This graph shows how the concentration of a reactant changed during a
chemical reaction. Which sentence best describes how the concentration of
the reactant changed?

The angular deceleration of the ball is -0.42 rad/s².

Angular acceleration is a measure of the rate of change of angular velocity of an object rotating about an axis. When an object rotates, its angular velocity (ω) can change as a result of various factors, such as the application of an external torque or the redistribution of mass in the object.

We can use the formula for angular acceleration:

α = (ωf - ωi) / t

where

α is the angular acceleration

ωi is the initial angular velocity

ωf is the final angular velocity (which is zero in this case since the ball comes to a stop)

t is the time it takes for the ball to come to a stop

To find the initial and final angular positions, we can use the formula:

θf - θi = ωi * t + (1/2) * α * t²

where

θi is the initial angular position (0 in this case)

θf is the final angular position (90 radians in this case)

Substtuting the given values, we have:

θf - θi = ωi * t + (1/2) * α * t²

90 - 0 = (9.13 rad/s) * 15 s + (1/2) * α * (15 s)²

Simplifying and solving for α, we get:

α = -0.42 rad/s²

Therefore, the angular deceleration of the ball is -0.42 rad/s².

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A is the answer  because it is the answer

AnswerHM???

Explanation:

I dONT KNOW

Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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Answer:

Explanation:

Potential energy at the top

PE = mgh = 15.0(9.81)(5.00) = 735.75 J

Kinetic energy at the bottom

KE = ½mv² = ½(15.0)(2.50)² = 46.875 J

Work done by friction is the difference

735.75 - 46.875 = 688.875 ≈ 689 J

HMMMMMmmmm Energy transformation efficiency is 100% because energy can be neither created nor destroyed. With the given answer, I'm guessing they want to know what percentage of the potential energy got converted to heat of friction

688.875 / 735.75 = 0.936289... ≈ 94%

With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

Given data

voltage supplied Vs= 1.5 volts

resistance R1= 1000 ohms

resistance R2= 500 ohms

The total resistance is

Rt= 1000+ 500

Rt= 1500 ohms

In series connection the current is the same for all components while the voltage divides across all components,the voltages consumed by each individual resistance is equal to the source voltage.

Therefore, With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

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Answer:

plz follow me

Explanation:

ougffgegehhehe

After 0.100 s, the cat would be 0.049 m below its initial position, with a velocity of 0.98 m/s. After 0.200 s, the cat would be 0.196 m below its initial position, with a velocity of 1.96 m/s. Finally, after 0.300 s, the cat would be  0.441 m below its initial position, with a velocity of approximately 2.94 m/s.

To calculate the position and velocity of the sleeping cat after certain time intervals, we need to make some assumptions and use basic principles of physics.

Assuming the cat falls vertically downward due to gravity and ignoring air resistance, we can apply kinematic equations to solve the problem.

(a) Position:

Using the equation for the position of an object in free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time, we can determine the position of the cat.

After 0.100 s: h = (1/2)(9.8 m/s^2)(0.100 s)^2 = 0.049 m (approximately)

After 0.200 s: h = (1/2)(9.8 m/s^2)(0.200 s)^2 = 0.196 m (approximately)

After 0.300 s: h = (1/2)(9.8 m/s^2)(0.300 s)^2 = 0.441 m (approximately)

(b) Velocity:

The velocity of the cat can be calculated using the equation v = gt, where v is the velocity and t is time.

After 0.100 s: v = (9.8 m/s^2)(0.100 s) = 0.98 m/s (approximately)

After 0.200 s: v = (9.8 m/s^2)(0.200 s) = 1.96 m/s (approximately)

After 0.300 s: v = (9.8 m/s^2)(0.300 s) = 2.94 m/s (approximately)

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The wave's wavelength is 2 metres.

1/ denotes the number of waves in a wave train that can be found in a length of one metre when wavelength is stated in metres, or the number in wavelength is stated in centimetres, then the length is one centimetre. This value is referred to as the spectrum line's wavenumber. The frequency equation is written as f = /, where is the wave speed and is the wavelength of the wave.

If the total distance between four consecutive crests of a wave is 6 meters, then the wavelength of the wave is equal to that distance divided by the number of crests, which is three.

So the wavelength of the wave is:

6 meters / 3 = 2 meters

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Answer:

The equation v – = v 0 + v 2 v – = v 0 + v 2 is reflects the fact that when acceleration is constant, v – is just the simple average of the initial and final velocities.

Explanation:

hope this is it

Explanation:

the equation v-=v0+v2-v-=v0+v2 is reflects the fact that when acceleration is constant,v- is just the simple areragevof the initial and final velocities

It consists of a bulb containing mercury attached to a glass tube of narrow diameter, the volume of mercury in the tube is much less than the volume in the bulb. The space above the mercury may be filled with nitrogen gas or it may be at less than atmospheric pressure, a partial vacuum.

Answer:

b)

Explanation:

From the options provided, the only drawback of using digital medical records is that Digital medical records might be impossible to access in a power outage. This is because digital records are saved on a database either locally or remotely. Regardless of which, the records can only be accessed through an authorized computer system that is connected to the database. These are electronic systems that require power to function. Without power you would not be able to use the computer and therefore, would not have access to the medical records. Unlike, paper records which can be accessed regardless of whether there is power or not.

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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Answer:

Explanation:

C. The energy on the macroscopic scale decreased, and the energy on the molecular scale increased.

A. friction converts some energy on the macroscopic scale to energy on the molecular scale.

B. The mechanical energy of the system decreased because of friction.

B. The mechanical energy of the system at the beginning of the experiment is equal to the mechanical energy of the system at the end of the experiment.

B. the mechanical energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.

The  ball rolling on the floor eventually comes to a stop which means that

the energy on the macroscopic scale decreased, and the energy on the

molecular scale increased.

This is a scale in which an object can be seen with the eyes. When

an object is in motion, the ball rolls away and becomes less visible hence a

decrease in the macroscopic scale.

During motion, friction converts some macroscopic energy into molecular

scale which is why there was an increase in it.

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Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.

Explanation:

Answer:

I=Q/T

2.8=Q/3

8.4C=Q

Explanation:

The two factors that affect the amount of thermal energy an object has are;

Thermal energy  can be regarded as the energy which is been contained within a system it can be considered as the one that is responsible for its temperature.

It should be noted that the Heat is the flow of thermal energy and it can be seen as opne that deals with how heat is transferred between different systems .

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b you should know this no need to explain if you dont know well I'm sorry its b

The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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The force that acts on a projectile in the horizontal direction is Gravitational force.

A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.

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The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

Thus, Waveforms with periodic variations are those that recur consistently at set intervals.

The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.

In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.

Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

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Therefore, of the three options given, the electromagnet with more coils around the metal rod is the most powerful if all other factors such as current and core material are kept constant.

What is the very short response to an electromagnet?

An electromagnet is a temporary magnet made by winding a wire around an iron core. When current flows through the coil, iron becomes a magnet, and when the current is cut off, it loses its magnetic properties.

What is Electromagnetism?

Electromagnetism is the branch of physics that deals with the electromagnetic forces that occur between charged particles. Electromagnetic force is one of the four basic forces and describes the electromagnetic field.

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Answer: The answer is B

Explanation:

Answer:

F - S - F

Explanation:

Answer:

F-S-F

Explanation:

PLATO ANSWER

The vectors addition permits locating the perfect result for the sum of the two vectors in option B).  See attached and the vector is directed to the right and up.

Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.

A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance

Disclaimer: your question is incomplete, please see below for the complete question.

The image shows the complete question.

Which vector is the sum of vectors à and b?

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To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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The exact order of steps used in every experiment of the scientific method.

The scientific method is defined as the process of making facts through testing and experimentation. The basic process includes making an observation, forming a hypothesis, making a prediction, carrying out an experiment, and then analyzing the results.

The six steps of the scientific method include asking a question about something doing background research about the topic, constructing a hypothesis, doing experiments to test the hypothesis, analyzing the data from the experiment, and making conclusions.

So we can conclude that option A is the correct answer.

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Answer:

spirit animal?

Explanation:

Answer:

Power is the rate at which work is done or energy is transferred in a unit of time. Power is increased if work is done faster or energy is transferred in less time.

(a) To solve for the mass of the rod, we can use the formula for rotational kinetic energy:

KE = (1/2) * I * w^2

where KE is the rotational kinetic energy, I is the moment of inertia, and w is the angular velocity.

At the beginning, when the bug is at the axis of rotation, the rotational kinetic energy of the rod is:

KE1 = (1/2) * I * w^2 = (1/2) * (3.10×10−3 kg⋅m^2) * (0.37 rad/s)^2 = 0.036 J

When the bug reaches the other end of the rod, the rotational kinetic energy is:

KE2 = (1/2) * I * w^2 = (1/2) * (3.10×10−3 kg⋅m^2) * (0.132 m/s)^2 / (0.480 m)^2 = 3.62×10^-5 J

The change in kinetic energy is due to the work done by the bug as it crawls along the rod. The work done by the bug can be calculated as the product of the force it exerts on the rod and the distance it crawls:

W = F * d

The force the bug exerts on the rod can be calculated using Newton's second law for rotational motion:

τ = I * α

where τ is the torque, α is the angular acceleration, and I is the moment of inertia.

Since the rod is rotating with a constant angular velocity, its angular acceleration is zero, so the net torque on the rod must be zero. This means that the torque exerted by the bug on the rod must be equal and opposite to the torque due to the angular momentum of the rod:

τ_bug = τ_rod

F * d = I * w

F = I * w / d

Substituting the values given, we get:

F = (3.10×10−3 kg⋅m^2) * (0.37 rad/s) / (0.480 m) = 0.0237 N

Now we can use the work-energy principle to find the mass of the rod:

W = KE2 - KE1 = F * d = (1/2) * m * v^2

where m is the mass of the rod and v is the tangential velocity of the bug at the end of the rod.

Substituting the values given, we get:

(1/2) * m * (0.132 m/s)^2 = 3.62×10^-5 J - 0.036 J

Simplifying and solving for m, we get:

m = 0.221 kg

Therefore, the mass of the rod is 0.221 kg.

(b) To find the mass of the bug, we can use the same equation we used to calculate the force it exerted on the rod:

F = I * α / d

where α is the angular acceleration of the rod caused by the bug crawling along it.

Since the rod is a thin uniform rod, its moment of inertia can be calculated as:

I = (1/3) * m * L^2

where L is the length of the rod.

Substituting the values given, we get:

I = (1/3) * (0.221 kg) * (0.480 m)^2 = 0.0202 kg⋅m^2

Now we can calculate the angular acceleration caused by the bug crawling along the rod. Since the rod is rotating with a constant angular velocity, its angular acceleration is given by:

α

Fade

finish

α = (w_f^2 - w_i^2) / (2 * θ)

where w_i is the initial angular velocity of the rod, w_f is the final angular velocity of the rod after the bug has crawled to the end, and θ is the angle through which the bug crawls, which is equal to the length of the rod:

θ = L = 0.480 m

Substituting the values given, we get:

α = (0.132 m/s)^2 / (2 * 0.480 m) = 0.072 rad/s^2

Now we can calculate the force exerted by the bug on the rod:

F = I * α / d = (0.0202 kg⋅m^2) * (0.072 rad/s^2) / (0.480 m) = 0.00303 N

Finally, we can use Newton's second law to find the mass of the bug:

F = m * a

where a is the tangential acceleration of the bug, given by:

a = r * α

where r is the distance from the bug to the axis of rotation, which is equal to the length of the rod minus the distance the bug has crawled, or:

r = L - d = 0.480 m - 0.480 m = 0 m

Therefore, the tangential acceleration of the bug is zero, and its mass is:

m = F / a = 0.00303 N / 0 m/s^2 = undefined

This means that the force exerted by the bug on the rod is not enough to cause any tangential acceleration, and therefore the mass of the bug is negligible compared to the mass of the rod. We can assume that the bug has zero mass for practical purposes.