True or False?

There are equal numbers of protons and electrons in neutral atoms.

The correct option is D. 3690s They can hare afford to nap if he does not want to lose the race.

D= 1000m

\(V_T\)= 0.27 m/s

\(T_t=\frac{1000}{0.27} = 3703.7sec\)

\(T_h = \frac{100}{15}\)\(= 6.7sec\)

\(T_t = 7+ t_n +t_h\)

\(3703.7 = 7+t_n +6.7\\t_n = 3703.7- 13.7\\t_n = 3690sec\)

The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.

In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.

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Answer:

3000 ke

Explanation:

Answer:

The number of protons is correct

Answer:

The number of protons

Explanation:

I took the test buddy boy

To calculate the amount of heat needed to increase the temperature of 150 grams of water from 25 degrees Celsius to 55 degrees Celsius, we can use the formula: Q = mcΔT, where Q is the amount of heat, m is the mass of the substance (in this case, water), c is the specific heat capacity of water, and ΔT is the change in temperature.

First calculate the change in temperature:ΔT = (final temperature) - (initial temperature)ΔT = (55°C) - (25°C)ΔT = 30°C.

Now, we can use the specific heat capacity of water, which is 4.184 J/g°C, to calculate the amount of heat needed: Q = mcΔTQ = (150 g) x (4.184 J/g°C) x (30°C)Q = 18828 J.

Therefore, the amount of heat needed to increase the temperature of 150 grams of water from 25 degrees Celsius to 55 degrees Celsius is 18,828 J.

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The rotational inertia of the rod with a mass of the rod is 1.6 grams and the length of the rod is 2m is 0.0533×10⁻⁶ kg/m².

From the given,

the rotational inertial of rod I,

I = I₁+I₂+I₃

mass of the one rod = 1.6 gram = 1.6×10⁻³kg

length of the rod = 2 cm = 0.02m

I = I₁+I₂+I₃

= (mL²/12)+(mL²/12)+0

= mL²/6

I =mL²/6

 = (1.6×10⁻³kg)×(0.02)²/6

 = (1.6×10⁻⁷)/3

 = 0.533 ×10⁻⁷

= 0.0533 ×10⁻⁶ kg/m²

Thus the rotational inertia of the rod is 0.0533×10⁻⁶ kg/m².

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The "Analysis" section of a lab report would most likely includes:

In the "Analysis" section of a lab report, it is common to discuss any errors or uncertainties that may have affected the experimental data. This may involve identifying sources of systematic and random errors and discussing their potential impact on the results.

Also, the section would typically describe the dependent and independent variables used in the experiment, providing a clear understanding of the factors being investigated and manipulated. By addressing these aspects, the "Analysis" section helps to evaluate the reliability and validity of the experimental findings.

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When measuring distance, you need eight significant figures.

The range of values that can be rationally attributed to a determined quantity by contrasting a parameter with the results of a measurement is represented by uncertainty.

The formula for percent distance uncertainty is as follows:

% Uncertainty = ( uncertainty in distance) / ( original value) × 100

data provided

haziness in the distant, ⁺ 2m

satellite's distance, 20000km

Calculating the percentage of uncertainty in a distance is as follows:

% Uncertainty = ( ⁺ 2m × \(\frac{10^{-3 } km}{1 km}\)) / (20000 km) × 100

= 1 × 10⁻⁵ %

The distance should be converted as follows:

d = (20000km) (10³/1)

= 20000000 km

Uncertainty exists in the distance between the satellite and the Earth, which is:

d = 20000000 km ⁺ 2m

Thus, the measurement of distance requires eight significant figures.

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Correct question:

Global positioning satellites (GPS) can be used to determine your position with great accuracy. If one of the satellites is 20,000 km from you, and you want to know your position to +-2m, what percent uncertainty in the distance is required? How many significant figures are needed in the distance?

The uncertainty in the distance is 1 × 10⁻⁵ % , and eight significant figures are needed in the distance.

Answer:

12.3°C should be the correct answer

Answer:

12.3

Explanation:

Answer:

400 kg-m/s

Explanation:

Given that,

Mass of the woman, m = 50 kg

Initial velocity, u = 8 m/s

Final velocity, v = 0 m/s

We need to find the change in momentum of the woman. It can be given by :

\(\Delta p=m(v-u)\\\\=50\times (8-0)\\\\=400\ kg-m/s\)

So, the change in momentum is 400 kg-m/s.

Answer:

A barcode reader (or barcode scanner) is an optical scanner that can read printed barcodes, decode the data contained in the barcode and send the data to a computer. Like a flatbed scanner, it consists of a light source, a lens and a light sensor translating for optical impulses into electrical signals.

Explanation:

A barcode reader (or barcode scanner) is an optical scanner that can read printed barcodes, decode the data contained in the barcode and send the data to a computer. Like a flatbed scanner, it consists of a light source, a lens and a light sensor translating for optical impulses into electrical signals.

The velocity of the hammer of mass 1.9 kg is 11.07 m/s.

Velocity is the rate of change of displacement.

To calculate the velocity of the hammer, we use the formula below.

Formula:

Where:

Substitute these values into equation 1

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The order is : Leaf, clam, coyote, fish, jellyfish

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The required magnitude of velocity and acceleration are calculated to be 2 m/s and 12 m/s² respectively.

The position of the particle is given as, x = 4t⁴

We know the velocity, V = dx/dt

dx/dt = d/dt (4t⁴) = 16 t³

The velocity at t = 0.5 s is given as,

V = 16 t³ = 16 × 0.5³ = 2 m/s

Acceleration function A = dV/dt

dV/dt = d/dt(16 t³) = 48 t²

A = 48 t² = 48(0.5)² = 12 m/s²

Thus, the magnitude of velocity and acceleration are calculated to be 2 m/s and 12 m/s² respectively.

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Answer:

Choice A. It has chloroplast

Plants have chloroplast and animals dont

Explanation:

It having chloroplasts is the observation which would support the claim that it is a plant cell rather than an animal cell.

This is as organelle which produces the pigment known as chlorophyll and it is used during the process of photosynthesis.

Plants are known as primary producers and are involved in this process which is why option B was chosen.

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Answer:number one is

a

Explanation:

I took this test

Muzzle Velocity = initial velocity of bullet = \(V_i\) = 300 m/s

Height "H" dropped at horizontal distance,

  a) x = 20m

  b) x = 40m

  c) x = 60m  

  d)  How far will it drop after 1 second = ?

We have to find the Height H dropped at the respective given horizontal distances. To find H first we have to calculate the time the bullet has taken to reach at every "X"(Horizontal Distance). So,

A) X = 20m

   v = 300m/s

    t = ?

                                    X = vt

                                    20 = 300 x t

                                    t = 0.067 seconds.

Now, Height dropped can be determine by 2nd equation of motion,

                                    \(H = V_{iy}t + \frac{1}{2}gt^2\)

As initial vertical velocity is zero because the question says that the bullet is fired in the horizontal direction and there is no velocity component in y-axis or vertical axis.

                                    \(H = \frac{1}{2}gt^2\)

                                    \(H = \frac{1}{2} x 10 x (0.067)^2\\\\H = (5)x(4.489x10^{-3})\\\\H = 0.022445 meters\)

B) X = 40m

    v = 300m/s

     t = ?

                               X = vt

                               40 = 300 x t

                                t = 0.133 seconds    

Now, Height dropped can be determine by 2nd equation of motion,

                                \(H = \frac{1}{2}gt^2\\\\H = \frac{1}{2}x10x(0.133)^2\\\\H = 0.088445 meters\)

C) X = 60m

    v = 300m/s

    t = ?

                                 X = vt

                                 60 = 300 x t

                                 t = 0.2 seconds

Now, Height dropped can be determine by 2nd equation of motion,

                                 \(H = \frac{1}{2}gt^2\\\\H = \frac{1}{2}x10x(0.2)^2 \\\\H = 0.2 meters\)

D) By the second equation of motion,

                                \(H=\frac{1}{2}gt^2 \\\\H = \frac{1}{2}x10x(1)^2 \\\\H = 5 meters\)

Angle = θ(theta) = 30

Initial velocity = \(V_0\) = 200m/s

Time to reach the ground = T = ?

Range = R = ?

The total time of flight is given by,

                                \(T = \frac{2V_0Sin(theta)}{g}\\\\T = \frac{2(200)Sin(30)}{10} \\\\T = \frac{200}{10}\\\\T = 20 seconds\)

the Range of projectile is given by,

                                \(R = \frac{V_0^2}{g}Sin2(theta)\\\\R = \frac{200^2}{10} Sin2(30)\\\\R = \frac{40000}{10}Sin60\\\\R = (4000)x(0.866)\\\\R = 3464.1 meters\)

Answer:

As the stone is falling totally under the influence of gravity and toward the earth surface the acceleration is due to gravity and positive. Hence acceleration due to gravity,g is 4m/s²

Given:

The applied force is,

The mass of the object is,

The constant velocity of the object is,

To find:

The coefficient of friction between the object and the surface

Explanation:

The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.

If the coefficient of friction between the object and the surface is

we can write the frictional force as,

For equilibrium condition,

Hence, the coefficient of friction between the object and the surface is 0.47.

An electric field with intensity ′E′ is applied to an electrical dipole with dipole moment ′p′. The dipole moves into a place where its axis forms an angle with the electric field.

Justification: Since electric fields are subject to the of superposition, the overall electromagnetic current of a system typically equal to the total of its individual electric fields. Each charge produces an electric field at pixel Value that is equal in size but moves in the opposite direction.

The flux through a surface is at its maximum when it is horizontal to field (left panels) and the paddock vector is parallel to a vector, A. When a surface is perpendicular to the field (figure 3d), no field lines intersect it and there is no flux through it.

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Answer:

c

Explanation:

The correct statement is: "The vibrations of the fields are perpendicular to the direction of motion of the wave."

To find the correct statement among all the options, we need to know more about the Electromagnetic wave.

What is electromagnetic wave?

How does the electromagnetic wave travel?

Thus we can conclude that the option (C) is correct.

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A pair of scissors is an example of a compound machine. Thus, the correct option is D.

A device which usually combines two or more simple machines together to work is called a compound machine. An example of a compound machine is a scissor. In a scissor, the functionality of a scissor and another scissor combines to cut a sheet of paper or cloth. Numerous compound machines can be created through the use of the six basic simple machines with each other.

Compound machines are also called as the complex machines which can be used to do more difficult jobs than simple machines alone. The tasks performed by the compound machines cannot be done easily with that of simple machines.

Therefore, the correct option is D.

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To find the amplitude of the oscillations of the pendulum, take newton's second law for rotational systems into consideration.

T = I α

-mg sin∅ = mL² d²∅ / dt²

Rearranging the equation as

d²∅ / dt² + g / L sin∅ = 0

If the amplitude of angular displacement is small enough, so the small angle approximation holds, then the equation of motion reduces to the equation of simple harmonic motion

d²∅ / dt² + g / L ∅ = 0

The simple harmonic solution is

∅(t) = ∅' cos(ωt)

where ∅' = initial angular displacement

and ω = √g/L the natural frequency of the motion.

The time period for one oscillation is

T = 2π / ω = 2π√L/g

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The three main approaches to the identification of unknown bacteria are as follows:Phenotypic identification, Molecular identification and Biochemical identification

1. Phenotypic identification

Phenotypic identification involves the physical and chemical characteristics of the bacterial colonies and cells. In this method, bacterial cells are studied through microscopy, their ability to grow on various types of media, cellular morphology, and other factors that are easy to observe.

2. Biochemical identification

Biochemical identification is based on the biochemical reactions of bacteria. This method involves the use of different chemical and biochemical tests to identify the bacteria. The tests are designed to identify specific enzymes or metabolic pathways. The results of the tests are then used to identify the bacteria.

3. Molecular identification

Molecular identification involves the use of DNA analysis to identify bacteria. In this method, the DNA of the bacterial cells is isolated and analyzed. This method has become popular in recent years due to its accuracy and speed.

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Answer:

SI unit of heat is joule and cgs unit of heat is calorie. 1 calorie = 4.18 joule.

Explanation:

The SI unit of heat is joule and the CGS unit of heat is calorie.

4.18 joules= 1 calorie

One astronomical unit (AU) is defined as the average distance between the Earth and the Sun, which is approximately 149.6 million kilometers. Therefore, to convert AU to kilometers, we can multiply the distance by 149.6 million.

The closest Venus comes to Earth is 0.28 AU, which is equal to 0.28 x 149.6 million = 41.888 million kilometers.

The closest Mars comes to Earth is 0.37 AU, which is equal to 0.37 x 149.6 million = 55.352 million kilometers.

Therefore, Venus comes about 13.464 million kilometers closer to Earth than Mars does.

When a hybrid car brakes to a stop, much of its kinetic energy is transformed into different forms of energy. One of the primary forms of energy that is produced during this process is heat. As the brakes of the car are applied, the friction between the brake pads and the wheels creates heat. This heat is then dissipated into the air around the car, resulting in a loss of energy.

Hybrid cars are designed to capture some of this lost energy and convert it into useful forms of energy that can be used to power the car. In many cases, the kinetic energy that is lost during braking is converted into electric potential energy, which is then stored in the car's battery. This energy can then be used to power the car's electric motor, which in turn can help reduce the car's overall fuel consumption.

It is through the conversion of kinetic energy into electric potential energy or the conversion of energy into work, hybrid cars are a great example of how technology can be used to improve the efficiency of vehicles and reduce their environmental impact.

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To find out how many feet per hour light travels, we need to convert miles per second to feet per hour. There are 5280 feet in a mile and 60 minutes in an hour, so we can use the following formula:

186,283 miles/second * 5280 feet/mile * 60 seconds/minute * 60 minutes/hour = 671,088,960,000 feet/hour

Therefore, light travels at approximately 671 billion feet per hour.

This is an incredibly fast speed, and it is important to note that nothing can travel faster than the speed of light. The speed of light has a profound impact on our understanding of the universe and has led to many scientific breakthroughs, including the theory of relativity. Understanding the properties of light and how it interacts with matter is crucial for fields such as optics, astronomy, and physics.

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When a meter stick is placed on a support, such as a pivot or fulcrum, it will balance if the center of mass of the meter stick is directly above the support. This is because the center of mass is the point where the weight of the meter stick can be considered to be concentrated, and if this point is directly above the support, the weight will be balanced.

If the center of mass of the meter stick is not directly above the support, the meter stick will not be balanced and will tip over. This is because there will be a net torque acting on the meter stick, which is the product of the weight force and the distance between the center of mass and the support. If the torque is non-zero, the meter stick will rotate until the torque is balanced.

Therefore, to ensure that the meter stick is balanced on the support, the center of mass must be located at the support position. If the center of mass is not at the support position, the meter stick will not balance and will either tip over or rotate until it reaches a balanced position.

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