This is really easy but I’m lazy

294 gumballs were added because if u subtract 230 from 1696 you get 1466 which was the number you had when you are 230 gumballs so you take 1466 and subtract it from 1760 you get the amount of gumballs that was added.

just like this other lady said 294 gumballs were added

We have the following equation for the lateral surface area of a triangular prism:

where a,b and c are the measures of the sides of the triangular base.

In this case, we have the following:

using the formula, we get:

now, we can solve for h to find the height:

therefore, the height of the solid is 31 cm

The graph of the solution to the inequality 5/8z > 5/6 is attached

From the question, we have the following parameters that can be used in our computation:

5/8z > 5/6

Multiply both sides of the inequality by 1/5

So, we have the following representation

1/8z > 1/6

Multiply both sides of the inequality by 8

So, we have the following representation

z > 8/6

Evaluate the quotient

This gives

z > 1.33

The above inequality means that the inequality starts from 1.33 and faces the right side

See attachment for the graph

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Step-by-step explanation:

perimeter of a rectangle = 2×length + 2×width = 28 ft

width = length - 2

length = width + 2

2×(width + 2) + 2×width = 28

2×width + 4 + 2×width = 28

4×width + 4 = 28

4×width = 24

width = 6 ft

and the length is width + 2 = 6+2 = 8 ft.

Answer:

D

Step-by-step explanation:

Took the test

9514 1404 393

Answer:

  126

Step-by-step explanation:

If n represents the original number, we have

  (35%)n = 98

  (80%)n = 224

We want to find (45%)n.

  (45%)n = (80% -35%)n = (80%)n -(35%)n

  (45%)n = 224 -98 = 126

45% of the number is 126.

Answer:

Not a random variable

Step-by-step explanation:

The last book a person read in City A is not a random variable because it is not a number as there is no numerical description for the outcome of this experiment.

Thus, the last book read by someone in City A is not a random variable.

Answer:

not random

Step-by-step explanation:

let's firstly convert the mixed fraction to improper fraction and proceed from there.

\(\stackrel{mixed}{2\frac{1}{4}}\implies \cfrac{2\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{9}{4}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{9}{4}\div \left(\cfrac{3}{8}\div \cfrac{1}{2} \right)\implies \cfrac{9}{4}\div \left(\cfrac{3}{8}\cdot \cfrac{2}{1} \right)\implies \cfrac{9}{4}\div \left(\cfrac{3}{4} \right) \\\\\\ \cfrac{9}{4}\cdot \left(\cfrac{4}{3} \right)\implies \cfrac{9}{3}\cdot \cfrac{4}{4}\implies 3\cdot 1\implies \text{\LARGE 3}\)

Answer: 180 cm2

if you add up all the sides you'll get 36 in total. if you divide the answer choices by 5 (the number of sides) in ONE (180 cm2) of the answers you'll get 36.

\(~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3^{2-x}=1\implies 3^2\cdot 3^{-x}=1\implies 3^2\cdot \cfrac{1}{3^x}=1\implies \cfrac{3^2}{3^x}=1 \\\\\\ 3^2=3^x\implies 2=x\)

The reading that separates the rejected thermometers from the others is given as follows:

1.175 ºC.

The z-score of a measure X of a normally distributed variable that has mean represented by \(\mu\) and standard deviation represented by \(\sigma\) is obtained by the equation presented as follows:

\(Z = \frac{X - \mu}{\sigma}\)

The mean and the standard deviation for this problem are given as follows:

\(\mu = 0, \sigma = 1\)

The 12% higher of temperatures are rejected, hence the 88th percentile is the value of interest, which is X when Z = 1.175.

Hence:

1.175 = X/1

X = 1.175 ºC.

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The area of the shaded region is 559 ft².

In order to find the area of the shaded region, we will subtract the area of the square from the area of the rectangle. That is:

area of the shaded region = area of rectangle - area of square

area of the shaded region = (32 * 20) - (9 * 9)

area of the shaded region = 640 - 81

area of the shaded region = 559 ft²

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Complete Question

See attached image

The correct answer is C) 9.9 lbs as it is above the upper boundary 6.4865, it is the outlier in this dataset.

An outlier is an observation that is much higher or lower than the other observations in a dataset.

In this case, the weights of the catfish range from 2.7 to 4.8 lbs, with one observation that is much higher at 9.9 lbs.

Therefore, 9.9 lbs is the outlier in this dataset.

To find the outlier in this dataset, we can calculate the interquartile range (IQR).

This is done by first calculating the first quartile (Q1) and third quartile (Q3).

The Q1 for this dataset =3.75

and the Q3= 4.675.

IQR= Q3 - Q1

= 0.925.

We then calculate the lower boundary as Q1 - (1.5 x IQR) = 2.3625.

The upper boundary is Q3 + (1.5 x IQR)= 6.4865.

Since 9.9 lbs is above this upper boundary, it is the outlier in this dataset.

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Answer:

1) 13 inches

2) 2z=x

3) 48 inches

Step-by-step explanation:

it snows 4/2 = 2 inches perhour

1. 2x 6.5 = 13 inches

2. y = 2z

3. 2x 24 = 48 inches

Answer:

Package

Step-by-step explanation: Hope it helps.

The length of midsegment of the trapezoid is MN = 66.5 units

The midsegment of a trapezoid is a line segment that connects the midpoints of the legs of the trapezoid.

The midsegment of a trapezoid is parallel to each base, and its length is one-half the sum of the lengths of the bases.

In this case, length of midsegment of the trapezoid will be:

MN = 1/2 × (76 + 57)

MN = 1/2 × (133)

MN = 66.5 units

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Answer:

yes???

Step-by-step explanation:

16 celsius is warmer than 0 celsius by 16 degrees.0 is colder by 16 degrees.

T o T hope that helped...

Complete Question

The complete question is shown on the first uploaded image  

Answer:

a

\(P(X < 65) =  0.003467\)

b

\(P(86 <  X <  110 )= 0.63928 \)

c

\(P(X > 120 ) =0.062024\)

Step-by-step explanation:

From the question we are told that

 The  mean is  \(\mu  =  \$ 100\)

 The  standard deviation is  \(\sigma  =  \$ 13\)

 Generally the probability that the  monthly utility bills is less than  $65  is  mathematically represented as

     \(P(X < 65) =  P(\frac{X  -  \mu }{\sigma }  < \frac{65  -  100 }{13 }   )\)

Generally

  \(\frac{X  -  \mu }{\sigma } =  Z (The\ standardized \ value \ of\  X )\)

So

 \(P(X < 65) =  P(Z < -2.70  )\)

From the z-table

    \(P(Z < -2.70  ) =  0.003467\)

So  

   \(P(X < 65) =  0.003467\)

Generally the  probability that a randomly selected utility bill is between $86​ and $​110 is mathematically represented as

 \(P(86 <  X<  110 )=  P( \frac{86 -100}{ 13} <  \frac{X - \mu}{\sigma } < \frac{86 -100}{ 13}    )\)

=>  \(P(86 <  X <  110 )=  P( \frac{86 -100}{ 13} < Z < \frac{110 -100}{ 13} )\)      

=>    \(P(86 <  X <  110 )=  P(-1.08 < Z < 0.77 )\)      

=>    \(P(86 <  X <  110 )= P(Z < 0.77 ) -  P(Z < -1.08 ) \)    

From the z-table

    \(P(Z < 0.77 ) = 0.77935\)

and  

   \(P(Z < -1.08 ) =  0.14007\)

So

     \(P(86 <  X <  110 )= 0.77935  -  0.14007 \)    

=>   \(P(86 <  X <  110 )= 0.63928 \)    

 Generally the probability that the  monthly utility bills is  more than $120  is mathematically represented as

         \(P(X >120 ) =  P(\frac{X  -  \mu }{\sigma }  > \frac{120  -  100 }{13 })\)

=>   \(P(X > 120 ) =  P(Z > 1.538   )\)

From the z-table

    \(P(Z > 1.54  ) =  0.062024\)

So  

   \(P(X > 120 ) =0.062024\)

The integral of the current I(t) over the interval [a,b] represents the change in the charge Q from time t=a to t=b.

The current in an electrical circuit is defined as the rate at which charge is flowing through a conductor. The equation that represents the current is I(t) = dQ(t)/dt, where Q(t) is the charge at time t and dQ(t)/dt is the derivative of Q(t) with respect to time, representing the rate of change of charge.

The integral of I(t) with respect to time between the limits a and b, i.e. ∫I(t)dt between the limits a and b, represents the change in the charge from time t = a to time t = b. This is because the definite integral of a rate of change gives the total change in the quantity being measured, in this case, the charge.

So, \(\int\limits^a_b {|(t)} \, dt = Q(b) -Q(a)\), which represents the change in the charge from time t = a to time t = b.

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Answer:

Option A

Step-by-step explanation:

-(12 x 2) x (-6) = -12 x (2 x b)

=> -24 x -6 = -12 x 2b

=> 144 = -24b

=> b = -6

Hoped this helped.

Answer:

See below

Step-by-step explanation:

For the second step, \(\angle T\cong\angle R\) by Alternate Interior Angles. The rest of the steps appear to be correct.

Answer:

4

Step-by-step explanation:

in all there is 4 places behind the decimal

Answer:

4

Step-by-step explanation:

17.1768

Answer:

Lower confidence limit = 20.191

Step-by-step explanation:

Sample mean; x' = 22

Sample standard deviation; s = 5.5

Sample size; n = 50

Confidence interval = 99%

Since sample size > 30, we will use the formula;

CI = x' ± zs/√n

Where;

x' is sample mean

s is sample standard deviation

n is sample size

z is z-value of the confidence interval

From the table attached, z for 99% = 2.3263

Thus;

CI = 22 ± (2.3263 × 5.5)/√50

CI = 22 ± 1.809

CI = 23.809 or 20.191

Lower confidence limit = 20.191

Using Maxwell's equations, we can determine the magnetic flux density. One of the Maxwell's equations is:

\(\displaystyle \nabla \times \mathbf{H} = \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t}\),

where \(\displaystyle \nabla \times \mathbf{H}\) is the curl of the magnetic field intensity \(\displaystyle \mathbf{H}\), \(\displaystyle \mathbf{J}\) is the current density, and \(\displaystyle \frac{\partial \mathbf{D}}{\partial t}\) is the time derivative of the electric displacement \(\displaystyle \mathbf{D}\).

In this problem, there is no current density (\(\displaystyle \mathbf{J} =0\)) and no time-varying electric displacement (\(\displaystyle \frac{\partial \mathbf{D}}{\partial t} =0\)). Therefore, the equation simplifies to:

\(\displaystyle \nabla \times \mathbf{H} =0\).

Taking the curl of the given magnetic field intensity \(\displaystyle \mathbf{R} =2\cos( 10^{10} t-600x)\hat{a}_{z}\, \text{Am}\):

\(\displaystyle \nabla \times \mathbf{R} =\nabla \times ( 2\cos( 10^{10} t-600x)\hat{a}_{z}) \, \text{Am}\).

Using the curl identity and applying the chain rule, we can expand the expression:

\(\displaystyle \nabla \times \mathbf{R} =\left( \frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial y} -\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial z}\right) \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Since the magnetic field intensity \(\displaystyle \mathbf{R}\) is not dependent on \(\displaystyle y\) or \(\displaystyle z\), the partial derivatives with respect to \(\displaystyle y\) and \(\displaystyle z\) are zero. Therefore, the expression further simplifies to:

\(\displaystyle \nabla \times \mathbf{R} =-\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial x} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Differentiating the cosine function with respect to \(\displaystyle x\):

\(\displaystyle \nabla \times \mathbf{R} =-2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Setting this expression equal to zero according to \(\displaystyle \nabla \times \mathbf{H} =0\):

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z =0\).

Since the equation should hold for any arbitrary values of \(\displaystyle \mathrm{d} x\), \(\displaystyle \mathrm{d} y\), and \(\displaystyle \mathrm{d} z\), we can equate the coefficient of each term to zero:

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x) =0\).

Simplifying the equation:

\(\displaystyle \sin( 10^{10} t-600x) =0\).

The sine function is equal to zero at certain values of \(\displaystyle ( 10^{10} t-600x) \):

\(\displaystyle 10^{10} t-600x =n\pi\),

where \(\displaystyle n\) is an integer. Rearranging the equation:

\(\displaystyle x =\frac{ 10^{10} t-n\pi }{600}\).

The equation provides a relationship between \(\displaystyle x\) and \(\displaystyle t\), indicating that the magnetic field intensity is constant along lines of constant \(\displaystyle x\) and \(\displaystyle t\). Therefore, the magnetic field intensity is uniform in the given medium.

Since the magnetic flux density \(\displaystyle B\) is related to the magnetic field intensity \(\displaystyle H\) through the equation \(\displaystyle B =\mu H\), where \(\displaystyle \mu\) is the permeability of the medium, we can conclude that the magnetic flux density is also uniform in the medium.

Thus, the correct expression for the magnetic flux density in the given medium is:

\(\displaystyle B =6\cos( 10^{10} t-600x)\hat{a}_{z}\).

Answer:

d. 1 < d < 2

e. t ≥ 5

f. -z ≤ 4

Step-by-step explanation:

Answer:

d. 5. 1 ≤ d ≤ 2

e. 4. t ≥ 5

f. 1. -z < 4

Step-by-step explanation:

d. d is between 2 and 1

The statement "d is between 2 and 1" means that d is greater than 1 and less than 2. We can represent this using the inequality 1 < d < 2. However, the answer choices do not match this exact form of inequality. To rephrase the inequality in a way that matches the answer choices, we can use the logical "and" operator to combine two inequalities: d is greater than or equal to 1, and d is less than or equal to 2. This gives us the inequality 1 ≤ d ≤ 2, which is answer choice 5.

e. t is not less than 5

The statement "t is not less than 5" means that t is greater than or equal to 5. This can be represented using the inequality t ≥ 5, which is answer choice 4.

f. The negative of z is not greater than 4

The statement "the negative of z is not greater than 4" means that -z is less than or equal to 4. We can represent this using the inequality -z ≤ 4, which is answer choice 2. However, the question does not include an answer choice for -z < 4, which is also true based on the statement.

Answer:

Given Figure has set of Stacked cubes.

To Draw the Base Plan, lets see its right side, Left Side and Front side view.

Right side:

It has 3 cubes in base.

2 cubes in 2nd layer clearly seen in figure and only 1 cube in 3rd layer.

Left Side:

It has 2 Cubes in base.

Both Cubes attached to 1st and 2nd cube of right side cubes.

Front Side:

It can be seen that, here base only has 2 rows of cubes.

Therefore,  1st Figure is correct Base Plan (or enclosed figure)

Note: Numbers in enclosed figure just shows the total no. of cubes in that stack.

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Answer: B

Step-by-step explanation: You can subtract 21 from 245 11 times but some will remain

Answer:

c) third quadrant

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

the quadrants are labeled left to right. Comment if u have any questions :)