Answer:
answer is B
Explanation:
what are advantages of using sinusoidal Voltages
Answer:
The advantages of using a pure sine wave for your appliances and machinery are as follows: Reduces electrical noise in your machinery.
translates to no TV lines and no sound system hum.
Cooking in microwaves is quicker.
Explanation:
The smoothest signal is a sine wave, and sine waves are the basis of all functions.
Every other continuous periodic function is a basis function, which means that it can be described in terms of sines and cosines.
For instance, using the Fourier series, I can describe the fundamental Sinusoidal frequency and its multiples in terms of the triangle and square waves.
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
(6) effects of urbanization on the urban hydrology
Answer:
123456
Explanation:
Who uses management information systems?
A) employee-level workers
B) supervisors
C) middle-level managers
D) top-level managers
Management information systems (MIS) are used by all levels of management, including employee-level workers, supervisors, middle-level managers, and top-level managers. MIS can be used to track and manage data, automate tasks, and make decisions.
Here are some examples of how MIS can be used by different levels of management:
Employee-level workers: Employee-level workers can use MIS to track their own productivity, manage their time, and communicate with other employees.
Supervisors: Supervisors can use MIS to track the productivity of their team, identify areas for improvement, and make decisions about resource allocation.
Middle-level managers: Middle-level managers can use MIS to track the performance of their department, identify trends, and make decisions about strategic planning.
Top-level managers: Top-level managers can use MIS to track the performance of the entire organization, identify opportunities for growth, and make decisions about strategic direction.
MIS can be a valuable tool for all levels of management. By using MIS, managers can make better decisions, improve efficiency, and achieve their goals.
Here are some of the benefits of using MIS:
Improved decision-making: MIS can provide managers with the data they need to make better decisions.
Increased efficiency: MIS can help managers to automate tasks and improve efficiency.
Improved communication: MIS can help managers to communicate with other employees and stakeholders.
Increased productivity: MIS can help managers to increase productivity by tracking and managing data.
Improved customer service: MIS can help managers to improve customer service by tracking customer interactions and providing feedback.
Reduced costs: MIS can help managers to reduce costs by automating tasks and improving efficiency.
Overall, MIS is a valuable tool that can be used by all levels of management to improve the performance of an organization.
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On axonometric projection, all lines indicating height, width, and depth remain:
a. Parallel.
b. Perpendicular.
c. Convergent.
d. Divergent.
On axonometric projection, all lines indicating height, width, and depth remain parallel.
In axonometric projection, which is a type of orthographic projection, the lines representing the three dimensions (height, width, and depth) of an object are drawn parallel to each other. This means that regardless of the distance or position of an object in relation to the viewer, the lines representing its dimensions do not converge or diverge.
Axonometric projection is commonly used in technical and architectural drawings to accurately represent three-dimensional objects on a two-dimensional surface. By keeping all lines parallel, it provides a consistent and proportional representation of the object's dimensions.
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Which do you think would cause the most destruction to the organisms in a food web: taking away the carnivores, taking away the herbivores, taking away the producers or taking away the decomposers? Use evidence from your Food Web diagram above to support your claim.
Answer:
Explanation:
I do not have access to your diagram but based on what I know, a food web cannot sustain itself without decomposers. They are the main guys who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow. So if decomposers are not there then producers cannot produce and thus herbivores cannot live and carnovers die out as well. Hope this makes sense.
Check out: https://www.nationalgeographic.org/encyclopedia/decomposers/
A food web cannot sustain itself without decomposers. They are the main components who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow.
What are decomposers?Decomposers are living organisms like fungi and bacteria. These decomposers are heterotrophic which means they must take the nutrients and it cannot make its own food. Decomposers play an eminent role in an ecosystem because of their process of nutrition.
They break down the dead plants and the animals. These break down the waste of the organisms. They are very eminent for all the ecosystem. If these were not in the ecosystem, the plants cannot get essential nutrients, dead matter and waste would deposit. So the nutrients in them gets recycled back so that they can be used again.
When fish dies, there is nothing which is ingested and the bladder air starts to release, which causes the fish to sink to the bottom. After few days, the internal organs of the dead fish gets decomposed, after which a gas is formed.
Therefore, A food web cannot sustain itself without decomposers.
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1.3
A tensile load of 50,000 lb is applied to a metal bar with a 0.6 in. x 0.6 in.
cross section and a gauge length of 2 in. Under this load, the bar elastically
deforms so that the gauge length increases to 2.007 in. and the cross section
decreases to 0.599 in. x 0.599 in. Determine the modulus of elasticity and
Poisson's ratio for this metal.
Answer:
modulus =3.97X10^6 Ib/in^2, Poisson's ratio = 0.048
Explanation:
A 75-hp motor that has an efficiency of 91.0% is worn-out and is replaced by a motor that has a high efficiency 75-hp motor that has an efficiency of 95.4%. Determine the reduction in heat gain in the room due to higher efficiency under full-load conditions (load factor
Answer:
the reduction in the heat gain is 2.8358 kW
Given that;
Shaft outpower of a motor = 75 hp = ( 75 × 746 ) = 55950 W
Efficiency of motor = 91.0% = 0.91
High Efficiency of the motor = 95.4% = 0.954
now, we know that, efficiency of motor is defined as; = /
where is the electric input given to the motor
so
= /
we substitute
= 55950 W / 0.91
= 61483.5 W
= 61.4835 kW
now, the electric input given to the motor due to increased efficiency will be;
= /
we substitute
= 55950 W / 0.954
= 58647.79 W
= 58.6477 kW
so the reduction of the heat gain of the room due to higher efficiency will be;
Q = -
we substitute
Q = 61.4835 kW - 58.6477 kW
Q = 2.8358 kW
Therefore, the reduction in the heat gain is 2.8358 kW
Explanation: i hope this answer your question if this is wrong or correct please let me know.also no trying to be rude but can you sent me like a thanks?
1. A thin-walled cylindrical pressure vessel is capped at the end and is subjected to an internal pressure (p). The inside diameter of the vessel is 6 ft and the wall thickness is 1.5 inch. The vessel is made of steel with tensile yield strength and compressive yield strength of 36 ksi. Determine the internal pressure required to initiate yielding according to (a) The maximum-shear-stress theory of failure, and (b) The maximum-distortion-energy theory of failure, if a factor of safety (FS) of 1.5 is desired.
a pressure cooker is a pan that cooks food much faster than ordinary pans by maintaining a higher pressure and temperature during cooking. the pressure inside the pan is controlled by a pressure regulator (the petcock) which keeps the pressure at a constant level by periodically allowing some steam to escape, thus preventing any excess pressure buildup. a certain pressure cooker has a volume of 6 l and an operating pressure of 75 kpa gage. initially, it contains 1 kg of water. heat is supplied to the pressure cooker at a rate of 500 w for 30 min after the operating pressure is reached. assuming an atmospheric pressure of 100 kpa, determine: a) the temperature at which cooking takes place. b) the amount of water left in the pressure cooker at the end of the process. assume some liquid water is still in the pan.
More cooking is done before the water actually begins to boil thanks to the raised pressure inside the cooker, which raises the boiling point of water above 1000C. In the end, food cooks more quickly.
Slow-cooked meals can be quickly prepared with pressure cookers. They are efficient in terms of electricity consumption and are excellent for tenderizing less expensive portions of meat. They are a healthy cooking method since they effectively retain nutrients and can cut cooking times by up to 50%. Water boils at 121°C (250°F) at that pressure. As a result, food may cook at considerably greater temperatures than it could under atmospheric pressure. Additionally, because cooking reactions quicken at higher temperatures, food cooks more quickly it is a good technology.
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4. a. A family purchased a 3 acre piece of land in Limuru for Kshs.30,000,000.00 fifteen years ago. They planted trees at a cost of Kshs.250,000.00 per acre. Each year they have been spending on average Kshs.25,000.00 per acre per month to take care of the trees and also to secure the property. They are now considering selling it. What is the minimum amount they should accept so as not to incur a loss bearing in mind that comparable properties have been yielding a rate of 6.5% interest per annum? (8 marks)
b. “Compulsory acquisition is the power of government to acquire private rights in land for public good without the willing consent of the owner but; in exchange for compensation”. Discuss this statement with special reference to the main considerations that ought to be made in conducting a valuation for compulsory acquisition. (12 marks)
The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.
Why should they accept this amount and why?To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.
Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.
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The UHRS platform is optimized for Edge/Internet Explorer only. You can still use your favorite browser, but keep in mind that you may experience technical issues when working on UHRS with a different browser than Edge or Internet Explorer.
UHRS is optimized for...
It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.
What is a UHRS?The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.
Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.
A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.
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For the beam loaded as shown in Fig Q2a. perform the following task:
Calculate the support reactions at A and E;
(i)
Draw the shear force diagram for the beam showing all important
values;
>
(iii)
Draw the bending moment diagram for the beam showing all
important values.
6 kN
10 KN
2 kN/m
B
D
1 m
1 m
1 m
1 m
Answer:
a
Explanation:
aaaaaa
what is a computer device
If a construction company is considering a new type of material to use in their construction, which factors would they
focus on? (Select all that apply.)
that the new material does the same thing as an existing material but better
that the new material does the same thing as an existing material but cheaper
that the science behind the material be familiar to and understood by its employees
that the properties of the new material meet their construction needs
I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.
Consider a simple ideal Rankine cycle and an ideal regenerative Rankine cycle with one open feedwater heater. The two cycles are very much alike, except the feedwater in the regenerative cycle is heated by extracting some steam just before it enters the turbine. Hence, the simple ideal Rankine cycle is more efficient than the ideal regenerative Rankine cycle. How would you compare the efficiencies of of these two cycles?
Answer:
They both have the same efficiency.
Explanation:
The simple ideal Rankine cycle and an ideal regenerative Rankine cycle with one open feedwater heater would both have the same efficiency because the extraction steam would just create a mini cycle that recirculates. The energy given to the feedwater heater is proportional to the added heat in the boiler to the feedwater in the simple cycle to raise its temperature to the same boiler inlet condition.
Therefore in comparison, the efficiency is the same for both.
Consider a 2.4-kW hooded electric open burner in an area where the unit costs of electricity and natural gas are $0.10/kWh and $1.20/therm (1 therm = 105,500 kJ), respectively. The efficiency of open burners can be taken to be 73 percent for electric burners and 38 percent for gas burners. Determine the rate of energy consumption and the unit cost of utilized energy for both electric and gas burners.
Answer:
1.75 kW
$0.137 kWh
4.61 kW
$3.16 therm
Explanation:
Utilized power input of the burner is
P(ui) = total power input * efficiency
P(ui) = 2400 W * 0.73
P(ui) = 1752 W or 1.75 kW
Unit cost of utilized energy is
C(ui) = Unit cost of electricity/efficiency
C(ui) = $0.1 / 0.73 kWh
C(ui) = $0.137 kWh
Power input to the gas burner is
P(gi) = Utilized power input of the burner / efficiency of the burner
P(gi) = 1.75 / 0.38
P(gi) = 4.61 kW
Unit cost of utilized energy is
C(gi) = Unit cost of gas /efficiency
C(gi) = $1.2 / 0.38 kWh
C(gi) = $3.16 therm
Shear stress t produces a shear strain Yxy (be- tween lines in the x direction and lines in the y direction) of Yxy 1200 u (i.e., y = 0.0012 m). (a) Determine the horizon- tal displacement da of point A. (b) Determine the shear strain Yx'y between the lines in the x' direction and the y' direction, as shown on Fig. P2.7-12. y δ, τ A τ 120 mm T y' 150 mm
A) The horizontal displacement of point A is 0.144 mm. B) The shear strain Yx'y between the lines in the x' direction and the y' direction is 0.00096 m.
What is shear strain?Shear strain is a type of deformation caused by a force applied to an object. It occurs when two opposite parallel forces are applied in opposite directions, causing the object to elongate in one direction and compress in the other. Shear strain is different from tensile strain, which happens when a force is applied in one direction only.
(a) The horizontal displacement of point A due to the shear stress τ is given by the equation da = τYxy. Substituting the given values, we obtain da = τ(0.0012 m) = (120 N/mm2)(0.0012 m) = 0.144 mm.
(b) The shear strain Yx'y between the lines in the x' direction and the y' direction is given by the equation Yx'y = da/δ', where δ' is the distance between the lines in the x' direction. Substituting the given values, we obtain Yx'y = (0.144 mm)/(150 mm) = 0.00096 m.
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The fracture strength of glass may be increased by etching away a thin surface layer. It is believed that the etching may alter the surface crack geometry (i. E. Reduce crack length and increase tip radius). Calculate the ratio of the etched and original crack tip radii if the fracture strength is increased by a factor of 4 when 63. 0% of the crack length is removed
Therefore, the difference between the original crack tip radius and the etched crack tip radius is 0.37.
The stress intensity factor (K), a measurement of the stress at a crack's tip, and a material's fracture strength are connected. Reducing the crack length and increasing the crack tip radius can increase a material's fracture strength, according to the stress intensity factor theory.
A reduction in the crack length of 1 - 0.63 = 0.37 is indicated by the removal of 63.0% of the crack length. Given that the fracture tip radius has presumably widened correspondingly, we can write:
Y1 * σ * √π * R1 = 4 * Y2 * σ * √π * R2
Dividing by Y2 * σ * √π, we get:
R1 / R2 = 4 * Y2 / Y1
R2 = R1 * (1 - 0.63) = R1 * 0.37
R1 / (R1 * 0.37) = 4 * Y2 / Y1
Dividing both sides by R1, we get:
1 / 0.37 = 4 * Y2 / Y1
R2 / R1 = 0.37 / 1 = 0.37
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A series of books was published at 10years intervals when the 10th book was issued the sum of publication years was 19,560 when was the 1st book published
Let's denote the publication year of the first book by x. Then the publication year of the second book is x + 10, the publication year of the third book is x + 20, and so on.
Since the sum of publication years of all ten books is 19,560, we can write the equation:
x + (x + 10) + (x + 20) + ... + (x + 90) = 19560Simplifying this equation, we get:
10x + (10 + 20 + ... + 90) = 1956010x + 450 = 1956010x = 19110x = 1911Therefore, the first book was published in 1911.
Tru or false A tractor is experiencing a reduction in pressure the amount of force this will result in decreasing the Propulsion of the tractor
Answer:
true
Explanation:
i took the test and got it right
Anyone help me please ?
Answer:
I can help but I need to know what it looking for
what is the direct current generator
Answer:
A direct-current (DC) generator is a rotating machine that supplies an electrical output with unidirectional voltage and current.
Explanation:
Hope this helps
factor to consider whe choosing business enviroment
Answer:
The six external factors affecting a business are technological, economic, social, cultural, political, and competitors
5. The maximum scaffold height not requiring toeboards is 20 feet.
A. True
B. False
the institute of electrical and electronics engineers is responsible for standards in which two areas? (choose two.)
IEEE is responsible for standards in the areas of electrical and electronics engineering.
What is engineer?
Engineers are professionals who create, design, analyse, construct, test, and evaluate machines, complex systems, structures, gadgets, and materials to satisfy functional objectives and requirements while taking into account the practicality, regulation, safety, and cost constraints. The Latin words ingeniare as well as ingenium are the origin of the English word engineer. A four-year bachelor's degree in engineering, or in some jurisdictions, a master's degree in engineering, along with four to six years of peer-reviewed professional practise, and passing the engineering board examinations make up the fundamental requirements for becoming an engineer. A person who is registered with an engineering council is typically considered a professional engineer. The link between scientific advancements as well as their subsequent applications to meet the needs of people and businesses and improve quality of life is formed by engineers' work.
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For a simply supported beam with a non-centered point loading, where would the approximate location of the maximum deflection be?
Answers Options:
at the end of the beam length
between the farther support and the load
at the center of the beam
between the closer support and the load
The maximum deflection for a simply supported beam with a non-centered point loading would be at the center of the beam. (option C)
What is the explanation for the above?When the point load is also at the mid-span, the absolute maximum deflection occurs. And it equals P l 3 48 E I. As a result, the distance between point 'P' and the right end for maximum deflection is equal to L/2, i.e. a = L/2.
Typically, support beams are built of wood, steel, or concrete. Among the numerous support, beams are: Cantilever - This beam only has an anchor at one end, leaving the other end unattached and swinging free. This beam is fixed because it is attached on both ends and will not rotate or move at the fulcrum.
The other types of beams are: simply supported beams, overhanging beams, fixed beams, and continuous beams.
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Hey guys can anyone list chemical engineering advancement that has been discovered within the past 20 years
engineering controls can be utilized as one element of hazard control
Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source.
Engineering controls are a type of hazard control that reduces or eliminates the hazard at its source. Engineering controls are used to minimize or eliminate hazards that pose a significant risk of harm or danger to individuals, such as chemical or noise exposure.
These measures are frequently a vital component of an effective occupational health and safety program in the workplace. Examples of engineering controls include the use of ventilation to control fumes, dust, and other airborne hazards, as well as the use of sound barriers to reduce noise levels. In addition, the use of machine guards, interlocks, and other safety devices on equipment and machinery is considered a form of engineering control to safeguard workers from contact with hazardous moving parts.
Other types of engineering controls include changes in the manufacturing process or the substitution of less harmful materials to eliminate the hazard. Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source. These controls, when combined with other forms of hazard control, such as administrative and personal protective equipment, provide a comprehensive approach to worker safety and health.
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A soil sample, taken from a borrow pit has a specific gravity of soil solids of 2.66. The sample was taken to a materials laboratory and tested. The results of a standard Proctor test are tabulated below.
Weight of Soil (lb) Moisture Content (%)
3.20 12.8
3.78 13.9
4.40 15.0
4.10 15.7
3.70 16.6
3.30 18.1
The maximum dry density in lb/ft3 is most nearly:_______
Answer:
115 Ib/ft^3
Explanation:
To determine the maximum dry density in Ib/ft3 we have to calculate :
Bulk unit weight ( yb ) ; W / v
Dry unit weight ( yd. ) : yb / ( 1 + w )
For every set of data given
assuming v = 1/30 ft^3
calculating for the 3 data set ( maximum dry density )
weight of soil (W) = 4.40
moisture content (%) (w) = 15.0 = 0.15
Bulk unit weight (yb) = 4.40 / (1/30) = 132 Ib/ft^3
Dry unit weight ( yd. ) = 132 / ( 1 + 0.15 ) = 114.702 Ib/ft^3
therefore after calculations the maximum dry density in Ib/ft^3 ≈ 115 Ib/ft^3