Tickets for a play cost $4 for each child and $8 for each adult. If there are only 20 children's tickets sold, which of the following equations could model how much total money y is made in ticket sales?

Answer:

It's night time?

Step-by-step explanation:

its 12:20 pm for also, stay safe :D

Answer:

Goodnight

Step-by-step explanation:

you stay safe too

Answer:

Step-by-step explanation:

If an angle measures x degrees, the measure of its supplement is (180-x) degrees.

This means that x-62.4 = 180-x, meaning that x=121.2.

So, the angles are 121.2 and 58.8 degrees.

Answer:

x^2 - 10x + 25

Step-by-step explanation:

(x - 5)^2

(x - 5)(x - 5)

x^2 - 5x - 5x +25

x^2 - 10x + 25

Hope this helps!

Answer:

x²-10x+25

Step-by-step explanation:

Khan academy

(x−5)² = x²-10x+25

Step-by-step explanation:

L X W X D = cubic feet volume

17 X 30 X .25 = 127. 5  ft^3

Kirk must earn an annual rate of return of approximately 6.07% on his investment to accumulate enough money to pay for the ring.

To calculate the annual rate of return Kirk must earn on his investment, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where:
A = final amount (the cost of the ring, which is $13,000 in 9 years)
P = initial amount (the amount Kirk currently has, which is $4,532)
r = annual interest rate (what we need to solve for)
n = number of times interest is compounded per year (assuming it's compounded annually, n = 1)
t = number of years (9 years)

Plugging in the given values:
$13,000 = $4,532(1 + r/1)^(1*9)
Next, simplify the equation:
(1 + r)^(9) = 13000/4532
Take the ninth root of both sides:
1 + r = (13000/4532)^(1/9)
Solve for r:
r = (13000/4532)^(1/9) - 1
Now, plug the value into a calculator to find r:
r = 0.0607

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Answer:

7 17/99

Step-by-step explanation:

Your answer is False

The pair of 1st line is vertical opposite angle and 2nd one is adjacent angles.

What is vertical opposite angle ?

When 2 lines meet one another, then the other angles, shaped thanks to intersection ar known as vertical angles or vertically opposite angles. A try of vertically opposite angles ar continuously adequate to one another. Also, a angle and its adjacent angle are supplementary angles, i.e., they add up to a hundred and eighty degrees.

Main body:

1st pair of line intersect each other , so ∠1 = ∠2 by using vertical opposite angle.

2nd pair of line also intersect each other , so ∠3 ,∠4 are adjacent angles.

Hence ,pair of 1st line is vertical opposite angle and 2nd one is adjacent angles.

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9514 1404 393

Answer:

  f(x) = x² +3

Step-by-step explanation:

The transformation

  g(x) = a·f((x -c)/b) +d

represents a vertical expansion by a factor of 'a', a horizontal expansion by a factor of 'b' (before the horizontal shift), a horizontal (right) shift by 'c' units, and an upward shift by 'd' units.

You want only an upward shift of 3, so ...

  g(x) = f(x) +3

For f(x) = x^2, the shifted function is ...

  f(x) = x^2 +3

__

Other choices are ...

  b. (x -3)^2 = right shift by 3

  c. 3x^2 = vertical expansion by a factor of 3

  d. (x +3)^2 = left shift by 3

The optimal solution for the given problem, obtained graphically, is x1 = 150 and x2 = 100, with a maximum total profit of 750. The primal problem indicates that all resources and requirements are satisfied. The dual variables associated with the machine hours and item 2 are both zero.

To find the optimal solution graphically, we plot the feasible region determined by the given constraints. The constraint 5x1 + 4x2 ≤ 1800 represents the available machine hours, while x1 ≥ 100 and x2 ≥ 50 represent the minimum demand for item 1 and item 2, respectively. Additionally, x1 ≥ x2 ensures that the number of items produced of type 1 is greater than or equal to the number of items produced of type 2.
By graphing these constraints, we identify the feasible region, which is the area where all constraints are satisfied. The objective function, Z = 2x1 + 3x2, represents the total profit. To maximize Z, we find the corner point within the feasible region that yields the highest profit. In this case, the optimal solution is x1 = 150 and x2 = 100, resulting in a maximum total profit of 750.
From the primal problem, we observe that all resources and requirements are met. The available machine hours (1800) are not fully utilized, and the minimum demands for item 1 (100) and item 2 (50) are both satisfied.
For the dual variables, associated with the machine hours and item 2, we find that both are zero. This indicates that there is no shadow price or economic interpretation for these constraints in the primal problem. The optimal value of the dual variable associated with the machine hours represents the rate of change in the objective function per unit increase in the available machine hours, and since it is zero, it implies that the objective function does not change with additional machine hours. Similarly, the dual variable for item 2 being zero suggests that the objective function is not affected by changes in the demand for item 2.
In summary, the optimal solution of x1 = 150 and x2 = 100 maximizes the total profit to 750. The primal problem shows that all resources and requirements are satisfied, and the dual variables associated with machine hours and item 2 are both zero, indicating no economic interpretation for these constraints in the primal problem.

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the complete question is:

     max Z=2x1+3x2
s. t.
5x1 + 4x2 ≤ 1800
(Time in hours on machine)
x1≥ 100 (Demand on item 1)
x2 ≥ 50
(Demand on item 2)
x1>=x2(Number of items produced of type 1>=N)
where x1 is the number of items produced of type 1, x2 is the numb total profit.
A. Find the optimal solution of the primal graphically B. Determine the status of resources and requirements froC. From part (A), find the optimal value of the dual vari hours on machine
D. From part (A), find the optimal value of the dual vv
item 2'

Answer: look at the images for the answer and the solution

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

correct on plato

Answer:

Y*x -2x=40min

Add the probability of rolling a 2, 4 or 6 to find the probability of the following compound event: rolling a die that lands on an even number (2, 4, or 6). So the option D is correct.

A simple occurrence is one that has just one possible conclusion. Because just one possible result—1—can be achieved, rolling a 1 would be a straightforward event. Because there is just one possible conclusion for the event—a 6—rolling more than a 5 would likewise be a straightforward event. A compound event is one that has multiple outcomes. One six-sided dice, for instance, has three possible results when an even number is rolled: 2, 4, or 6.

The probability of rolling a die that lands on an even number (2, 4, or 6) is 3/6 or 1/2. This is because there are three possible outcomes (2, 4, and 6) out of a total of six possible outcomes (1, 2, 3, 4, 5, and 6).

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The complete question is:

Which answer correctly describes how to find the probability of the following compound event: rolling a die that lands on an even number (2, 4, or 6)?

A. Add the probability of rolling a 3

B. Add the probability of rolling a 4 or 6

C. Add the probability of rolling a 2

D. Add the probability of rolling a 2, 4 or 6

The area under the curve to the right of 64 is 0.2514.

To find the area under the curve to the right of 64 in a normal distribution with mean μ = 60 and standard deviation σ = 6, follow these steps:

1. Calculate the z-score: z = (x - μ) / σ, where x = 64.
  z = (64 - 60) / 6
  z = 4 / 6
  z ≈ 0.67

2. Use a z-table or calculator to find the area to the left of z = 0.67.
  The area to the left of z = 0.67 is approximately 0.7486.

3. Subtract the area to the left from 1 to find the area to the right of z = 0.67.
  Area to the right = 1 - 0.7486
  Area to the right ≈ 0.2514

So, the area under the curve to the right of 64 in this normal distribution is approximately 0.2514.

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Sylvia and Patrick gathered information on the weight of cars and the mileage they get, and then proceeded to plot the data on a graph.

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Answer:

9.9\(cm^{3}\)

Step-by-step explanation:

Formula:

1/3(area of the base x height)

1/3 [2.175(2.175)(6.3)]

1/3(4.730625)(6.3)

1/3(29.8029375)

9.9343125

Is the perimeter of the base is 8.7, we need to divide that by 4 (2.175) to find out the side length of the square.  The area of the square, we need to multiply 2.175 by 2.175.

9.9343125 rounded to the nearest tenth is 9.9

Helping in the name of Jesus.

Answer:

76, 69

Step-by-step explanation:

x - y = 7

x + y = 145

Subtract these 2 equations

-2y = -138

y = 69

145 - 69 = 76  x = 76

Answer:

x=2, y=1

Step-by-step explanation:

y=x-1

y=3-x

x-1=3-x

2x=4

x=2

From the construction, quadrilateral ACBD is a rhombus because circles A and B have the same radius.

A chord is a line that do not pass though the center of a circle and joins two points on its circumference. It majorly divides the circumference of a circle into major and minor arcs.

With the given conditions in the question, quadrilateral ACBD sides ae chords. As regards the circles, sides AC and AD are chords circle B. Also, CB and BD are chords on circles A. So that the sides of quadrilateral ACBD are equal.

The main reason why the quadrilateral is a rhombus is because circles A and B have the same diameter, thus the same radius.

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The equations that can be used to eliminate m₂ are 1. m₂ = 3m₁ and 4. m₂g - T=m₂a₂

From the question, we have the following parameters that can be used in our computation:

1. m₂ = 3m₁

2. --m₁g cosθ + T= m₁a₁

3. a₁ = a₂

4. m₂g - T=m₂a₂

To eliminate m₂, the equation to use must have a term or factor that has m₂

using the above as a guide, we have the following:

1. m₂ = 3m₁ and 4. m₂g - T=m₂a₂

Hence, the equations are 1. m₂ = 3m₁ and 4. m₂g - T=m₂a₂

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Question

A physics student solving a physics problem has obtained the following four equations that describe the physics of a system of masses connected:

1. m2 = 3m1

2. --mig cosθ + T= miai

3. a1 = a2

4. m2g-T=m2a2

The student decides to eliminate the unknown m2. Which two of the equations can be used to eliminate m2?

Answer:

hope it helps..

Step-by-step explanation:

1- Indicate on the x-axis the boundaries defined by the intervals on each piece of the domain.

2- For each piece of the domain, graph on that interval using the corresponding equation pertaining to that piece.

The solution to the linear function M(x) = 180 is of x = -5.

The linear function equation is the slope-intercept form. Thus, it is expressed as f(x) = mx + b where m is the slope and b is the y-intercept of the line.

In this problem, the function is defined as follows:

M(x) = 120 - 12x.

M(x) represents the balance remaining on the gift card after x movie tickets priced at $12 are purchased.

The domain of the situation is given as follows:

x ≥ 0. {discrete}

As the number of tickets cannot assume negative neither decimal values.

The equation is:

M(x) = 180.

The solution is calculated as:

120 - 12x = 180

12x = -60

x = -60/12

x = -5.

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To solve the problem, we can use the equations for the axial deformation of a bar under axial load:

ε = δ/L

σ = Eε

where ε is the strain, δ is the displacement, L is the length of the bar, σ is the stress, and E is the modulus of elasticity.

(a) To find the displacements at points B and C, we can use the equation:

δ = PL/AE

where P is the axial load, L is the length of the bar, A is the cross-sectional area, and E is the modulus of elasticity.

For point B, the axial load is 5000 lb and the cross-sectional area is 1 sq in. The length of the bar is 10 in (15 in - 5 in). The modulus of elasticity is 30x10^6 psi. Therefore, the displacement at point B is:

δB = (5000 lb x 10 in) / (1 sq in x 30x10^6 psi) = 0.0167 in

For point C, the axial load is 2000 lb and the cross-sectional area is 0.25 sq in. The length of the bar is 12 in (15 in - 3 in). The modulus of elasticity is 30x10^6 psi. Therefore, the displacement at point C is:

δC = (2000 lb x 12 in) / (0.25 sq in x 30x10^6 psi) = 0.008 in

(b) To find the axial load in each shaft, we can use the equation:

P = σA

where P is the axial load, σ is the stress, and A is the cross-sectional area.

For shaft AB, the stress is:

σAB = δB/LAB x E = 0.0167 in / 10 in x 30x10^6 psi = 50 psi

The cross-sectional area is 1 sq in. Therefore, the axial load in shaft AB is:

PAB = σAB x AAB = 50 psi x 1 sq in = 50 lb

For shaft BC, the stress is:

σBC = (δC - δB)/LBC x E = (0.008 in - 0.0167 in) / 3 in x 30x10^6 psi = -25 psi

The cross-sectional area is 0.196 sq in (π(0.375 in)^2 / 4). Therefore, the axial load in shaft BC is:

PBC = σBC x ABC = -25 psi x 0.196 sq in = -4.9 lb

The negative sign indicates that the load is compressive.

For shaft CD, the stress is:

σCD = -δC/LCD x E = -0.008 in / 3 in x 30x10^6 psi = -80 psi

The cross-sectional area is 0.049 sq in (π(0.25 in)^2 / 4). Therefore, the axial load in shaft CD is:

PCD = σCD x ACD = -80 psi x 0.049 sq in = -3.92 lb

The negative sign indicates that the load is compressive.

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Given:

Percentage of numbers unlisted = 40% = 0.40

Sample size, n = 5

Let's find the probability that all 5 of the selected houses have unlisted numbers.

To find the probability, we have:

p(numbers unlisted) = 0.40

Hence, we have:

q = 1 - p = 1 - 0.40 = 0.60

For the probability, apply the binomial probability:

0 .

Solving further:

Therefore, the probability that all 5 numbers have unlisted numbers is 0.01024

• ANSWER:

0.01024

Answer:

A. The quotient of 2 and a number

Step-by-step explanation:

2n would be 2 multiplied by n

It can also be written as twice a number or double a number or the product of two and a number.

The quotient of 2 and a number would be 2/n therefore the answer is the quotient of 2 and a number

Answer:

A. The quotient of 2 and a number

Step-by-step explanation:

2n would be multiplied not divided.

Answer:

1 + x

Step-by-step explanation:

he will earn x amount of dollars per hour for work(x dollars per hour)

On the way he found a dollar bill (+1)

The integer is 1