A line in the hydrogen spectrum has a wavelength of 6564A°.
Let's take the Balmer series into consideration when determining the wavelength of a line in the hydrogen spectrum.
Then the hydrogen line spectra equation can be given as,
wave number = R[(1/(n₁²) - (1/(n₂²)]
where the first energy level in the Balmer series is n₁ .The higher energy level in the Balmer series is n₂. The Rydberg constant is R, which equals 109677 cm⁻¹.
For the Balmer series, n₁ = 2 and n₂ = 3
Putting the values in above equation, then we get,
Wave number = 109677 [( 1/2² - 1/3² ) cm⁻¹]
Wave number= 109677 ( 1/4 - 1/9 ) cm⁻¹
Wave number= 109677 ( 5/36 ) cm⁻¹
Wave number= 15232.91 cm⁻¹
The reciprocal of wave number is wavelength thus we can write as,
wavelength = 1/wavenumber = (1 /15232.91)cm
As a result, a line in the hydrogen spectrum has a wavelength of 6564A°.
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3. A missile is launched at a speed of 39.2 m/s at an angle of 30° to the ground. What is its
range? How long does it take to reach its maximum height? How high did it go vertically?
Time which missile will take to reach its maximum height is 2 seconds. and The maximum height it will reach is 58.8.
What is the relation between time and acceleration?
The time, velocity and acceleration are related in such a way that time is directly proportional to velocity and time is inversely proportional to acceleration.
i.e. t = u/g
As given in the question,
Initial velocity (u) = 39.2 m/s, and angle is 30°
initial vertical velocity = 39.2 sin30° = 19.6 m/s
So, the time taken can be calculated by:
t = u/g
t = 19.6/9.8
t = 2 seconds.
and the maximum height can be calculated by equation:
\(h = ut + \frac{1}{2} at^2\)
\(h = 39.2 + \frac{1}{2} 9.8 (2)^2\)
\(h = 39.2 + 19.6\)
h = 58.8 m
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1. At what displacement the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm?
The displacement at which the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm is 1.5cm.
How does the amplitude of simple harmonic motion affect the ratio of kinetic to potential energy at a specific displacement?The amplitude of simple harmonic motion affects the ratio of kinetic to potential energy at a specific displacement in the following way: as the amplitude increases, the ratio of kinetic to potential energy decreases. This is because the amplitude represents the maximum displacement from the equilibrium position, and as the amplitude increases, the potential energy of the particle increases, while the kinetic energy remains constant. Therefore, at a specific displacement, a particle with a larger amplitude will have a greater proportion of its energy in the form of potential energy, while a particle with a smaller amplitude will have a greater proportion of its energy in the form of kinetic energy.
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ANSWERED: Which action will cause the induced current to decrease or remain constant?
*zoom in answer to remove computer lines*
Answer:
Reversing the polarity of the magnet
Explanation:
The action that will cause the induced current to decrease or remain constant is "reversing the polarity of the magnet"
To reverse the polarity, a battery and coil of copper can be used. Reversing the polarity of the magnet will also cause the induced current to reverse in direction. The polarity of the magnet actually determines the direction of the electromagnetic force.
Voltage
Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above
Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.
According to the Ohm's Law, the current through a conductor between two points is directly proportional to the voltage across the two points.
Mathematically,
V ∝ I
V = IR
where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.
Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.
Hence All of the above option in the given question are true.
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2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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an aircraft with a landing speed of 295km/h lands on an aircraft carrier with a landing area 205m long. find the minimum constant decleration required for a safe landing
Answer:
20.38 m/s^2 deceleration
Explanation:
295 km/hr = 91.94 m/s
v goes from 91.94 to 0 average v = 40.97 m/s
d = vt
205 = 40.97 t t = 5 seconds
d = vo t - 1/2 a t^2
205 = 91.94 ( 5) - 1/2 (a)(5^2)
a = 20.38 m/s^2 (DECELERATION)
1) Determine the magnitude of energy for each of the blanks on the diagram. Give the correct values for 1A, 1B, and 1C.
2)Explain how the energy transformations follow the Law of Conservation of energy throughout the skier's path. Must answer in complete sentences.
3)Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the terms kinetic energy, heat energy, mechanical energy, total energy and friction. Must answer in complete sentences.
Answer:
Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789
The total energy at each point in the path of the skier is constant as the
skier travels down the slope.
1) 1A P.E. = 15,000 J, 1B K.E. = 19,000 J, 1C, P.E. = 0 J2) The mechanical energy of the system is constant3) Energy is given off as heat due to friction such that the total energy of the system is not conserved if friction is experiencedReasons:
1) Given that the total mechanical energy, M.E. is constant, we have;
M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant
M.E. = K.E. + P.E.
At the start, we have;
P.E. = 25,000 J
K.E. = 0 J
Therefore;
M.E. = 25,000 J + 0 J = 25,000 J
At point 1A, we have, K.E = 10,000 J
P.E. = M.E. - K.E.
Therefore;
P.E. = 25,000 - 10,000 = 15,000
The potential energy at point 1A, P.E. = 15,000 J
At point 1B, we have; PE = 6000 J
K.E. = M.E. - P.E.
Therefore;
K.E. = 25,000 J - 6,000 J = 19,000 J
At 1B, K.E. = 19,000 J
At point 1C, we have; K.E. = 25,000 J
Therefore;
P.E. = 25,000 J - 25,000 J = 0 J
At 1C P.E. = 0 J
2) The Law of Conservation of Energy states that the energy in a closed
system is constant.
The energy transformation follows the Law of Conservation of energy
given that the total mechanical energy is constant at all points along the
path.
3) The energy of a system is not conserved when a external force is
applied.
If the skier experiences friction, the force of friction does work to reduce
the speed of the skier, thereby reducing the kinetic energy at a point
downslope, where the potential energy has already been reduced,
resulting in an reduction in the mechanical energy of the system.
Therefore, if the skier experiences friction, the total energy of the system is
not conserved, as energy will be consumed in the work done by friction
which is converted to heat and sound energies.
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two pictures show friends playing with a string telephone. in which picture can they hear each other
Answer:
In picture one because string telephones are best heard when there is more tension on the string
Explanation:
Two identical point charges of +Q coul are separated by a distance of 10 cm.
(a) Calculate the work done per unit change to bring up another charge from far
away along the perpendicular bisector of the line joining the two charges to
the point point midway between the charges.
(b)If one of the two charges in part(a) is changed from +Q to –Q, calculate the
work done per unit charge to bring up a charge to the same position as
above.
Answer:
IM NOT SMART
Explanation:
A candle is sitting in front of a concave mirror at a distance of 12.2 cm. It is found that an image of the candle appears at 25.0 cm. What is the focal length of the mirror?
3.52 cm
8.20 cm
10.4 cm
22.1 cm
The focal length of the concave mirror is approximately option B. 8.20 cm,
To solve this problem, we can use the mirror equation, which relates the object distance (d_o), image distance (d_i), and the focal length (f) of a concave mirror. The equation is:
1/f = 1/d_o + 1/d_i
Given the object distance (d_o) is 12.2 cm and the image distance (d_i) is 25.0 cm, we can plug in these values to find the focal length (f):
1/f = 1/12.2 + 1/25.0
To solve for f, first find the common denominator and combine the fractions:
1/f = (25 + 12.2) / (12.2 * 25) = 37.2 / 305
Now, take the reciprocal of both sides to isolate f:
f = 305 / 37.2
After calculating, we get:
f ≈ 8.20 cm
Thus, the focal length of the concave mirror is approximately 8.20 cm, Therefore the correct option to option b.
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Can someone please help me with this one
Answer:
im pretty sure the answer is A. up but im not 100% sure
What wavelength of light (in nm) is associated with a frequency of 5.72 E14 Hz
Answer: 520 nm; 5.77 × 1014 Hz; 3.82 × 10−19 J
Your ability to process language in the left hemisphere of the brain and spatial in the right hemisphere of the brain is called
Answer: Parietal lobe
Explanation: The parietal lobe controls the ability to read, write, and understand spatial concepts. Therefore, you gain the ability to process language through the left hemisphere of your brain.
Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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Discuss the similarities and differences between the electrical force on a charge and the magnetic force on a charge.
Explanation:
Both are field dependent. Electric force is dependent on charge, while Magnetic force is dependent on current or rate of charge flow
A light, inextensible cord passes over alight, frictionless pulley with a radius of15 cm. It has a(n) 18 kg mass on the left and a(n) 2.6 kg mass on the right, both hanging freely. Initially their center of masses are a vertical distance 1.5 m apart.The acceleration of gravity is 9.8 m/s².
At what rate are the two masses accelerating when they pass each other answer in units of m/s^2
Answer:
quizlet
Explanation:
they help
If the error in the angle is 0.50, the error in sin 90° is
The error in the measurement of sin 90 degrees at the given error in angle is 0.001.
Error in measurementThe error in measurement is obtained from the difference between the actual measurement and the observed measurement.
The error of sin 90 degrees is calculated as follows;
Actual measurement = sin 90 = 1
Observed measurement = sin(90 - 0.5)
Observed measurement = sin(89.5) = 0.999
Error in measurement of sin 90 degreesError in measurement = Actual measurement - Observed measurement Error in measurement = 1 - 0.999
Error in measurement = 0.001
Thus, the error in the measurement of sin 90 degrees at the given error in angle is 0.001.
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HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.70 m below. Calculate the velocity (in m/s) of the fish just before it hits the water. (Assume that the eagle is flying in the x direction and that the y direction is up.)
Answer:
Explanation:
The fish will have horizontal velocity of 2.6 m/s which is also the velocity of eagle. Additionally , he will have vertical velocity due to fall under gravity .
v² = u² + 2 g H .
v² = 0 + 2 x 9.8 x 4.7 m
= 92.12
v = 9.6 m /s
The fish's final velocity will have two components
vertical component = 9.6 m/s downwards
Horizontal component = 2.6 m /s .
Resultant velocity = √ ( 9.6² + 2.6² )
= √ ( 92.16 + 6.76 )
= 9.9 m /s
Answer:
The speed of fish at the time of hitting the surface is 9.95 m/s.
Explanation:
Horizontal speed, u = 2.6 m/s
height, h = 4.7 m
Let the vertical velocity at the time of hitting to water is v.
Use third equation of motion
\(v^2 = u^2 - 2 gh \\\\v^2 = 0 + 2 \times 9.8\times 4.7\\\\v = 9.6 m/s\)
The net velocity with which the fish strikes to the water is
\(v' = \sqrt{9.6^2 + 2.6^2 }\\\\v' = 9.95 m/s\)
100=50a
find acceleration
Fnet =ma
The answer is\(2ms^{-2}\).
we know that
Force can be calculated by: F=ma
F=>total force
m=>mass of the object
a=> acceleration
by observing the given data we can say
F=100
m=50
a=?
so we can find the value by using
a=F/m
=100/50
=2
So the answer is \(2ms^{-2}\).
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B (B=26.5)
56.0%
A (A = 44.0)
28.0°
C(C=31.0)
< 1 of 1 >
Part A
Given the vectors A and B shown in the figure ((Figure 1)), determine the magnitude of B-A
Express your answer using three significant figures.
195] ΑΣΦ
|B-A =
Determine the magnitude of B-A is 53.68
1.4
Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.
Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.
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Two thin parallel conducting plates are placed 2.0 cm apart. Each plate is 2.0 cm on a side; one plate carries a net charge of 8.0μC, and the other plate carries a net charge of −8.0μC. What is the charge density on the inside surface of each plate? What is the electric field between the plates?
Gauss's law and charges of the same sign repel allows us to find the results for the questions about the charged plates are:
The charge inside the plates is zero.The field in the middle of the plates is: E = 2.26 10⁶ N/CGauss's law.Gauss's law says that the electric flux through a Gaussian surface is proportional to the charge inside it.
Ф = ∫ E . dA = \(\frac{q_{int}}{\epsilon_o } \)
where Ф is the flux, E the electric field, A the area, \(q_{int}\) the charge inside the surface.
They indicate that we have two metallic plates with a charge of 80 μC = 80 10⁻⁶ C in each one, since the plate is metallic, the electrons are free to move in it and repel each other, therefore the ones that are farthest from each other are placed, this is concentrated on the surface of the metal plate, therefore the charge inside the surface is zero.
Let's use Gauss's law to find the electric field, we define a Gaussian surface with a cylinder base parallel to the plate, in this case the field created by the charge is parallel to the normal of the surface of the plates.
2 E A = \(\frac{q_{int}}{\epsilon_o} \)
The two comes from the fact that the electric field is emitted towards both sides of the plate.
The charge density on each plate is:
σ = q A
Let's substitute.
E A = \(\frac{\sigma A}{2 \ \epsilon_o} \)
The electric field is a vector magnitude, so vector addition must be used, see attached for the direction of the electric field.
\(R_{total} = E_1+E_2\)
\(E_{total} = \frac{\sigma}{\epsilon_o} \)
Let's calculate.
The charge density.
\(\sigma = \frac{q}{l^2} \)
\(\sigma = \frac{ 80 \ 10^{-6} } { 2.0 \ 2.0}\)
σ = 20 10⁻⁶ C
The total electric field.
E = \(\frac{20 \ 10^{-6} }{8.85 \ 10^{-12} } \)
E = 2.26 10⁶ N/C
In conclusion, using Gauss's law and that charges of the same sign repel each other, we can find the result for the questions about the charged plates:
The charge inside the plates is zero.The field in the middle of the plates is: E = 2.26 10⁶ N/CLearn more about Gauss's law here: brainly.com/question/15175106
Please help
4. What are the lowest points on a transverse wave called?
a. Crests
b. troughs
C. compressions
d. rarefractions
5. Any substance that a wave moves through is called a
a. medium
b. vibrate
C. crest
d. frequency
Answer:
Explanation:
the lowest points of a transverse wave are called the troughs what is the wavelength of a wave traveling through a rope if the distance from one crest to the next is 1 meter a. 2 m
4. Low points are called troughs
5. Medium: substance through which a wave can travel
A toy uses a spring to shoot an arrow with a suction cup on the end. The toy shoots a 34.2 g arrow and gives it a speed of 5.50 m/s. If the efficiency of the toy is 69.0%, how much elastic potential energy was stored in the spring? Show all your work.
Answer:
0.750 J
Explanation:
69% of the elastic energy is converted to kinetic energy.
0.69 EE = KE
0.69 EE = ½ mv²
EE = mv² / 1.38
EE = (0.0342 kg) (5.50 m/s)² / 1.38
EE = 0.750 J
Help asap pls. Which of the following best describes how high and low pitch are different?
A) A high-pitched sound has a high amplitude and a low-pitched sound has a low amplitude.
B) A high-pitched sound is loud while a low-pitched sound is quiet.
C) A person is close to a high-pitched sound and far away from a low-pitched sound.
D) A high-pitched sound has a high frequency and a low-pitched sound has a low frequency.
A tree limb is blown loose from a tree during a storm. As it falls, it gains
speed. Which type of energy is the tree limb gaining as it falls?
O A. Kinetic energy
B. Gravitational potential energy
O C. Nuclear energy
OD. Light energy
Answer:
B Gravitational potential energy
Explanation:
Make one comparison between the moral condition of the world at the time of the Flood with our day. Only One Short explanation.
The moral condition of the world today appears to be worse than it was in the antediluvian era.
The biblical account of the flood records that the world delved into apostasy in the days of Noah so much so that God regretted the fact that he created man. Some of the evils of the antediluvian world include; sodomy, drunkenness, lewdness and several forms of immorality.
We can see that these vices that led to the destruction of the world due to moral bankruptcy in the antediluvian era is still very much prevalent in our world today. The moral condition of the world today appears to be worse than it was in the antediluvian era.
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Consider a system of two charges of magnitude 2 × 10-7 C and 4.5 × 10-7 C which is acted upon by a force of 0.1 N. What is the distance between the two charges?
To find the distance between two charges, we can use Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The formula for Coulomb's law is:
F = (k * |q1| * |q2|) / r^2
where:
F is the force between the charges,
k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges.
Given:
|q1| = 2 × 10^-7 C
|q2| = 4.5 × 10^-7 C
F = 0.1 N
k = 8.99 × 10^9 N m^2/C^2
We can rearrange the equation to solve for r:
r^2 = (k * |q1| * |q2|) / F
Plugging in the values:
r^2 = (8.99 × 10^9 N m^2/C^2 * 2 × 10^-7 C * 4.5 × 10^-7 C) / 0.1 N
r^2 = (8.99 × 2 × 4.5) * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * 10^(-7 + 9 - 1)
r^2 = 80.91 * 10^1
r^2 = 809.1
Taking the square root of both sides:
r = √809.1
r ≈ 28.46
Therefore, the distance between the two charges is approximately 28.46 units.
How many Hydrogens are present on the Products side?
Answer:
two H atoms
Explanation: