The value of (3^0+2^0) * 5^0

1
25
0
2​

a. For the conversion, the chief should multiply 8 by 5,280 to convert the 8 miles to feet. The Option C is correct

b. It will take the crew 440 minutes to paint 8 miles.

One mile is equal to 5280 feet. So, to convert our miles to feet, we need to multiply the length or distance in miles times 5280.

To convert miles to feet, the chief should multiply number of miles by the conversion factor of 5,280 feet per mile.

The measurement in feet will be:

= 8 miles * 5,280 feet/mile

= 42,240 feet.

B. If the crew can paint 96 feet in one minute, we will use unit rate of feet per minute to determine how long it will take to paint 42,240 feet which is:

= 42,240 feet /96 feet

= 440 minutes.

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Answer:

4.5 inch per 1 sec

Step-by-step explanation:

18/4=4.5

Answer:

The answer is 256 + 336 = 592. Although in reality you couldn't play soccer that much in two days.

On solving the provided question, we can say that equality of given trapezium we find, y=13/10 and x=21

A convex quadrilateral with exactly one pair of opposite sides that are parallel to one another is called a trapezium. When drawn on a piece of paper, the trapezium is a two-dimensional shape that resembles a table. A quadrilateral is a polygon in Euclidean geometry that has four sides and four vertices.

Since ABCD~PQRS

then, on comparing

5y-3/4 = 7/8

y=13/10

On comparing angle,

3x+24=87°

3x=63°

x=21

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Answer:

$0.14 per ounce

Step-by-step explanation:

Divide $2.24 by 16 and theres your answer

If four fudge machines complete a big order in 32 hours. then it takes 128 hours  to complete the order with 4 times the number of machines.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

The number of machines in a factory are four

4 machines complete a big order in 32 hours.

If all the machines at the fudge factory work at the same pace, we need to find How many hours would it take to complete the order with 4 times the number of machines.

4 times the number of machines.

=4×4=16 machine.

How long it will take for 16 machines to complete the same order.

4/32=16/x

Apply cross multiplication

4x=512

x=128

Hence 128 hours would it take to complete the order with 4 times the number of machines.

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In a survey, the number of students who don't like any of the three vegetables is 172. Total students = 293, The number of college students who don't like any of these three vegetables can be calculated.

Total students = 293,

Those who like Brussels sprouts = 69,

Those who like Broccoli = 94,

Those who like Cauliflower = 55,

Those who like both Brussels sprouts and broccoli = 30,

Those who like both Brussels sprouts and cauliflower = 25,

Those who like both broccoli and cauliflower = 21,

Those who like all three vegetables = 13.

Number of students who like Brussels sprouts only = 69 - 30 - 25 - 13

= 1

Number of students who like Broccoli only = 94 - 30 - 21 - 13

= 30

Number of students who like Cauliflower only = 55 - 25 - 21 - 13

= 1

Total students who like only one vegetable = 1 + 30 + 1

= 32.

Number of students who like two vegetables = 30 + 25 + 21

= 76.

Therefore, the total number of students who don't like any of these three vegetables is:

293 - 32 - 76 - 13 = 172.

The number of students who don't like any of the three vegetables is 172.

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Answer:

(x + 1)(x + 2) is divisible by 3.

Step-by-step explanation:

Assume that x is not divisible by 3. This means that x can be expressed as x = 3k + r, where k is an integer and r is the remainder when x is divided by 3. Since x is not divisible by 3, the remainder r must be either 1 or 2.

Case 1: r = 1

If r = 1, then x = 3k + 1. Now let's consider (x + 1)(x + 2):

(x + 1)(x + 2) = (3k + 1 + 1)(3k + 1 + 2)

= (3k + 2)(3k + 3)

= 3(3k^2 + 5k + 2)

We can see that (x + 1)(x + 2) is divisible by 3.

Case 2: r = 2

If r = 2, then x = 3k + 2. Now let's consider (x + 1)(x + 2):

(x + 1)(x + 2) = (3k + 2 + 1)(3k + 2 + 2)

= (3k + 3)(3k + 4)

= 3(3k^2 + 7k + 4)

We can see that (x + 1)(x + 2) is divisible by 3.

Hence, the statement is proven.

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Answer:

Step-by-step explanation:

EZ

its 21

Answer: 92

Step-by-step explanation:

Formula : Sum of first n numbers = Average x n

Given: Average score on first 6 tests= 84

A score on all 8 tests = 86

Then, Sum of first 6 numbers = 84 x 6 = 504

Sum of first 8 numbers = 86 x 8 = 688

Sum of two last numbers = (Sum of first 8 numbers) - (Sum of first 6 numbers)

= 688-504

=184

Average of last two numbers = (Sum of two last numbers )÷2

= 184÷2

= 92

Hence,  the average of your last two test scores = 92.

Answer:

\( \sf \: 2x + 2\)

Step-by-step explanation:

Given expression,

→ (3x + 4) - (x + 2)

Let's simplify the expression,

→ (3x + 4) - (x + 2)

→ 3x + 4 - x - 2

→ (3x - x) + (4 - 2)

→ (2x) + (2)

→ 2x + 2

Hence, the answer is 2x + 2.

Answer:

An equation in the form y = mx + b is in the 'slope y-intercept' form where m is the slope and b is the y-intercept. We can rewrite our equation, y = 4, in slope y-intercept form as follows: y = 0x + 4. Here, it is clear that the slope, or m, is zero. Therefore, the slope of the horizontal line y = 4 is zero

Answer:

C.

Step-by-step explanation:

The vertex and the point of intersection is just one point identifiied by its x and y vlaues

Answer:

1/4

Step-by-step explanation:

2 to the power of -2 would be 1/4.

This is because 2 to the power of -1 would be 1/2. And the power of 2 would square the 2 as the denominator making it 1/4.

The reason -1 makes the 2 turn into a fraction is that to the power of 2 means 2x2, to the power of one means 2, The power of zero would therefore divide by 2 so 2/2 = 1 and so 2 to the power of -1 would be 1/2.

         \(\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}\)

    What is 2 to the power of -2?

   \(\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}\)

Let's look at the last property of exponents - \(\bold{\#7 - negative\:exponents}\)

                                    \(\Large\text{$a^{-n}=\displaystyle\frac{1}{a^n}$}\)

So if we have a number with a negative exponent, we flip it over.

According to Property #7,

      \(\Large\text{2^{-2}=\displaystyle\frac{1}{2^2} =\frac{1}{4}$}\)

                    \(\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{60}{1}\)

The length of side arc to the nearest arc of a unit is 18.0 units. The closest option is 16.7 units.

To find the length of side ac, we need to use the Pythagorean theorem which states that in a right triangle, the sum of the squares of the two shorter sides (legs) is equal to the square of the longest side (hypotenuse). In this case, we are given the length of the two legs (ab and bc), so we can use the formula:
a^2 + b^2 = c^2
where a and b are the lengths of the legs and c is the length of the hypotenuse.
Plugging in the values we have:
6.6^2 + 16.7^2 = c^2
Simplifying this equation, we get:
43.56 + 278.89 = c^2
322.45 = c^2
Taking the square root of both sides, we get:
c = 17.97
Therefore, the length of side ac to the nearest tenth of a unit is 18.0 units. The correct option is not listed in the question, but  the closest option is 16.7 units.

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Answer:

4. Is 6 eggs

5. Is 7 eggs

Step-by-step explanation:

There are many ways Julio can roll the ball to reach it target. We can evaluate this situation by using probability.

Hence, we can evaluate the outcome by using probability.

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Answer:

2.646

Step-by-step explanation:

You have to 6 to the 1 and then take the square root of the number which is seven leaving you with 2.646

Answer:

x = ±√7

Step-by-step explanation:

Symbolically, we have x^2 - 6 = 1,  and so x^2 = 7, so that x = ±√7

Answer:  approximately 24 square units in the shaded areas

Step-by-step explanation:  

The area of the entire dark circles will be for each πr², then divided by 2 to get the area of the semicircles created on the sides of the triangles:

16π + 9π = 25π   Half that times value for pi

≈ 39.2699  is the area of the dark semicircles. Round to 39.27

Now the fun! Find the area of the parts subtracted by the light semicircle:

The area of the entire circle is 25π  or about 78.54. The triangle is half of an inscribed rectangle, 6×8, so 48.  Subtracted from the circle leaves about 30.54 in the four slices between the arcs of the circumference and the perimeter of the rectangle. We are concerned with only half of the slices, so we will subtract 15.27

Area of the dark semicircles minus the area of the light slices will leave the area of the shaded crescents:

Answer: 7x + 9w if you are just simplifying

Step-by-step explanation:

This is the UML diagram for the development of the program, in which Shapes 2D is the superclass and Circle, Square, Triangle, Rectangle, Rhombus, and Parallelogram are subclasses.

​​​​​​​This is the program in C++ demonstrating the above classes.

#include<iostream>

using namespace std;

class shapes

{

public:

   string name;

   string color;

   virtual void getAttributes()=0;

};

class Circle: public shapes

{

public:

   float radius;

   Circle(string n,string c, float r)

   {

       name=n;

       color=c;

       radius=r;

   }

   float getPerimeter()

   {

       return(2*(3.142)*radius);

   }

   float getArea()

   {

       return((3.142)*(radius*radius));

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Square:public shapes

{

public:

   float side;

   Square(string n,string c, float s)

   {

       name=n;

       color=c;

       side=s;

   }

   float getPerimeter()

   {

       return(4*side);

   }

   float getArea()

   {

       return(side*side);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Triangle:public shapes

{

public:

   float base;

   float height;

   float side1;

   float side2;

   float side3;

   Triangle(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter side1\n";

       cin>>side1;

       cout<<"Enter side2\n";

       cin>>side2;

       cout<<"Enter side3\n";

       cin>>side3;

       return(side1+side2+side3);

   }

   float getArea()

   {

       cout<<"Enter base\n";

       cin>>base;

       cout<<"Enter height\n";

       cin>>height;

       return((0.5)*base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rectangle:public shapes

{

public:

   float length;

   float breadth;

   Rectangle(string n,string c, float l,float b)

   {

       name=n;

       color=c;

       length=l;

       breadth=b;

   }

   float getPerimeter()

   {

       return(2*(length+breadth));

   }

   float getArea()

   {

       return(length*breadth);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rhombus:public shapes

{

public:

   float diagonal1;

   float diagonal2;

   float side;

   Rhombus(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter Side\n";

       cin>>side;

       return(4*side);

   }

   float getArea()

   {

       cout<<"Enter diagonal 1\n";

       cin>>diagonal1;

       cout<<"Enter diagonal 2\n";

       cin>>diagonal2;

       return((0.5)*diagonal1*diagonal2);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Parallelogram:public shapes

{

public:

   float base;

   float height;

   Parallelogram(string n,string c, float b,float h)

   {

       name=n;

       color=c;

       base=b;

       height=h;

   }

   float getPerimeter()

   {

       return(2*(base+height));

   }

   float getArea()

   {

       return(base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

int main()

{

   int choice;

   while(1)

   {

       cout<<"\n\nEnter your choice :";

       cout<<"\n1 for Circle\n";

       cout<<"2 for Square\n";

       cout<<"3 for Triangle\n";

       cout<<"4 for Rectangle\n";

       cout<<"5 for Rhombus\n";

       cout<<"6 for Parallelogram\n";

       cin>>choice;

       system("cls");

       switch(choice)

       {

       case 1:

           {

               float r;

               cout<<"Enter radius\n";

               cin>>r;

               Circle c("Circle","Yellow",r);

               c.getAttributes();

               cout<<"Perimeter : "<<c.getPerimeter()<<endl;

               cout<<"Area : "<<c.getArea()<<endl;

           }break;

       case 2:

           {

               float side;

               cout<<"Enter side\n";

               cin>>side;

               Square s("Square","Red",side);

               s.getAttributes();

               cout<<"Perimeter : "<<s.getPerimeter()<<endl;

               cout<<"Area : "<<s.getArea()<<endl;

           }break;

       case 3:

           {

               Triangle t("Triangle","Green");

               t.getAttributes();

               cout<<"Perimeter : "<<t.getPerimeter()<<endl;

               cout<<"Area : "<<t.getArea()<<endl;

           }break;

       case 4:

           {

               float l,b;

               cout<<"Enter Length and breadth\n";

               cin>>l>>b;

               Rectangle r("Rectangle","Blue",l,b);

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 5:

           {

               Rhombus r("Rhombus","Purple");

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 6:

           {

               float b,h;

               cout<<"Enter base\n";

               cin>>b;

               cout<<"Enter height\n";

               cin>>h;

               Parallelogram p("Parallelogram","Pink",b,h);

               p.getAttributes();

               cout<<"Perimeter : "<<p.getPerimeter()<<endl;

               cout<<"Area : "<<p.getArea()<<endl;

           }break;

       }

   }

}

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We have found two quadratic functions with x-intercepts (-5,0) and (5,0): f(x) =\(x^2 - 25\), which opens upward, and g(x) = \(-x^2 + 25\), which opens downward.

For the quadratic function that opens upward, we can use the x-intercepts (-5,0) and (5,0) to set up the equation:

f(x) = a(x + 5)(x - 5)

where a is a constant that determines the shape of the parabola. If this function opens upward, then a must be positive. Expanding the equation, we get:

f(x) = a(x^2 - 25)

To determine the value of a, we can use the fact that the coefficient of the x^2 term in a quadratic equation determines the shape of the parabola. Since we want the parabola to open upward, we need the coefficient of x^2 to be positive, so we can set a = 1:

f(x) = x^2 - 25

For the quadratic function that opens downward, we can use the x-intercepts (-5,0) and (5,0) to set up the equation:

g(x) = a(x + 5)(x - 5)

where a is a constant that determines the shape of the parabola. If this function opens downward, then a must be negative. Expanding the equation, we get:

g(x) = a(x^2 - 25)

To determine the value of a, we can use the fact that the coefficient of the x^2 term in a quadratic equation determines the shape of the parabola. Since we want the parabola to open downward, we need the coefficient of x^2 to be negative, so we can set a = -1:

g(x) = -x^2 + 25

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The slope of the line passing through the points (-5, -4) and (-13, 2) is -3/4.

Slope is simply expressed as a change in y over the change in x.

It is expressed as

\(m = \frac{y_2 - y_1}{x_2 - x_1}\)

Given the points:
(-5, -4) and (-13,2)​

Point (-5, -4):

x₁ = -5

y₁ = -4

Point (-13,2)​:

x₂ = -13

y₂ = 2

Plug the given x and y values into the slope formula and simplify.

\(m = \frac{y_2 - y_1}{x_2 - x_1}\\\\m = \frac{2 - (-4)}{-13 - (-5)}\\\\m = \frac{2 + 4}{-13 + 5}\\\\m = \frac{6}{-8}\\\\m = -\frac{3}{4}\)

Therefore, the slope of the line is -3/4.

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Answer:

102

Step-by-step explanation:

You have to subtract 214 - 112 you get 102.

the growth factor is simply the same amount, but in decimal format, so what is 5.1% of anything?

\(\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{5.1\% of anything}}{\left( \cfrac{5.1}{100} \right)anything}\implies 0.051(anything)\)

so the growth factor is simply the decimal format of 0.051.