The turbine develops 150 kW of power, which is transmitted to the gears such that C receives 70% and D receives 30%. Determine the angle of twist of end E of the shaft relative to B . Express your answer using three significant figures.

Answer:

Work to develop software and related documents that respect the privacy of those who will be affected by that software.

Explanation:

In the Software Engineering Code of Ethics and Professional Practice, under Principle, which is section three (3) of the document, it is stated in clause 12 on what information should a professional Engineer keep private.

In it, it is stated that professionals engineers should keep private information relating to "Work to develop software and related documents that respect the privacy of those who will be affected by that software."

Problem 2:A large tubular workpart with an outside diameter of 45 inches and an inside diameter of 25 inches needs to be faced on a lathe. The facing operation will be carried out at a rotational speed of 30 rev/min, a feed rate of 0.020 in/rev, and a depth of cut of 0.150 in. Determine:Cutting time to complete the facing operation.Cutting speeds.

Metal removal rates at the beginning and end of the cut.(a) The cutting time to complete the facing operation is given by the formula as follows:$$t_c=\frac{L}{frn}$$where L is the length of the workpart to be cut, f is the feed rate, r is the depth of cut, and n is the rotational speed.Let us first determine the length of the workpart to be cut. Since it is a tubular workpart, the length of the workpart is given by its circumference, that is,$$L=\pi\frac{(D_o-D_i)}{2}$$$$L=\pi\frac{(45-25)}{2}=31.42 in$$Substituting the values of L, f, r, and n, we get$$t_c=\frac{L}{frn}$$$$t_c=\frac{31.42}{0.020\times0.150\times30}=104.73\ minutes$$Therefore, the cutting time to complete the facing operation is 104.73 minutes.(b) The cutting speeds at the beginning and end of the cut are given by the formula as follows:$$v=\pi D n$$where D is the mean diameter of the workpart. The mean diameter of the workpart is given by,$$D=\frac{(D_o+D_i)}{2}$$$$D=\frac{(45+25)}{2}=35 in$$Substituting the values of D and n, we get$$v=\pi D n$$$$v=\pi\times35\times30$$$$v=3298.15\ in/min$$Therefore, the cutting speed is 3298.15 in/min.(c) The metal removal rate at the beginning and end of the cut are given by the formula as follows:$$Q=\frac{f\times v}{2}$$Substituting the values of f and v, we get at the beginning of the cut,$$Q=\frac{f\times v}{2}$$$$Q=\frac{0.020\times3298.15}{2}=32.98\ in^3/min$$Similarly, the metal removal rate at the end of the cut is,$$Q=\frac{f\times v}{2}$$$$Q=\frac{0.020\times3180.06}{2}=31.80\ in^3/min$$Therefore, the metal removal rate at the beginning of the cut is 32.98 in3/min, and at the end of the cut is 31.80 in3/min.Problem 3:Solve the problem as the previous one, except that the machine tool controls operate at a constant cutting speed by continuously adjusting rotational speed for the position of the tool relative to the axis of rotation.

The rotational speed at the beginning of the cut =30 rev/min, and is continuously increased thereafter to maintain a constant cutting speed.Since the machine tool controls operate at a constant cutting speed, the cutting speed can be calculated by the formula as follows:$$v=C_s\times R_p$$$$v=C_s\times\Delta r\times n$$$$v=C_s\times0.075\times n$$where Cs is the constant cutting speed, Rp is the radius of the tool relative to the axis of rotation, Δr is the change in radius of the tool for each unit change in length of cut, and n is the rotational speed.Since the rotational speed is 30 rev/min at the beginning of the cut, the constant cutting speed can be calculated by substituting the values of Δr, n, and v at the beginning of the cut.$$\Delta r=\frac{(D_o-D_i)}{2L}$$$$\Delta r=\frac{(45-25)}{2\times31.42}=0.075 in$$$$C_s=\frac{v}{\Delta r\times n}$$$$C_s=\frac{3298.15}{0.075\times30}=14662.8\ in/min$$Therefore, the constant cutting speed is 14662.8 in/min.To maintain a constant cutting speed, the rotational speed needs to be adjusted continuously. Let us calculate the rotational speed at the end of the cut. Since the metal removal rate is constant,$$Q=\frac{f\times v}{2}$$$$v=\frac{2Q}{f}$$$$v=\frac{2\times31.80}{0.020}=3180.06\ in/min$$Substituting the values of Cs, Δr, and v, we get$$C_s\times\Delta r\times n=v$$$$n=\frac{v}{C_s\times\Delta r}$$$$n=\frac{3180.06}{14662.8\times0.075}=2.720\ rev/min$$Therefore, the rotational speed at the end of the cut is 2.720 rev/min.

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Answer:

\(T=92.16 \°C\)

\(y_{et}=0.433\\\\y_w=0.567\)

Explanation:

Hello,

In this case, the Raoult's law for this problem is:

\(y_{et}P=x_{et}P_{et}^{sat}\\\\y_{w}P=x_{w}P_{w}^{sat}\)

Which can be written as:

\(P=x_{et}P_{et}^{sat}+x_{w}P_{w}^{sat}\)

Thus, by using the Antoine equation, we can symbolically represent the the temperature at which such mixture boil:

\(1atm=0.2608*10^{(8.13484-\frac{ 1662.48}{238.131+T})}/760+0.7392*10^{(5.40221-\frac{1838.675}{-31.737+T-273.15})}/1.01325\)

The solution, by numerical iteration process (there is not way to solve it analytically) is 92.16 °C considering the data extracted from NIST database. Next, vapor fractions are:

\(y_{et}=x_{et}*10^{(8.13484-\frac{ 1662.48}{238.131+T})}/760/P\\\\y_{et}=0.2608*10^{(8.13484-\frac{ 1662.48}{238.131+92.16})}/760/1atm\\\\y_{et}=0.433\\\\y_w=1-y_{et}=1-0.433\\\\y_w=0.567\)

Regards.

The loss characteristic of the 200 foot coaxial cable is approximately 6.55 dB/100 feet.

To calculate the loss characteristic, we can use the following formula:

L = 10*log10((P1/P2)*(Z2/Z1))

Where L is the loss in dB, P1 is the power at the source, P2 is the power at the end of the cable, Z1 is the source impedance, and Z2 is the cable impedance.

In this case, P1 is 29 dBm, which is equivalent to 0.794 W. P2 is unknown, but we can assume it is the same as P1, since the cable is terminated with a 50 ohm load. Z1 and Z2 are both 50 ohms. Plugging in these values and solving for L, we get:

L = 10*log10((0.794/0.794)*(50/50)) = 0 dB

This means that the cable itself does not introduce any loss. However, we need to consider the loss per unit length, which is given by:

L/length = 0 dB/200 ft = 0 dB/100 ft

Converting this to dB/100 feet, we get:

Loss characteristic = (0 dB/100 ft) * 6.55 = 6.55 dB/100 ft

Therefore, the loss characteristic of the 200 foot section of coaxial cable is approximately 6.55 dB/100 feet.

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Explanation:

Remember, to say a product is incorporated with aesthetic design implies that its overall appearance is designed to look beautiful to the eyes of the user/buyer. For example, a clothing company whose target market is mainly focused on women's clothing would need to take into consideration that certain colors like pink, blue, etc are attractive to women more than men. So they'll have to ensure the colors of their clothing are suitable to the needs of their target market.

The Universal Design process involves building products that can be used by a wide range of users at ease. For example, you may ask yourself: Is my product/service easily accesible to those with disabilities?

Other processes include;

In either a finite set with 11 elements, we obtain the following when multiplying by 4 modulo (11).

If a material cannot be broken down into a simpler form, it is regarded as an element. Their unique atomic number can be used to identify them. According their atomic number, the elements are grouped in the periodic table, and those with similar qualities may be noted.

7*7+17*7+1 modulo(11)=[7*7 modulo(11)+17*7 modulo(11)+1 modulo(11)]modulo(11)

=[49 modulo(11)+119 modulo(11)+1 modulo(11)]modulo(11)

=[5+9 +1]modulo(11)

=15 modulo(11)

=4 modulo(11)

7*7+17*7+1 modulo(11)=4 modulo(11)

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The goal of Nozick's discussion of experience machines is c. to devise a thought experiment that elucidates what we value in life.

The Importance of Machines and Machine Making:

Man relies on machines for transportation, communication, and work, among other things. People with specialized knowledge in the application of scientific principles to problem solving design and develop machines.

Many of humanity's problems have been solved mechanically, chemically, and electronically by these engineers, scientists, and inventors. The benefits of the industrial revolution, such as unprecedented increases in agricultural outputs that have improved food security, are just a few of the positive wonders it has wrought.

They have also brought misery and oppression to many people through ingenious weapons of war, some of which have brought the world to its knees.

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The python code that estimates pi using a given text is shown below

A Python code to estimate pi using the given text where comments (#) are used for explanatory purpose is as follows:

import string

# read the text file

with open('text.txt', 'r') as file:

   text = file.read()

# convert all uppercase letters to lowercase

text = text.lower()

# remove all characters that are not in the alphabet Ax

text = ''.join(filter(lambda x: x in string.ascii_lowercase + ' ', text))

# create the character vector x

x = list(text)

# calculate the frequency of each letter

freq = {}

for letter in string.ascii_lowercase:

   freq[letter] = x.count(letter) / len(x)

# print the estimated pi for each letter

for letter in string.ascii_lowercase:

   print(f"p({letter}) = {freq[letter]}")

Note that you need to replace text.txt with the name of the text file that contains the text you want to parse.

This code reads the text file, converts all uppercase letters to lowercase, removes all characters that are not in the alphabet Ax, and creates the character vector x.

Then it calculates the frequency of each letter in x and prints the estimated pi for each letter.

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D. Neither. Technician A is incorrect because the oil filter wrench should be positioned at the outer end of the filter, not the inner end. Technician B is also incorrect because the oil pan drain plug should be turned counterclockwise to loosen it, not clockwise.

1. Technician A says that when removing an oil filter, position the oil filter wrench at the inner end of the filter. This is because the oil filter wrench should grip the filter tightly to prevent it from slipping and damaging the filter or the wrench. By placing the wrench at the inner end, it can grip the filter securely.

2. Technician B says that when loosening an oil pan drain plug, turn it clockwise. This is incorrect. To loosen an oil pan drain plug, it should be turned counterclockwise. This is because most bolts and screws, including drain plugs, are designed to be loosened by turning counterclockwise. Turning a drain plug clockwise can cause it to become even tighter and more difficult to remove.

3. Therefore, the correct answer is A. Technician A is correct in advising to position the oil filter wrench at the inner end of the filter when removing it. However, Technician B is incorrect in advising to turn an oil pan drain plug clockwise when loosening it. It should be turned counterclockwise to loosen it.

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Answer:

1. Chemical engineering is a broad field that encompasses a wide range of topics, including chemistry, physics, mathematics, and engineering. This makes it a challenging field to study, as students must have a strong foundation in all of these subjects. Additionally, chemical engineers are responsible for designing and operating large-scale chemical processes, which can be complex and dangerous. As a result, chemical engineering is considered to be one of the most difficult and complex aspects of engineering.

2. Stoichiometry is the study of the quantitative relationships between the reactants and products in a chemical reaction. It is important for chemical engineers because it allows them to calculate the amount of reactants and products that will be produced in a reaction. This information is essential for designing and operating chemical processes safely and efficiently.

3. Yes, consumers would notice if process control standards were not met. For example, if the temperature in a food processing plant is not controlled properly, the food could spoil. Similarly, if the pressure in a chemical plant is not controlled properly, there could be an explosion. As a result, it is important for chemical engineers to ensure that process control standards are met in order to protect the safety of consumers.

4. If I were a chemical engineer who had been given the task of working with a museum curator to create a display case for a rare painting, I would choose a control system that uses sensors to monitor the temperature, humidity, and light exposure of the painting. The control system would then adjust the conditions in the display case as needed to maintain the painting in its optimal condition. For example, if the temperature in the display case starts to rise, the control system would turn on a fan to cool it down. Similarly, if the humidity in the display case starts to increase, the control system would turn on a dehumidifier to dry it out.

5. A culture of caution is one in which everyone in the workplace is aware of the potential hazards and takes steps to prevent accidents. This can be accomplished by providing employees with safety training, enforcing safety regulations, and creating a workplace environment where employees feel comfortable reporting safety concerns.

Here are some additional tips for cultivating a culture of caution in the workplace:

* **Create a safety culture that emphasizes prevention over reaction.** This means teaching employees to think about safety before they act, and to be proactive in identifying and correcting potential hazards.

* **Make safety a priority at all levels of the organization.** This means setting clear safety goals, providing resources for safety training, and holding employees accountable for following safety procedures.

* **Encourage employees to speak up about safety concerns.** Employees should feel comfortable reporting any safety hazards they see, no matter how small they may seem.

* **Create a positive and supportive safety culture.** Employees should feel like they are part of a team and that their safety is important to the organization.

Explanation:

Drawing, in other words, aid you in defining your new area and selecting you scrap metal and finish. When changing structural components as a result of building, like moving a bearing wall, drawings are needed.

Architecture is a difficult profession that requires a lot of labor. All successful architects have put in tremendous effort and sacrifice to reach where they are.

Entry criteria range at Cca to Extracts, with BBB being the most often requested grade by universities and institutions. Moreover, you typically need five GCSEs with a grade of C or over, encompassing English and arithmetic. Degrees in design and landscaping architecture often don't call for any particular A level topics.

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Answer:

i think its called leggings thats wut my shop teacher told me

Explanation:

Using the Newton's second law of motion we will see that the acceleration is  0.0875 m/s^2.

The acceleration of a vehicle is determined by the force acting on it and its mass, as described by Newton's second law of motion:

F = m * a

where F is the force acting on the object, m is the mass of the object, and a is the resulting acceleration.

In this case, the force acting on the vehicle is 0.07 N, and the mass of the vehicle is 0.8 kg. Substituting these values into the equation above, we get:

0.07 N = 0.8 kg * a

Solving for a, we get:

a = 0.07 N / 0.8 kg

a = 0.0875 m/s^2

Therefore, the acceleration of the 0.8 kg vehicle powered by 0.07 N of force is 0.0875 m/s^2.

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Answer:

a)

normal circular pitch = 7.8539 mm

transverse circular pitch = 9.0689 mm

axial circular pitches = 15.7077

b)

transverse diametral pitch is 0.3464 teeth/mm

transverse pressure angle is 22.8°

c)

Addendum = 2.5 mm

dedendum = 3.125 mm

pinion diameter = 54.8482 mm and Gear diameter = 164.5448 mm

Explanation:

Given that;

module m = 2.5 mm

Number of teeth on Gear  nG = 57 TEETH

Number of teeth on Pinion  nP = 19 TEETH

Helix angle W = 30°

Normal Pressure angle β = 20°

finding the circular pitch

Pc = πm

we substitute

Pc = π * 2.5 mm = 7.8539 mm

now the diametral pitch p = π / Pc

= π / 7.8539

= 0.4 teeth/mm

a)

So the normal circular pitch

Pn = π / P

Pn = π / 0.4

Pn = 7.8539 mm

the transverse circular pitch

Pt = Pn / cosW

Pt = 7.8539 / cos30°

Pt = 9.0689 mm

for axial circular pitches

Px = Pt / tanW

Px = 9.0689 / tan30°

Px = 15.7077

b)

The transverse diametral pitch and the transverse pressure angle.

The transverse diametral pitch Pt = PcosW

= 0.4 * cos30°

= 0.3464 teeth/mm

transverse diametral pitch is 0.3464 teeth/mm

transverse pressure angle  β1 = tan^-1 ( tan βn / cos W)

=  tan^-1 ( tan20° / cos 30°)

= tan^-1 ( 0.42027 )

β1 = 22.8°

transverse pressure angle is 22.8°

c)

The addendum, dedendum, and pitch diameter of each gear

Now from table standard Tooth proportions for Helical Gears;

Addendum a = 1/p

= 1 / 0.4

= 2.5 mm

dedendum b = 1.25 / p

= 1.25 / 0.4

= 3.125 mm

now  pinion diameter dP = Np / PcosW

= 19 / 0.4 (cos30°)

= 54.8482 mm

Gear diameter dG = nG / pcosW

= 57 / 0.4 (cos30°)

= 164.5448 mm

Explanation:

most big airports. my father has the same degree and works for southwest airlines

Formwork is a temporary structure that is used in construction to provide support and shape to freshly poured concrete until it is strong enough to stand on its own.

It is a crucial component of any construction project as it ensures that the concrete is poured into the desired shape and size, and prevents any potential collapses or deformations. Additionally, formwork helps to create a smooth and uniform finish to the concrete surface, which is important for both aesthetic and functional purposes. Overall, formwork is an essential tool in modern construction, providing a safe and reliable method of shaping and supporting concrete structures.

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Answer:

16

Explanation:

The supporting load-bearing components of the structure will rest on footings that make up a slab on grade foundation. Concrete slabs are poured for the remaining portion of the ground floor. The entire finished flooring is put in place immediately on top of the concrete slab.

Modern structures frequently use concrete slabs as structural support for their flat, horizontal surfaces. While thinner mud slabs may be used for outside paving, steel-reinforced slabs, typically between 100 and 500 mm thick, are most frequently utilized to construct floors and ceilings (see below). The ground floor of many residential and commercial buildings is constructed from a large concrete slab that is either supported by foundations or rests directly on the subsoil. These slabs are often categorized as suspended or ground-bearing. If a slab rests directly on the foundation, it is considered to be ground-bearing; otherwise, it is suspended. There are numerous typical slab designs for multi-story structures (see "Design" for more types): Applications for beam and block, also known as rib and block, are mostly found in residential and commercial settings. Pre-stressed beams and hollow blocks make up this sort of slab, which is temporarily supported until it sets, usually after 21 days. A precast hollow core slab that is crane-installed on the job site. Thinner, pre-cast concrete slabs are strung between the steel frames of high rise buildings and skyscrapers to create the floors and ceilings on each level. Along with homes, high rise structures and sizable shopping centres also use cast in-situ slabs. Shutters and reinforced steel are used to cast these in-situ slabs on the spot.

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A 0.5 cm-diameter rod of Al2O3, having an engineering yield strength of 241 MPa, can withstand a maximum force of 2,273 N with no plastic deformation.

This can be calculated as follows: We know that the engineering yield strength (σy) of Al2O3 = 241 MPa Area (A) of the rod is given by: A = (πd²)/4Where d = diameter of the rod = 0.5 cm= 0.005 m Therefore, A = (π x 0.005²)/4= 1.9635 x 10^-5 m²Using the formula for stress (σ) which is given by:σ = F/A Where F is the force applied, we can obtain the maximum force that the rod can withstand with no plastic deformation, by equating the stress (σ) to the yield strength (σy).

σ = σy=> F/A = σy=> F = A x σy=> F = 1.9635 x 10^-5 m² x 241 x 10^6 Pa=> F = 4,723.053 NAs we know that the force applied should be less than the maximum force that can be applied without any plastic deformation, the maximum force that the rod can withstand with no plastic deformation is the maximum force obtained above, which is approximately equal to 2,273 N.

Therefore, the maximum force that a 0.5 cm-diameter rod of Al2O3, having an engineering yield strength of 241 MPa, can withstand with no plastic deformation is 2,273 N.

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Answer:

I think the answer is d: underground tunnel

Explanation:

Hope this helps

Bob comes to the conclusion that a living area rooms are not a reliable indicator of its sale value based just on 0.05 weak correlation score.

What exactly does correlation entail? A statistical measure called correlation describes how linearly closely two variables are related (meaning they change together at a constant rate). It's a typical technique for illustrating straightforward relationships without explicitly mentioning cause and effect.

However, correlation is the analytic term used to describe the relationship between two numerical values. Furthermore, we consider the relationship to be linear, meaning that for each unit change in one element, the other will also change by a defined amount.

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Answer: See explanation

Explanation:

69.48 / 7.2 = 965 as written in the question isn't correct. The correct answer should have been:

69.48 / 7.2 = 9.65

It should be noted that when we divide, the answer that one gets cannot be more than the two numbers that were used for the division. Hence, there's no way that 965 would be more than 69.48 and 7.2.

Profit-Centric Design Professionals can be developed by training and educating people on design principles, business strategies, and user research in order to create profitable solutions.

A profit center is a branch or division of a company that directly contributes to the bottom-line profitability of the corporation. A profit center is treated as a separate business, with revenues recorded separately.

Developing Profit Centric Design Professionals entails design, business, and user research training in order to create profitable solutions for clients.

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Answer:

  5 rpm

Explanation:

Each turn of the driver gear moves 10 teeth past the point of engagement with the driven gear. That is half of the 20 teeth on the driven gear, so it makes 1/2 turn for each turn of the driver.

In 1 minute, the driver makes 10 turns, so the driven gear makes 5 turns. Its speed is 5 rpm.

a.  The sources of the PMOS transistors are connected to the power supply voltage (VDD). b. The XOR gate can be implemented using a combination of NMOS and PMOS transistors. The inverter can be implemented using a single NMOS transistor and a single PMOS transistor.

To implement the given logic gates using CMOS technology, we can use a combination of NMOS and PMOS transistors. Here's how you can implement each gate:

a) 3-input NAND gate:

A 3-input NAND gate can be implemented using a series connection of three NMOS transistors and a parallel connection of three PMOS transistors.

```

         +---------+

Input A --|         |

         |   NAND  |--- Output

Input B --|         |

         |         |

Input C --|         |

         +---------+

```

The NMOS transistors are connected in series between the input nodes and the output node. The gates of the NMOS transistors are connected together, acting as the input of the NAND gate. The sources of the NMOS transistors are connected to the ground (GND). The PMOS transistors are connected in parallel between the output node and the power supply voltage (VDD). The gates of the PMOS transistors are connected together and act as the input of the NAND gate. The sources of the PMOS transistors are connected to the power supply voltage (VDD).

b) 2-input OR gate:

A 2-input OR gate can be implemented using a parallel connection of two NMOS transistors and a series connection of two PMOS transistors.

```

         +---------+

Input A --|         |

         |   OR    |--- Output

Input B --|         |

         +---------+

```

The NMOS transistors are connected in parallel between the input nodes and the output node. The gates of the NMOS transistors are connected together and act as the input of the OR gate. The sources of the NMOS transistors are connected to the ground (GND). The PMOS transistors are connected in series between the output node and the power supply voltage (VDD). The gates of the PMOS transistors are connected together, acting as the input of the OR gate. The sources of the PMOS transistors are connected to the power supply voltage (VDD).

c) 2-input XNOR gate:

A 2-input XNOR gate can be implemented using a combination of NMOS and PMOS transistors. It can be implemented using a 2-input XOR gate followed by an inverter.

```

         +---------+

Input A --|         |

         |   XOR   |---- Output

Input B --|         |

         +----+----+

              |

              |   Inverter

              |

             Output

```

The XOR gate can be implemented using a combination of NMOS and PMOS transistors. The inverter can be implemented using a single NMOS transistor and a single PMOS transistor.

Note: The specific sizes and configurations of the transistors may vary depending on the desired performance and technology parameters. The above illustrations provide a simplified representation of the gate implementations using CMOS technology.

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Rail could implement dedicated passenger-freight trains and improve scheduling coordination between the two services.

To move passengers with freight, rail systems can adopt a few strategies similar to what airlines do. One approach is to establish dedicated passenger-freight trains that are specifically designed to accommodate both types of transportation. These trains would have separate compartments or sections for passengers and freight, allowing them to coexist efficiently. By allocating specific cars or areas of the train for passenger travel, rail companies can ensure a comfortable and convenient experience for passengers while still transporting freight.

Additionally, improving scheduling coordination between passenger and freight services is crucial. Rail companies can implement better planning and communication systems to optimize the flow of both passengers and freight. This involves designing timetables that minimize conflicts between passenger and freight trains, allowing for smooth operations and reducing delays. Enhanced coordination between the various rail operators, freight companies, and passenger service providers would be essential to ensure efficient movement and avoid conflicts in scheduling and routes.

Furthermore, infrastructure investments can play a significant role in facilitating the movement of passengers with freight. Expanding and upgrading rail networks to accommodate increased passenger and freight traffic is crucial. This may involve building additional tracks or dedicated rail lines specifically for passenger trains or establishing terminals that can handle both passenger and freight services effectively. Creating efficient intermodal connections between rail and other modes of transportation, such as airports or ports, can further enhance the seamless movement of passengers and freight.

In summary, rail systems can move passengers with freight by implementing dedicated trains, improving scheduling coordination, and investing in infrastructure. By considering the unique needs of both passenger and freight services and finding ways to integrate them effectively, rail companies can offer a more versatile and efficient transportation solution.

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Answer:

Explanation:

The temperature difference used for calculation would depend on the desired indoor temperature, the outdoor temperature, and the desired level of energy efficiency. A professional heating system designer would be able to provide a more accurate answer based on the specific requirements of the building and the heating system being designed.

Answer:

sorry im answering questions for the points cuz im built dfferent

Explanation:

Answer: That happens to me too sometimes. I hate when people give the wrong answers...like if u don't know the answer, then don't respond

918.63517 is the answer.