the variable resistor r in the circuit of fig. 11.50 is adjusted until it absorbs the maximum average power. find r and the maximum average power absorbed.

Answer:

Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.

Explanation:

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

hope this helps...

K.E=1/2mv^2

     =1/2x1x10^2

     =50

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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Answer:

greater than.

Explanation:

Answer:

3.75 m/s

Explanation:

55/4.3 = 48/x

12.8 = 48/x

x = 48 : 12.8

x = 3.75 m/s

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CARRY ON LEARNING

CAN YOU BRAINLEST ME PLEASE

The work done by the gaseous system if the volume is increased to 0.12 cubic meters is given as 21,600 joules

To find the work done by the gas, we can use the formula:

W = PΔV

where W is the work done, P is the pressure of the gas, and ΔV is the change in volume.

At the initial state, the pressure is P = 2.7 × 10^5 Pa and the volume is V1 = 0.04 m^3. At the final state, the volume is V2 = 0.12 m^3.

The change in volume is ΔV = V2 - V1 = 0.12 m^3 - 0.04 m^3 = 0.08 m^3.

Substituting these values into the formula, we get:

W = PΔV = (2.7 × 10^5 Pa) × (0.08 m^3) = 21,600 J

Therefore, the work done by the gaseous system is 21,600 joules (J).

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Answer:

4.6x10^4 joules

Explanation:

The vector values are '21 kilometers north'   and '1 cm in the positive c-direction'.

Given:

The following values:

To find:

The vector values from the given values.

Solution:

The vector quantities are those quantities with magnitude and direction.

Scalar quantities are those quantities with only magnitude and no direction.

The vector values are '21 kilometers north'   and '1 cm in the positive c-direction'.

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Answer:

mass and distance

Explanation:

mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

Explanation:

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The principle of lateral continuity works, because they are continuous. Rocks that are alike but were separated by an erosional feature, can be originally continuous.

Answer:

10m

Explanation:

assuming the ball was at 0 m/s before, after 5 seconds the ball would be traveling at 10m

The velocity of Bob at 11 seconds is 4.27 m/s.

The velocity of Bob at 11 seconds is calculated by applying average velocity formula as shown below.

v = ( total displacement ) / ( total time )

v = ( X₃ + X₁₁ ) / ( 3 + 11 )

where;

4 = ( 9 + 11u ) / ( 14 )

where;

The velocity of Bob at 11 seconds is calculated as;

4 = ( 9 + 11u ) / 14

9 + 11u = 56

11u = 56 - 9

11u = 47

u = 47 / 11

u = 4.27 m/s

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Because one mole of H X 2 is typically lighter than N e, it stands to reason that it would have a higher entropy than N e. Ne, on the other hand, is thought to have a higher entropy due to its lower molar mass.

A chemical equation can be examined for changes in physical states and the number of moles of product and reactant particles to predict relative changes in entropy using the same factors on a macroscopic level.

The species with the greater molar mass between two monoatomic ones will have a greater standard entropy. The more mobile of two allotropic forms of an element will have a higher standard entropy value. The entropies of these substances are not zero, despite the fact that their conventional internal energies and enthalpies would be. The "energies of formation" of elements in their normal states are typically set to zero because there is no absolute scale of energy.

Entropy, on the other hand, gauges the distribution of energy among the numerous quantum states that can accept it; they exist even in pure substances.

Evidently, entropies often rise with molecule weight. This is, of course, a direct reflection of the fact that translational quantum states are more densely packed in heavier molecules, making them more occupiable, for the noble gases.

The additional impacts of rotational quantum levels are visible in the entropies of the diatomic and polyatomic molecules.

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Answer:

1. a vector field is an assignment of a vector to each point in a subset of space.

2. The direct answer is that it happens through Newton’s second law. If an object is in a potential field that is different at different points in space, then the object will experience a force in the direction in which the potential energy decreases. Newton’s second law says that a force causes a change in motion, which changes the kinetic energy.

3. According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.

4. Ions are charged atoms that form when an atom donates or accepts one or more negatively charged electrons. Cations (ions with a positive charge) are attracted to anions (ions with a negative charge). This attraction is called an ionic bond.

5. Magnetic Field

Hope it Helps!!!!

ANSWER

0s to 3s

EXPLANATION

To find the time interval where the object was traveling more quickly, we have to find the velocity of the object during each interval.

From a position-time graph, we can obtain the velocity of the object from the slope of the graph in each interval. To find those slopes, we just have to divide the vertical difference by the time interval.

The interval from 0s to 3s:

The interval from 3s to 5s and the interval from 7s to 8s have a horizontal line, so the slope is zero and therefore the velocity is zero - meaning that the object was not moving during these periods.

The interval from 5s to 7s,

And the interval from 8s to 12s,

Two of these three velocities are negative. Negative velocity indicates that the object is moving backward.

From these velocities, the greatest one, in absolute value, is the one between 0s to 3s. During this interval, the object is moving backward but at the greatest velocity.

Answer:

A)  Δf = - 49 m, B)  v (7)  = -56 m / s, a = - 8 m / s², C)  t = 0.866 s

Explanation:

A) In this exercise ask to find the displacement and the average velocity, give the function of the movement

           f (t) = - 4t² +3

and the range of motion 0≤ t ≤ 7

the displacement is

for t = 0

           f (0) = 3

for t = 7 s

           f (7) = - 4 7² +3

           f (7) = -46 m

the total displacement is

           Δf = f (7) - f (0)

           Δf = -46 - 3

            Δf = - 49 m

the average speed is defined as the displacement between the time interval

           v = Df / Dt

           v = -49 / 7

           v = - 7 m / s

B) the speed and acceleration of the end points of the motion

the speed of defined by

          v = \(\frac{dx}{dt}\)

in this case

         v = \(\frac{df}{dt}\)

         v = -8t

let's calculate

          v (7) = -8 7

          v (7)  = -56 m / s

acceleration is defined by

          a = \(\frac{dv}{dt}\)

          a = - 8 m / s²

acceleration is constant throughout the movement

C) the point where the direction changes.

This point is a point where the position goes from positive to negative, the point f = 0

        0 = -4t² +3

        t = √¾

        t = 0.866 s

Answer You need to consider that the gravity on earth is 9.8 m/s/s. This means any object you let go on the earths surface will gain 9.8 m/s of speed every second. You need to apply a force on the object in the opposite direction to avoid this acceleration. If you are pushing something up at a constant speed, you are just resisting earths acceleration. The more massive and object is, the greater force is needed to accelerate it. The equation is Force = mass*acceleration. So for a 2kg object in a 9.8 m/s/s gravity you need 2kg*9.8m/s/s = 19.6 Newtons to counteract gravity. Work or energy = force * distance. So to push with 19.6 N over a distance of 2 meters = 19.6 N*2 m = 39.2 Joules of energy. There is an equation that puts together those two equations I just used and it is E = mgh

The amount of Energy to lift an object is (mass) * (acceleration due to gravity) * (height)

:Hence, the Work done to life the mass of 2 kg to a height of 10 m is 196 J. Hope it helps❤️❤️❤️

Explanation:

(a) The average acceleration of this sprinter is 3.31 m/s².

(b) The time taken for the sprinter to reach the speed is 3.5 s.

The average acceleration of this sprinter is calculated as follows;

v² = u² + 2as

where;

v² = 0 + 2as

a = v² / 2s

a = ( 11.5² ) / ( 2 x 20 )

a = 3.31 m/s²

The time of motion of the sprinter is calculated as follows;

v = u + at

v = 0 + at

t = v / a

t = ( 11.5 ) / ( 3.31 )

t = 3.5 s

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Answer:

D. trying to eat healthier foods

Explanation:

Answer:

I was just working on this now
z² - 0.8z - 98

Explanation:

To solve this problem, we first need to define some variables:

X: the average position of the atom at time t = Nr

p: the probability of transiting to the right

q: the probability of transiting to the left (q = 1-p)

N: the number of times the atom transits from one site to another

r: the time it takes for the atom to transit from one site to another

t: the total time for which we are calculating the average position

z: the mean square value of the atom's position at time t

With these definitions in mind, we can now proceed to solve the problem:

a. To calculate the average position of the atom at time t = Nr, we can use the following formula:

X = p*(X+1) + q*(X-1)

This formula states that the average position of the atom is equal to the probability of transiting to the right multiplied by the position one unit to the right, plus the probability of transiting to the left multiplied by the position one unit to the left.

Solving for X, we get:

X = (p-q)/(p+q)

Substituting p = 0.6 and q = 0.4, we get:

X = (0.6-0.4)/(0.6+0.4) = 0.2/1 = 0.2

This means that the average position of the atom at time t = Nr is 0.2 units to the right.

b. To calculate the mean square value (z-7)² at time t, we can use the following formula:

(z-7)² = p*((z+1)-7)² + q*((z-1)-7)²

This formula states that the mean square value is equal to the probability of transiting to the right multiplied by the square of the position one unit to the right minus 7, plus the probability of transiting to the left multiplied by the square of the position one unit to the left minus 7.

Solving for (z-7)², we get:

(z-7)² = p*(z+1-7)² + q*(z-1-7)²

= pz² + 2pz + p - 49 + qz² - 2qz - q - 49

= (p+q)*z² - 2(p-q)*z - 98

Substituting p = 0.6 and q = 0.4, we get:

(z-7)² = (0.6+0.4)*z² - 2(0.6-0.4)*z - 98

= z² - 0.8z - 98

This means that the mean square value (z-7)² at time t is a quadratic function of z.

Answer:

The answer is 5×10‐⁵

Step-by-step Explanation:

\( \alpha = \frac{l2 - l1}{l1( \beta 2 - \beta 1)} \)

let ß be ø

\( \alpha = \frac{40.05 - 40}{40(45 - 20)} \)

\( \alpha = \frac{0.05}{40 \times 25} \)

\( \alpha = \frac{0.05}{1000}\)

\( \alpha = \frac{0.05}{1000}\)\( \alpha = 5.0 \times {10}^{ - 5} \)

Answer:

A is correct a.p.e.x approved

Explanation:

have a nice day

Answer:

The angular displacement is not a length (not measured in meters or feet), so an angular displacement is different than a linear displacement. ... As the object rotates through the angular displacement phi, the point on the edge of the disk moves distance sa along a circular path.

5.73 seconds pass before the centripetal acceleration equals the tangential acceleration in strength.

This enables you to calculate the change in velocity in metres per second squared (m/s²). The change in velocity (v) over the change in time (t) is known as acceleration (a). It can be determined using the formula a = v/t.

a = v²/r

where a is the centripetal acceleration, v is the speed of the car, and r is the radius of the circular track (half the diameter).

a = (2.97 m/s²)

r = (195 m)/2 = 97.5 m

v² = ar = (2.97 m/s²)(97.5 m) = 289.58 m²/s²

v = √(289.58 m²/s²) = 17.01 m/s

at = dv/dt

where at is the tangential acceleration, and v is the speed of the car. Since the car is starting from rest, its initial speed is zero, so we can simplify the formula to:

at = v/t

where t is the elapsed time.

We want to find the time at which the magnitude of the tangential acceleration is equal to the magnitude of the centripetal acceleration, so:

at = ac

v/t = ac

t = v/ac = 17.01 m/s / 2.97 m/s² = 5.73 s

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Answer:

720W

Explanation:

PLEASE MARK ME AS BRAINLIEST AND HAVE A NICE DAY

The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.

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Answer:

P = (2 + 3) * V       where V is their initial speed  (total momentum)

P = 2 * 10 + 3 * Vx     where Vx here would be V3

If the initial momentum is not known how can one determine the final velocity of the 3 kg obj.

Also work depends on the sum of the velocities

W (initial) = 1/2 (2 + 3) V^2     the initial kinetic energy

W (final) = 1/2 * 2 * V2^2 + 1/2 * 3 * V3^2

It appears that more information is required for this problem