Three objects move with a velocity of 1 m/s what is the total kinetic energy of the system?

Hi there!

Recall Newton's Law of Universal Gravitation:

\(\large\boxed{F_g = \frac{Gm_1m_2}{r^2}}\)

G = Gravitational Constant

m1, m2 = mass of objects (kg)

r = distance between objects (m)

There is an INVERSE-SQUARE relationship between the gravitational force and the distance between the objects, so:

\(F_g = \frac{Gm_1m_2}{(\frac{1}{4}r)^2} = F_g = \frac{Gm_1m_2}{\frac{1}{16}r^2}\)

\(= 16G\frac{m_1m_2}{r^2} = 16F_g\)

Thus, the gravitational force between the objects would INCREASE by a factor of 16.

Hello!

Distance of R/2:

Since a conducting sphere is referenced in this situation, all of its charge will be distributed along its SURFACE. Therefore, there is NO enclosed at a distance of R/2 from the center.

Using Gauss's Law:
\(\oint E \cdot dA = E\cdot A = \frac{Q_{encl}}{\epsilon_0}\)

E = Electric field strength (N/C)
A = Area of Gaussian surface (m²)

Q = Enclosed charge (C)
ε₀ = Permittivity of free space C²/Nm²)

If the enclosed charge is 0, then:
\(E \cdot A = \frac{0}{\epsilon_0}\\\\\boxed{E = 0 \frac{N}{C}}\)

Distance of '2R':

We can once again use Gauss's Law to solve. This time, however, a surface of radius '2R' encloses ALL of the charge of the sphere.

\(E \cdot A = \frac{Q_{encl}}{\epsilon_0}\)

'A' is equivalent to the surface area of a sphere of radius '2R', or:
\(A = 4\pi (2R)^2\\\\A = 4\pi (4R^2)\\\\A = 16\pi R^2\)

Substituting this expression back into Gauss's Law:
\(E \cdot 16\pi R^2 = \frac{Q}{\epsilon_0}\\\\E = \frac{Q}{16\pi R^2\epsilon_0}\)

To simplify:
\(E = \frac{1}{4\pi \epsilon_0 } * \frac{Q}{4R^2}\\\)

OR using k = 1/4πε₀:
\(\boxed{E = \frac{kQ}{4R^2}}\)

The requried combined length of the trains are 1.8 kilometers.

Velocity is defined as the rate of change in the position of an object with respect to time.

Here,

Let's first convert the speeds from km/h to m/s to make our calculations easier,

The first train travels at 108 km/h = 30 m/s.

The second train travels at 72 km/h = 20 m/s.

Now, we can calculate the relative speed of the trains:

The relative speed between the two trains is 30 m/s - 20 m/s = 10 m/s.

We know that the first train overtakes the second train in 60 seconds. During this time, the first train will cover a distance equal to the combined length of both trains.

Let's denote the length of the first train as L₁ and the length of the second train as L₂. Then, we can write,

Distance covered by the first train in 60 seconds = L₁

Distance covered by the second train in 60 seconds = L₂ + L₁ (because the second train is L₂ behind the first train when it is overtaken)

The speed of the first train is 30 m/s, so its distance covered in 60 seconds is:

Distance covered by the first train in 60 seconds = 30 m/s x 60 s = 1800 m

Similarly, the speed of the second train is 20 m/s, so its distance covered in 60 seconds is,

Distance covered by the second train in 60 seconds = 20 m/s x 60 s = 1200 m

L₁ = 1800 m - 1200 m = 600 m

L₁ + L₂ = 1800 m

So the combined length of both trains is:,
L₁ + L₂ = 1800 m

L₁ + L₂ = 1.8 km

Therefore, the combined length of both trains is 1.8 km.

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Option e is true. The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.

According to the Law of conservation of energy. Although energy cannot be generated or destroyed, it may be transferred from one form to another.

The following statements are true;

a)All of its energy must be potential energy before it falls.

b)At the conclusion of its fall, all of its energy must be transformed to kinetic energy.

c)During its fall, the sum of its kinetic and potential energy must match the initial quantity of potential energy.

d)Total energy = Kinetic Energy + Potential Energy.

Hence, option e is correct.

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Answer:

A

Explanation:

Amplitude = height of the wave = 1

Wavelength = 3

They are slightly shifted.

The first statement is the correct one.  Don't make me type the whole thing out.

Answer:

Explanation:

7

Answer:

- Reduction of surface roughness

- Use of lubricant

- Give a streamlined shape

- Replace the sliding friction force with the rolling friction force

- Application and use of ball or roller bearings

- Air Cushion Application

8

Given:

m = 1000 kg

F = 8000 N

g = 10m/s²

____________

μ - ?

Friction coefficient:

μ = F / (m·g) = 8000 / (1000·10) = 0.8

Answer:

four covalent bonds is the answer

Each plate of the capacitor has a charge of 6.5 micro-coulombs. It takes 15.2 j of energy to move a 13.0-mc charge from one plate of a capacitor to the other.

The work done in moving a charge q across a potential difference V is given by:

W = qV

We are given that it takes 15.2 J of energy to move a charge of 13.0 mc (micro-coulombs) from one plate of a capacitor to the other. We can convert micro-coulombs to coulombs by dividing by 10^6:

q = 13.0 × 10^-6 C

We are also told that the voltage across the capacitor is constant. Therefore, we can find the voltage by dividing the work done by the charge moved:

V = W/q = 15.2 J / 13.0 × 10^-6 C = 1.169 × 10^6 V

The charge on each plate of the capacitor is equal and opposite, so each plate has a charge of:

q/2 = 6.5 × 10^-6 C

Therefore, each plate of the capacitor has a charge of 6.5 micro-coulombs.

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Answer:

because the electricity always looking for a way to get to the ground

\( \huge \mathfrak \red{AnSwer}\)

Birds can sit on power lines and not get electric shocks because the electricity is always looking for a way to get to the ground. The birds are not touching the ground or anything in contact with the ground, so the electricity will stay in the power line.

Answer:

they reflect light waves

Explanation:

The tiny drops or ice particles in clouds scatter between 20 and 90 percent of the sunlight that strikes them

Answer:

They reflect light waves

Explanation:

The components of the vector v are given as:

where v is the magnitude of the vector and theta is the angle.

In this case we have v=253 and theta=55.8°, plugging this values into the y component we have:

Therefore the y component is 209.25 meters.

Answer:

\( \huge{ \boxed{ \bold{ \sf{90 \: joule}}}}\)

✑ First , Let's know what kinetic energy is :

⇾ The energy possessed by a body by the virtue of it's motion is called kinetic energy of the body. A flying bird , a moving car , running water , wind , a bullet fired from a gun , an arrow left from a bow , rolling stone etc are some examples of kinetic energy.

The Kinetic energy of a moving body is determined by the formula :

\( \boxed{ \underline{ \sf{KE= \frac{1}{2} m {v}^{2} }}}\)

Here ,

--------------------------------------------------------------

☇ Now , Let's solve :

☄ Given :

☄ To find :

⤿ \( \boxed{ \sf{KE= \frac{1}{2} m {v}^{2} }}\)

Plug the values and simplify :

→ \( \sf{ \frac{1}{2} \times 20 \times {(3)}^{2} }\)

→ \( \sf{ \frac{1}{2} \times 20 \times 9}\)

→ \( \boxed{ \bold{\sf{90 \: joule}}}\)

Hope I helped !

Have a wonderful day ! ツ

~TheAnimeGirl ♡

7.5 hours or 450 minutes. 15/2=7.5

For the 1.0 gram sample of the same radionuclide, the required half life will be of 7.5 hours.

Given data:

The amount of sample at initial is, a = 2.0 g.

The half-life for 2.0 g sample is,  \(t_{1/2}=15 \;\rm hr\).

In the given problem, it is a simple calculation but the concept of half life is used . The half life is defined as the a time interval required for one-half of nucleus of sample to undergo complete decay.  

In the given problem,

2.0 g of sample = 15 hours

1.0 g of sample = 15/2 hours

                         = 7.5 hours

Thus, we can conclude that for the 1.0 gram sample of the same radionuclide, the required half life will be of 7.5 hours.

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At the top of the hill, the cars have a great deal of gravitational potential energy, equal to the cars' weight multiplied by the height of the hill. When the cars are released from the chain and begin coasting down the hill, potential energy transforms into kinetic energy until they reach the bottom of the hill.

Answer:

0.2 hours

Explanation:

1864+7397=8199436 thats it

Answer:0.45s

Explanation:

Trust me

Answer:

D. there is not enough information to tell

Explanation:

I have already read this in grade five

Technically, there is not enough information to tell, because in your picture, you cut off the last word in the question.

If the last word in the question is "acceleration", then "C" is the correct choice.

If some other word is the last one in the question, then it has to be "D".

All the answers are in the pics I have sent. I hope this will help you. Have a good day!

Velocity at which the car can take the curve without skidding to the outside of the curve is approximately 29.5 m/s.

To determine the speed at which the car can take the curve without skidding to the outside of the curve, we need to calculate the maximum force of static friction that can act on the car as it goes around the curve.

The maximum force of static friction can be found using the formula:

f_max = friction_coefficient * f_norm

where f_max is the maximum force of static friction, friction_coefficient is the coefficient of static friction between the tires and the pavement (0.87), and f_norm is the normal force acting on the car.

The normal force can be found by calculating the centripetal force acting on the car as it goes around the curve, which can be found using the formula:

f_cent = m * a_cent

where f_cent is the centripetal force, m is the mass of the car (1091 kg), and a_cent is the centripetal acceleration, which can be found using the formula:

a_cent = v² / r

where v is the velocity of the car and r is the radius of the curve (36 m).

Substitute the value of a_cent in the formula for f_cent

f_cent = m * (v² / r)

Also we know that the maximum force of static friction is equal to the normal force acting on the car

f_max = f_norm = m * (v² / r)

Now we know friction_coefficient * f_norm = m * (v² / r)

so we can substitute the value of friction_coefficient and m and r

0.87 * m * g * sin(25) = m * (v² / 36)

v = √(0.87 * 9.8 * 36 * sin(25))

v = 29.5m/s

Therefore, the velocity of the car without skidding outside the curve is 29.5m/s

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The angular displacement of the tires in revolutions is approximately 216,867.47 revolutions.

First, let's convert the diameter of the tires from centimeters to meters:

d = 66 cm = 0.66 m

Next, let's convert the speed from km/h to m/s:

v = 300 km/h = (300/3.6) m/s = 83.33 m/s

The circumference of the tire is:

C = πd = π(0.66 m) = 2.075 m

The distance traveled by the car in 1.5 hours is:

d = vt = (83.33 m/s)(1.5 hours)(3600 s/hour) = 450,000 m

The number of revolutions of the tire is equal to the distance traveled divided by the circumference of the tire:

n = d/C = 450,000 m / 2.075 m = 216,867.47

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Answer:

дангггггггггггггггггггггггггггггггггггггггггггггг

Answer: D.

Explanation: I took the test

Answer:

Explanation:

The weight of a body is defined as the force with which it is attracted towards the centre of a planet. A spring balance measures it. It's unit is Newton ( N ) in the SI system and dyne in the CGS system.

Hope I helped!

Best regards!

Weight is force.

The CGS unit of force is the dyne.

The SI unit of force is the Newton.

If a baseball has a negative velocity and a negative acceleration, its speed is decreasing.

Velocity is a vector quantity that includes both magnitude (speed) and direction. In this case, the negative velocity indicates that the baseball is moving in the opposite direction of a chosen positive reference direction. Acceleration, on the other hand, represents the rate of change of velocity and also includes both magnitude and direction.

When the velocity and acceleration have the same sign (both negative in this case), it means that the baseball is slowing down. This is because the acceleration is acting in the opposite direction to the velocity, which results in a decrease in speed. Therefore, the speed of the baseball is decreasing.

Mass of Jupiter=1.9×10

27

㎏=M

1

Mass of Sun=1.99×10

30

㎏=M

2

Mean distance of Jupiter from Sun=7.8×10

11

m=r

G=6.67×10

−11

N㎡㎏

−2

Gravitational Force, F=

r

2

GM

1

M

2

F=

(7.8×10

11

)

2

6.67×10

−11

×1.9×10

27

×1.99×10

30

F=4.16×10

23

N

The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.

The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:

RC = τ, where R is the resistance and C is the capacitance of the circuit.

Rearranging the above formula, we get:R = τ / C

Where τ is the time constant and C is the capacitance of the circuit.

From the figure, the capacitance is given as 0.1 μF

.Substituting the values of τ and C in the above formula, we get:

R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)

R = 220 Ω

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Answer:

W = 210 N

Explanation:

For an ideal machine:

\(Work\ In = Work\ Out\\(P)(L)=(W)(H)\)

where,

P = Effort = Spring Scale Reading = 70 N

L = Effort Arm = Length of inclined plane = 12 m

W = Actual Load (Weight) to be lifted = ?

H = Load Arm = Height = 4 m

Therefore,

\((70\ N)(12\ m) = (W)(4\ m)\\\\W = \frac{(70\ N)(12\ m)}{4\ m}\)

W = 210 N