true aur false
every rational number is not an integer

The acceleration of the particle at S = 40 m is approximately 2\(m/s^2\)

To determine the acceleration of the particle when S = 40 m, we need to use the information given in the graph. The graph shows the velocity of the particle as a function of its displacement, S. Recall that acceleration is the rate of change of velocity with respect to time.

We can estimate the acceleration at S = 40 m by finding the slope of the tangent line to the velocity curve at that point.

One way to estimate the slope of the tangent line is to draw a line that is as close as possible to the curve at the point S = 40 m, and then find the slope of that line. We can use a ruler to draw a tangent line that intersects the curve at S = 40 m, as shown in the graph.

We then measure the displacement and velocity of two points on the tangent line, one on either side of S = 40 m. For example, we might choose the points S = 35 m and S = 45 m, and find their corresponding velocities, which are approximately v = 25 m/s and v = 45 m/s, respectively.

The slope of the tangent line is then given by the change in velocity over the change in displacement:

acceleration = (v2 - v1) / (S2 - S1)

Substituting the values we found, we get:

acceleration = (45 m/s - 25 m/s) / (45 m - 35 m) = 2\(m/s^2\)

Therefore, the acceleration of the particle at S = 40 m is approximately 2\(m/s^2\).

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The forecast value for time period 2 is 210, and the forecast error is -110 when the actual value is 100. Option B

To calculate the forecast value for time period 2, we substitute W = 2 into the regression equation:

y = 200 + W + 2W^2

= 200 + 2 + 2(2^2)

= 200 + 2 + 2(4)

= 200 + 2 + 8

= 210

Therefore, the forecast value for time period 2 is 210.

To calculate the forecast error, we compare the forecasted value with the actual value for time period 2. Given that the actual value is 100, the forecast error can be calculated as the difference between the actual value and the forecast value:

Forecast error = Actual value - Forecast value

= 100 - 210

= -110

Hence, the forecast error is -110.

Therefore, the correct answer is:

Forecast value = 210; forecast error is -110. So Option B is correct.

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Answer:

$31.63/hr

Step-by-step explanation:

Given parameters:

 Yearly salary  = $65788

  Number hours worked per week  = 40hrs

Unknown:

Hourly wage  = ?

Solution:

The hourly wage is found by dividing the yearly salary by the total number of hours worked per year.

  There are 52 weeks in a year;

   Number of hours worked per year  = 52 x 40  = 2080hrs

Hourly wage per year = \(\frac{65788}{2080}\)   = $31.63/hr

The coordinates of the center is (32, 40.5).

length of the radius of the circle is 73 units.

The coordinates of the center is solved using the formula for midpoints expressed as

Midpoint x-coordinate = (x₁ + x₂) / 2

Midpoint y-coordinate = (y₁ + y₂) / 2

Plugging in the values:

x₁ = 8 and y₁ = 13

x₂ = 56 and y₂ =68

Midpoint x-coordinate

= (8 + 56) /2

= 64/2

= 32

Midpoint y-coordinate

= (13 + 68) /2

= 81/ 2

= 40.5

distance formula will be used to find the length of the radius of the circle

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

Plugging in the values:

= √[(56 - 8)² + (68 - 13)²]

= √(48² + 55²)

= √(2304 + 3025)

= √5329

= 73

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Answer:

Corresponding

Co-interior

None

Alternate exterior

Alternate interior

Corresponding

Answer:

-10 i think

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

3 to the third power + 42

as a percentage.  

Answer:

It is B

Step-by-step explanation:

If The item she wants to buy is priced at $21, before discount and tax. After the discount, and before tax, the price is $20.79 then the discount is 21%

percentage, a relative value indicating hundredth parts of any quantity.

Given,

Sydney has a loyalty card good for a discount at her local hardware store.

The item she wants to buy is priced at $21, before discount and tax.

After the discount, and before tax, the price is $20.79.

21-20.79=0.21

Now multiply 0.21 with 100

0.21×100

21

Hence 21 is the percent of discount.

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Gary will be able to deduct $1,450 in medical expenses on his 2021 tax return.

Based on the information you provided, we can calculate Gary's deductible medical expenses using the following terms:

1. Qualified medical expenses: $5,200
2. AGI (Adjusted Gross Income): $50,000

According to the IRS, taxpayers can deduct qualified medical expenses that exceed 7.5% of their AGI for the tax year 2021. Here's the step-by-step calculation for Gary's deductible medical expenses:

Step 1: Calculate 7.5% of Gary's AGI
7.5% x $50,000 = $3,750

Step 2: Subtract the 7.5% AGI threshold from Gary's qualified medical expenses
$5,200 - $3,750 = $1,450

Gary will be able to deduct $1,450 in medical expenses on his 2021 tax return.

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Answer:

the area is C. 39

Step-by-step explanation: If you split them into there own shapes and add them at the end.

2 x 6 = 12

3 x 5 = 15

3 x 4 = 12

12 + 12 = 24

24 + 15 = 39

hope this makes sense

Answer:

The answer is D.

Step-by-step explanation:

To write an equation in slope-intercept form for the line drawn on the scatter plot showing how many comic books Sheldon has left at the end of each day, you will need to calculate the slope (m) and y-intercept (b) based on the data provided.

First, determine two points (x1, y1) and (x2, y2) from the scatter plot. Then, use the slope formula:

m = (y2 - y1) / (x2 - x1)

Next, use the point-slope form equation to find the y-intercept (b):

y1 = m * x1 + b

Finally, plug in the slope and y-intercept values into the slope-intercept form equation:

y = mx + b

Keep in mind that I cannot provide specific numbers without the actual scatter plot data. However, this process will guide you through finding the equation for the line in slope-intercept form.

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Answer:

Step-by-step explanation:

Answer : Original price 382

55% of 382 = $210

Answer:

-4 and 9/10

Step-by-step explanation:

Since everything in parentheses is simplified, you just subtract like terms.

(-1/2)-(1/5)

(5/10)-(2/10)

(-7/10)

9^2 - 9^2 = 0

(-4/5)+(1/10)        (It's a plus sign because the (1/10) was negative and since you are subtracting (two negatives make a positive) it turns positive.

(-8/10) + (1/10)

(-7/10)

(-7/10)^2

(-49/10)

-4 9/10

(a) The Null And Alternate hypothesis are stated below,

(b) The value of test-statistic is 3,

(c) The "p-value" is 0.0013,

(d) The hypothesis is rejected because p-value is less than 0.025.

Part (a) : The appropriate null and alternative hypotheses are:

Null hypothesis (H₀): The average LSAT score at the University of Pennsylvania is equal to or less than the national average of 1,300.

Alternative hypothesis (Hₐ): The average LSAT score at the University of Pennsylvania is significantly higher than the national average of 1,300.

Part (b) : To calculate the test-statistic, we use formula : t = (x' - μ)/(s / √n),

where x' = sample mean, μ = hypothesized population mean, s = sample standard deviation, and n = sample size.

Substituting the given values,

We get,

t = (1375 - 1300)/(125 / √25) = 3;

So, the value of the test statistic is 3.

Part (c) : To calculate "p-value", we need to find the probability of getting a t-value as extreme or more extreme than 3, assuming that the null hypothesis is true.

We know that for a two-tailed test at a significance level of 0.03, the p-value is approximately 0.0013.

Part (d) : To test the hypotheses using the p-value, we compare it to the significance-level.

Since the p-value is less than 0.025 (half of the significance level for a two-tailed test), we reject the null hypothesis and conclude that there is sufficient evidence to support the claim.

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The given question is incomplete, the complete question is

The admissions officer for the graduate programs at the university of Pennsylvania believes that the average score on the LSAT exam at his university is significantly higher than the national average of 1,300. an accepted standard deviation for LSAT scores is 125. random sample of 25 scores had an average of 1,375.

(a) State the appropriate null and alternative hypotheses.

(b) Calculate the value of the test statistic

(c) Calculate the p-value.

(d) Use the p-value to test the hypotheses and conduct the test at the 0.025 level.

In a net of a solid, the number of faces meeting at each vertex can be determined by examining the net and counting the number of lines that meet at each vertex. Each line corresponds to an edge of a face, so the number of lines meeting at a vertex is equal to the number of faces meeting at that vertex.

For example, if we consider a cube net, we can see that three faces meet at each vertex. Therefore, a cube has three faces meeting at each vertex.

Similarly, for other solids, we can count the number of faces meeting at each vertex by examining the net. For example, for a regular tetrahedron, four faces meet at each vertex; for a regular octahedron, four faces meet at each vertex; for a regular dodecahedron, three faces meet at each vertex; and for a regular icosahedron, five faces meet at each vertex.

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(i) If f is an even function, then f(y) = 2 ∫[0,∞] f(x) cos(2πxy) dx.

(ii) If f is an odd function, then f(y) = -2i ∫[0,∞] f(x) sin(2πxy) dx.

The Fourier transform pair for a function f(x) is defined as follows:

F(k) = ∫[-∞,∞] f(x) \(e^{-2\pi iyx}\) dx

f(x) = (1/2π) ∫[-∞,∞] F(k) \(e^{2\pi iyx}\) dk

Now let's prove the given properties:

(i) If f is an even function, then f(y) = 2∫[0,∞] f(x) cos(2πxy) dx.

To prove this, we start with the Fourier transform pair and substitute y for k in the Fourier transform of f(x):

F(y) = ∫[-∞,∞] f(x) \(e^{-2\pi iyx}\) dx

Since f(x) is even, we can rewrite the integral as follows:

F(y) = ∫[0,∞] f(x) \(e^{-2\pi iyx}\) dx + ∫[-∞,0] f(x) \(e^{2\pi iyx}\) dx

Since f(x) is even, f(x) = f(-x), and by substituting -x for x in the second integral, we get:

F(y) = ∫[0,∞] f(x) \(e^{-2\pi iyx}\) dx + ∫[0,∞] f(-x) \(e^{2\pi iyx}\)dx

Using the property that cos(x) = (\(e^{ ix}\) + \(e^{- ix}\))/2, we can rewrite the above expression as:

F(y) = ∫[0,∞] f(x) (\(e^{-2\pi iyx}\) + \(e^{2\pi iyx}\))/2 dx

Now, using the definition of the inverse Fourier transform, we can write f(y) as follows:

f(y) = (1/2π) ∫[-∞,∞] F(y) \(e^{2\pi iyx}\) dy

Substituting F(y) with the expression derived above:

f(y) = (1/2π) ∫[-∞,∞] ∫[0,∞] f(x) \(e^{-2\pi iyx}\) + \(e^{2\pi iyx}\)/2 dx dy

Interchanging the order of integration and evaluating the integral with respect to y, we get:

f(y) = (1/2π) ∫[0,∞] f(x) ∫[-∞,∞] (\(e^{-2\pi iyx}\) + \(e^{2\pi iyx}\))/2 dy dx

Since ∫[-∞,∞] (\(e^{-2\pi iyx}\) + \(e^{2\pi iyx}\))/2 dy = 2πδ(x), where δ(x) is the Dirac delta function, we have:

f(y) = (1/2) ∫[0,∞] f(x) 2πδ(x) dx

f(y) = 2 ∫[0,∞] f(x) δ(x) dx

f(y) = 2f(0) (since the Dirac delta function evaluates to 1 at x=0)

Therefore, f(y) = 2 ∫[0,∞] f(x) cos(2πxy) dx, which proves property (i).

(ii) If f is an odd function, then f(y) = -2i ∫[0,∞] f(x) sin(2πxy) dx.

The proof for this property follows a similar approach as the one for even functions.

Starting with the Fourier transform pair and substituting y for k in the Fourier transform of f(x):

F(y) = ∫[-∞,∞] f(x) \(e^{-2\pi iyx}\) dx

Since f(x) is odd, we can rewrite the integral as follows:

F(y) = ∫[0,∞] f(x) \(e^{-2\pi iyx}\) dx - ∫[-∞,0] f(x) \(e^{-2\pi iyx}\) dx

Using the property that sin(x) = (\(e^{ ix}\) - \(e^{-ix}\))/2i, we can rewrite the above expression as:

F(y) = ∫[0,∞] f(x) \(e^{-2\pi iyx}\) - \(e^{2\pi iyx}\)/2i dx

Now, following the same steps as in the proof for even functions, we can show that

f(y) = -2i ∫[0,∞] f(x) sin(2πxy) dx

This completes the proof of property (ii).

In summary:

(i) If f is an even function, then f(y) = 2 ∫[0,∞] f(x) cos(2πxy) dx.

(ii) If f is an odd function, then f(y) = -2i ∫[0,∞] f(x) sin(2πxy) dx.

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Answer:

A 4-liter container holds more than a 3500-milliliter container

Step-by-step explanation:

4 liters = 4000 milliliters

4000 > 3500

The answer of the given question based on the circle is ,  the answer is option (d) 8/3π.

In geometry, an arc is  portion of circumference of a circle. It is  curved line that connects two points on  circle. The length of arc is proportional to the angle that it subtends at the center of the circle.

Since EFB is a straight line and EB is a diameter of the circle, angle EFB subtends the entire circle at F. Therefore, the angle subtended by arc EFD is the difference between the angles subtended by arcs EF and EB.

Arc EF subtends a full circle at F, so its angle is 2π radians. Arc EB subtends a straight angle at F, so its angle is π radians.

Therefore, the angle subtended by arc EFD is:

2π - π = π

The length of arc is given by formula L = rθ, where r is  radius of  circle and θ is  angle (in radians) subtended by  arc at  center of  circle.

In this case, r = 4 and θ = π, so the length of the arc corresponding to angle EFD is:

L = rθ = 4π

Therefore, the answer is (d) 8/3π.

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Answer:

(x+3) is a factor of your question

Step-by-step explanation:

x²-6x-27

x²+3x-9x-27

x(x+3)-9(x+3)

(x+3)(x-9)

Answer:

Hope it can help you and please mark me as a brainlist .....

Answer:

i think its d

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

y = 8x + 15

When x=0, y = 15

When y=0, x = -1.875

True. Since the square matrix that represents the DCT coefficient is an orthogonal matrix, its inverse and transpose are the same. This property is a fundamental characteristic of orthogonal matrices and holds true for all orthogonal matrices.

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False While it is true that the square matrix that represents the DCT coefficient is orthogonal, it does not mean that its inverse and transpose are the same.

the inverse of an orthogonal matrix is its transpose. However, the transpose of the matrix does not necessarily mean that it is the same as the inverse of the matrix. In the statement is false because the inverse and transpose of an orthogonal matrix are not always the same.


The Discrete Cosine Transform (DCT) coefficient matrix is an orthogonal matrix. In the case of orthogonal matrices, the inverse matrix is indeed equal to the transpose of the original matrix. This is because the product of an orthogonal matrix and its transpose results in the identity matrix.

Since the square matrix representing the DCT coefficient is an orthogonal matrix, its inverse and transpose are the same.

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Answer:

9

Step-by-step explanation:

Answer:

jawbhvgh

Step-by-step explanation:

QJAWNDBSVX