This animal has a backbone; nurses its offspring; likes to gnaw; has a bushy tail; stores food for winter; and has stripes on its back.

The beaker with a 0.6 molar solution is hypertonic to the bag with a 0.2 molar solution.

When a cell is placed in a solution with a higher solute concentration, the solution is hypertonic to the cell. This means that there is a net movement of water from the cell into the solution, causing the cell to shrink or even collapse. In the context of the given scenario, the dialysis bag is filled with a 0.2 molar solution, and it is placed in four different beakers with solutions of different molarities.

The beaker with a 0.4 molar solution is isotonic to the dialysis bag, which means that the solute concentration is the same inside and outside the bag. Thus, there is no net movement of water into or out of the bag.

The beaker with a 0.2 molar solution is also isotonic to the bag. Therefore, there will be no net movement of water.

The beaker with a 1.0 molar solution is hypertonic to the dialysis bag. Thus, there is a net movement of water from inside the bag to the surrounding solution, causing the bag to shrink.

The beaker with a 0.6 molar solution is hypertonic to the bag. Therefore, there is a net movement of water from inside the bag to the surrounding solution, causing the bag to shrink.

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A toxicant is a substance such as heavy metals, chemical compounds, and excessive concentrations of nutrients that degrades the environment and is harmful to organisms.

Various criteria can be used to categorize chemical substances. One such analysis is founded on the distinct components present. For instance, hydrides, oxides, and halides all contain one or maybe more hydrogen atoms as well as one or maybe more halide (Group 17) atoms.

A compound is created when two or more components mix through a chemical reaction. A chemical changes involving simple molecules and elements results in the formation of large compounds like proteins.

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The value of ΔG∘rxn for the reaction 2NO(g) + O2(g) → N2O4(g) is 33.5 kJ.

To find ΔG∘ for the reaction 2NO(g) + O2(g) → N2O4(g), we can use the given reactions with known ΔG∘rxn values:

1. N2O4(g) → 2NO2(g), ΔG∘rxn = 2.8 kJ

2. NO(g) + 1/2O2(g) → NO2(g), ΔG∘rxn = -36.3 kJ

We can rearrange these reactions and their ΔG∘rxn values to match the target reaction:

1. 2NO2(g) → N2O4(g), ΔG∘rxn = -2.8 kJ (reversed N2O4 reaction)

2. NO2(g) → NO(g) + 1/2O2(g), ΔG∘rxn = 36.3 kJ (reversed NO2 reaction)

Now, we can sum these two reactions to obtain the target reaction:

2NO(g) + O2(g) → N2O4(g)

ΔG∘rxn = (-2.8 kJ) + (36.3 kJ)

ΔG∘rxn = 33.5 kJ

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In order to answer the question first we must write the atomic number of each element:

Zirconium (Zr): 40

Cadmium (Cd): 48

Iridium (Ir): 77

Iron (Fe): 26

Then, we have to complete the distribution of electrons in each orbital for each atom:

The first 4 levels have the following distribution:

Level1: 1s

Number of electrones: 2

Level 2: 2s, 2p

Number of electrones 8 (2 in the s orbital and 6 in the p orbitals).

Level3: 3s, 3p, 3d

Number of electrones 18 (2 in the s orbital, 6 in the p orbital and 10 in the d orbitals)

Level 4: 4s, 4p, 4d, 4f

Number of electrones 32 (2 in the s orbital, 6 in the p orbitals, 10 in the d orbitals and 14 in the f orbitals)

The order in which the orbitlas are completed depends on the energy of each level. For example the 4s orbitals will be completed before the 3d orbitals because their energy is lower.

The order is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p...

Now, knowing the atomic number we can answer the question:

For Zirconium (total 40 electrones):

2 electrones are predicted in the 4d orbital

For Cadmium (total 48 electrones):

10 electrones are predicted in the 4d orbital

For iridium, as it has an atomic number higher than Cadmium we can predict tha it also complets the 4d orbital, then it has also 10 electrones in it.

For iron (total 26 electrones)

Iron has no electrones in the 4d orbitals

Answer: Molarity when 25.0 g of the compound \(NaClO_{3}\)is placed in 85.0 mL of solution is 294.12 M.

Explanation:

Given: Mass = 25.0 g

Volume  = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity is the number of moles of a substance divided by volume in liter.

Hence, molarity of given solution is calculated as follows.

\(Molarity = \frac{mass}{Volume (in L)}\)

Substitute the values into above formula as follows.

\(Molarity = \frac{mass}{volume (in L)}\\= \frac{25.0 g}{0.085 L}\\= 294.12 M\)

Thus, we can conclude that molarity when 25.0 g of the compound \(NaClO_{3}\)is placed in 85.0 mL of solution is 294.12 M.

Answer:

I'm pretty sure that it's lithium because it gives up one of their 3 electrons, so li

Answer:

C

Explanation:

This is a chemical property because a catalyst is added(fire). Without a catalyst a marshmallow would stay a marshmallow. The sugar caramelizes(this is not physical because sugar is burning)

answer; the last two is me and u :

It would require 6.31 kJ of energy to change 2.8 g of liquid water to steam if the water is already at 100°C.

To solve this problem, we need to use the following equation:

q = n * ΔHvap

where q is the amount of energy required to vaporize the liquid, n is the number of moles of water, and ΔHvap is the molar heat of vaporization.

First, we need to calculate the number of moles of water in 2.8 g. We can use the molar mass of water, which is approximately 18 g/mol:

moles of water = mass / molar mass

moles of water = 2.8 g / 18 g/mol

moles of water = 0.1556 mol

Next, we can use the equation above to calculate the amount of energy required to vaporize this amount of water:

q = n * ΔHvap

q = 0.1556 mol * 40.6 kJ/mol

q = 6.31 kJ

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It would require 6.31 kJ of energy to change 2.8 g of liquid water to steam if the water is already at 100°C.

To solve this problem, we need to use the following equation:

q = n * ΔHvap

where q is the amount of energy required to vaporize the liquid, n is the number of moles of water, and ΔHvap is the molar heat of vaporization.

First, we need to calculate the number of moles of water in 2.8 g. We can use the molar mass of water, which is approximately 18 g/mol:

moles of water = mass / molar mass

moles of water = 2.8 g / 18 g/mol

moles of water = 0.1556 mol

Next, we can use the equation above to calculate the amount of energy required to vaporize this amount of water:

q = n * ΔHvap

q = 0.1556 mol * 40.6 kJ/mol

q = 6.31 kJ

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Answer:

72N

12m/s

Explanation:

f=ma

=6×12

=72N

a=f÷m

=72÷6

=12m/s

Answer

moles = 5.81 mol

Explanation

Given:

Volume = 144 L

AT SATP

1 mole = 24.4651 L

Solution:

1 mole = 24.4651 L

x mole = 144 L

x = 144/24.4651

x = 5.8 mol

The balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -

Given equation: 3O2+4Co⟶2Co2O3Using the symbol e− for an electron. The redox reaction can be broken down into two half-reactions. The reduction half-reaction is the one in which a species gains electrons and the oxidation half-reaction is the one in which a species loses electrons. The half-reactions are as follows: Reduction Half-reaction Half-reaction equation: O2 + 2e- → 2O2 -Oxidation number of oxygen in O2=0 and in O2^-= -1Charge on the left side = 0Charge on the right side = 2 x (-1) = -2Thus, 2 electrons are added to the left side to balance the charge, making the half-reaction:O2 + 2e- → 2O2 -Oxidation Half-reaction Half-reaction equation: 4Co → 4Co2+ + 8e-Oxidation number of cobalt in Co=0 and in Co2+ =+2Charge on the left side = 0Charge on the right side = 4 x (+2) + 8 x (-1) = -4Thus, 8 electrons are added to the right side to balance the charge, making the half-reaction:4Co → 4Co2+ + 8e-Thus, the balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -

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When ice  is heated to at least 375 degrees Celsius, it will vaporize.

Ice is the solid state of frozen water, which usually occur at 0 degrees Celsius.

When ice is heated above 0 degrees Celsius, it melts into liquid water and further heating of the liquid water will increase to total internal energy of the liquid water.

Liquid water boils at 100 degrees Celsius and when the liquid water is heated above this temperature, it changes its phase from liquid to gaseous phase.

The ice heated to at least 375 degrees Celsius will vaporize.

The change in the state of the Ice from 0 degrees Celsius to 375 degrees Celsius include the following;

Ice(solid phase) → liquid water (liquid phase) → vapor (gaseous phase).

Thus, when ice  is heated to at least 375 degrees Celsius, it will vaporize.

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Answer:

It wouldn't let me post it for some reason. Its all in the picture.

:)

Answer:

1.  Chloro(methylchloranuidyl)methane

2.   1-Chloro-3,3-dimethylbutane

3.  2-bromobutane

Answer:

hot

Explanation:

Answer:

the main use of coal in the United States is to generate electricity.

Coal is a combustible black or brownish-black sedimentary rock with a high amount of carbon and hydrocarbons

Coal is formed when dead plant matter decays into peat and is converted into coal by the heat and pressure of deep burial over millions of years.

The percent of chloride ion in a sample if 2. 500 g of the sample produces 1. 750 g of agcl when treated with excess ag⁺ is 17.2 percent.

What is mass percent?

The ratio of the mass of the solute contained in a solution to the mass of the solution as a whole is known as the mass percent.

Explanation:

Given:

Mass of sample = 2. 500 g

Mass of AgCl = 1. 750 g

The percent of chloride ion in a sample is calculated as,

Molar mass of AgCl = 143.32 g/mol

\(Molar mass of Chlorine atom = 35.45 g/mol\)

Assume that all of the sample's chlorine has precipitated into silver chloride. As a result, the amount of chlorine in silver chloride will match the amount of chlorine in the sample.

First we have to find mass of chlorine,

\(In 143.32 g of silver chloride, mass of chlorine present is 35.45 gSo, in 1.3487 g of silver chloride, mass of chlorine present will be =35.45g/143.32 g * 1.750 g = 0.43 g\)

Therefore, the percent of chloride ion in a sample is

\(Mass of pure chloride compound = 2.500 gMass of chlorine = 0.43 g%Chlorine = 0.43/2.5 *100%Chlorine = 17.2 %\)

Hence, the percent of chloride ion in a sample is \(17.2%\) percent.

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Answer:

4m/s² north.

Explanation:

Data obtained from the question include the following:

Mass (m) = 10Kg

Force (F) = 40N North.

Acceleration (a) =...?

Force is simply the product of mass and acceleration. It is represented mathematically as:

Force (F) = Mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain the acceleration of the object as follow:

40 = 10 x a

Divide both side by 10

a = 40/10

a = 4m/s²

Since the force was applied in the north direction, the object will also accelerate in the north direction. Therefore, the acceleration of the object is 4m/s² north.

The temperature at which 24.6 g of chlorine gas, Cl₂ will exert a pressure of 652 mmHg when confined in a 8.5 1 L container is -16 °C

We'll begin by obtaining the number of mole of chlorine gas, Cl₂ in the container. Details below:

Mole = mass / molar mass

Mole of of chlorine gas, Cl₂ = 24.6 / 71

Mole of of chlorine gas, Cl₂ = 0.346 mole

Finally, we shall determine the temperature. This is shown below:

PV = nRT

0.858 × 8.51 = 0.346 × 0.0821 × T

Divide both sides by (0.346 × 0.0821)

T = (0.858 × 8.51) / (0.346 × 0.0821)

T = 257 K

Subtract 273 to obtain answer in °C

T = 257 - 273

T = -16 °C

Thus, can conclude that the temperature is -16 °C

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The equation related to reaction between Sulfur dioxide and oxygen to produce sulfur trioxide is 2SO\(_2\)(g) + O\(_2\)(g) \(\rightarrow\) 2SO\(_3\) (g).  SO\(_2\)  is limiting reagent.

The reactant that controls how much of the products are generated inside a chemical reaction is known as the limiting reagent. Since some of the other reactants remain that after limiting reagent has been used fully, it is occasionally discovered that they are in excess in the reactions. The theoretical yield is the most product that can theoretically be produced.

2SO\(_2\)(g) + O\(_2\)(g) \(\rightarrow\) 2SO\(_3\) (g)

moles of SO\(_2\) =20.0 g / 64.07

                      =0.312moles

moles of O\(_2\)= 15.6 g/32

                   =0.487moles

On dividing the moles by stoichiometry, out of  O\(_2\) and SO\(_2\), SO\(_2\)  is limiting reagent.

Therefore,  the equation related to reaction between Sulfur dioxide and oxygen to produce sulfur trioxide is 2SO\(_2\)(g) + O\(_2\)(g) \(\rightarrow\) 2SO\(_3\) (g).  SO\(_2\)  is limiting reagent.

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A cell with iron and chromium electrodes in an electrolyte can convert Fe²+ to Fe and Cr to Cr³⁺. The anode is Cr, the cathode is Fe, and the voltage is 0.56 V. The balanced equation is: 2Fe²⁺ + Cr --> 2Fe + Cr³⁺

The cell for this reaction would consist of two half-cells:

Anode: \($\mathrm{Cr \rightarrow Cr^{3+} + 3e^-}$\)

Cathode:\($\text{Fe}^{2+} + 2\text{e}^- \rightarrow \text{Fe}$\)

The overall reaction is:

\(2Fe^{2+} + Cr \rightarrow 2Fe + Cr^{3+}\)

The anode is where oxidation occurs, and the cathode is where reduction occurs. In this case, the anode is the half-cell with the chromium metal, and the cathode is the half-cell with the iron(ii) ion.

To calculate the voltage of the cell, we need to find the standard reduction potentials for each half-reaction and use the equation:

E°cell = E°reduction (cathode) - E°oxidation (anode)

The standard reduction potential for Fe2+ to Fe is -0.44 V, and the standard reduction potential for Cr3+ to Cr is -0.74 V.

E°cell = (-0.44 V) - (-0.74 V) = 0.30 V

So the voltage of the cell is 0.30 V.

The electron flow would be from the anode to the cathode, with electrons leaving the chromium metal and entering the iron(ii) ion to form iron metal.

The anode is the half-cell with the chromium metal, and the cathode is the half-cell with the iron(ii) ion.

The balanced overall equation is:  2Fe²⁺ + Cr --> 2Fe + Cr³⁺

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Option B= Burning candle wax

Answer:buning candle wax B

Explanation:

A P E X

The bonding model for sodium metal and sodium chloride are fundamentally different, reflecting the differences between metallic and ionic bonds. The metallic bond in sodium metal is characterized by free electrons, while the ionic bond in sodium chloride is characterized by the strong electrostatic forces between positive and negative ions.

Sodium (Na) is a metal, and its bonding model is based on the metallic bond. In a metallic bond, the valence electrons are not bound to any one individual atom, but instead are free to move through the entire metallic lattice, resulting in a highly conductive, solid material. The metallic bond is held together by electrostatic attraction between the positively charged metal ions and the negatively charged electrons.

On the other hand, sodium chloride (NaCl) is an ionic compound, and its bonding model is based on the ionic bond. In an ionic bond, electrons are transferred from one atom to another atom, resulting in the formation of ions. The positive and negative ions are held together by strong electrostatic forces.

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Answer:

TRUE :)

Explanation:

blood is pumped through the pulmonary artery to the lungs, where it picks up oxygen and releases carbon dioxide.

Answer:

False

Explanation:

it takes it to tha lungs.

Answer : The correct symbol and charge for each of the ions must be \(Na^{+1}\) and \(Cl^{-1}\).

Explanation :

The covalent compound are usually formed when two non-metals react.

Ionic compound are usually formed when a metal reacts with a non-metal.

As we know that the sodium chloride is an ionic compound in which sodium is an alkali metal and has one valence electron and chlorine is a non-metal and has 7 valence electrons.

When sodium atom donates an electron to a chlorine atom then it forms an ionic compound that is sodium chloride (NaCl) and the resulting positive ion \(Na^{+1}\) and negative ion \(Cl^{-1}\) form a stable ionic compound.

Hence, the correct symbol and charge for each of the ions must be \(Na^{+1}\) and \(Cl^{-1}\).

Answer:

answer questions brain

The use of cold methanol is important because it is used to recrystallize or solidify the product.

Since, ice bath is also used in nitration of methyl benzoate because in this reaction the concentrated acid like sulfuric acid is used with water and it is very exothermic.

The formation pure solid from the impure solid compound by mixing with hot solvent and form saturated solution. Now, this solution as cools and pure crystal grows when solubility of the compound decreases. This whole process is called re-crystallization.

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