There are many "waves" in nature. Give a few examples and
indicate whether they are longitudinal or transverse.

Answer:

v = 0.0251 km/h

Explanation:

Given that,

The average distance from its center of mass of 1000 meters.

The time taken is  24 hours and 57 minutes to complete one orbit

We need to find the orbital velocity of the spacecraft OSIRIS-REx.Let it is v. SO,

\(v=\dfrac{2\pi r}{t}\)

Putting all the values,

\(v=\dfrac{2\pi \times 100}{24\ hours\ and\ 57\ minutes}\\\\v=\dfrac{2\pi \times 100}{(86400+3420)}\\\\v=0.00699\ m/s\)

or

v = 0.0251 km/h

So, the average orbital velocity is 0.0251 km/h.

Answer:

electrical energy to mechanical energy.

Explanation:

Answer:

Minimum uniform acceleration in Km/hr² is 20,505.05 km/hr²

Explanation:

In other to determine the acceleration, we can use the formula below

acceleration = velocity/time

Time wasn't given in the question, hence we calculate for time using the parameters given and the formula below

Velocity= distance/time

time = distance/velocity

distance = 2000m ⇔ 2km

time = 2/203

time = 0.0099

Hence, we look for acceleration

which is

acceleration = 203/0.0099

= 20,505.05 km/hr² ⇔ 2.0 × 10⁴

The slope of 3.2913 indicates that for every one degree Fahrenheit increase in temperature.

Finally, the temperature when the number of chirps is 0 is not represented by the slope or the y-intercept, but rather by extrapolating the regression line to the x-axis.

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Answer:

90 mAmps

Explanation:

V=IR

V/R = I

9 v / 100 ohm = .09 amps = 90 mAmps

It would take 4.1 seconds for the car to accelerate from rest to 270 km/h.

So, the acceleration can be written as a = k(300 - v)

where k is the constant of proportionality and v is the velocity of the car in km/h.

It is known that, when the car is at rest, i.e., v = 0, it can accelerate from rest to 135 km/h in 10 s.

So, we can write;135 = k(300 - 0) => k = 135/300 => k = 0.45

Now, we are to find the time taken by the car to accelerate from rest to 270 km/h.

Let t be the time taken.

So, the velocity of the car after time t is given by;

v = 300 - 270e^(-0.45t)

Putting v = 0 in the above equation,

we get;

0 = 300 - 270e^(-0.45t)

  => e^(-0.45t) = 10/9

  => -0.45t = ln(10/9)

  => t = 4.1 sec

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The graph showing F as a function of y shows that D, the cube will oscillate between y=0.05 m and y=0.09 m.

From the graph, the force exerted on the cube increases linearly as the cube is displaced upwards from its equilibrium position at y = 0.07 m. When the cube is displaced to y = 0.05 m, the net force is upward and greater than the weight of the cube. This causes the cube to accelerate upward.

As the cube moves upward, the force exerted by the water decreases until it is equal to the weight of the cube at y = 0.07 m. At this point, the net force on the cube is zero and the cube momentarily comes to rest. The cube then continues to move upward, but the force exerted by the water is now downward, causing the cube to slow down and eventually come to a stop at y = 0.09 m.

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The complete question is:

A 4.0 kg cube is placed in a container of water. A student observes that the cube floats while performing simple harmonic motion. The net force exerted on the cube F represents the sum of the force due to gravity and the force exerted on the cube by the water. A force probe is used to measure F as a function of the cube's distance y from the bottom of the container. The graph shows F as a function of y, where the positive direction is upward. Which of the following statements is correct about the motion of the cube if it is released from rest at a vertical position of y = 0.05 m?

A) The cube will have a constant upward acceleration of 2.0 m/s².

B) The cube will have a constant downward acceleration of 2.0 m/s²

C) The cube will travel upward with a changing. c acceleration until it comes to rest at a position of y= 0.07 m.

C) The cube will oscillate between y = 0.05 m and y = 0.09 m.

Answer:

The most thick paper can support maximum weight.

Explanation:

A paper is defined as a thin sheet of material that is prepared chemically or mechanically processing of the cellulose fibers which are derived from the grasses, wood, bamboos, trees or rags.

In the context, there are three different but identical sheets of paper that are arranged in different ways. Weights are placed over the papers. Now the most thick paper of the three provided will support most of the weight.

Paper thickness or paper weights are measured in GSM. GSM stands for grams per square meter. The thicker paper will have higher GSM.  

Answer:

2×10⁻⁷ Ωm

Explanation:

From the question,

R = 4ρL/πd².................... Equation 1

Where R = Resistance of the wire, ρ = resistivity of the wire, L = length of the wire, d = diameter of the wire.

Therefore,

ρ = Rπd²/4L............. Equation 2

Given: R = 1 ohm, ρ = 1×10⁻⁷Ωm

1×10⁻⁷ = πd²/4L.................... Equation 3

If the length and the diameter are doubled, and the resistance remaining constant

ρ' = π(2d)²/4(2L)

Where ρ'  = new resistivity

ρ' = 4πd²/8L

ρ' = 2πd²/4L = 2ρ

ρ' = 2(1×10⁻⁷)

ρ' = 2×10⁻⁷ Ωm

Answer:

President who did not win the popular vote

Explanation:

Critics of the Electoral college argue that the system can result in a selection of what?

The x- & y-components in vector A are denoted by Ax and Ay. The angle between the vector and the x-axis was equal by tan(-1) Ay/Ax.

The vector is a quantity or phenomenon with independent properties for both size and direction. Any mathematical and geometrical representation of a quantity is another use of the term. Elements of vectors in nature include motion, pressure, electromagnetic fields, or weight.

Physical quantities called vectors need both magnitude as well as direction. Scalars include things like height, energy, area, and volume. Vectors can take the forms of displacement, acceleration, and acceleration.

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Answer:

D.

Explanation:

Force and distance are inversely related, so a greater distance results in a weaker force.

Answer: Microscope is an instrument that is used for observing micro particles, cells, and nanosized particles.

Explanation:

Placing one hand below the stage of the microscope and other hand must be used to hold the arm of the microscope. This facilitates the safety of the microscope as it will provide support to the entire structure of the microscope and also to the lens and mirrors attached to the structure of the microscope. If any of the part get damaged or lost during carrying it will affect the overall functioning of the microscope.

Answer:

wrapping the electrical cord around the arm of the microscope

Explanation:

just took the test

The change in the momentum of the bullet can be expressed as,

Finally, the bullet moves in the opposite direction therefore, final velocity is taken as negative.

Plug in the known values,

Thus, the change in the momentum of bullet is 12.1 kgm/s.

Answer:t would be 17 m/s

If we use V2 = V1 + a*t

Sub in 5 for v1

2m/s*2 for a

And

6 for t

That should give you the answer.

The correct option is (b) 227 kg.

The 500 lb rock samples the astronauts carried back from the moon weighed 227 kilograms.

The astronaut transported a 550 lb sample.

2.20lbs = 1 kilogram.

1 lbs = 1/2.20

Since, 1 lb = 0.45 kg,

500 lb almost equals 227 kg.

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The turntable's rotation angular velocity when the block reaches the outer edge is 5.578 rads⁻¹

The inertial moment of the turntable block = \(\frac{1}{2} mr^{2}\)

The inertial moment of the block = \(mr^{2}\)

According to the law of conservation of angular momentum, the total angular momentum of the system when the block is seated at the center and when the block is at the outside edge must be the same since no external torque operates on the system.

Additionally,

ω= 2\(\pi\)f, where f represents rpm, can be used to determine

ω= 2π×63/60 = 6.597

So, I*ω = I' * ω'

\([\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0)^{2} ]6.597= [\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0.5)^{2} ]\)*ω'

ω' = 5.578 rads⁻¹

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By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

When the player strikes the ball, kinetic energy is at its greatest.

Kinetic energy = 1/2*m*\(v^{2}\)

where m denotes mass and v denotes velocity.

Therefore, kinetic energy is inversely correlated with square of velocity.

When a player strikes the ball, velocity is at its highest.

Thus, when the player strikes the ball, kinetic energy is at its highest.

It is the energy that a body has because it is moving.

Kinetic energy comes in five different forms:

Kinetic energy is measured in Joules.

Importance of kinetic energy:

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Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

The image distance (v) is 26.25 cm. We can use the formula for focal length of a concave mirror:  1/f = 1/do + 1/di
Where f is the focal length, do is the object distance, and di is the image distance.

We know that the focal length is 15 cm, and the object distance is 35 cm. Plugging these values into the formula:
1/15 = 1/35 + 1/di
Now we can solve for di:
1/di = 1/15 - 1/35
1/di = (7 - 3)/105
1/di = 4/105
di = 26.25 cm
So the image distance is 26.25 cm.

Using the formula for focal length of a concave mirror, we can calculate that the image distance is 26.25 cm when the object is 35 cm from the mirror. To find the image distance for a concave mirror, you can use the mirror formula:
1/f = 1/u + 1/v
where f is the focal length, u is the object distance, and v is the image distance.
Given the focal length (f) is 15 cm and the object distance (u) is 35 cm, we can substitute these values into the formula:
1/15 = 1/35 + 1/v
To solve for the image distance (v), first find the common denominator and then subtract 1/35 from both sides:
(35 - 15) / (15 * 35) = 1/v
20 / 525 = 1/v
Now, take the reciprocal of both sides to find v:
v = 525 / 20
v = 26.25 cm

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The greater the molecular motion, the greater the pressure the molecules exert. The correct option is 2.

The movement of constituent particles or molecules in a specific direction is defined as molecular motion. Heat and temperature have an effect on molecular motion.

This is because the pressure is the result of the collisions of gas molecules with the walls of the container they are in. When the molecular motion of the gas molecules increases (due to an increase in temperature, for example), they move faster and collide with the walls of the container with greater force and frequency, which increases the pressure exerted by the gas.

Conversely, when the molecular motion of the gas molecules decreases (due to a decrease in temperature, for example), they move more slowly and collide with the walls of the container with less force and frequency, which decreases the pressure exerted by the gas.

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The interaction of a nonelectrolyte and water differs from the interaction of an electrolyte and water because nonelectrolytes do not conduct current while electrolytes can conduct current.

The solution that does not let the current pass through any state either liquid or molten is called nonelectrolyte.

For example, sugar and alcohol are nonelectrolytes.

On the contrary, electrolytes are those mediums, compounds, or substances that allow electric charges to pass through them.

In this way they conduct electricity.

For example, when an ionic substance dissolved in water forms an ionic solution it let the current pass through such as NaCl, HCl, etc. Sodium chloride dissolves in water forming ions of sodium and chloride ions and making the solution electro conductive.

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If the frog population is in Hardy-Weinberg equilibrium, the frequency of the green-skin allele will be 0.28 (or 28%) in the following generation.

The Hardy-Weinberg equilibrium is a genetic principle that states that in the absence of evolutionary factors, the frequency of alleles in a population stays constant from generation to generation. Equation \(p^2 + 2pq + q^2 = 1\) can be used to define the equilibrium, where p stands for the frequency of the dominant allele (brown skin) and q stands for the frequency of the recessive allele (green skin).

We can conclude that q2 = 0.12 because q2 is the frequency of the green-skin homozygotes and 12% of the other frogs display the green-skin phenotype. Taking 0.12's square root, we discover that q = 0.3464.

We may compute p as 1 - q because p + q = 1, which results in p = 0.6536.

As a result, the frequency of the brown-skin allele (p) will be roughly 0.65 (or 65%) while the frequency of the green-skin allele (q) will be approximately 0.35 (or 35%) in the following generation.

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Answer:

The applied horizontal force that will accelerate a 400-kg crate at 1 m/s2 across a factory floor against a friction force half its weight is 800 N.

Explanation:

The friction force is given by:

F_f = μmg

F_f = μmg = 0.5 * 400 kg * 9.8 m/s² = 1960 N

The net force on the crate is given by:

F_net = F_a - F_f

The net force is equal to the mass of the crate times its acceleration, so:

m * a = F_a - F_f

400 kg * 1 m/s² = F_a - 1960 N

F_a = 400 kg * 1 m/s² + 1960 N = 800 N

Therefore, the applied horizontal force that will accelerate a 400-kg crate at 1 m/s2 across a factory floor against a friction force half its weight is 800 N.

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