The tune-up specifications of a car call for the spark plugs to be tightened to a torque of 50 N⋅ m . You plan to tighten the plugs by pulling on the end of a 23-cm-long wrench. Because of the cramped space under the hood, you'll need to pull at an angle of 125° with respect to the wrench shaft. With what force must you pull? F=?
Answers
Answer:
F=265.39N
Explanation:
In order to solve this problem, we must first draw a diagram of what the problem looks like (see attached picture).
So, in order to find the torque we must use the torque formula:
\(\tau=rxF\)
or
\(\tau=rFsin\theta\)
In this case we can either use 125° or 55°, the answer should be the same. So when solving the formula for F we get:
\(F=\frac{\tau}{r sin\theta}\)
so we can now substitute values:
\(F=\frac{50Nm}{(23x10^{-2}m)sin 125^{o}}\)
so
F=265.39N
Related Questions
Merchants get commission from selling products that are consigned to them true or false
Answers
Answer:
true
Explanation:
.Q3. The database Subset_Table is as follows (the entire database is shown).
Product ID productName Supplier ID Category ID Unit Price 9 Mishi kobe niku 4 6 18-500 g pkgs 97
18 Carnarvon tigers 7 8 16 kp pkg 62.5
20 Sir rodney’s marmalade 8 3 30 gift boxes 81
27 Schoggi schokolade 11 3 100 -100 g pleces 43.9
Please write down the final output of the following two SQL statements. You only need to write down the actual final output and do not need to provide any description. CREATE TABLE My_Items AS SELECT * FROM Subset_Table WHERE Unit LIKE '%pie%' OR Unit LIKE %pkgs%' OR Product Name LIKE '%' AND Price < 80; SELECT CategoryID, COUNT (ProductID) AS NumOfitems FROM My_Items GROUP BY CategoryID ORDER BY CategoryID ASC.
Answers
The result shows the CategoryID and the count of ProductID for each category in ascending order of CategoryID.
The final output of the two SQL statements would be as follows:
CREATE TABLE My_Items AS SELECT * FROM Subset_Table WHERE Unit LIKE '%pie%' OR Unit LIKE '%pkgs%' OR ProductName LIKE '%' AND Price < 80;
The output of this statement would be a new table called "My_Items" containing the following rows from the Subset_Table:
Product ID | ProductName | Supplier ID | Category ID | Unit | Unit Price
9 | Mishi kobe niku | 4 | 6 | 18-500 g pkgs | 97
18 | Carnarvon tigers | 7 | 8 | 16 kp pkg | 62.5
20 | Sir rodney’s marmalade | 8 | 3 | 30 gift boxes | 81
SELECT CategoryID, COUNT(ProductID) AS NumOfItems FROM My_Items GROUP BY CategoryID ORDER BY CategoryID ASC;
The output of this statement would be the following result:
CategoryID | NumOfItems
3 | 1
6 | 1
8 | 1
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a pressure cooker is a pan that cooks food much faster than ordinary pans by maintaining a higher pressure and temperature during cooking. the pressure inside the pan is controlled by a pressure regulator (the petcock) which keeps the pressure at a constant level by periodically allowing some steam to escape, thus preventing any excess pressure buildup. a certain pressure cooker has a volume of 6 l and an operating pressure of 75 kpa gage. initially, it contains 1 kg of water. heat is supplied to the pressure cooker at a rate of 500 w for 30 min after the operating pressure is reached. assuming an atmospheric pressure of 100 kpa, determine: a) the temperature at which cooking takes place. b) the amount of water left in the pressure cooker at the end of the process. assume some liquid water is still in the pan.
Answers
More cooking is done before the water actually begins to boil thanks to the raised pressure inside the cooker, which raises the boiling point of water above 1000C. In the end, food cooks more quickly.
Slow-cooked meals can be quickly prepared with pressure cookers. They are efficient in terms of electricity consumption and are excellent for tenderizing less expensive portions of meat. They are a healthy cooking method since they effectively retain nutrients and can cut cooking times by up to 50%. Water boils at 121°C (250°F) at that pressure. As a result, food may cook at considerably greater temperatures than it could under atmospheric pressure. Additionally, because cooking reactions quicken at higher temperatures, food cooks more quickly it is a good technology.
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When there is a large difference between the speed of the impeller and the turbine
Answers
When there is a large difference between the speed of the impeller and the turbine, it is known as a high speed ratio. In fluid dynamics, the impeller is a rotating component that is responsible for imparting energy to the fluid, while the turbine is a stationary component that converts the fluid's kinetic energy into mechanical work.
A large speed difference between the impeller and the turbine can have several effects. Firstly, it increases the velocity of the fluid as it passes through the impeller, resulting in higher kinetic energy. This increased kinetic energy is then converted into mechanical work by the turbine. Therefore, a higher speed ratio can lead to increased power output from the system.
Additionally, a large speed ratio can also cause a greater pressure drop across the impeller and turbine. This pressure drop is necessary to maintain the flow of fluid through the system. The higher the speed ratio, the greater the pressure drop required to ensure sufficient fluid flow.
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the competitive battles among rival sellers striving for better market positions, higher sales and market shares, and competitive advantage suggest the rivalry force multiple choice is stronger when firms strive to be low-cost producers than when they use differentiation and focus strategies. is often weak when rivals have emotional stakes in business or face high exit barriers. is largely unaffected by whether industry conditions tempt rivals to use price cuts or other competitive weapons to boost unit sales. tends to intensify when strong companies with sizable financial resources, proven competitive capabilities, and respected brand names hurdle entry barriers looking for growth opportunities and launch aggressive, well-funded moves to transform into strong market contenders. is weaker when more firms have weakly differentiated products, buyer demand is growing slowly, and buyers have moderate switching costs.
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tends to intensify when strong companies with sizable financial resources, proven competitive capabilities, and respected brand names hurdle entry barriers looking for growth opportunities and launch aggressive, well-funded moves to transform into strong market contenders.
A competitive analysis, also known as a competitor analysis, evaluates your company's performance in relation to other companies in your market providing equivalent products or services.
A competitor study identifies each participant's operational strengths, substantive shortcomings, product offers, market dominance, and missed opportunities, according to David Taffet, CEO of Petal, and focuses on finding market competitors positioned to intrude on your potential.
These are some ways competitor analyses aid in business improvement:
Determine your areas of strength and weakness.Recognize the environment you work in.Analyze the trends in your industry.Make plans for future expansion.To know more about competitive:
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b) Discuss the recent trends in Production and operations management.
Answers
Explanation Operations management is an area of management concerned with designing and controlling the process of production and redesigning business operations in the production of goods or services.[1] It involves the responsibility of ensuring that business operations are efficient in terms of using as few resources as needed and effective in meeting customer requirements.
if the oil pressure gauge fluctuates over a wide range from zero to normal operating pressure, the most likely cause is group of answer choices low oil supply. broken or weak pressure relief valve spring. air lock in the scavenge pump intake.
Answers
If the oil pressure gauge fluctuates over a wide range from zero to normal operating pressure, the most likely cause is air lock in the scavenge pump intake.
Oil pressure gauge fluctuation is a common problem for the engine. It can occur due to various reasons such as faulty oil pressure gauge, oil pump failure, improper maintenance of the engine, oil leakage, and much more. But if the oil pressure gauge fluctuates over a wide range from zero to normal operating pressure, the most likely cause is air lock in the scavenge pump intake.The scavenge pump in the engine is used to remove the oil from the engine's crankcase and delivers it back to the oil tank. If there is an air lock in the scavenge pump intake, then it will not pump the oil properly from the crankcase and deliver it back to the oil tank. It will cause the oil pressure to fluctuate over a wide range from zero to normal operating pressure.To fix this issue, you should first check the oil level in the engine and make sure that it is at the proper level. After that, you can check the scavenge pump intake for any air lock or blockage. If there is an air lock, then you need to remove it. If there is a blockage, then you need to remove the blockage to get the oil pump working again properly.
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An engineer is testing the shear strength of spot welds used on a construction site. The engineer's null hypothesis at a 5% level of signigicance, is that th mean shear strenfth of spot welds is at least 3.1 MPa. The engineer randomly selcts 15 Welds and measures the shear strength is 3.07 MPa with a sample standard deciation of 0.069 MPa. Which of the following statment is true?
a) The null hypothesis should not be rejected.
b) The null hypothesis should be rejected.
c) The alternate hypothesis should be rejected.
d) The null and alternate hypotheses are equally likely.
Answers
Answer:
b) The null hypothesis should be rejected.
Explanation:
The null hypothesis is that the mean shear strength of spot welds is at least
3.1 MPa
H0: u ≥3.1 MPa against the claim Ha: u< 3.1 MPa
The alternate hypothesis is that the mean shear strength of spot welds is less than 3.1 MPa.
This is one tailed test
The critical region Z(0.05) < ± 1.645
The Sample mean= x`= 3.07
The number of welds= n= 15
Standard Deviation= s= 0.069
Applying z test
z= x`-u/s/√n
z= 3.07-3.1/0.069/√15
z= -0.03/0.0178
z= -1.68
As the calculated z= -1.68 falls in the critical region Z(0.05) < ± 1.645 the null hypothesis is rejected and the alternate hypothesis is accepted that the mean shear strength of spot welds is less than 3.1 MPa
A team power plant operates on an ideal reheat Rankine cycle. The plant maintains the boiler pressure at 17.5 Mpa, the reheater section at 2 Mpa and the condenser at 1 kPa. Steam enters both stages of the turbine at 600 oC. If the mass flow rate is 12 kg/s, determine:
a) The total rate of heat input in the boiler;
b) The total rate of heat rejected in the condenser;
c) The power produced in MW;
d) The thermal efficiency of the cycle in %.
_________.
h1 (kJ/kg) Format : 96.609
v1 (m3/kg) Format : 0.002
wP_in (kJ/kg) Format : 46.7
h2 (kJ/kg) Format : 64.2
h3 (kJ/kg) Format : 4399.8
s3 (kJ/kgK) Format : 9.889
h4 (kJ/kg) Format : 6938.43
h5 (kJ/kg) Format : 4740.5
s5 (kJ/kgK) Format : 9.9047
x6 Format : 0.2339
h6 (kJ/kg) Format : 4856.4
Qin (kJ/s) Format : 57484
Qout (kJ/s) Format : 39633
W (MW) Format : 23.54
Efficiency (%) Format : 90.2
Answers
a) The total rate of heat input in the boiler is -57484 kJ/s.
b) The total rate of heat rejected in the condenser is 39633 kJ/s.
c) The power produced in the cycle is 23.54 MW.
d) The thermal efficiency of the cycle is 4.096%.
Given data:
Mass flow rate (m) = 12 kg/s
Boiler pressure (P1) = 17.5 MPa
Reheater pressure (P2) = 2 MPa
Condenser pressure (P3) = 1 kPa
Inlet temperature (T1) = 600 °C
Specific enthalpy at state 1 (h1) = 96.609 kJ/kg
Specific volume at state 1 (v1) = 0.002 m³/kg
Specific work input (wP_in) = 46.7 kJ/kg
Specific enthalpy at state 2 (h2) = 64.2 kJ/kg
Specific enthalpy at state 3 (h3) = 4399.8 kJ/kg
Entropy at state 3 (s3) = 9.889 kJ/kgK
Specific enthalpy at state 4 (h4) = 6938.43 kJ/kg
Specific enthalpy at state 5 (h5) = 4740.5 kJ/kg
Entropy at state 5 (s5) = 9.9047 kJ/kgK
Quality at state 6 (x6) = 0.2339
Specific enthalpy at state 6 (h6) = 4856.4 kJ/kg
a) The total rate of heat input in the boiler:
Qin = m (h1 - h6)
= 12 (96.609 - 4856.4)
= -57484 kJ/s (negative sign indicates heat input)
b) The total rate of heat rejected in the condenser:
Q out = m (h4 - h5)
= 12 (6938.43 - 4740.5)
= 39633 kJ/s
c) The power produced in MW:
W = m (h1 - h2 + wP_in)
= 12 (96.609 - 64.2 + 46.7)
= 23.54 MW
d) The thermal efficiency of the cycle:
Efficiency = (W / Qin) x 100
= (23.54 / 57484) x 100
= 0.04096 x 100
= 4.096%
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B1) 20 pts. The thickness of each of the two sheets to be resistance spot welded is 3.5 mm. It is desired to form a weld nugget that is 5.5 mm in diameter and 5.0 mm thick after 0.3 sec welding time. The unit melting energy for a certain sheet metal is 9.5 J/mm3 . The electrical resistance between the surfaces is 140 micro ohms, and only one third of the electrical energy generated will be used to form the weld nugget (the rest being dissipated), determine the minimum current level required.
Answers
Answer:
minimum current level required = 8975.95 amperes
Explanation:
Given data:
diameter = 5.5 mm
length = 5.0 mm
T = 0.3
unit melting energy = 9.5 j/mm^3
electrical resistance = 140 micro ohms
thickness of each of the two sheets = 3.5mm
Determine the minimum current level required
first we calculate the volume of the weld nugget
v = \(\frac{\pi }{4} * D^2 * l\) = \(\frac{\pi }{4} * 5.5^2 * 5\) = 118.73 mm^3
next calculate the required melting energy
= volume of weld nugget * unit melting energy
= 118.73 * 9.5 = 1127.94 joules
next find the actual required electric energy
= required melting energy / efficiency
= 1127 .94 / ( 1/3 ) = 3383.84 J
TO DETERMINE THE CURRENT LEVEL REQUIRED use the relation below
electrical energy = I^2 * R * T
3383.84 / R*T = I^2
3383.84 / (( 140 * 10^-6 ) * 0.3 ) = I^2
therefore 8975.95 = I ( current )
The boost converter of Fig. 6-8 has parameter Vs 20 V, D 0.6, R 12.5 , L 10 H, C 40 F, and the switching frequency is 200 kHz. (a) Determine the output voltage. (b) Determine the average, maximum, and minimum inductor currents. (c) Determine the output voltage ripple. (d) Determine the average current in the diode. Assume ideal components.
Answers
Answer:
a) the output voltage is 50 V
b)
- the average inductor current is 10 A
- the maximum inductor current is 13 A
- the maximum inductor current is 7 A
c) the output voltage ripple is 0.006 or 0.6%V₀
d) the average current in the diode under ideal components is 4 A
Explanation:
Given the data in the question;
a) the output voltage
V₀ = V\(_s\)/( 1 - D )
given that; V\(_s\) = 20 V, D = 0.6
we substitute
V₀ = 20 / ( 1 - 0.6 )
V₀ = 20 / 0.4
V₀ = 50 V
Therefore, the output voltage is 50 V
b)
- the average inductor current
\(I_L\) = V\(_s\) / ( 1 - D )²R
given that R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6
we substitute
\(I_L\) = 20 / (( 1 - 0.6 )² × 12.5)
\(I_L\) = 20 / (( 0.4)² × 12.5)
\(I_L\) = 20 / ( 0.16 × 12.5 )
\(I_L\) = 20 / 2
\(I_L\) = 10 A
Therefore, the average inductor current is 10 A
- the maximum inductor current
\(I_{Lmax\) = [V\(_s\) / ( 1 - D )²R] + [ V
given that, R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6, L = 10 μH, T = 1/200 kHz = 5 hz
we substitute
\(I_{Lmax\) = [20 / (( 1 - 0.6 )² × 12.5)] + [ (20 × 0.6 × 5) / (2 × 10) ]
\(I_{Lmax\) = [20 / 2 ] + [ 60 / 20 ]
\(I_{Lmax\) = 10 + 3
\(I_{Lmax\) = 13 A
Therefore, the maximum inductor current is 13 A
- The minimum inductor current
\(I_{Lmax\) = [V\(_s\) / ( 1 - D )²R] - [ V
given that, R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6, L = 10 μH, T = 1/200 kHz = 5 hz
we substitute
\(I_{Lmin\) = [20 / (( 1 - 0.6 )² × 12.5)] - [ (20 × 0.6 × 5) / (2 × 10) ]
\(I_{Lmin\) = [20 / 2 ] -[ 60 / 20 ]
\(I_{Lmin\) = 10 - 3
\(I_{Lmin\) = 7 A
Therefore, the maximum inductor current is 7 A
c) the output voltage ripple
ΔV₀/V₀ = D/RCf
given that; R = 12.5 Ω, C = 40 μF = 40 × 10⁻⁶ F, D = 0.6, f = 200 Khz = 2 × 10⁵ Hz
we substitute
ΔV₀/V₀ = 0.6 / (12.5 × (40 × 10⁻⁶) × (2 × 10⁵) )
ΔV₀/V₀ = 0.6 / 100
ΔV₀/V₀ = 0.006 or 0.6%V₀
Therefore, the output voltage ripple is 0.006 or 0.6%V₀
d) the average current in the diode under ideal components;
under ideal components; diode current = output current
hence the diode current will be;
\(I_D\) = V₀/R
as V₀ = 50 V and R = 12.5 Ω
we substitute
\(I_D\) = 50 / 12.5
\(I_D\) = 4 A
Therefore, the average current in the diode under ideal components is 4 A
As a technician, you have a work order to set up a WiFi access point for a residential customer. As part of the survey, you need to determine if a laptop will connect to the farthest part of the house. Calculate the received power of the WiFi signal at the garage if the router is located 80 feet away from the garage. The router is a TP-Link Archer AX3000 and it transmits 30dBm in the 2.4 GHz band. The laptop at the other end has a receiver sensitivity of -67 dBm. Consider if the laptop will be able to operate over the WiFi link at the given distance.
Answers
The received power of the WiFi signal at the garage is **-7 dBm**.
To calculate the received power, we need to consider the path loss between the router and the garage. Path loss depends on the distance and the transmission power. Given that the router is transmitting at 30 dBm and the distance is 80 feet, we can use the Friis transmission equation:
Received Power (in dBm) = Transmit Power (in dBm) + 20 * log10(frequency) - 20 * log10(distance) - Path Loss
Assuming the 2.4 GHz band, the calculation becomes:
Received Power (in dBm) = 30 dBm + 20 * log10(2.4 GHz) - 20 * log10(80 feet) - Path Loss
Now, to determine if the laptop can operate over the WiFi link at the given distance, we compare the received power (-7 dBm) with the receiver sensitivity (-67 dBm). Since the received power is higher than the receiver sensitivity, the laptop should be able to connect and operate over the WiFi link at the given distance.
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All of the following are properties of a refrigerant EXCEPT:
A. It has a super low boiling point.
B. It changes its state without breaking down.
C. It vaporizes and condenses at the correct temperature and pressure.
D. Its pressure remains unchanged during the cooling cycle.
Answers
The option that is not a property of refrigerants is;
D: Its pressure remains unchanged during the cooling cycle.
Properties of Refrigerants
A refrigerant is defined as a working fluid that is used in the refrigeration cycle of air conditioning systems and heat pumps.
Now, there are a couple of desirable properties of refrigerants and they are;
They must have low boiling Point.They must have high critical Temperature.They must have high latent heat of vaporization.Low specific heat of liquid.Low specific volume of vapor.Non-corrosive to metal.Non-flammable.Non-explosive.Non-toxicLow costEasy to liquify at moderate pressure and temperatureEasy to locating leaks by odour or suitable indicatorMixes well with oil.Lokking at the given options, the only one that is not a property of a refrigerant is that Its pressure remains unchanged during the cooling cycle.
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For the network of Fig. below, draw the output waveform if Vr = 4.3V , R = 1000Omega and Vi=25 sin ot. Assume an Si diode is used. + R D V_{i}; V_{r}; V_{o}
Answers
Air enters a diffuser operating at steady state at 540°R, 15 lbf/in.2, with a velocity of 600 ft/s, and exits with a velocity of 60 ft/s. The ratio of the exit area to the inlet area is 8. Assume that The air is the ideal gas model for the air and ignoring heat transfer, determine
Answers
Answer: Hello the question is incomplete below is the missing part
Question: determine the temperature, in °R, at the exit
answer:
T2= 569.62°R
Explanation:
T1 = 540°R
V2 = 600 ft/s
V1 = 60 ft/s
h1 = 129.0613 ( value gotten from Ideal gas property-air table )
first step : calculate the value of h2 using the equation below
assuming no work is done ( potential energy is ignored )
h2 = [ h1 + ( V2^2 - V1^2 ) / 2 ] * 1 / 32.2 * 1 / 778
∴ h2 = 136.17 Btu/Ibm
From Table A-17
we will apply interpolation
attached below is the remaining part of the solution
Q1: You have to select an idea developing an application like web/mobile or industrial, it should be based on innovative idea, not just a simple CRUD application. After selecting the idea do the following: 1) How your project will be helpful and what problem this project addresses. (10-Marks) 2) Write down the requirements. (10Marks) 3) List the functional and non-functional requirements of your project. (10marks) 4) Which process model you will follow for this project and why? (10marks) 5) Draw the Level 0, and level 1 DFD of your application. (20marks)
Answers
Answer:
Creating an app is both an expression of our self and a reflection of what we see is missing in the world. We find ourselves digging deep into who we are, what we would enjoy working on, and what needs still need to be fulfilled. Generating an app idea for the first time can be extremely daunting. Especially with an endless amount of possibilities such as building a church app.
The uncertainty has always spawned a certain fear inside creators. The fear of creating something no one will enjoy. Spending hundreds of dollars and hours building something which might not bring back any real tangible results. The fear of losing our investment to a poor concept is daunting but not random. But simple app ideas are actually pretty easy to come by.
Great app idea generation is not a gift given to a selected few, instead, it is a process by which any of us are able to carefully explore step by step methods to find our own solution to any problem. Whether you are a seasoned creator or a novice, we have provided a few recommendations to challenge and aid you as you create your next masterpiece.
if I am right then make me brainliest
why it is essential in thermocouple-extension wire junction to do connect carefully to avoid large errors?
Answers
Yes, in a thermocouple-extension wire junction, it is essential to connect carefully to avoid large errors because any small changes in the connection can lead to significant temperature measurement errors.
The thermocouple generates a small voltage, which is measured by the extension wire, and any disruption or variation in the connection can alter the signal and lead to incorrect readings.
This is particularly important in high-precision temperature measurements, where even small errors can have a significant impact on the results.
Furthermore, the extension wire and thermocouple wires may have different materials and electrical properties, and any poor connections can cause changes in the resistance, which can affect the signal.
Therefore, it is crucial to ensure that the connection is stable and secure, and that the wires are correctly matched and connected with minimum resistance. Any misconnections or poor contacts can lead to measurement errors, which can impact the quality and reliability of the temperature readings.
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Answer the following either true (T) or false (F) (5 pts)
A geotechnical engineer made a preliminary settlement analysis for a foundation of an office building that is to be constructed at a location where the soil strata contain a compressible clay layer. She calculated 50 mm of primary consolidation settlement. The building will impose an average vertical stress of 150 kPa in the clay layer. As often happens in design practice, design changes are required. In this case, the actual thickness of the clay is 30% more than the original soil profile indicated. The estimated new primary consolidation settlement will also be 30% more and equal to 65 mm.
A foundation with an inclined load will tend to have a smaller bearing capacity than the same foundation with a vertical load.
Secondary settlement of a foundation is caused by a constant applied stress.
Consolidation can be defined as the reduction in soil volume due to the expulsion of water following loading.
Dense sand and undrained clay soils tend to experience punching shear failure.
Answers
Answer:
1. True
2. True
3. False
Explanation:
The office location is where the soil layer is not uniform. The thickness of the soil varies which could lead to doors being jammed. The engineer needs to estimate the differential in clay soil.
The inclined surface can hold less weight than a vertical surface. The capacity to hold the weight is due to the gravitational force which is exerted to the load.
Every motor vehicle except for
grade.
must be equipped with a parking brake that can hold a vehicle stationary on any
a) Motorcycles
b) Ambulances
c) Garbage trucks
Answers
Answer:
Motor Cycles
Explanation:
Motor cycles have no parking brake
THE MASS FOR OBJECT 1 is 107.01 grams what is the objects force in Newton’s answer please
Answers
Given that,
Mass of the object 1, m = 107.01 grams
To find,
Force on the object.
Solution,
The force acting on the object is gravitational force. The force is given by the formula as follow :
F = mg
g is acceleration due to gravity
F = 0.10701 kg × 9.8 m/s²
F = 1.048 N
So, the force acting on object 1 is 1.048 N.
What did the US and USSR agree on in the INF Treaty? They agreed to reduce nuclear weapons. They agreed that new European nations would be democratic. They agreed to tear down the Berlin Wall. They agreed that the USSR should break into several countries.
Answers
Answer:
they agreed to reduce nuclear weapons
Answer:
A
Explanation:
Edu 2023
What test should be performed on abrasive wheels
Answers
Answer:
before wheel is put on it should be looked at for damage and a sound or ring test should be done to check for cracks, to test the wheel it should be tapped with a non metallic instrument (I looked it up)
The test that should be performed on abrasive wheels is the ring test.
What is the purpose of the ring test on the abrasive wheels?The ring test can be regarded as one of the mechanical test that is used to know whether the wheel is cracked or damaged.
To carry out this test , the wheel will be arranged to be in the 45 degrees each side and it is then aligned to be at a specific diameter, this can be done by the expert in this field to know the state of that wheel.
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The predator uav has the following characteristics: has the following characteristics: wingspan = 14.85 m, wing area = 11.45 m2, maximum weight = 1020 kgf, and fuel weight = 295 kgf. the power plant is a rotax four-cylinder, four-stroke engine of 85 horsepower driving a two-blade, variable-pitch pusher propeller. assume that the oswald efficiency factor is 0.7, the zero-lift drag coefficient is 0.03, the propeller efficiency is 0.9, and the specific fuel consumption is 0.2 kgf of fuel per horsepower per hour. calculate the following:
1: maximum velocity at sea level.
2: the maximum range
3: the maximum endurance
Answers
The maximum velocity at sea level can be found using the following equation:
V_max = sqrt((2 * W) / (rho * S * CL_max))
where:
W = maximum weight = 1020 kgf
rho = air density at sea level = 1.225 kg/m^3
S = wing area = 11.45 m^2
CL_max = maximum lift coefficient = (2 * W) / (rho * V^2 * S)
To find CL_max, we need to assume a value for the velocity V and iterate until convergence. Let's start by assuming V = 70 m/s:
CL_max = (2 * 1020 kgf) / (1.225 kg/m^3 * (70 m/s)^2 * 11.45 m^2) = 1.87
Now we can use this value to find the maximum velocity:
V_max = sqrt((2 * 1020 kgf) / (1.225 kg/m^3 * 11.45 m^2 * 1.87)) = 35.5 m/s
Therefore, the maximum velocity of the Predator UAV at sea level is approximately 35.5 m/s.
Maximum Range:
The maximum range can be found using the following equation:
R = (L/D) * (1/OE) * ln(Wi/Wf)
where:
L/D = lift-to-drag ratio = CL / CD
CL = lift coefficient = W / (0.5 * rho * V^2 * S)
CD = drag coefficient = CD_0 + (CL^2 / (pi * e * AR))
CD_0 = zero-lift drag coefficient = 0.03
e = Oswald efficiency factor = 0.7
AR = aspect ratio = (wingspan)^2 / S
OE = overall efficiency = propeller efficiency * engine efficiency
propeller efficiency = 0.9
engine efficiency = 0.85 (assuming 85 horsepower for the engine)
Wi = initial weight = maximum weight + fuel weight = 1020 kgf + 295 kgf = 1315 kgf
Wf = final weight = maximum weight
We can start by assuming a value for the velocity V and iterating until convergence. Let's start with V = 25 m/s:
CL = 1315 kgf / (0.5 * 1.225 kg/m^3 * (25 m/s)^2 * 11.45 m^2) = 1.67
AR = (14.85 m)^2 / 11.45 m^2 = 19.3
CD = 0.03 + (1.67^2 / (pi * 0.7 * 19.3)) = 0.071
L/D = 1.67 / 0.071 = 23.5
OE = 0.9 * 0.85 = 0.765
R = 23.5 * (1/0.765) * ln(1315 kgf/1020 kgf) = 393 km
Now we can try a different value for V, let's say V = 30 m/s:
CL = 1315 kgf / (0.5 * 1.225 kg/m^3 * (30 m/s)^2 * 11.45 m^2) = 1.24
AR = (14.85 m)^2 / 11.45
inspections may be_____ or limited to a specific area such as electrical or plumbing
A. Metering
B. General
Answers
1.What is three phase? why it is needed?
2. What is the condition to be balanced? Write down voltage equation of a balanced 3 phase voltage source and draw their phasor diagram.
Answers
1. We can see here that three phase refers to a type of electrical power transmission that uses three alternating current (AC) waveforms that are 120 degrees out of phase with each other. This is different from single-phase power transmission, which uses only one AC waveform.
What is voltage?Voltage, also known as electric potential difference, is a measure of the electrical potential energy per unit of charge in an electrical circuit. It is defined as the amount of work required to move a unit of electric charge between two points in a circuit, typically measured in volts (V).
Three-phase power is needed because it allows for more power to be transmitted over a given amount of wire or cable. With three-phase power, the power is delivered in a more consistent manner, which means that there is less voltage drop over long distances.
2. In order for a three-phase system to be balanced, the three phases must have the same amplitude and be 120 degrees out of phase with each other. The voltage equation of a balanced three-phase voltage source is given by:
Vph = Vline / √3
where Vph is the phase voltage and Vline is the line voltage. The phasor diagram for a balanced three-phase system shows three sinusoidal waveforms that are displaced by 120 degrees from each other.
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There is interdependence between an organization and its information systems". Discuss this statement.
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There is interdependence between an organization and its information systems have a mutual dependency on each other.
What is the organization?An institution made up of individuals or a group of individuals who gather together to accomplish a single, common goal is referred to as an organization.
Information systems and organizations are mutually influenced by one another. Inability to efficiently advantage of innovative technologies, an organization should be receptive to the effects of data systems, which have an impact on how information systems are designed.
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What unit of electricity is used as a signal for a computer?
Answers
Answer:
A power supply unit (PSU) converts mains AC to low-voltage regulated DC power for the internal components of a computer. Modern personal computers universally use switched-mode power supplies
Answer:
Volt is the SI (Standard International) unit of electrical potential of the..
Explanation:
4. Your supervisor texts you during the working hours for no reasons. S/he also invited you for a
dinner to discuss your salary increase issue during a weekend. What should be your role based
on the Ontario's Occupational Health and Safety Act ("OHSA") to deal your supervisor? Discuss.
Answers
If your supervisor is texting you during work hours for no reason, you should speak to him or her about it. If your supervisor is inviting you to dinner to discuss your salary increase issue, you should tell him or her that you are not comfortable with that and would prefer to discuss it during work hours. Your supervisor's behaviour is inappropriate and violates the Ontario's Occupational Health and Safety Act ("OHSA"). You should discuss the issue with your supervisor and try to resolve the issue. If you are not able to resolve the issue, you can file a complaint with the Ontario Ministry of Labour.
Occupational Safety and Health Act:
The Occupational Safety and Health Act of 1970 is a United States labour legislation that governs federal occupational health and safety law in the private sector and federal government. Congress passed it in 1970, and President Richard Nixon signed it on December 29, 1970.
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a dipole of moment p=Qa coul-m is aligned parallel to an electric field along the x axis. The field is non-uniform and varies in magnitude lineary along the x axis with a rate of change dE/dx=K. find the force on the dipole.
Answers
Answer:
F = Qa*K
Explanation:
The force on the dipole is expressed as the negative gradient of the potential energy.
Thus;
Force; F = -dU/dx
Now, the potential energy is given as;
U = -pE
So, dU/dx = -pdE/dx
Since F = -dU/dx
Then, F = p*dE/dx
We are given p = Qa
Then;
F = Qa(dE/dx)
We are given that dE/dx = K
Thus;
F = Qa*K
Americans spent approximately __ cents of each dollar on the purchase of energy?
Answers
Answer:
14 cents
Explanation:
1 trillion US dollar