Answer:
a. To show that 111000 can be produced by G, we can follow the rules of the grammar G by repeatedly applying the rules until we reach the desired string: S -> E -> 111 -> 1151 -> 11151 -> 111051 -> 111000 Therefore, 111000 can be produced by G.
b. To count the number of different derivations in G that can produce 111000, we can use the fact that G is an unambiguous grammar, which means that each string in the language of G has a unique derivation in G. Since there is only one way to derive 111000 in G, there is only one different derivation in G that can produce 111000.
c. To generate even-length strings in {0,1}* with G, we can add the following rules to G: S -> 0S | 1S | E E -> epsilon The first rule allows us to generate any even-length string by alternating between 0 and 1, and the second rule allows us to terminate the derivation with an empty string. With these rules added, we can derive any even-length string in {0,1}* by starting with S and repeatedly applying the rules until we reach the desired even-length string.
Explanation:
Write 83,120 in expanded form using powers of 10.
Answer:
8*10000+3*1000+1*00+2*10+2
Explanation:
Christopher needs to order some new supplies for the restaurant where he works. The restaurant needs at least 775 spoons. There are currently 355 spoons. If each set on sale contains 10 spoons, write and solve an inequality which can be used to determine s, the number of sets of spoons Christopher could buy for the restaurant to have enough spoons.
The inequality which can be used to determine s, the number of sets of spoons Christopher could buy for the restaurant to have enough spoons is
35 + 10s ≥ 75
What is an inequality?An inequality is simply used to show the relationship between the expressions that aren't equal.
The restaurant needs at least 75 spoons and there are currently 35 spoons and each set on sale contains 10 spoon.
Let each set be represented as s. This will be illustrated as:
35 + (10 × s) ≥ 75
35 + 10s ≥ 75
Collect like terms
10s ≥ 75 - 30
10s ≥ 45
Divide
s ≥ 45/10
s ≥ 4.5
The restaurant must have at least 5 sets.
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The inequality that can be used to determine s, the number of sets of spoons Christopher could buy for the restaurant, is 35 + 10s ≥ 75.
What is inequality?Inequality is a term used to show two relations between two values that are not equal to each other.
Given, the restaurant needs at least 775 spoons. They have 355 spoons and each set contains 10 spoons.
Then the expression is ;
35 + (10 × s) ≥ 75
35 + 10s ≥ 75
Like terms are extracted
10s ≥ 75 - 30
10s ≥ 45
s ≥ 45/10
s ≥ 4.5
Thus, the inequality in the number of sets of spoons is 35 + 10s ≥ 75.
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Water is pumped steadily through a 0.10-m diameter pipe from one closed pressurized tank to another tank. The pump adds 4.0 kW of energy to the water and the head loss of the flow is 10 m. Determine the velocity of the water leaving the pump and discharging into tank B.
Complete Question
Complete Question is attached below.
Answer:
\(V'=5m/s\)
Explanation:
From the question we are told that:
Diameter \(d=0.10m\)
Power \(P=4.0kW\)
Head loss \(\mu=10m\)
\(\frac{P_1}{\rho g}+\frac{V_1^2}{2g}+Z_1+H_m=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}+Z_2+\mu\)
\(\frac{300*10^3}{\rho g}+35+Hm=\frac{500*10^3}{\rho g}+15+10\)
\(H_m=(\frac{200*10^3}{1000*9.8}-10)\)
\(H_m=10.39m\)
Generally the equation for Power is mathematically given by
\(P=\rho gQH_m\)
Therefore
\(Q=\frac{P}{\rho g H_m}\)
\(Q=\frac{4*10^4}{1000*9.81*10.9}\)
\(Q=0.03935m^3/sec\)
Since
\(Q=AV'\)
Where
\(A=\pi r^2\\A=3.142 (0.05)^2\)
\(A=7.85*10^{-3}\)
Therefore
\(V'=\frac{0.03935m^3/sec}{7.85*10^{-3}}\)
\(V'=5m/s\)
A wind tunnel is used to study the flow around a car. The air is drawn at 60 mph into the tunnel. (a) Determine the pressure in the test section as determined by the manometer. (b) Determine the pre
Answer:
The answer is below
Explanation:
The complete question is attached.
a) Bernoulli equation is given as:
\(P+\frac{1}{2}\rho V^2+ \rho gz=constant\\\\\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\)
Where P = pressure, V = velocity, z = height, g = acceleration due to gravity and ρ = density.
\(\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\\\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_1}{\gamma} +\frac{V_1^2}{2g} +z_1=\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2\\\\but \ z_1=z_2,P_1=0,V_1=0,V_2=60\ mph=88\ ft/s. Hence:\\\\\frac{P_2}{\gamma} =-\frac{V_2^2}{2g} \\\\P_2=\gamma*-\frac{V_2^2}{2g} =\rho g*-\frac{V_2^2}{2g} \\\\P_2=-\frac{V_2^2}{2}*\rho=-\frac{(88.8\ ft/s)^2}{2} * 0.00238\ slug/ft^3=-9.22\ lb/ft^2\\\\P_2+\gamma_{H_2O}h-\gamma_{oil}(1/12 \ ft)=0\\\\\)
\(\gamma_{oil}=0.9\gamma_{H_2O}=0.9*62.4\ lb/ft^3=56.2\ lb/ft^3\\\\Therefore:\\\\-9.22\ lb/ft^2+62.4\ lb/ft^3(h)-56.2\ lb/ft^3(1/12\ ft)=0\\\\h=0.223\ ft\)
b)
\(\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2=\frac{P_3}{\gamma} +\frac{V_3^2}{2g} +z_3\\\\but \ z_3=z_2,V_3=0,V_2=60\ mph=88\ ft/s. \\\\\frac{P_2}{\gamma}+\frac{V_2^2}{2g} = \frac{P_3}{\gamma}\\\\\frac{P_3-P_2}{\gamma}=\frac{V_2^2}{2g} \\\\P_3-P_2=\frac{V_2}{2g}*\gamma=\frac{V_2^2}{2g}*\rho g\\\\P_3-P_2=\frac{V_2}{2}*\rho=\frac{(88\ ft/s^2)^2}{2}*0.00238\ slg\ft^3\\\\P_3-P_2=9.22\ lb/ft^2\)
What is the eye an example of?
sense organ
stimulus
a relay neuron
sens organ is the eye example
Which of the following is a basic type of weld? O Groove O Lap O Edge O Corner
what is not a possible benefit of using a while loop?
it is crucial to remember that if not used appropriately, while loops might result in infinite loops.
A control flow statement called a while loop enables code to be run repeatedly depending on a condition. The following are some potential advantages of utilising a while loop:
1.It permits rerunning a section of code while a specific condition is true.
2.It can be used to carry out iterative tasks like processing list or array elements.
By eliminating the need for redundant or repeating statements, it can make code simpler.
The basic syntax of a while loop is as follows:
while (condition) {
// code to be executed while condition is true
}
As the benefits described above are the main benefits of utilising a while loop, it is untrue to claim that there is an advantage to doing so. However, it is crucial to remember that if not used appropriately, while loops might result in infinite loops.
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True or false: You can create a network with two computers.
Answer
True
Suppose a student table has two columns, names and marks. How to get name and marks of top three students
Answer:
SELECT Name, Marks FROM Student s1 where 3 <= (SELECT COUNT(*) FROM Students s2 WHERE s1.marks = s2.marks)
A)H is a discrete-time LTI system with impulse response h[n] = (1/3)^n u[n].The system input is given by x[n] = (1/4)^n u[n].Find the output signal y[n].B)H is a discrete-time LTI system with impulse responseh[n] = { 1, 2 ≤ n ≤ 5}; { 0, otherwise.} = u[n − 2] − u[n − 6].The system input is given by x[n] = (−1/3)^n u[n].Find the output signal y[n].
Thus, the output signal y[n] is y[n] = (3/4)^{n-3} + 25/14 - (3/2)^n.
A) To find the output signal y[n], we can use the convolution sum:
y[n] = x[n] * h[n]
where * denotes convolution.
Substituting the given values of x[n] and h[n], we get:
y[n] = Σ x[k] h[n-k], where the sum is over all k such that x[k] and h[n-k] are defined.
So, we have:
y[n] = Σ (1/4)^k u[k] (1/3)^(n-k) u[n-k]
= (1/3)^n Σ (1/4)^k u[k] u[n-k]
Note that the sum is over k such that both u[k] and u[n-k] are nonzero. Since u[k] is 1 for k ≥ 0, and u[n-k] is 1 for n-k ≥ 0, we have:
0 ≤ k ≤ n
Therefore, the sum can be simplified to:
y[n] = (1/3)^n Σ (1/4)^k
= (1/3)^n (1 + 1/4 + 1/16 + ...)
This is a geometric series with first term 1 and common ratio 1/4. The sum of a geometric series with first term a and common ratio r is:
Σ ar^k = a/(1-r)
Using this formula, we get:
y[n] = (1/3)^n (1/(1-1/4))
= (4/3)^n
Therefore, the output signal y[n] is y[n] = (4/3)^n.
B) To find the output signal y[n], we again use the convolution sum:
y[n] = x[n] * h[n]
Substituting the given values of x[n] and h[n], we get:
y[n] = Σ x[k] h[n-k], where the sum is over all k such that x[k] and h[n-k] are defined.
So, we have:
y[n] = Σ (-1/3)^k u[k] (u[n-k-2] - u[n-k-6])
Note that the sum is over k such that both u[k] and the step functions are nonzero. Since u[k] is 1 for k ≥ 0, we have:
0 ≤ k ≤ n+5
To simplify the sum, we break it up into two parts:
y[n] = Σ (-1/3)^k u[k] u[n-k-2] - Σ (-1/3)^k u[k] u[n-k-6]
The first sum is over k such that k ≤ n+2, and the second sum is over k such that k ≤ n+6. Therefore, we have:
y[n] = Σ (-1/3)^k u[k] u[n-k-2] - Σ (-1/3)^k u[k] u[n-k-6]
= Σ (-1/3)^k u[k] u[n-k-2] + Σ (-1/3)^k u[k] (1-u[n-k-6])
= Σ (-1/3)^k u[k] u[n-k-2] + Σ (-1/3)^k u[k] - Σ (-1/3)^k u[k] u[n-k-6]
= Σ (-1/3)^k u[k] u[n-k-2] + Σ (-1/3)^k u[k] - Σ (-1/3)^{n-k} u[k] u[k-4]
Note that the first sum is over k such that k ≤ n+2, the second sum is over all k, and the third sum is over k such that k ≥ 4.
To evaluate the sums, we consider each one separately:
Σ (-1/3)^k u[k] u[n-k-2] = (-1/3)^n u[n-2] + (-1/3)^{n-1} u[n-1] + (-1/3)^{n-2} u[n-2] + ... + (-1/3)^2 u[2] + (-1/3) u[1] + u[0]
This is a finite sum that can be evaluated using the formula for a finite geometric series. Since the common ratio is -1/3, we have:
Σ (-1/3)^k u[k] u[n-k-2] = [(-1/3)^n - (-1/3)^{n-3}]/(1-(-1/3)) = (-3/4)^n + (3/4)^{n-3}
The second sum is over all k, so we have:
Σ (-1/3)^k u[k] = 1/(1-(-1/3)) = 3/2
The third sum is over k such that k ≥ 4. We can shift the index by setting j = k-4, so that j ≥ 0. Then, we have:
Σ (-1/3)^{n-k} u[k] u[k-4] = Σ (-1/3)^{n-j-4} u[j+4] u[j]
Note that the sum is over j such that j ≤ n-4. Since u[j+4] is 1 for j ≥ -4, and u[j] is 1 for j ≥ 0, we have:
-4 ≤ j ≤ n-4
Therefore, the sum can be simplified to:
Σ (-1/3)^{n-k} u[k] u[k-4] = Σ (-1/3)^{n-j-4} = (-3/4)^{n-4} + (-3/4)^{n-5} + (-3/4)^{n-6} + ... + (-3/4)^{-4}
This is a finite sum that can be evaluated using the formula for a finite geometric series. Since the common ratio is -3/4, we have:
Σ (-1/3)^{n-k} u[k] u[k-4] = [(3/4)^{-4} - (-3/4)^{n-4}]/(1-(-3/4)) = 4/7 - (3/4)^n
Therefore, the output signal y[n] is:
y[n] = (-3/4)^n + (3/4)^{n-3} + 3/2 + 4/7 - (3/4)^n
= (3/4)^{n-3} + 25/14 - (3/2)^n
Hence, the output signal y[n] is y[n] = (3/4)^{n-3} + 25/14 - (3/2)^n.
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Describe the blade design for a wind turbine that you would choose. Why did you choose this design?
Answer: aerofoil type blades
Explanation: they are more difficult to make but offer better performance and higher rotational speeds making them ideal for electrical energy generation.
who is the strongest avenger i say hulk but who knows at this point
Answer:
or is the strongest evenger she hulk
Explanation:
?????????
Answer:
Thor!
Explanation:
In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.
Never operate electric tools outdoors or in wet conditions unless circuit is protected by what?.
Never operate electric tools outdoors or in wet conditions unless the circuit is protected by a ground fault circuit interrupter (GFCI).
When a number of electric entities are connected through various conductors is called a circuit.
Here,
A ground fault circuit interrupter (GFCI) helps to avoid the repercussion caused due to electric shocks. An individual receives a shock, the GFCI perceives this and cuts off the current before the individual can get any damage. it is usually installed where electrical circuits come into reference with water.
Thus, Never operate electric tools outdoors or in wet conditions unless the circuit is protected by a ground fault circuit interrupter (GFCI).
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6 Section 1
Whole Numbers
18. An illustration of a shaft is shown. Find the lengths, in millimeters, of A,
B, C, and D.
A) 35 + 21 + 18 + 23 + 11
B) 23 + 11
C) 35 + 21
D) 21 + 18 + 23 + 11
What construction issues might require the services of a hazmat worker? (Select all that apply.)
asbestos
radioactive waste
lead
biologicals
sheet metal
Hazmat workers may be required for construction issues involving:
asbestosradioactive wastelead.What construction issues require hazmat workers?Hazmat workers are trained to handle hazardous materials safely and effectively. In construction, they help to remove materials that are dangerous to workers and the environment.
Asbestos, radioactive waste and lead are dangerous. These workers are trained to safely remove these materials and dispose of them properly. Other hazardous materials such as biologicals or sheet metal requires specialized workers depending on extent of the hazard.
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The US navy recently funded the development of submersible drones to investigate shipwrecks located
on the ocean floor of the Marianas Trench. In this region of the world the ocean floor is located about
7.0 miles below sea level. Calculate the pressure a submersible drone would need to withstand 7 miles
below the surface of the ocean.
The pressure a submersible drone would need to withstand 7 miles is given to be 114.49 MPA
How to solve for the pressure of the submersible droneWer have P = rho x H
Where Rho s is the Sp x the weight of the sea water
= 10163 . 16n/m²
We are to proceed to find the value of H
H = 7. 0 miles below sea water
= 11265.408m
P = 11265.408m x 10163 . 16n/m²
= 114,492.144
= 114.49 MPA
Hence we can say that the pressure of the submersible drone should be equal to 114.49 MPA
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Working with Categorical Variables The columns cut, color, and clarity are categorical variables whose values represent discrete categories that the diamonds can be classified into. Any possible value that a categorical variable can take is referred to as a level of that variable. As mentioned at the beginning of these instructions, the levels of each of the variables have a natural ordering, or ranking. However, Pandas will not understand the order that these levels should be in unless we specify the ordering ourselves. 2 Create a markdown cell that displays a level 2 header that reads: "Part 3: Working with Categorical Variables". Add some text explaining that we will be creating lists to specify the order for each of the three categorical variables. Create three lists named clarity_levels, cut_levels, and color_levels. Each list should contain strings representing the levels of the associated categorical variable in order from worst to best. We can specify the order for the levels of a categorical variable stored as a column in a DataFrame by using the pd. Categorical() function. To use this function, you will pass it two arguments: The first is the column whose levels you are setting, and the second is a list or array containing the levels in order. This function will return a new series object, which can be stored back in place of the original column. An example of this syntax is provided below: df.some_column = pd. Categorical (df.some_column, levels_list) Create a markdown cell explaining that we will now use these lists to communicate to Pandas the correct order for the levels of the three categorical variables. Use pd. Categorical() to set the levels of the cut, color, and clarity columns. This will require three calls to pd. Categorical(). Create a markdown cell explaining that we will now create lists of named colors to serve as palettes to be used for visualizations later in the notebook. Create three lists named clarity_pal, color_pal, and cut_pal. Each list should contain a number of named colors equal to the number of levels found for the associated categorical variable. The colors within each list should be easy to distinguish from one-another.
The solution with the requested markdown cells and code:
Part 3: Working with Categorical Variables
In this section, we will create lists to specify the order for each of the three categorical variables: clarity, cut, and color.
First, let's create the lists:
python
Copy code
clarity_levels = ['I1', 'SI2', 'SI1', 'VS2', 'VS1', 'VVS2', 'VVS1', 'IF']
cut_levels = ['Fair', 'Good', 'Very Good', 'Premium', 'Ideal']
color_levels = ['J', 'I', 'H', 'G', 'F', 'E', 'D']
Now, we will use the pd.Categorical() function to set the levels of the cut, color, and clarity columns:
python
Copy code
df['cut'] = pd.Categorical(df['cut'], cut_levels)
df['color'] = pd.Categorical(df['color'], color_levels)
df['clarity'] = pd.Categorical(df['clarity'], clarity_levels)
Finally, let's create lists of named colors to serve as palettes for visualizations:
python
Copy code
clarity_pal = ['lightgray', 'blue', 'green', 'orange', 'purple', 'yellow', 'pink', 'red']
cut_pal = ['red', 'orange', 'yellow', 'green', 'blue']
color_pal = ['brown', 'gray', 'pink', 'green', 'blue', 'purple', 'red']
These palettes will help us distinguish the different levels of each categorical variable in our visualizations.
Now that we have set the correct order for the categorical variable levels and created color palettes, we can proceed with further analysis and visualization of the diamond dataset.
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Consider the Fourier series for the periodic function: x(t)=sin(5t)−cos(10t)−sin(20t) The Fourier coefficient angle θ
2
of the combined trigonometric series is: Select one: 180 0 90 −90
The Fourier series is used to represent a periodic function as a combination of sine and cosine functions. In this case, the periodic function is x(t) = sin(5t) - cos(10t) - sin(20t). To find the Fourier coefficients, we need to determine the values of the coefficients A_n and B_n in the series representation:
Where ω is the angular frequency. First, let's find the value of A_0, which represents the DC component or the average value of the function over one period. In this case, the function x(t) is symmetric about the y-axis, so A_0 will be zero. Next, let's find the values of A_n and B_n for n > 0. The coefficients A_n represent the amplitudes of the cosine terms, and the coefficients B_n represent the amplitudes of the sine terms.
Simplifying these integrals and performing the calculations, we can find the values of A_n and B_n for different values of n. For the given function x(t) = sin(5t) - cos(10t) - sin(20t), the Fourier coefficient angle θ2 represents the angle at which the coefficient B2 reaches its maximum value. To determine this angle, we need to calculate the values of B_n for different values of n and find the angle at which B2 is maximum. Once we have the values of B_n, we can find the angle θ2 using the formul I apologize, but without performing the calculations for B_n, I cannot provide a specific answer for the value of θ2. However, I hope this explanation helps you understand the process of finding the Fourier coefficients and the concept of θ2 in the context of a Fourier series.
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2. You should hold your fingers on the power switch when holding a plugged-
in power tool.
A True
B. False
An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.
Answer:
b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.
Explanation:
An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.
It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.
định khoản nghiệp vụ sau : tạm ứng cho nhân viên A đi công tác bằng tiền mặt 50.000
Answer:
report on a fight you have witnessed
AC motor characteristics require the applied voltage to be proportionally adjusted by an AC drive whenever the frequency is changed. True or false?
what is the worst way to show self-management?
a. Plant a time to evaluate your progress
b. Set your own career your
c. Ask your boss to set all your goals
d. Ask for feedback on your progress
The worst way to show self-management is to ask your boss to set all your goals. Self-management is the act of managing one's own behavior, time, and resources effectively to reach a goal.
It is the ability to organize oneself and control impulses, emotions, and actions. It is a skill that requires discipline, self-awareness, and commitment. There are different ways to show self-management, but some ways are better than others.Asking your boss to set all your goals is the worst way to show self-management because it shows a lack of initiative and responsibility. It suggests that you are not willing to take ownership of your career or invest in your development. It also implies that you are not confident in your ability to set and achieve your own goals. By asking your boss to set all your goals, you are giving away your power and agency, and relying on someone else to define your success and progress. This approach can be limiting, disempowering, and demotivating.There are better ways to show self-management, such as planting a time to evaluate your progress, setting your own career goals, and asking for feedback on your progress. Planting a time to evaluate your progress is a proactive way to assess your performance and identify areas for improvement. Setting your own career goals demonstrates ambition, vision, and ownership of your future. Asking for feedback on your progress shows a willingness to learn, grow, and adapt to new challenges. These approaches are more empowering, engaging, and effective than relying on your boss to set all your goals.
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Average setup time on a certain production machine is 5.0 hr. Average batch size is 52 parts, and average operation cycle time is 4.2 min. The reliability of this machine is characterized by mean time between failures of 37 hr and a mean time to repair of 55 min.
(a) If availability is ignored, what is the average hourly production rate of the machine.
(b) Taking into account the availability of the machine, determine its average hourly production rate.
(c) Suppose that availability only applied during the actual run time of the machine and not the setup time. Determine the average hourly production rate of the machine under this scenario.
(a) The machine's average hourly production rate without considering availability is 6.02 parts/hr.
(b) The machine's average hourly production rate, taking into account availability, is 6.17 parts/hr.
(c) The machine's average hourly production rate when only available during run time is 5.71 parts/hr.
How to solve calculations on a production machine?(a) To calculate the average hourly production rate of the machine without considering availability, we need to first calculate the total time it takes to produce a batch of 52 parts.
Total time = (setup time) + (operation time per part x batch size)
Total time = 5.0 hr + (4.2 min/part x 52 parts)/60 min/hr
Total time = 5.0 hr + 3.64 hr
Total time = 8.64 hr
Average hourly production rate = Batch size / Total time
Average hourly production rate = 52 parts / 8.64 hr
Average hourly production rate = 6.02 parts/hr
Therefore, the average hourly production rate of the machine without considering availability is 6.02 parts/hr.
(b) To calculate the average hourly production rate of the machine taking into account availability, we need to first calculate the machine's availability using the mean time between failures (MTBF) and mean time to repair (MTTR) values.
Availability = MTBF / (MTBF + MTTR)
Availability = 37 hr / (37 hr + 0.92 hr)
Availability = 0.975 or 97.5%
Now we can calculate the total time that the machine is available for production:
Available time = Total time x Availability
Available time = 8.64 hr x 0.975
Available time = 8.42 hr
Average hourly production rate = Batch size / Available time
Average hourly production rate = 52 parts / 8.42 hr
Average hourly production rate = 6.17 parts/hr
Therefore, the average hourly production rate of the machine taking into account availability is 6.17 parts/hr.
(c) If availability only applies during the actual run time of the machine and not the setup time, we need to adjust the available time calculation:
Available time = (operation time per part x batch size) / 60 min/hr x Availability
Available time = (4.2 min/part x 52 parts) / 60 min/hr x 0.975
Available time = 4.11 hr
Total time = Available time + setup time
Total time = 4.11 hr + 5.0 hr
Total time = 9.11 hr
Average hourly production rate = Batch size / Total time
Average hourly production rate = 52 parts / 9.11 hr
Average hourly production rate = 5.71 parts/hr
Therefore, the average hourly production rate of the machine taking into account availability only during run time is 5.71 parts/hr.
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A light string can a station- support ary hanging load before of 25.0 kg breaking. An object of mass m = 3.00 kg attached to the string rotates on a friction- less, horizontal table in a circle of radius 0.800 m, and the other end of the T Figure P6.1 string is held fixed as in Figure P6.1. What range of speeds can the object have before the string breaks?
The magnitude of the velocity vector represents the object's current speed.The velocity vector points in the same general direction as the motion of the object.
What speed range is the object capable of before the string snaps?The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).
A hanging mass of 25 kg will exert a force of:
25 * 9.81 = 254.25 Newtons on the string
Thus, during rotation, the force exerted should remain less than this. Force on an object in circular motion is given by:
F = (m * v^2) / r
F = mv2/r = 3.0(v2)/0.8 = (25)9.8 = 245
v = sqrt(245 x 0.8 / 3.0) = 8.1 m/s
v is from 0 to 8.1 m/s
Thus, the magnitude of the velocity should not exceed 8.1 meters per second.
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Standards relating to technical drawing
Answer:
Borders, Dimensions Identified, Scale, Text Box with Date/Author/Title/Version Number
Explanation:
Technical drawings have many standards in order to maintain integrity and ensure that they can be used by engineers to produce what is mapped out in the drawing.
Every technical drawing needs to have borders and a text box with all information related to the drawing. This includes the date it was created, date it was updated, version number, title, and author.
Furthermore, each drawing should have necessary dimensions with a scale. At the same time, technical drawings should not be over-dimensioned or repetitive.
All of these things must be on a technical drawing to allow professional engineers to sign off on drawings.
Team communication is often more formal than other types of group communication.
True
False
Answer:
True
Explanation:
How does inductive reactance depend on the frequency of the ac voltage source and the rms current through the inductor?.
Directly proportional.
As the inductive reactance is directly proportional to the frequency, by increasing the frequency the inductive reactance of the inductor increases.
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discuss 7 habits of highly effective people and how important are ethics in today's society
Answer:
Explanation:
The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include
Being proactive
Starting anything with the end in mind
First things first
Always thinking towards a win-win situation
Seeking initially to understand, then going on to want to be understood
Synergize, and lastly
Growing
) Identify the reason leading to the common use of a 3-phase 4-wire system
The main reason for the common use of a 3-phase 4-wire system is the need to deliver power to different types of loads efficiently and effectively.
A 3-phase 4-wire system provides three alternating currents that are 120 degrees out of phase with each other. This type of system is commonly used in industrial and commercial settings because it can handle higher power loads than single-phase systems. The fourth wire is a neutral wire, which provides a return path for any unbalanced current in the system. This is important because it ensures that the voltage across each load remains balanced, which is necessary for the proper functioning of electrical equipment. Additionally, the use of a 3-phase system allows for the use of smaller and more efficient motors, reducing energy consumption and costs. Overall, the use of a 3-phase 4-wire system is essential for delivering power effectively and efficiently to various types of loads.
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