Three objects each have mass m. Each object feels a force from the other two, but not from any other object. Initially the first object is at x=−L, y=0; the second object is at x=+L, y=0; and the third object is at x=0, y=L. The momentum of the system of the particles at the initial time is zero. At a later time the first object is at x=−L/3, y=+L/4; and the second object is at x=+L/2, y=−L. At this later time, where is the third object? Find the x-position of the third object

Answers

Answer 1

The x-position of the third object is 0 and the y-position is √(119L²/144), which is approximately 0.98L.

To find the x-position of the third object at the later time, we can use conservation of momentum. Since the momentum of the system was initially zero, it must still be zero at the later time.

Let's define the direction from left to right as the positive x-direction, and the direction from bottom to top as the positive y-direction.

The momentum of the system in the x-direction is initially zero, and since there are no external forces acting on the system, it must remain zero at the later time. This means that the total momentum of the two objects in the x-direction must be equal and opposite.

From the given information, we know that the x-coordinates of the first and second objects have changed by Δx = L/3 + L/2 = 5L/6. Since the masses of all three objects are equal, the first and second objects must have the same magnitude of momentum in the x-direction, so each must have momentum mΔx/2 to the right.

Therefore, the third object must have momentum mΔx to the left, and since the momentum of the system is zero, the third object must have the same magnitude of momentum in the y-direction as the first and second objects combined.

Using the Pythagorean theorem, we can find the magnitude of the displacement of the first and second objects in the y-direction: √[(L/4)² + (L/3)²] = √(25L²/144)

Therefore, the magnitude of the momentum of the first and second objects combined in the y-direction is 2m√(25L²/144).

Since the third object has the same magnitude of momentum in the y-direction, we can use the Pythagorean theorem again to find its displacement in the y-direction: √(L² - [(5L/12)² + (2L/3)²]) = √(L² - 25L²/144)

Simplifying this expression, we get: √(119L²/144). Therefore, the x-position of the third object is 0 and the y-position is √(119L²/144), which is approximately 0.98L.

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Related Questions

A child of mass 46. 9 kg sits on the edge of
a merry-go-round with radius 1. 5 m and moment of inertia 86. 5305 kg m2. The merrygo-round rotates with an angular velocity of
2 rad/s. The child then walks towards the
center of the merry-go-round and stops at a
distance 0. 645 m from the center. Now what
is the angular velocity of the merry-go-round?
Answer in units of rad/s

Answers

The final angular velocity of the merry-go-round is 2.805 rad/s.

Substituting the given values into the above equations, we get:

L1 = 86.5305 kgm^2 * 2 rad/s = 173.061 Nms

I1 = 86.5305 kgm^2 + 46.9 kg * (1.5 m)^2 = 184.9265 kgm^2

r = 0.645 m

m = 46.9 kg

Therefore, I2 = I1 - m * r^2 = 53.410 kgm^2

Substituting I1, I2, and ω1 into the equation for angular momentum conservation, we get:

86.5305 kgm^2 * 2 rad/s = 53.410 kgm^2 * ω2

Solving for ω2, we get:

ω2 = (86.5305 kgm^2 * 2 rad/s) / (53.410 kgm^2) = 2.805 rad/s.

Angular velocity is a physical concept used to describe the rate of change of angular displacement of an object over time. Angular displacement refers to the change in the orientation or position of an object relative to an axis, while angular velocity describes the rate at which this change occurs.

Angular velocity is measured in units of radians per second (rad/s) and is calculated as the ratio of the change in angular displacement to the time taken for the change to occur. This means that an object with a higher angular velocity will rotate or move around an axis more quickly than an object with a lower angular velocity. Angular velocity is an important concept in physics and is used in many applications, including in the design of machinery, navigation systems, and robotics.

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Are carbon compounds rigid and strong

Answers

yes, but it takes a lot of energy to break all those iconic bonds .

where on earth can you stand and, over the entire year, see the entire sky?

Answers

Answer: Both the north and south pole

a toy cork gun contains a spring whose spring constant is 18n/m. the spring is compressed 7.47 cm and then used to propel a 9 cork. the cork, leaves the spring from the spring's relaxed length. with what speed, in m/s, does the cork leave the spring?

Answers

The cork leaves the spring at a speed of 3.02 m/s.

We can use the conservation of energy to determine the speed at which the cork leaves the spring.

The initial potential energy stored in the spring is converted to the kinetic energy of the cork as it leaves the spring. Neglecting air resistance, the conservation of energy equation is:

(1/2) k x^2 = (1/2) m v^2

where k is the spring constant, x is the distance the spring is compressed, m is the mass of the cork, and v is the speed of the cork as it leaves the spring.

Substituting the given values:

(1/2) * 18 N/m * (7.47 cm / 100 cm/m)^2 = (1/2) * 0.009 kg * v^2

Solving for v:

v^2 = (18 N/m * (7.47 cm / 100 cm/m)^2) / 0.009 kg

v^2 = 9.119 m^2/s^2

Taking the square root of both sides:

v = 3.02 m/s

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The Joule is the unit used for kinetic
energy. It is based on meters,
klograms, and
O grams
O liters
O seconds

Answers

Grams is the right answer.

Which of the following is a vector?
7 meters
0.007 cm
7x 106m
7 miles Northwest

Answers

The vector from the following options needs to be identified.

The last option 7 miles Northwest is a vector.

Vectors

A vector is a geometric object that has both magnitude and direction.

For example: Velocity, force, displacement etc.

A scalar is a geometric object that has only magnitude.

For example: Speed, distance etc.

The first three options 7 meters, 0.007 cm and \(7\times 10^6\ \text{m}\) are all distances, with no direction mentioned. So, they are scalar quantities.

The last option is 7 miles northwest has distance as well as direction so it is a vector quantity.

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A driver traveling at 100\,\dfrac{\text{km}}{\text{h}}100 h km ​ 100, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction notices the speed limit changes to 50\,\dfrac{\text{km}}{\text{h}}50 h km ​ 50, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction. The driver takes 0.9\,\text{s}0.9s0, point, 9, start text, s, end text to slow down to 50\,\dfrac{\text{km}}{\text{h}}50 h km ​ 50, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction with constant acceleration. We want to know how many meters the driver travels while slowing down.

Answers

Answer:

67.5

Explanation:

d = (Vo+ v/2)t

d = (150/2)(0.9)

d = 67.5

A plane is going at a speed of 300 km/h at 63 W of N. The wind hits the plane at a direction of 65 km/h at 52 S of E. What is the final direction of plane and the speed at which it is moving?

Answers

It’s around the g force so it’s gonna be around 54 km/h

why does deceleration lower force during a collision?​

Answers

The force depends on the change of momentum. After a deceleration the momentum is less, so the change of momentum is less, so the force is less.

what index of refraction halves the wavelength that light has in a vacuum?
a) 1.33
b) 1.50
c) 1.41
d) 2.00
e) 5.00

Answers

The index of refraction that halves the wavelength that light has in a vacuum is 2.00. Therefore, the correct option is (d) 2.00.

When light passes from one medium to another, it changes its velocity, and thus its wavelength. The index of refraction is a measure of how much light is bent when passing through a medium and can be calculated using Snell's Law:n1sin θ1=n2sin θ2where n1 and n2 are the indices of refraction of the two media, and θ1 and θ2 are the angles that the light makes with the normal line in the first and second media, respectively.

For a given angle of incidence, we can see that the index of refraction is directly proportional to the sine of the angle of refraction, which means that as the angle of refraction increases, so does the index of refraction. Now, let's assume that light is passing from vacuum (with index of refraction n1=1) to a medium with an unknown index of refraction n2.

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Find the equivalent resistance across the two ends A and B of the given circuit. ​

Answers

The provided circuit has a 1 ohm equivalent resistance across its two endpoints, A and B.

If R 3 and R 4 were parallel in R", then the resistance would be 1 ohm.

Calculate R' and R" now:

where R' is one ohm and R" is one ohm

formula: R'+R"=1+1=2 ohm

The other R"' and R"" are likewise calculated in parallel when we do so:

The whole resistance is therefore 1 ohm.

1 ohm is the ultimate response.

What does resistance mean for electrical current?

Electrical resistance is a force that opposes the passage of current and is hence resistance to electricity. In this sense, it acts as a gauge for the difficulty of current flow. Ohms () are used to measure resistance.

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Estimate the voltage across the 30-ohm resistor.

Answers

Answer:

1.5= x/30 =X= 30 x 1.5= 45 volts

Explanation:

A boat pulls an inner tube behind it using a rope. The rope exerts a force 155 N on the inner tube at an angle of 5.88 above the horizontal. What are the horizontal and vertical components of this force?

A boat pulls an inner tube behind it using a rope. The rope exerts a force 155 N on the inner tube at

Answers

Answer:

154 N horizontal (to the right) 15.9 N vertical (up)

Explanation:

I got it right :)

estimate the acceleration due to gravity (in m per s2.

Answers

In conclusion, the acceleration due to gravity is a crucial aspect of physics that enables us to experience weight on Earth. It has a value of approximately 9.81 m/s² near sea level. One of the ways to estimate it is by using a pendulum.

The acceleration due to gravity refers to the acceleration an object experiences as a result of the force of gravity. It is one of the most fundamental physical concepts in existence. The acceleration due to gravity is generally represented as “g,” and it varies depending on the planet or moon in question as well as the object’s distance from the object in question. When on Earth, the acceleration due to gravity is roughly 9.81 m/s² near sea level. This acceleration due to gravity is what enables us to stay on the planet and experience weight when we stand or sit on the ground. The value of the acceleration due to gravity may be determined by using a number of methods. One common approach is to use a pendulum. The formula for determining the acceleration due to gravity is g = (4π²L)/T², where L is the length of the pendulum and T is the time it takes for one full swing. Using this equation, it is possible to estimate the acceleration due to gravity for any planet or moon where there is a pendulum.

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When is the kinetic energy of the ball zero and when is it at its highest? When is its potential energy at its lowest and at its highest? What happens to the kinetic energy and potential energy between point A and point B? (3 points)

Answers

Answer:

if there is only one planet in the universe and the ball is there it will have 0 kinetic energy if the ball is in the very center of that planet only if the planet itself is absolutely motionless. its at its highest if the planet is moving away from the ball at a slightly faster speed forever. Between point A and B both potential energy and kinetic energy are at perfect 0.

Explanation:

never will have a measurable kinetic or potential energy status unless every single object is included in the calculation.

You will need the following items: a rope about 10 to 20 meters long, a meter or yard stick, a watch that records seconds, and a helper. Tie one end of the rope to a doorknob or other secure object at about waist height. Have your helper take one end of the rope and whip it up and down, while you watch. Answer the questions below.

What type of wave was created? How do you know?

Estimate the wavelength of the wave produced.

Estimate the frequency of the wave produced. This is most easily estimated by counting the number of waves that pass the measuring device within a particular time interval as measured on your watch, or by counting the number of times the hand is shaken up and down.

Compute the velocity of your wave.

Answers

Answer:

1. The wave created is a transversal wave because the medium goes up and down. (I used what someone put in the comments because it's correct.)

2. 20 Meters

3. 60 Hz (Hertz)

4. 1200m/s

Explanation:

Not sure if all of this is correct, but I did this assignment so..

Please mark me brainliest. I answered all questions.

Which is a unit of volume?

A) centimeter
B) meter
C) milligram
D) milliliter

Answers

Answer:

I think milligram is the correct answer.

Answer:

D. milliliter

Explanation:

Took it on usatestprep

Pls help me I need help thanks.

Pls help me I need help thanks.

Answers

Answer: The  Answer Is A

Explanation:

a positive charge travels to the right near a wire carrying a current to the right. What is the direction of the force exerted by the charge on the wire

Answers

When a positive charge travels to the right near a wire carrying a current to the right, the force exerted by the charge on the wire, based on Newton's third law, will be directed downwards.

The direction of the force exerted by the charge on the wire is determined by the magnetic field produced by the current-carrying wire. Using the right-hand rule, the magnetic field will be in a circular pattern around the wire. In this case, the magnetic field at the location of the positive charge will be directed into the plane (or page).

The force on the positive charge, according to the Lorentz force equation (F = q(v x B)), will be upwards (perpendicular to both the velocity of the charge and the magnetic field). Therefore, the force exerted by the charge on the wire, based on Newton's third law, will be directed downwards.

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A bowler rolls a 5 kg ball down a frictionless bowling alley. The ball accelerates at an average rate of 2 m/s. How much force did the bowler apply to the ball

Answers

A force of 10N was applied to the ball by the bowler.

What is a force?

A force is any interaction that, when unopposed, will change the motion of an object. It can be a push or a pull. What are the Effects of Force?

Typically, motion can either be described as:

Change in speedChange in direction

Effects of a forceForce can make a body that is at rest to move.It can stop a moving body or slow it down.It can accelerate the speed of a moving body.It can also change the direction of a moving body along with its shape and size.

It is determined by the formula; F = ma

Where m = mass

a = acceleration

From the question;

m = 5kg

a = 2m/s2

F = ma

F = 5 x 2

F = 10N

Hence, the bowler applied a force of 10N to the ball.

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As long as proper safety precautions have been taken, why can explosives be trans- ported long distances without exploding?

Answers

If the right safety measures are implemented, explosives can be transported across great distances without blowing up since they need a precise combination of circumstances to detonate. A particular temperature, pressure, and confinement are some of these conditions. The explosive won't go off if these requirements are not met.

Explosives are kept in specialized containers during transit in order to prevent accidental detonation owing to environmental conditions like heat, shock, or pressure. The containers are made to keep the explosive from coming into contact with anything else that might set it off.

Additionally, the transportation of explosives is strictly regulated and subject to tight safety guidelines. These safety precautions guarantee that explosives are handled, transported, and stored safely to reduce the possibility of unintentional detonation.

Transporting explosives still entails inherent dangers, thus it should only be done by skilled experts who are aware of the necessary safety procedures and potential hazards.

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A child (m = 30. 5 kg) is sitting in a boat (m = 53. 0 kg); both are at rest together. He throws a rock (m = 5. 61 kg) into the lake horizontally at a speed of 10. 50 m·s-1

Answers

The velocity of the child and the boat after throwing the rock is 0.705 m/s in the opposite direction of the rock.

Let us solve the given problem by the application of the law of conservation of momentum. Since the system was at rest initially, therefore, its momentum before throwing of the rock is zero.Now let's see the momentum of the system after throwing of the rock. According to the law of conservation of momentum,The total momentum of the system remains conserved and zero. Hence the momentum of the boat and the child will be equal and opposite to the momentum of the rock.momentum of the rock = mvwhere,m = 5.61 kgv = 10.5 m/smomentum of the rock = 5.61 × 10.5 = 58.965 N sAs per the law of conservation of momentum, the total momentum of the system remains conserved and zero.After throwing the rock, the momentum of the boat and the child in the opposite direction is given by;momentum of the boat and the child = 58.965 N sBut the child and the boat were at rest initially, so their momentum was zero.Therefore, the momentum of the child and the boat together after throwing the rock is equal and opposite to the momentum of the rock.The momentum of the child and the boat is given by;momentum of the child and the boat = - 58.965 N s (opposite direction)We know that momentum is the product of mass and velocity.i.e., p = mvWhere, p = momentumm = massv = velocityThe mass of the child is m1 = 30.5 kgThe mass of the boat is m2 = 53 kg The mass of the child and the boat is given by; m1 + m2 = 30.5 + 53 = 83.5 kgLet the velocity of the child and the boat be V. Therefore the momentum of the child and the boat is given by;Momentum of the child and the boat = (m1 + m2)VLet's apply the principle of the law of conservation of momentum to calculate the velocity of the child and the boat after throwing the rock. The momentum of the rock before throwing = momentum of the rock after throwing. The momentum of the child and the boat before throwing = the momentum of the child and the boat after throwing. Therefore, the equation will be;momentum of the rock before throwing = momentum of the child and the boat after throwing

5.61 × 0 = (m1 + m2)V + (-58.965)83.5V = 0.705 m/s.

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Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.

Answers

The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.

In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.

The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.

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Please answer correctly cause I am not really sure..

Is this statement true or false?
There are SEVEN days between a NEW MOON and a FIRST QUARTER MOON.

Answers

The full cycle of moon phases averages 29.531 days. A quarter of that is 7.38 days. So "7 days" is a pretty good approximation for casual conversation. It's true.

Answer:True

Explanation:

The full cycle of the moon is 29.631 or we could say 29.5 and the quarter is 7.34 I think so yes it’s true it’s appropriately a full average and if you subtract this two it true

I load a 0.4 kg marble into a slingshot and shoot it directly upward by applying a 36.2 N force
stretching it a distance of 10 cm. How fast is the marble traveling when it is initially released from
the slingshot? How high does the marble go?

Answers

Answer:50mph

Explanation:

A box of weight W = 500 N is set on a light plank d = 5 meters from a fulcrum. A force F is applied to the plank on the opposite side of the fulcrum a distance D = 10 meters from the fulcrum, as shown. What minimum force is required to lift the box?

A box of weight W = 500 N is set on a light plank d = 5 meters from a fulcrum. A force F is applied to

Answers

Given data

*The weight of the box is W = 500 N

*The distance of the plank from the fulcrum is d = 5 m

*The given force at a distance from the fulcrum is D = 10 m

The minimum force is required to lift the box is given by the net torque as

\(\begin{gathered} \tau=0 \\ W\times d-F\times D=0 \\ W\times d=F\times D \end{gathered}\)

Substitute the known values in the above expression as

\(\begin{gathered} 500\times5=F\times10 \\ F=250\text{ N} \end{gathered}\)

Hence, the minimum force is required to lift the box is F = 250 N

A 43 gram mass carrying a charge of 9 μC is suspended in a vertical upward-directed electric field. What is the magnitude of the electric field?

Answers

Answer:

down below in image

Explanation:

A 43 gram mass carrying a charge of 9 C is suspended in a vertical upward-directed electric field. What

The magnitude of the electric field is approximately 46,822 N/C.

To find the magnitude of the electric field, we can use the equation:

E = F / q

Where:

E is the electric field strength

F is the force acting on the mass

q is the charge on the mass

Given:

Mass (m) = 43 grams = 0.043 kg

Charge (q) = 9 μC = 9 × 10^(-6) C

Gravity (g) = 9.8 m/s² (acceleration due to gravity)

The force acting on the mass is the gravitational force:

F = m g

Substituting the values:

F = 0.043 kg × 9.8 m/s²

F = 0.4214 N

Now  calculate the electric field strength:

E = F / q

E = 0.4214 N / 9 × 10^(-6) C

E = 46,822 N/C

Therefore, the magnitude of the electric field is approximately 46,822 N/C.

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How does inertia relate to forces

Answers

Answer:

Even in space, objects have mass. And if they have mass, they have inertia. That is, an object in space resists changes in its state of motion. A force must be applied to set a stationary object in motion.

A car and a large truck traveling at the same speed collide head-on and stick together. Which vehicle experiences the larger change in the magnitude of its momentum

Answers

Answer:

Both vehicles experience the same change in momentum

Explanation:

Let m represent the mass of the vehicle, and 2m represent the mass of the large truck, and let v represent their initial speed, we have;

The total initial momentum, \(p_i\) given as follows;

\(p_i\) = 2·m·v - m·v = m·v

The total final momentum, \(p_f\) = (2·m + m) × \(v_f\)

By the principle of conservation of linear momentum, the total initial momentum = The total final momentum

m·v = (2·m + m) × \(v_f\)

m·v = 3·m·\(v_f\)

∴ v = 3 × \(v_f\)

\(v_f\) = v/3

The change in the momentum for the large truck = 2·m·v - 2·m·\(v_f\)

Therefore;

The change in the momentum for the large truck = 2·m·v - 2·m·v/3 = 2·m·(v - v/3)

The change in the momentum for the large truck = 2·m·(v - v/3) = 2·m·2·v/3 =  4·m·v/3

The change in the momentum for the car = m·v - m·(-\(v_f\)) = m·v - m·(-v)/3 = m·v + m·(v)/3 = 4·m·v/3

Therefore, the change in the momentum for the large truck = The change in the momentum for the car and both vehicles experience the same change in momentum.

The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, how far does he travel while stopping?

Answers

Answer:

\(9.5\; {\rm m}\).

Explanation:

Let \(u\) and \(v\) denote the velocity of this hockey player before and after stopping, respectively. The question states that \(u = 9.5\; {\rm m\cdot s^{-1}}\) and implies that \(v = 0\; {\rm m\cdot s^{-1}\) since the hockey player has come to a stop.

The duration of this acceleration is \(t = 2\; {\rm s}\).  

Since the acceleration of this hockey player was constant, SUVAT equation would apply. In particular, the SUVAT equation \(x = (1/2)\, (v + u) \, (t)\) gives the displacement \(x\) of this hockey player during that \(2\; {\rm s}\) of acceleration:

\(\begin{aligned} x &= \frac{1}{2}\, (9.5\; {\rm m\cdot s^{-1}} + 0\; {\rm m\cdot s^{-1}})\, (2\; {\rm s}) = 9.5\; {\rm m} \end{aligned}\).

In other words, this hockey player would have travelled \(9.5\; {\rm m}\) while stopping.

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