torch is rated 2.2v.0.25A.calculate the charge passing through the bulb in one second and energy transferred by the passage of each coulomb of charge.

ans-0.25 C and 2.2J

Answer:

F (force) can be written F/L  = K I1 I2 where K is some constant

F1 = 4 F1    if I1 and I2 are each doubled

If both currents are doubled, the new force of attraction between the wires will be 0.4 mN.

The force of attraction between two parallel wires carrying equal currents is given by Ampere's law, which states that the force is directly proportional to the product of the currents and inversely proportional to the square of the distance between the wires. Given that the current in each wire is 10A and the force of attraction is 1mN, we can use this information to calculate the distance between the wires.

Let's assume the distance between the wires is "d".

Using the formula for the force of attraction between the wires:

F = (μ₀ * I₁ * I₂) / (2πd)

where F is the force, μ₀ is the permeability of free space, I₁ and I₂ are the currents, and d is the distance between the wires.

Rearranging the formula, we can solve for d: d = (μ₀ * I₁ * I₂) / (2πF)

We know that F = 1mN, I₁ = I₂ = 10A, and μ₀ = 4π x 10^(-7) N/A².

Substituting these values into the formula, we can find the distance between the wires:

d = (4π x 10^(-7) N/A² * 10A * 10A) / (2π * 1mN)

Simplifying the expression, we find: d = (4 x 10^(-6) N/A² * 100 A²) / (2 x 10^(-3) N)

d = 200 x 10^(-6) m

d = 0.2 mm

Now, if both currents are doubled to 20A, we can calculate the new force of attraction between the wires using the same formula:

F' = (μ₀ * I₁' * I₂') / (2πd)

where F' is the new force, I₁' and I₂' are the new currents, and d is the distance between the wires.

Substituting the values, we get: F' = (4π x 10^(-7) N/A² * 20A * 20A) / (2π * 0.2mm)

Simplifying the expression, we find: F' = (4 x 10^(-6) N/A² * 400 A²) / (4 x 10^(-4) N)

F' = 400 x 10^(-6) N

F' = 0.4 mN

Therefore, the new force of attraction between the wires will be 0.4 mN, if both currents are doubled.

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Answer:

Elastic potential energy is stored when materials stretch or compress. Examples of it include springs, rubber bands, and slingshots.

Explanation:

The coefficient of static friction on a horizontal surface is found to be 0.83.

The ratio between the perpendicular force pushing the objects together and the resistive frictional force is known as the coefficient of friction. The formula for the friction coefficient is = F N. Depending on the items creating friction, the coefficient of friction changes. The value might be larger than 1 but is often between 0 and 1.

Force (f)= 65N ;  Mass (m) = 8Kg ; Acceleration due to gravity (g) =  9.8 m/s²  

μ = Coefficient of static friction.

Static friction force, f = μmg

μ = f/mg ;

  => 65/(8 x 9.8) = 0.83

The nature and roughness of the surfaces in contact affect the coefficient of static frictional force. It does not depend on the size or surface area of the surfaces. The value might be larger than 1 but is often between 0 and 1.

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The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:

k = Q / (A * ΔT * L) = Rth * (A * ΔT)

Reorganizing this equation gives:

Rth = k / (A * ΔT)

The given information in the problem is:

Rate of heat flow (Q) = 14.0 watts

Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C

Temperature difference (ΔT) = 28°C

Substituting these values into the equation, we have:

k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK

So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.

Answer:

0 J

Explanation:

KE = .5(m)(v2-v1)

if velocity is constant v2 = v1, then v2 - v1 = 0

therefore if (v2-v1) = 0, then KE must also be equal to 0

Answer:

86.7

Explanation:

sana makatulong yung answer ko

Answer:

The answer is magma

Explanation:

I'm 99.99% this is right

Answer: its magnetic reversal

Explanation: jus took the test make brainly

Answer:

Explanation:

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Let's state the Newton's Third Law of Motion.

The Newton's Third Law of Motion states that when two bodies interact, the forces they apply to each other are equal in magnitude and opposite in direction.

Therefore, since the forces the bodies exert equal forces in opposite direction on each other, it means that forces come in pairs.

The forces can be said to be action-reaction force pairs

Therefore, Newton's third Law of Motion states that all forces come in pairs.

ANSWER:

All forces come in pairs.

Explanation

the charge is given by the expression

Step 1

Let

hence

therefore, the answer is

I hope this helps you

The potential energy of the object before it fell is determined as 147 (kg). J.

The potential energy of an object is the energy possessed by an object due to its position above the ground level.

The potential energy of an object depends on the mass and height of the object above the ground.

P.E = mgh

where;

Substitute the given parameters and solve for the potential energy of the object as shown below.

P.E = (m , kg)(15 m)(9.8 m/s²)

P.E = 147 (kg). J

Thus, the potential energy of the object before it fell is determined as 147 (kg). J.

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Answer:

A car traveling south with its cruise control set

Explanation:

Turning could cause anything to slow down but going forward could mean that anything could go faster.

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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Answer:10.m and 10. M

Explanation:

A displacement vector with a magnitude of 20. m could have perpendicular components with magnitudes of C. 12 m and 16 m.

A displacement vector with a magnitude of 20. meters can be decomposed in 2 perpendicular components.

They would form a right triangle, in which the displacement vector would be the hypotenuse (a) and the components would be the legs (b, c).

Given the magnitude of the legs, we can calculate the magnitude of the hypotenuse using the Pythagorean theorem.

\(c = \sqrt{a^{2} + b^{2} }\)

Let's use this formula to calculate the displacement vector for each pair of legs.

\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(10.m)^{2} + (10.m)^{2} }= 14.1m\)

\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(12m)^{2} + (8.0m)^{2} }= 14.4m\)

\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(12m)^{2} + (16m)^{2} }= 20m\)

\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(16m)^{2} + (8.0m)^{2} }= 17.9m\)

A displacement vector with a magnitude of 20. m could have perpendicular components with magnitudes of C. 12 m and 16 m.

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The mass of the object experimented on in this situations is 20 kg. So, option(C) is correct.

A force is something that pushes or pulls an object. The objects' interactions with one another are what causes push and pull. Force can also be expressed using words like stretch and squeeze.

When an object with mass is pushed or pulled, it changes its velocity, according to the definition of force in physics.

The product of mass (m) and acceleration (a) represents the amount of force (F). Mathematically speaking, the force equation or formula can be written as follows:

F = ma

According to given parameters:

Force = 30 N; acceleration = 1.5 m/s². So, mass = 30/1.5 kg = 20 kg.

Force = 70 N; acceleration = 3.5 m/s². So, mass = 70/3.5 kg = 20 kg.

Force = 85 N; acceleration = 4.25 m/s². So, mass = 85/4.25 kg = 20 kg.

Hence, the mass of the object experimented on in this situations is 20 kg.

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A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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According to the given statement The voltage gradient between the plates is ​45.2kV/m

The Volt/meter (V/m) unit of measure for potential gradient is standard. Take a look at the graph between the potential gradient and distance. The potential gradient is strong when the object is close to or at a low distance from the high voltage wire; as you increase the distance, the gradient reduces.

Flux Density

D = 2μC/m²

D =2×10⁻⁶ C/m²

ε\(_0\) = 8.85 × 10⁻¹² F/m

ε\(_r\) = 5

D/E = ε\(_0\)ε\(_r\)   hence voltage gradient

E = D/ε\(_0\)ε\(_r\)

= \(\frac{2 \times 10^{-6}}{8.85 \times 10^{-12} \times 5} \mathrm{~V} / \mathrm{m}\)

= 45.2kV/m

The voltage gradient between the plates is ​45.2kV/m

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Answer:

yes

Explanation:

Answer:

The brachistochrone curve is an idealized curve that provides the fastest descent possible.

Explanation:

There is actually an analytical solution to this case or, with some derivation work, we can use the PDE functionality of COMSOL Multiphysics to solve the problem.

The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.

when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.

It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.

The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.

To simulate gravity for the inhabitants, the concept of the centrifugal force is used.

Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.

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As the object falls down, it pushes air aside, and the air pushes back (newton's 3rd law) so the air slows down the object a very tiny amount. This causes friction. The friction produces some heat as well.

The stress in Magapascals is 80 Magapascals

This question can be solved by applying Young's modulus.

Young's modulus : Young's modulus states that, stress  is directly proportional to strain.

Where Stress is pressure acting the body. The s.i unit of stress is N/m² or Pascal. And it can be expressed mathematically as,

From the question,

\(P = 10000/(125*10^{-6} )\)

\(P =\) \(8*10^{7}\) Pascals

\(P =\) 80 Magapascals

Hence the stress in Magapascals is 80 Magapascals

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The stress experimented by the tie-bar is 80 megapascals.

The tie-bar is under axial load. Under the assumption that force is distributed uniformly in the cross-section area, we can use the following definition of normal stress (\(\sigma\)), in megapascals:

\(\sigma = \frac{F}{A}\) (1)

Where:

\(F\) - Axial force, in meganewtons.

\(A\) - Cross-section area, in square meters.

If we know that \(F = 10\times 10^{-3}\,MN\) and \(A = 125\times 10^{-6}\,m^{2}\), then the stress experimented by the tie-bar is:

\(\sigma = \frac{10\times 10^{-3}\,MN}{125\times 10^{-6}\,m^{2}}\)

\(\sigma = 80\,MPa\)

The stress experimented by the tie-bar is 80 megapascals.

Answer:

a) 0m

b) 6m

Explanation:

First, we need to remember:

Displacement: Difference between final and initial position.

Distance traveled: Total distance traveled.

a) If the final position is the same as the initial position, then:

final position = initial position

And we know that:

displacement = final position - initial position = 0

Then the displacement of the book is zero.

b)

We can assume that the book traveled along the perimeter of the table.

The table is a rectangle of width 1.2m and length 1.8m

Remember that for a rectangle of width W and length L, the perimeter is:

P = 2*L + 2*W

Then the perimeter of the table is:

P = 2*1.2m + 2*1.8m = 6m

This means that the distance traveled by the book is 6 meters.

Answer:

longitudinal wave

i guess

sry if its wrong

Answer:

Uniformly accelerated rectilinear motion (MRUA), also known as uniformly varied rectilinear motion (MRUV), is one in which a mobile moves along a straight path being subjected to a constant acceleration.

Explanation:

Answer:

A) v_{f1} = -3.2 m / s,  B) LEFT , C) v_{f2} = -0.12 m / s,  D) LEFT

Explanation:

This is a collision exercise that can be solved using momentum conservation, for this we define a system formed by gliders, so that the forces during the collision are internal and the moment is conserved.

Let's use the subscript 1 for the lightest glider m1 = 0.160 kg and vo1 = 0.820 m / s

subscript 2 for the heaviest glider me² = 0.820 kg and vo2 = -2.27 m / s

Initial instant. Before the crash

          p₀ = m₁ v₀₁ + m₂ v₀₂

Final moment. After the crash

          p_f = m₁ v_{f1} + m₂ v_{f2}

          p₀ = p_f

          m₁ v₀₁ + m₂ v₀₂ = m₁ v_{f1} + m₂ v_{f2}

 as the shock is elastic, energy is conserved

         K₀ = K_f

         ½ m₁ v₀₁² + ½ m₂ v₀₂² = ½ m₁ \(v_{f1}^2\) + ½ m₂ \(v_{f2}^2\)

         m₁ (v₀₁² - v_{f1}²) = m₂ (v_{f2}² -v₀₂²)

let's make the relationship

         (a + b) (a-b) = a² -b²

         m₁ (v₀₁ + v_{f1}) (v₀₁-v+{f1}) = m₂ (v_{f2} + v₀₂) (v_{f2} -v₀₂)

let's write our two equations

         m₁ (v₀₁ -v_{f1}) = m₂ (v_(f2) - v₀₂)                                  (1)

         m₁ (v₀₁ + v_{f1}) (v₀₁-v_{f1}) = m₂ (v_{f2} + v₀₂) (v_{f2} -v₀₂)

we solve

         v₀₁ + v_{f2} = v_{f2} + v₀₂

we substitute in equation 1 and obtain

         M = m₁ + m₂

         \(v_{f1} = \frac{m_1-m_2}{M} v_o_1 + 2 \frac{m_2}{M} v_f_2\)

         \(v_f_2 = \frac{2m_1}{M} v_o_1 + \frac{m_2-m_1}{M} v_o_2\)vf2 = 2m1 / mm vo1 + m2-m1 / mm vo2

we calculate the values

         m₁ + m₂ = 0.160 +0.3000 = 0.46 kg

         v_{f1} = \(\frac{ 0.160 -0.300} {0.460} \ 0.820 + \frac{2 \ 0300}{0.460} \ (-2.27)\)

         v_{f1} = -0,250 - 2,961

          v_{f1} = - 3,211 m / s

         v_{f2} = \(\frac{2 \ 0.160}{0.460} \ 0.820 + \frac{0.300 - 0.160}{0.460 } \ (-2.27)\)

         v_{f2} = 0.570 - 0.6909

         v_{f2} = -0.12 m / s

now we can answer the different questions

A) v_{f1} = -3.2 m / s

B) the negative sign indicates that it moves to the left

C) v_{f2} = -0.12 m / s

D) the negative sign indicates that it moves to the LEFT

The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.

To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.

The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.

Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).

To calculate the area, we can break it down into two separate integrals:

1. The area above the x-axis (forward motion):

Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:

Area1 = velocity * time = 20 m/s * 4 s = 80 m

2. The area below the x-axis (backward motion):

The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:

Area2 = velocity * time = -10 m/s * 1 s = -10 m

To find the total distance traveled, we add the absolute values of the areas:

Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m

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