true or false: a tennis ball following a parabolic trajectory without air resistance has two forces acting on it; gravity downward and a force keeping it moving forward.

Answer:

Anyone can sit in a corner office and delegate tasks, but there is more to effective leadership than that. Effective leaders have major impacts on not only the team members they manage, but also their company as a whole. Employees who work under great leaders tend to be happier, more productive and more connected to their organization – and this has a ripple effect that reaches your business's bottom line

Explanation:

:)

Answer: The displacement of the object is 5 units to the right.

Explanation: 0 + 3 - 4 + 6 = 5

(left is in the negative direction, whereas right is in the positive.)

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

The impulse, momentum and final velocity can all be obtained from Newton's second law.

Let us recall that the impulse is obtained as the product of force and time.

Impulse = Force × time

Impulse = 6 N × 10 s = 60 Ns

From Newton's second law of motion;

F.t = mv - mu

Since the object was initially at rest;

F.t = mv

Hence, the final velocity of the object is 60 Kgms-1

The final velocity is obtained from;

F.t = mv

v = F.t/m

v = 6 × 10/20

v = 3 m/s

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Answer:

20 hours

Explanation:

if the truck travels 110 miles in one hours, 110 times 20 equals 2,200.

another way is- 2,200 divided by 110 = 20 hours.

1.24% percentage of parts will not meet the weight specs amd the sample means will fall between 25.046 and 25.354 ounces.

a. To determine the percentage of parts that will not meet the weight specifications, we need to calculate the probability of a part weighing less than 24.7 ounces or more than 25.7 ounces. First, we need to calculate the z-scores for these values using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation. For 24.7 ounces:

z1 = (24.7 - 25.2) / 0.20 = -2.50

For 25.7 ounces:

z2 = (25.7 - 25.2) / 0.20 = 2.50

Using Table-A (Z-score table), we can find the area under the standard normal curve corresponding to these z-values. From the table, the area to the left of -2.50 is 0.0062, and the area to the right of 2.50 is also 0.0062. Therefore, the total probability of a part not meeting the weight specs is:

P(z < -2.50 or z > 2.50) = P(z < -2.50) + P(z > 2.50) = 0.0062 + 0.0062 = 0.0124

So, the percentage of parts that will not meet the weight specs is .

b. To determine the values within which 99.74% of the sample means will fall, we need to calculate the margin of error for a sample mean. The margin of error is given by the formula:

E = z * (σ / sqrt(n))

where E is the margin of error, z is the z-score corresponding to the desired level of confidence (in this case, 99.74% corresponds to a z-score of 2.75), σ is the standard deviation, and n is the sample size.

Plugging in the values:

E = 2.75 * (0.20 / sqrt(10)) ≈ 0.154

The range of sample means will be within ±E of the population mean. Therefore, the values within which 99.74% of the sample means will fall are:

25.2 ± 0.154 = (25.046, 25.354)

So, for samples of size 10, 99.74% of the sample means will fall between 25.046 and 25.354 ounces.

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The upper limit on the efficiency of any heat engine operating between two reservoirs is determined by the Carnot efficiency formula. This theoretical efficiency is given by:

Carnot efficiency = 1 - (Tc/Th)

Where Tc is the temperature of the cold reservoir (in Kelvin) and Th is the temperature of the hot reservoir (in Kelvin). Keep in mind that this is the maximum possible efficiency, and real-world heat engines typically have lower efficiencies due to various losses and imperfections.

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Explanation:

\(Force = mass × acceleration\)

\(50 = 0.26 \times a\)

\(a = 192.307 \: m {s}^{ - 2} \)

The force between the two charges is approximately 0.089 Newtons. Since the charges have opposite signs, the force is attractive, pulling the charges towards each other.

Coulomb's law describes the relationship between the magnitude of the electric force between two charged objects and the distance between them. According to Coulomb's law, the force (F) between two charges (q1 and q2) separated by a distance (r) is given by the formula:

\(F = k * (|q1| * |q2|) / r^2\)

where k is the electrostatic constant (approximately\(9 * 10^9\) \(Nm^2/C^2\)).

In this case, the negative charge (q1) is \(-2.0 * 10^(-4)\) C, and the positive charge (q2) is \(6.5 * 10^(-4)\)C. The distance between them (r) is 0.28 m.

Substituting these values into the Coulomb's law equation, we can calculate the force between the charges. The force will have a magnitude and a direction, depending on the signs of the charges. If the charges have opposite signs, as in this case, the force will be attractive.

Substituting the values:

F = \((9 * 10^9 Nm^2/C^2) * (|-2.0 * 10^-4 C| * |6.5 * 10^-4 C|) / (0.28 m)^2\)

Calculating the magnitude of the force:

F = \((9 * 10^9 Nm^2/C^2) * (2.0 * 10^-4 C) * (6.5 * 10^-4 C) / (0.28 m)^2\)

F = 0.089 N

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True, some of the tiles in Byzantine mosaics were placed at an angle to reflect the light. This was done to enhance the visual appearance and create a dazzling effect.

Byzantine mosaics were used to decorate and embellish the walls, floors, and ceilings of buildings such as churches, palaces, and public places. They were made of small, colored, and shiny tiles called tesserae, which were arranged in various patterns to create intricate and sophisticated designs. One of the notable features of Byzantine mosaics was the use of tesserae at different angles to reflect the light and create a mesmerizing effect. The artists who created the mosaics were highly skilled and trained, and they knew how to use the properties of light to enhance their art. By placing the tiles at an angle, they could make the light bounce off the surface and produce a sparkling and radiant effect. The use of angles also allowed the artists to create depth, texture, and movement in their designs, which made them more dynamic and engaging. The Byzantine mosaics are still admired and revered for their beauty and craftsmanship, and they continue to inspire and influence artists and designers to this day.

In summary, some of the tiles in Byzantine mosaics were placed at an angle to reflect the light and create a dazzling effect. This technique was used by the artists to enhance the visual appearance and create depth, texture, and movement in their designs. The use of tesserae at different angles is one of the defining characteristics of Byzantine mosaics, and it reflects the skill and creativity of the artists who made them.

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In an incompressible flow, the speed at which an acoustic wave propagates depends on the physical properties of the medium through which it is traveling. Generally speaking, the speed of an acoustic wave in an incompressible flow is slower than in a compressible flow, since the latter can support pressure waves that move faster than sound.

The speed of an acoustic wave in an incompressible flow can be calculated using the following formula:

c = √(K/ρ)

where c is the speed of the wave, K is the bulk modulus of the medium (a measure of its resistance to compression), and ρ is its density.

For example, if we assume a bulk modulus of 2.3 GPa and a density of 1000 kg/m^3 (typical values for water), we get a speed of approximately 1500 m/s for an acoustic wave in an incompressible flow.

It's worth noting that this speed can vary depending on the exact conditions of the flow, as well as any obstructions or other features that might affect the propagation of the wave. Nonetheless, the above formula provides a useful starting point for understanding the speed of acoustic waves in incompressible flows.

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Answer:

part a)100 cm

Explanation:

i just did that as a lab

Answer:

0.4

Explanation:

time is disance divided by speed.

a) Tina drives approximately 69.93 meters before passing David.

b) Her speed as she passes him is approximately 34.77 m/s.

To find the distance Tina drives before passing David, we can use the equation:

\(\[d = ut + \frac{1}{2}at^2\]\)

where:

d is the distance traveled,

u is the initial velocity (0 m/s for Tina),

a is the acceleration (2.90 m/s² for Tina), and

t is the time.

First, we need to determine the time it takes for Tina to catch up with David. Since David is driving at a constant speed of 31.0 m/s, the time Tina needs to catch up can be found using the equation:

\(\[t = \frac{d}{v}\]\)

where:

\(\(t\)\)  is the time,

\(\(d\) \\\) is the initial distance between Tina and David (0 m), and

v  is the relative velocity of Tina with respect to David (31.0 m/s).

Substituting the values, we find:

\(\[t = \frac{0\,m}{31.0\,m/s} = 0\,s\]\)

Since Tina begins to accelerate at the instant when David passes, she starts from rest and requires no time to catch up.

a) Using the equation for distance, we find:

\(\[d = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2}(2.90\,m/s²)(0\,s)^2 = 0\,m\]\)

Therefore, Tina does not drive any distance before passing David.

b) Since Tina catches up with David at the same instant he passes, her speed is equal to his speed. Thus, her speed as she passes him is approximately 31.0 m/s.

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Tina drives approximately 158.2 meters before passing David. Tina's speed as she passes David is 31.0 m/s.

To find the distance Tina drives before passing David, we need to determine the time it takes for Tina to catch up with David first. We can use the equation:

d = v0t + 0.5at2

Where d is the distance, v0 is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation to solve for t:

t = (v - v0) / a

Substituting the given values:

t = (0 - 31.0 m/s) / (-2.90 m/s²)

t ≈ 10.69 seconds

To find the distance:

d = v0t + 0.5at2

d = 0 + 0.5(-2.90 m/s²)(10.69 s)2

d ≈ 158.2 meters

Therefore, Tina drives approximately 158.2 meters before passing David.

To find Tina's speed as she passes David, we can use the equation:

v = v0 + at

Substituting the given values:

v = 0 m/s + (2.90 m/s²)(10.69 s)

v ≈ 31.0 m/s

Therefore, Tina's speed as she passes David is 31.0 m/s.

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Earth has a definite orbit within the solar system whose the orbit is mainly a result of the mass of the Sun.

An orbit is defined as the regular, repeating path that one object in space takes around another while an object in an orbit is called a satellite which may be natural, such as the Earth or the Moon. According to the height of satellites from the earth, these orbit are classified as

Most of the weather and some communications satellites will tend to have a high Earth orbit which is farthest away from the surface. The main difference between orbit and orbitals is that the former is defined as a fixed path of electron revolutions, whereas the latter is defined as an uncertain region with a high probability of finding an electron.

Therefore, the Earth has a definite orbit within the solar system whose the orbit is mainly a result of the mass of the Sun.

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The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:

- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m

- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m

To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.

The equation for the braking distance of a vehicle is given by:

d = (v^2) / (2 * μ * g)

where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.

Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.

For small cars with a mass of 563 kg:

- Minimum braking distance:

  v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s

  μ_min = 0.536

  d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m

  Maximum braking distance:

  μ_max = 0.599

  \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)

For large trucks with a mass of 3951395 kg:

- Minimum braking distance:

  v = 8989 km/h = 2496.944 m/s (same as for small cars)

  μ_min = 0.350

 \(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)

  Maximum braking distance:

  μ_max = 0.480

 \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)

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Answer:

it is b on edge not d, well atleast for me it was b

Explanation:

Answer:

B) one battery, two switches, and three light bulbs

Explanation:

The ball moves as it is kicked on this soccer field because its inertia has been overcome.

The ball remains stationary on the ground until the soccer player shoots it in the image below. However, when the ball is kicked, the forces on the ball suddenly become unbalanced. The ball starts moving across the field as the inertia has been negated. Air is compressed when the ball is kicked.

This compressed air pushes the ball causing it to move and return to its original state. Add to this the elasticity of the ball material. A disproportionate force acts on the ball, slowing it down so it won't roll forever. The main force that slows the ball down to a stop is friction. When a ball rolls on the ground the frictional force acts between the surface of the ball and the ground.

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Answer:The energy of nuclear fission is released as kinetic energy of the fission products and fragments, and as electromagnetic radiation in the form of gamma rays; in a nuclear reactor, the energy is converted to heat as the particles and gamma rays collide with the atoms that make up the reactor and its working fluid.

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48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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Answer:

Explanation:

0.44

The closest to the number of meters that the horse would travel in a second option D, 25 meters .

To find the distance that a horse travels in one second while galloping at a speed of 42 miles per hour, we need to convert miles per hour to meters per second.

We can start by using the conversion factor of 1 mile = 1609.34 meters and 1 hour = 3600 seconds.

42 miles/hour = (42 x 1609.34) meters / (3600 seconds) = 18.8976 meters/second

Therefore, the horse would travel approximately 18.9 meters in one second at a speed of 42 miles per hour.

To verify this answer, we can also use the formula:

distance = speed x time

We know that the speed of the horse is 42 miles per hour. To convert this to meters per second, we need to divide by 2.237. This gives us:

speed = 42 miles/hour ÷ 2.237 = 18.8 meters/second (rounded to one decimal place)

If we assume that the horse is traveling for exactly one second, we can plug in the values to find the distance:

distance = speed x time = 18.8 meters/second x 1 second = 18.8 meters

Therefore, we can conclude that the answer is closest to option D, 25 meters

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Answer:The Oort Cloud is about 70 000 times as far

Answer:

a. v(1.8) = -3.14 m/s

b. \(v_{max} = 3.925\ m/s\)

c. \(a_{max} = 3.08\ m/s^2\)

Explanation:

a.

The speed of a particle executing simple harmonic motion is given by the following equation:

\(v(t) = -A \omega \ Sin(\omega t)\)

where,

v = velocity = ?

A = Amplitude = 5 m

ω = angular frequency = \(\frac{2\pi}{Time Period} = \frac{2\pi}{8\ s}\) = 0.785 s

t = time

First we find time at 3 m by using equation for displacement:

\(x = 3\ m = ACos(\omega t)\\Cos((0.785 rad/s)(t)) = \frac{3\ m}{5\ m}\\t(0.785\ rad/s) = Cos^{-1} (0.6)\\t = \frac{0.927\ rad}{0.785\ rad/s}\\t = 1.18 s\)

Therefore,

\(v(1.8) = velocity at 3\ m = -A\omega Sin(\omega t)\\v(1.8) = -(5\ m)(0.785\ rad/s)Sin((0.785\ rad/s)(1.18\ s))\\\)

v(1.8) = -3.14 m/s

c.

The maximum speed is given as:

\(v_{max} = A\omega\\v_{max} = (5\ m)(0.785\ rad/s)\\\)

\(v_{max} = 3.925\ m/s\)

The maximum acceleration is given as:

\(a_{max} = A\omega^2\\v_{max} = (5\ m)(0.785\ rad/s)^2\\\)

\(a_{max} = 3.08\ m/s^2\)

Answer:

the acceleration of the elevator is increasing

Explanation:

For this exercise we propose the solution using Newton's second law

         F -W = m a

         F = m (g + a)

If the net force increases, it implies that the acceleration of the elevator is increasing, since the acceleration of gravity is constant as the ascent is accelerating.

Answer:

The answer is B

Explanation:

Because when the both sides aren't balanced one side has to cause motion. (fall down)

Being made of charged particles, plasmas can do things gases cannot, like conduct electricity. And since moving charges make magnetic fields, plasmas also can have them. In an ordinary gas, all the particles will behave roughly the same way. Auroras, lightning, and welding arcs are also plasmas; plasmas exist in neon and fluorescent tubes, in the crystal structure of metallic solids, and in many other phenomena and objects. The Earth itself is immersed in a tenuous plasma called the solar wind and is surrounded by a dense plasma called the ionosphere.

Plasma is a type of matter in which many electrons freely roam around the nuclei of atoms.

Although plasma is commonly thought of as a subset of gases, the two states behave very differently. Plasmas, like gases, have no definite shape or volume and are denser than solids or liquids.

Plasma is a sort of matter in which numerous electrons freely roam around the nuclei of atoms.

Plasma has been described as the fourth state of matter, alongside solid, liquid, and gas.

Normally, electrons in a solid, liquid, or gaseous sample of matter remain bound to the same nucleus.

Thus, plasma is considered a distinct phase because it does not conform to the standard descriptions and physical laws that are used to describe the standard three states of matter.

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