true or false applied chemistry does not have a specific goal or application

Answers

Answer 1

Answer:

False. The goal of chemistry is to accumulate knowledge. Sometimes true. Biochemistry involves ... Sometimes true. Applied Chemistry is used to attain specific goals ... Applied Chemistry.

Explanation:

I really hope this helped :)


Related Questions

What is the density of a 500g box whose volume is 67 ml?

Answers

Answer:

7.46 g/mL

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 500 g

volume = 67 mL

We have

\(density = \frac{500}{67} \\ = 7.462686\)

We have the final answer as

7.46 g/mL

Hope this helps you

for the following pairs of elements, identify the element that would be expected to be more electronegative based on periodic tables

for the following pairs of elements, identify the element that would be expected to be more electronegative

Answers

Answer:

Chlorine (Cl)

Explanation:

Bromine: 2.96 electronegative

Chlorine: 3.16 electronegative

3.16 > 2.96

Hope this helps!!

in an attempt to neutralize of a solution, of a solution was added. what is the of the resulting solution?

Answers

The pH of the resulting solution would depend on the identity and concentration of the added neutralizing solution.

When a solution is neutralized, it means that the pH of the solution has been adjusted to 7, which is considered neutral on the pH scale. The pH of the resulting solution after neutralization would depend on the identity and concentration of the neutralizing solution that was added.

For example, if an acidic solution with a pH of 3 was neutralized with a basic solution with a pH of 11, the resulting pH would be around 7. However, if a weaker basic solution with a pH of 9 was used instead, the resulting pH would be slightly acidic, around 6.5. It is important to note that the amount of the neutralizing solution added also plays a role in determining the final pH of the resulting solution.

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When an acidic or basic solution is neutralized, the pH of the resulting solution depends on the identity and concentration of the neutralizing solution.

If the neutralizing solution is a strong acid or base, it would completely dissociate in water and result in a pH closer to the pH of the added solution. For example, if a strong base like sodium hydroxide (NaOH) is added to an acidic solution, the hydroxide ions (OH-) from NaOH will react with the hydrogen ions (H+) from the acid to form water. The resulting solution will have a pH closer to 7, which is neutral.

On the other hand, if the neutralizing solution is a weak acid or base, the pH of the resulting solution would depend on the concentration and dissociation constant of the weak acid or base. The resulting solution will have a pH that is slightly higher than the initial pH, depending on the concentration and dissociation constant of acetic acid.

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calculate the ph of a solution made by putting 4.62 g of lioh into water and diluting to a total volume of 400. ml

Answers

Solution's pH made by putting 4.62 g of LiOH into water and diluting to a total volume of 400 ml is approximately 13.45.

To calculate the pH of the solution made by putting 4.62 g of LiOH into water and diluting to a total volume of 400 ml, we need to first determine the concentration of hydroxide ions (OH-) in the solution using the following formula:

Concentration of OH- = (moles of LiOH) / (volume of solution in liters)

The molar mass of LiOH is 23.95 g/mol + 16.00 g/mol + 1.01 g/mol = 40.96 g/mol. Therefore, the number of moles of LiOH in 4.62 g can be calculated as:

moles of LiOH = (4.62 g) / (40.96 g/mol) = 0.1127 mol

The volume of the solution is 400 ml, which is equivalent to 0.4 L. Therefore, the concentration of OH- in the solution can be calculated as:

Concentration of OH- = (0.1127 mol) / (0.4 L) = 0.2818 M

Next, we can use the formula for the pOH of a solution to determine the pH of the solution:

pOH =\(-log[OH-]\)

pOH = \(-log(0.2818)\)

pOH = 0.5507

Finally, we can use the relationship between pH and pOH to calculate the pH of the solution:

pH = 14 - pOH

pH = 14 - 0.5507

pH = 13.4493

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PLZ HELP GIVING BRAINLEST TO WHO EVER HELPS AND GETS THE RIGHT ANSWER. Plz and tysm

The pavement on a hot day has transformed light energy from______ to heat energy.


1. Radiation

2. Conduction

3. Convection

4.All of the above

Answers

Answer:

4. all the above

Explanation:

It's all of the above because Thermal energy has all three. An example is like a pot of water on the stove boiling.  Radiation is coming off of the eye of the stove. Conduction occurs when heat transfers from hot to cold ( like the handle of the pot). Convection occurs in the boiling of the water by rotating causing the heat to rise.

The d-d transition in [Ti(H2O)6]3+(aq) produces an absoption maximum at 500 nm. What is the magnitude of DELTA for this complex in kJ/mol?
HINT: E=h v and c =LAMBDA v
Enter answer using 3 sig figs, doNOT include decimal point

Answers

The magnitude of Δ for this complex is 2.40 x 10^4 kJ/mol.

We can use the relation between energy (E) and frequency (v) of light:

E = h*v

where h is the Planck's constant.

The frequency of light can be related to its wavelength (λ) and speed of light (c) as:

v = c/λ

where c is the speed of light.

We know that the absorption maximum for the d-d transition in \([Ti(H_2O)_6]^{3+}\)occurs at a wavelength of 500 nm. Therefore, the frequency of the absorbed light is:

v = c/λ = (3.00 x 10^8 m/s) / (500 x 10^-9 m) = 6.00 x 10^14 Hz

The energy of the absorbed light can be calculated using the first equation:

E = hv = (6.626 x 10^-34 Js) * (6.00 x 10^14 Hz) = 3.98 x 10^-19 J

We can convert this energy to kilojoules per mole using the Avogadro's number:

3.98 x 10^-19 J * (6.02 x 10^23 mol^-1) / 1000 J kJ^-1 = 2.40 x 10^4 kJ mol^-1

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The magnitude of DELTA for the d-d transition in [Ti(H2O)6]3+(aq) is 26.4 kJ/mol. To calculate DELTA, we first need to calculate the frequency of the absorbed light

To calculate DELTA, we first need to calculate the frequency of the absorbed light using the formula E = hν, where E is the energy of the absorbed light, h is Planck's constant, and ν is the frequency of the light.

We can then use the formula c = λν, where c is the speed of light and λ is the wavelength of the absorbed light, to calculate the frequency. The wavelength of the absorbed light is given as 500 nm. Using these equations, we can calculate the frequency of the absorbed light to be 6.0 x 10^14 s^-1.

Next, we use the equation DELTA = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the absorbed light, to calculate DELTA.

Substituting the values into the equation, we get DELTA = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(500 x 10^-9 m) = 39.8 x 10^-20 J. Converting the result to kJ/mol using Avogadro's number, we get 26.4 kJ/mol.

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To what temperature must a given Mass of nitrogen at 0°c heated so that both it volume and pressure will be double.​

Answers

1/4  temperature must give Mass of nitrogen at 0°c heated so that both it volume and pressure will be double.​

To double both the volume and pressure of a given mass of nitrogen at 0°C, we can utilize the combined gas law, which relates the initial and final states of a gas. The combined gas law is expressed as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.

Since we want to double both the volume and pressure, we can set P2 = 2P1 and V2 = 2V1. Plugging these values into the combined gas law equation, we get:

(2P1 * 2V1) / T1 = P1 * V1 / T2

Simplifying the equation, we find:

4P1V1 = P1V1 / T2

Cancelling out the common terms, we have:

4 = 1 / T2

Rearranging the equation, we find:

T2 = 1 / 4

Therefore, to double both the volume and pressure of the given mass of nitrogen at 0°C, it must be heated to a temperature of 1/4 or 0.25 times its initial temperature.

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g Determine whether the statements below are true or false. I. The relationship between the concentrations of reactants and products of a system at equilibrium is given by the law of mass action. [ Select ] II. At equilibrium, the concentrations of the reactants and products are constant over time. [ Select ]

Answers

True is the answer to statement I, and true is the answer to statement II. The relationship between the concentrations of reactants and products of a system at equilibrium is given by the law of mass action.

In other words, the mass action law states that the rate of a chemical reaction is proportional to the concentrations of the reactants. The concentrations of the reactants and products are constant over time when the system reaches equilibrium. The rate of the forward reaction is equal to the rate of the reverse reaction at equilibrium, and there is no net change in the concentration of the reactants and products. When there is a disturbance to an equilibrium system, such as changing the temperature or pressure, the system will shift to re-establish equilibrium.

The two statements given are true, and are in line with the concept of chemical equilibrium. When a chemical reaction reaches equilibrium, the concentrations of the reactants and products no longer change. At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction, and the equilibrium position can be changed by changing the temperature, pressure, or concentration of the reactants or products. The mass action law is a mathematical equation that relates the concentrations of the reactants and products to the rate of the chemical reaction. The equilibrium constant is derived from the mass action law and is used to predict the position of equilibrium for a chemical reaction.

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The second step in the Gram staining procedure involves flooding the slide for one minute with ____
A. a decolorizing agent. B. iodine. C. safranin.

Answers

The second step in the Gram staining procedure involves the flooding of the slide for the one minute is with iodine . The correct option is B. iodine.

There are the four fundamental steps in the Gram stain process , the first is to apply a base color that is the crystal violet. In second step  adding the Gram's iodine as the mordant. In the third step, the Rapid decolorization with the acetone, the ethanol, or the combination of the two and in the four step,  Using the safranin as the counterstain.

Thus, the iodine will be used in the second step in the Gram staining process that involves the flooding in the slide for one minute.

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heat of vaporization is the amount of heat required to

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Heat of vaporization is the amount of heat energy required to convert a substance from its liquid state to its gaseous state at a constant temperature and pressure. It is a measure of the strength of the intermolecular forces holding the molecules together in the liquid phase.

Heat of vaporization:

Heat of vaporization is the amount of heat energy required to convert a substance from its liquid state to its gaseous state at a constant temperature and pressure. It is a measure of the strength of the intermolecular forces holding the molecules together in the liquid phase.

When a substance is heated, the added energy increases the kinetic energy of the molecules, causing them to move faster. As the temperature rises, the average kinetic energy of the molecules increases, and eventually, the molecules have enough energy to overcome the intermolecular forces and escape from the liquid phase, forming a gas.

The heat of vaporization is specific to each substance and is typically expressed in units of joules per gram (J/g) or calories per gram (cal/g). It is an important property in various applications, such as in the design of cooling systems, understanding phase changes, and calculating energy requirements for processes involving vaporization.

Fact:

The heat of vaporization for water is approximately 40.7 kilojoules per mole (kJ/mol) at its boiling point of 100 degrees Celsius.

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The heat of vaporization is the amount of heat required to convert one gram of a substance from its liquid state to its gaseous state without any change in temperature. It is denoted by delta Hvap.

This is a measure of the energy that is required to overcome the intermolecular forces that hold a liquid together and break the bonds between the molecules to form a gas.Heat of vaporization is the amount of heat required to convert one gram of a substance from its liquid state to its gaseous state without any change in temperature.

There are many interesting phenomena where the heat of vaporisation can be seen. For instance, heat is continuously added to liquid water when it boils on a hob in order to overcome the intermolecular interactions and turn it into water vapour. Similar to how sweat evaporates from our skin, the heat that is removed from us as the sweat changes from a liquid to a gas cools us down.

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What is the final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l?

Answers

The final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l will be 475 K.

The volume as well as Kelvin temperature will be directly proportional whenever the pressure on even a sample of such a dry gas remains held constant. PV = k would be the law's equation.

Charle's law give the relation between the temperature and volume is shown as:

\(V_{1} / T_{1} = V_{2} / T_{2}\)

where. V is volume and T is temperature.

Given data :

\(V_{1} =22.4 l\\V_{2} = 38.3 l\\T_{1} = 278 K\\T_{2} = ?\)

Put the value of given data in above equation.

22.4 l /   38.3 l = 278k / \(T_{2}\)

\(T_{2}\) = 475 K.

Therefore, the final temperature will be 475 K.

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Select the correct answer.

What effect does an increase in products have on the reaction rate of a mixture at equilibrium?

A.
The forward reaction rate increases.
B.
Both the forward and the reverse reaction rates decrease.
C.
Both the forward and the reverse reaction rates increase.
D.
The reverse reaction rate increases.

Answers

Answer:

Both the forward and the reverse reaction rates decrease.i hope I help you to day and have a good day

add lone pairs to the lewis structure of the polyhalide ion clf−2 .

Answers

The Lewis structure of the polyhalide ion ClF2- can be modified by adding lone pairs to the appropriate atoms.

How can the Lewis structure of the polyhalide ion ClF2- be adjusted by incorporating lone pairs?

In the Lewis structure of the polyhalide ion ClF2-, additional lone pairs can be added to specific atoms to accurately represent the electronic configuration.

By including lone pairs, we account for the non-bonding electrons that exist around the central atom (chlorine) and the terminal atom (fluorine). These lone pairs help maintain the octet rule and depict a more complete representation of the electron distribution within the molecule.

Adding lone pairs to the Lewis structure of ClF2- involves placing two lone pairs on the chlorine atom and leaving no lone pairs on the fluorine atoms. This configuration satisfies the octet rule for each atom and provides a balanced distribution of electrons.

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Explain how the bonding model for sodium metal would differ from the bonding model for sodium chloride, NaCi

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Sodium metal is quite reactive; sodium ions (as in NaCl) are quite unreactive. Cl^- ions are not reactive; they are stingily attracted to positive ions such as Na^+with which they form ionic bonds.

The bonding in NaCl involves a sodium ion and a chloride ion while the bonding in sodium metal involves sodium ions and a sea of electrons.

NaCl involves sodium and ion and chloride ion held together by an ionic bond. The sodium atom transfers an electron to chlorine atom to yield the chloride ion. This ion pair exists in the compound called sodium chloride.

In sodium metal, the sodium cations interact electrostatically with a sea of electrons in a metallic bond. Hence, while the bonding in sodium chloride involves an ion pair, the bonding in sodium metal involves sodium ions and a sea of electrons.

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Can someone do questions, 1, 2 and 3 if possible please?

Can someone do questions, 1, 2 and 3 if possible please?

Answers

Mass of magnesium ribbon is 0.21 g.

Mass of oxygen gas reacts with magnesium is 0.11 g

Number of moles of magnesium is 0.00875

Number of moles of oxygen is 0.0068.

Ratio of moles of magnesium and oxygen = 1.2 : 1

The number of moles of a substance equals the ratio of its given mass in a chemical reaction to the mass of one mole of that substance. One mole of any substance equals Avogadro's number, that is, 6.023 × 10²³.

we know that mass of crucible and lid = 35.56 g

mass of crucible and lid and magnesium = 35.77 g

Thus mass of magnesium = 35.77 - 35.56 = 0.21 g

mass of crucible and lid and magnesium oxide = 35.88 g

thus, mass of oxygen = 35.88 - 35.77 = 0.11 g

Now, Number of moles of magnesium = 0.21/24 =  0.00875

         Number of moles of Oxygen = 0.11/16 = 0.0068

Ratio of Number of moles of magnesium to Number of moles of Oxygen = 0.00875/0.0068 = 1.2 : 1.

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In a balanced chemical equation, a. Atoms are conserved. B. Coefficients are equal. C. Molecules are equal. D. Energy is not conserved.

Answers

Atoms are conserved in a chemical equation that is balanced. The choice that is best is A. We can see two copper, four chloride, four iodine, four potassium, and four atoms present

What sort of chemical equation would you use?

Chemical equations are used to depict how reactants change into products. For instance, iron sulfide is created when iron (Fe) and sulfur (S) combine (FeS). FeS = S(s) + Fe(s) (s) An iron-sulfur interaction is indicated by the plus symbol.

What do chemical equation solutions consist of?

They were equations that use chemical symbols and formulae to express chemical reactions. The reactants are shown on the left side of a chemical equation, and the products were shown on the right.

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drag the h2o molecule next to the hno3 molecule and observe what happens. what chemical species is transferred from hno3 to h2o? enter its name, not its formula.

Answers

HNO3 transfers a hydrogen ion to H2O.

What species is transferred from HNO3 to H2O?

When the H2O molecule is brought close to the HNO3 molecule, a transfer of a hydrogen ion (H+) occurs from HNO3 to H2O.

This transfer leads to the formation of H3O+ (hydronium ion) and NO3- (nitrate ion).

HNO3, also known as nitric acid, is a strong acid composed of hydrogen (H), nitrogen (N), and oxygen (O) atoms. H2O, or water, consists of two hydrogen (H) atoms and one oxygen (O) atom.

In the presence of an acid like HNO3, water can act as a base and accept a proton (H+) from the acid.

As HNO3 donates a proton to H2O, the hydrogen ion (H+) bonds with one of the lone pairs of electrons on the oxygen atom in H2O, forming the hydronium ion (H3O+).

This process is represented by the equation: HNO3 + H2O -> H3O+ + NO3-.

The resulting hydronium ion, H3O+, is a positively charged ion with a central hydrogen atom bonded to three hydrogen atoms and a lone pair of electrons.

The nitrate ion, NO3-, carries a negative charge and consists of one nitrogen atom bonded to three oxygen atoms.

In summary, when the H2O molecule is brought near the HNO3 molecule, a transfer of a hydrogen ion occurs, resulting in the formation of hydronium ion (H3O+) and nitrate ion (NO3-).

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Relative formula mass of carbon manoxide​

Answers

Explanation:

The relative formula mass of a substance, shown in grams, is called one mole of that substance. So one mole of carbon monoxide has a mass of 28 g, and one mole of sodium oxide has a mass of 62 g

Answer:

M(CO)=28 (g/mol)

Explanation:

M= 12+16=28 (g/mol)

Are the properties of the element and its compounds the same? Use
fluorine and fluorides to explain your answer.
3 marks

Answers

The properties of the element and its compounds are not the same. In the case of fluorine, we know that this is a volatile and reactive element but fluorides are stable and less harmful elements that can serve beneficial purposes.

Difference between fluorine and fluorides

Fluorine is a chemical element that is known for its ability to combine easily with oxygen and other elements. It is a highly reactive substance but this is not the case with fluorides. The fluorides have already undergone a reaction so they are no longer as volatile as fluorine in the ordinary state.

They are used in toothpaste formulations to strengthen the gums but this cannot be said of fluorine which should not be tasted in the raw state.

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Work Right, Work Safe at School and at Home
A laboratory is any area where science investigation occurs. Even your kitchen can be considered as one. What laboratory tools or equipment can be substituted with kitchen-wares? Choose five tools found in the laboratory and give a kitchenware that can serve as a substitute for each.

Laboratory Tools Kitchen-wares Substitute
Name:
Drawing/Illustration:
Use:
Name:
Drawing/Illustration:
Use:
Name:
Drawing/Illustration:
Use:
Name:
Drawing/Illustration:
Use:
Name:
Drawing/Illustration:
Use:

QUESTIONS:
1. Why is it important to know the use of laboratory tools and equipment? Give at least two reasons.

2. Why must working safe be practice in the laboratory?

Answers

A. Hot Plate - Materials are heated using hot plates. A stove may readily take the place of this equipment.

B. Test Tube Holder - Kitchen tongs, which come in various sizes, can be utilized in the absence of test tube holders.

C. Beakers and flasks are used for both measuring liquids and combining various ingredients. At home, measuring cups and measuring spoons can take their place because they are wide or tall enough to be used for mixing and still have the ability to be used to measure the ingredients.

D. Stirring Rod - A stirring rod can be replaced by a variety of items. Chopsticks are an example because of their similar shape, as are spoons, ladles, and forks if the container allows them.

E. Funnel - Typically, the material used to make a kitchen funnel and a laboratory funnel is the sole distinction. Kitchen funnels are often made of plastic, whereas laboratory funnels are made of heat-resistant glass. Nevertheless, as long as it is not exposed to extremely high temperatures, it can still perform the duties of a standard laboratory funnel.

1. Before conducting any type of experiment, you should always be familiar with your lab's equipment because, without it, you won't know how to use your materials or how to fix a mistake you might make with it.

2. You may aid in preventing or eliminating hazards by being familiar with the laboratory you're working in and by constantly adhering to the correct safety protocols. Additionally, you'll be aware of what to do in the unfortunate case that something goes wrong.

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Can someone help me with this

Can someone help me with this

Answers

Answer:

i believe the correct answer is "Complete metamorphosis"

Explanation:

the synthesis of ch3oh(g) from co(g) and h2(g) is represented by the equation above. the value of kc for the reaction at 483 k is 14.5. a mixture of co(g) and h2(g) is pumped into a previously evacuated 2.0 l reaction vessel. the total pressure of the reaction system is 1.2 atm at equilibrium. what will be the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l at constant temperature? responses less than 1.2 atm less than 1.2 atm greater than 1.2 atm but less than 2.4 atm greater than 1.2 atm but less than 2.4 atm 2.4 atm 2.4 atm greater than 2.4 atm

Answers

According to Boyle's law which is a law for constant temperature the  the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l  is 2.4 atmospheres.

What is Boyle's law?

Boyle's law is an experimental gas law which describes how the pressure of the gas decreases as the volume increases. It's statement can be stated as, the absolute pressure which is exerted by a given mass of an ideal gas is inversely proportional to its volume provided temperature and amount of gas remains unchanged.

Mathematically, it can be stated as,

P∝1/V or PV=K. The equation states that the product of of pressure and volume is constant for a given mass of gas and the equation holds true as long as temperature is maintained constant.

According to the equation the unknown pressure and volume of any one gas can be determined if two gases are to be considered.That is,

P₁V₁=P₂V₂

Substitution in above equation gives P₂=1.2×2/1=2.4 atmospheres.

Hence, the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l  is 2.4 atmospheres.

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what is not a colligative property

Answers

Qualities of a solution known as coagulative qualities rely on the quantity of solute particles present but not on the kind of solute.

Boiling point elevation, osmotic pressure, and vapour pressure depression are a few examples of colligative qualities. Solubility is the response to the query of what is not a collative property.

The amount of a solute that can dissolve in a solvent is known as its solubility, and the solute's type does affect this quantity. Solubility is not a collative quality, then.

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My topic is cell phone radiation’s for my stem fair project, what should be my question and hypothesis?

Answers

Here are some potential questions and hypotheses for a stem fair project on cell phone radiation:

Question: Does the distance between a cell phone and a person's head affect the level of radiation exposure?

Hypothesis: If a cell phone is held closer to a person's head, then the level of radiation exposure will be higher.

Question: Do different types of cell phone cases affect the level of radiation exposure?

Hypothesis: If a cell phone is covered by a case made of a certain material, then the level of radiation exposure will be lower.

Question: How does the amount of time a person spends on their cell phone affect their level of radiation exposure?

Hypothesis: If a person spends more time on their cell phone, then their level of radiation exposure will be higher.

It's important to note that these are just a few potential ideas, and you may want to come up with your own question and hypothesis based on your interests and the resources available to you. It's also important to conduct thorough research and use reliable sources to support your conclusions.

Determine the empirical formula for each of the following 0.0130 mol carbon, 0.0390 hydrogen.

Answers

Here in the question determine the number of moles of each element relative to the other elements. Divide all the quantities by the smallest moles

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An increase in the bat population would most likely result in
А
Decrease in mold growth
B
An increase in the outisde insect population
с
A decrease in bat bug population
D
A decrease in the outside insect population

Answers

Answer:

Explanation:

D

A decrease in the outside insect population

A template of a Venn diagram representing common and differentiating characteristics of covalent and ionic bonds is shown.


Which of the following characteristics can be written only in space B?
Occurs in substances that have at least one non-metal
Occurs in substances that have a repeating lattice structure
Occurs in substances that have discrete molecular structure
Occurs in substances that have high melting points

A template of a Venn diagram representing common and differentiating characteristics of covalent and

Answers

Ionic and covalent bonds can occur in substances that have a repeating lattice structure.

Ionic and covalent bonds

Ionic bonds are formed when an atom donates electron (s) to another atom. Covalent bonds, on the other hand, are formed when two atoms share electrons to complete their octet states.

Ionic compounds are formed from a combination of metal and non-metal atoms. They usually have crystalline lattice structures with high melting points.

Covalent compounds are formed between non-metal atoms. They can also have lattice structures but generally have lower melting points because the forces holding the molecules together are weaker.

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Answer:

Occurs in substances that have a repeating lattice structure

Explanation:

In a 2.00 g sample, which has the greatest number of atoms?
AI
S
All are equal
Na
Р

Answers

Answer

so AI has 13 atoms

S has 16 atoms

Na has 11 atoms

P has has 15 atoms

so the one with the most is S

S is sulfur

sulfur has many uses when it is processed along with some some biological uses.

Explanation:

hydrogenation of a monounsaturated fatty acid yields a saturated fatty acid. oleic acid, ch3(ch2)7ch

Answers

The hydrogenation of a monounsaturated fatty acid, such as oleic acid, can indeed yield a saturated fatty acid.

Oleic acid has the molecular formula CH₃(CH₂)7CH=CH(CH₂)7COOH, where the double bond is located between the ninth and tenth carbon atoms from the carboxylic acid end.

Hydrogenation is a chemical reaction that involves the addition of hydrogen (H₂) to a compound. In the case of oleic acid, hydrogenation can be achieved by using a suitable catalyst, typically a metal catalyst such as nickel or palladium, under specific reaction conditions.

During hydrogenation, the double bond in oleic acid is broken, and hydrogen atoms are added to the carbon atoms that were part of the double bond. This process converts the unsaturated fatty acid into a saturated fatty acid. The resulting saturated fatty acid derived from oleic acid is called stearic acid, which has the molecular formula CH₃(CH₂)16COOH.

By undergoing hydrogenation, oleic acid, a monounsaturated fatty acid with one double bond, is converted into stearic acid, a saturated fatty acid with no double bonds. The addition of hydrogen atoms effectively saturates the fatty acid chain, removing the unsaturation.

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Complete Question:  hydrogenation of a monounsaturated fatty acid yields a saturated fatty acid. oleic acid, ch3(ch2)7ch. What is the difference in molecular structure between oleic acid and stearic acid after hydrogenation?

Tick the substance that is not a covalent structure
Silicon dioxide
Methane
Sodium Chloride
Carbon Monoxide

Answers

Sodium chloride is a compound which does not  have a covalent structure.

What is a  compound?

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

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