to find the mass number you add the protons + the electrons
true or false ​

Molecules have sufficient kinetic energy to overcome the intermolecular forces in the liquid. So option B is correct.

Molecules of a liquid can pass into the vapor phase provided that the molecules have adequate kinetic energy to beat the intermolecular powers in the fluid.

This happens when the temperature of the fluid is close to its edge of boiling point, and the vapor tension of the fluid is high. The surface pressure of the fluid affects the vaporization cycle.

So, the correct option is b) "molecules have sufficient kinetic energy to overcome the intermolecular forces in the liquid."

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by rounding them to the neerest 10

Answer:

Specific heat, ratio of the quantity of heat required to raise the temperature of a body one degree to that required to raise the temperature of an equal mass of water one degree.

Explanation:

by dividing the heat capacity by the quantity of substance in a body, the resulting specific heat capacity is a function of the structure of the substance itself. In particular, it depends on the number of degrees of freedom that are available to the particles in the substance, each of which type of freedom allows substance particles to store thermal energy.

Answer:

Explanation:

percent yield is ratio of actual yield or experimental yield divided by theoretical yield multiplied by 100 .

percent yield of 93.4 % means , the actual yield is 93.4 % what was expected from the reaction on the basis of given chemical reaction .

If in the experimental process , some sodium hydrogen carbonate is left unreacted due to absence of reactant HCl which is also required to obtain product , the percent yield will be increased if the required HCl is also provided .

Hence the percent yield will be increased if required HCl is made available .

Paper chromatography is a technique used to separate a mixture into its component molecules. In this process, molecules migrate and move up the paper at different rates due to the differences in solubility, which results in varying levels of absorption onto the paper. By analyzing the position of each molecule on the paper, scientists can identify and separate the individual components of the mixture.

Paper chromatography is a highly effective technique used in scientific research to separate a mixture of different molecules into their individual components. This method relies on the fact that different molecules have varying degrees of solubility in a given solvent.

When a mixture is placed on a strip of paper and then dipped into a solvent, the solvent is drawn up the paper via capillary action. As the solvent moves up the paper, the different components of the mixture begin to separate out based on their unique solubility properties. Some components may be highly soluble and will be carried up the paper quickly, while others may be less soluble and will move more slowly.

This difference in solubility is what allows for the separation of the mixture into its individual components. Once the solvent has traveled a certain distance up the paper, the different components can be identified by their unique positions on the paper strip. Overall, paper chromatography is a powerful tool for separating and identifying different molecules based on their different solubility properties.

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The bonds in each of the following substances ionic, nonpolar covalent, or polar covalent: (a) KCl - Ionic bond, (b) P4 - Nonpolar covalent bond, (c) BF3 - Polar covalent bond. (d) SO2 - Polar covalent bond

(a) KCl: The bond between potassium (K) and chlorine (Cl) in KCl is an ionic bond. Ionic bonds form between atoms with significantly different electronegativities, resulting in the transfer of electrons from one atom to another.

In this case, potassium donates one electron to chlorine, forming the K+ cation and Cl- anion, resulting in an electrostatic attraction between them.

(b) P4: Phosphorus (P) exists as P4, where four phosphorus atoms are bonded together. The bond within P4 is a nonpolar covalent bond. Nonpolar covalent bonds occur between atoms with similar electronegativities, resulting in an equal sharing of electrons between them.

In P4, each phosphorus atom contributes one electron to form a covalent bond, resulting in a stable molecule.

(c) BF3: The bond in BF3, between boron (B) and fluorine (F), is a polar covalent bond. Polar covalent bonds form when there is an unequal sharing of electrons between atoms with different electronegativities.

In BF3, the fluorine atoms are more electronegative than boron, causing a partial negative charge on the fluorine atoms and a partial positive charge on the boron atom.

(d) SO2: The bond in SO2, between sulfur (S) and oxygen (O), is a polar covalent bond. Similar to BF3, the electronegativity difference between sulfur and oxygen results in an unequal sharing of electrons.

The oxygen atoms attract the electrons more strongly, resulting in a partial negative charge on the oxygen atoms and a partial positive charge on the sulfur atom.

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The theoretical yield of carbon dioxide is 333.7 g, and the percentage yield is 93.5%.

Percentage yield is used to measure the efficiency or effectiveness of a chemical reaction or process in producing the desired product.

Theoretical yield

From the equation of the reaction: 2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O

Mole ratio of C₂H₆ and CO₂ = 2:4 or 1:2

Mole of 114 g C₂H₆ = 114/30.07

= 3.79 moles

Equivalent mole of CO₂ = 3.79 x 2

= 7.58 moles

Theoretical yield of CO₂ = 7.58 x 44.01

= 333.7 g

If 312 g is actually produced;

Percent yield = yield/theoretical yield x 100%

= 312/333.7 x 100%

= 93.5%

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Your question is incomplete, most probably the full question is this:

A 114 g sample of ethane (C2H6) burns in excess oxygen.

2C2H6(g) + 702(g) → 4CO2(g) + 6H2O (

a.

What is the theoretical yield of carbon dioxide? (6 points)

b. If 312 g is actually produced, what is the percent yield? (6 points)

Answer:

Gas

Explanation:

Legend primordial element element by radioactive decay Atomic number color: red=gas

The menstrual cycle is regulated by hormones. Luteinizing hormone and follicle-stimulating hormone, which are produced by the pituitary gland, promote ovulation and stimulate the ovaries to produce estrogen and progesterone.

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Show the two (neutral) organic starting materials that would be used to synthesize the following ketone by a hydroxide mediated crossed‑aldol reaction the product formed is alpha-beta unsaturated carbonyl compound.

The condensation response among distinctive molecules of an aldehyde or ketone in a protic solvent which includes water or alcohol constitutes the crossed aldol response. When condensation is among distinctive carbonyl compounds, it's far referred to as crossed aldol condensation.

Applying the retrosynthetic evaluation technique, the systems of the beginning substances are decided via way of means of the usage of the bottom catalyzed for the crossed aldol mechanism. The beginning substances are aldehyde and ketone compounds that react with every different to present the goal molecule.

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Answer:

127,236 kj of heat

Explanation:

This is the final answer

Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

The new concentration of the KCl solution after mixing 1 L new volume is 0.28 M.

Concentration in terms of molarity will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ = molarity of old KCl solution = 1.6 M

V₁ = volume of old KCl solution = 175 mL = 0.175 L

M₂ = molarity of new KCl solution = ?

V₂ = volume of new KCl solution = 1 L

On putting all these values on the above equation, we get

M₂ = (1.6)(0.175) / (1) = 0.28 M

Hence resultant concentration is 0.28 M.

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Answer:

4.08moles

Explanation:

The balanced equation of this reaction is given as:

H2SO4 + 2NaOH -> Na2SO4 + 2H2O

From the above balanced equation, 1 mole of H2SO4 is needed to react with 2 moles of NaOH.

Using the formula below to calculate the number of moles in 200g of H2SO4;

mole = mass/molar mass

Molar mass of H2SO4 = 1(2) + 32 + 16(4)

= 2 + 32 + 64

= 98g/mol

number of moles = 200g ÷ 98g/mol

n = 2.04mol

Since 1 mole of H2SO4 is needed to react with 2 moles of NaOH.

Then, 2.04mol of H2SO4 is needed to react with 2.04 × 2/1 = 4.08moles of NaOH.

Answer:

Answer 'A'

Explanation:

There are 3 acid-base theories.

- Arrhenius Theory

- Bronsted-Lowry Theory

- Lewis Theory

In the Arrhenius and the Bronsted-Lowry Theories, for an acid to be an acid two requirements must be met. That is, the substance must be soluble in water and two, undergo ionization generating a hydronium cation (H₃O⁺) and a base anion (A⁻) in process; i.e., H-Anion + H₂O => H₃O⁺ + Anion⁻.

The Lewis Theory defines acids and bases in terms of electron pair donation (the base) and electron pair acceptor (the acid). This theory does not require the presence of an ionizable hydrogen in the substance of interest, only non-bonded electron pairs (base) and a cationic character that accepts electron pairs without violating the octet rule in chemical bonding.

For the purpose of answering your question, the Arrhenius and Bronsted-Lowry theories are sufficient for defining acids and bases undergoing ionization in aqueous media. With this, one should understand also that acids and bases are classified as strong acids and strong bases (compounds that ionize 100% aqueous media) or weak acids and weak bases (compounds that do not ionize 100% in aqueous media).

Strong Acids* include HCl, HBr, HI, HNO₃, HClO₄ & H₂SO₄ (1st ionization step only). Strong Bases include Group IA and Group IIA hydroxides except for Beryllium Hydroxides. The weak acids are compounds with ionizable hydrogens that are NOT members of the strong 6 listed above. The weak bases are ammonia and ammonia derivatives in aqueous media.

It is recommended that students only need to memorize the strong six acids in that any compound not one of these six with an ionizable hydrogen is a weak acid whether you know its name or not. The weak bases, as mentioned, are ammonia and ammonia derivatives in water. These compounds will undergo coordinate bonding to generate an ionizable compound containing an ammonium cation and hydroxyl anion. The reaction is as follows:

               RNH₂ + H₂O => RNH₃⁺OH⁻(aq) => RNH₃⁺(aq) + OH⁻(aq)

Typically, weak acids and weak bases undergo very limited ionization in the range of 1% to 2%. The compounds remaining are in concentrations of 98% - 99% unionized but form soluble homogeneous solutions.

If you have further questions, kick back a note. Doc

___________________-

*Some scholars include sulfurous acid (H₂SO₃) as a strong acid but analysis shows aqueous solutions - under special conditions - to contain unionized  H₂SO₃ and thus violates the 100% ionization requirement.

Answer:

Caesium (55Cs) has 40 known isotopes, making it, along with barium and mercury, one of the elements with the most isotopes. The atomic masses of these isotopes range from 112 to 151. Only one isotope, 133Cs, is stable. The longest-lived radioisotopes are 135Cs with a half-life of 2.3 million years, ... It constitutes most of the radioactivity still left from the Chernobyl accident ...

Answer:

any push or pull that causes an object to move, stop, or change speed or direction

Description:

zayn your my enemy

a) In contrast, CH2ClCH2CO2H lacks a double bond and cannot undergo resonance, making the conjugate base less stable and the acid weaker, b) In the pair M-ClC6H4CO2H and P-ClC6H4CO2H, P-ClC6H4CO2H would be expected to be stronger

a. In the pair CH2ClCH2CO2H and CH3CHCHCO2H, CH3CHCHCO2H would be expected to be stronger. This is because the presence of the double bond in CH3CHCHCO2H allows for delocalization of the negative charge in the conjugate base, making it more stable. The presence of the double bond facilitates resonance, which disperses the negative charge over a larger area, resulting in greater stability of the conjugate base. In contrast, CH2ClCH2CO2H lacks a double bond and cannot undergo resonance, making the conjugate base less stable and the acid weaker.

b. In the pair M-ClC6H4CO2H and P-ClC6H4CO2H, P-ClC6H4CO2H would be expected to be stronger. This is because the para position (P) is closer to the carboxylic acid group than the meta position (M), allowing for greater delocalization of the negative charge in the conjugate base. The closer proximity of the electron-withdrawing chlorine group to the carboxylic acid group enhances the acidity of P-ClC6H4CO2H compared to M-ClC6H4CO2H. The electron-withdrawing effect of the chlorine group stabilizes the conjugate base, making the acid stronger.

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Answer:

C. they are two forms of the same basic force

Explanation: Hope this helps :)

The units used to represent the gas constant (R) affect its value. The most often used units are R = 8.314 J/(mol K) (joules per mole kelvin) in the International System of Units (SI) and R = 0.0821 L/(mol K) (litres per

A physical constant known as the gas constant (R) links a gas's characteristics to its temperature, pressure, and volume. It is a crucial thermodynamic constant, particularly in the ideal gas law, and is represented by the letter R. R's value, which is commonly expressed in units of energy per mole, depends on the units chosen to express it.Several branches of research and engineering, including chemistry, physics, and materials science, depend heavily on the gas constant. It is used to determine how gases will behave in a variety of situations, including chemical reactions, combustion, and refrigeration. The gas constant also offers a foundation for comparing various gases and figuring out their physical and chemical gas constant (R)

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Answer: im pretty sure its D

Explanation:

The CEC for this soil sample is 675.2 cmol(+)/kg.

The % Base Saturation for this soil sample is approximately 136.62%.

The % Acid Saturation for this soil sample is approximately 60.55%.

To    calculate the CEC, % Base Saturation (B.S.), and % Acid Saturation for the given soil sample:

a. Calculation of CEC (Cation Exchange Capacity):

CEC is the sum of exchangeable cations in the soil. From the given results, we have:

CEC = Ca2+ + Mg2+ + K+ + Al3+

CEC = (100 mg/L + 45 mg/L + 85.5 mg/L + 94.2 mg/L) / (25 g / 1000)

CEC = 168.7 mg / (25 g / 1000)

CEC = 675.2 cmol(+)/kg

b. Calculation of % Base Saturation (B.S.):

% B.S. represents the percentage of CEC occupied by base cations. In this case, we consider Ca2+, Mg2+, and K+ as base cations. The formula to calculate % B.S. is:

% B.S. = (Ca2+ + Mg2+ + K+) / CEC * 100

% B.S. = (100 mg/L + 45 mg/L + 85.5 mg/L) / (168.7 cmol(+)/kg) * 100

% B.S. = 230.5 mg / (168.7 cmol(+)/kg) * 100

% B.S. = 136.62%

c. Calculation of % Acid Saturation:

% Acid Saturation represents the percentage of CEC occupied by acid cations, in this case, H+ and Al3+. The formula to calculate % Acid Saturation is:

% Acid Saturation = (H+ + Al3+) / CEC * 100

% Acid Saturation = (8.0 mg/L + 94.2 mg/L) / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 102.2 mg / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 60.55%

Please note that the given values were in milligrams per liter (mg/L), and the CEC and % Saturation values were calculated assuming a conversion from mg/L to cmol(+)/kg using the mass of the soil sample (25 g).

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Measles is a communicable disease that requires immunization to prevent illness when exposed to it.

Measles is a communicable disease and highly contagious. It  is usually very serious in children. The disease can be contacted through droplets in the air, physical contact and through mother-to-child transmission.

It is a very serious disease as it is caused by a virus which replicates very fast in the throat and nose thereby creating symptoms such as runny nose, coughing, sneezing and is usually accompanied with a rash.

The severity and death rates is what gave rise to the creating of a measles vaccine which is usually given to babies after birth to make them immune to the potential exposure to the virus.

Diabetes, bronchitis and strep throat have no vaccine as they can always be treated or managed with over-the-counter drugs.

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Answer:

A is its answer

Explanation:

Fan uses electrical energy and makes it to mechanical energy by rotating

Same is with the drill

Trampoline does not use electrical energy

Lamp uses electrical energy but it converts it into light energy and heat energy

So A is the answer

Answer:

Explanation:

Thus the chemical formula for aluminium permanganate is formed by cross exchanging the coefficient of valencies of aluminium and permanganate (with each other). Thus the chemical formula for aluminium permanganate is represented as : Al(MnO4)3.

comprises start, propagation, and termination for a radical addition reaction employing HBr and propene. The following is the reaction:

----> CH3CH=CH2 + HBr + peroxide CH₃CH₂CH₂Br

1) The following actions are included in the initiation steps:

RO - RO ——> ----> 2RO° RO° + H- Br ROH + Br°

2) The propagation steps that are involved in this step are:

CH2 + Br° = CH3 - CH — CH3, CH2, and CH2Br

----> CH3 - °CH - CH2 - Br + H - Br Br + Br° CH3 - CH2 - CH2 -

3) The final phase consists of:

       Br° + Br° ——> Br - Br\s2 Br --->

                CH3 - °CH - CH2 - CH3, CH2, CH2, and Br        

                                 |

                    CH3, CH2, CH2, and Br

Br + Br° ---> CH3 - °CH - CH2 - CH3 - CH - CH2 - Br | Br

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The mole fraction of \(CH_3OH\)in the solution is 0.850 or 85.0%.

To calculate the mole fraction (Χ) of methanol (CH3OH) in the given solution, we need to determine the number of moles of CH3OH and the number of moles of \(C_6H_5COOH\)(benzoic acid) in the solution.

First, we can calculate the number of moles of CH3OH using its volume and density:

Mass of CH3OH = Volume x Density = 8.50 mL x 0.792 g/mL = 6.732 g

Number of moles of CH3OH = Mass / Molar mass = 6.732 g / 32.04 g/mol = 0.210 mol

Next, we can calculate the number of moles of \(C_6H_5COOH\)using its mass and molar mass:

Number of moles of C6H5COOH = Mass / Molar mass = 4.53 g / 122.12 g/mol = 0.0371 mol

The total number of moles of solute in the solution is the sum of the moles of CH3OH and C6H5COOH:

Total number of moles = 0.210 mol + 0.0371 mol = 0.247 mol

Finally, we can calculate the mole fraction of \(CH_3OH\)using its number of moles and the total number of moles:

Mole fraction of \(CH_3OH\)= Number of moles of \(CH_3OH\)/ Total number of moles = 0.210 mol / 0.247 mol = 0.850

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