Answer:
-48,800,000 or 71,200,000
Explanation:
subtraction or addition :D
I hope I helpped (ㆁωㆁ)
57. Example of the law of force and acceleration
Answer:
Newton's Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass. Your leg muscles pushing pushing on the pedals of your bicycle is the force.
Explanation:
Please help! Will mark brainliest!
Answer:
im pretty sure its d
Explanation:
If the gravitational force between a planet of mass M and a satellite of mass m at distance is 2.5 * 10 ^ 3 * N what is the force exerted on a larger satellite of mass 2m , at a distance 0.8r away from planet M ?
Answer:
F = 7.8 10³ N
Explanation:
For this exercise we will use the law of universal Gravitational
F = G M m / r²
for initial conditions
F₀ = G M m₀ / r₀²
They tell us that the mass changed at m = 2m distance at r = 0.8r₀
we substitute
F = G M 2m₀ / (0.8 r₀) ²
F = (GM m₀/ r₀²) \(\frac{2}{0.64}\)
F = 3.125 F₀
let's calculate
F = 3.125 2.5 10³
F = 7.8125 10³ N
compare the above electric field to the electric field of a large parallel plate capacitor with the same voltage and distance between the plates. which one is larger? is this expected? explain.
The electric field due to a point charge will always be greater than that of a parallel plate capacitor.
The electric field due to a point charge is given by the formula E=kq/r². Compare the above electric field to the electric field of a large parallel plate capacitor with the same voltage and distance between the plates.
According to Coulomb's law, the electric field due to a point charge varies inversely with the square of the distance from the charge. The magnitude of the electric field between the plates of a capacitor is uniform and is given by E=V/d (where V is the voltage across the plates and d is the distance between them).
Thus, the electric field between the plates of a capacitor is given by E=V/d. Comparing both electric fields, we get that `E\(_{point}\) = E\(_{plates}\).
It's expected because the electric field between the plates of a capacitor is uniform, and its magnitude depends on the distance between the plates and the voltage applied.
The electric field due to a point charge, on the other hand, varies inversely with the square of the distance between the charge and the point where we want to measure the field. Therefore, the electric field due to a point charge will always be greater than that of a parallel plate capacitor.
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A hot air balloon cools down it is compressed by the air around it,for this prosses identify the sign of the heat ,the change in internal energy and the work explain you answers.
1.change of internal energy : + -
2.heat loss :+ -
3.work done :+ -
Explain why
The answers to the questions about a hot air balloon cooling down are as follows:Change of internal energy: -Heat loss: -Work done: +
The change of internal energy of the hot air balloon when it cools down is negative (-). The internal energy of the hot air balloon decreases as the balloon loses heat. Therefore, there is a decrease in internal energy, which is the sign of the heat.The heat loss of the hot air balloon when it cools down is negative (-). The hot air balloon loses heat to the cooler air surrounding it. Therefore, the heat loss is negative (-) due to the heat transfer from the hot air balloon to the cooler air.
The work done on the hot air balloon when it cools down is positive (+). When the hot air balloon cools down, it becomes denser than the surrounding air. Therefore, the weight of the hot air balloon increases, and the hot air balloon sinks down to the ground. As a result, work is done on the hot air balloon by the surrounding air to push it down to the ground.In conclusion, the sign of the heat, the change in internal energy, and the work done on the hot air balloon when it cools down are negative (-), negative (-), and positive (+), respectively.
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7. Two people are pushing a 40.0kg table across the floor. Person 1 pushes with a force of 490N
[W], and person 2 pushes with a force of 565N (N). If the coefficient of kinetic friction between
the table and the floor is 0.613, determine the acceleration of the table.(12.7m/s2 [49.1° Nofw])
Answer:
20.4 \(m/s^{2}\)
Explanation:
To start doing this problem, first draw a free body diagram of the table. My teacher always tells us to do this, and I find that it is very helpful. I have attached a free body diagram to this answer- take a look at it.
First, let us see if Net force = MA. To do that, we need to determine whether the object is at equilibrium horizontally. For an object to be at equilibrium, it either needs to be moving at a constant velocity or not moving at all. Also, if an object is at equilibrium, there will not be any acceleration. But we know that there IS acceleration horizontally, so it cannot be in equilibrium. If it is not in equilibrium, we can use the formula ∑F= ma.
Let us determine the net force. Since the object is moving horizontally, we can ignore the weight and normal force, because they are vertical forces. The only horizontal forces we need to worry about are the applied force and force of friction.
Applied force = 1055 N (490 + 565)
Friction force= Unknown
To find the friction force, use the kinetic friction formula, Friction = μkN
μk is the coefficient, which the problem includes- it is 0.613.
N is the normal force, which we have to find.
*To find the normal force, we have to determine if the object is at equilibrium VERTICALLY. Since it has no acceleration vertically (it's not moving up/down), it is at equilibrium. Now, when an object is at equilibrium in one direction, it means that all the forces in that direction are equal. What are our vertical forces? Weight (mg) and Normal force (N). So it means that the Normal force is equal to the Weight.
Weight = mg = (40)(9.8) = 392 N
Normal force = 392 N
Now, plug it back into the formula (μkN): (0.613)(392) = 240.296 N
Friction = 240.296 N
Now that we know the friction, we can find the horizontal net force. Just subtract the friction force, 240.296 from the applied force, 1055 N
Horizontal Net Force: 814.704 N
Now that we know the net force, plug in the numbers for the formula
∑F= ma.
814.704 = (40.0)(a)
*Divide on both sides)
a = 20.3676 m/s^2
Round it to 3 significant figures, to get:
20.4 \(m/s^{2}\)
When the atmosphere is absolutely unstable, the environmental lapse rate is ________ the dry adiabatic lapse rate.
Answer: greater than
Explanation:
which process receives geo thermal energy naturally
A rifle is aimed horizontally at a target 53 m away. The bullet hits the target 2.3 cm below the aim point.
The time of flight of bullet is 0.0685 seconds and the speed when it emerges out of the gun is 775.
As the bullet is fired horizontally from the gun at a distance of 53m away. But the bullet hits the target 2.3cm below the target.
So, the vertical displacement of the bullet is 2.3cm. The accelerations in the vertical direction will be g (acceleration due to gravity).
(a) As we know, in case of gravity, we can use equations of motion,
So, using equation,
S = ut + 1/2gt²
Where, u is the initial velocity of the bullet which is 0m/s in this case,
S is the vertical displacement of the bullet,
g is acceleration due to gravity and,
t is time of flight of the bullet.
Putting all the values,
S = 1/2gt²
2.3/100 = 1/2(9.8)(t²)
0.023 = 4.9t²
t² = 0.00469387
t = √0.0046987
t = 0.0685 seconds.
(b) The velocity as it emerges from the gun is equal to the muzzle velocity of the gun,
So, we can write,
Muzzle velocity V = Horizontal distance covered/time taken.
V = 53/0.0685
V = 773.72 m/s.
One thing that should be noted here is that the initial velocity that we took as zero in part (a) is taken with respect to the vertical motion and nit the Horizontal motion. So, one should not confuse the muzzle velocity in part (b) with the initial velocity mentioned in the part(a)
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Complete question - A rifle is aimed horizontally at a target 53 m away. The bullet hits the target 2.3 cm below the aim point. Find
(a) the bullets time of flight and (b) its speed as it emerges from the rifle?
Required information You grab a book and give it a quick push across the top of a horizontal table. After a short push, the book slides across the table, and because of friction, comes to a stop. Let the subscripts be the following: b = book, t = table, e = Earth, h = hand. If the book has a mass of 0.420 kg and the coefficient of friction between the book and the table is 0.400, what is the net force acting on the book after you have stopped pushing it, while it is sliding across the table? Enter a positive answer, if the net force is in the direction of motion and a negative answer, if the net force is opposite to the direction of motion.
To find the net force acting on the book while it is sliding across the table, we need to calculate the frictional force.
1. Identify the required information:
mass of the book (m b) = 0.420 kg and coefficient of friction (μ) = 0.400.
2. Calculate the gravitational force acting on the book (F- gravity) = m b * g,
where g = 9.81 m/s^2 (acceleration due to gravity).
F-gravity = 0.420 kg * 9.81 m/s^2 = 4.1202 N.
3. Since the book is on a horizontal table, the normal force (F_ normal) equals the gravitational force acting on the book:
F_ normal = F_ gravity = 4.1202 N.
4. Calculate the frictional force (F_ friction) acting opposite to the direction of motion using the formula: F_ friction = μ * F_ normal.
F_ friction = 0.400 * 4.1202 N = 1.64808 N.
5. The net force acting on the book (F_ net) is equal to the frictional force, but with a negative sign since it's opposite to the direction of motion:
F_net = -1.64808 N.
The net force acting on the book after you have stopped pushing it, while it is sliding across the table, is -1.64808 N.
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Answer the following question in your activity notebook. 1. Which of the exercises you've done were easy to perform? 2. Did you continue performing those exercises which you found to be difficult? Why? 3. Were you confident in doing those exercises on your own? Why?
Answer: They are all easy to perform as they are bodyweight exercises.
Explanation:
no difficult exercise so NA. Yes I was plenty of online video to watch to address issues
Connecting a charged object to the ground creates a way for the charged object to leak that charge into the earth. This is called ?
Answer:
lightning KILLUAAAA
The two conditions for equilibrium often result in a system of equations such as
F1 + F2 = 64.0 N
and
4.00F1 − 2.00F2 = 0.
(Due to the nature of this problem, do not use rounded intermediate values in your calculations
(a) Find F1.
N
(b) Find F2.
N
The object must experience no net force at all. Moreover, the object's net torque must likewise be zero.
Equation of state equals balance?Equilibrium is the condition in which all of the forces acting on a body are perfectly balanced and the body is immobile. An object is considered to be in an equilibrium state when all of the forces acting on it are equal and in balance. Equilibrium is the state of a thing at rest.
Give me one sentence that describes equilibrium.Everything remains the same while a situation is in equilibrium. An object is considered to be in an equilibrium state when all of the forces acting on it are equal and in balance.
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The density of water is 1000 kg m^3. What is the value expressed in gcm^-3 units? please help me..
(1) 1000 (2) 100 (3) 1 (4) 0.1 (5) 0.01
Here's the neat, cool way to convert units like this:
-- 1 kilogram = 1,000 grams
-- 1 meter = 100 centimeters
So . . . . .
(1000 kg/m³) x (1000 g/kg) x (1 m/100 cm)³ =
(1,000 kg/m³) x (1,000 g/kg) x (1 m³/1,000,000 cm³) =
(1,000 x 1,000 x 1 / 1,000,000) (kg-g-m³ / m³-kg-cm³) = 1 g/cm³
assume that the car moves with constant acceleration. find the distance (in m) the car travels in the first 8.20 s.
a) The average acceleration of the car is 5.25 m/s². (b) The car travels 168 m in the first 8.00 s. (c) The speed of the car 10.0 s after it begins its motion is 52.5 m/s.
(a) To determine the average acceleration of the car, we use the formula:
average acceleration = change in velocity / time interval
The change in velocity is the final velocity minus the initial velocity. Since the car starts from rest, the initial velocity is zero. The final velocity is 42.0 m/s, as given in the problem. The time interval is 8.00 s, also given in the problem. Therefore, we have:
average acceleration = (42.0 m/s - 0 m/s) / 8.00 s
average acceleration = 5.25 m/s²
Therefore, the average acceleration of the car is 5.25 m/s².
(b) To find the distance the car travels in the first 8.00s, we use the formula:
distance = (1/2) x acceleration x time interval²
Since the car moves with constant acceleration, we can use the average acceleration we found in part (a) as the acceleration in this formula. Therefore, we have:
distance = (1/2) x 5.25 m/s² x (8.00 s)²
distance = 168 m
Therefore, the car travels 168 m in the first 8.00 s.
(c) To find the speed of the car 10.0 s after it begins its motion, we can use the formula:
final velocity = initial velocity + acceleration x time interval
Since the car moves with constant acceleration, we can use the average acceleration we found in part (a) as the acceleration in this formula. The initial velocity is zero, since the car starts from rest. The time interval is 10.0 s, as given in the problem. Therefore, we have:
final velocity = 0 m/s + 5.25 m/s² x 10.0 s
final velocity = 52.5 m/s
Therefore, the speed of the car 10.0 s after it begins its motion is 52.5 m/s.
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Complete question:
A certain automobile manufacturer claims that its deluxe sports car will accelerate from rest to a speed of 42.0m/s in 8.00s.
(a) Determine the average acceleration of the car.
(b) Assume that the car moves with constant acceleration. Find the distance the car travels in the first 8.00s.
(c) What is the speed of the car 10.0s after it begins its motion if it can continue to move with the same acceleration?
Can someone help me with these five questions? With an explanation, please! Refer to these photos:
1) The body moved from 0 cm to 4 cm at a constant speed of 1 cm/s.
2) The object moved at a constant speed of 3 cm/s from 0 cm to 3cm
3) Two objects are speeding up and one object is slowing down.
4) The object moved from 4s to 8s at a constant speed of 4 cm/s
5) The horizontal line appears at 5 m/s is the second graph.
What is acceleration?We know that acceleration has to do with the change of of velocity of an object with time.
1) We can see that the position changes by equal amounts in equal time intervals thus the body moved from 0 cm to 4 cm at a constant speed of 1 cm/s.
2) Looking at the shape of the second graph we can see that the object moved at a constant speed of 3 cm/s from 0 cm to 3cm
3) From the images of the ticker tapes, we can see that two objects are speeding up and one object is slowing down.
4) From the fourth graph, we can see that the object moved from 4s to 8s at a constant speed of 4 cm/s
5) The graph in which the horizontal line appears at 5 m/s is the second graph.
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A car of mass 750 kg accelerates away from traffic lights. At the end of the first 100 m it has reached a speed
of 12 m/s. During this time, its engine provides an average forward force of 780 N, and the average force of
friction on the car is 240 N.
a Calculate the work done on the car by the force of its engine.
b Calculate the work done on the car by the force of friction.
c Using ke. = mv2, calculate the increase in the car's kinetic energy at the end of the first 100 m.
d Explain whether your answers are consistent with the principle of conservation of energy.
the work done on the car by the force of its engine is 78,000 J.
" The work done on the car by the force of friction is 24,000 J.
Increasing the car's kinetic energy at the end of the first 100 m is 54,000J
a. Completed work = force x distance. Engine output = 780 N, that is,
780 N x 100 m = 78,000 J.
b. Completed work = force x distance. Friction force = 240 N, that is,
240 N x 100 m = 24,000 J.
c. Kinetic energy = 1 \ 2 x m x v2
= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.
How powerful is the engine of a car?Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.
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what is keplers third law?
Kepler's third law states that the square of the period of a planet's orbit around the sun is proportional to the cube of its average distance from the sun.
Kepler's third law, also known as the law of harmonies, is a mathematical relationship that describes the motion of planets around the sun. It states that the ratio of the cube of a planet's average distance from the sun to the square of its orbital period is constant for all planets in the solar system.
Mathematically, this can be expressed as T^2 = k*R^3, where T is the orbital period of the planet, R is its average distance from the sun, and k is a constant of proportionality. Kepler's third law is an important tool for astronomers to study and understand the dynamics of the solar system.
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this is a type of protein that helps to speed up metabolic reactions while remaining unchanged.
Answer:
A fundamental task of proteins is to act as enzymes—catalysts that increase the rate of virtually all the chemical reactions within cells.
Can you help me on this please
Answer: the water level would rise since the pebble displaces minimal water compared to the boat.
Explanation:..........
How can energy conservation be considered an energy source?
Answer:This could be in the form of using fewer energy services or using devices that require less energy.
Explanation:
A type of mirror that focuses light and produces real images ?
Answer:
concave mirror
Explanation:
Only a concave mirror is capable of producing a real image and this only occurs if the object is located a distance greater than a focal length from the mirror's surface.
Answer:
concave mirror
Explanation:
it has a reflecting surface
Refer to your lab guide and review the data in Table F to complete each statement.
The mass of G1 at all times during this trial was 0.5
kg.
The velocity of G1 + G2 after the collision was
m/s.
The momentum of G1 after the collision was o
kg . m/s.
Answer:
0.5 kg
-1.24 m/s
-2.10 kg•m/s
Explanation:
Answer:
Full Questions + Answers
Explanation:
Refer to your lab guide and review the data in Table F to complete each statement.
The mass of G1 at all times during this trial was
0.5
kg.
The velocity of G1 + G2 after the collision was
-1.24
m/s.
The momentum of G1 after the collision was
-2.10
kg · m/s.
Light of wavelength 600 nm in air goes into a medium where the index of refraction is 1.73. What is the frequency of this light in the medium?
I need it with the given,unknowns ans equation and solution
ASAP
Answer:
5.00 × 10^14 Hz
Explanation:
The wavelength of the light in the medium can be calculated by using the formula:
λ = v / f
Where;
λ = wavelength (m)
v = speed of light
f = frequency (Hz)
From the provided information, λ = 600 nm (600 × 10^-9m), v = 3 × 10^8m/s.
λ = v / f
λ = 3 × 10^8/600 × 10^-9
λ = 0.005 × 10^(8+9)
λ = 0.005 × 10^17
λ = 5.00 × 10^14 Hz
The frequency of the light in the medium is 5.00 × 10^14 Hz
What do I have to answer guys? I really didn’t get this theme so I would be grateful for explanation or answer
The complete equations are:
Charge flows Q = electric current (I) x (t) time.The potential difference V = I current x R resistance.Resistance R = V potential difference / I current.What is the potential difference?The difference that might exist between any two points. The amount of work required to move a unit positive charge along any path from one point to another without accelerating is referred to as the electric field.
The external effort required to move a charge in an electric field from one position to another is known as an electric potential difference or voltage.
Therefore, the formula are:
Charge flows Q = electric current (I) x (t) time.The potential difference V = I current x R resistance.Resistance R = V potential difference / I current.To learn more about potential differences, refer to the link:
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A great strength of correlational research is the O cause-effect sequencing of events. O ambiguity of the results. O ability to extract the influence of confounded variables. f
O act that it occurs in real-world settings.
A great strength of correlational research is the -fact that it occurs in real-world settings.
What is correlational research?Correlational research is a form of non-experimental research methodology that employs statistical analysis to investigate the link between two variables. The impacts of unrelated factors on the variables under inquiry are not investigated by correlational research designs.
Characteristics-
1.Non-experiment: It implies that in order to support or refute a theory, researchers do not necessarily need to modify variables using a scientific technique.
2.Backward-looking: Correlational research solely considers historical information and keeps track of past events. It is measured and used by researchers to identify historical patterns between two variables.
3.Dynamic: Correlational research's patterns between two variables are never static and are constantly evolving. Due to numerous causes, two variables with a history of negative correlation studies may eventually show a positive correlation relationship.
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Speed can be represented by many different ____________________ of distance and time.
Speed can be represented by many different units of distance and time.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Speed is defined as distance per unit time so it's unit are meter per sec, kilo-meter per hour, that is different unit of distance and time.
Speed can be represented by many different units of distance and time.
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Kofi, with mass 42.00 kg, is riding a skateboard with a mass of 2.00 kg and traveling at 1.20 m/s. Kofi jumps off and the skateboard stops dead in its tracks. In what direction and with what velocity did he jump
He jumped off with a velocity of 1.26 m/s in the same direction as the skateboard .
Conservation of linear momentumAccording to the principle of conservation of linear momentum, the total momentum of a system is constant. Hence;
Total momentum before = (42.00 kg + 2.00 kg) 1.20 m/s = 52.8 Kgm/s
Total momentum after = (42.00 kg × v) + (2.00 kg × 0) = 42.00 v Kgm/s
Applying the law of conservation of linear momentum;
52.8 Kgm/s = 42.00 v Kgm/s
v = 52.8/42.00
v = 1.26 m/s
He jumped off with a velocity of 1.26 m/s in the same direction as the skateboard .
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you place a large pebble in a slingshot, pull the elastic band back to your chin, and release it, launching the pebble horizontally at a speed of vv. you then repeat the exact same procedure (pulling the elastic band back the same distance) with a smaller pebble. the smaller pebble leaves the slingshot with a speed of 5v5v. how does the mass of the larger pebble compare to that of the smaller pebble?
The smaller pebble leaves the slingshot with a speed of 500 m/s.The mass of the larger pebble 25 times more mass compare to that of the smaller pebble.
In Both the cases work done by the elastic band is same i.e
WLarger = WSmaller
(1/2)MLargerVLarger2 = (1/2)MSmallerVSmaller2
MLarger/MSmaller = (VSmaller/VLarger)2
MLarger/MSmaller =(500/100)2 =25
Teenagers, young adults, and others utilise various stimulant medications collectively referred to as "speed" to feel more focused and alert, and occasionally to get euphoric. Additionally, some people take various forms of speed to suppress their appetite. You lack brute force, intimidation, and might without speed. Simply for show and to assist friends who are moving large pieces of furniture, they are useless. The good news is that speed can be improved with the right physical preparation. The velocity of a body or object determines the direction of its motion. Speed is often measured as a scalar value. The most basic definition of a vector quantity is velocity. It gauges the rate at which a distance varies. It relates to the speed at which displacement is altering. Its velocity is the speed at which something is travelling in a particular direction.
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We have access K samples in order to compute our estimation. Select one or more statement(s) from the options below that are correct about model free or model based approaches? A) Model Free Approach first tries to estimates the probability distribution before estimating the expectation B) Model Based Approach first tries to estimates the probability distribution before estimating the expectation C) Model Based Approach estimate would be given by ΣK i=1 f(Xi)/K D) Model Free Approach estimate would be given by ΣK i=1 f(Xi)/K
The correct statement(s) about model free and model based approaches are:B) Model Based Approach first tries to estimates the probability distribution before estimating the expectation
D) Model Free Approach estimate would be given by ΣK i=1 f(Xi)/K
A and C are incorrect.
Model free approaches do not estimate the probability distribution before estimating the expectation. Instead, they use the observed data to estimate the parameters of the distribution directly.
Model based approaches do estimate the probability distribution before estimating the expectation. They typically use a probabilistic model to represent the underlying distribution of the data, and then estimate the parameters of the model from the data. Once the parameters are estimated, the expectation can be calculated using the estimated probability distribution.
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