

in the opposite direction, that is, the angle must be

               41.2º to the South of the East

In conclusion, using the kinematics of the uniform motion and the addition of vectors, results are:

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Answer:

Explanation:

Answer

How about a thunder storm. I don't know if you live in a city or out in the sticks as I do. Lighting is very obvious and it is not a good idea to be out when experiencing a thunderstorm, especially in an open field. You might be the only thing around that will cause the lightning to be connected to the ground.#  Seconds later, you will hear the thunder which is quite harmless. If you live in the city, observing this is not quite so easy. There are all kinds of buildings around and some of them may block your view.

#The great golfer, Lee Travino, was "hit" by lightening storm twice while playing in tournaments.

Answer:  

4.27s

Explanation:

If "t" represents the time traveled from the time rock 2 is dropped until the collision, then the time traveled for rock 1 = t + 1. And, since rock #1 is dropped making its initial velocity = 0, then:

The distance rock 1 travels is  

x = (0)(t + 1) + 1/2(-9.8)(t + 1)2 = -4.9(t2 + 2t + 1) = -4.9t2 - 9.8t - 4.9

The distance rock 2 travels  

x = -11.3t + 1/2(-9.8)t2 = -11.3t - 4.9t2

For the distances must be equal when the rocks collide:  

-4.9t2 - 9.8t - 4.9 = -11.3t - 4.9t2  

-9.8t - 4.9 = -11.3t  

-4.9 = -1.5t  

t = 3.267 s

Now, the distance they traveled can be found by plugging the 3.267 s back into either equation:

x = -11.3(3.267) - 4.9(3.267)2 = -89.2 m or 89.2 m below where they began

The time the first rock was in the air is t + 1 = 3.267 + 1 = 4.267 s = 4.27 s

Let

First rocks time be x

Second rocks time be x+1

initial velocity=u=11.3m/s

Distance of both rocks be s1 and s2

\(\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2\)

Now

\(\\ \sf\longmapsto s1=11.3x+5x^2\)

\(\\ \sf\longmapsto s2=11.3(x+1)+5(x+1)^2\)

As both collide then

\(\\ \sf\longmapsto s1=s2\)

\(\\ \sf\longmapsto 11.3x+5x^2=11.3x+11.3+5(x+1)^2\)

\(\\ \sf\longmapsto 5x^2=11.3+5x^2+10x+1\)

\(\\ \sf\longmapsto 10x+12.3=0\)

\(\\ \sf\longmapsto x=1.23s\)

Displacement

\(\\ \sf\longmapsto 11.3(1.23)=13.8m\)

Done

The amount of time which the impetus was implemented is 3.04 seconds.

The momentum of the automobile is 34124.26 kg*m/s.

In order to figure out the time, the following formula for impulse can be applied: impulse = force x time. Reformulating and rearranging this equation, we reach the derivative of time = impulse / force. With the provided calculations of 536.49 N*s divided by 176.32 N, these figures conclude that the amount of time which the impetus was implemented is 3.04 seconds.

Additionally, we can use the formula of momentum = mass x velocity to further determine the vehicular testament of import. When applying these specified numbers of 2546.9 kg and 13.4 m/s respectively, the momentum of the automobile is 34124.26 kg*m/s.

momentum = 2546.9 kg x 13.4 m/s

= 34124.26 kg

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The water flow rate from the faucet, assuming a steady flow, is approximately 0.0001608 cubic meters per second.

The phenomenon of a water stream "necking down" as it falls can be explained by the principle of conservation of mass. According to this principle, the flow rate of water remains constant throughout the system.

In the given figure, the water stream emerges from a faucet with an initial cross-sectional area of 1.8 cm² (Area one). As the water falls, it narrows down to a smaller cross-sectional area of 0.3 cm² (Area two) at a height of 25 cm.

To calculate the water flow rate assuming steady flow, we can use the formula:

Flow rate = A₁√(2gh) / A₁² - A₂²

Where A₁ and A₂ are the initial and final cross-sectional areas, respectively, g is the acceleration due to gravity, and h is the height of the water column.

Plugging in the given values, we have:

Flow rate = 1.8 cm² √(2 × 9.8 m/s² × 25 cm) / (1.8 cm²)² - (0.3 cm²)²

Converting the units to match, we get:

Flow rate = 0.018 m² √(2 × 9.8 m/s² × 0.25 m) / (0.018 m²)² - (0.003 m²)²

Simplifying the expression, we find:

Flow rate ≈ 0.0001608 m³/s

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We can use the formula:

distance = velocity × time

We know the distance the tuna swam (9.3 meters) and its velocity (1.5 meters per second), so we can solve for the time it took:

time = distance / velocity

time = 9.3 / 1.5

time ≈ 6.2 seconds

So it took the tuna approximately 6.2 seconds to swim 9.3 meters towards Lila's fishhook.

Answer: 0.3 m/sec

Explanation:

Vrel = (Vs-Vm) = (0.8-0.5) = 0.3 m/sec

Answer:

0.3 m/s east

Explanation:

Answer:

Decreases

Explanation:

I think this is right tell me if it's wrong.

Answer:

Increases.

Explanation:

The density of the second medium increases, the angle of refraction also increases because of higher density of the medium. In more denser medium, there is more resistance for the light ray so it bends more as compared to less denser medium in which less bending of light ray occur. The angle of refraction increases when the density of medium is more than the previous medium so we can say that the angle of refraction increases due to increase in density of another medium.

The correct answer for the radius of a white dwarf is determined by a balance between the inward force of gravity and the outward push of is Electron Degeneracy Pressure.

 How does a white dwarf's mass affect its radius?

When you raise pressure, you also increase gravity and make the particles closer together, which causes the thing to get smaller because the only way to increase pressure is by adding mass. In other words, the radius of a white dwarf decreases with increasing mass.

A star's gravitational collapse will be stopped by electron degeneracy pressure if its mass is below the Chandrasekhar limit (1.44 solar masses). The force preventing a white dwarf star from collapsing is this one.

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The equilibrium between the outward push of "electron degeneracy pressure" and the inward force of gravity determines a white dwarf's radius.

What is quantum degeneracy pressure?

The more widespread phenomenon known as quantum degeneracy pressure has many different manifestations, including electron degeneracy pressure. As a result, a pressure is created to prevent the compression of matter into smaller amounts of space. The same fundamental process that determines the electron orbital structure of elements produces electron degeneracy pressure.

If a star's mass is below the Chandrasekhar limit, electron degeneracy pressure will prevent gravitational collapse (1.44 solar masses). A white dwarf star is kept from collapsing by this pressure. Because the degeneracy pressure provided by the electrons is weaker than the gravitational pull inward, a star that is larger than this limit.

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The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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When the thistle funnel is moved upwards towards the surface of the liquids, the height (h) decrease.

What happens when the thistle funnel is moved upward?

An important principle outlined by Pascal's law states that any fluid (in this instance, liquids) experiences equal transmission of force in every direction within it. Hence, there is an intimate relationship between the height of a liquid column and its pressure.

Raising a thistle funnel reduces this height causing loss of weight from above this point thus decreasing its pressure.

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See complete question in the attached image.

(1) the average velocity of this motion is 0.55 m/s.

(2) the acceleration is of the trip is 0 m/s²

The given parameters;

displacement on hike = 5,000 m East, 3,000 m North and 1,000 m West.

(1) Average velocity is the ratio of the total displacement to total time of motion.

A simple sketch of the motion is given as;

                                 1000 m  

                               P --------- ↑

                                ↑            ↑ 3000 m

                                ↑            ↑

 Q|------------------------|------------|

         4000 m             1000 m

A line joining point P and Q is the resultant displacement = hypotenuse side of the right triangle.

\(R^2 = 4000^2 + 3000^2\\\\R^2 = 25,000\\\\R = \sqrt{25,000,000} \\\\R = 5,000 \ m\)

The total distance is calculated as;

= 5000m + 3,000m + 1,000 m

= 9,000 m

The time of this motion is calculated as;

\(speed = \frac{total \ distance }{time \ of \ motion} \\\\1 = \frac{9,000}{t} \\\\t = 9,000 \ s\)

The average velocity is calculated as;

\(v= \frac{displacement }{t} \\\\v = \frac{5,000 \ m}{9,000 \ s} = 0.55 \ m/s\)

Thus, the average velocity of this motion is 0.55 m/s.

(2) Acceleration is the change in velocity per change in time of motion,

\(a = \frac{v_2-v_1}{t} \\\\\)

at constant speed, v₁ = v₂, and v₂ - v₁ = 0

Thus, the acceleration is of the trip is 0 m/s²

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Answer:

I KNOW THE ANSWER IT WILL COST 30$

Explanation:

By using the formula, angular velocity is 942.5 rad/s

Given that a centrifuge consists of a container held at a distance of 0.20 m from its axis. When turned on, the centrifuge spins the container and its contents round at 9000 revolutions per minute.

The radius r = 0.2 m

Convert revolution to radian

1 revolution = 360 degree

360 degrees = 2\(\pi\) rad

9000 rev = 9000 x 2\(\pi\) = 56548.67 rad

The given time is

1 minute = 60 seconds

Angular velocity w = angular distance / time

w = ∅/t

Substitute all the necessary parameters into the formula

w = 56548.67/60

w = 942.5 rad/s

Therefore, its angular velocity is 942.5 rad/s approximately.

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The meaning of the word, " analgesic " is B. a medicine to remove pain.

Any substance used to relieve pain is referred to as an analgesic drug, also known as an analgesic, analgaesic, pain reliever, or painkiller.

Analgesics, commonly known as painkillers, are drugs that treat a variety of pains, such as headaches, injuries, and arthritis. Both opioid analgesics and anti-inflammatory analgesics alter how the brain interprets pain. Some analgesics, such as stronger OTC medicines, combination analgesics, and all opioids, must be purchased with a prescription.

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Answer:

B. Design tests to measure and compare the energy released by

earthquakes

Answer:

To solve this problem, you'll need to break the initial velocity of the seed into its horizontal and vertical components, then use the equations of motion to find the time of flight and horizontal distance.

The initial velocity (v) of the seed is 2.65 m/s. The angle it's launched at (θ) is 30.0 degrees below the horizontal. The height (h) it's launched from is 0.460 m.

First, calculate the horizontal (v_x) and vertical (v_y) components of the velocity. Because the seed is launched downward, the vertical component will be negative:

v_x = v * cos(θ) = 2.65 m/s * cos(30.0) = 2.29 m/s

v_y = v * sin(θ) = -2.65 m/s * sin(30.0) = -1.325 m/s

Next, use the equation of motion to find the time it takes for the seed to hit the ground:

h = v_y * t + 0.5 * g * t^2

Where g is the acceleration due to gravity, which is approximately 9.8 m/s². Solving the equation for t gives:

t = (-v_y - sqrt((v_y)^2 - 4 * 0.5 * g * (-h))) / (2 * 0.5 * g)

Plugging in the values:

t = (1.325 + sqrt((-1.325)^2 - 4 * 0.5 * 9.8 * (-0.460))) / (2 * 0.5 * 9.8)

t = 0.182 seconds

Finally, use the horizontal velocity and time of flight to find the horizontal distance the seed covers:

x = v_x * t = 2.29 m/s * 0.182 s = 0.417 m

So, the seed lands after approximately 0.182 seconds and travels approximately 0.417 meters horizontally.

Current cannot flow uphill in any of the listed options: a light bulb, a battery, a flowing water conduit, or a resistor. Hence option E) is the correct answer.

Current cannot flow uphill in any of the listed options: a light bulb, a battery, a flowing water conduit, or a resistor. In an electrical circuit, current is the flow of electric charge carried by electrons. Current flows in a closed loop, typically from the positive terminal of a power source (such as a battery) through the circuit components and back to the negative terminal. A light bulb, battery, flowing water conduit, and resistor all have specific roles within a circuit, but none of them allow current to flow uphill. In a circuit, current always flows from a higher electric potential to a lower electric potential. This is known as the direction of conventional current flow. In the case of flowing water, water flows downhill due to gravity, following the path of least resistance. Similarly, in an electrical circuit, current flows along the path of least resistance, from higher voltage (electric potential) to lower voltage. Therefore, option E) is the correct answer current does not flow uphill in any of the mentioned options.

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Note Complete Question

Current can flow uphill in a:

A)light bulb

B)battery

C)flowing water conduit

D)resistor

E) none of the above

Answer:

the cave walls reflect sound waves

Explanation:

i did the study island

Answer:

in the Earths core

Explanation:

Single Wire moves down, loop rotates left.

A single-wire system is a method of transmitting power or signals using only a single conductor. This is in contrast to the usual use of a pair of wires to provide a complete circuit, or an electrical cable containing (at least) two conductors for this purpose.

A single-wire transmission line is not the same as a single-wire earth return system. This is beyond the scope of this article. The latter system relies on reverse current flow through earth, using earth as a second conductor between earth terminal electrodes. A single-wire transmission line does not have a second conductor of any kind. 

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- The resistance of the first resistor (R₁) is 12 Ω.

- The electromotive force (EMF) of the battery is 18 V.

- The internal resistance of the battery is 12 Ω.

To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.

Let's start by calculating the resistance of the first resistor (R₁):

1. Apply Ohm's law to find the voltage drop across the external circuit:

  V = I * R

  V = 1 A * 6 Ω

  V = 6 V

2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:

  V = E - Ir

  6 V = E - (1 A * r)   (where r is the internal resistance of the battery)

3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:

  E = 6 cells * 3 V/cell

  E = 18 V

4. Substitute the value of E in the equation from step 2:

  6 V = 18 V - r

  r = 12 Ω

Therefore, the resistance of the first resistor (R₁) is 12 Ω.

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Explanation:

wavelength=3.42m

velocity=330m/s

T=?

v=f×wavelength

f=330÷3.42

f=96.5Hz

T=1/f

=1/96.5

T=0.01s

Answer:

To every action there is an equal and opposite reaction

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction.

Explanation: