Translate the phrase into a variable expression. Use the letter k to name the variable. If necessary, use the asterisk (*) for multiplication and the slash (/) for division. wak the number of keys on the keyring minus 2... Answer here​

The required original price of the coat is given as £95.

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

here,
let the original price of the coat be x,
According to the question
x - 17% of x = 78.85
x - 0.17x = 78.85
0.83x = 78.85
x = 78.85 / 0.83
x = £95

Hence, the cost of the coat before the sale is £95.

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To determine whether the assumption of constant error variance is satisfied for a model with tut, independent variables x, and x₂, you would examine the residual plot where the residuals are plotted against predicted values y.

This plot is also known as the plot of residuals versus fitted values. In this plot, if the residuals are randomly scattered around the horizontal line of zero, then the assumption of constant error variance is satisfied. However, if there is a pattern in the residuals, such as a funnel shape or a curve, then the assumption of constant error variance may not be met. It is important to ensure that the assumption of constant error variance is met, as violation of this assumption can lead to biased and inefficient estimates of the model parameters. Additionally, it can affect the reliability of statistical inferences and lead to incorrect conclusions.
In summary, to determine whether the assumption of constant error variance is satisfied for a model with tut, independent variables x, and x₂, you would examine the residual plot where the residuals are plotted against predicted values y. It is important to check this assumption to ensure the validity of the model and the accuracy of the results.This plot allows you to assess the variance of the residuals and identify any patterns, which could indicate that the assumption of constant error variance may not be met. If the plot shows no discernible pattern and the spread of residuals appears to be uniform across the range of predicted values, the assumption of constant error variance is likely satisfied.

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Using logarithms we obtain: log10(35) ≈ 1.5441, log10(520.6990) ≈ 0.6990 and log10(3) ≈ 0.4771

To approximate the value of each expression using logarithms, we can follow these steps:

1. Use the provided logarithmic approximations:

- log10 3 ≈ 0.4771
- log10 5 ≈ 0.6990
- log10 7 ≈ 0.8451
- log10 11 ≈ 1.0414

2. Let's start with the expression log10(35):

- We can rewrite 35 as 7 * 5.  

- Applying the logarithmic property log(ab) = log(a) + log(b), we have:    

 log10(35) = log10(7 * 5) = log10(7) + log10(5)  

- Using the provided logarithmic approximations, we get:    

  log10(35) ≈ 0.8451 + 0.6990  

- Calculating this, we obtain:    

  log10(35) ≈ 1.5441

3. Moving on to the expression log10(520.6990):

- We can see that 520.6990 is already a single number, so we can directly apply the logarithm:
 log10(520.6990)
- Using the provided logarithmic approximation for log10 520.6990, we have:
 log10(520.6990) ≈ 0.6990
- Therefore, log10(520.6990) ≈ 0.6990.

4. Finally, let's approximate log10(3):
- Using the provided logarithmic approximation for log10 3, we get:
  log10(3) ≈ 0.4771

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Answer:

25/3

Step-by-step explanation:

not confident if you know please make me correct

Answer:

\(25/3.\)

Step-by-step explanation:

\(if \: x = 5\\ if \: y = 3 \\ then \to \\ {9x}^{2} y {}^{ - 3} = \frac{ {9x}^{2} }{y{}^{3} } = \frac{9 \times {5}^{2} }{ {3}^{3} } \to \\ \\ {9x}^{2} y {}^{ - 3} = {5}^{2}3{}^{ - 1} \\ {9x}^{2} y {}^{ - 3} = \boxed{25/3} \to \: if \: x \: = 5 \: and \: y = 3.\)

♨Rage♨

At 8000 feet MSL in the teardrop could a descent to 3,200 feet commence.

What is aircraft?

A vehicle that can fly is known as an aircraft. It does so by getting help from the air. It does this by either employing static lift, the dynamic lift of an airfoil or, in a few rare instances, the downward push from jet engines. Aerial vehicles include, but are not limited to, planes, helicopters, airships (including blimps), gliders, paramotors, and hot air balloons.

As given, your aircraft was cleared for the ils rwy 18 at Lincoln municipal and crossed the Lincoln Vortac at 5,000 feet MSL.

Therefore, at 8000 feet MSL in the teardrop could a descent to 3,200 feet commence.

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For a card game with a pack of total 52 cards, where success is that drawn card is face card. The excepted value for this game is - 0.615.

In probability theory, Expected Value is the estimated gain or loss in partaking in an event many times. It is calculated by the formula written as \(E(X) = \sum P(X) × X \)

where, X is the number of trials and

In other words, sum of multiplication of probability of gain to gain amount and multiplication of probability of loss to loosing amount. We have a experiment card game. There is a total 52 card deck. Let's consider an event X that one card is drawn from 52.

Number of face cards in pack of 52 = 3× 4 = 12

Number of non- face cards in pack of 52 = 52 - 12 = 40

Probability that drawn card is face card or probability of success = 12/52 = \( \frac{ 3}{13}\)

Probability that drawn card is not face card or probability of loss = \( \frac{40}{52} = \frac{10}{13} \)

winning amount on probability of success= $4

So, excepted value = \(4 \times \frac{3}{13} - 2 \times \frac{10}{13} \)

= \( - \frac{8}{13} \) = - 0.615

Hence, required value is - 0.615.

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Answer:

x+2

hope this helps ;)

and cute pfp

Answer:

Step-by-step explanation:

x-1, because 3 fits the criteria, x>=1

To Find :-

Solution :-

Here according to the question ,

\(\longrightarrow Cost \ of \ each \ crackers \ = \ c \)

And , she purchases ,

\(\longrightarrow \textit{ boxes of cheese crackers = 6 } \\\\\longrightarrow\textit{ boxes of poppy's seed crackers = 5 }\\\\\longrightarrow \textit{ boxes of plain crackers = 5 } \)

And she represents cost by ,

\(\longrightarrow Cost = 6c + 5c + 5c \)

To find equivalent , take out c as common ,

\(\longrightarrow Cost = c (6+5+5)\)

Add the constant terms inside the brackets ,

\(\longrightarrow Cost = c \times 16 \)

Multiply ,

\(\longrightarrow \underline{\underline{Cost = 16c }}\)

Hence the equivalent expression is 16c .

Answer:

1 1/5

hope this helps! :D

Answer:

minimum of -3

Step-by-step explanation:

Because that is the lowest point on the graph

The problem with solving 1110 - 1110 using 2's complement in 7-bit data representation is that it results in an overflow, and to overcome this, either increase the number of bits or use a larger data type for representation.

We are subtracting 1110 from 1110 using 2's complement and using 7-bit data representation. Let's go through the steps:

Step 1: Convert 1110 to its 2's complement representation in 7 bits:

  - In 7 bits, the leftmost bit is the sign bit.

  - Since the leftmost bit of 1110 is 1 (indicating a negative number), we can simply represent it as it is: 1110.

Step 2: Perform the subtraction using 2's complement:

  1  1  1  0

- 1  1  1  0

------------

  0 0 0 0

The result of the subtraction is 0000. However, this result is problematic because it is not within the range that can be represented with 7 bits using 2's complement.

To overcome this problem and prevent overflow, we can take the following steps:

1. Increase the number of bits: Increase the number of bits used for representing the numbers. Using more bits allows for a larger range of representable numbers and reduces the chance of overflow. If possible, use more bits for data representation.

2. Use a larger data type: If using a fixed number of bits is a requirement, consider using a larger data type, such as a larger integer type, that can accommodate the expected range of values without overflow.

3. Check for overflow conditions: Before performing arithmetic operations, check for potential overflow conditions. For example, when subtracting two negative numbers or adding two positive numbers, the result should have a different sign. If the signs of the operands are the same and the result has the opposite sign, it indicates overflow.

4. Handle overflow cases: If overflow occurs, take appropriate actions based on the specific requirements of your application. This could involve truncating or discarding the most significant bits of the result or applying additional logic to handle the overflow condition appropriately.

By considering these suggestions and adjusting the number of bits or data type used for data representation, you can overcome the problem of overflow when performing arithmetic operations using 2's complement.

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Step-by-step explanation:

Since the interior angles of a triangle always add up to 180°, we can use an equation to find out how many degrees the remaining angle is. We can use the letter x to represent that angle.

We also have to keep in mind that a right angle is 90°.

90+45+x=180

Now, we can start solving. First, we should combine like terms.

135+x=180

Next, we can subtract 135 from both sides to get the value of x.

135+x=180

-135    -135

x=45

So, the other angle is 45°.

Answer:

45°

Therefore, the probability that a randomly selected point within the square falls in the red-shaded area is 68%.

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, where 0 represents an impossible event and 1 represents a certain event. The probability of an event A is denoted as P(A). To calculate the probability of an event, we divide the number of favorable outcomes by the total number of possible outcomes.

Here,

The area of the red-shaded region is the area of the square minus the area of the white right-angled triangle. The area of the square is the length of one side squared, which is:

Area of square = 5 cm × 5 cm

= 25 cm²

The area of the right-angled triangle is one-half the base times the perpendicular height, which is:

Area of triangle = (1/2) × base × height

= (1/2) × 4 cm × 4 cm

= 8 cm²

Therefore, the area of the red-shaded region is:

Area of red-shaded region = Area of square - Area of triangle

= 25 cm² - 8 cm²

= 17 cm²

To find the probability that a randomly selected point within the square falls in the red-shaded area, we need to divide the area of the red-shaded region by the total area of the square, which is:

Probability = Area of red-shaded region / Area of square

Probability = 17 cm² / 25 cm²

= 0.68 or 68%

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This is the desired expression for the total solution.

To solve the differential equation, we assume that the solution is of the form y(t) = c(t)eat. Then, we have:

y'(t) = c'(t)eat + aceat

y(0) = c(0)e0a = y

Substituting these into the differential equation, we get:

c'(t)eat + aceat = a(c(t)eat) + bu(t)

Simplifying this equation, we get:

c'(t) = bu(t)e-at

Integrating both sides from 0 to t, we get:

c(t) - c(0) = ∫0t bu(r)e-ar dr

Multiplying both sides by eat, we get:

y(t) - y = e-at(c(0) + ∫0t bu(r)e-ar dr)

Rewriting the right-hand side in terms of a constant c and a function h(t), we get:

y(t) = e-at y + c ∫0t bu(r)e-ar dr

where c = eay and h(t) = bu(t)e-at. This is the desired expression for the total solution.

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The probability of three rooks being placed on a 3x3 chessboard without any of them being able to capture another is about 3.57%.

There are a total of 9 squares on a 3x3 chessboard, and we need to place 3 rooks on these squares. There are 9 choices for the first rook, 8 choices for the second rook, and 7 choices for the third rook.

However, not all of these choices will result in a valid configuration where none of the rooks can capture each other. To be valid, each row and each column must have at most one rook.

Let's consider the number of valid configurations. Without loss of generality, we can assume that the first rook is placed in the first row. There are 3 choices for the column of the first rook. The second rook can be placed in any of the 6 remaining squares, but only 3 of these squares are in rows or columns that do not already have a rook. Finally, the third rook can be placed in any of the 3 remaining squares, but only 2 of these squares are in rows or columns that do not already have a rook.

Therefore, the total number of valid configurations is 3 x 3 x 2 = 18.

The total number of ways to place the rooks is 9 x 8 x 7 = 504.

Therefore, the probability that none of the rooks can capture any of the other two is 18/504 = 1/28, or approximately 0.0357.

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We have two similar tetrahedrons, where the shaded has dimensions that are half the dimensions of the large tetrahedron.

A. For scaled figures, the volume is affected by the cube of the scale factor.

This means that if the dimensions are half the original dimensions, the volume will be 0.5³ = 0.125 times the original volume.

Then, if the volume of the large tetrahedron is 138 in³, then the volume of the shaded tetrahedron is:

B. In the case of the areas, the area of a scaled figure will be affected by the square of the scale factor.

We have to calculate the area for both tetrahedrons.

The shaded tetrahedron has edge lengths of 16 cm. Then, we can calculate his total surface as four times the area of a face, as we have four equal faces per tetrahedron.

We then start by calculating the area of an equlateral triangle with side 16 cm.

We can draw this figure to help with the calculations:

We now that the area of a triangle is half the product of the base and the height, so we calculate the height as:

Now we can calculate the area of the triangle as:

Then, the area of the shaded tetrahedron is:

We can now calculate the area of the large tetrahedron, which has edges of length 2*16 = 32 cm.

We can start calculating the height again:

We can now calculate the area of a face as:

and the total surface of the large tetrahedron as:

We can now compate the ratio between areas:

We can see that the areas are related by the square of the scale factor.

Answer:

A. The volume of the shaded tetrahedron is 17.5 in³.

B. The surface of the shaded tetrahedron is 256√3 cm².

The surface of the large tetrahedron is 1024√3 cm².

Answer:

8

Step-by-step explanation:

\(\bar{x}=np=10(0.8)=8\)

Answer:

value of c is negative

constant are in factor bla bla.

Step-by-step explanation:

Answer:

AC is a Side of Traingle .....................

The measure of the side length of AC will be 13 inches

Let the triangle be ABC. Then the perimeter of the triangle will be

Perimeter = AB + BC + CA

Triangle ABC has a perimeter of 40 inches.

The side's lengths are given as AB = 12 inches and BC = 15 inches.

Then the measure of the side length of AC will be

40 = 12 + 15 + AC

40 = 27 + AC

AC = 13 inches

The missing diagram is given below.

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The equation of the circle with center at (-1, 5) and passes through the point (2, 9) is equal to (x + 1)² + (y - 5)² = 25.

Mathematically, the standard form of the equation of a circle is given by;

(x - h)² + (y - k)² = r²

Where:

Next, we would determine the length of the radius (r) by using the distance formula. Mathematically, the distance between two (2) points that are on a coordinate plane can be calculated by using this formula:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Substituting the given parameters into the formula, we have;

Radius = √[(2 - (-1))² + (9 - 5)²]

Radius = √[(2 + 1)² + (4)²]

Radius = √[3² + 4²]

Radius = √[9 + 16]

Radius = √25

Radius = 5 units.

For the equation of a circle, we have:

(x - h)² + (y - k)² = r²

(x - (-1))² + (y - 5)² = 25

(x + 1)² + (y - 5)² = 25

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Complete Question:

Write the equation of the circle with center at (-1, 5) and passes through the point (2, 9).

Answer:

X=30

Step-by-step explanation:

...

Answer:

\(y = 6-x\)

take two coordinates:

(0, 6), (6, 0)

find slope:

\(\sf \frac{y_2 - y_1}{x_2 - x_1}\)

\(\frac{0-6}{6-0}\)

\(\sf \frac{-6}{6}\)

\(-1\)

find equation:

\(\sf y_1 - y = m(x_1 - x)\)

\(\sf y - 6 = -1 (x - 0)\)

\(\sf y = 6-x\)

Answer:

B. y=6-x

Step-by-step explanation:

The reason why I know it is B is that in the graph, it is going down on the line, and it passes through the x-axis. So, it would be a - and not +.

I hope this helps

Answer:

2

Step-by-step explanation:

You set up and equation:

5+6x = 17

You solve it and get 2.

Step-by-step explanation:

17-5 = 12

The most likely course of action an auditor would follow in planning a sample of cash disbursements if they are aware of several unusually large cash disbursements is to stratify the cash disbursements population.

By stratifying the population, the auditor can ensure that the unusually large disbursements are represented in the sample. This allows for a more accurate assessment of the control procedures and detection of potential irregularities or misstatements related to the large disbursements.

It provides a focused analysis of the high-risk transactions while maintaining the integrity of the sampling process. Setting the tolerable rate of deviation at a lower level or increasing the sample size may not specifically address the concern of the unusually large disbursements.

Continually drawing new samples until all the unusually large disbursements appear in the sample may not be efficient and may not provide a representative sample for analysis.

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Answer:

20/100*x=$30

20x/100=$30

x/5=$30

x=$30*5

x=$150

Step-by-step explanation:

20 percent of 150 equals 30 so 150 times 20 percent would give you 30

Answer:

-69. Nice!

Step-by-step explanation:

The slope of a line between two points is defined as the ration between the vertical distance and the horizontal distance - note that it doesn't matter if you go from the first to the second point, or the opposite, signs will end up fixed anyways. Let's get calculating!

\(\Delta y = -12 -57 = -69 \\ \Delta x = 99 - 98 = 1\)

Your slope is \(m = {\Delta y \over \Delta x}={-69 \over 1 } = -69\)

The one-sample chi-square test is used to determine whether the distribution of a single categorical variable significantly differs from what would be expected by chance. The statement is True.

The one-sample chi-square test is a statistical test used to determine if there is a significant difference between the observed frequency and the expected frequency in a single categorical variable. It compares the observed frequency distribution of a variable to the expected frequency distribution, assuming that the null hypothesis is true.

This test compares observed frequencies to expected frequencies and calculates a chi-square statistic to assess the significance of the difference.

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