there must be equal amounts of mass on both side of the center of mass of an object.T/F

MAIN ANSWER in 30 WORDS:
A) α = 8.8 rad/s^2; B) at = 118.8 m/s^2; C) ac = 413.52 m/s^2.

EXPLANATION PART IN 120 WORDS:
A) Angular acceleration α can be calculated using the formula α = (ω - ω0)/Δθ. Substituting values, we get α = (8.8 - 4.4)/5.5 = 0.8 rad/s^2.

B) Tangential acceleration at can be calculated using the formula at = Rα, where R is the radius of the platform. Substituting values, we get at = 34 × 0.8 = 27.2 m/s^2.

C) Final centripetal acceleration ac can be calculated using the formula ac = Rω^2, where ω is the final angular velocity. Substituting values, we get ac = 34 × 8.8^2 = 413.52 m/s^2.

Therefore, the angular acceleration is 0.8 rad/s^2, the tangential acceleration at the outer edge of the platform is 27.2 m/s^2, and the final centripetal acceleration at the outer edge of the platform is 413.52 m/s^2.

The angular acceleration of the platform is 0.8 rad/s^2, the tangential acceleration at the outer edge of the platform is 27.2 m/s^2, and the final centripetal acceleration at the outer edge of the platform is 2617.6 m/s^2.

A) The angular acceleration α of the platform can be calculated using the formula: α = (ω^2 - ω0^2) / (2Δθ). Plugging in the values, we get α = (8.8^2 - 4.4^2) / (2 * 5.5) = 44/11 rad/s².

B) The tangential acceleration at of a point on the outer edge can be calculated using the formula: at = α * R. Converting R to meters, we get R = 0.34 m. Thus, at = (44/11) * 0.34 = 1.36 m/s².

C) The final centripetal acceleration ac can be calculated using the formula: ac = ω^2 * R. Plugging in the values, we get ac = 8.8^2 * 0.34 = 26.424 m/s².

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true. condensation is when gas converts to liquid. the molecules move slower because of a loss of thermal energy, so it forms liquid

The spring has potential energy at position 1 because it is at its free/unstretched length and is therefore in its equilibrium position.

The spring also has potential energy at position 2 because it is compressed, and a compressed spring has potential energy.

Gravitational potential energy is given by mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. In this case, the slider is released from rest at position 1 and comes to rest at position 2, so its height above the ground decreases. Therefore, the gravitational potential energy at position 1 is less than the gravitational potential energy at position 2, and not greater as one of the options states.

The spring potential energy at position 2 is negative because work is done by the slider in compressing the spring, and work done by a system is negative. This negative potential energy is equal in magnitude to the positive work done by the slider in compressing the spring.

The spring potential energy at position 2 is not equal to the change in gravitational potential energy between positions 1 and 2, because the change in gravitational potential energy depends only on the change in height of the slider, and not on the compression of the spring.

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Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

The putty ball experiences the greater change in momentum than the tennis ball

The change in momentum of an object is given by the difference between its final momentum and its initial momentum.

We can use the following formula to calculate the change in momentum:

Δp = pf - pi

where;

For the tennis ball, the initial momentum is:

pi = mvi

pi = (0.0567 kg)(10 m/s) = 0.567 kg m/s

The final momentum is:

pf = mvd

pf = (0.0567 kg)(8 m/s) = 0.4536 kg m/s

The change in momentum is therefore:

Δp = pf - pi = 0.4536 kg m/s - 0.567 kg m/s = -0.1134 kg m/s

For the putty ball, the initial momentum is the same as for the tennis ball:

pi = mvi = (0.0567 kg)(10 m/s) = 0.567 kg m/s

Since the putty ball sticks to the wall, its final velocity is zero.

Therefore, the final momentum is:

pf = 0

The change in momentum is therefore:

Δp = pf - pi = 0 - 0.567 kg m/s = -0.567 kg m/s

Comparing the two values, we can see that the putty ball experiences the greater change in momentum, as its momentum decreases by a larger amount (0.567 kg m/s) than the momentum of the tennis ball (0.1134 kg m/s).

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I was researching something for some teaching resources when I came across the phrase "six-sided number cube" on the AP Statistics website, which is a sort of Martian-like description of what we call a die in English.

With six numbers, there are 63 potential combinations. In general, the formula shown below can be used to determine how many combinations are possible given a set of n elements: 2n – 1 is the number of combinations with n elements. The equation then reads as follows for 6 elements. 6 elements could be combined in 720 different ways using the formula 6*5*4*3*2. If you have the option, you can alter the order of the components in a way that uses less of each.

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The field to rotate this dipole from an orientation of 36.0 does a lot of work. In order to find out how much work is done, we need to consider the rotational energy of the dipole. The rotational energy is given by:

E = 1/2 * I * omega^2

where I is the moment of inertia of the dipole and omega is the angular velocity. From the given information, we can calculate the rotational energy to be:

E = 1/2 * I * (36.0 * 2 * pi / 360)^2

= 1/2 * I * 4 * pi^2

= 2 * I * pi^2

Thus, the work done by the field is:

W = 2 * I * pi^2 * 36.0

= 72 * I * pi^2

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Answer:

Approximately \(69\; {\rm N}\) at approximately \(126^{\circ}\).

Explanation:

Assume that both angles in the question are relative to the positive \(x\)-axis (towards the positive horizontal direction.)

Horizontal component (\(x\)-component) of the two forces would be:

Note that the \(x\)-component of the \(90\; {\rm N}\) force is negative since this components points away from the positive \(x\!\)-direction.

Hence, the net force in the \(x\)-component would be:

\((50\; {\rm N}) \, \cos(30^{\circ}) + (90\; {\rm N}) \, \cos(160^{\circ}) \approx (-41.3) \; {\rm N}\).

(Again, this component is negative since it points away from the positive \(x\)-axis.)

Similarly, the vertical component (\(y\)-component) of the two forces would be:

Hence, the net force in the \(y\)-component would be:

\((50\; {\rm N}) \, \sin(30^{\circ}) + (90\; {\rm N}) \, \sin(160^{\circ}) \approx 55.8\; {\rm N}\).

Refer to the diagram attached. The resultant net force is the vector sum of the components. Apply the Pythagorean Theorem to find this net force:

\(\begin{aligned}(\text{net force}) &= \sqrt{(\text{$x$-component})^{2} + (\text{$y$-component})^{2}} \\ &\approx \sqrt{(-41.3)^{2} + (55.8)^{2})}\; {\rm N} \\ &\approx 69\; {\rm N}\end{aligned}\).

Find the angle of this net force relative to the positive \(x\)-axis using the inverse cosine function \(\arccos\):

\(\begin{aligned}\arccos\left(\frac{(\text{$y$-component})}{(\text{net force})}\right) &\approx \arccos\left(\frac{55.8\; {\rm N}}{69\; {\rm N}}\right) \\ &\approx 126^{\circ}\end{aligned}\).

(The units might need to be converted into degrees.)

Answer:

Favorable sites include the tops of smooth, rounded hills; open plains and water; and mountain gaps that funnel and intensify wind. Wind resources are generally more favorable for electricity generation at higher elevations above the earth's surface

Answer:

9iuiedyfidhjDhjdgagf

Explanation:

iru5rogiaighshergouethothoh

Answer:

a. All the laboratory equipment given are very basic equipment used in all the laboratories. Name of each equipment is as follows:

b. Use of each laboratory equipment identified is:

While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the phase-locking of the auditory nerve fibers.

This means that the nerve fibers fire in synchrony with the sound wave and the brain can then interpret this as a low-frequency tone. This is because the membrane's responsiveness decreases at lower frequencies, making it more difficult for it to accurately encode the pitch information.
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the timing of the membrane's vibrations, also known as phase-locking. This explanation means that low-frequency sounds are represented by the synchronization of the membrane's movements with the incoming sound waves, allowing for accurate encoding of these lower pitches.

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Answer:

inclined plane

Explanation:

An inlcined plane is a simple machine used to slide an object over an obstacle

The final angular velocity of the merry-go-round is 2.805 rad/s.

Substituting the given values into the above equations, we get:

L1 = 86.5305 kgm^2 * 2 rad/s = 173.061 Nms

I1 = 86.5305 kgm^2 + 46.9 kg * (1.5 m)^2 = 184.9265 kgm^2

r = 0.645 m

m = 46.9 kg

Therefore, I2 = I1 - m * r^2 = 53.410 kgm^2

Substituting I1, I2, and ω1 into the equation for angular momentum conservation, we get:

86.5305 kgm^2 * 2 rad/s = 53.410 kgm^2 * ω2

Solving for ω2, we get:

ω2 = (86.5305 kgm^2 * 2 rad/s) / (53.410 kgm^2) = 2.805 rad/s.

Angular velocity is a physical concept used to describe the rate of change of angular displacement of an object over time. Angular displacement refers to the change in the orientation or position of an object relative to an axis, while angular velocity describes the rate at which this change occurs.

Angular velocity is measured in units of radians per second (rad/s) and is calculated as the ratio of the change in angular displacement to the time taken for the change to occur. This means that an object with a higher angular velocity will rotate or move around an axis more quickly than an object with a lower angular velocity. Angular velocity is an important concept in physics and is used in many applications, including in the design of machinery, navigation systems, and robotics.

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Answer:

Q = 7837500 Joules.

Explanation:

Cho các dữ liệu sau đây;

Khối lượng = 25 kg

Nhiệt độ ban đầu = 25°C

Nhiệt độ cuối cùng = 100°C

Nhiệt dung riêng = 4,18 * 10³ = 4180 J/kg.K

Để tìm nhiệt lượng cần thiết;

Về mặt toán học, nhiệt dung được cho bởi công thức;

\( Q = mcdt\)

Ở đâu;

Chuyển đổi:

Nhiệt độ ban đầu = 25°C đến Kelvin = 273 + 25 = 298 K

Nhiệt độ cuối cùng = 100°C đến Kelvin = 273 + 100 = 373 K

dt = T2 - T1

dt = 373 - 298

dt = 75 Kelvin

Thay các giá trị vào phương trình, ta có;

\( Q = 25 *4180*75\)

Q = 7837500 Joules.

Answer:C car

Explanation:

Answer:water

Explanation:

Water may be a nutrient that makes up 60% of our body weight. it's important in many functions, it's part of every cell in every tissue in the body.

Water carries other nutrients to all or any parts of the body, it carries waste out of the body and it helps to manage body temperature. When you run or play sports your body heats up pretty quickly.

Your body starts to sweat as a way to get rid of the heat. When the sweat evaporates on your skin your body and blood get cool. it's very important to replace the fluid that is lost by sweating so as not to become dehydrated.

If you get dehydrated the body cannot cool itself anymore and your performance will drop. Without enough water, whether you're exercising or sitting all day, you're at risk for dehydration which can be fatal

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Answer:

Technician B is correct by saying that the larger diameter (i.e the conductor's diameter), the less resistance it has.

Explanation:

According to the law of electrical resistance, the resistance of a metallic conductor is proportional to the length of the conductor, but inversely proportional to the cross-sectional area of the conductor.

\(R = p\frac{l}{A}\)

where R is the resistance of the conductor.

p is the intrinsic resistivity of the material with which the conductor is made.

l is the length of the conductor.

A is the cross-sectional area of the conductor.

This law simply means that if we increase the length of a conductor, or reduce the area, the electrical resistance of the conductor will increase, and vice versa.

Technician B is correct by saying that the larger diameter (i.e the conductor's diameter), the less resistance it has.

This is because the area of the conductor is proportional to the cross-sectional area. And the larger the cross-sectional area of a conductor, the lesser its resistance will be.

Answer:

distance

Explanation:

A scalar quantity is a quantity which is described in size but no direction is given. Distance is described in metres, no direction but displacement is described in metres and direction.

Answer:

2.5x10^4 J (scientific notation)

25,000 (Acellus)

Equation:

Q=mcΔT

where:

Q=heat

m = mass

c = specific heat

ΔT=change in temperature

Any rearranging?

Let's see.

No, we need heat.

So no rearranging.

Plug in the numbers and solve

It takes approximately 28,224 joules of heat to raise 0.0438 kg of aluminum from room temperature to its melting point.

To calculate the heat required to raise the temperature of aluminum from room temperature to its melting point, we need to use the specific heat capacity formula: Q = m × c × ΔT

where:

Q = heat (in joules)

m = mass of aluminum (in kilograms)

c = specific heat capacity of aluminum (in joules per kilogram per degree Celsius)

ΔT = change in temperature (in degrees Celsius)

Given:

Mass of aluminum (m) = 0.0438 kg

Specific heat capacity of aluminum (c) = 900 J/kg°C (approximate value for aluminum)

Change in temperature (ΔT) = melting point (660°C) - room temperature (20°C) = 640°C

Now, let's calculate the heat (Q):

Q = 0.0438 kg × 900 J/kg°C × 640°C

Q = 28,224 J (joules)

So, it takes approximately 28,224 joules of heat to raise 0.0438 kg of aluminum from room temperature to its melting point.

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A chemical reaction has occurred if for each combination any of the following is observed:

In a chemical reaction, one or more reactants are changed into one or more products, which are then changed back into one or more reactants.

Chemical elements or chemical compounds make up substances. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

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The average rate at which the cable does work is 294,000 J/s.

The given parameters:

The average rate at which the cable does work is calculated as follows;

\(P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{3000 \times 9.8 \times 200}{20} \\\\P = 294,000 \ J/s\)

Thus, the average rate at which the cable does work is 294,000 J/s.

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The motor could  lift 15 g in a time of 8 seconds 10884 meter.

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Given that motor operates at 200 W.

At time interval of 8 second, it do a work = 200×8 joule = 1600 joule.

Hence,  it lift 15 g in a time of 8 seconds = 1600/(0.015×9.8) meter

= 10884 meter.

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An object's mass rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force experienced by a body. The weight of a body can be different as it depends on where and under what conditions it is kept.

However mass is the measure of the amount of matter contained in a body and it is always constant.

Weight is defined as the amount of force exerted on a body by a moving gravitational field or any other field at the surface of the earth. It is measured in Newton (N)

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Answer:

10,000 N

Explanation:

Given that a rocket pushes exhaust 10, 000 N. Without any other forces acting on the rocket, how much force does the rocket go forward?

Solution

Since there is no any other additional forces, according to Newton's 3rd law of motion which state that:

In every action there will be equal and opposite reaction.

The action expelled by the rocket through its exhaust system is of 10000N.

The reactive force will be equal and opposite which will be same -10,000 N

Therefore, the rocket will go forward with a force of magnitude 10,000 N

The chief function of lighting is to provide illumination, making objects visible to the human eye. It also enhances the aesthetics of a space and serves various practical applications such as reading, studying, and working.

From a practical standpoint, the chief function of lighting is to provide illumination. Illumination refers to the process of lighting up a space or object, making it visible to the human eye. Lighting allows us to see and navigate our surroundings, ensuring safety and comfort.

Lighting serves several practical functions in our daily lives. It plays a crucial role in enhancing the aesthetics of a space, creating ambiance, highlighting architectural features, or setting the mood for different activities. Moreover, lighting is essential for various practical applications such as reading, studying, working, cooking, and performing tasks that require visual precision.

Different types of lighting fixtures, such as incandescent bulbs, fluorescent lights, and LED lights, are used to fulfill these functions. Incandescent bulbs produce light by heating a filament, while fluorescent lights use gas discharge to produce light. LED lights, on the other hand, use semiconductors to emit light efficiently.

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The chief function of lighting from a practical standpoint is to provide illumination to an environment. It helps in visibility in various activities, in addition to enhancing the beauty of a room. Light is necessary for human activities, especially when it comes to night time.

The light will make it possible for people to carry out their activities without any difficulties and also make the environment look beautiful. In general, the function of lighting is to provide illumination, which is significant in different situations and environments. For instance, street lighting is essential because it enhances visibility at night, making it safe for pedestrians and motorists to move around. It also acts as a deterrent to crime, such as robberies, muggings, and other forms of criminal activities that may occur at night. Similarly, home lighting is necessary because it enhances the beauty of the home and provides visibility to the occupants.

It allows people to carry out their activities effectively, read, study, and do other things without straining their eyes. In offices, lighting is necessary because it improves the working environment and reduces accidents that may occur due to poor visibility. Furthermore, it is essential in factories, production lines, and other industrial settings where workers need adequate lighting to carry out their tasks effectively. Finally, lighting is significant in public places like parks, museums, and stadiums, where it enhances the beauty of the surroundings and makes it possible for people to enjoy themselves during the day and night.

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Answer:

42m/s

6.06s

Explanation:

To find the initial velocity and time in which the ball is fling over the ground you use the following formulas:

\(x_{max}=\frac{v_o^2sin(2\theta)}{g}\\\\x_{max}=vt_{max}\)

θ: angle = 45°

vo: initial velocity

g: gravitational constant = 9.8m/s^2

x_max: max distance = 180 m

t_max: max time

by replacing the values of the parameters and do vo the subject of the first formula you obtain:

\(v_o=\sqrt{\frac{gx_{max}}{sin(2\theta)}}\\\\v_o=\sqrt{\frac{(9.8m/s^2)(180m)}{sin(2(45\°))}}=42\frac{m}{s}\)

with this value of vo you calculate the max time:

\(t_{max}=\frac{x_{max}}{v}=\frac{x_{max}}{v_ocos(45\°)}\\\\t_{max}=\frac{180m}{(42m/s)cos(45\°)}=6.06s\)

hence, the initial velocity of the ball is 42m/s and the time in which the ball is in the air is 6.06s

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TRANSLATION:

Para encontrar la velocidad inicial y el tiempo en el que la pelota está volando sobre el suelo, use las siguientes fórmulas:

θ: ángulo = 45 °

vo: velocidad inicial

g: constante gravitacional = 9.8m / s ^ 2

x_max: distancia máxima = 180 m

t_max: tiempo máximo

reemplazando los valores de los parámetros y haciendo el tema de la primera fórmula que obtiene:

con este valor de vo usted calcula el tiempo máximo:

por lo tanto, la velocidad inicial de la pelota es de 42 m / sy el tiempo en que la pelota está en el aire es de 6.06 s

Answer:

Water is omnipresent in our environment on a global scale: in the seas, oceans, lakes, rivers, in glaciers and ice floes... but also in the atmosphere (clouds,

Rain, hail, snow, water vapor...). Water is also omnipresent in our environment

Daily: water to drink, to cook, to wash...