Answer:
ABC
Explanation:
The voltage delivered by a primary battery is: Select the correct answer below:
a. directly proportional to its size
b. inversely proportional to its size
c. directly proportional to the square of its size
d. unrelated to its size
The correct answer is b. inversely proportional to its size. This means that as the size of a primary battery decreases, the voltage it delivers increases.
This is because the voltage of a primary battery is determined by the chemical reactions that occur within it, and these reactions are more concentrated in smaller batteries. However, it is important to note that the voltage delivered by a primary battery can also be affected by factors such as temperature and the age of the battery. Additionally, it is important to consider the specific type of primary battery being used, as different types may have different voltage outputs.
Overall, understanding the relationship between battery size and voltage is important for selecting the right battery for a given application.
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Convert each into decimal form. a) 1.056 x 10-3 b) 0.560 x 102
Answer:
A. 7.56
b. 57.12
Explanation:
Hope that's right have a nice day :)
Write the equation for the beta decay of Beryllium-10. (Beryllium is element number 4)
\(^{10}_{4} \text{Be} \longrightarrow ^{0}_{-1} \beta+^{10}_{5} \text{B}\)
How to balance this equation
Answer:
2Al + 3Ni(SO4) -------> 1Al2(SO4)3 + 2Ni
Explanation:
The amount of acrylamide found in potato chips is 1.7 mg/kg. If a serving of potato chips is 34 g, how many moles of acrylamide are you consuming?
"\(8.140\times 10^{-7} \ moles\)" number of moles of acrylamide are you consuming.
According to the question,
Molar mass of acrylamide,
71 g/mole→ Mole of acrylamide per kg of chips will be:
= \(\frac{Mass \ of \ acrylamide}{Molar \ mass \ of \ acrylamide}\)
By substituting the values, we get
= \(\frac{0.0017}{71}\)
= \(2.394\times 10^{-4} \ moles\)
In 34 g of chips,
→ The moles of acrylamide will be:
= \(\frac{moles \ per \ kg\times 34}{1000}\)
= \(\frac{2.394\times 10^{-4}\times 34}{1000}\)
= \(8.140\times 10^{-7} \ moles\)
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thinking about how the MTT assay works, what is the potential
mechanism by hich your drug could be causing a falso-positive [i.e.
making it seem like cells are dead when they arent]?.
The MTT assay is commonly used to assess cell viability and measure cellular metabolic activity. In this assay, MTT (3-(4,5-dimethylthiazol-2-yl)-2,5-diphenyltetrazolium bromide) is reduced by active mitochondria in viable cells to form insoluble formazan crystals, which can be quantified spectrophotometrically.
If a drug is causing a false-positive result in the MTT assay, where cells appear dead even though they are not, several potential mechanisms could be considered:
1. Drug interference with mitochondrial function: The drug may directly or indirectly interfere with mitochondrial activity, affecting the reduction of MTT and leading to a false-positive result. This interference could disrupt electron transport or oxidative phosphorylation, impairing mitochondrial function.
2. Drug-induced cytotoxicity: The drug may have toxic effects on cells, causing cell death or inhibiting cellular metabolic activity. This could result in reduced MTT reduction and the appearance of false-positive results.
3. Drug-induced cellular stress responses: Certain drugs can induce cellular stress responses, such as activation of autophagy or induction of antioxidant defenses. These responses could alter cellular metabolism or mitochondrial function, influencing MTT reduction and leading to false-positive results.
4. Drug interference with MTT assay components: The drug itself may interact with the MTT reagent or other components of the assay, leading to altered MTT reduction and subsequent false-positive results. This could occur through chemical reactions or interference with the optical measurement of formazan crystals.
It is important to thoroughly investigate the potential mechanisms and perform additional assays or tests to confirm the observed effects and distinguish between true cell death and false-positive results in the MTT assay.
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Which is the function of space observatory technology?
classify objects in space
collect soil and rock samples
carry astronauts and equipment
capture panoramic surface images
Answer:
D the answer
Explanation:
Answer:
A
Explanation:
Classify objects in space
A student walks to school in the morning when the outside temperature is 60°F. When the same student walks home after school, the outside temperature has dropped to 35°F. In this situation, how is thermal homeostasis maintained?
Answer:
Explanation:
When the same student walks home after school, the outside temperature has dropped to 35 degrees. In this situation, how is thermal homeostasis maintained? answer choices The student's heart rate drops as a negative feedback mechanism to deliver less oxygen to the lungs
Answer:
The student's heart rate drops as a negative feedback mechanism to deliver less oxygen to the lungs
Explanation:
The temperature has declined by 25 degrees Farenheit from 60 to 35.
Elemental bromine reacts vigorously with elemental sodium metal to form a white solid. Does this characteristic of elemental bromine represent a physical or a chemical property?
The characteristic of elemental bromine reacting vigorously with elemental sodium metal to form a white solid represents a chemical property.
Chemical characteristics define how substances react or change chemically. A white solid forms when elemental bromine and sodium metal combine, suggesting a chemical transition.
However, a substance's physical attributes can be detected or quantified without changing its chemical composition. Colour, density, melting, and boiling points are physical qualities.
It is a chemical property of elemental bromine to react with sodium metal and generate a new compound.
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PLES help me for brainless
Answer:
a 1 doesn't belong
Explanation:
Gas has fast moving molecules.
Liquids have slow moving molecules.
Solids have vibrating molecules.
Arrange the following compounds in order of decreasing dispersion interactions: CCl4, CH4, C3H8. Explain please!
The order of decreasing dispersion interactions for the given compounds is CCl4 > C3H8 > CH4.
Dispersion interactions, also known as London dispersion forces or van der Waals forces, are weak intermolecular forces that arise due to temporary fluctuations in electron distribution around molecules. These forces are influenced by factors such as molecular size and shape, as well as the number of electrons in the molecule.
1. CCl4 (Carbon tetrachloride) has a molecular formula of CCl4 and consists of a central carbon atom surrounded by four chlorine atoms. It is a relatively large molecule with a high electron count, which contributes to stronger dispersion forces.
2. C3H8 (Propane) has a molecular formula of C3H8 and consists of three carbon atoms and eight hydrogen atoms in a chain configuration. Although it has a smaller electron count than CCl4, its size and shape still contribute to significant dispersion forces.
3. CH4 (Methane) has a molecular formula of CH4 and consists of a central carbon atom surrounded by four hydrogen atoms. It is the smallest molecule among the three, with the lowest electron count, resulting in the weakest dispersion forces.
In summary, the dispersion interactions decrease in the order CCl4 > C3H8 > CH4 due to differences in molecular size, shape, and electron count.
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The order of decreasing dispersion interactions is: CCl4 > C3H8 > CH4. Dispersion interactions, also known as London dispersion forces, occur between nonpolar molecules due to temporary fluctuations in electron density.
The strength of these interactions depends on the size of the molecule, with larger molecules experiencing stronger dispersion forces. In the case of the compounds CCl4, CH4, and C3H8, all three are nonpolar molecules, meaning they experience dispersion interactions as their primary intermolecular force. To arrange these compounds in order of decreasing dispersion interactions, we need to consider their molecular sizes. CCl4 is the largest molecule of the three, followed by C3H8 and then CH4. Therefore, CCl4 would experience the strongest dispersion forces, followed by C3H8 and then CH4. This can be explained by looking at the electron cloud of each molecule. CCl4 has four chlorine atoms bonded to a central carbon atom, making it a large molecule with a high electron density.
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what is the ksp of caf2 if its molar solubility is 2.04 x 10-4 m? group of answer choices 3.4 x 10-11 none of these 1.9 x 10-38 4.2 x 10-8
The ksp of caf2 if its molar solubility is 2.04 x 10-4 m is 3.40 x 10⁻¹¹.
Solubility is described because the maximum quantity of a substance with the purpose to dissolve in a given quantity of solvent at a distinct temperature. Solubility is a function property of a selected solute-solvent combination, and exclusive substances have greatly differing solubilities.
calculation:-
Caf₂ ----> Ca²⁺ + 2f⁻
s 2s
Ksp = [Ca²⁺] [f⁻]
ksp = [s][2s]²
= 4s³
Given
S = 2.04 x 10⁻⁴
⇒ Ksp = 4( 2.04 x 10⁻⁴)²
⇒ Ksp = 4 ( 8.49 x 10⁻¹²
⇒ Ksp = 3.40 x 10⁻¹¹
Solubility is the capability of a substance, the solute, to form an answer with some other substance, the solvent. Insolubility is the other belonging, the inability of the solute to shape this kind of solution.
Solubility refers to the best quantity of solute that may dissolve in a regarded amount of solvent at a given temperature. In a solvent, an answer is a homogeneous aggregate of one or greater solutes.
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Type the correct answer in the box. Spell all words correctly.
Which product is the largest agricultural export of the United States?
_______is the largest agricultural export of the United States,
Answer:
I think it will soyabean which is largest agriculture export of us
Answer:
its corn
Explanation:
Which group has the highest ionization energies? Explain why.
Answer:
nobel elements (gr. 18) because they are fully stable due to octet complete--------------------------------------------------
HOTS
A container made of same metal when exposed to
humid climate develops green coating.
Identify the metal. Give reason for both a & b.
determine how many grams of kno3 would dissolve in 100g of water at 50 degrees celcuis to make a saturated solution
The amount of KNO₃ would dissolve in 100g of water at 50 degrees celcuis to make a saturated solution is 44 g.
To create a saturated solution of KNO₃ in 100g of water at 50 degrees Celsius, the following steps should be taken:
Step 1: Find out the mass of the solvent in the saturated solution.
The solvent is water in this instance. So, using the formula for the mass of a solution, we can calculate the mass of the solvent in the saturated solution as follows:
Mass of solvent = Mass of solution - Mass of solute
= 100 g - Mass of KNO₃
Step 2: Determine the amount of solute that would be dissolved in the solution to make it saturated.
The mass of KNO₃ that would dissolve in 100 g of water at 50°C to create a saturated solution is 56g/100g of water.
Step 3: Calculate the mass of KNO₃ that would dissolve in 100g of water to make a saturated solution.
Mass of KNO₃ = Solubility of KNO₃ × Mass of solvent
Mass of KNO₃ = 56 g/100 g × (100 g - Mass of KNO₃)
Now, let's solve for Mass of KNO₃;
56 = 56g(100-Mass of KNO₃)/100100 - Mass of KNO₃ = 100
Multiply both sides of the equation by 100 to obtain;
5600 - 100 Mass of KNO₃ = 100
Mass of KNO₃ = 5600/10100 - 56
= 44 g
Therefore, 44 g of KNO₃ would dissolve in 100g of water to make a saturated solution.
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what is the major product(s) to be expected on application of the hydroboration/oxidation procedure of (z)-3-methyl-2-pentene?
Alcohols are produced via the two step hydroboration-oxidation process. In an Anti-Markovnikov process, the boron connects to the alkene bouble bond's least substituted carbon while the hydrogen (from BH3 or BHR2) attaches to the more substituted carbon.
What is Hydroboration ?A limiting reagent is one that is completely consumed during a reaction, hence restricting the product's yield. Compared to the limiting reagent, the other reactant(s) are present in excess. The amount of product that could be produced based on the molar ratios is known as the theoretical yield. The amount that was actually retrieved is divided by the theoretical yield to determine the percent yield. For this amount to be expressed as a percentage, multiply it by 100.
What is Oxidation procedure ?A chemical process called oxidation occurs. As a result of atoms or groups of atoms losing electrons, it is described as a process. The addition or loss of oxygen or hydrogen in a chemical species is another method to define oxidation. When these things happen, oxidation occurs.
When an atom, molecule, or ion loses one or more electrons during a chemical reaction, oxidation takes place. The chemical species' oxidation state increases while oxidation takes place. Oxygen is not always necessary for oxidation to occur. The phrase was initially used when oxygen produced an electron loss during a process.
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1. You may be using medium for shoot regeneration from leaf explants of a plant in Expt-5. The plant media may contain the plant growth regulators (hoones) BA and NAA. The molecular weight of BK is 72 A : and NAA is 186. The media is pH to 5.8. (a) Before making the plant media, you found the pH to be 3.6. What would you add quiekly to get it to a pH of 5.8 (give a specific name of the solution)? Why? (1 pt) (b) How much BA will be weighed fot a 1M solution? (Y po) (c) Convert your answer from (b) to mg/ml. (Y/ pt) (d) Convert your answer from (c) to mg 1 . (1 pt) (e) How much BA will be weighed for a 5mM solution? (1/4pt) (f) Convert your answer from (c) to mg/ml. ( /4pt ) (g) Convert your answer from (f) to mg/L. (H/ pt) (h) Your stock solution of BA is 5mM and your working solution is 0.2mg/.. What volume of the stoc be added to 250ml of medium? [Hint: fook at the previous answers Keep to 4 decimal pts.) (3 pts Convert your answer from (h) to μI, and which pipettor will you use to aliquot the B. A? (1 pt)
(a) To get the pH of the media to 5.8, you would add NaOH solution. NaOH is used as a basic solution, and when it is added to a solution, it will increase the pH of the solution.
(b) The molecular weight of BA is 225.3. To prepare a 1M solution, you would have to weigh out 225.3 grams of BA.(c) To convert a 1M solution of BA to mg/mL, you can use the following equation: 1 mole = molecular weight in grams; 1000 millimoles = 1 mole. So, 1 M = 1000 mg/mL. Therefore, a 1M solution of BA is equivalent to 1000 mg/mL .(d) To convert a concentration of 1000 mg/mL .
Therefore, to calculate the weight required for a 5 mM solution, use the following formula :Mass of BA = molarity × volume × molecular weight= 5 × 0.001 × 225.3= 1.1265 grams(f) To convert a concentration of 5 mM to mg/mL, we use the following formula: Concentration (mg/mL) = (Concentration (mM) × Molecular weight) / 1000= (5 × 225.3) / 1000= 1.1265 mg/mL(g)
To convert a concentration of 1.1265 mg/mL to mg/L, we multiply by 1000, so 1.1265 mg/mL = 1126.5 mg/L.(h) Given that the stock solution of BA is 5 mM and the working solution is 0.2 mg/mL.
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when a soap film gets *very* thin, down to a molecular lengths scale, its reflection across the entire visible spectrum becomes zero. why?
A soap film is thin enough to exhibit interference of light, meaning that the light waves passing through it can reinforce or cancel each other out.
When the thickness of the soap film decreases to a molecular scale, the film acts as a thin-film interferometer and the reflection across the entire visible spectrum becomes zero.
Because the light waves passing through the front and back surfaces of the film interfere destructively, leading to zero reflection. This condition is known as the "minimum reflection" and is used to accurately measure the thickness of thin films.
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What are the half-reactions for a galvanic cell with Zn and Mg electrodes?
the half-reactions
cathode : Zn²⁺ (aq) + 2e⁻ ---> Zn (s)
anode : Mg (s) → Mg²⁺ (aq) + 2e−
a balanced cell reaction
Zn²⁺(aq) + Mg(s)→ Zn(s) + Mg²⁺ (aq)
Further explanationGiven
Zn and Mg electrodes
Required
The half-reactions for a galvanic cell
Solution
To determine the reaction of a voltaic cell, we must determine the metal that serves as the anode and the metal that serves as the cathode.
To determine this, we can either know from the standard potential value of the cell or use the voltaic series
1. voltaic series
Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
So the metal on the left will easily undergo oxidation and function as anode
Since Mg is located to the left of Zn, then Mg functions as anode and Zn as a cathode
2. Standard potentials cell of Mg and Zn metals :
Mg2+ + 2e– → Mg E° = -2,35 V
Zn2+ + 2e– → Zn E° = -0,78 V
The anode has a smaller E°, then Mg is the anode and Zn is the cathode.
Answer:
Explanation:help
If 0.35 g (0.00253 mol) of salicylic acid (MW 138.12) yields 0.00157 mol of aspirin (MW 180.16), what is the % yield? a. 15.7 % b. 62.1% c. 25.3 % d. 53.2%
The % yield is approximately 62.1%. The percent yield is an important measure of the efficiency of a chemical reaction and indicates the success of the reaction in converting reactants into products.
To calculate the percent yield, we need to compare the actual yield (0.00157 mol) with the theoretical yield and then calculate the percentage.
First, let's calculate the theoretical yield of aspirin. The molar ratio between salicylic acid and aspirin is 1:1, so the number of moles of aspirin produced should be the same as the number of moles of salicylic acid used, which is 0.00253 mol.
Next, we'll calculate the theoretical mass of aspirin:
Mass = moles × molecular weight
Mass of aspirin = 0.00253 mol × 180.16 g/mol
Mass of aspirin = 0.455 g
Now we can calculate the percent yield:
% yield = (actual yield / theoretical yield) × 100
% yield = (0.00157 mol / 0.00253 mol) × 100
% yield = 0.6195 × 100
% yield = 61.95%
Rounding to one decimal place, the percent yield is approximately 62.1%.
The percent yield of the reaction is approximately 62.1%. This means that 62.1% of the maximum possible amount of aspirin was obtained from the given amount of salicylic acid. The percent yield is an important measure of the efficiency of a chemical reaction and indicates the success of the reaction in converting reactants into products.
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Determine the equilibrium constant for the following reaction at 298 K. CIO(g) + O2(g) → Cl(g) + O3(8) AG° = 34.5 kJ/mol 0.986 4.98 x 10-4 8.96 x 10-7 5.66 x 105 1.12 x 106
the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.
The equilibrium constant for the given reaction, CIO(g) + O2(g) → Cl(g) + O3(g), at 298 K can be determined using the Gibbs free energy of the reaction and the following equation:ΔG° = - RT lnK
where ΔG° is the standard Gibbs free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.
The equation can be rearranged to solve for K:K = e^(-ΔG°/RT)where e is the natural logarithmic base, and all other variables are the same as in the previous equation.Substituting the given values,
we have:ΔG° = 34.5 kJ/molR = 8.314 J/(mol·K)T = 298 K
Using these values, we get:-
ΔG°/RT = (-34.5 × 10^3 J/mol) / (8.314 J/(mol·K) × 298 K)
= -13.19e^(-ΔG°/RT) = e^(-13.19) = 8.96 × 10^-7
Therefore, the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.
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If 0.0025 mol of NaNO3 forms during the reaction, what is the concentration of NaNO3 in the final solution?
Answer:Hi! I hope this will help you with your question, whether this is an assignment or not. The answer that I get is 0.033 concentration.
If 0.0025 mol NaNo3 forms during the reaction, the concentration of NaNO3 in the final solution should be 0.033.
Explanation:
What is the molar concentration of a solution prepared by dissolving 3.05 grams of sodium acetate in enough water to prepare 3.43 x 102 mL of the solution
Answer:
0.296 M
Explanation:
What is the molar concentration of a solution prepared by dissolving 3.05 grams of sodium acetate in enough water to prepare 3.43 x 102 mL of the solution
sodium acetate NaCH3COO has molar mas of
23 + 12 +24 + 1 +32 = 92 g/mol
3.05 g is 3.05 g/ 92 g/mol = 0.0328 moles
it is distributed over 102 mL = 0.102 L
its concentration is 0.0328/ 0.102 =0.296 M Mhttps://brainly.com/question/25586315?answering=true&answeringSource=feedPublic%2FhomePage%2F3#
Fe(no3)3 + na0h > fe(oh)3 + nano3 is balanced or unbalanced?
Answer:
Unbalanced
Explanation:
\(\text{Fe}(\text{NO}_3)}_3+ \text{NaOH} \rightarrow \text{Fe(OH)}_3 + \text{NaNO}_3\\\\\text{Balanced reaction:}\\\\\text{Fe}(\text{NO}_3)}_3+ 3\text{NaOH} \rightarrow \text{Fe(OH)}_3 + 3\text{NaNO}_3\)
Why is proline often found at places in proteins that are not alpha-helical? (Select all that apply.) Proline, unlike other amino acids, has a fixed angle of rotation around its C(alpha)-C(O) bond. Proline is only found in beta-sheets. Proline has a side chain that is too bulky for alpha-helices. Proline, unlike other amino acids, has a fixed angle of rotation around its C(alpha)-N bond. Proline fits well into beta-turns.
The properties of proline that often lead to it being found at places in proteins that are not alpha-helical include:
A: Proline, unlike other amino acids, has a fixed angle of rotation around its C(alpha)-C(O) bond.
D: Proline, unlike other amino acids, has a fixed angle of rotation around its C(alpha)-N bond.
E: Proline fits well into beta-turns.
Proline is unique among the amino acids in that it has a cyclic peptide bond between its nitrogen and its alpha-carbon, which results in a fixed angle of rotation around both the C(alpha)-C(O) bond and the C(alpha)-N bond. This rigid conformation makes proline poorly suited for alpha-helical structures, but ideal for beta-turns, which are common structural elements in proteins that help to create specific protein-protein interactions and maintain protein stability.
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The below table compares the number of electrons in two neutral atoms.
atom:
Ne 10
Na 11
Compare the electron configuration and atomic radius of these two atoms and use that to explain the difference in their reactivity.
_is the only metal that normally exists on earth as a liquid
Answer:
Mercury
Explanation:
mercury, and it's the only metal that normally exists on Earth as a liquid.
Calculate the number of moles found in 3.045x1024 atoms of helium.
PLS HELP
Explanation:
so for this u have to use this equation where
Moles = number of particle/6.02×10^23
= 3.045 × 10^24/6.02×10^23
= 5.0581
write it to 3 S.F so 5.06 moles
Read the following scenarios and elaborate what is wrong with students's behaviour.
1.) Diana and Mike were going to be late to their next class.After rushing to put away a few materials, they left the rest of the materials on the table.
2.) Cindy broke a test tube.Carefully she picked up the pieces with one hand and placed them in her other hand.Then she dumped the glass pieces into the wastebasket.
3.) Mike and Colleen had a lot of chemicals left from their investigation.They dumped the chemical in the sink and left the water running in the sink as they left class.
ANYONE PLEASE HELP ME IN CHEMISTRY BECAUSE I HAVE TO PASS THIS TOMORROW AT 4TH PERIOD I HOPE Y'ALL CAN HELP ME:(
1. Diana and Mike left the rest of their materials on the table.
2. Cindy picked up the pieces by hand, which is not safe, could've cut her.
3. Dumping chemical in the sink is wrong and should never be done. The also left the water running, which is a waste of water.
Hope this helps :))