This is (compound) probability: Picking two numbers from 1-10 and getting a multiple of 3 both times.

Answer:

There are 10 counters in the bag and you want the 4

As their is only one for the probability is

1/10

There are now 9 counters left in the bag.

You only want the even ones , which are 2 6 8 and 10 ( four has been taken out)

There are only four even counters in the bag of nine counters so the probability is

4/9

As you want both of these to occur, you need to multiply them

1/10 x 4/9 = 49/90

Step-by-step explanation:

The probability of getting a multiple of 3 both times is 2/30.

The Probability in mathematics is the possibility of an event in time. In simple words, how many times that incident is happening in any given time interval.

Given:

We are randomly picking two numbers from 1-10.

Multiple of 3 between 1 and 10 are 3, 6, 9.

To find the probability:

Here, we are considering the that the numbers are chosen without replacement.

The probability of getting a multiple of 3 both times,

= 3/10 x 2/9

= 6/90

= 2/30

Therefore, the probability is 2/30.

To learn more about the probability;

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