Three-fourths of the animals at an animal shelter are dogs. One-sixth of the dogs are beagles. What fraction of the animals at the animal shelter are beagles?

For least amount of fencing, length and width of rectangular area should be 14 feet and 7 feet respectively.

Let us consider length and width are l and w respectively.

Area of rectangular region = l x w

l x w = 98

w = 98/l

Since, no fencing needed along the river.

So, perimeter of rectangular region, P = 2w + l

Substituting the value of w in above expression.

We get,    

P = 2(98/l) + l

= 196 /l + l

For least amount of fencing, perimeter should be minimum

Differentiate perimeter expression with respect to length l.

dP/dl = -196/l^2 +1 =0

l^2 = 196

l= sqrt(196)

l= 14 feet

so, w= 98/14

w = 7

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Answer:

\(C(99,55)\,C(33,22)\,C(44,33)\)

Step-by-step explanation:

A permutation refers to arrangement of the objects or numbers in order.  Combinations refers to selecting the objects or numbers from a group of objects or collection such that the order of the objects does not matter.

A delegation of 55 Republicans, 22 Democrats, and 33 Independents is selected from a group of 99 Republicans, 33 Democrats, and 44 Independents.

So,

Number of ways \(=C(99,55)\,C(33,22)\,C(44,33)\)

Answer 7/12

Step-by-step explanation:

Answer:

Step-by-step explanation:

The radius is the length from the center dot to the circle.

They gave you the radius

r=6 1/4 in

Answer:

12-3y-2x+x+2x = x-3y+12

3x+2y-2x+y+12 = x+3y+12

4y+3y+3x-6y-10-2 = 3x+y-12

x+3y+2x-3x+7+5 = 3y+12        

Step-by-step explanation:

Answer:

(a)

\(\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}\)

(b): Cell industry

(c) See Explanation

Step-by-step explanation:

Given (Missing from the question)

\(Bank = 26\)

\(Cable = 44\)

\(Car = 42\)

\(Cell = 60\)

\(Collection = 28\)

\(Total = 200\)

Solving (a) Show the frequency and percent frequency.

The percentage frequency is calculated by:

\(\%Freq = \frac{Freq}{Total} * 100\%\)

So. we have:

\(\%Freq = \frac{26}{200} * 100\% = 13\%\) --  Bank

\(\%Freq = \frac{44}{200} * 100\% = 22\%\) --- Cable

\(\%Freq = \frac{42}{200} * 100\% = 21\%\) --- Car

\(\%Freq = \frac{60}{200} * 100\% = 30\%\) --- Cell

\(\%Freq = \frac{28}{200} * 100\% = 14\%\) --- Collection

The table becomes:

\(\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}\)

Solving (b): The industry with the highest complaints

From the above table, the highest frequency is 60 and this represents the number of complaints of Cell industry.

Hence, the cell industry has the highest number of complaints

Solving (c): Comment

The percentage frequency table shows that the industry with the highest number of complaints is the cell industry (at 30%) and the industry with the least is the banking industry (at 13%)

we have

7/10 and 2/3

so

10=2*5

3=3*1

the LCM=2*5*3=30

therefore

the answer is 30

Rewrite the fractions with the common denominator

7/10 -----> multiply by 3/3 ------> 21/30

2/3 -----> multiply by 10/10 ----> 20/30

Answer:

To convert euros to pounds, we have to multiply the amount in euros by the exchange rate. So, the sunglasses cost 90 * 0.875 = 78.75 pounds.

To use a suitable approximation, we can round the exchange rate to the nearest hundredth, which is 0.88. This makes the calculation easier and gives a close estimate of the actual value.

Using the rounded exchange rate, the sunglasses cost 90 * 0.88 = 79.2 pounds.

We can see that both the exact and the approximate values are greater than 70 pounds, so Elyas is wrong. The sunglasses cost more than 70 pounds

Step-by-step explanation:

Answer:

33 , 39

Step-by-step explanation:

given

9 , 15 , 21 , 27

there is a common difference between consecutive terms, that is

15 - 9 = 21 - 15 = 27 - 21 = 6

to obtain terms in the sequence add 6 to the preceding term

27 + 6 = 33

33 + 6 = 39

the next two terms are 33 and 39

Answer: 20

Step-by-step explanation: ABCD Equals 80 so each side would be 20. 20 , 40 , 60 , "80".

Answer:

the answer is 20 i got it right on the test

Step-by-step explanation:

Answer:

24j + 24

Step-by-step explanation:

6(3j + 4 +j)

6(4j + 4)

24j + 24

Answer: 20

Step-by-step explanation:

2x^2 + 4y=

2(2)^2 + 4(3)=

2(4)+12=

8+12=20

Answer:

The required probability for the high temperature which 90% of the August days exceed. is 0.0333

Step-by-step explanation:

High temperatures in a certain city for the month of August follow a uniform distribution over the interval 61° F  to 91° F   . Find the high temperature which 90°  F of the August days exceed.

Let assume that X is the random variable

The probability mass function is:

\(f(x) = \dfrac{1}{b-a}\)

\(f(x) = \dfrac{1}{91-61}\)

\(f(x) = \dfrac{1}{30}\)

Thus; The probability density function of X can be illustrated as :

\(f(x) = \left \{ {{ \ \ \dfrac{1}{30}} \atop { \limits }}_ \right. _0\)       61 <  x < 91  or otherwise

The required probability for the high temperature at 90°  F can be calculated as follows:

\(P(X> 90) = \int\limits^{91}_{90} {f(x)} \, dx\)

\(P(X> 90) = \int\limits^{91}_{90} \ {\dfrac{1}{30} \, dx\)

\(P(X> 90) = {\dfrac{1}{30} \int\limits^{91}_{90} \ \, dx\)

\(P(X> 90) = {\dfrac{1}{30} [x]^{91}_{90}\)

\(P(X> 90) = {\dfrac{1}{30} (91-90)\)

\(P(X> 90) = {\dfrac{1}{30} \times 1\)

\(P(X> 90) = 0.0333\)

The required probability for the high temperature which 90% of the August days exceed. is 0.0333

Answer:

Step-by-step explanation:

10 plzz give me brainliest see ya

Answer:

2x² + 5x + c = 0

For this quadratic equation to have one double root, the discriminant must equal 0.

5² - 4(2)(c) = 0

25 - 8c = 0

c = 25/8

2x² + 5x is not a perfect square because the coefficient of x², 2, is not a perfect square.

2x² + 5x is not a perfect square.

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Answer:

16 deliveries

Step-by-step explanation:

238 ≤ 10d + 78

160 ≤ 10d

16 ≤ d

Thus, he needs to make at least 16 deliveries to make at least $238 in one day.  Any less than 16 deliveries will cause him to fall short of his goal and any more than 16 deliveries will cause him to exceed his goal.

Answer:

It is False

Step-by-step explanation:

16>17 is not a true statement.

Answer:

Definitely B

Step-by-step explanation:

Answer:

It's D guys

Step-by-step explanation:

Answer:

(x-2)^2 + (y+2)^2 = 25

Step-by-step explanation:

First calculate the center using the midpoint formula

Mpq=(xP/2 + xQ/2) ; (yP/2 +yQ/2)

=(- 2/2 + 6/2) ; (1/2 + -5/2)

=(2;-2) coordinates of the center

Use the general formula (x-a)^2 + (y-a)^2 =r^2 to find equation and the radius.

Substitute the coordinates of the center

(x-2)^2 + (y+2)^2 = r^2

Substitute the point (-2,1) for the value of r^2

(-2-2)^2 + (1+2)^2 = r^2

r^2 = 25

The equation is (x-2)^2 + (y+2)^2 = 25

Answer:

\(z^{-4} ; ~~ or ~~ \dfrac{1}{z^4}\)

Step-by-step explanation:

          \(\bf a^n * a^m = a^{m+n}\\\\(a^x)^y = a^{x*y}\\\\a^{-m}=\dfrac{1}{a^m}\)

\(\sf (Z^7*z^{-5})^{-2} = (Z^{7 +(-5)})^{-2}\)          {When bases are same, add the exponents}

                   \(= (z^2)^{-2}\\\\= z^{2*(-2)} ~~ {\bf [(a^m)^n=a^{m*n}]}\\\\=z^{-4}\\\\=\dfrac{1}{z^4} ~~ {\bf[a^{-m}=\dfrac{1}{a^m}]}\)

Answer:

Step-by-step explanation:

Circumference would be if the situation is asking for the amount of something around the edge. For example, the number of tiles to be placed around the swimming pool would be asking for circumference.

Area would be if the situation is asking for the amount of something spread through the entire item. For example, the amount of water total in a swimming pool would be asking for area.

Hope it helps!

Check the picture below.

so hmm we have a 6x6 square atop and a triangle with base of 6 and a height of "h", let's get "h".

\(\sin( 42^o )=\cfrac{\stackrel{opposite}{h}}{\underset{hypotenuse}{2}} \implies 2\sin(42^o)=h \implies 1.34\approx h \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \textit{\LARGE Areas} }{\stackrel{triangle}{\cfrac{1}{2}(\underset{b}{6})(\underset{h}{1.34})}~~ + ~~\stackrel{ square }{(6)(6)}} ~~ \approx ~~ 4.02+36~~ \approx ~~ \text{\LARGE 40.0}\)

Answer:

y=50+12x y=100+9x

Step-by-step explanation:

Answer and Step-by-step explanation:

To find out how many more yards of red fabric Reuben used, we need to subtract the amount of yellow fabric from the amount of red fabric. Since the two fractions have different denominators, we need to find a common denominator before subtracting them. The least common multiple of 8 and 4 is 8, so we can rewrite both fractions with a denominator of 8:

7/8 - 1/4 = 7/8 - (1/4) * (2/2) = 7/8 - 2/8 = (7 - 2)/8 = 5/8

So, Reuben used 5/8 yards more red fabric than yellow fabric.

Answer and Step-by-step explanation:

This problem involves the use of trigonometric functions.

First, we will use the tangent trig function, and then the sine trig function.

\(tan(32) = \frac{x}{15}\)

We solve for x by multiplying both sides by 15.

15(tan(32)) = x

Put this into a calculator and solve.

x = 9.373

Now, we solve for y.

\(sin(32) = \frac{9.373}{y}\)

We multiply by y on both sides first.

y(sin(32)) = 9.373

Now, we divide each side by sin(32).

\(y = \frac{9.373}{sin(32)}\)

Put this into a calculator and solve.

y = 17.6877

x = 9.373

y = 17.6877

These are your answers.

#teamtrees #WAP (Water And Plant)

The mean for Jeremy's data set is 19

From the question, we have the following parameters that can be used in our computation:

20, 37, 4, 2, 35, 33, 2

To find the mean of Jeremy's data set, we need to add up all the numbers in the set and then divide by the total number of numbers in the set:

Mean = (20 + 37 + 4 + 2 + 35 + 33 + 2) / 7

Mean = 133 / 7

Mean = 19

Hence, the mean of Jeremy's data set is 19.

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Answer:

6.79%

Step-by-step explanation:

1.00 - 3=0.97

7 * 0.97 = 6.79

Distributive because he changed the fractions to the way it would go.

Answer:

-2<=y<=-7

Step-by-step explanation: