Triangle Congruence by ASA,AAS, and HL Practice Are these triangle congruent? If so, state the rule which you used to determine Congruence.

Step-by-step explanation:

1st blank => ratios

2nd blank => 100 (one hundred)

Answer:

Step-by-step explanation:

You want the slope, y-intercept, and equation for a line that passes through the points (2, -2) and (8, 1).

The slope formula is used to find the slope:

  m = (y2 -y1)/(x2 -x1)

  m = (1 -(-2))/(8 -2) = 3/6 = 1/2

The slope-intercept equation can be rearranged to give the y-intercept:

  b = y - mx

  b = 1 -(1/2)(8) = 1 -4 = -3 . . . . . . using (x, y) = (8, 1)

The slope-intercept form equation is ...

  y = mx +b . . . . . . where m is the slope, and b is the y-intercept

Using the found values, the equation is ...

  y = 1/2x -3

Answer:

C. 15 centimeters

Step-by-step explanation:

The Triangle Midsegment Theorem

segment LM = 1/2 of AC

LM = 1/2 * 30

LM = 15 cm

Answer:

original cost is 135$

Step-by-step explanation:

100%×54$÷40%= 135

Answer: Bird A's top speed is 1428 MPH.

Step-by-step explanation: 238x6 = 1428

Answer:

YZ=27

Step-by-step explanation:

Since ZX is perpendicular bisector of WY, so

WZ=YZ,

4n-13=n+17,

3n=30,

n=10,

YZ=n+17=27

Hello, I was happy to solve the problem. If you find a bug, post in the comments or click on the report, I will see it and try to fix it as soon as possible.

The answer to this problem: 2

Answer:

The hourly pay for the lifeguards in 2001 was of $6.31.

Step-by-step explanation:

The hourly pay, in dollars, in t years after 1995, is given by the following equation:

\(P(t) = 5.60(1.02)^{t}\)

What was the hourly pay for the lifeguards in 2,001?

2001 is 2001 - 1995 = 6 years after 1995. So this is P(6).

\(P(t) = 5.60(1.02)^{t}\)

\(P(6) = 5.60(1.02)^{6} = 6.31\)

The hourly pay for the lifeguards in 2001 was of $6.31.

Answer:

(29.99 + 18.65 + 32.59) 0.85 = 0

(29.99 + 18.65 + 32.59) - 0.15(29.99 + 18.65 + 32.59) = 0

Step-by-step explanation:

The 15% off represents percentage discount. The relationship between percentage discount and total cost is given by the equation;

Actual cost - (Percentage discount) Actual cost = Total cost

The correct options are;

(29.99 + 18.65 + 32.59) 0.85 = 0

(29.99 + 18.65 + 32.59) - 0.15(29.99 + 18.65 + 32.59) = 0

Answer:

(29.99 + 18.65 + 32.59) 0.85 = 0 is correct

Step-by-step explanation:

Answer:

A) 150%

B) 20.67 J

Step-by-step explanation:

A) To determine the efficiency of the engine, we can use the formula:

efficiency = (work output / heat input) x 100%

In this case, the engine does 62 J of work each cycle, so the work output is 62 J. We're also given that the engine absorbs 2 times as much heat as it discharges to the environment, so we can express the heat input as 2 times the heat discharged:

heat input = 2 x heat discharged

Therefore, we can rewrite the efficiency formula as:

efficiency = (62 J / (2 x heat discharged)) x 100%

Simplifying this expression, we get:

efficiency = 31 J / heat discharged

Now we need to determine the value of heat discharged. We know that the engine absorbs 2 times as much heat as it discharges, so the net heat input is 3 times the heat discharged:

net heat input = heat input - heat discharged = 2 x heat discharged - heat discharged = heat discharged

Therefore, we can express the net heat input as:

net heat input = 3 x heat discharged

Now we can use the first law of thermodynamics, which states that the net heat input is equal to the work output plus the heat discharged:

net heat input = work output + heat discharged

Substituting the given values, we get:

3 x heat discharged = 62 J + heat discharged

Solving for heat discharged, we get:

heat discharged = 20.67 J

Now we can calculate the efficiency:

efficiency = 31 J / 20.67 J = 1.50 or 150%

Therefore, the efficiency of the engine is 150%.

B) To determine the quantity of heat discharged to the environment each cycle in Joules, we can use the value we calculated above for heat discharged:

heat discharged = 20.67 J

Therefore, the quantity of heat discharged to the environment each cycle is 20.67 J.

Hope this helps!

n⁴ - 2n³ - 23n² + 24n + 144 is the standard form of given zeroes.

What is a linear equation in mathematics?

A linear equation is an algebraic equation of the form y=mx+b. m is the slope and b is the y-intercept. The above is sometimes called a "linear equation in two variables" where y and x are variables.

                              A linear equation is an equation that raises a variable to the first power. ax+b = 0 is an example of a 1 variable. x is a variable and a and b are real numbers.  

Roots : -3(mult . 2), 4(mult.2)

the function is given as

     f(n) = (n + 3)² (n - 4)²

         = (n + 3) (n + 3 ) ( n - 4 ) ( n - 4)

        = (n² + 6n + 9) (n² - 8n + 16 )

        = n⁴ - 8n³ + 16n² + 6n³ - 48n² + 96n + 9n² - 72n + 1

collecting like term,

    f(n) = n⁴ - 2n³ - 23n² + 24n + 144

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Answer:

Jemma: 22x + 5

Debra: 20x

Step-by-step explanation:

The rate at which the volume of the cylinder is changing is 600 mm^3/min, and the rate at which the surface area is changing is 240π mm^2/min.

To find the rate at which the volume and surface area of the cylinder are changing, we can use the given formulas for volume and surface area and differentiate them with respect to time. Let's calculate the rates at the moment when the radius of the base is 10 mm.

Given:

Radius rate of change: dr/dt = 3 mm/min

Height: h = 20 mm

Radius: r = 10 mm

Volume of the cylinder (V) = \(r^2h\)

Differentiating with respect to time (t), we have:

dV/dt = 2rh(dr/dt) + \(r^2\)(dh/dt)

Since the height of the cylinder is constant, dh/dt = 0.

Substituting the given values:

dV/dt = 2(10)(20)(3) + (10^2)(0)

dV/dt = 600 + 0

dV/dt = 600 mm^3/min

Therefore, the rate at which the volume of the cylinder is changing at the given moment is 600 mm^3/min.

Surface area of the cylinder (SA) = 2πrh + 2π\(r^2\)

Differentiating with respect to time (t), we have:

dSA/dt = 2πr(dh/dt) + 2πh(dr/dt) + 4πr(dr/dt)

Again, since the height of the cylinder is constant, dh/dt = 0.

Substituting the given values:

dSA/dt = 2π(10)(0) + 2π(20)(3) + 4π(10)(3)

dSA/dt = 0 + 120π + 120π

dSA/dt = 240π mm^2/min

Therefore, the rate at which the surface area of the cylinder is changing at the given moment is 240π mm^2/min.

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Answer: Each ticket cost 13 pounds

Step-by-step explanation: If the total cost is 104 pounds and there are 8 friends who each bought one ticket, then you have to divide the total cost (104 pounds) by the total number of tickets (8) 104/8 = 13

For the given expression, the addition of coefficients is \(5x^2 + 2x - 7\).

In algebra, a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression. In other words, it is the number that is being multiplied by the variable.

Addition is a basic mathematical operation that combines two or more numbers or quantities to produce a sum. It is denoted by the plus sign (+). When two or more numbers are added, the result is called the sum or total.

First, we need to combine like terms by adding the coefficients of terms with the same variable(s) raised to the same power.

\((6x^2 + 10x - 7) + (-x^2 - 8x)\)

\(= 6x^2 + (-x^2) + 10x + (-8x) - 7\) (grouping like terms together)

\(= (6x^2 - x^2) + (10x - 8x) - 7\) (rearranging terms)

\(= 5x^2 + 2x - 7\) (combining the coefficients)

Therefore, the final answer for the addition of coefficients is \(5x^2 + 2x - 7.\)

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The total amount the man had = 52,200 rupees. Out of this, he gave 21,750 rupees to his son, 13,050 rupees to his daughter, and 17,400 rupees to his wife , the total amount given away by the man = 21,750 + 13,050 + 17,400 = 52,200 rupees.

A man gave 5/12 of his money to his son, 3/7 of the remainder to his daughter, and the remaining to his wife. If his wife gets Rs. 8,700, what is the total amount?

The given problem can be solved using the concept of ratios and fractions. Let us solve the problem step-by-step.Assume the man had x rupees with him.The man gave 5/12 of his money to his son.

The remaining amount left with the man = x - 5x/12= (12x/12) - (5x/12) = (7x/12)The man gave 3/7 of the remainder to his daughter.'

Amount left with the man after giving it to his son = (7x/12)The amount given to the daughter = (3/7) x (7x/12)= (3x/4)The remaining amount left with the man = (7x/12) - (3x/4)= (7x/12) - (9x/12) = - (2x/12) = - (x/6) (As the man has given more money than what he had with him).

Therefore, the daughter's amount is (3x/4) and the remaining amount left with the man is (x/6).The man gave all the remaining amount to his wife.

Therefore, the amount given to the wife is (x/6) = 8700Let us find the value of x.x/6 = 8700 x = 6 x 8700 = 52,200

Therefore, the man had 52,200 rupees with him.He gave 5/12 of his money to his son. Therefore, the amount given to his son is (5/12) x 52,200 = 21,750 rupees.

The remaining amount left with the man = (7/12) x 52,200 = 30,450 rupees.He gave 3/7 of the remainder to his daughter. Therefore, the amount given to his daughter is (3/7) x 30,450 = 13,050 rupees.

The amount left with the man = (4/7) x 30,450 = 17,400 rupees.The man gave 17,400 rupees to his wife.
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Answer:

I think its C

Step-by-step explanation:

The length of 4 feet to metres is 1.22 metres.

The units is in feet. Therefore, let's convert it to metres. The length is given as 4 feet.

Hence,

1 feet = 0.3048 metres

4 feet = ?

cross multiply

length in metres = 4 × 0.3048

length in metres = 1.2192

Therefore, the length to the nearest hundredth is 1.22 metres.

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The stock closest to its Purchase price is ABC Toys, with a change of $3.

To determine which stock is closest to its purchase price, we need to compare the changes in stock value to their initial purchase prices. However, we do not have information about the initial purchase prices of each stock.

One way to approach this problem is to calculate the absolute value of the change in stock value for each stock and then compare those values. The stock with the smallest absolute value of change will be closest to its purchase price.

Using this method, we get:

ABC Toys: |–$3| = $3

Golden Grains: |+$4| = $4

Fast Cars: |–$8| = $8

XYZ Clothing: |+$1| = $1

Therefore, the stock closest to its purchase price is ABC Toys, with a change of $3.

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Answer: 3/13

Step-by-step explanation:

answer: f(x)= 3x^2-9x+3

Answer:

3.5

Step-by-step explanation:

3/5 in a decimal is 3.5

Answer:112

Step-by-step explanation:

I did it and we doing the same test rn haha. What did you get for the grant one?

According to the information, the maximum infection rate is:  k * 2500 * (5000 - 2500) = 6250k = 40

To address this problem, we can use the law of the infection rate, which states that the infection rate is directly proportional to the product of the number of people infected and the number of people not infected. Therefore, we can write:

where "k" is a constant of proportionality. Since we want to find the number of people infected that produces the maximum infection rate, we can consider the infection rate as a function of the variable "x" representing the number of people infected. Therefore, we can write:

To find the value of "x" that maximizes the infection rate, we can derive this function and set the derivative equal to zero:

This implies that 5000 - 2x = 0, and therefore:

Therefore, the number of infected people that produces the maximum daily rate of infection is 2,500.

However, we must verify that this result is consistent with the information given in the problem. We know that when there are 1,000 people infected, the flu spreads at the rate of 40 new cases per day. Therefore, if we add 1,500 more infected people (for a total of 2,500), the infection rate would be:

If the infection rate is 40 new cases per day, we have:

which implies that:

Therefore, the maximum infection rate is:

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For a curve to be a density curve, it must meet certain conditions such as it should be non-negative, and the area under the curve should equal 1. Furthermore, the curve should be continuous and smooth, and there should be no values outside the range of the data.

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Maximum: 1, Minimum: -3, Midline y = -1, Amplitude = 4, Period = π, Frequency = 1/π,  equation -4cos(2x) + 1:

Sinusoidal Functions

It refers to the oscillating functions like the sine or cosine which range from a minimum and maximum value periodically.

The graph shown can give us all the information we need to answer these questions:

Maximum: 1

Minimum: -3

The midline goes through the center value (mean) of the max and min values, i.e.

Equation of the midline:

y = (1-3)/2

y = -1

Amplitude is the difference between the maximum and minimum values

A =4

The period is the time it takes to complete a cycle. We can see the minimum value is first reached at x=0 and next at  x = π

Thus the period is

T = π

The frequency is the reciprocal of the period:

f = 1/T = 1/π

The angular frequency is

ω = 2πf

ω = 2

The equation of the function is a negative cosine (since it starts at the minimum) or a shifted sine or cosine. We'll choose the negative cosine, knowing all the parameters:

f(x) = -4cos(2x) + 1

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