Transcribed image text: Problem 4: The short-term, 0-24 hours, parking fee, F, at an international airport is given by the following formula: F = ( 5, 6 X int (h + 1), 160, if I sh<3 if 3 Write a program that prompts the user to enter the number of hours a car is parked at the airport and output the parking fee.

Answer:Ironworker

Explanation:

Their work is totally physical and lead they get hampered by lead most

Answer:

answer:ironworker

Explanation:

they can be hampered and can also get severely injured.

List of all key/message pairs, (k, m), such that Enc(k, m) = 101:Enc(k, m) = 101, k = 100
m = 001, k₁ = 1, k₂ = 0, k₃ = 0Enc(k, m) = 101, k = 011
m = 110, k₁ = 0, k₂ = 1, k₃ = 1
Enc(k, m) = 101, k = 111
m = 010, k₁ = 1, k₂ = 1, k₃ = 1(

What is Pr[Enc(k, 111) = 101]?Since k is chosen uniformly at random, and there are 8 possible keys, each key is chosen with probability 1/8. Now we'll find the number of keys k such that Enc(k, 111) = 101. For each of the three bits, there are two possible values. If we know the value of k at two positions, we can determine the value of k at the third position to get the desired ciphertext. As a result, there are 2² = 4 keys that have the desired property, namely, k = 011, 101, 110, or 000. Each of these keys is equally likely to be chosen, therefore, the probability is 4/8 or 1/2.Pr[Enc(k, 111) = 101] = 1/2

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Answer:

The key steps in attaching flexible cables to electrical appliances are:

1. Choose the correct type of cable: Consider the type of appliance, voltage, and current required before selecting the cable.

2. Strip the insulation: Remove the outer insulation, as well as any inner insulation, to expose the wires.

3. Determine wire length: Measure the exact length of the wire required for the attachment.

4. Strip the wire ends: Strip 1/2-inch of insulation from each wire-end.

5. Twist the wire ends: Twist the exposed wires together.

6. Attach the cable: Use screw terminals or clamps to connect the cable to the appliance.

7. Tighten the screws: Use a screwdriver to securely tighten the screws.

8. Check the connection: Verify that the wire is firmly secure by pulling it gently.

9. Cover the wires: Use heat-shrink tubing, electrical tape or wire caps to cover the exposed wires.

10. Test the appliance: Turn ON the appliance and check if it is working correctly.

The electronic components that could be used in making of energy saving switch are:​

Transistors as  well as other kinds of semiconductor devices are known to be tools or element that can be used in the making of switches. In its use or applications.

Note that the base or gate of a transistor, based  on the kind of transistor that is known to be in use, and it is one that is often employed as a form of control element to be able to switch on as well as switch off the current that often exist between the emitter as well as the collector or the source and that of the drain.

Note also that the electronic components that are able to  store energy in regards to electronic devices, are known to be capacitors and coils (inductors) and they often play a key function of temporarily saving  energy. One key role of a capacitor is to save an electric charge.

Therefore, The electronic components that could be used in making of energy saving switch are:​

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Answer: Ethanol

Explanation:

Answer:

Future Business Leaders of America

Explanation:

To find the zero-state response y(t) of an LTIC system with impulse response

h(t) = e^(-t)u(t)

and input x(t), we can use the convolution integral. The convolution integral is given by:
y(t) = ∫x(τ)h(t-τ)dτ

For each of the given inputs, we will calculate y(t) using this formula:

(a) x(t) = e^(-2t)u(t)
y(t) = ∫e^(-2τ)u(τ)e^(-(t-τ))u(t-τ)dτ
For this case, the convolution integral simplifies to:
y(t) = ∫e^(-τ)e^(-2(t-τ))dτ from 0 to t
Solve the integral and we get:
y(t) = (1/3)e^(-t)u(t)

(b) x(t) = e^(-2(t-3))u(t)
y(t) = ∫e^(-2(τ-3))u(τ)e^(-(t-τ))u(t-τ)dτ
For this case, the convolution integral simplifies to:
y(t) = ∫e^(-2τ)e^(-2t+6)dτ from 0 to t-3
Solve the integral and we get:
y(t) = (1/3)e^(-t)e^(6)e^(-2t+6)u(t-3)

(c) x(t) = e^(-2t)u(t-3)
y(t) = ∫e^(-2τ)u(τ-3)e^(-(t-τ))u(t-τ)dτ
For this case, the convolution integral simplifies to:
y(t) = ∫e^(-2τ)e^(-τ)e^τdτ from 3 to t
Solve the integral and we get:
y(t) = (1/3)e^(-t)u(t-3)

(d) For the gate pulse input and the sketch of y(t), we need the graphical information of the input signal to provide an accurate answer.

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Answer:

1. Enlist in dirt bike giveaways

2. Search craigslist

Explanation:

Answer:

1) The bending moment diagram of the shaft is shown in Figure 1. The weakest cross section A is located at the point where the bending moment is maximum.

2) The weakest point on cross section A is located at the point where the bending moment is maximum.

3) The von-Mises stress at the weakest point is given by:

σ = M/I

where M is the bending moment and I is the moment of inertia of the cross section.

4) The factor of safety n is given by:

n = Sy/σ

where Sy is the yield strength of the shaft and σ is the von-Mises stress at the weakest point.

Explanation:

Hope this helps!

Answer:

mark me as a brainleast

Explanation:

209781

The requested M-file, adapted from the given Maclaurin.m, is as follows:

```matlab

function [fxa,fxt,et,ea,iter] = Maclaurin_cos(x,es,maxit)

% Maclaurin series of cosine function

% [fxa,fxt,et,ea,iter] = Maclaurin_cos(x,es,maxit)

% input:

% x = value at which series evaluated

% es = stopping criterion (default = 0.0001)

% maxit = maximum iterations (default = 100)

% output:

% fxa = estimated value

% fxt = true value

% et = true relative error (%)

% ea = approximate relative error (%)

% iter = number of iterations

% defaults:

if nargin < 2 || isempty(es), es = 0.0001; end

if nargin < 3 || isempty(maxit), maxit = 100; end

% initialization

iter = 1;

sol = 1;

ea = 100;

fxt = cos(x);

et = abs((fxt - sol)/fxt)*100;

% iterative calculation

while (1)

   solold = sol;

   sol = sol + ((-1)^iter)*(x^(2*iter))/factorial(2*iter);

   iter = iter + 1;

   if sol ~= 0

       ea = abs((sol - solold)/sol)*100;

       et = abs((fxt - sol)/fxt)*100;

   end

   if ea <= es || iter >= maxit

       break;

   end

end

fxa = sol;

end

```

To evaluate the Maclaurin series for cos(x) at x = π/3, we can call the function and display the results as follows:

```matlab

x = pi/3;

[fxa, fxt, et, ea, iter] = Maclaurin_cos(x);

fprintf('Approximate value of cos(pi/3): %.10f\n', fxa);

fprintf('True percent relative error: %.4f%%\n', et);

fprintf('Approximate percent relative error: %.4f%%\n', ea);

``

The output will provide the approximate value of cos(π/3), the true percent relative error, and the approximate percent relative error for each iteration.

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Answer:

F=200kN

Explanation:

Frederick Taylor created a series of guidelines known as the "motion study principles" to boost productivity at work. Time study, motion study, fatigue study, etc technique conduct research are the four divisions into which they fall.

Motion studies are the study of actions like lifting, putting things down, standing, changing direction, and other actions that are made when performing routine work.

In order to execute the task effectively in less time, unnecessary moves are attempted to be removed. The following three headings comprise the fundamentals: Making use of the human body. The layout of the workplace. Machinery and tools design.

Motion study principles will be the which will help in designing or putting films into a particular order. Also how the routine works are being made is suggested.

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Answer:

Explanation:

I do not have access to your diagram but based on what I know, a food web cannot sustain itself without decomposers. They are the main guys who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow. So if decomposers are not there then producers cannot produce and thus herbivores cannot live and carnovers die out as well. Hope this makes sense.

Check out: https://www.nationalgeographic.org/encyclopedia/decomposers/

A food web cannot sustain itself without decomposers. They are the main components who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow.

Decomposers are living organisms like fungi and bacteria. These decomposers are heterotrophic which means they must take the nutrients and it cannot make its own food. Decomposers play an eminent role in an ecosystem because of their process of nutrition.

They break down the dead plants and the animals. These break down the waste of the organisms. They are very eminent for all the ecosystem. If these were not in the ecosystem, the plants cannot get essential nutrients, dead matter and waste would deposit. So the nutrients in them gets recycled back so that they can be used again.

When fish dies, there is nothing which is ingested and the bladder air starts to release, which causes the fish to sink to the bottom. After few days, the internal organs of the dead fish gets decomposed, after which a gas is formed.

Therefore, A food web cannot sustain itself without decomposers.

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Answer:

The product and process are designed simultaneously

Explanation:

PENN

a) ROM is a non-volatile memory.

b) The devices that can drive the address bus during a CPU write cycle include memory-mapped I/O devices, such as video cards and sound cards.

Read-Only Memory (ROM) is a type of non-volatile memory which means that the data stored on ROM is not lost when the power is turned off. ROM stores permanent data and instructions that are required to boot up the computer or device. It contains firmware such as BIOS which cannot be changed by the user without specific hardware. Because ROM is non-volatile, it is widely used to store critical programs that must always be available to the system, even during power outages.

During a write cycle, the CPU outputs an address onto the address bus to specify where the data should be written. Memory-mapped I/O requires the use of the same address bus and data bus lines that are used by memory. Therefore, memory-mapped I/O devices will also drive the address bus during a CPU write cycle. This allows the CPU to transfer data between memory and I/O devices in a uniform and efficient manner. By using memory-mapped I/O, an I/O device can be treated as if it were a part of memory, allowing for convenient access to I/O registers and other device-specific features.

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The coordinates of the center of curvature at time t = 1s are:

X coordinate: 8 meters

Y coordinate: 3 meters

To find the center of curvature, we need to determine the radius of curvature (R) and the coordinates of the center (Cx, Cy).

Given:

x = 2t² + 3t - 1

y = 5t - 2

To find the radius of curvature (R), we can use the following formula:

R = [(1 + (dy/dt)²)^(3/2)] / |d²y/dt²|

Differentiating y with respect to t gives:

dy/dt = 5

Differentiating dy/dt with respect to t gives:

d²y/dt² = 0 (since the derivative of a constant is zero)

Substituting these values into the radius of curvature formula:

R = [(1 + 5²)^(3/2)] / |0|

R = ∞ (infinity)

Since the radius of curvature is infinite, the center of curvature lies at infinity.

However, if we interpret the problem as finding the coordinates of the center at a given time t = 1s, we can substitute t = 1 into the equations for x and y to find the coordinates of the particle at that time.

x = 2(1)² + 3(1) - 1

x = 2 + 3 - 1

x = 4 meters

y = 5(1) - 2

y = 5 - 2

y = 3 meters

At time t = 1s, the coordinates of the particle are (4, 3) meters. However, since the radius of curvature is infinite, there is no specific center of curvature associated with this curvilinear motion.

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Answer:

not sure

Explanation:

not sure

The recommended vessel wall thickness is 0.57 inches. The thickness of the walls is critical since it aids in the prevention of deformation of the walls when subjected to high-pressure environments.

The vessel's thickness is determined using the following equation: t = P r / (2S.E + 0.6P), where t is the thickness, P is the pressure, r is the radius, S.E is the joint effectiveness, and S is the maximum allowable stress.

In this scenario, P = 2200 psi, S.E = 0.88, S = 15500 psi,

and r = (3V/4π)^(1/3) = (3*9.5/4π)^(1/3) = 0.8766 feet.

Therefore, t = 2200*0.8766 / (2*0.88*15500 + 0.6*2200) = 0.57 inches.  

The pressure vessel's wall thickness is determined using the ASME boiler and pressure vessel code, section VIII, division A pressure vessel is a container that is used to contain high-pressure liquids and gases. They are frequently used in the petrochemical industry and are sometimes used to transport hazardous substances.

The maximum allowable stress of mild steel is 15500 psi.

The joint effectiveness is used to assess the strength of the vessel's welded joints. In this scenario, the joint effectiveness is 88%.The vessel's thickness is determined using the following equation:

t = P r / (2S.E + 0.6P),

where t is the thickness, P is the pressure, r is the radius, S.E is the joint effectiveness, and S is the maximum allowable stress. In this scenario,

P = 2200 psi, S.E = 0.88, S = 15500 psi,

r = (3V/4π)^(1/3) = (3*9.5/4π) ^ (1/3) = 0.8766 feet.

Therefore, t = 2200*0.8766 / (2*0.88*15500 + 0.6*2200) = 0.57 inches. The wall thickness of a pressure vessel must be sufficient to withstand the internal pressure. Furthermore, the vessel's thickness must be sufficient to prevent deformation of the walls when subjected to high-pressure environments. The thickness of the walls is often influenced by the design of the vessel. The length, radius, and shape of the vessel all play a role in determining its thickness.

The recommended vessel wall thickness is 0.57 inches. The thickness of the walls is critical since it aids in the prevention of deformation of the walls when subjected to high-pressure environments. Furthermore, the design of the vessel, including its length, radius, and shape, has an impact on the thickness of its walls.

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Answer:

\(T_o=82.1sec\)

Explanation:

From the question we are told that:

Lost Time \(t=12secs\)

Sum of critical flow ratios \(X=0.72\)

Generally the Webster Method's equation for Optimum cycle time is is mathematically given by

 \(T_o=\frac{1.5t+5}{1-x}\)

 \(T_o=\frac{1.5*12+5}{1-0.72}\)

 \(T_o=82.1sec\)

Answer:

If a gpa a 2.2 that bad

Explanation:

Answer:

it gives pressure this makes it stay where it has to be and lock it

Explanation:

yan llng alam ko

On the print you would expect the pitch diameter of the gear to be 9.00 inches. Option A is right.

Gear ratio = 1/3

This is solved as number of teeth on pinion / teeth on gear

= Np/Ng

The pitch diameter = 1.5 x 2

= 3

Diametral pitch = 12

NP = 3 x 12 = 36

This is the teeth on piston

Ng = 3NP

Ng = 3 * 36

= 108

Hence pitch diameter = 108/12 = 9

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Answer:

A uniform T-section beam is 100 mm wide and 150 mm deep with a flange thickness of 25 mm and a web thickness of 12 mm. If the limiting bending stresses for the material of the beam are 80 MN/m2 in compression and 160 MN/m2 in tension, find the maximum u.d.l. that the beam can carry over a simply supported span of 5 m.

Explanation:

hope this helps if not let me know

The density of the object is 3333.33 kg/m³. The density of an object is a measure of how heavy it is for a given size, i.e. the mass of material per unit volume.

Gravity, also known as gravitational force, pulls objects with mass toward each other. We frequently consider the force of gravity from Earth. This force is responsible for keeping your body on the ground. Any object with mass, on the other hand, exerts a gravitational force on all other objects with mass.

Density: This can be defined as the ratio of the mass of a body to its volume.

The unit of density is kg/m³.

From Archimedes principle,

R.d = W/U = D/D'

Where R.d = relative density, W = weight of the object in air, u = upthrust in water, D = Density of the object, D' = Density of water.

W/U = D/D'

making D the subject of the equation

D = D'(W/U).......................... Equation 1

Given: W = 5.0 N, U = 5.0 -3.5 = 1.5 N, D' = 1000 kg/m³

U = lost in weight = weight in air - weight in water

Substitute into equation 1

D = 1000(5/1.5)

D = 3333.33 kg/m³

Thus the density of the object = 3333.33 kg/m³

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Answer:

Option B: False

Explanation:

A heat engine is a device which operates in a manner that heat is converted into mechanical work.

A simple example of a heat engine is a drinking bird. The oscillatory motion of the drinking bird is as a result of the thermal expansion and contraction of a chemical compound in its beak, which creates an imbalance in its position of equilibrium. This causes it to oscillate.

Heat engines usually work by extracting heat once there is a temperature gradient available in the system and using it to perform work. Another good example is the internal combustion engine. It extracts heat from the explosion of the burning fuels and uses it to power the car.

Answer: Kirchhoff's voltage law

Ethanol production from sugarcane is comprised by the following steps: cleaning of sugarcane and extraction of sugars; juice treatment, concentration and sterilization; fermentation; distillation and dehydration.