True or False: Vacancies are always a non-equilibrium defect in a material.

a) The Gantt chart view for the project is shown below. The finish date is April 6, 2023. The critical path is A-B-E-F-H-I-K-L and its duration is 25 days.

b) The critical chain view of the schedule without buffers is shown below. The critical chain is A-C-D-E-G-H-I-J-K-L and its duration is 18 days. Adding the project buffer of 25% of the critical chain duration (4.5 days) and the feeding buffers, the end date is April 10, 2023.

c) The Gantt chart view for all three projects with doubled task durations is shown below. The finish date is May 13, 2023.

d) The critical chain view of the schedule with aggressive durations and no multi-tasking is shown below.

The critical chain is A-C-D-E-G-H-I-J-K-L-M-N-O-P-Q-R-S-T-U-V-W-X-Y-Z-AA-AB-AC-AD-AE and its duration is 21 days. Adding the project buffer of 25% of the critical chain duration (5.25 days) and the feeding buffers, the end date is May 23, 2023.

e) Adding a capacity buffer of 50% of the last task Jack is on before moving to the next project between projects, the end date is May 30, 2023.

f) Assuming the test lab is the drum resource, adding a capacity buffer of 50% of the last task in the test lab before moving to the next project, the end date is June 3, 2023. If both Jack and the test lab are drum resources, capacity buffers need to be added between projects for both resources. The overall end date will depend on the size of the buffers added.

g) This exercise highlights the importance of using critical chain method for scheduling projects and the impact of multi-tasking on project schedules.

Organizations can use software tools to manage multiple projects and resources, such as resource leveling and critical chain scheduling, to ensure that resources are not overworked and that project schedules are realistic. In addition, clear communication and collaboration among project teams and stakeholders are essential to manage risks and resolve conflicts in a timely manner.

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Add the peak motor current (A), the number 1.25, and the cable's overall length to the conductor material's resistance (•m) (m). The voltage drop from the power supply to the motor is divided by the result.

Ampacity is the greatest continuous current a conductor can carry while in use without going above its temperature rating. Amperes, or "amps," are used to measure current.

Ampacity is the greatest continuous current a conductor can carry while in use without going above its temperature rating. Amperes, or "amps," are used to measure current. To prevent the wire from overheating, you must utilise the proper size wire for the current (load) required of the circuit.

The kind and quantity of electrical devices connected to a circuit define the conductor's ampacity requirements. A general-purpose home circuit is typically built for 20 amps. It's possible that lighting circuits are just 15 amps rated.

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Answer:

Trash rack

Open channel

Fore bay

Pen stock

Inlet valve

Turbine

Tailrace

Generator

Power house

Answer:

  any of AND, NOR, XOR

Explanation:

An AND gate will give a Low output for any input Low. The logic circuit could be an AND gate.

A NOR gate will give a Low output for any input High. The logic circuit could be a NOR gate.

An XOR gate will give a Low output for an even number of High inputs. The logic circuit could be an XOR gate.

The logic circuit could be any of ...

  AND or NOR or XOR

__

Additional comment

What you consider a "basic" gate is not defined here. All of these are catalog items. If you consider only AND, OR, and NOT to be the basic gates, then your answer is AND.

Answer:

Option A is the correct answer. The bus traveled at 50 mph for 20 minutes

Explanation:

The complete question is

Which of the following choices best describes velocity of a bus traveling along its route? A. The bus traveled at 50 mph for 20 minutes. B. The airplane traveled southwest at 280 mph. C. The car went from 35 mph to 45 mph. D. The train made several stops, with an average rate of 57 mph.

Solution

In option A the bus is travelling at a speed of 50 miles per hour. This describes the velocity of bus along its route.

The other options are about the velocity of airplane, car and train

Engineer's approvall makes it appropriate to alter from the drawing

Engineering drawing is a document that contain the design of an engineer represented in a sketch.

deviating fron the drawing is same as deviating from the design. it is therefore necessary to call the engineers attention before altering the drawing.

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This part might take approximately 5,000 minutes to resist the cyclic loading before failure.

The endurance of an engineering part under cyclic loading can be estimated using the concept of fatigue life. Fatigue life refers to the number of cycles a material can withstand before failure under a specific stress level. In this case, the part is made of 2014-T6 aluminum and subjected to a cyclic stress of 200 MN/m2.

To determine the endurance, we need to consider the fatigue strength of the material, which represents its resistance to cyclic loading. Fatigue strength is determined through experimental testing and analysis. By dividing the fatigue strength by the applied cyclic stress, we obtain the number of cycles the part can endure before failure.

Fatigue is a common failure mechanism in engineering materials and structures subjected to cyclic loading. Understanding the fatigue behavior of materials is essential in designing components that can withstand long-term cyclic loads without failure.

Factors such as material properties, stress levels, loading frequency, and surface conditions can influence the fatigue life of a part. Engineers employ various techniques to predict and improve the fatigue life, including stress analysis, fatigue testing, and design modifications.

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Answer:

ben black diyorum ve Iyi srdsler dilerim

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Technician a is correct. The car may veer off course due to loose ball joints. The propensity of a vehicle to veer from one side of the road to the other is known as wander.

The propensity of a vehicle to veer from one side of the road to the other is known as wander. Uneven tire pressure or mismatched tires are potential causes number one. Linkage binding or inadequate lubrication is a potential cause number two. The third potential factor is binding or inadequate lubrication of the steering gear.

The bottom line is that before you start to address poor steering performance, you must identify the underlying source of the issue. Oversteer and understeer have been discussed separately, but we've also included 10 other common steering issues with their likely causes below. You can stop cursing and start fixing your steering problems by locating potential problem areas.

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According to the sector model of North American city structure, members of low-income groups tend to live in the central business district (CBD) and the inner-city area.

The sector model of North American city structure is an urban land use model that was created by Homer Hoyt in 1939. It divides a city into a series of sectors that radiate outwards from the CBD. These sectors differ in terms of their socio-economic characteristics and are defined by their level of wealth, housing type, and level of social and economic status.

Land use patterns in the sector model are concentrated around the central business district and expand radially outwards, with the most desirable areas occupying the outermost ring. Members of low-income groups tend to live in the central business district and the inner-city area.

Hence, it can be concluded that according to the sector model of North American city structure, members of low-income groups tend to live in the central business district (CBD) and the inner-city area.

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Technicians A is correct in the given scenario. The correct option is C.

Exhaust gas is a byproduct of combustion that exits the tailpipe of an internal combustion engine.

It consists of a gas mixture that includes carbon dioxide (CO2), carbon monoxide (CO), nitrogen oxides (NOx), hydrocarbons (HC), and particulate matter (PM).

Technician B is mistaken. CO2 levels in the exhaust should be less than 15%, preferably between 13% and 14.5% for petrol engines and 11% to 13% for diesel engines.

High CO2 levels can actually indicate inefficient engine operation, as it means that not all of the fuel in the engine is being burned and is being wasted as exhaust.

Thus, C is the correct answer. A technician is correct.

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Answer:

yes

Explanation:

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Answer:

ee

Explanation:

This is an over the top question

The program requires a sequence control structure; First, we get input for the variables, and then use the formula to calculate the amount of calories burnt.

The program in python is as follows, where comments (in italics) are used to explain each line.

#This gets input for age, in years

age = int(input("Age (years): "))

#This gets input for weight, in pounds

weight = int(input("Weight (pounds): "))

#This gets input for heart rate, in beats per minutes

heart_rate = int(input("Heart Rate (beats per minutes): "))

#This gets input for time, in minutes

time = int(input("Time (Minutes) : "))

#This calculates the calories burnt for men

calories_man = ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * time / 4.184

#This calculates the calories burnt for women

calories_woman = ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022 ) * time / 4.184

#This prints the calories burnt for men

print('Men: %0.2f calories' % calories_man)

#This prints the calories burnt for women

print('Women: %0.2f calories' % calories_woman)

Please note that the program does not check for valid inputs

See attachment for program output

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In Stokes flow, the fluid velocity is proportional to the forces acting on the fluid and the fluid is assumed to be viscous and incompressible. The fluid velocity near a rotating sphere in Stokes flow can be determined using the equations of fluid dynamics.

Kinematic reversibility is a property of Stokes flow, which states that the fluid flow is symmetric with respect to time reversal. This means that if the fluid velocity is recorded at a certain time, then the same velocity field will be obtained if time is reversed and the flow is replayed in the reverse direction.

When a sphere is rotating near a wall, the flow of fluid around the sphere creates a velocity field that pushes the sphere away from the wall. This flow can be considered as the fluid being pushed away from the sphere and towards the wall. If the flow is time-reversed, the fluid velocity field would be the same, but the direction of the velocity would be reversed. This means that the fluid would be drawn towards the sphere and away from the wall, pulling the sphere towards the wall.

Therefore, based on the property of kinematic reversibility in Stokes flow, the rotating sphere near a wall will experience a force that could either push it away from the wall or draw it towards the wall, depending on the direction of the flow.

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When you park next to a curb, your wheels must be no more than:

When parking next to a curb, it is important to position your vehicle in a way that allows for safe and efficient use of the road.

The distance between your wheels and the curb is regulated in order to ensure that parked vehicles do not obstruct traffic and allow for smooth movement of other vehicles on the road.

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Answer:

After the vehicle is involved in an accident or fire.

After the vehicle is involved in an accident or fire. Therefore option C is correct.

CNG (Compressed Natural Gas) containers in vehicles need to be inspected after the vehicle is involved in an accident or fire. This is because accidents or fires can cause structural damage or compromise the integrity of the CNG container.

It's crucial to assess the container's condition thoroughly after such incidents to ensure there are no leaks or damages that could lead to hazardous situations.

Regular inspections help identify any potential safety risks and ensure that the CNG container remains in a safe and functional state, promoting the overall safety of the vehicle and its occupants.

Inspections after other events like car washes, rain, or parking outside are not necessary for CNG container safety.

Therefore option C is correct.

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Answer:

  20 mW

Explanation:

You want to know the average power in milliwatts represented by 72 J per hour.

1 J/s = 1 W

  \(\dfrac{72\text{ J}}{1\text{ h}}=\dfrac{72\text{ J}}{1\text{ h}}\times\dfrac{1\text{ h}}{3600\text{ s}}\times\dfrac{1\text{ W}}{1\dfrac{\text{J}}{\text{s}}}\times\dfrac{1000\text{ mW}}{1\text{ W}}=\dfrac{72\times1000}{3600}\text{mW}\\\\=\boxed{20\text{ mW}}\)

In order to find the temperature required to obtain 0.5% C at a distance of 0.5mm beneath the surface of a 0.2% C steel in 2 hours, given 1.1% C at the surface, we can make use of the Jominy end-quench test.

In the Jominy end-quench test, a standard size and shape of steel sample is heated to a high temperature and then quickly quenched at one end by spraying water on it. The water quenches the steel, causing it to cool rapidly from the high temperature. As the steel cools, it undergoes a transformation from austenite to a mixture of ferrite and pearlite.

As the steel cools, it undergoes a transformation from austenite to ferrite and pearlite. The distance from the quenched end to the point where this transformation is complete is a measure of the steel's hardenability. The hardenability of the steel depends on its composition and the cooling rate. A higher carbon content and a faster cooling rate will result in a higher hardenability.

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An airplane flying across the sky experience drag force determined by the factors including the speed of flight, coefficient of skin friction and the reference surface area

The boundary layer thickness is approximately 0.233 cm

The total skin friction drag, is approximately 265 N

Reason:

First part:

Given parameters are;

Chord length, L = 3 m

Velocity of the plane, V = 200 m/s

Density of the air, ρ = 1.225 kg/m³

Viscosity of the air, μ = 1.81 × 10⁻⁵ kg/(m·s)

The Reynolds number is given as follows;

\(R_{eL} = \dfrac{\rho \times V \times L}{\mu}\)

Therefore;

\(R_{eL} = \dfrac{1.255 \times 200 \times 3}{1.81 \times 10^{-5}} = 4.16022099448 \times 10^7 \approx 4.16 \times 10^7\)

Boundary layer thickness, \(\delta_L\), for laminar flow, is given as follows;

\(\dfrac{ \delta_L }{L}=\dfrac{5.0}{\sqrt{R_{eL} } }\)

\({ \delta_L }=\dfrac{5.0 \times L}{\sqrt{R_{eL} } }\)

Which gives;

\({ \delta_L }=\dfrac{5.0 \times 3}{\sqrt{4.16 \times 10^{7}} } \approx 2.33 \times 10^{-3 }\)

The boundary layer thickness, \(\delta_L\) ≈ 2.33 × 10⁻³ m = 0.233 cm

Second Part

The total skin friction is given as follows;

\(Dynamic \ pressure, q = \dfrac{1}{2} \cdot \rho \cdot V^2\)

Therefore;

\(q = \dfrac{1}{2} \times 1.225 \times 200^2 = 24,500\)

The dynamic pressure, q = 24,500 N/m²

Skin friction drag coefficient, \(C_D\), is given as follows;

\(C_D = \dfrac{1.328}{\sqrt{R_{eL} } }\)

Therefore;

\(C_D = \dfrac{1.328}{\sqrt{4.16 \times 10^7 } } \approx 2.06 \times 10^{-4}\)

Skin friction drag, \(D_f\), is given as follows;

\(D_f\) = q × \(C_D\) × A

Where;

A = The reference area

∴ \(D_f\) = 24,500 N/m² × 2.06 × 10⁻⁴ × 3 m × 17.5 m = 264.9675 N ≈ 265 N

The total skin friction drag, \(D_f\) ≈ 265 N

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The calculation for the number of pistons required to lift in PLTW POE depends on specific design factors and cannot be determined without more information.

To calculate the number of pistons required to lift in PLTW POE (Project Lead The Way Principles of Engineering), you would need specific information about the system design, including factors such as the weight to be lifted, desired lifting capacity, force requirements, and mechanical advantage.

The calculation would involve considering the forces involved, the efficiency of the system, and any additional factors such as safety margins or load distribution.

Without more specific information about the system and its requirements, it is not possible to provide a generic calculation for the number of pistons required.

It is recommended to refer to the PLTW POE curriculum or consult the project guidelines and resources provided by your instructor or educational institution for specific calculations and guidance on determining the number of pistons required for lifting in a given scenario.

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I don't know how?

i hate it that it says 20 charcters long

Given:Velocity of the engine oil, v = 1.3 m/s Diameter of the horizontal tube, D = 15 cm = 0.15 m Pressure drop, ΔP = 12 kPa.

We know that: Pumping power required = (Pressure drop × Volume flow rate) ÷ Efficiency Volume flow rate, Q = πD²/4 × vQ = π(0.15)²/4 × 1.3Q = 0.01335 m³/s= 13.35 L/s Substitute the values: Pumping power required = (12 kPa × 0.01335 m³/s) ÷ 0.70 Pumping power required = 226.9 W

Therefore, the pumping power required to overcome this pressure drop is 226.9 W (rounded off to the nearest tenth).Note: The efficiency value is not given. It is assumed as 0.70 (typical efficiency value of pumps).

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The output of a combiner is normally fed into an inverter.

The output of a combiner in a photovoltaic system is typically in DC form and needs to be converted into AC for use in homes and businesses. An inverter is used for this purpose, which converts the DC output from the combiner into AC power that can be used to power electrical devices. The combiner is responsible for combining the electrical output of multiple solar panels into a single output, which makes the electrical output more efficient and manageable. Once the output is combined, it is then sent to the inverter for conversion. Overall, the combination of a combiner and an inverter is crucial for the operation of a photovoltaic system.

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In the case above,  It will take more time for a tooth of wheel B and C to make a full turn (slower) than it will for a tooth of wheel A.

A gear wheel is known to be a kind of a wheel that is known to be made up of a teeth and/or cogs that is known to function with those of other aspect of the wheel or part.

Note that in the above case, lets use a scenario that  Wheel P has 5 teeth. Wheel M has 3 teeth and wheel N has 1 teeth.  If wheel P makes a full turn, wheel M turn will be slower as  well as wheel N which will take more time.

Therefore, In the case above,  It will take more time for a tooth of wheel B and C to make a full turn than it will for a tooth of wheel A.

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For a hashtable that requires integer keys, I would choose the Jenkins one-at-a-time hash algorithm. It is a simple and efficient hash algorithm that produces a 32-bit hash value for any given key.

Here is an example implementation of the Jenkins one-at-a-time hash algorithm in Java:

public static int hash(int key) {

   int hash = 0;

   for (int i = 0; i < 4; i++) {

       hash += (key >> (i * 8)) & 0xFF;

       hash += (hash << 10);

       hash ^= (hash >> 6);

   }

   hash += (hash << 3);

   hash ^= (hash >> 11);

   hash += (hash << 15);

   return hash;

}

This implementation takes an integer key as input and produces a 32-bit hash value as output. It uses a loop to process each byte of the key in turn, adding it to the hash value and performing some bitwise operations to mix the bits together. Finally, it applies some additional mixing operations to produce the final hash value.

The Jenkins one-at-a-time hash algorithm is a good choice for integer keys because it is fast, simple, and produces a good distribution of hash values for most inputs.

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The true strain at the maximum load can be calculated using the Hollomon equation. With k = 750 MPa and m = 0.6, and a true stress of 552 MPa at the maximum load, we can solve for the true strain.

To calculate the true strain at the maximum load, we can rearrange the Hollomon equation as follows:

σ = kε^m,

where σ is the true stress and ε is the true strain. We are given σ = 552 MPa, k = 750 MPa, and m = 0.6. Rearranging the equation, we have:

ε = (σ / k)^(1/m).

Substituting the given values, we get:

ε = (552 MPa / 750 MPa)^(1/0.6) ≈ 0.448.

Therefore, the true strain at the maximum load is approximately 0.448.

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Process capacity can be increased by balancing a process.

Line balancing is a technique used in production and manufacturing to optimize the allocation of work among different workstations or processes. The main goal of line balancing is to minimize idle time and maximize productivity by distributing work evenly across the available resources. In this context, the statement that process capacity can be increased by balancing a process is true.

When a process is balanced, the workload is evenly distributed among the workstations, ensuring that each station operates at its maximum efficiency. By eliminating bottlenecks and reducing idle time, line balancing helps to increase the overall throughput and productivity of the process.

Balancing a process involves analyzing the tasks required and the time it takes to complete each task. By rearranging the sequence of tasks or adjusting the allocation of resources, it is possible to create a more efficient workflow. This optimization not only reduces the overall processing time but also increases the capacity of the process to handle a higher volume of work.

It's important to note that while line balancing can increase process capacity, it may not necessarily involve the bottleneck resource. The bottleneck resource is the part of the process that limits the overall throughput. While it is crucial to identify and address bottlenecks, line balancing focuses on optimizing the entire process rather than solely focusing on the bottleneck.

In summary, line balancing can increase process capacity by optimizing the allocation of work among different workstations or processes. By evenly distributing the workload and minimizing idle time, line balancing improves productivity and enables the process to handle a higher volume of work.

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Answer:

For  lower disk :   V = e^θ​rω(0)/h  = 0

At the upper disk:  V = e^θ​rω(h)/h  = e^θ​rω

Hence The physical boundary conditions are satisfied

Explanation:

Velocity field ( V ) = e^θ​rωz/h

Upper disk located at  z = h

Determine the dimensions of the velocity field

velocity field is two-dimensional ; V = V( r , z )

applying the no-slip condition

condition : The no-slip condition must be satisfied

For  lower disk Vo = 0 when disk is at rest z = 0

∴  V = e^θ​rω(0)/h  = 0

At the upper disk  V = e^θ​rω  given that a upper disk it rotates at z = h

∴ V = e^θ​rω(h)/h  = e^θ​rω

Hence we can conclude that the velocity field satisfies the appropriate physical boundary conditions.

Answer:

Sole Proprietorship, General Partnership , Limited Partnership, corporation

Explanation:

Business in something that an individual or a group of people do for a living and produce products and services that benefits the society and the people. There are several entities that can be common in business. Some common form of entities are :

Sole Proprietorship : One to one

-- here there is only one owner in the business and he maintains and manages the entire business functions under his control.

Limited Partnership : many to one

-- here two or more than two partners establish business and runs it but only one or more is liable to the amount of the investments.

General Partnership : many to many

-- It is a business partnership where all the partners shares the profits, the assets, legal liabilities and financial liabilities, etc.

Corporation : many to one

It is a business entity where a group of individual or a group of companies run a single business which is generally authorized by the state.

Some of the typical types of the entities that one may think to be common in term of the business entities are about the relationships that are held within many to many and one to many.

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Consider the four sub-cases for each of those three cases two positives, two negatives, one of each . Show that some of those sub-cases are not possible in each case. Then examine each sub-case to see if it indicates overflow.

Two's complement is a mathematical operation that converts a positive binary number with equivalent value reversibly into a negative binary number with equivalent value.

it occurs using the binary digit with the greatest place value to indicate whether the binary number is positive or negative.

Consider each of those three cases' four sub-cases. There are two positives and two negatives, with one of each.

Demonstrate that some of the sub-cases are not feasible in each case. Then, for each sub-case, determine whether it indicates overflow.

Thus, by this it can be proved that in a 2’s complement number system addition overflows if and only if the carry from the sign position does not equal the carry into the sign position.

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