this is the chemical formula for talc (the main ingredient in talcum powder):an analytical chemist has determined by measurements that there are moles of silicon in a sample of talc. how many moles of hydrogen are in the sample?be sure your answer has the correct number of significant digits.

Answer:

Sodium hydroxide is deliquescent (absorbs moisture from the atmosphere) solid. It cannot be weighed accurately. Therefore, it is not possible to prepare a standard solution of sodium hydroxide of accurately known concentration by weighing NaOH.

Answer:

firer burning I'm thinking

Answer:Is sugar water a mixture or a compound? Define mixtures and compounds, and explain how without tasting it, Nicole can test to make sure she is using the sugar water in the glaze. The sugar-water is a mixture because it is chemically bonded, not chemically combined. A mixture is something that has 2 substances or more. hope this helps

Explanation:

Answer:

There are 0.1 moles of solute in 250 mL of 0.4 M solution

Explanation:

because it is

The mass of NaCl required to raise the boiling point of 4.73 L of water by 1.00°C is 25.3 g.

The boiling point elevation (ΔTb) is given by the equation ΔTb = Kb × molality, where Kb is the boiling point elevation constant for water (0.51°C/m) and molality is the concentration of solute in mol/kg of solvent. To calculate the molality, we need to convert the volume of water to mass (assuming a density of 1 g/mL) and calculate the number of moles of water. We have:

To raise the boiling point by 1.00°C, we need to find the molality that gives a ΔTb of 1.00°C. Rearranging the equation above, we get:

Now we can calculate the mass of NaCl required to achieve this molality:

Therefore, the mass of NaCl required to raise the boiling point of 4.73 L of water by 1.00°C is 25.3 g (since 550 g is more than the mass of water).

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Answer:

the substance of the composition change the

properties.

Answer:

It's a metaphor. It's comparing Jordan and their emotions to a tornado

According to specific heat capacity, 3360 J are released when a 8.00-gram sample of water changes from liquid to solid at 0°C.

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

Substituting values in above formula Q= 8×4.2×(100-0)=3360 J.

Thus, 3360 J are released  when a 8.00-gram sample of water changes from liquid to solid at 0°C.

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Answer:

nitrate C U N 03 twice and silver To G. This is the balanced reaction. And in the kitchen ...

There are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.

The number of moles of a substance can be calculated by using the following formula:

molarity = no. of moles / volume

According to this question, a volume of 2300 mL solution is contained in 0.68 M MgSO4. The number of moles is calculated as follows:

no of moles = 0.68M × 2.3

no. of moles = 1.56

Therefore, there are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.

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Answer:

Propane

Explanation:

Hubless cast-iron piping shall be supported every other joint, unless over six feet in length, then it shall be provided with support at every joint.

According to the 2021 edition of the International Plumbing Code (IPC), Hubless cast-iron piping shall be supported every other joint unless the length exceeds 10 feet. In that case, it shall be provided with support at every joint. It's important to note that plumbing codes and regulations can vary by jurisdiction, so it's always best to consult the specific plumbing code applicable to your location for accurate and up-to-date information.

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Answer:

200

Explanation:

Answer:

A bee sting has a ph of 5, and is therefore an acid. Litmus paper goes red (or stays red) in acidic solutions.

Answer:

The Blue Litmus Paper should turn red

Explanation:

Bee venom has a pH of 5.5, which means it is mildly acidic which in turn should make the Litmus paper turn Red. Hope this helps!

Step 1

The reaction must be completed and balanced as follows:

C3H8 + 5 O2 => 3 CO2 + 4 H2O

-------------

Step 2

Information provided:

20.0 g of C3H8

10.0 g of O2

----

Information needed:

1 mole of C3H8 = 44.1 g

1 mole of O2 = 32.0 g

(use your periodic table please)

-------------

Step 3

By stoichiometry,

C3H8 + 5 O2 => 3 CO2 + 4 H2O

44.1 g C3H8 ---------- 5 x 32.0 g O2

20.0 g C3H8 ---------- X

X = 20.0 g C3H8 x 5 x 32.0 g O2/44.1 g C3H8

X = 72.6 g O2

For 20.0 g of C3H8, 72.6 g of O2 is needed, but there is only 10.0 g of O2.

Therefore,

Answer:

The limiting reactant = O2

The excess = C3H8

Ba(N03)2 is the unknown compound. correct option is (C).

Na2So4 -----> precipitate

Nacl ---------> No reaction

Na2Co3 --------> precipitate

Ba (No3)2 + Na2So4 -----------> BaSo4 (s) + 2 NaNo3 (aq)

Here white precipitate of barium sulphate will be produced.

Ba (No3)2 + Na2Co3 ------------> BaCo3 (s) + 2NaNO3 (aq)

Here white precipitate of barium carbonate will be produced.

Titration is a process of chemical analysis in which the quantity of some constituent of a sample is determined by adding to measured sample to an exactly known quantity of another substance with which the desired constituent reacts in a definite, known proportion.

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The initial concentration of Co(NO3)2 is 0.05 M and NaOH is 0.1 M. NaOH is the limiting species, and 0.084 g of Co(OH)2 precipitate should be obtained.

a) Concentration of Co(NO3)2 = 0.05 M, concentration of NaOH = 0.1 M

b) Molecular equation: Co(NO3)2(aq) + 2NaOH(aq) -> Co(OH)2(s) + 2NaNO3(aq)

  Net ionic equation: Co2+(aq) + 2OH-(aq) -> Co(OH)2(s)

c) NaOH is the limiting species.

d) 0.084 g of Co(OH)2 precipitate should be obtained.

e) The percent yield is 51.6%.

In this problem, we're given the initial masses of Co(NO3)2 and NaOH, as well as the volume of water in which they are dissolved. From this information, we can calculate the initial concentrations of each species. Next, we write out the balanced molecular and net ionic equations for the reaction, which involves a double replacement reaction between Co(NO3)2 and NaOH to form Co(OH)2 precipitate and NaNO3.

To determine which species is limiting, we compare the stoichiometry of the reactants and determine that NaOH is limiting. Using stoichiometry, we calculate the mass of Co(OH)2 precipitate that should be obtained if the reaction goes to completion. Lastly, we can calculate the percent yield of the reaction by comparing the actual mass of product obtained to the theoretical yield.

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Answer:

0.84kg of gatorade powder is needed.

Explanation:

From the question given above, we were told that the team manager mixes 0.6kg of gatorade powder with 5 gallons of water.

Now, to obtain the desired amount of the powder of gatorade needed for 7 gallons of water, we simply do the following:

If 0.6kg of gatorade powder required 5 gallons of water,

Then Xg of gatorade will require 7 gallons of water i.e

Xg of gatorade = (0.6 x 7)/5

Xg of gatorade = 0.84kg

Therefore, to maintain the same gatorade mixture, the team manager must mix 0.84kg of gatorade powder with the 7 gallons of water.

Answer:

where is the questions........

Answer:Wavelength can be defined as the distance between two successive crests or troughs of a wave. It is measured in the direction of the wave. Description: Wavelength is the distance from one crest to another, or from one trough to another, of a wave (which may be an electromagnetic wave, a sound wave, or any other wave).

Answer:

Is this from edge?

if so which lesson is it from and is this an assignment or a quiz?

I think the answer is C (Much of the evidence for evolution comes from fossils.)

A fossil is the remains or traces of organisms that lived in the past.The statement is true about fossils is much of the evidence for evolution comes from fossils. Therefore, option C is correct.

Any surviving remains, impression, or evidence of a once-living thing from a previous geological epoch is referred to as a fossil. Examples include exoskeletons, bones, shells, animal or microbe imprints in stone, items preserved in amber, hair, petrified wood, and DNA traces. The fossil record is the collection of all fossils.

The remains or evidence of prehistoric life that have been preserved by natural processes are known as fossils. Shells, bones, animal or microbe imprints in stone, exoskeletons, items preserved in amber, petrified wood, coal, hair, oil, and DNA traces are a few examples of fossils.

The majority of fossils are created when a living thing (such as an animal or plant) dies and is swiftly buried by sediment (such as mud, sand or volcanic ash).

Thus, option C is correct.

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Answer:

See explanation

Explanation:

An ionic bond involves the transfer of electrons from one atom to another. Typically, ionic bond occurs between a metal and a non metal such as between Na and Cl.

A polar covalent bond occurs between  two elements having a significant difference in elctronegativity. As a result of this, the shared electron pair is closer to the more electronegative atom thereby making the molecule polar.

A covalent bond involves the sharing of electrons between two atoms that are very close in electronegativity values.  The shared electron pair is located at an equidistant position from the nucleus of the both bonding atoms.

For MgCl2, the electronegativity difference is 3.0 - 1.2 = 1.8, the bond is ionic

For F2, the electronegativity difference is 4.0 -4.0 = 0, it is a pure covalent bond.

For NaCl, the electronegativity difference is 3.0 - 0.9 = 2.1, the bond is ionic

The following chemical equations have been balanced using the appropriate coefficients.

Mg(OH)2 + NaCl → MgCl2 + 2NaOH

H2SO4 + BaCl2 → BaSO4↓ + 2HCl

AgNO3 + Fe(NO3)2 → AgFeO2↓ + 2NO3

Balancing chemical equations in chemistry involves adjusting the coefficients of the reactants and products in a chemical reaction so that the number of atoms of each element is equal on both sides of the equation.

Note: Never change the subscripts in a chemical formula to balance an equation. Only coefficients can be changed.

Mg(OH)2 + NaCl → MgCl2 + 2NaOH

H2SO4 + BaCl2 → BaSO4↓ + 2HCl

AgNO3 + Fe(NO3)2 → AgFeO2↓ + 2NO3

MgCl2 + 2NaOH → Mg(OH)2↓ + 2NaCl

3NaOH + Fe2(SO4)3 → Fe(OH)3↓ + 3Na2SO4

Pb(NO3)2 + 2KCl → PbCl2↓ + 2KNO3

MgSO4 + BaCl2 → MgCl2 + BaSO4↓

Cu(NO3)2 + 2KOH → Cu(OH)2↓ + 2KNO3

Al(OH)3 + NaOH → NaAlO2 + 2H2O

BaCO3 + H2SO4 → BaSO4↓ + CO2↑ + H2O

ZnCl2 + 2AgNO3 → 2AgCl↓ + Zn(NO3)2

BaSO4 + 2KOH → Ba(OH)2↓ + K2SO4

Fe(NO3)3 + 3KOH → Fe(OH)3↓ + 3KNO3

NaHCO3 + KHCO3 → NaKHCO3 + H2O + CO2↑

Ba(OH)2 + Na2CO3 → BaCO3↓ + 2NaOH

Al + H2SO4 → Al2(SO4)3 + H2↑

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The growth of the balloon after being taken out of liquid nitrogen is a result of the increase in temperature, which leads to an increase in the kinetic energy and speed of the gas molecules, causing them to spread out and expand, resulting in the expansion of the balloon.

The phenomenon you are describing, where a small, partially inflated balloon grows in size after being taken out of liquid nitrogen, can be explained by the principles of gas expansion due to temperature change.

When the balloon is submerged in liquid nitrogen, it is exposed to an extremely low temperature. As a result, the air molecules inside the balloon lose thermal energy and their average kinetic energy decreases. This decrease in kinetic energy causes the molecules to slow down and move closer together, leading to a decrease in pressure and volume of the gas inside the balloon.

When the balloon is removed from the liquid nitrogen and placed on the table, it starts to warm up. As the temperature increases, the air molecules regain thermal energy and their average kinetic energy rises. This increase in kinetic energy causes the molecules to move faster and spread out, leading to an increase in pressure and volume of the gas inside the balloon.

Furthermore, gases typically exhibit a property known as Thermal expansion, which means they expand when heated and contract when cooled. As the temperature of the air inside the balloon rises, the gas expands, causing the balloon to grow in size.

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True. "Almost 1 in 5 traffic crashes in Texas involve driver distraction". This means that approximately 20% of traffic crashes in Texas are caused by driver distraction.

Driver distraction refers to any activity that diverts the attention of the driver from the task of driving, which includes visual, manual, or cognitive distractions. Examples of driver distractions include texting or talking on the phone, eating or drinking, talking to people in the vehicle, or even using in-car technologies such as navigation systems.

To reduce the risk of driver distraction, it is important for drivers to prioritize their attention and focus on the task of driving. This means avoiding activities that take their eyes off the road, hands off the wheel, or mind off the driving task.

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The pH of the buffer after the addition of 0.068 mol NaOH is calculated to be approximately 11.02.

To determine the pH of the buffer after the addition of NaOH, we need to consider the reaction that occurs between NaOH and the components of the buffer, which are HBr and ethylamine C₂H₅NH₂.

The reaction between NaOH and HBr is a neutralization reaction:

HBr + NaOH → NaBr + H₂O

This reaction consumes HBr and produces water. The reaction between NaOH and ethylamine is an acid-base reaction:

NaOH + C₂H₅NH₂ → NaC₂H₅NH₂ + H₂O

This reaction consumes NaOH and produces ethylamine salt (sodium ethylamine) and water.

Given that 0.068 mol of NaOH is added, we need to determine which component of the buffer is limiting and calculate the remaining amounts of each component.

moles of HBr = (0.0805 L) x (1.05 mol/L) = 0.084525 mol

moles of ethylamine = (0.2049 L) x (0.953 mol/L) = 0.1955097 mol

Given the moles NaOH = 0.068 mol

Since the moles of HBr (0.084525 mol) is greater than the moles of NaOH (0.068 mol), HBr is the limiting component.

So, the remaining moles HBr

= moles HBr - moles NaOH

= 0.084525 mol - 0.068 mol

= 0.016525 mol

Volume of the buffer = 0.0805 L + 0.2049 L = 0.2854 L

The final concentration of HBr

= remaining moles HBr / volume of the buffer

= 0.016525 mol / 0.2854 L ≈ 0.0579 M

So, pOH

=\(-log_{10}(Kb) + log_{10}(concentration of the ethylamine)\)

= \(-log10(4.5 \times 10^{-4}) + log_{10}(0.953 M)\)

≈\(-log10(4.5 \times 10^{-4}) + 0.9793\)

pH = 14 - pOH

  ≈ \(14 - (-log_{10}(4.5 \times 10^{-4}) + 0.9793) \approx 11.2\)

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