The oscillator's amplitude decreases with time at a time constant of five.
Given the information below:
0.368 as the amplitude fell by 36.8%.
10.0 seconds have passed.
To calculate the time constant's value:
Mathematically, the formula: gives the amplitude for damped harmonic motion.
\(X/X_{o} =e^{t/2r}\)
t is the time.τ is the time constant.X is the instantaneous value of amplitude.\(X_{0}\) is the initial value of amplitude.Substituting the given parameters into the formula, we have:
Time constant = 5
What is the amplitude of the oscillator?
The amplitude of oscillation is defined as distance from the mean or equilibrium position to either extreme. Oscillation is termed as one complete to and fro motion of the particle from its mean position.
What is meant by harmonic oscillation?
In classical mechanics, a harmonic oscillator is a system that, when displaced from it's equilibrium position, experiences a restoring force F proportional to the displacement x , where k is a positive constant.
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Urgent! Which is not an example of work? Question 2 options: pushing a box across the floor picking up a box off the floor raising a barbell over your head trying to push a rock that never moves
Answer:
trying to push a rock that never moves
Explanation:
1. A car slows to a stop as it comes to a red light. Its
acceleration is -5 m/s² and stops after 2.3 seconds.
What was its initial velocity?
The initial velocity of the car as it slow to rest with an acceleration of -5 m/s² is 11.5 m/s.
What is velocity?
This can be defined as the ratio of displacement to the time of a body
To calculate the initial velocity of the car, we use the formula below.
Formula:
u = v-at........ Equation 1Where:
u = Initail velocityv = Final velocitya = Accelerationt = Time.From the question,
Given:
v = 0 m/sa = -5 m/s²t = 2.3 secondsSubstitute these values into equation 1
u = 0-(-5×2.3)u = 0+11.5u = 11.5 m/s.Hence the initial velocity of the car is 11.5 m/s
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A child has an ear canal that is 1. 3 cm long. at what sound frequencies in the audible range will the child have increased hearing sensitivity?
A child has an ear canal that is 1. 3 cm long. Sound frequencies in the audible range for the child to have increased hearing sensitivity is 6600 Hz to 19,800 Hz
The shape of the human ear is similar to a pipe that has a closed end and other end is open. Hence,
λ = 4L where L is the length of child's ear
Wavelength, λ = 4 × Length of the ear of the child
λ = 4 × 0.013m
λ = 0.052m
Frequency is the no. of oscillations per unit time.
The frequency of the sound, ν = c/λ
where c is the speed of sound i.e. 343 m/s
λ is the wavelength of sound
The child's audible range is equal to
ν = 343/0.052
ν = 6600Hz
We can also say that, ν is 13200 Hz or 19,800 Hz.
In general, the audible range of frequency for human ear is 20Hz to 20,000Hz.
Hence, sound frequencies in the audible range will the child have increased hearing sensitivity is 6600Hz to 19800 Hz.
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It took a bulldozer 62,000 J of work to move a rock 30 m. It took 5 minutes. How much force did the bulldozer have to apply?
A- 2066.6 N
B- 413.33 N
C- 12,400 N
D- 10,333.33 N
Answer:
A (2066,6 N)
Explanation:
Use the Work formula
62.000J = F . 30
62.000/30 = 2066,6 N
The amout of time it took to move the rock doesn´t matter at all.
It is called a distraction variable, We don´t need it to solve the problem it is there just to confuse.
a point that moves on a coordinate line is in simple ---select--- when its distance d from the origin at time t is given by either d = a sin(t) or d = a cos(t
A point that moves on a coordinate line is in simple harmonic motion when its distance d from the origin at time t is given by either d = a sin(t) or d = a cos(t).
Simple harmonic motion is a type of periodic motion in which an object moves back and forth along a straight line. A point that moves on a coordinate line is in simple harmonic motion when its distance from the origin at time t is given by either d = a sin(t) or d = a cos(t). The amplitude of the motion is a, which represents the maximum distance from the origin that the point reaches.
The motion is periodic, meaning that it repeats itself at regular intervals of time. Simple harmonic motion is common in many physical systems, such as springs, pendulums, and sound waves.
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Please help, I don't get this
A negative charge of -0.0005 C exerts an attractive force of 9.0 N on a second charge that is 10m away. What is the magnitude of the second charge?
The magnitude of the second charge is calculated using Coulomb's law. The magnitude of the second charge is 0.00022 C.
What is Coulomb's law ?Coulomb's law states the force exerted between two charges is directly proportional to magnitude of charges and inversely proportional to their distance.
F = k q1 q1/r²
where k is a constant equal to 8 × 10⁹ Nm²/C²
Given F = 9 N
q1 = - 0.0005 C
r = 10 m
9 N = - 0.0005 C × q2 × 8 × 10⁹ Nm²/C² /(100 m²)
q2 = 9 N × 100 m² / (- 0.0005 C ×8 × 10⁹ Nm²/C² )
= 0.00025 C
Therefore, the magnitude of the second charge here is 0.00025 C.
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The magnitude of the second charge is 3.6 x 10⁻⁶ C.
What is the magnitude of the charge?The electric charge carried by a single proton, or alternatively, the magnitude of the electric charge carried by a single electron, which has charge e, is the elementary charge, which is often represented as e or occasionally q. This fundamental physical constant is this elemental charge.
The electric force between two point charges is given by Coulomb's law:
F = kq₁q₂ / r²
where F is the force between the charges,
k is Coulomb's constant (9 x 10⁹ N·m²/C²),
q₁ and q₂ are the magnitudes of the charges,
and r is the distance between them.
In this problem, we are given the force between two charges and one of the charges.
We can rearrange Coulomb's law to solve for the magnitude of the second charge:
q₂ = F * r² / (k * q₁)
Substituting the given values, we get:
q₂ = 9.0 N * (10 m)² / (9 x 10⁹ N·m²/C² * 0.0005 C)
q₂ = 3.6 x 10⁻⁶ C
Therefore, the magnitude of the second charge is 3.6 x 10⁻⁶ C.
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Choose all of the correct statements below.
You dump a container of salt into a container of pepper to create a homogenous mixture.
Atmospheric oxygen gas is a pure substance.
A pure substance is formed when you combine all of the ingredients for a salad for lunch.
You create a homogenous mixture by completely dissolving your fruit punch powder in water.
The air we breathe is a solution (homogenous mixture).
It is impossible to ever separate the components of a mixture.
Sodium and chlorine chemically combine to form the pure substance table salt.
We are going to be highlighting both the correct and incorrect options in this exercise with their explanations
The correct options are
"You create a homogenous mixture by completely dissolving your fruit punch powder in water"
This is correct because a homogeneous mixture is a mixture in which the composition is uniform throughout the mixture
"The air we breathe is a solution (homogenous mixture)."
This is correct because In air, all gases would have a uniform composition. Therefore, the air is an example of homogeneous mixture.
The incorrect options are
"You dump a container of salt into a container of pepper to create a homogenous mixture"
This is not correct because a homogeneous mixture is a mixture in which the composition is uniform throughout the mixture.
"Atmospheric oxygen gas is a pure substance"
This is not correct because atmospheric oxygen gas consists of other substance and elements e.g Nitrogen
"A pure substance is formed when you combine all of the ingredients for a salad for lunch"
This is not correct because a pure substance is substance that does not contain other element hence it does not have impurities
"It is impossible to ever separate the components of a mixture."
This is not correct because we can separate the components of a mixture by employing the correct separation techniques
"Sodium and chlorine chemically combine to form the pure substance table salt"
Salt is a composed of two elements Sodium and Chlorine to form a compound, hence a salt is not a pure substance
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Question 9 of 25
What is one difference between an atom and a molecule?
A. Only molecules can become ions.
B. Only atoms can become ions.
C. An atom can contain one or more chemical bonds.
D. A molecule can contain more than one element.
Light of wavelength 5. 6×10−7m passes through two parallel slits and falls on a screen 4. 5 m away. Adjacent bright bands of the interference pattern are 2. 2 cm apart.
Part A
Find the distance between the slits.
Express your answer to two significant figures and include the appropriate units.
d = Part B
The same two slits are next illuminated by light of a different wavelength, and the fifth-order minimum (m = 5)for this light occurs at the same point on the screen as the fourth-order minimum (m = 4) for the previous light. What is the wavelength of the second source of light?
Express your answer to two significant figures and include the appropriate units.
λ =
A. The distance between the slits is approximately 3.21 × \(10^{-6}\) m.
B. The wavelength of the second source of light is approximately 4.48 × \(10^{-7}\) m.
Part A:
To find the distance between the slits (d), we can use the formula for the interference pattern:
d * sin(θ) = m * λ
Where:
d is the distance between the slits
θ is the angle between the line perpendicular to the slits and the direction of the bright band
m is the order of the bright band (m = 1, 2, 3, ...)
λ is the wavelength of the light
In this case, we know that adjacent bright bands are 2.2 cm apart, which can be converted to meters by dividing by 100:
2.2 cm = 0.022 m
We can consider the first-order (m = 1) bright band. The angle θ can be approximated as the tangent of the angle:
θ ≈ tan(θ) = opposite/adjacent = 0.022 m / 4.5 m
Now we can rearrange the formula to solve for d:
d = (m * λ) / sin(θ)
Using the values we have:
d = (1 * 5.6 × \(10^{-7}\) m) / sin(0.022 m / 4.5 m)
Calculating this expression:
d ≈ 3.21 × \(10^{-6}\) m
Therefore, the distance between the slits is approximately 3.21 × \(10^{-6}\) m.
Part B:
For the second source of light, we know that the fifth-order minimum (m = 5) occurs at the same point on the screen as the fourth-order minimum (m = 4) for the previous light. Let's assume the wavelength of the second source of light is λ'.
We can set up the following equation using the formula for interference patterns:
d * sin(θ) = m * λ'
For the fourth-order minimum, we have:
d * sin(θ) = 4 * λ
And for the fifth-order minimum, we have:
d * sin(θ) = 5 * λ'
Since both minima occur at the same point on the screen, the values of sin(θ) and d are the same for both equations. Therefore, we can equate the right sides of the equations:
4 * λ = 5 * λ'
To find λ', we can rearrange the equation:
λ' = (4 * λ) / 5
Substituting the known value for λ:
λ' = (4 * 5.6 × \(10^{-7}\) m) / 5
Calculating this expression:
λ' = 4.48 × \(10^{-7}\) m
Therefore, the wavelength of the second source of light is approximately 4.48 × \(10^{-7}\) m.
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The diagrams show four blocks of steel. The blocks are all drawn to the same scale. The same quantity of thermal energy is given to each block. Which block shows the greatest rise in temperature?
Block 4 shows the greatest rise in temperature. The rise in the temperature is inversely proportional to the initial length. The concept of thermal expansion is used in the given problem.
What is thermal expansion?Thermal expansion is the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.
The formula for the thermal expansion is found as;
\(\rm \triangle L = L \alpha \triangle T \\\\\ \triangle T = \frac{\triangle L}{L\alpha}\)
The rise in the temperature is inversely proportional to the initial length;
Block 4 has the smallest initial length.
Hence, the block 4 has the greatest rise in temperature.
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DUE IN 4 HOURS! HELP! WILL MARK BRAINLIEST IF DONE WITHIN THE HOUR!
Maisey is running 12mph and comes to an abrupt stop in 3 seconds when she hears her name called. What is her acceleration?
Answer:
~ 0.001 m/s^2
Explanation:
If you convert 12 miles per hour to, miles per second, it makes this easier to calculate, so do that first
12m/ 1 hour * 1 hour/ 60 mins * 1 min/ 60 sec = ~0.003333 miles per second.
Next remember that acceleration = velocity/time
So our new velocity: 0.003333 over time: 3 seconds = the acceleration.
0.003333/3 = 0.001 m/s^2
at what angle wl the projectile have the highest peak? angle 60 degrease,45 degrease, 30degrease?
Answer:
Explanation:
The highest peak attained by a projectile is at an angle of 60 degrees.
The peak height of a projectile is directly proportional to the initial value of the vertical velocity component and the angle with which it is thrown.
Also, the formula for calculating the peak value of any projectile motion is given by,
\(H = \frac{u^2sin^2\theta}{2g}\)
Where H is the peak height
u is the initial velocity ( in the vertical direction)
\(\theta\\\) is the angle with which it is thrown
g is the acceleration due to gravity
If it is given, the initial velocity is the same. Hence, H is directly proportional to \(sin^2\theta\\\) which increases with an increase in \(\theta\\\). Hence, the greater the angle, the greater the height of the projectile would be.
Since The highest angle among the given option is 60 degrees, it attains the highest peak.
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8. A tank shoots a projectile at an angle of 67* above the horizon and at a speed of 53 m/s
toward an enemy tank. How far away will the enemy be located for a direct hit?
I
Answer:
Explanation:
We are tp calculate the range of the projectile. This is expressed as;
R = 2Usin theta/g
Given
U = 53m/s
Theta = 67°
Substitute;
R = 2(53)sin67/9.8
R = 106sin67/9.8
R = 106(0.9205)/9.8
R = 97.57/9.8
R = 9.96m
Hence the enemy is 9.98m located for a direct hit.
The equalizing temperature changes in response to changes in external forces of the boundary conditions of climate. What is this about?.
Answer:
It's climate sensitivity.
What is the net force acting on the airplane?
740 N right -->
700 N right -->
100 N left <--
760 N right -->
\(\huge{ \mathrm{ \underline{ Answer }\: \: ✓ }}\)
Total force acting on right side = 800 N
Total force acting on left side :
60 N + 40 N100 NNow, equivalent force acting on the plane is :
greater force - minor force 800 N - 100 N 700 NewtonsAnd the direction of equivalent force will be the direction of greater force, that is right direction.
Hence, Correct option is :
700 N right -->_____________________________
\(\mathrm{ \:TeeNForeveR\:}\)
What is the minimum energy needed to change the speed of a 1600-kg sport utility vehicle from 15. 0 m/s to 40. 0 m/s?.
The power required to change a sport utility vehicle's speed is 2725 Watt.
What is speed?A measure of how quickly an object's location can shift in any direction. Speed is defined as the distance traveled divided by the time required to cover that distance. It is a scalar because speed only has a directions and no magnitude. In common usage and kinematics, the speed of an object is a scalar quantity and is defined as the amount of the change within this object's motion per unit of time or over time.
How do you calculate the speed and its measurement?Speed is calculated as follows: speed = distance * time. Knowing the units for distance and time is necessary to calculate the units for speed. The units will be in metres per second (m/s) in this example since the distance is measured in metres (m) and the time is measured in seconds (s).
Speed is a unit of measurement for how quickly something is moving. The most popular speed measurements are miles per hour (mph), kilometers per hour (km/h), and metres per second (m/s).
Briefing:Mass of the sport utility = 1600kg
Initial velocity (v1) - 15m/s, (152 = 225)
Final velocity (v2) - 40m/s, ( 402 = 1600)
To find the energy required, Kinetic energy (K.E) = 1/2 mv2
K.E = final K.E - initial K.E
= 1/2(v2-v1)
= 1/2×1600×(1600-225)
= 80 × 1375
= 11000 J
Power = Energy (E)/Time (t) = 1100joule/4sec
= 2725Watt.
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17) Name two ways you could decrease the potential energy of a bucket full of water sitting on a bench.
Explanation:
The potential energy of an object has the following formula
Potential energy = mgh
where m = mass of the object
g = acceleration due to gravity
h = height of the object
This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.
In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.
This can be done by: -
(i) Lifting the bucket full of water in such a way that you
decrease its height as compared to the bench.
(ii) Put the bucket full of water on a stool whose height is
lower than the bench.
Answer:
1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.
2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket
If the force is applied to a car, then its acceleration will ___________ because of Newton's _____________.
2. A javelin is thrown through an angle of 30o to the horizontal. Find the time taken by the javelin to reach the maximum height if the initial velocity is 60ms-1 [ take g =10 ms-1]
Answer:
3 seconds
Explanation:
The initial velocity is 60 m/s at an angle of 30° to the horizontal, so we can calculate the initial velocity in the vertical direction as
Viy = Vi sin(θ)
Viy = 60 sin(30)
Viy = 60(0.5)
Viy = 30 m/s
Then, we can use the following equation to calculate the time that it takes to reach the maximum height.
\(\begin{gathered} v_{fy}=v_{iy}-gt \\ v_{fy}+gt=v_{iy} \\ gt=v_{iy}-v_{fy} \\ \\ t=\frac{v_{iy}-v_{fy}}{g} \end{gathered}\)At a maximum height the vertical velocity is 0 m/s, so replacing viy = 30 m/s, vfy = 0 m/s and g = 10 m/s², we get
\(\begin{gathered} t=\frac{30\text{ m/s-0m/s}}{10\text{ m/s}^2} \\ \\ t=\frac{30\text{ m/s}}{10\text{ m/s}^2} \\ \\ t=3\text{ s} \end{gathered}\)Therefore, the answer is 3 seconds
ASTRONOMY!!!
Towards the end of her Ted Talk, Ghez says, "it's actually like looking at a pebble at the bottom of a stream." What is meant by this?
Ghez's statement about "looking at a pebble at the bottom of a stream" refers to the difficulty of observing and studying black holes.
Ghez is referring to the fact that black holes are incredibly dense and have an intense gravitational pull that makes it difficult to observe them directly. Instead, scientists must infer their presence through the effects they have on nearby stars and other matter.
This requires extremely sensitive instruments and sophisticated techniques, much like trying to spot a pebble at the bottom of a stream. The comparison emphasizes the challenges involved in studying black holes and highlights the incredible achievements of Ghez and her colleagues in doing so.
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a runner taking part in a 400-m dash must run around the end of a track that has a circular arc with a radius of curvature of 38 m. if he completes the 400 m dash in 47.6 s and runs at constant speed throughout the race, what is his centripetal acceleration as he runs the curved part of the track?
A runner taking part in a 400-m dash must run around the end of a track that has a circular arc with a radius of curvature of 38 m. if he completes the 400 m dash in 47.6 s and runs at a constant speed throughout the race as he runs the curved part of the track, the centripetal acceleration of the runner in the 400-m dash is 32.24 m/s².
In order to calculate the centripetal acceleration of the runner in a 400-m dash, we must first consider the circular arc with a radius of curvature of 38 m. The speed of the runner throughout the race must also remain constant. As the runner completes the 400-m dash in 47.6 s, we can then calculate the centripetal acceleration as he runs the curved part of the track.
The centripetal acceleration (ac) is equal to the square of the speed of the runner (v) divided by the radius of curvature of the track (r). Therefore, the centripetal acceleration can be calculated using the equation ac = v²/r.
Given that the speed of the runner is constant throughout the race, we can calculate the centripetal acceleration as follows: ac = (400 m/47.6 s)²/38 m = 32.24 m/s².
Therefore, the centripetal acceleration of the runner in the 400-m dash is 32.24 m/s² as he runs the curved part of the track.
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A wave has a time period of 0.1s and is travelling at a speed of 340 m/s. calculate the wavelength of the wave
If a wave has a time period of 0.1s and is travelling at a speed of 340 m/s, the wavelength of the wave is 34 meters.
What is wave?A wave is a dynamic disturbance of one or more quantities that propagates in physics, mathematics, and related sciences. When waves oscillate frequently around an equilibrium value at a certain frequency, they are said to be periodic.
The wavelength of the wave = speed of the wave × time period of the wave
= 340 m/s × 0.1 s
= 34 m.
Hence, the wavelength of the wave is 34 meters.
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Which statement describes a chemical property related to the particles that make up a material
Answer:
Salt crystals are hard and brittle because they are made up of atoms that combine by ionic bonding.
Explanation:
How does the time of fall relate to the weight (mg) of the coffee filters? What happens to the time of fall if you double the mass of falling filters? Explain
The time of fall of an object is not directly related to its weight (mg), but rather to the acceleration due to gravity (g) and the distance it falls.
In the case of coffee filters, assuming they have a similar shape and size, the weight (mg) will be proportional to the mass (m) of the filters.
Doubling the mass of the falling filters will not have a direct effect on the time of fall if we assume that air resistance is negligible. According to the equation for the time of fall, which is derived from the
kinematic equations:
Time = √((2 * distance) / g)
The mass of the falling object does not appear in this equation. Therefore, doubling the mass will not change the time of fall if other factors such as distance and acceleration due to gravity remain constant.
However, in real-world scenarios, where air resistance is present, the time of fall can be affected by the mass of the falling filters. Increased mass can lead to increased air resistance, which can slow down the filters and increase the time of fall. This effect becomes more significant as the mass and size of the falling object increase.
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Which choice below correctly pairs a scientist with their work on atoms and elements
options=
Thompson-the plum pudding model.
Dalton-the quantum theory of the atom.
Bohr-the uncertainty of particles in an atom.
Rutherford-the atomic theory of matter.
The choice that correctly pairs a scientist with their work on atoms and elements is Thompson-the plum pudding model
Dalton's work on atoms and elements is called the atomic theory of matter. The quantum theory of the atom was proposed by Erwin Schrödinger. Bohr's work on atoms and elements is called planetary model / Bohr's atomic model. The uncertainty of particles in an atom is the work of Werner Heisenberg. Rutherford's work on atoms and elements is called Rutherford model of the atom or Rutherford atomic model.
The plum pudding model was the atomic model of J J Thomson. It was proposed in 1900. It explains the inner structure of the atom. He also discovered electrons during a cathode ray tube experiment in 1897.
Therefore, the choice that correctly pairs a scientist with their work on atoms and elements is Thompson-the plum pudding model
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The duration between the emission of the sound from the echo reception is: t - 1.5 s. the distance between the observer and the sound receiver knowing that the speed of sound in the air is worth
V - 340 m/s is:
Answer:
. tt tt t t t t t t tt t tt t t jk j k j k j k j k jk k j k jk
For a symmetrical step-index slab waveguide with n1=2.2, n2=2.2 and d=6micrometer propagating light at 1.55 micrometer, draw the dispersion curves for TE modes (Normalized frequency V versus normalized propagation constant
To draw the dispersion curves for TE modes in a symmetrical step-index slab waveguide, we need to plot the normalized frequency (V) versus the normalized propagation constant (β).
Given the following parameters:
- n1 = 2.2 (refractive index of the core)
- n2 = 2.2 (refractive index of the cladding)
- d = 6 micrometers (thickness of the waveguide)
- λ = 1.55 micrometers (wavelength of light)
The normalized frequency (V) for TE modes is given by:
V = (2π / λ) * a * [(n1^2 - n2^2)^(1/2)]
The normalized propagation constant (β) for TE modes is given by:
β = (2π / λ) * n1 * [(n1^2 - n2^2)^(1/2)]
To plot the dispersion curves, we vary the core width (a) while keeping the other parameters constant. The range of core widths to consider will depend on the specific requirements of the waveguide.
Without specific values for the core width (a) range, we cannot provide a complete graph. However, you can use the given equations to calculate the corresponding values of V and β for different core widths, and then plot the dispersion curves accordingly.
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Would you want to minimize or maximize the heat transfer to and from the handrails? Explain your reasoning.
Answer:
minimize some of the steel and the handrails would be a lot more safer for the children
Explanation:
I would like to minimize the heat transfer from the handrails because when it is decrease, the friction will increase.
What is Heat transfer?
Any or all of a number of events, referred to as processes, known as heat transfer, are capable of moving energy + entropy from one place to another. Typically, convection, nonlinear thermal, etc. conduction are used to describe specific methods. It involves the slow, energy- and entropy-transfer-involved process of conduction between adjacent molecules.
A hot fluid, such as air, must move during convective; this process is typically quite quick.
Radiation is indeed the term for the electromagnetic radiation that is used to describe how energy is transferred from its emission at a heated surface to its absorption on that other surface without a medium.
The reason behind minimizing the heat transfer from the handrails is because when the heat transfer is decreased, the friction in the rails will increase, and it will be easy to hold them for support.
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Can anyone tell the answer