The Z register is never updated in any microoperation found in the RSC's microcode specification, which brings up the following questions: a. Under what condition is the Z register updated? b. When Z is updated, under what condition would it be set to zero? c. When Z is updated, under what condition would it be set to one?
Answers
Based on the information provided, we can assume that the Z register is not updated through any of the microoperations in the RSC's microcode specification. However, we do not have enough information to determine under what conditions the Z register would be updated.
In general, microcode specifications define the microoperations that are performed by the processor's control unit to execute machine instructions. These microoperations can include operations such as register transfers, arithmetic and logic operations, and conditional branching.
It is possible that the Z register is updated through a microoperation that is not explicitly listed in the RSC's microcode specification. Alternatively, the Z register may only be updated under specific conditions that are not mentioned in the specification.
To determine under what conditions the Z register is updated, we would need to consult the processor's architecture manual or datasheet, which should provide a detailed description of the processor's register set and instruction set.
As for whether the Z register would be set to zero or one when it is updated, this would depend on the specific instruction being executed and the logic implemented in the microcode. Generally, the Z register is used to store the result of a comparison or arithmetic operation and is set to zero if the result is equal to zero and set to one if the result is not equal to zero. However, this may vary depending on the specific implementation.
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Related Questions
Which of the following are consequences of burning coal for energy? (mark all that apply) Check All That Apply A. increased levels of CO2 in the atmosphere B. increased heavy metals (lead and mercury) released into the air C. acidified rain D. increased radicals that deplete ozone in the stratosphere:
Answers
The following are consequences of burning coal for energy increased levels of CO2 in the atmosphere, increased heavy metals (lead and mercury) released into the air and Acidified rain. The correct options are a, b and c.
Burning coal produces a number of main emissions: Sulphur dioxide (SO2), which causes respiratory conditions and acid rain, Nitrogen oxides (NOx), which cause respiratory diseases and smog, Particulates that cause lung sickness, respiratory diseases, fog, and haze, The main greenhouse gas produced by burning fossil fuels (coal, oil, and natural gas) is carbon dioxide (CO2).
Mercury and other heavy metals have been associated with developmental and neurological harm in both humans and other animals. Power stations produce bottom ash and fly ash as byproducts of burning coal.
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HELP PLEASE!! ASAP!!!!
can some answer this 2 questions please as paragraph i want it nowww it is graded what action should be taken to make it safe ? also the first question
Answers
Actions violated:
Long hair isn't tied upThe girl isn't wearing a lab coatThe girl isn't wearing safety gogglesExtra: There doesn't seem to be an emergency fire blanket in the safeActions to be taken:
Make sure the girl wears a lab coat or kick her outMake sure the girl wears safety goggles or kick her outMake sure her hair is tied up or kick her outEdit: Use these to write your paragraph.
In southeast Utah, the San Juan River and its tributaries have cut through hundreds of feet of Paleozoic sedimentary rocks. The photo below shows the Honaker Trail Formation, the Halgaito Formation, and the Cedar Mesa Sandstone. Each unit is composed of rocks that were deposited in distinct environments, and record the transition from a marine to continental setting.
- The Honaker Trail Formation is made up of predominately carbonates, which record deposition in a shallow marine setting.
- The Halgaito Formation is located above the Honaker Trail Formation. This unit is composed of siltstones and sandstones deposited in channel and flood plain environments on a coastal plain.
- The layers of the Cedar Mesa Sandstone make up the steep cliffs of this region. This unit is composed of sandstones, which accumulated mostly in an eolian, or wind-blown environment.
Use the information above and your knowledge of relative dating to rank the geologic events from oldest to youngest. Pay particular to the sediments and depositional environments for each formation.
Oldest Event Youngest Event
__________ ____________
1.Carbonate sediments were deposited in a shallow marine depositional environment.
2. Sediment was deposited in stream and floodplain depositional environments.
3. An abundance of sand was transported and deposited by wind in a large dune field.
4. The San Juan River and tributaries incised downward into preexisting sedimentary rock units.
Answers
Ranking the geologic events from oldest to youngest:
1. Carbonate sediments were deposited in a shallow marine depositional environment.
2. Sediment was deposited in stream and floodplain depositional environments.
3. An abundance of sand was transported and deposited by wind in a large dune field.
4. The San Juan River and tributaries incised downward into preexisting sedimentary rock units.
The San Juan River and tributaries incised downward into preexisting sedimentary rock units. Therefore, the correct order of geologic events from oldest to youngest is: Carbonate sediments were deposited in a shallow marine depositional environment; sediment was deposited in stream and floodplain depositional environments; an abundance of sand was transported and deposited by wind in a large dune field; and the San Juan River and tributaries incised downward into preexisting sedimentary rock units.
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a nitrogen compressor in a chemical plant adiabatically compresses 600 ft3/s of n2 from 15 psia and 77°f to 300 psia and 900°f. the nitrogen then passes through a heat exchanger, where it is cooled at constant pressure to an outlet temperature of 150°f. determine the power input (hp) to the compressor and the rate of heat transfer (btu/hr) removed from the nitrogen in the heat exchanger. assume a calorically perfect gas with specific heats evaluated at the mean temperatures for each process.
Answers
Given data:The nitrogen compressor adiabatically compresses 600 ft3/s of N2 from 15 psia and 77°F to 300 psia and 900°F. The nitrogen then passes through a heat exchanger, where it is cooled at constant pressure to an outlet temperature of 150°F.
Assume a calorically perfect gas with specific heats evaluated at the mean temperatures for each process.Power Input (HP) to the compressor We know that, Hence,The power input to the compressor is 4760 HP.Rate of heat transfer (BTU/hr) removed from the nitrogen in the heat exchanger From the ideal gas law,
PV = nRTTherefore, the rate of heat transfer (Q) is:
Q = nCp(T2 – T1) … … (ii)Using the relationship
Q = pV/RT Cp (T2 – T1) … … (iii)For the first process, using
Cp = (7/2) RThus, Using
Cp = (5/2) RThus, Substituting the given values in equation (iii), we getThe rate of heat transfer (Q) removed from the nitrogen in the heat exchanger is -377.24 × 106 BTU/hr.
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What is the driving force behind evolving technology?
is the main factor that drives the evolution of technology.
Answers
Creativity and Innovation.
Communication, Innovativeness, knowledge, quality of the product, and motivation...
a An aircraft flies at Mach 2 at 51,000 feet (P. = 11.0 kPa, T = 216.7 K) propelled by a simple turbojet engine (i.e. no bypass). If the inlet is effectively isentropic find the stagnation temperature and pressure into the compressor. The engine compressor has a pressure ratio of 10 with an isentropic efficiency of 90%: find the stagnation temperature and pressure at compressor exit. (Ans: 793.3 K: 0.861 MPa) b In the combustor the velocities are low (so the stagnation and static pressures are equal) but the absolute stagnation pressure falls by 5%. At turbine entry the stagnation temperature is 1400 K and the turbine has an efficiency of 90%. Find the stagnation temperature and pressure downstream of the turbine. (Ans: 996.7 K; 0.212 MPa) c If the final propulsive nozzle is isentropic, find the velocity of the jet assuming that the expansion is to the static pressure after the nozzle, which is equal to that of the surrounding atmosphere. Calculate the gross and net thrust per unit mass flow, the propulsive efficiency and, from the temperature rise in the combustor, the overall efficiency. (Ans: V = 1069 m/s; Fa = 1069 N kg 's-'; Fn = 479 Nkg='s-1; n = 0.711; 16 = 0.464)
Answers
All answers are mentioned below.
Describe isentropic pressure?Isentropic pressure refers to the pressure that results from a thermodynamic process that occurs at constant entropy. In other words, the entropy of a system does not change during an isentropic process, and therefore the pressure changes in a specific manner based on the initial and final states of the system. Isentropic processes are typically adiabatic, meaning that no heat is added or removed from the system during the process. These processes can occur in many different forms, such as in a compressor, a nozzle, or a thermodynamic cycle. In each of these cases, the isentropic pressure change can be calculated using the first and second laws of thermodynamics, along with the specific conditions of the process.
a. The inlet to the compressor can be analyzed using the isentropic relationship between pressure and temperature. Given the ambient conditions of P = 11.0 kPa and T = 216.7 K, the stagnation pressure and temperature can be found using the equation:
P0 = P * (1 + (γ - 1) / 2 * M^2)^(γ / (γ - 1))
where γ = 1.4 is the ratio of specific heats for air.
Solving for P0, we find that the stagnation pressure is 22.0 kPa. To find the stagnation temperature, we use the equation:
T0 = T * (1 + (γ - 1) / 2 * M^2)
Solving for T0, we find that the stagnation temperature is 533.3 K.
Next, the pressure ratio of the compressor is given as 10 and the isentropic efficiency is 90%, so the actual pressure rise can be calculated as:
P2/P1 = η * P2/P1,isentropic
where η is the isentropic efficiency. Solving for P2, we find that the pressure at the exit of the compressor is 86.1 kPa.
The temperature rise in the compressor can be calculated using the equation:
T2 = T1 * (P2 / P1)^((γ - 1) / γ)
Solving for T2, we find that the temperature at the exit of the compressor is 793.3 K.
b. In the combustor, the velocities are low, so the stagnation and static pressures are equal, and the stagnation pressure falls by 5%. The fall in stagnation pressure can be expressed as:
P0,comb = P0 * (1 - ΔP / P0)
where ΔP is the fall in stagnation pressure. Solving for P0,comb, we find that the stagnation pressure in the combustor is 20.38 kPa.
Next, the stagnation temperature at turbine entry is given as 1400 K, and the turbine efficiency is 90%. The temperature at turbine exit can be found using the equation:
T3 = T2 * ηturbine
Solving for T3, we find that the temperature at turbine exit is 996.7 K.
The pressure at turbine exit can be found using the equation:
P3 = P2 * (T3 / T2)^(γ / (γ - 1))
Solving for P3, we find that the pressure at turbine exit is 0.212 MPa.
c. The velocity of the jet can be found by finding the velocity of an isentropic expansion from the stagnation conditions at the exit of the propulsive nozzle to the ambient conditions. The velocity can be found using the equation:
V = (2 * (γ / (γ - 1)) * R * T0 * (1 - (P / P0)^((γ - 1) / γ)))^0.5
where R is the specific gas constant for air. Solving for V, we find that the velocity of the jet is 1069 m/s.
The gross thrust per unit mass flow can be found using the equation:
Fa = V * (1 - (P / P0))
Solving for Fa, we find that the gross thrust per unit mass flow is 1069 N kg
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Solving for Fa, we have find that the gross thrust per unit mass flow is 1069 N·kg.
Describe isentropic pressure?Isentropic pressure refers to the pressure that results from a thermodynamic process that occurs at constant entropy. In other words, the entropy of a system does not change during an isentropic process, and therefore the pressure changes in a specific manner based on the initial and final states of the system. Isentropic processes are typically adiabatic, meaning that no heat is added or removed from the system during the process. These processes can occur in many different forms, such as in a compressor, a nozzle, or a thermodynamic cycle. In each of these cases, the isentropic pressure change can be calculated using the first and second laws of thermodynamics, along with the specific conditions of the process.
a. The inlet to the compressor can be analyzed using the isentropic relationship between pressure and temperature. Given the ambient conditions of P = 11.0 kPa and T = 216.7 K, the stagnation pressure and temperature can be found using the equation:
P0 = P * (1 + (γ - 1) / 2 * M^2)^(γ / (γ - 1))
where γ = 1.4 is the ratio of specific heats for air.
Solving for P0, we find that the stagnation pressure is 22.0 kPa. To find the stagnation temperature, we use the equation:
T0 = T * (1 + (γ - 1) / 2 * M^2)
Solving for T0, we find that the stagnation temperature is 533.3 K.
Next, the pressure ratio of the compressor is given as 10 and the isentropic efficiency is 90%, so the actual pressure rise can be calculated as:
P2/P1 = η * P2/P1,isentropic
where η is the isentropic efficiency. Solving for P2, we find that the pressure at the exit of the compressor is 86.1 kPa.
The temperature rise in the compressor can be calculated using the equation:
T2 = T1 * (P2 / P1)^((γ - 1) / γ)
Solving for T2, we find that the temperature at the exit of the compressor is 793.3 K.
b. In the combustor, the velocities are low, so the stagnation and static pressures are equal, and the stagnation pressure falls by 5%. The fall in stagnation pressure can be expressed as:
P0,comb = P0 * (1 - ΔP / P0)
where ΔP is the fall in stagnation pressure. Solving for P0,comb, we find that the stagnation pressure in the combustor is 20.38 kPa.
Next, the stagnation temperature at turbine entry is given as 1400 K, and the turbine efficiency is 90%. The temperature at turbine exit can be found using the equation:
T3 = T2 * ηturbine
Solving for T3, we find that the temperature at turbine exit is 996.7 K.
The pressure at turbine exit can be found using the equation:
P3 = P2 * (T3 / T2)^(γ / (γ - 1))
Solving for P3, we find that the pressure at turbine exit is 0.212 MPa.
c. The velocity of the jet can be found by finding the velocity of an isentropic expansion from the stagnation conditions at the exit of the propulsive nozzle to the ambient conditions. The velocity can be found using the equation:
V = (2 * (γ / (γ - 1)) * R * T0 * (1 - (P / P0)^((γ - 1) / γ)))^0.5
where R is the specific gas constant for air. Solving for V, we find that the velocity of the jet is 1069 m/s.
The gross thrust per unit mass flow can be found using the equation:
Fa = V * (1 - (P / P0))
Solving for Fa, we find that the gross thrust per unit mass flow is 1069 N kg
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what are the besl measures used for data variation or dispersion
Answers
Answer:
STANDARD DAVIATION OR SD
Explanation:
BECAUSE it is commonly in measuring of dispersion and it also the most roubst measure of variability
How many flip-flop values are complemented in an 8-bit binary ripple counter to reach the next count value after: 0110111 and 01010110?
Answers
Answer:
- Four (4) flip-flop values will complemented
- one (1) flip-flop value will complemented
Explanation:
To find how many flip flop number of bits complemented, we just need to figure out what the next count in the sequence is and find how many bits have changed.
taking a look at the a) 00110111
we need to just 1 to the value,
so
00110111 + 0000001 = 00111000
So here, only the first four bits are complemented.
Therefore Four (4) flip-flop values will complemented
Next
b) 01010110
we also add 1 to the value
01010110 + 00000001 = 01010111
only the first bit is complemented.
Therefore one (1) flip-flop value will complemented
The map of the points and polygons of a model laid out in a 2-dimensional space is:
a tile
a UV map
a bitmap
a topography
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This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answers
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
"hapter One Review Questions 1. Where did the Industrial Revolution start and why did it begin there? 2. What does "emerging" mean, emerging technologies and how are they found? 3. What makes "emerging technologies" happen and what impact will they have on Individuals, Society, and Environment?
Answers
An agrarian and handicraft economy was replaced by one that was dominated by industry and machine manufacturing during the Industrial Revolution in modern history. The world as a whole was affected by this process after it started in Britain in the 18th century.
The first three industrial revolutions were which three?These first three industrial revolutions shaped our contemporary society. The world we live in underwent a fundamental transformation with the advent of each of these three innovations: the steam engine, the age of science and mass production, and the rise of digital technology. And right now, it's taking place once more, for the fourth time.
The term is frequently used to describe emerging technologies, or those expected to become available in the next five to ten years. It is typically reserved for technologies that are having, or are anticipated to have, significant social or economic effects.
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vết nứt tế vi là gì?
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who is the strongest avenger i say hulk but who knows at this point
Answers
Answer:
or is the strongest evenger she hulk
Explanation:
?????????
Answer:
Thor!
Explanation:
In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.
which other factors do you need to consider when preparing to move gondolas?
Answers
The factors that you need to consider when preparing to move gondolas are:
Heightwidthlength color. How do you move a gondola?In choosing gondola one need to look at some factor in decisions such as height.
Know that it is good to consider the construction material and also the center wall configuration for its building also.
The factors that you need to consider when preparing to move gondolas are:
Heightwidthlength color.Learn more about gondola from
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Identify three architectural structures, natural or man made, that have withstood the test of time. describe the geometric shapes that they represent or contain.
Answers
The three architectural structures, natural or man made, that have withstood the test of time. describe the geometric shapes that they represent or contain are statues.
How are geometric shapes utilized in architecture?Architects use geometry to take a look at and divide areas in addition to draft specified construction plans. Builders and engineers depend upon geometric concepts to create systems safely. Designers practice geometry (in conjunction with color and scale) to make the aesthetically appealing areas inside. Applying geometry in the layout is unavoidable.
Man-Made systems can consist of seawalls, breakwaters, harbor walls, pontoons and piers, to say a few. These may be crafted from a whole lot of substances now no longer constrained to wood, concrete, or metal, in addition to herbal rock that has been installed vicinity as a sea defence.
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Nonrenewable resources indirectly harness the energy of the ____? PLEASE HELP ILL GIVE YOU BRAINLEIST!
A. the Sun
B. atmosphere
C. carbon atoms
D. Earth’s interior
Answers
Answer: C. carbon atoms
Explanation:
Non-renewable energy resources is a term usually used to refer to fossil fuels such as oil, natural gas and coal. These fossil fuels are so termed as they are remains of dead plant and animal matter from millions of years ago.
The main element in these fossil fuels is carbon which is the universal building block of life so will be present in the remains of previously alive matter. When non-renewable energy sources are therefore used, it is energy from carbon atoms that is being harnessed.
A. The Sun
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The drag on a 2 m diameter satellite dish due to an 80 km/hr wind is to
be determined through a wind tunnel test using a geometrically similar 0.4 m
diameter model dish. Assume standard air for both model and prototype. (a) At what
air speed should the mode test be run? (b)With all similarity conditions satisfied, the
measured drag on the model was determined to be 170 N. What is the predicted drag
on the prototype dish?
Answers
A) The air speed at which the mode test should be run is; 400 km/hr
B) The predicted drag on the prototype dish is; 170 N
What is the drag force on the model?
We are given;
diameter of satellite dish = 2m
Wind speed; Y = 80 km/hr
Diameter of model dish = 0.4 m
Reynolds number is essential for this, thus, the formula is;
Vm * Dm/vm = VD/v
where;
D is the diameter of the dish
Vm = (vm/v) (D/Dm) Y
If vm/v = 1, then
Vm = (2/0.4) * 80
Vm = 400 km/hr
B) The formula to find the drag on the prototype dish with all similarity conditions satisfied is;
F_p = (Fm/Vm² * Dm²) * Vp² * Dp²
Thus, plugging in the relevant values gives;
F_p = (170/(400² * 0.4²)) * 2² * 80²
F_p = 170 N
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Write a statement that assignsall elements in the arrayatomicWeights the value 1.003,independent of the size of thearray.atomicWeights(:) = 1.0032
Answers
A statement that assigns all elements in the array atomic Weights the value 1.003,independent of the size of the array is atomicWeights(:) = 1.0032.
An array is a grouping of identically typed components that are stored in adjacent memory locations and can each be individually referred to using an index to a special identifier. There is no need to declare five distinct variables when declaring an array of five int values (each with its own identifier). are by default not set. This indicates that none of the components in the array have any specific values assigned to them; rather, their contents are unknown at the time the array is declared.
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noooo plssschvwekjshdjkshdjkshdjksahdk
Answers
Answer:
chehdhfhfhd
Explanation:
fjrjshrhdhr
A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of 350 MPa. Using the distortion-energy and maximum-shear-stress theories, determine the factors of safety for the following plane stress states.
a. σx = 94 MPa, and τxy = -75 MPa
b. σx = 110 MPa, σy = 100 MPa
c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa
Answers
Answer:
Explanation:
From the given question:
Using the distortion energy theory to determine the factors of safety FOS can be expressed by the relation:
\(\dfrac{Syt}{FOS}= \sqrt{ \sigma x^2+\sigma y^2-\sigma x \sigma y+3 \tau_{xy^2}}\)
where; syt = strength in tension and compression = 350 MPa
The maximum shear stress theory can be expressed as:
\(\tau_{max} = \dfrac{Syt}{2FOS}\)
where;
\(\tau_{max} =\sqrt{ (\dfrac{\sigma x-\sigma y}{2})^2+ \tau _{xy^2\)
a. Using distortion - energy theory formula:
\(\dfrac{350}{FOS}= \sqrt{94^2+0^2-94*0+3 (-75)^2}}\)
\(\dfrac{350}{FOS}=160.35\)
\({FOS}=\dfrac{350}{160.35}\)
FOS = 2.183
USing the maximum-shear stress theory;
\(\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{94-0}{2})^2+ (-75)^2\)
\(\dfrac{350}{2 FOS} =88.51\)
\(\dfrac{350}{ FOS} =2 \times 88.51\)
\({ FOS} =\dfrac{350}{2 \times 88.51}\)
FOS = 1.977
b. σx = 110 MPa, σy = 100 MPa
Using distortion - energy theory formula:
\(\dfrac{350}{FOS}= \sqrt{ 110^2+100^2-110*100+3(0)^2}\)
\(\dfrac{350}{FOS}= \sqrt{ 12100+10000-11000\)
\(\dfrac{350}{FOS}=105.3565\)
\(FOS=\dfrac{350}{105.3565}\)
FOS =3.322
USing the maximum-shear stress theory;
\(\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{110-100}{2})^2+ (0)^2\)
\(\dfrac{350}{2 FOS} ={ (\dfrac{110-100}{2})^2\)
\(\dfrac{350}{2 FOS} =25\)
FOS = 350/2×25
FOS = 350/50
FOS = 70
c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa
Using distortion- energy theory formula:
\(\dfrac{350}{FOS}= \sqrt{ 90^2+20^2-90*20+3(-20)^2}\)
\(\dfrac{350}{FOS}= \sqrt{ 8100+400-1800+1200}\)
\(\dfrac{350}{FOS}= 88.88\)
FOS = 350/88.88
FOS = 3.939
USing the maximum-shear stress theory;
\(\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{90-20}{2})^2+ (-20)^2\)
\(\dfrac{350}{2 FOS} =\sqrt{ (35)^2+ (-20)^2\)
\(\dfrac{350}{2 FOS} =\sqrt{ 1225+ 400\)
\(\dfrac{350}{2 FOS} =40.31\)
\(FOS} =\dfrac{350}{2*40.31}\)
FOS = 4.341
Which of the following would be useful to the building of a skyscraper? (Select all that apply.)
steep grading
deep foundation
wide footing
large footprint
Answers
Answer:
steep grading
Explanation:
the farthest
Explain packaging films and how gums are used in packaging films
Answers
packaging films can be measured in several ways.Many devices for measuring film permeability to oxygen are on the market
A wastewater treatment plant discharges 2.0 m^3/s of effluent having an ultimate BOD of 40.0 mg/L into a stream flowing at 15.0 m^3/s. Just upstream from the discharge point, the stream has an ultimate BOD of 3.5 mg/L. The deoxygenation constant kd is estimated at 0.22/day.
a. Assuming complete and instantaneous mixing, find the ultimate BOD of the mixture of wastewater and river just downstream from the outfall.
b. Assuming a constant cross sectional area for the stream equal to 55 m^2 , what ultimate BOD would you expect to find at a point 10,000 m downstream?
Answers
Answer:
What grade is this is for??
If the water surface elevation in reservoir B is 110 m, what must be the water surface elevation in reservoir A if a flow of 0.03 m3 /s is to occur in the cast iron pipe
Answers
The water surface elevation must be 110.2631 meters for a flow of 0.03m³ to occur in the cast pipe
For cast iron the chart has 0.0012 from Moody's chart
0.016 for cast iron
\(hf = \frac{flQ^{2}}{12.1d5}\)
\(h1 = h2+\frac{Q^{2} }{12.1} [\frac{0.0012*100}{(12/1000)^5} +\frac{0.0016*150}{(15/100)^5} ]\)
\(h1 = 110m+\frac{0.03^2}{12.1} [\f\frac{0.12}{0.00032} +\frac{0.24}{0.000759} ]\\\\h1 = 110+0.0000744[375+3162.06]\\\\= 110 + 0.2631m\\\\= 110.2631m\)
Therefore the water surface elevation must be 110.2631 meters for a flow of 0.03m³ to occur in the cast pipe
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Can I have free money? I want to get a new pc
Answers
Answer:
NO!
Explanation:
A cylindrical work part has a diameter and a height of both as 6cm. The coefficient of friction at the die work interface is 0.10. The work metal has a strength coefficient of 270MPa, yield strength of 110MPa, and a strain hardening exponent of 0.15. Determine the instantaneous force in N at a height of 4cm
Answers
Consider a condenser in which steam at a specified temperature is condensed by rejecting heat to the cooling water. If the heat transfer rate in the condenser and the temperature rise of the cooling water is known, explain how the rate of condensation of the steam and the mass flow rate of the cooling water can be determined. Also, explain how the total thermal resistance R of this condenser can be evaluated in this case.
Answers
Answer:
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Explanation:
How will the rate of condensation of the steam and the mass flow rate of the cooling water can be determined
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Consider the following expression BNF:
::= + | - |
::= * | / |
::= | ( )
::= 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
Using recursive descent, and only recursive descent, scan expressions that adhere to this BNF
to build their expression tree; write an integer valued function that scans the tree to
evaluate the expression represented by the tree.
There are plenty of clever programs online that you can download to evaluate arithmetic
expression tree; if you want zero in this assignment, download one and submit it as
programming assignment #2; if you want a grade greater than zero, please follow our
instructions. Thanks.
Input:
• A numeric expression adhering to this BNF.
Output:
• Some representation of the expression tree.
• The result of evaluating the expression.
Answers
The program will be:
import java.io.IOException;
import java.util.Scanner;
/* This class represents a Node in Expression Tree that will contain a digit(symbol) and will have links to its
* left and right childs, which would be recursively having its own left and right sub childs accordingly
*/
class Node {
public char data; // Store Node Data
public Node leftChild; // pointer to left sub tree
public Node rightChild;// pointer to right sub tree
// Constructor to initialize Node with data
public Node(char x) {
data = x;
}
// display the Node's data stored
public void displayNode() {
System.out.print(data);
}
}
/* This is Stack class (Stack1) which performs push(), pop(), isEmpty() operation on Node's data */
class Stack1 {
private Node[] a; // Stack of type Node
private int top, m; // top = top of stack variable, m = Maximum Size of the Stack
public Stack1(int max) {
m = max;
a = new Node[m];
top = -1;
}
What is a have program?Java is a popular object-oriented programming language and software platform that powers billions of devices such as notebook computers, mobile devices, gaming consoles, medical devices, and many more.
Java's rules and syntax are based on the C and C++ programming languages. The program is illustrated based on the information.
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What is the difference between Architecture drawing and engineering drawing?
Answers
Drawing, in other words, aid you in defining your new area and selecting you scrap metal and finish. When changing structural components as a result of building, like moving a bearing wall, drawings are needed.
Is working in architecture difficult?Architecture is a difficult profession that requires a lot of labor. All successful architects have put in tremendous effort and sacrifice to reach where they are.
For architecture, what grades are required?Entry criteria range at Cca to Extracts, with BBB being the most often requested grade by universities and institutions. Moreover, you typically need five GCSEs with a grade of C or over, encompassing English and arithmetic. Degrees in design and landscaping architecture often don't call for any particular A level topics.
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In the figure below, block A weighs 20 lb , while block B weighs 10 lb . Friction between the surfaces of the two blocks may be assumed negligible, but there is friction between block A and its underlying surface, and between block B and its adjacent confining surface, both with a kinetic friction coefficient of 0.25. The angle that the inclined face of block A makes with the horizontal is θ= 75 ∘ . A vertical downward force, P= 8 lb is applied to block B .
What is the acceleration of block B?
What is the acceleration of block A?
Answers
Answer:
As P is continually increased, the block will now slip, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, with f remaining constant thereafter as P is increased.