The weight of a box is having a mass of 100 kg is ___n

Answer:

The frequency heard is 576.78 Hz

Explanation:

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

This is what happens in the first part of this problem, where the sender is train A and the receiver is train B. They are both moving in opposite directions. In this case, where both are in motion, the frequency perceived by the receiver will increase when receiver and transmitter increase their separation distance and will decrease whenever the separation distance between them is reduced. The following expression is considered the general case of the Doppler effect:

\(f'=f*\frac{v+-vR}{v+-vE}\)

Where:

f ', f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s-1)

v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 343 m / s

vR, vE: Speed ​​of the receiver and the emitter respectively. Its unit of measure in the S.I. is the m / s

±, ∓:

We will use the + sign:

We will use the sign -:

In this case you are in a car traveling at 20 m/s and an ambulance is behind you traveling 35 m/s in the same direction.

In this case the receiver, you in the car, moves away from the emitter, while the emitter, the ambulance, approaches the receiver behind you in the same direction. So the frequency is calculated by the expression:

\(f'=f*\frac{v-vR}{v-vE}\)

Being:

and replacing:

\(f'=550 Hz*\frac{343 m/s-20 m/s}{343 m/s-35 m/s}\)

you get:

f'= 576.78 Hz

The frequency heard is 576.78 Hz

A product concept is a detailed version of a new product idea stated in a way that consumers find meaningful; a is the way consumers perceive the actual or potential product.

A product may be described as- “an amazing, idea, approach, records, item, or carrier this is the quit end result of a procedure and serves as a want or want satisfier. it also includes a package deal of tangible and intangible attributes (benefits, functions, functions, makes use of) that a vendor offers to a consumer for buy.”

A purchaser is a person or a set who intends to reserve, or uses purchased goods, merchandise, or offerings normally for private, social, own family, family and comparable wishes, who isn't always without delay related to entrepreneurial or business sports. The time period maximum generally refers to someone who purchases items and offerings for non-public use.

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The maximum power that could be produced by the steam engine is approximately 88.2 kW. The maximum power that could be produced by the steam engine can be calculated using the thermodynamic equation for the efficiency of a Carnot cycle, which is given by:

η = (T₁ - T₂) / T₁

where η is the efficiency, T₁ is the temperature of the heat source, and T₂ is the temperature of the heat sink. In this case, the heat source temperature is unknown, but we can find it using the saturation temperature at the pressure of 6.8 MPa, which is approximately 364°C. Similarly, the temperature at the heat sink pressure of 1.21 MPa is approximately 191°C.

Using the efficiency equation and the given heat input rate of 250 kW, we can calculate the maximum power output of the steam engine as:

P max = η * Qin

where P max is the maximum power output and Qin is the heat input rate. Plugging in the values, we get:

P max = η * 250 kW = (364 - 191) / 364 * 250 kW ≈ 88.2 kW

Therefore, the maximum power that could be produced by the steam engine is approximately 88.2 kW.

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1) Note that the Roof is dark colored. Given the laws of physics, it will absorb all light.

2) the window is transparent, hence, it will transmit ALL light.

3) the door is dark-colored but has some glass on it. Thus, it will absorb MOST but not all light.

4) the side of the building which is painted white will reflect all light.

Note that dark surfaces absorb light because they are able to absorb photons, or particles of light, and convert them into other forms of energy.

This is because the atoms and molecules in dark surfaces have a large number of unpaired electrons that are able to absorb the energy of photons and transition to a higher energy state.

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Answer:

D H2 + O2 ---> H2O

Explanation:

Answer:

I am not sure what the answer is but keep reading.

Explanation:

The answer is not D or A for sure

In a deep vacuum, the pressure exerted by the atmosphere on a gauge line is negligible or close to zero. A vacuum is defined as a region with a low gas pressure, typically much lower than atmospheric pressure.

In a deep vacuum, the pressure is significantly lower compared to atmospheric pressure. The atmosphere exerts pressure on objects due to the weight of the air above them. However, in a deep vacuum where air or any other gas is absent, there is no medium to exert pressure on the gauge line.

A vacuum is defined as a region with a low gas pressure, typically much lower than atmospheric pressure. In a deep vacuum, the pressure is close to zero or negligible. This means that the atmosphere does not exert any significant pressure on a gauge line placed in a deep vacuum.

It is important to note that the absence of pressure in a deep vacuum does not mean the absence of other effects, such as radiation pressure or gravitational forces, which may still be present depending on the specific conditions. However, in terms of atmospheric pressure, it is essentially nonexistent in a deep vacuum.

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An object's mass, rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force due to an existing field (In most cases, gravitational field) that is experienced by the body. The weight of the same body can be different in different environments it's observed.

However, the mass of the body is the exact measure of the amount of matter contained in a body. Which is constant, regardless of the environment, or conditions the body is observed.

Hence, for real-world calculations and experimentation, the mass of the body is considered to represent the amount of matter it contains rather than its weight.

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Answer:

A reference frame is that frame to which the qualities of an object are related:

For instance - an object may described by - mass, speed, acceleration, size,  etc,

It is important to remember that Newton's Laws of motion do not hold in accelerated reference frames -

Einstein's laws of special relativity are only true in frames that move with contant speed to one another

There is a gravitational force between the Moon and the Earth, that tries to pull the Moon toward the latter. This constant tug on the Moon as it moves around the Earth is called a "centripetal" force.

gravitational force:

This force is balanced by the "centrifugal" force, that pulls on the Earth and keeps the moon in motion. The Moon orbits Earth, and it travels in a circle around it. There is a force between Earth and the Moon called gravity. Gravity causes larger objects to pull smaller ones towards them. Earth is larger than the Moon, which is why it pulls on the Moon. At the same time, the Sun is pulling on Earth. The Sun is larger than Earth. The balance between these two pulls is what keeps the Moon in orbit around Earth. As the Moon orbits the Earth, it experiences a gravitational force. This force acts as a centripetal force, keeping the Moon in its circular path. If this force were to disappear, the Moon would travel in a straight line, moving away from Earth. At the same time, Earth is being pulled by the Sun, which is why it experiences a centrifugal force. The balance between these two forces keeps the Moon in orbit around Earth.

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Answer:

B. radio waves

Explanation:

Trust me It's correct

According to the data given in the question the net force on the box is of 5 N.

All of the forces that are applied to an object are added up to form the net force. As a consequence of the fact that it (force) is a vector and therefore that two forces with identical magnitudes and opposing directions cancel each other out, the resultant force is the total of the forces, or put another way, the net force is just the total of all the forces.

Given data :

Force on box to the left side (F1) = 15 N

Force on box to the right side (F2) = 20 N

Because both forces are in opposite direction

Hence,

Net force = F2 - F1

Net force = 20 - 15

Net force = 5 N.

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Answer:

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt. Speed (or rate, r) is a scalar quantity that measures the distance traveled (d) over the change in time (Δt), represented by the equation r = d/Δt.

Explanation:

hope this helps a little bit sorry if i got it wrong

Answer:

a = 0.3 m/s²

Explanation:

Given: 45 N, 150 kg

To find: a

Formula: \(a = \frac{F}{m}\)

Solution: To find a, divide the force by the weight  

A = F ÷ m

=  45 ÷  150

= 0.3 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

Explanation:

I am going to sign off....here is a possible scenario:

    Current thru 3 ohm = 1.05 Amp V3 = 3.15 V   Current through 4 ohm  = .58 A      through 5 ohm = .464 A    (voltage across these two resistors is 2.32 v )

As the force exerted by the mass in the both cases was same on the both sides so that the object was said to be in the rest condition so they are said to be same in both conditions.

define pulleys ?

A wheel on an axle or shaft known as a pulley is used to transfer power from the shaft to the cable or belt or to sustain movement and direction change of a taut cable or belt. When a pulley is supported by a frame or shell and is used to guide a cable or apply force rather than transmit power to a shaft, the supporting shell is referred to as a block and the pulley may be referred to as a sheave.

For the purpose of locating the cable or belt, a pulley may include a groove or grooves between flanges around its circle. A rope, cable, belt, or chain may serve as the driving component of a pulley system.

As the force exerted by the mass in the both cases was same on the both sides so that the object was said to be in the rest condition so they are said to be same in both conditions.

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Answer:

load (l)=400N

Effort(E)=50N

mechanical advantage (MA)= load ÷Effort

(ma)=400÷50

(ma)=8

Explanation:

I copy pasted from the answer from the same question. Remember to first check if ur question is there

Answer:

0.3 seconds approximately

Explanation:

Given that the height of the building is 55.9 m and cement block accidentally falls from rest from the edge of a 55.9-m-high building. The initial velocity of the block will be equal to zero. The final velocity will be achieved by using the formula:

V^2 = U^2 + 2gH

Where g = 9.8 m/s^2

H = 55.9m

V^2 = 0 + 2 × 9.8 × 55.9

V^2 = 1095.64

V = sqrt(1095.64)

V = 33.1 m/s

The velocity When the block is 11.2 m above the ground will be 33.1 m/s and the height h = 11.2 - 1.7 = 9.5 m

The time of escape can be calculated by using the formula;

h = Ut + 1/2gt^2

9.5 = 33.1t + 1/2 × 9.8 × t^2

9.5 = 33.1t + 4.9t^2

4.9t^2 + 33.1t - 9.5

By using quadratic formula to calculate the time, the negative value is ignored and the positive values will be the time the man has to get out of the way.

Please find the attached file for the remaining solution.

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 250 g

volume = 100 cm³

So we have

\(density = \frac{250}{100} = \frac{5}{2} \\ \)

We have the final answer as

Hope this helps you

The number of Calories of net work required for the cheetah to reach its top speed is 85.6 Cal.

W = Fd

Where W is the work done,

F is the force applied, and d is the displacement.

The force F applied is the net force acting on the cheetah, which is the difference between the force of friction and the force of the cheetah's muscles.

Therefore,F = maWhere m is the mass of the cheetah and a is its acceleration.

The displacement d can be calculated using the formula;

d = v²/2aWhere v is the final velocity and a is the acceleration.

Substituting the given values in the above equations,

F = ma

F = 59.0 kg × (31.1 m/s) / 2.50 sF = 731.32 NN = Fnet

work = Fdnet

work = 731.32 N × 490.01 mdnet work = 358,608.13 J

Therefore, the net work required for the cheetah to reach its top speed is 358,608.13 J.(

b) One food Calorie equals 4186 J.

Therefore, to find the number of Calories of net work required for the cheetah to reach its top speed, we can divide the net work by the energy equivalent of one food Calorie.

Thus,net work in Calories = net work in joules / 4186net work in Calories = 358,608.13 J / 4186

net work in Calories = 85.6 Cal

Therefore, the number of Calories of net work required for the cheetah to reach its top speed is 85.6 Cal.

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Answer: wavelength

Explanation:

The kinematic relations allow finding the results for the different questions are:

     1.  The acceleraations is a = 375 m/s²

     2. The time is t = 62.5 s

     3. The velocity at the ground is  v = -14.7 m / s

     4.  The time to the bottoncliff is    1.7 s

     5.  The height isy₀ = 122.5 m

     6.

         A) The velocity is v = 25.2 m / s

         B)  The height  for t=1 s is  y = 18.1 m

     7.

         A)  Time in the air is t = 2 s

         B)  The final veloicty is   v = - 19.6 m / s

Kinematics analyzes the movement of bodies, finding relationships between the position, velocity and acceleration of bodies.

Let's look for the answers to a series of questions:

1. They indicate the initial and final velocities of the body and the time to reach it is 20 s, ask how much the acceleration is worth

Let's use the relationship

             v = v₀ + a t

             a = \(\frac{v-v_o}{t}\)

             a = \(\frac{17500-10000}{20}\)

             a = 375 m/s²

2. What is the time it takes to travel a distance of 125 m with an acceleration of 4 m / s²

             x = v₀ t + ½ a t²

As it leaves the direction its initial velocity is zero

             x = ½ to t²

             t = \(\sqrt{\frac{2x}{a} }\)

             t = \(\sqrt{\frac{2 \ 125}{4} }\)

             t = 62.5 s

3. A pencil falls from a height and reaches the floor in a time of 1.5 s what is the speed when reaching the floor

            v = v₀ - g t

As it is released its initial velocity is zero

            v = -g t

            v = - 9.8 1.5

            v = -14.7 m / s

The negative sign indicates that the velocity is directed downwards.

4. From the edge of a cliff 40 m high, an apple is thrown downward with an initial velocity of 15 m / s. How long does it take to get to the bottom?

             y = y₀ + v₀ t - ½ g t²

In this case the initial velocity is negative because it is directed downwards and when it reaches the floor its height is zero, let us substitute

Suppose the acceleration is g = 10 m / s²

             0 = 40 - 15 t - ½ 10 t²

             0 = 40 - 15 t - 5 t²

let's solve the quadratic equation

             t² + 3 t - 8 = 0

             t = -3 + Ts 9 + 4 8/2

            t = -3 + 6. 4/2

             t₁ = - 4.9 s

            t₂ = 1.7 s

The time must be a positive quantity, so the correct answer is 1.7 s

5. A stone is dropped from the ceiling and it takes a time 5 s to reach the floor, which is the height of the ceiling

           y = y₀ +v₀ t - ½ g t²

as it is released from the ceiling its initial velocity is zero and the height upon reaching the floor is zero

          0 = y₀ + 0 - ½ g t²

          y₀ = ½ g t²

          y₀ = ½ 9.8 5²

          y₀ = 122.5 m

6. A man at a height of 30 m throws a ball downward at 7 m / s

    A) The speed when reaching the ground

    B) The height of the ball when a time of 1 s has fallen.

  A) Let's use the kinematics relation

              v² = v₀² - 2 g (y -y₀)

              v = 7² - 2 9.8 (0 -30)

              v = 25.2 m / s

 B)   y = y₀ + v₀ t - ½ g t²

        y = 30  7 1 - ½ 9.8 1²

        y = 18.1 m

7.  A watermelon is dropped from rest from the top of a 20m cliff.  

 A) time in the air

 B) ground speed

  A) Let's use the relation

       y = y₀ + v₀ t - ½ g t²

It is released its initial velocity is zero and when it reaches the ground its height is zero (y = 0)

       0 = y₀ + 0 - ½ g t²

       t = \(\sqrt{\frac{2y_o}{g} }\)

       t = \(\sqrt{\frac{2 \ 20}{9.8} }\)

       t = 2 s

B) the speed when reaching the ground

       v = v₀ - g t

       v = 0 - 9.8 2

       v = - 19.6 m / s

The negative sign indicates that the speed is down

In conclusion using the kinematic relations we can find the results for the different questions are:

   1.  The acceleraations is a = 375 m/s²

   2. The time is t = 62.5 s

   3. The velocity at the ground is  v = -14.7 m / s

   4.  The time to the bottoncliff is    1.7 s

   5.  The height isy₀ = 122.5 m

   6.

      A) The velocity is v = 25.2 m / s

      B)  The height  for t=1 s is  y = 18.1 m

  7)

      A)  Time in the air is t = 2 s

      B)  Te final veloicty is   v = - 19.6 m / s

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Diagram A shows two laser beams, one blue and one red, that are incident on a mirrored surface. Diagram B shows two laser beams, one blue and one red, that are incident on a transparent block of glass then The blue and red laser beams reflect at the same angle, and they refract at different angles.

A laser emits a very focused beam of light that can be used in a variety of equipment and technologies. Light Amplification by Stimulated Emission of Radiation is what the letters in the term laser stand for. The word "laser" is an acronym for "Light Amplification by Stimulated Emission of Radiation." In a laser beam, the light waves are "coherent," which means they are all traveling at the same speed and wavelength. To do this, excited electrons are passed through an optical "gain medium," which could be a solid substance like glass or a gas.

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The impulse that Earth exerts on a 210 g apple that is falling from a tree during the first 0.50 seconds can be calculated using the formula for impulse.

Impulse is defined as the change in momentum of an object, and is given by the equation:

J = Δp

where,

J is the impulse.

Δp is the change in momentum.

To calculate the impulse that Earth exerts on the apple, we need to know the initial momentum and the final momentum of the apple during the first 0.50 seconds.

Since the apple is falling freely, its initial momentum is zero (because it is at rest), and its final momentum can be calculated using the formula:

p = mv

where,

p is the momentum.

m is the mass.

v is the velocity.

Since the apple is falling freely, we can use the equation for free fall to find the velocity:

v = gt

where g is the acceleration due to gravity, and t is the time.

At the end of 0.50 seconds, the velocity of the apple can be calculated as: v = gt = (9.8 m/s²)(0.50 s) = 4.9 m/s.

Therefore, the final momentum of the apple can be calculated as:

p = mv = (0.210 kg)(4.9 m/s) = 1.029 kg m/s.

The change in momentum (Δp) during the first 0.50 seconds is simply the final momentum, since the initial momentum is zero.

Therefore, the impulse that Earth exerts on the apple during the first 0.50 seconds is given by:J = Δp = 1.029 kg m/s

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Given:

Diameter, D = 10.0 m

Distance, x = 7.38 x 10¹⁰ m

Wavelength, λ = 633 nm

Let's find how far apart the closest objects it could possibly resolve.

First, apply the formula for the angle for angle separation (limit of resolution):

Thus, we have:

Now, to find the distance of the closest objects, we have:

Thus, we have:

Therefore, the distance of the closest objects is 5699.28 meters.

• ANSWER:

5699.28 m

The electric flux through the top face of the cube, with a point charge q at the center of the cube, can be calculated using symmetry.

When a point charge q is located at one of the corners of the cube, we can use symmetry to determine the electric flux through one of the three faces not touching the charge. By imagining surrounding the charge with seven additional cubes, each cube will contribute to the electric flux through the face.

Since each cube has six faces, there will be a total of 6 * 8 = 48 faces. However, not all of these faces will give a non-zero, equivalent electric flux. Only the faces that are perpendicular to the electric field lines will contribute to the flux.

Since the electric field lines will pass through the center of each cube face, there will be a total of 6 non-zero, equivalent electric fluxes through the faces of the eight cubes surrounding the charge.

(a) In the case where a point charge q is located at the center of the cube, the electric field lines will be radially symmetric, pointing outward in all directions. Due to the symmetry of the cube, the electric field lines passing through the top face of the cube will be parallel to that face.

Since the electric flux is defined as the dot product of the electric field and the surface area vector, and the angle between them is 0 degrees, the dot product becomes zero, resulting in zero electric flux through the top face.

(b) When the point charge q is located at one of the corners of the cube, we can imagine surrounding the charge with seven additional cubes. This forms a larger cube with the charge at one of its corners. Each cube contributes to the electric flux through its faces. Since each cube has six faces, there will be a total of 6 * 8 = 48 faces in the configuration of the eight cubes.

However, not all of these faces will contribute to a non-zero, equivalent electric flux. Only the faces that are perpendicular to the electric field lines will have a non-zero flux. Considering the symmetry of the arrangement, the electric field lines will pass through the center of each cube face, making them perpendicular to the faces. Thus, there will be six non-zero, equivalent electric fluxes through the faces of the eight cubes surrounding the charge.

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The speed of the motorcycle is  9.02777m/s in 7.2 sec.

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

v(0) = 5.8

s(0)=0

s(7.2) = 65

s(t) =at^2/2 + v(0)t

s(7.2) = a(7.2)^2 + 5.8(7.2) = 65

a = (65-41.76)/51.84

a= 23.24/51.84 = about 0.4483 m/s²

v(t) = s'(t) = at +v(0) = at +5.8

v(7.2) = 0.4483(7.2) + 5.8

= 9.02777

velocity in 7.2 seconds is about 9.03 meters per second

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A. The speed of the waves will remain unchanged if the mass is tripled without stretching the wire.

B. The speed of the waves will be halved if the wire is replaced with an identical one, except twice as long. This is because the waves will have to travel twice the distance in the same amount of time.

C. The speed of the waves will remain unchanged if the wire is replaced with one of the same lengths, but two times as heavy.

D. The speed of the waves will be halved if the wire is stretched to thrice its original length. This is because the waves will have to travel thrice the distance in the same amount of time.

E. The speed of the waves will be halved if the mass is increased by a factor of 18.0 and the wire is stretched to double its original length. This is because the waves will have to travel twice the distance in the same amount of time. The speed of the waves will thus be V/2.

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For a pipe 60.0 cm long, open at both ends: Fₐₒᵥ₁ = 282.8 Hz, Fₐₒᵥ₂ = 848.4 Hz, Fₐₒᵥ₃ = 1414 Hz. For a pipe closed at one end: Fᶜₗₒ₁ = 94.3 Hz, Fᶜₗₒ₂ = 282.8 Hz, Fᶜₗₒ₃ = 471.4 Hz.

Fundamental frequency and the frequency of the first three overtones of a pipe 60.0 cm long, open at both ends:

Fₐₒᵥ₁, Fₐₒᵥ₂, Fₐₒᵥ₃ = 282.8 Hz, 848.4 Hz, 1414 Hz

Fundamental frequency and the frequency of the first three overtones of a pipe 60.0 cm long, closed at one end:

Fᶜₗₒ₁, Fᶜₗₒ₂, Fᶜₗₒ₃ = 94.3 Hz, 282.8 Hz, 471.4 Hz

Number of the highest harmonic that may be heard by a person who can hear frequencies from 20.0 Hz to 2.00x10⁴ Hz in a pipe open at both ends:

n = 99

Number of the highest harmonic that may be heard by a person who can hear frequencies from 20.0 Hz to 2.00x10⁴ Hz in a pipe closed at one end:

n = 198

For a pipe open at both ends, the fundamental frequency (Fₐₒᵥ₁) can be calculated using the formula Fₐₒᵥ₁ = v / 2L, where v is the speed of sound and L is the length of the pipe. In this case, the length of the pipe is 60.0 cm (or 0.60 m).

Using the known speed of sound (approximately 343 m/s), we can substitute these values into the formula to find Fₐₒᵥ₁ = 343 / (2 * 0.60) = 282.8 Hz.

The frequencies of the first three overtones can be calculated by multiplying the fundamental frequency by the harmonic number (1, 2, 3). Therefore, Fₐₒᵥ₂ = 2 * Fₐₒᵥ₁ = 2 * 282.8 Hz = 565.6 Hz, and Fₐₒᵥ₃ = 3 * Fₐₒᵥ₁ = 3 * 282.8 Hz = 848.4 Hz.

For a pipe closed at one end, the fundamental frequency (Fᶜₗₒ₁) can be calculated using the formula Fᶜₗₒ₁ = v / 4L, where v is the speed of sound and L is the length of the pipe. Substituting the values, we find Fᶜₗₒ₁ = 343 / (4 * 0.60) = 94.3 Hz.

The frequencies of the first three overtones for a closed pipe can be calculated using the formula Fᶜₗₒₙ = (2n - 1) * Fᶜₗₒ₁, where n is the harmonic number. Thus, Fᶜₗₒ₂ = (2 * 2 - 1) * Fᶜₗₒ₁ = 3 * 94.3 Hz = 282.8 Hz, and Fᶜₗₒ₃ = (2 * 3 - 1) * Fᶜₗₒ₁ = 5 * 94.3 Hz = 471.4 Hz.

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Answer:

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Explanation:

The x - component of the initial velocity is given as:

Ux = Vi cos theta

Ux = 100cos 60

Ux = 50m/s