Given
Charged objects attract neutral objects.
To find
True or false
Explanation
Neutral objects have both positive and negative charges.It attracts any charged particle
Conclusion
The given statement is True
Max and his friend want to ride in the front car of a roller coaster. What happens to the car's kinetic energy as the roller coaster car is pulled to the top of the first big hill?
A.
Its kinetic energy is released into the air at the top of the hill.
B.
Its kinetic energy is added to the potential energy to give it twice as much speed.
C.
Its kinetic energy is converted to potential energy at the very top of the hill.
D.
Its kinetic energy is transferred to the wheels so it can roll quickly down the hill.
Answer:
KE =1/2mv^2
Explanation:
KE depends upon movement of the body
Can anyone help with this physics question
1. If a plane flies at 4.5 x 102 km/h against a 3.2 x 102 km/h wind, how long does it take the plane to fly between two stations that are 300 km apart?
2. A person runs from the front to the back of an aircraft at a velocity of 3.0 m/s. IF the aircraft carrier is moving forward at 20.0 m/s, how fast does the spy appear to be running when viewed by an observer on a stationary submarine?
3. Suppose a dolphin begins to chase a fish at 37.0 km/h when the fish is 50.0 m away. The fish swims away at a speed of 15.0 km/h. How long would it take the dolphin to catch the fish?
4. an animal transport moves at 30.0 m/s north along a highway. Inside a dog moves at 2.00 m/s at an angle of 45o east of north. What is the velocity of the dog relative to the road?
distance = speed x time.
In this case, the distance is 300 km, the speed of the plane relative to the ground is the vector sum of its own speed and the wind speed, which is:
(4.5 x 102 km/h) - (3.2 x 102 km/h)
= 1.3 x 102 km/h.
Therefore,
time = distance / speed
= 300 km / (1.3 x 102 km/h)
= 230 s or 3.83 minutes.
2. To find the apparent velocity of the spy when viewed by an observer on a stationary submarine, you can use the formula:
velocity = relative velocity + velocity of the observer.
In this case, the relative velocity of the spy is 3.0 m/s and the velocity of the observer is -20.0 m/s (negative because the aircraft carrier is moving in the opposite direction of the submarine).
Therefore,
velocity = 3.0 m/s + (-20.0 m/s)
velocity = -17.0 m/s
3. To find the time it takes for the dolphin to catch the fish, you can use the formula:
time = distance / (speed of the dolphin - speed of the fish).
In this case, the distance is 50.0 m, the speed of the dolphin is 37.0 km/h, and the speed of the fish is 15.0 km/h.
Therefore,
time = 50.0 m / ((37.0 km/h) - (15.0 km/h))
= 50.0 m / 22.0 km/h
time = 2.27 s.
4. To find the velocity of the dog relative to the road, you can use the principle of relative velocity. The velocity of the dog relative to the road is the vector sum of its velocity relative to the vehicle and the velocity of the vehicle relative to the road. The velocity of the vehicle relative to the road is 30.0 m/s north and the velocity of the dog relative to the vehicle is 2.00 m/s at an angle of 45 degrees east of north.
Therefore, velocity of the dog relative to the road is:
(2.00 m/s * cos(45)) m/s north + (2.00 m/s * sin(45)) m/s east
= 1.41 m/s north + 1.41 m/s east.
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a car having a mass of 10kg accelerates from 10m/s square to 16 m/s square in t seconds? What is the force exerted by the car?
Answer:
The answer is 160 N
Explanation:
I did the test
Hope this helps :)
Bacteria prefer a dry environment to a damp or moist environment. False True
Answer:
false
Explanation:
cause bacteria prefers moist and damp environment
Answer:
False
Explanation: bacteria thrive on moister and grow due to it. if the enviroment they were in were to be dry, the bacteria itself would die. Hope this helps! :)
3. In a physics experiment on static friction, two objects made of identical material are tied together with string. The first object has a mass of 5.0 kg and the second object has a mass of 3.0 kg. Students measure the maximum force of static friction as 31.4 N to move both objects across a horizontal surface. Im (a) What is the coefficient of static friction? (b) What is the magnitude of the tension in the string if they pull on the first object? (c) A student pushes the 3.0 kg object with a force of 15.0 [down]. What are the magnitudes of the maximum force of static friction and the tension now? (d) Will your answers to (c) change if the student pushes down on the 5.0 kg object instead? Explain.
(a) The coefficient of static friction between the two objects is 0.628. (b) 25.6 N. (c) the magnitudes of the maximum force of static friction and the tension are 15.0 N and 12.6 N,resp. (d) the answe to (c) will not change.
(a) The coefficient of static friction (μs) is calculated by dividing the maximum force of static friction by the normal force between the objects. In this case, μs = 31.4 N / ((5.0 kg + 3.0 kg) * 9.8 m/s^2) = 0.628.
(b) When pulling on the first object, the tension in the string is equal to the maximum force of static friction, which is 31.4 N.
(c) When the student pushes the 3.0 kg object downward with a force of 15.0 N, the maximum force of static friction is equal to the applied force, which is 15.0 N. The tension in the string is then calculated by subtracting the force applied by the student from the maximum force of static friction: Tension = 31.4 N - 15.0 N = 16.4 N.
(d) If the student pushes down on the 5.0 kg object instead, the answers to (c) will not change. The maximum force of static friction and the tension will still be 15.0 N and 16.4 N, respectively, as they depend on the applied force and not the mass of the object being pushed.
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What are the units used to measure specific heat capacity?.
The units used to measure specific heat capacity is Joules per kilogram per Kelvin.
What is specific heat capacity?It is the amount of heat absorbed per kilogram of material when the temperature rises by 1 kelvin.
Specific heat capacity C is the Joules of energy in form of heat per kilogram per Kelvin temperature. The units represented by
C = ___ J/kg.K
Thus, the units used to measure specific heat capacity is Joules per kilogram per Kelvin.
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When observing an object, you determine it is moving at a constant velocity and in a straight line. Which of these best describe the situation?.
The net force acting on the object must be zero.
Constant velocity:
A velocity is constant when both its magnitude and direction does not change over time. In simpler words, this is when the rate of change of position of an object remains the same throughout a period of time.
Velocity gives us information about the rate of change of object position, meaning how fast can object position is changing per unit time. In physics, velocity is defined as the displacement divided by time where displacement is defined as the difference between your final and initial positions.
Furthermore, when an object travels the same distance every second, then the object is said to be moving with constant velocity. This means that the magnitude of the velocity (or speed) and the direction of the velocity both remain constant.
Hence the net force acting on the object must be zero when it is moving at a constant velocity and in a straight line.
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which statement did kepler’s investigations of the movement of the planets explain?
Answer:
Kepler made extensive measurements and created a mathematical model of the movement of the planets around the sun, these analyzes are written in the form of three laws
Explanation:
Answer:
Earth is not the center
Explanation:
A 30 N net force on a skater produces an acceleration of 0.6 m/s2 . What is the mass of the skater?
The mass of the Skater is 50 Kg.
We have a skater who is under the influence of 30 Newton of force.
We have to determine the mass of skater.
State Newton's Second law of Motion ?Newton's second law of motion states that the rate of change of momentum is directly proportional to the force applied. Mathematically-
\($F\;\alpha \; \frac{dp}{dt}\)
According to the question, we have -
Force on Skater - 30 N
Acceleration Produced - 0.6 \(m/s^{2}\)
We know -
F = ma
30 = m x 0.6
m = 30/0.6 = 50 Kg
Hence, the mass of the Skater is 50 Kg
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Which statement about force is true?
A. It transfers energy only when one object touches another.
OB. It always makes objects move.
C. It only affects large objects.
D. It can act between objects that touch, or it can act at a distance.
SUBMIT
Answer: D
Explanation: I saw it in a bill nye video.
mple lever. A lift is used to carry boxes to the top floor of a hotel 20 m high. A total weight of 100 kg of boxes was carried up in 20 seconds. If the useful output of the engine driving the lift mechanism is 1.2 kilowatt, calculate the efficiency of the engine of the lift mechanism. (a) (i) What is meant by a
The efficiency of the system of the levers is 122%.
What is the efficiency?We have to note that the efficiency is the ratio of the work out put to the work out put multiplied by 100. In this case, we are told that a lift is used to carry boxes to the top floor of a hotel 20 m high. A total weight of 100 kg of boxes was carried up in 20 seconds. and that the useful output of the engine driving the lift mechanism is 1.2 kilowatt.
Work input = 100 Kg * 9.8 m/s^2* 20 m = 19600 J
Work output = 1.2 kilowatt * 10^3 * 20 = 24000 J
Then we have;
Efficiency = Work out put/ Work input * 100
= 24000/19600 * 100
= 122%
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Calculate the distance the gecko covers when sprinting from rest to 2 m/s in a time of 1.5 s.
I got the answer D = 1.49 m, but i think I may have done something wrong or misinterpreted it.
Thank you!
Answer:
1.5 m
Explanation:
a = v/t
a = 2/1,5 = 4/3
x = 1/2 a t² + vt + x
x = 1/2 × 4/3 × 9/4 = 3/2 =1.5 m
what performance is characteristic of flight at maximum lift/drag ratio in a propeller-driven airplane? maximum
The performance characteristic of flight at the maximum lift/drag ratio in a propeller-driven airplane is the highest lift-to-drag ratio (L/D max) achievable during flight.
This means that the airplane is operating at its most aerodynamically efficient condition, where the lift produced by the wings is maximized while the drag force is minimized. This optimal condition is crucial for maximizing the airplane's endurance and range.
To summarize:
1. The performance characteristic is the maximum lift-to-drag ratio (L/D max).
2. This occurs when the airplane is operating at its most aerodynamically efficient condition.
3. This condition is essential for maximizing the airplane's endurance and range.
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Jason wants to conserve energy. he could:
ride the bus to and from work
write to his local congressman
change the type of paint used in his house
pass out flyers about the issue
If Jason wants to conserve energy, he could ride the bus to and from work.
What is the law of Conservation of energy?The law of Conservation of energy states that energy cannot be created nor destroyed but can be changed from one form to another.
There is no net change in conserving energy.
Thus, Jason conserves energy by riding the bus to and from work.
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Jalen combines two substances in science class. Once combined, only one of the two substances
is visible. When he placed this combination into a filter, substance 1 stayed in the filter while
substance 2 went through it. Which of the following claims regarding Jalen's combination is the
most accurate?
a. This combination is not a mixture because he cannot see one of the substances.
b. The combination is a mixture because the substances can be separated.
c. The combination is not a mixture because the substances can be separated.
d. The combination is a mixture only because he cannot see one of the substances,
Answer: b. The combination is a mixture because the substances can be separated
Explanation: Based on the facts presented above, the combination of both both substances can be referred to as a mixture due to the following:
A mixture is obtained when two or more substances or materials are combined without a chemical reaction. This is observed when Jalen combined substance 1 and 2 with only one of the substances becoming visible after the combination.
The other reason is that, a mixture can be separated back into its original constituent, this is evident when the combination was filtered with only substance 2 going through the filter and substance 1 remaining in the filter
A bowling ball of mass my 3.7 kg is rolled down the lane with a velocity of 2.2 m/s. It strikes a single remaining pinm, = 0.37 kg head on. After the collision the bowling ball has a velocity (in the same direction) of v7 = 1.05 m/s. 4 335 Part (a) Write an expression for the velocity of pin in the horizontal direction after the impact Vp
The velocity of the pin in the horizontal direction after the impact is 3.95 m/s.
Given, Mass of the bowling ball, mb = 3.7 kg
Velocity of the bowling ball before the collision, v1 = 2.2 m/s
Mass of the pin, mp = 0.37 kg
Velocity of the bowling ball after the collision,
v2 = 1.05 m/s
Let v3 be the velocity of the pin in the horizontal direction after the impact.In the horizontal direction, there is no external force acting on the system. Therefore,
momentum before collision = momentum after collision.
mb * v1 + mp * 0 = mb * v2 + mp * v3
v3 = [mb * v1 + mp * (v1 - v2)] / mp
Substitute the given values in the above expression.
v3 = [(3.7 kg) * (2.2 m/s) + (0.37 kg) * (2.2 m/s - 1.05 m/s)] / (0.37 kg)v3 = 3.95 m/s
Hence, the velocity of the pin in the horizontal direction after the impact is 3.95 m/s.
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5- A 5 kg object is dropped from rest in a medium that exerts a resistive force with magnitude proportional to the square of the speed. The magnitude of the resisting force is 1 N when the magnitude of the velocity is 2 m/s. Find the velocity v(t) of the object at any time t>0, and find its terminal velocity.
The velocity of the object at any time can be described by the equation \(v(t)=\frac{2}{3} t+\frac{2}{3}\). The terminal velocity of the object is 3 m/s.
In this scenario, the resistive force acting on the object is proportional to the square of its speed. Let's denote the velocity of the object as v(t) and the resistive force as F(r).
According to the given information, when the magnitude of the velocity is 2 m/s, the magnitude of the resisting force is 1 N.
Using Newton's second law, we can write the equation of motion for the object as:
m × a = F(r),
where m is the mass of the object and a is its acceleration.
The resistive force F(r) can be expressed as F(r) = k * v(t)^2, where k is a constant of proportionality. Substituting this into the equation of motion, we have:
m × a = k × \(v(t)^{2}\).
Given that the mass of the object is 5 kg, we have:
5 × a = k × \(v(t)^{2}\).
When the magnitude of the velocity is 2 m/s and the magnitude of the resisting force is 1 N, we can substitute these values into the equation above:
5 × a = k × \(2^{2}\).
5 × a = 4k.
Now, we need to find the expression for the acceleration a. We know that acceleration is the derivative of velocity with respect to time, so a = dv(t)/dt. Rearranging the equation, we get:
\(\frac{d}{dv} (t)=\frac{4k}{5}\)
To find v(t), we integrate both sides of the equation with respect to t:
\(\int\limits^ {} \, dxv(t)=\int\limits^ {} \, (\frac{4k}{5} )dt\).
Integrating, we obtain:
\(v(t)= \frac{4k}{5} t+C\),
where C is the constant of integration.
We are given that when the magnitude of the velocity is 2 m/s, the magnitude of the resisting force is 1 N. This condition allows us to determine the value of the constant C. When v(t) = 2, we have:
\(2= \frac{4k}{5} t+C\).
Since the magnitude of the resisting force is proportional to the square of the velocity, we can write:
1 = k * ×\(2^{2}\).
Solving this equation, we find that k = 1/4.
Substituting the value of k back into the equation, we have:
\(2=(4*\frac{\frac{1}{4} }{5} )*t+C\)
\(2=(\frac{2}{5} )*t+C\).
Simplifying further, we get:
\(C= 2-(\frac{2}{5} )*t\).
Finally, substituting the value of C into the equation for v(t), we have:
\(v(t)=\frac{4}{5} *t+2-(\frac{2}{5} )*t\),
\(v(t)=\frac{2}{3} *t+\frac{2}{3}\)
The velocity v(t) of the object at any time t is given by\(v(t)=\frac{2}{3} t+\frac{2}{3}\).
The terminal velocity of an object is the maximum constant velocity it can achieve in a resisting medium.
In this case, as time goes to infinity (t -> ∞), the term \(\frac{2}{3} t\) in the velocity equation becomes dominant, and the constant term \(\frac{2}{3}\) becomes negligible.
Therefore, the terminal velocity of the object is 3 m/s.
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Which characteristic pair would NOT be included on a dichotomous key to identify these organisms?
The correct answer is (c) It is the most common type of key used by biologists to identify organisms based on their characteristics.
What is the dichotomous key?
A form of identification key called a dichotomous key is used in biology to categorize and identify organisms according to their properties. Only one of a set of paired assertions or options is true for the creature being identified in this series of statements and choices.
To reduce the list of potential names and ultimately choose the organism's name, the user follows the instructions that are supplied after each sentence.
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Missing parts;
Which of the following is not a characteristic of a dichoto-
mous key?
(a) The dichotomous key has a “quartet” of statements de-
scribing the characteristics of organisms.
(b) Each statement is followed by directions to go to an-
other pair of statements until the name of the organism
is identified.
(c) It is the most common type of key used by biologists to
identify organisms based on their characteristics.
(d) Paired statements present an “either-or” choice so that
only one statement is true.
(e) a and b.
on bode's advice, herschel named his newly discovered planet after:
Answer:
On Bode's advice, Herschel named his newly discovered planet after: the Greek god Uranus.
Explanation:
Herschel named his newly discovered planet Uranus on Bode's advice for a couple of reasons:
Mythological Naming Convention: During that time, it was a common practice to name celestial objects after mythological figures, particularly gods from Greek and Roman mythology. Bode suggested following this convention and recommended that Herschel choose a name from Greek mythology for the newly discovered planet.
Connection to the Sky: Uranus was chosen as the name for the planet because it was the name of the Greek god of the sky. Given that Herschel had discovered a celestial object in the sky, naming it after the god associated with the sky seemed fitting.
By naming the planet Uranus, Herschel paid homage to the mythological tradition of naming celestial bodies while also establishing a connection between his discovery and the vastness of the sky.
Hope this helps!
What part of the microscope do you adjust to change the amount of light?
The microscope has two sets of lenses, one in the eyepiece and one in the objective lens. The amount of light is changed by adjusting the diaphragm of the microscope. The diaphragm controls the amount of light that passes through the stage and is focused on the object being viewed.
There are two types of diaphragms in a microscope: the iris diaphragm and the disk diaphragm. The iris diaphragm is adjustable, while the disk diaphragm is preset. The iris diaphragm is located near the base of the microscope and can be adjusted to control the amount of light that enters the microscope. It works like a camera aperture, opening or closing to let in more or less light. When the iris diaphragm is closed, less light enters the microscope, and the image appears darker.
When the iris diaphragm is open, more light enters the microscope, and the image appears brighter. By adjusting the iris diaphragm, you can get the best possible image of the object being viewed. To summarize, the diaphragm is the part of the microscope that you adjust to change the amount of light. The iris diaphragm is adjustable, while the disk diaphragm is preset. By adjusting the diaphragm, you can get the best possible image of the object being viewed.
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a dart is launched with a speed of 16.0 m/s at an angle of 30.0o above horizontal. how many seconds elapse from launch until the dart travels a horizontal distance of 4.0 m?
The time taken by the dart to reach the distance of 4 meters is 0.25 seconds
The speed of the dart is 16 m/s
The dart is launched at an angle of 30°
The distance traveled by the dart = 4 m
The time taken by the dart to reach a particular distance can be found using the formula
s = d / t
where s is the speed
d is the distance
t is the time taken
Let us re-write the above equation in order to find the time taken,
t = d /s
Let us substitute the known values in the above equation, we get
t = 4 / 16
= 0.25 seconds
Therefore, the time taken by the dart is 0.25 seconds
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eyeglass lenses can be coated on the inner surfaces to reduce the reflection of stray light to the eye. if the lenses are medium flint glass of refractive index 1.62 and the coat- ing is fluorite of refractive index 1.432, (at) what minimum thickness of film is needed on the lenses to cancel light of wavelength 550 nm reflected toward the eye at normal incidence? (b) will any other wave- lengths of visible light be cancelled or enhanced in the reflected light?
The minimum thickness of the film needed to cancel light of wavelength 550 nm reflected toward the eye at normal incidence is zero. No other wavelengths of visible light will be cancelled or enhanced in the reflected light.
To determine the minimum thickness of the film needed to cancel light of wavelength 550 nm reflected toward the eye at normal incidence, we can use the concept of interference in thin films.
For constructive interference to occur and cancel the reflected light, the phase difference between the light waves reflected from the top and bottom surfaces of the film should be an integer multiple of the wavelength.
The condition for constructive interference in a thin film is given by:
2nt = mλ
Where:
n = refractive index of the film
t = thickness of the film
m = integer representing the order of the interference (m = 0 for the first minimum)
λ = wavelength of the incident light
In this case, the incident light is traveling from the medium flint glass (refractive index 1.62) to the fluorite coating (refractive index 1.432).
For the first minimum (m = 0), the phase difference should be zero. Thus, the thickness of the film (t) should satisfy:
2nt = 0
Since the refractive index of the film is less than the refractive index of the medium flint glass, we can assume the film is thinner than a wavelength of light. Therefore, we can disregard the higher-order interference effects.
Now we can solve for the minimum thickness of the film (t) using the equation:
2nt = 0
t = 0 / (2n)
t = 0
The minimum thickness of the film needed to cancel light of wavelength 550 nm reflected toward the eye at normal incidence is zero.
(b) Since the minimum thickness of the film is zero, no other wavelengths of visible light will be cancelled or enhanced in the reflected light.
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One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other words, they stick together after the collision and move off with a common velocity. Momentum is conserved. The speed of the object that is moving initially is 25 m/s. The masses of the two objects are 3.0 and 8.0 kg. Determine the final speed of the two-object system after the collision for the case when the large-mass object is the one moving initially and the case when the small-mass object is the one moving initially.
Large object moving, small object at rest:
v = 18.18m/s
Small object moving, large object rest:
v= 6.81m/s
Explanation:
p = mv
m1•Vi1 + m2•Vi2 = m1•Vf1 + m2•Vf2
First Scenario (large object moving):
For small object,
p=mv
p= 3kg • 0 = 0
For large object,
p= mv
p= 8kg • 25m/s = 200kg•m/s
Combined,
p1+p2 (small object + large object) = 200m/s
After the collision, there is one mass,
new mass is 8kg + 3kg = 11kg
So now , p = mv again. In this case
200m/s = (11kg)•v
v = (200kg•m/s)/(11kg) = 18.18 m/s
Second Scenario (small object moving):
p1v1 = 3kg•25m/s = 75kg•m/s
p2v2 = 8kg•0 = 0
p1v1 + p2v2 = 75kg•m/s
New mass = 8kg+ 3kg = 11kg
p = mv
75kg•m/s = 11kg•v
v = (75kg•m/s)/11kg = 6.81m/s
The concorde jet was a supersonic plane created in 1976 to speed transportation across the ocean it traveled at twice the speed of sound shortening a normal seven to eight hour transatlantic trip to three and and a half hours however the concorde still had to fly in the atmospheric conditions as every other plane given this information
In Stratosphere layer the Concorde cruise, the troposphere wouldn't carry the Concorde. The temperature increases with weight in stratosphere.
The stratosphere layer is one of the layers of the atmosphere on Earth. In an upward direction, it is the second layer of the atmosphere. Right under the stratosphere is the lowest layer, the troposphere. The mesosphere is the stratosphere's higher-level neighbour. At mid-latitudes, the stratosphere's bottom is located around 10 kilometres (6.2 miles, or about 33,000 feet) above the surface. A 50 km altitude marks the stratosphere's highest point (31 miles). With latitude and seasonal changes, the height of the lower stratosphere varies. When compared to the poles, the lower boundary of the stratosphere can range from 7 km (4 miles) to 20 km (12 miles), or a height of 65,000 feet, close to the equator.
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Why Concorde jet was not cruise in Troposphere?
Where do rock formations go when they are subducted?
Group of answer choices below
A. Above the surface
B. Into the ocean
C. Into the mantle
D. To the core
Option C: Rock formations are subducted into the mantle after subduction.
Describe subduction.Where two or more lithospheric plates meet, a geological process called as subduction recycles rocks from the oceanic lithosphere into the Earth's mantle. Where the tectonic plate converged between the oceanic lithosphere and a less dense lithosphere, the heavier plate sinks beneath the other plate into the mantle.
Deeply subducted sedimentary and metaphorical rocks eventually melt to generate magma, which subsequently cools to form igneous rock.
Therefore the rock cycle encompasses the entire process and lasts millions of years.
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The boat's 'echo sounder' could not be used in an aeroplane to measure its heigh
above the ground unless it had been modified.
True, this is because the echo sounder that is applicable to boats cannot be used directly for airplanes
How does an echo sounder work?By sending out sound waves and timing how long it takes for them to bounce back, an echo sounder, sometimes referred to as a sonar, is a device frequently used in boats to gauge the depth of the water beneath the craft.
When a sound pulse from an echo sounder strikes a solid item in the water, such as fish, vegetation, or other objects, the signal is reflected back to the surface.
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Traveling at high altitudes_________ vehicle engine performance when compared to operating the same vehicle at sea level
Answer:
Lessens
Explanation:
The performance of an engine at high altitudes is lower due to the decreasing density of air with elevation, such that at high altitude, the density is much less and a given quantity of oxygen occupies much more space at high altitudes, and the oxygen content in the air drawn in is lesser at high altitude, and the combustion power is much lesser at high altitudes when the engine speed is high up to about 4000 rpm.
If an electroscope is negatively charged, what will happed to the leaves if another negatively charged rod were brought close to the electroscope
If an electroscope is negatively charged and another negatively charged rod is brought close to it, the leaves of the electroscope will repel each other and move further apart.
This is because like charges (in this case, negative charges) repel each other according to the principle of electrostatics. The negatively charged rod creates an electric field around it, and when it approaches the negatively charged electroscope, the negative charges in the electroscope experience a repulsive force.
This force causes the leaves of the electroscope to separate as they repel each other due to the like charges. The movement of the leaves in response to the presence of the negatively charged rod is a result of the redistribution of charge within the electroscope.
The negative charge on the rod induces a separation of charges in the electroscope, with negative charges being repelled towards the leaves. As a result, the leaves acquire a higher negative charge, causing them to repel each other and move apart. This serves as a visual indication of the presence of the negatively charged rod and the resulting repulsive forces between the charges.
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A person on a daily diet of 2,500 calories should get no_more than
calories from fat each day.
Answer:
35%
Explanation:
Answer:
its 83
Explanation: