True or False:
All graphical models involve a number of parameters which is
POLYNOMIAL in the number of random variables.
Answers
False. Not all graphical models involve a number of parameters that is polynomial in the number of random variables.
Graphical models are statistical models that use graphs to represent the dependencies between random variables. There are different types of graphical models, such as Bayesian networks and Markov random fields. In graphical models, the parameters represent the conditional dependencies or associations between variables.
In some cases, graphical models can have a number of parameters that is polynomial in the number of random variables. For example, in a fully connected Bayesian network with n random variables, the number of parameters grows exponentially with the number of variables. Each variable can have dependencies on all other variables, leading to a total of 2^n - 1 parameters.
However, not all graphical models exhibit this behavior. There are sparse graphical models where the number of parameters is not polynomial in the number of random variables. Sparse models assume that the dependencies between variables are sparse, meaning that most variables are conditionally independent of each other. In these cases, the number of parameters is typically much smaller than in fully connected models, and it does not grow polynomially with the number of variables.
Therefore, the statement that all graphical models involve a number of parameters that is polynomial in the number of random variables is false. The parameter complexity can vary depending on the specific type of graphical model and the assumptions made about the dependencies between variables.
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Related Questions
deduce the relationship between e.m.u and e.s.u in technology .
Answers
In the CGS system, the unit of charge is the charging unit (ESU). Also known as "Statistical Pendant" (StatC). In the CGS system, the load unit is the electromagnetic unit (E.M.E.).
The e.s.u. of charge, also known as franklin or statcoulomb, is the charge such that two similar q=1statC charges at a space of 1cm from each other exert an electrostatic force of 1dyn on each other.
The e.m.u. of current, also called the biot or abampere, is the current such that two infinitely-long straight, parallel conductors carrying 1abA of current and separated by 1cm exert a magnetostatic force of 2dyn on each other.
The relations between these units are such that
\(\frac{1 statC}{1 abA * 1s} = \frac{1 statC}{1abC} = \frac{1}{C} = \frac{1 statA}{1abA} = \frac{\frac{1 statC}{s} } {1 abA}\)
where c is the speed of light.
The ESU and EMU systems of electromagnetic units are different and they should generally be considered separate and independent (if relatively similar), and they do not coincide with the gaussian set of electromagnetic units.
For example, since the electrical displacement vector D is defined as \(E + 4\pi P\) in the ESU system and \(\frac{1}{c^{2} } E + 4\pi P\) the EMU system, it is not possible to exchange the formulas of one system for another without using a formula dictionary like the one at Jackson's end. There is not. classical electrodynamics.
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Who is responsible for providing working conditions which are free from fall dangers?
Answers
Answer:
I am pretty confident it is the Employer!
Explanation:
They have the responsibility to provide a safe workplace that is free from serious hazards, according to the General Duty Clause of the OSH Act (OSHA Standards)
I hope this helped you!! :D
Answer:
Employers
Explanation:
OSHA requires employers to: Provide working conditions that are free of known dangers. Keep floors in work areas in a clean and, so far as possible, a dry condition. Select and provide required personal protective equipment at no cost to workers.
What is promotion? a company's portion of the total industry sales for a certain type of product the value placed on a product, usually given in monetary terms determining how to get the product to the right people, in the right amounts, at the right time and place any form of communication that a business uses to inform, persuade, or remind potential customers about their products
Answers
Promotion is any form of communication that a business uses to inform, persuade, or remind potential customers about their products. The goal is to raise awareness, draw attention to, and encourage consumers to purchase the product over competing options.
All of the activities that inform consumers about a product, brand, or service are referred to as promotions.
Companies communicate about sales promotions through a variety of media, including printed materials like posters, coupons, direct mail pieces, and billboards; radio and television commercials; and digital media like text messaging, email, websites, and social media, among others.
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5. For what purpose do we employ the "double-truck live load model"?
6. Why do we employ dynamic impact factor to the live load model?
Answers
5.The "double-truck live load model" is employed for the purpose of determining the maximum load that a bridge or structure can sustain. It is a method used in structural engineering to analyze the stress and deflection caused by the passage of a double-truck vehicle on a bridge.
By considering the weight distribution, axle spacing, and dynamic effects of the double-truck vehicle, engineers can assess the structural integrity and ensure that the bridge or structure is designed to withstand the anticipated loads and remain safe for public use.
6.The dynamic impact factor is employed in the live load model to account for the additional dynamic effects that occur when a moving load traverses a structure.
As a vehicle or load moves across a bridge or structure, it causes dynamic vibrations and oscillations due to its motion and interaction with the structure.
The dynamic impact factor takes into consideration these dynamic effects and amplifies the live load to ensure the structural design can withstand the combined static and dynamic loads imposed by moving vehicles or loads.
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Briefly explain thermal expansion using the potential energy–versus–interatomic spacing curve.
Answers
As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.
What are the uses of Thermal Expansion?Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.
It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.
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Water flows through this orifice meter by gravity. The orifice diameter is 50 cm and water height difference is 10 m. If the contraction coefficient is 0.62 and velocity coefficient is 0.90, the flow rate through the orifice is most nearly:
Answers
Answer:
Q ≅ 1.53 m³/s
Explanation:
From the given information:
The flow rate of the orifice is:
\(v = c_v \sqrt{2gh}\)
\(v = 0.90 \times \sqrt{2*9.81 * 10}\)
where;
\(Q = c_d \times \sqrt{2gh} \times A\); &
\(c_d = c_c \times c_v\)
∴
\(Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2\)
\(Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2\)
\(Q = 0.558 \times 14.00714104 \times 0.1963495408\)
Q ≅ 1.53 m³/s
The top surface of an L = 5mmthick anodized aluminum plate is irradiated with G = 1000 W/m2 while being simultaneously exposed to convection conditions characterized by h = 50 W/m2 ⋅ K and T[infinity] = 25°C. The bottom surface of the plate is insulated. For a plate temperature of 400 K as well as α = 0.14 and ε = 0.76, determine the radiosity at the top plate surface, the net radiation heat flux at the top surface, and the rate at whic
Answers
Answer:
\(J=1963W/m^2\)
\(q_{rad}=963w/m^2\)
\(\triangle T= -0.378k/s\)
Explanation:
From the question we are told that:
\(L=5mm => 5*10^{-3}\\Irradiation G=1000W/m^2\\h=50W/m^2\\T_{infinity} = 25C.\\Plate\ temperature\ T_p= 400 K\\\alpha=0.14\\E=0.76\)
at Temp=400K
\(E=2702kg/m^2,c=949J/kgk\)
Generally the equation for Radiosity is mathematically given by
\(J=eG+\in E_p\)
\(J=(1-\alpha)G+\in \sigma T^4\)
\(J=(1-0.14)1000+0.76 (5.67*10^_{8}) (400)^4\)
\(J=1963W/m^2\)
Generally the equation for net radiation heat flux \(q_{rad}\) is mathematically given by
\(q_{rad}=J-G\\q_{rad}=1963-1000\)
\(q_{rad}=963w/m^2\)
Generally the equation for and the rate of plate temp \(\triangleT\) is mathematically given by
\(\triangle T= -\frac{q_{con} +q_{rad}}{Ecl}\)
\(\triangle T= \frac{45(400)-(30+273+963)}{(2702*949*0.005)}\)
\(\triangle T= -0.378k/s\)
What are the colors of a sign which tells you the distance to the next exit of a highway?.
Answers
Green with white lettering are the colours of a sign which tells you the distance to the next exit of a highway.
What are the colour signs of distance?Green is a common color for directional signage. Along with location and directions, these signs also tell you how far something is. Blue: This color is also used for wayfinding signage. Information on nearby amenities including rest areas, hospitals, gas stations, and motels is provided by these signs.
Red could be difficult to understand in a crisis because we are taught to interpret it as "stop." Contrarily, green signifies safety and "go," making it clear to the public to maintain composure and abide by the denotations. This is why green emergency signs are utilized in public buildings.
White: A white backdrop indicates a regulatory sign. Yellow: A general warning is sent by the color yellow. Green: Green denotes safe directing indicators or traffic patterns.
Thus, Green with white lettering.
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A 75,000 ft3 clarifier is to be used to treat wastewater. The recycle ratio is 50%, the sludge volume index (SVI) is 125, and the return activated sludge concentration is 8000 mg/L. The biomass concentration is 3500 mg/L. The combined design flow rate of the primary and secondary clarifiers is 2.5 MGD. After primary treatment, the wastewater has an influent BOD concentration of 200 mg/L and an influent suspended solids concentration of 200 mg/L. Two secondary clarifiers, each 28 ft in diameter, are then used. After secondary treatment, the effluent BOD concentration is 15 mg/L, and the effluent suspended solids concentration is 20 mg/L. The volume of sludge produced is 0.5 MGD. What is most nearly the solids residence time
Answers
Answer:
11 hours approximately
Explanation:
We are to calculate mean cell residence time mcrt
= Mass of solid in reactor/mass of solid wasted in a day
Q = Qe + We
Q = 2.5
Qw = 0.5
Qe = 2.5 - 0.5
= 2 MGD
10⁶/svi
= 10⁶/125
= 8000
X = 3500
Xe = 20mg/
1MGD = 0.1337million
Mcrt = 75000x3500/[0.5*8000*10⁶+2*20*10⁶] x 0.1337
= 262500000/[4000000000+40000000} x 0.1337
= 262500000/574800000
= 0.45668 days
= 0.45668 x 24 hours
= 10.9603 hours
Approximately 11 hours
what is the output of print(np array((1, 2, 3 1)))
[1 2 3 1 2 3]
[1 4 9] [14 14 14]
[14]
Answers
The correct output for the provided code is:
[1 2 3 1]
<output of the second line of code is not provided>
[14]
The input in the first line is incorrect as there is a missing comma between 3 and 1, so the code will throw a syntax error.
Assuming the correct input is (1, 2, 3, 1) instead of (1, 2, 3 1), the output of print(np.array((1, 2, 3, 1))) will be:
[1 2 3 1]
This code creates a 1-dimensional array with the values 1, 2, 3, and 1.
The next line of code is not provided correctly, so we cannot determine the output of it. It is expected to be a NumPy function call that operates on an array and produces an output.
The last line of code, print([14]), simply prints a list with one element, 14.
In summary, the correct output for the provided code is:
[1 2 3 1]
<output of the second line of code is not provided>
[14]
The missing second line of code makes it difficult to provide a more detailed explanation of the overall functionality and purpose of the code. However, the first line creates a NumPy array, and the third line prints a list with one element. NumPy is a popular library for scientific computing in Python, and it provides many functions for manipulating arrays and performing mathematical operations.
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Cellular network towers are configured in such a way so that they avoid what type of problem?
Answers
Answer:
They are configured this way to avoid overlap issues.
Explanation:
difficult
to do things:
matter how
but they have a right
4
2. Are you aware of human rights violations happening
in your community? Explain.
3. Which laws protect citizens from human rights
violations?
Answers
If there are human rights violations happening in a community, it means that individuals' fundamental rights are being violated or disregarded.
How to explain the informationHuman rights violations can take various forms, including discrimination, arbitrary arrest or detention, torture, restrictions on freedom of speech or assembly, and denial of basic necessities such as food, water, and healthcare. The specific violations and their severity would depend on the context and circumstances within that community.
To respond to human rights violations, various mechanisms exist at the national and international levels. Many countries have laws and legal frameworks in place that protect citizens' human rights. These laws may encompass constitutional provisions, human rights acts or charters, labor laws, and specific legislation addressing discrimination, torture, or other violations. Victims or concerned individuals can seek legal recourse through domestic courts and judicial systems.
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Bruce wants to present to his client in architectural drawing that shows the exact details of a living room kitchen bedroom and stairs in relation to other areas of the house which type of architectural drawings should Bruce use?
Answers
Answer:
section view in a general plan.
Explanation:
In Engineering, it is a standard and common practice to use drawings and models in the design and development of buildings, tools or systems that are being used for proffering solutions to specific problems in different fields such as banks, medicine, telecommunications and industries.
Hence, an architect or design engineer make use of drawings such as pictorial drawings, sketches, or architectural (technical) drawing to communicate ideas about a plan (design) to others, record and retain informations (ideas) so that they're not forgotten and analyze how different components of a plan (design) work together.
Architectural drawing is mainly implemented with computer-aided design (CAD) software and it's typically used in plans and blueprints that illustrates how to construct a building or an object.
Additionally, architectural drawings such as a section view in a general plan, show in detail how the areas of a building relate to each other, as well as accurately illustrating the actual (true) shape and size of a building in the design and development process.
In this scenario, Bruce wants to present to his client an architectural drawing that shows the exact details of a living room, kitchen, bedroom and stairs in relation to other areas of the house. Thus, the type of architectural drawings Bruce should use is a section view in a general plan.
A section view presents a vertical perspective or view by slicing through the building; revealing the exact details of wall construction, floor-to-floor construction, height and thickness of beam, and other support systems with respect to the living room, kitchen, bedroom, etc., in the building.
The critical crack length for a through crack in a thick plate of 7150-T651 aluminum alloy that is in uniaxial tension. For this alloy Kic = 25.5 MPa SqRt.(m) and sigma f = 400 MPa. Assume Y = SqRt. (pi)
Answers
The critical crack length for a through crack in a thick plate of 7150-T651 aluminum alloy under uniaxial tension can be determined using fracture mechanics principles. For this particular alloy, the fracture toughness (Kic) is given as 25.5 MPa√m, and the ultimate tensile strength (σf) is 400 MPa.
By assuming a yield strength (Y) equal to the square root of pi, the critical crack length can be calculated.
Fracture mechanics is a field of study that deals with the behavior of materials when subjected to cracks or flaws. The critical crack length represents the maximum allowable size of a crack within a material before it fails catastrophically. In this case, we are considering a through crack in a thick plate of 7150-T651 aluminum alloy that is subjected to uniaxial tension.
To determine the critical crack length, we need to use the fracture toughness value (Kic) and the ultimate tensile strength (σf) of the material. The fracture toughness measures a material's resistance to crack propagation, and it is given as 25.5 MPa√m for this particular aluminum alloy. The ultimate tensile strength represents the maximum stress the material can withstand before failure, and it is specified as 400 MPa.
In fracture mechanics, the critical crack length can be calculated using the equation:
a = (Kic / (Y * σf))²
Here, Y represents the yield strength of the material. In this case, Y is assumed to be equal to the square root of pi (√π). By substituting the given values into the equation, we can determine the critical crack length for the 7150-T651 aluminum alloy under uniaxial tension.
The calculation of the critical crack length will provide a value in terms of the crack size (a). This value represents the maximum allowable crack length before failure occurs. It is crucial to consider the critical crack length in engineering applications to ensure the structural integrity and safety of components made from the aluminum alloy.
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The effective resistance of parallel resistors is always _____ than the lowest individual value.
a) more
b) less
c) no different than
Answers
Answer:
A
Explanation:
Answer:
the answer is a
Explanation:
it is a because thats what the answer is
A landscaper plants 18 bushes in a 36-foot section of land along the side of a house. How many bushes does the landscaper plant in a 10-foot section of land?.
Answers
Answer:
5
Explanation:
If he plants in 36 feet half the bushes, then for 10 feet, 5 bushes he would plant. You could also use the rule of three.
Q1. Convert 200 km
hur
to inches/
ms
Answers
Answer:
2.187 inches
hope it would be helpful
Answer:
2.187 in.
Explanation:
Complete the grading of fine aggregate table given below. Plot grading curve and calculate
fineness modulus. Also comment on the type of the grading curve.
Answers
Answer:
Attachment...?
Explanation:
Determine the slopes and deflections at points B and C for the beam shown below by the moment-area method. E=constant=70Gpa I=500 (10^6)mm^4
Answers
Answer:
hello your question is incomplete attached below is the complete question
answer :
Slopes : B = 180 mm , C = 373 mm
Deflection: B = 0.0514 rad , C = 0.077 rad
Explanation:
Given data :
I = 500(10^6) mm^4
E = 70 GPa
The M / EI diagram is attached below
Deflection angle at B
∅B = ∅BA = [ 150 (6) + 1/2 (300)*6 ] / EI
= 1800 / ( 500 * 70 ) = 0.0514 rad
slope at B
ΔB = ΔBA = [ 150(6)*3 + 1/2 (300)*6*4 ] / EI
= 6300 / ( 500 * 70 ) = 0.18 m = 180 mm
Deflection angle at C
∅C = ∅CA = [ 1800 + 300*3 ] / EI
= 2700 / ( 500 * 70 )
= 2700 / 35000 = 0.077 rad
Slope at C
ΔC = [ 150 * 6 * 6 + 1/2 (800)*6*7 + 300(3) *1.5 ]
= 13050 / 35000 = 373 mm
A lake with a surface area of 525 acres was monitored over a period of time. During onemonth period the inflow was 30 cfs (ie. ft3 /sec), the outflow was 27 cfs, and a 1.5 in seepage loss was measured. During the same month, the total precipitation was 4.25 inches. Evaporation loss was estimated as 6 inches. Estimate the storage change for this lake during the month.
Answers
Answer:
The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.
Explanation:
We must estimate the monthly storage change of the lake by considering inflows, outflows, seepage and evaporation losses and precipitation. That is:
\(\Delta V_{storage} = V_{inflow} -V_{outflow}-V_{seepage}-V_{evaporation}+V_{precipitation}\)
Where \(\Delta V_{storage}\) is the monthly storage change of the lake, measured in cubic feet.
Monthly inflow
\(V_{inflow} = \left(30\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)
\(V_{inflow} = 77.76\times 10^{6}\,ft^{3}\)
Monthly outflow
\(V_{outflow} = \left(27\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)
\(V_{outflow} = 66.98\times 10^{6}\,ft^{3}\)
Seepage losses
\(V_{seepage} = s_{seepage}\cdot A_{lake}\)
Where:
\(s_{seepage}\) - Seepage length loss, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{seepage} = 1.5\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{seepage} = (1.5\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{seepage} = 2.86\times 10^{6}\,ft^{3}\)
Evaporation losses
\(V_{evaporation} = s_{evaporation}\cdot A_{lake}\)
Where:
\(s_{evaporation}\) - Evaporation length loss, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{evaporation} = 6\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{evaporation} = (6\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{evaporation} = 11.44\times 10^{6}\,ft^{3}\)
Precipitation
\(V_{precipitation} = s_{precipitation}\cdot A_{lake}\)
Where:
\(s_{precipitation}\) - Precipitation length gain, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{precipitation} = 4.25\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{precipitation} = (4.25\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{precipitation} = 8.10\times 10^{6}\,ft^{3}\)
Finally, we estimate the storage change of the lake during the month:
\(\Delta V_{storage} = 77.76\times 10^{6}\,ft^{3}-66.98\times 10^{6}\,ft^{3}-2.86\times 10^{6}\,ft^{3}-11.44\times 10^{6}\,ft^{3}+8.10\times 10^{6}\,ft^{3}\)
\(\Delta V_{storage} = 4.58\times 10^{6}\,ft^{3}\)
The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.
The volume of water gained and the loss of water through flow,
seepage, precipitation and evaporation gives the storage change.
Response:
The storage change for the lake in a month is 1,582,823.123 ft.³How can the given information be used to calculate the storage change?Given parameters:
Area of the lake = 525 acres
Inflow = 30 ft.³/s
Outflow = 27 ft.³/s
Seepage loss = 1.5 in. = 0.125 ft.
Total precipitation = 4.25 inches
Evaporator loss = 6 inches
Number of seconds in a month is found as follows;
\(30 \ days/month \times \dfrac{24 \ hours }{day} \times \dfrac{60 \, minutes}{Hour} \times \dfrac{60 \, seconds}{Minute} = 2592000 \, seconds\)
Number of seconds in a month = 2592000 s.
Volume change due to flow, \(V_{fl}\) = (30 ft.³/s - 27 ft.³/s) × 2592000 s = 7776000 ft.³
1 acre = 43560 ft.²
Therefore;
525 acres = 525 × 43560 ft.² = 2.2869 × 10⁷ ft.²
Volume of water in seepage loss, \(V_s\) = 0.125 ft. × 2.2869 × 10⁷ ft.² = 2,858,625 ft.³
Volume gained due to precipitation, \(V_p\) = 0.354167 ft. × 2.2869 × 10⁷ ft.² = 8,099,445.123 ft.³
Volume evaporation loss, \(V_e\) = 0.5 ft. × 2.2869 × 10⁷ ft.² = 11,434,500 ft.³
\(Storage \, change \, \Delta V = \mathbf{V_{fl} - V_s + V_p - V_e}\)Which gives;
ΔV = 7776000 - 2858625 + 8099445.123 - 11434500 = 1582823.123
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why you so mean to me? leave my questions please. answer them
Answers
Answer: Why is even here then.
Explanation:
The steel shaft has a diameter of 40 mm and is fixed at its ends A and B . If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa.
Q6/
Answers
Answer:
See explanation.
Explanation:
Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.
If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
What we need to perform?We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,
P=2×pi×N×T/60 or T=60×p/2×pi×N
Where P=power transmitted by the shaft=50×10³W
N=rotation speed of the shaft in rpm=730rpm
Pi=3.142
T is the twisting moment
By substituting the values for pi, N and P, we get
T=654Nm or 654×10³Nmm
Also, T=pi×rho×d³/16 or rho=16×T/pi×d³
Where rho=maximum shear stress
T = twisting moment=654×10³Nmm
d= diameter of shaft= 40mm
By substituting T, pi and d
Rho=52Mpa
b. For a hollow shaft, the value for rho is unknown
T=pi×rho(do⁴-di⁴/do)/16
Rho=T×16×do/pi×(do⁴-di⁴)
Where
T= twisting moment=654×10³Nmm gotten above
do=outside shaft diawter=40mm
di= inside shaft diameter =30mm
Pi=3.142
Substituting values for pi, do, di and T.
Rho=76Mpa
Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
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Definition of Assessment (ddp question)
Answers
Answer:
An assessment is the evaluation or estimation of the nature, quality, or ability of someone or something.
36. What is mass? (4.4)
A. The area of an object.
B. A measure of how much work an object can do.
c. The amount of matter an object or body contains.
D. The force that tends to rotate or turn things.
Answers
Answer:
Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.
Explanation:
Mass is the matter that makes up objects
Water is a great eroder. Man-made levees must be tough. They are often built of
A. rock and concrete.
B. packed mud and dirt.
C. sandbags and gravel.
Answers
Bye the e e
Water is a great erode. Man-made levees must be tough. They are often built of rock and concrete. The correct option is A.
What are Man-made levees?Man-made levees are designed to withstand the erosive power of water and prevent flooding in areas near bodies of water.
As such, they are constructed using strong and durable materials, such as rock and concrete, that can resist the forces of water and prevent erosion.
These materials provide a solid and stable foundation for the levees, which is important for ensuring their effectiveness in protecting against flooding.
Packed mud and dirt or sandbags and gravel may not provide sufficient strength and durability to withstand the erosive power of water and may not be suitable for building effective levees.
Thus, the correct option is A.
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Estimate properties and pipe diameter Determine the diameter of a steel pipe that is to carry 2000 gal/min of gasoline with a pressure drop of 5 psi per 100 ft of horizontal pipe. Pressure drop is a function of flow rate, length, diameter, and roughness. Either iterative methods OR equation solvers are necessary to solve implicit problems. Total head is the sum of the pressure, velocity, and elevation. What is the density of gasoline
Answers
Answer:
Diameter of pipe is 0.535 ft
Explanation:
see attachment, its works out 1st half
Y(S) = Short Questions g through j are regarding the following transfer function: g) What is the DC gain (or simply the gain) of the transfer function H(s)? X(s) H(S) 8 2s2+2s+10 h) The input x(t) is increased by 0.5 from its current steady state value and kept constant at the new value, how much will output y(t) change when it reaches steady state? i) What is the output steady state value Yss when the input is constant at 2.0? j) What is the offset in the above case (part i)?
Answers
The DC gain (or simply the gain) of the transfer function H(s) can be found by setting s=0 in the transfer function. Therefore, the DC gain of H(s) is:
H(0) = 8/10 = 0.8
Assuming the system is stable, the output y(t) will eventually reach a new steady-state value. The change in the output can be found by first finding the new steady-state value of the output and then subtracting the old steady-state value from it.
The new steady-state value of the output can be found by first finding the Laplace transform of the new input, which is 0.5 units higher than the previous steady-state input:
X(s) = (8+0.5)/s = 8.5/s
The Laplace transform of the output can be found by multiplying the Laplace transform of the input by the transfer function:
Y(s) = X(s)H(s) = (8.5/s) (2s^2+2s+10)/8
Simplifying, we get:
Y(s) = (17s^2 + 17s + 85)/80s
The new steady-state value of the output is the value of y(t) as t approaches infinity, which is equal to the inverse Laplace transform of Y(s) evaluated at s=0:
Yss = lim(s->0) sY(s) = lim(s->0) (17s^2 + 17s + 85)/(80) = 85/80
The change in output is then:
delta_y = Yss - Y_old = 85/80 - 8 = 0.0625
Therefore, the output will increase by 0.0625 units in steady state.
The steady-state value of the output can be found by setting s=0 in the Laplace transform of the transfer function:
H(0) = 8/10 = 0.8
Yss = Xss H(0) = 2(0.8) = 1.6
Therefore, the output steady-state value is 1.6.
The offset in this case is the difference between the input and output steady-state values. Therefore, the offset is:
offset = Xss - Yss = 2 - 1.6 = 0.4
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determine the cross-sectional area of each bar so that the bars fracture simultaneously when the load p
Answers
When two or more rods are subjected to an axial load, the load-bearing capacity of each rod is essential in ensuring that the rods fracture simultaneously.
The cross-sectional area of each bar is critical in determining the load-bearing capacity. Let us assume that there are two rods with cross-sectional areas A1 and A2, and they carry loads P1 and P2, respectively. If the rods fracture simultaneously, the load carried by each rod will be the same.
Therefore, we can write the following equation to determine the cross-sectional area of each bar so that the bars fracture simultaneously when the load P is applied. A1P = A2P Since the bars will fracture simultaneously, their load-bearing capacities will be equal.
Therefore, the equation can be simplified to A1 = A2. Thus, the cross-sectional area of each bar will be equal. This is the condition required for the bars to fracture simultaneously. In conclusion, if two or more rods are subjected to an axial load, the cross-sectional area of each bar should be equal to ensure that the bars fracture simultaneously.
This ensures that the load is distributed uniformly, and the rods do not fail at different points.
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6.03 Discussion: Then & Now - Safety
Discussion Topic
I'm Done
In this unit, you have learned about the evolution of the industry’s machines, through both technology and innovation. These improvements have reduced risk and injury to the Operating Engineers.
Choose one innovation or device.
Explain why you think that technology is the most important advancement in Operating Engineers’ safety.
Answers
Answer:
Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.
2. You should hold your fingers on the power switch when holding a plugged-
in power tool.
A True
B. False