The total work done by a conservative force, such as those described by Hooke's law or gravitation, is independent of the path taken and depends only on the initial and final positions. This means that the work done by conservative forces is path-independent and has the property of being recoverable as potential energy.
The total work done by a conservative force like Hooke's law or gravitation is zero if the initial and final positions of the object are the same. This is because conservative forces are path-independent, meaning the work done only depends on the endpoints and not the path taken between them. Therefore, any work done in one direction will be exactly cancelled out by work done in the opposite direction.
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What is a neutral atom?
A. An atom containing only neutrons
B. An atom with an equal number of protons and neutrons
C. An atom with an equal number of electrons and neutrons
D. An atom with an equal number of protons and electrons
\( \sf{option \: \: d)}\)
An atom with an equal number of protons and electronsHope It's Helps~
Answer:
A. An atom containing only neutrons
Explanation:
Find the weight (W) of a 60 kg table.
g on earth is
9.8 m/s2
Explanation:
Weight = Fg = mg = (60 kg)*(9.8 m/s2) = 588 N.
find the volume of a cone with diameter 12 m and height 20 m. a. 40 pi m3 c. 240 pi m3 b. 120 pi m3 d. 720 pi m3
The cone has a 240π m³ capacity.
Describe Volume .
Volume in mathematics refers to how much three-dimensional space an object or closed surface takes up. The volume is expressed in cubic units such as m3, cm3, in3, etc. It is how much space a thing or material occupies.
Volume and capacity are two more names for the same thing.
Cone diameter is 12 meters, given.
radius = diameter/2 = 12/2 = 6 meters.
Cone height is 20 meters.
Cone volume is calculated using 1/3πr2h.
where h = height and r = radius
volume equals 1/3 x π (6)2 x 20.
volume equals 240 m³
As a result, the volume is 240 m³
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An engineer is investigating potential energy with two
identical magnetic roller coaster cars on different sides of a
center magnet that cannot move. To test her ideas, the
engineer will move one car one space. Which movement will
result in the largest increase in potential energy?
A.
Moving Car 1 one space toward the center magnet.
B.
Moving Car 2 one space toward the center magnet.
C.
Moving Car 2 one space away from the center magnet.
D.
All these movements will result in the same change in potential energy
because they each move a roller coaster car the same distance.
Answer:
Since they move in the same direction, share the same magnetic qualities, and move one unit identically We can safely say its Dwhat range of field strengths would be required to scan the mass range between 16 and 300, for singly charged ions, if the accelerating voltage is held constant?
The magnetic field strength required to scan the mass range between 16 and 300 for singly charged ions is 0.0398 T.
The magnetic field strength required to focus the ion at a particular mass-to-charge ratio is given by the equation:
B = (V × r) ÷ (B² × 2 × (mB ÷ q))
where V is the accelerating voltage, r is the radius of the magnetic sector, B is the magnetic field strength, m is the mass of the ion, and q is its charge.
Since we are dealing with singly charged ions, q = 1. We know the values of V₁ and B₁ for CH⁴⁺ ions. Therefore, we can use the above equation to find the radius r of the magnetic sector:
r = (V₁ × m) / (B₁² × 2 × q)
We can now use this value of r and the above equation to find the magnetic field strength B₂ required to scan the mass range between 16 and 300:
B₂ = The atomic mass of CH₄ is 16 u.
The ions with mass-to-charge ratio of 16 and 300 have masses of 16 u/q and 300 u/q, respectively.
For singly charged ions, we have
m ÷ q = mass ÷ charge = mass.
B₂ = √((V₁ × 16 u) ÷ (2 × r)) ÷ 1.00 + √((V₁ × 300 u) ÷ (2 × r)) ÷ 1.00
√((V₁ × m) ÷ (2 × q × r))
V₁ = 3.00 x 10³ V, B₁ = 0.126 T
Using the above equations, we can calculate the value of r:
r = (V₁ × m) / (B₁² × 2 × q)
= (3.00 x 10³ V × 16 u) / (0.126 T)² × 2 × 1
= 3.08 x 10⁻³ m
Substituting the values of r and V₁ in the equation for B:
B₂ = √((V₁ × 16 u) ÷ (2 × r)) ÷ 1.00 + √((V₁ × 300 u) ÷ (2 × r)) ÷ 1.00
B₂ = √((3.00 x 10³ V × 16 u) ÷ (2 × 3.08 x 10⁻³ m)) ÷ 1.00 + √((3.00 x 10³ V × 300 u) / (2 × 3.08 x 10⁻³ m)) ÷ 1.00
B₂ = 0.0398 T
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The complete question is:
When a magnetic sector mass spectrometer was operated with an initial accelerating voltage (V1) of 3.00 x 103 V, a magnetic field (B1) of 0.126 T was required to focus the CH4 + ion on the detector.
What magnetic field strength would be required to scan the mass range between 16 and 250 for singly charged ions if the accelerating voltage is held constant?
The influence of the moon on the tides on earth is greater than that of the sun. Which best explains this?.
More so than the Sun, the Moon is closest to Earth. The moon is closer to the earth than the sun, which results in a larger gravitational gradient for the moon even though the sun is considerably more massive and has stronger overall gravity than the moon.
The sun is 390 times further from Earth than the moon despite having a mass that is 27 million times greater. The inverse cube of the distance to the tide-producing item describes how tidal generating forces change. When the sun, moon, and Earth are lined up (during a new or full moon), the solar tide adds to the lunar tide, resulting in exceptionally high high tides and extremely low low tides, both of which are known as springtides.
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Completion Status: A Click Submit to complete this assessment. estion 4 A 12 in diameter rod is subjected to an axial tensile load of 60 kips. Compute. a. The normal stress developed on an inclined plane at an angle of 25 with the cross section of the rod. b. The maximum normal stress developed in the rod.
The normal stress on an inclined plane at 25 degrees can be calculated using σ = F / A * cos²θ, while the maximum normal stress is σ_max = F / A_max.
a. To calculate the normal stress developed on an inclined plane, we use the formula: σ = F / A * cos²θ. Given that the diameter of the rod is 12 inches, the radius (r) is half of the diameter, which is 6 inches or 0.5 feet. The cross-sectional area of the rod (A) can be calculated using the formula for the area of a circle: A = π * r². Substituting the values, we get A = π * (0.5)^2 = π * 0.25 = 0.7854 square feet.
Now, we can calculate the normal stress using the given axial tensile load (F) of 60 kips and the angle (θ) of 25 degrees. Since the load is given in kips (1 kip = 1000 pounds), we convert it to pounds by multiplying by 1000: F = 60 * 1000 = 60000 pounds.
Using the formula σ = F / A * cos²θ, we substitute the values and calculate the normal stress:
σ = 60000 / 0.7854 * cos²25 ≈ 95317.91 psi (pounds per square inch).
b. The maximum normal stress in the rod occurs when the inclined plane is aligned with the maximum cross-sectional area. In this case, the maximum cross-sectional area (A_max) is the same as the cross-sectional area of a circle, which is π * r². Substituting the radius value, we get A_max = π * (0.5)^2 = π * 0.25 = 0.7854 square feet.
To calculate the maximum normal stress (σ_max), we use the formula σ_max = F / A_max. Substituting the given axial tensile load (F) of 60 kips and the maximum cross-sectional area (A_max), we calculate the maximum normal stress:
σ_max = 60000 / 0.7854 ≈ 76448.44 psi (pounds per square inch).
Therefore, the normal stress developed on an inclined plane at an angle of 25 degrees with the cross section of the rod is approximately 95317.91 psi, and the maximum normal stress developed in the rod is approximately 76448.44 psi.
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A wooden beam is 6.50 m long and weighs 325 N. It rests on two supports that are 3.00 m apart. Jane weighs 575 N. She stands on the beam in the center and then walks toward one end. How close to the end can she come before the beam begins to tip?
Suki can go 0.854 meters to the end before the beam starts to tilt.
Beam length: L = 6.5 m
Beam weight: W b = 336 N
Suki's weight is W s = 590 N.
Suki stands in the middle of the steel beam and moves toward the end. Since the beam is supported by two posts that are spaced three meters apart, the distance she may go before the beam starts to lean is determined by how far she moves from the left support.
Thus;
according to formula
Wb × (3/2) = (Ws × x)
where:
Wb= Beam weight
Ws= Suki's weight
Adding the necessary values results in;
336 × 1.5 = 590 × x
x = (336 × 1.5)/590
x = 0.854 m
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60 kg acceleration due to gravity in the moon
Therefore, a 60kg object would weigh approximately 96 Newtons on the moon.
Weight calculation .The acceleration due gravity on the moon is a measure of how much objects accelerate toward the moon's surface under the influence of its gravitational force. It is denoted by the symbol g and gas a value of approximately 1.6m/s²
To calculate the weight of a 60kg object on the moon, you can use the formula:
Weight = mass × acceleration due to gravity
Weight = 60kg × 1.6m/s²
Weight on the moon = 96N
Therefore, a 60kg object would weigh approximately 96 Newtons on the moon.
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why is it more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity?
It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity because of static friction.
Static friction refers to the resistance encountered when attempting to initiate the movement of two objects that are in contact with each other but not currently in motion relative to each other. When an object is at rest, the force of static friction acts in the opposite direction to any force applied to it.
In this case, the force applied to the carton is the force needed to start moving it from rest. The force of static friction is greater than the force applied to the carton, making it difficult to start moving the carton from rest.
Once the carton is moving with constant velocity, the force of static friction is no longer acting on it. The only force acting on the carton is the force that is applied to keep it moving at a constant velocity. This force is equal to the force of kinetic friction which is less than the force of static friction.
To summarize, the initial effort required to overcome the static friction between a heavy carton and its resting position is greater compared to the continuous force needed to maintain its constant velocity. The force of static friction is greater than the force applied to the carton, making it difficult to start moving the carton from rest.
Once the carton is moving with constant velocity, the force of static friction is no longer acting on it, and the only force acting on the carton is the force that is applied to keep it moving at a constant velocity.
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Monochromatic light of wavelength lambda, such as light from a laser, is directed through two narrow parallel slits that are a distance d apart. There is a viewing screen a very long distance R away from the slits that is used to observe the interference pattern that emerges from the light shining through the slits. The distance that light travels from one slit to the screen is r1 and the distance that light travels from the other slit to the screen is r2. The central bright fringe of the interference pattern results due to a path difference, r1 – r2, of zero. What path difference is required to produce the first order bright fringe that is adjacent to the central bright fringe?
Answer:
When r1 – r2 equal the wavelength of the monochromatic light
Explanation:
This is because to observe a bright fringe a constructive interference pattern of path difference, r1 – r2 = mλ is observed, where m is an integer and λ = wavelength of monochromatic light.
For bright fringes and thus constructive interference, r1 – r2 must be integral multiples of the wavelength, λ. When r1 – r2 , we have the central bright fringe and thus m = 0.
The first order bright fringe which is adjacent to the central bright fringe is obtained when m = 1,
So r1 – r2 = 1 × λ
r1 – r2 = λ
Thus, the path difference required to produce the first order bright fringe that is adjacent to the central bright fringe is when r1 – r2 = λ, the wavelength of the monochromatic light.
What is the ratio of the density of a material to the density of water?
The ratio of density of a material to the density of water is known as relative density or specific gravity.
According to water at 4 °C, specific gravity often refers to relative density.
A substance's specific gravity is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature. The ratio of the densities of the two materials is also this.
This physical quantity does not possess units as it is a ratio of two similar physical quantities.
The relative density of water is said to be 1, ice is 0.92, sea water is 1.03.
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If you have 100 kg of each of these substances, which would require the most energy to increase its temperature by 25 Kelvin?
A. iron
B. carbon
C. rubber
D. air
Answer:
a
Explanation:
Answer:
A Iron
Explanation:
Hope this helps :D
what is a universal law?
Answer:
Universal law is the set of natural, non-man-made, and immutable conditions that determine how reality and consequence operate within the realm that humans exist in.
Explanation:
a dart of mass md is launched straight upward toward a block of mass mb that hangs at rest from a string, as shown in figure 1. immediately before the dart collides with the block, the dart has a speed v0 . the dart then collides with and sticks to the block, and the dart-block system travels upward to a height h before the system comes to rest, as shown in figure 2. what is the change in momentum of the dart-block system immediately before the collision to the instant when the system comes to rest?
The system comes to rest at height h, its final momentum is 0.
To find the change in momentum of the dart-block system, we need to compare the momentum immediately before the collision to the momentum when the system comes to rest. Let's follow these steps:
1. Calculate the initial momentum of the dart and block before the collision:
Since the block is at rest, its initial momentum is 0. The initial momentum of the dart is given by the product of its mass (md) and velocity (v0). So, initial momentum of the system is md*v0.
2. Determine the combined mass of the dart and block after the collision:
Since the dart sticks to the block, their combined mass is (md + mb).
3. Calculate the final velocity of the dart-block system just after the collision:
Using conservation of momentum, we can write the equation: (md * v0) = (md + mb) * vf, where vf is the final velocity of the system. Solve for vf: vf = (md * v0) / (md + mb).
4. Calculate the change in potential energy when the system rises to a height h:
The change in potential energy is given by ΔPE = (md + mb) * g * h, where g is the acceleration due to gravity.
5. Determine the initial kinetic energy just after the collision:
The initial kinetic energy (KE) is given by (1/2) * (md + mb) * vf^2.
6. Using conservation of energy, set the initial kinetic energy equal to the change in potential energy:
(1/2) * (md + mb) * vf^2 = (md + mb) * g * h.
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A scientist is studying the effects of sunlight on rose bushes. Which of the
following is a testable question about this topic?
Answer:
Does more sunlight make rose bushes grow taller?
Explanation:
When conducting a research, the researcher usually poses research questions in order to confirm or disprove the research hypothesis. A research question addresses the key issues and questions that the research project is intended to answer. Good research questions always aim at improving the body of knowledge on the selected topic of the research. Research questions must be narrowed down to specific details of the topic. They must also be testable, they must not be vague.
If I am studying the effect of sunlight on rose bushes, then the question, 'does more sunlight make rose bushes grow taller?' Is apt to the research because it can be tested by exposing various thorn bush plants to varying degrees of sunlight and recording my observation.
Answer:
If rose bushes receive more hours of sunlight each day, they will grow taller.
Explanation:
I just answered it on Apex, and they like to switch up how they word things sometimes.
How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it during condensation in the atmosphere Water gains energy during evaporation and condensation in the lithosphere. Water gains energy in condensation and releases it in evaporation. Water releases energy during evaporation and condensation.
Answer:
Water gains energy during evaporation and releases it during condensation in the atmosphere
Explanation:
In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.
In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.
In condensation, the molecules of gaseous water looses energy and becomes liquid.
Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.
Answer:
K12 HE HE
Explanation:
a spring has a natural length of 12.0 cm. if a 26.0-n force is required to keep it stretched to a length of 26.0 cm, how much work w is required to stretch it from 12.0 cm to 19.0 cm? (round your answer to three decimal places.)
The work required to stretch the spring from 12 cm to 19 cm is 0.91 J
What is work done ?When an object is moved across a specific distance by an external force, work is the quantity of energy that is transmitted to the object.
According to the given information
Natural length = 12 cm
Stretched length = 26 cm
Change in length ( x ) = 26 - 12 = 14 cm = 0.14 m
Force required = 26 N
It is known to us that spring force F = K x
K = \(\frac{F}{x}\)
K = \(\frac{26}{0.14}\)
K = 185.7 N/m
This is the stiffness of the spring
Now the Force that is required to stretch the spring F = K\(x_{1}\)
\(x_{1}\) = change in length of the spring = 19 - 12 = 7 cm = 0.07 m
F = 185.7 × 0.07
F = 13 N
Now the work that is done in stretching the spring W = F × \(x_{1}\)
W = 13 × 0.07
W = 0.91 J
The work required to stretch the spring from 12 cm to 19 cm is 0.91 J
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calculate the magnitude of 1. B+Q 2. B-Q where B is=3i+4j Q is=5i-2j+1k
Answer: The magnitude of B+Q is √69 and the magnitude of B-Q is √41.
Explanation:
Let's calculate the magnitude of B+Q and B-Q.
First, we'll start with B+Q. We know that B is equal to 3i + 4j and Q is equal to 5i - 2j + 1k. So, to find B+Q, we simply add the corresponding components of B and Q:
(3i + 4j) + (5i - 2j + 1k) = 8i + 2j + 1k
To find the magnitude of B+Q, we use the Pythagorean theorem, just like we would in finding the distance between two points in a plane. But since we have three dimensions (i, j, and k), we have to square the values of 8i, 2j, and 1k and add them up, and then take the square root of the result.
The magnitude of B+Q is √(8^2+2^2+1^2) = √(64+4+1) = √69
Now, let's move on to B-Q. We know that B is equal to 3i + 4j and Q is equal to 5i - 2j + 1k. So, to find B-Q, we subtract the corresponding components of Q from B:
(3i + 4j) - (5i - 2j + 1k) = -2i + 6j - 1k
To find the magnitude of B-Q, we again use the Pythagorean theorem, just like we would in finding the distance between two points in a plane. But since we have three dimensions (i, j, and k), we have to square the values of -2i, 6j, and -1k and add them up, and then take the square root of the result.
The magnitude of B-Q is √((-2)^2+6^2+(-1)^2) = √(4+36+1) = √41
And there you have it! The magnitude of B+Q is √69 and the magnitude of B-Q is √41.
Note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. a 0.4-m3 rigid tank contains refrigerant-134a initially at 160 kpa and 40 percent quality. heat is now transferred to the refrigerant until the pressure reaches 600 kpa. note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. determine the amount of heat transferred. (please provide an answer before moving on to the next part.)
Based on the calculations, the amount of heat transferred is equal to 2,317 kJ.
Given the following data:
Volume of tank = 0.4 m³.
Initial pressure = 160 kPa.
Final pressure = 600 kPa.
Initial quality, x = 40% = 0.4
How to calculate the amount of heat transferred?From the superheat table A-12, the specific volumes of the saturated liquid and vapor at 160 kPa are:
Vf(160 kPa) = 0.0007437 m³/kg. Vg(160 kPa) = 0.12348 m³/kg.Next, we would determine the initial specific volume by using this formula:
V₁ = (1 - x)Vf + xVg
V₁ = (1 - 0.4)0.0007437 + (0.4)0.12348
V₁ = 0.049838 m³/kg.
Also, we would find the mass of this refrigerant at the initial state by using this equation:
m = V/V₁
m = 0.4/0.049838
Mass, m = 8.03 kg.
From the superheat table A-12, the internal energy of the saturated liquid and vapor at 160 kPa are:
Uf(160 kPa) = 31.09 kJ/kg. Ug(160 kPa) = 221.35 kJ/kg.At the initial state, we would find U₁ from the quality:
U₁ = (1 - x)Uf + xUg
U₁ = (1 - 0.4)31.09 + (0.4)221.35
U₁ = 107.19 kJ/kg.
From the superheat table A-13, the final specific volume and internal energy of the saturated liquid and vapor at 600 kPa are:
Vf = 0.057006 m³/kg.Uf = 367.81 kJ/kg.At the final state, we would find U₂ by extrapolating with the last two points in the table:
\(U_2 = 357.96 + (\frac{367.81 \; - \; 357.96}{0.057006\;-\;0.055522}) \times (0.049838\;-\;0.055522)\\\\U_2 = 357.96 + (\frac{9.85}{0.001484}) \times (-0.005684)\\\\U_2 = 357.96 + 37.73\\\\\)
U₂ = 395.69 kJ/kg.
Now, we can calculate the amount of heat transferred:
Q = m(U₂ - U₁)
Q = 8.03(395.69 - 107.19)
Q = 8.03(288.5)
Q = 2,316.66 ≈ 2,317 kJ.
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You wish to date a hip bone fragment you found at a cave site.
You find a ratio of 1 14C atoms for every 31 14N atoms. How many
half- lives have elapsed?
To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.
The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.
In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.
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the force of ________ moves sodium ions ________ the axon
The force of electrostatic attraction moves sodium ions into the axon.
In a neuron, the movement of ions plays a crucial role in generating electrical signals. Sodium ions (Na+) have a positive charge, while the inside of the axon has a negative charge. Due to this electrostatic attraction between opposite charges, sodium ions are pulled into the axon. This force is essential for the process of depolarization during the propagation of an action potential.
When an action potential is initiated, channels in the cell membrane open, allowing sodium ions to flow into the axon. This influx of sodium ions further depolarizes the axon and triggers the propagation of the electrical signal. The force of electrostatic attraction ensures that sodium ions move in the direction required for the proper functioning of nerve impulses.
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What happens if we remove heat from water at 0°C? Does the temperature change? Explain. (Select all that apply.)
a. The temperature of the water remains constant.
b. The temperature of the water will decrease.
c. The water will undergo sublimation.
d. The water freezes.
Which of the answers below are examples of moderate activities?
A- walking slowly, floating in a pool, bicycling 2-3 mph
B- playing video games, sleeping, watching TV
C- bicycling 5-9 mph, walking briskly, recreational swimming
Exercises that register between 3 and 6 METs are considered moderate- intensity activities because they get you moving quickly enough or vigorously enough to burn off three to six times as much energy per minute as you do while you're sitting still.
What purpose do moderate activities serve?Chronic Heart Disease
Your chance of developing these diseases can be decreased by engaging in at least 150 minutes of moderate physical activity each week. By engaging in additional exercise, you can further lower your risk. Additionally, regular exercise helps lower blood pressure and lower cholesterol.
Which courses are moderately paced?Your heart rate will rise while you engage in moderate aerobic activity, and you'll also feel warmer and breathe more quickly than usual.
This may entail taking a quick stroll.
leisurely cycling or cycling on flat land.mild swimmingAquatic exercise.tennis doubles. volleyball.What would you say is moderate intensity exercise?A quick method to gauge relative intensity is the conversation test. In general, you can converse but not sing while engaging in moderate-intensity exercise. In general, you won't be able to speak for more than a few words without pausing to take a breath if you're engaging in vigorous-intensity activities.
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The potential energy for a mass on a spring is proportional to the square of which of these quantities?
OA.mass
OB.frequency
OC.period
OD.displacement
O E. velocity
A hippo's body is 4.0 m long with front and rear feet located as in (Figure 1). The hippo carries 80% of its weight on its front foot. Part A How far from its tail is the hippo's center of gravity?
The hippo's center of gravity is located 3.2 meters from its tail.
To determine the distance of the hippo's center of gravity from its tail, we need to consider the weight distribution between its front and rear feet. Given that the hippo carries 80% of its weight on its front foot, we can assume that 80% of the hippo's total weight acts at the front. Let's denote the distance from the tail to the center of gravity as "x."
Since the rear foot is located at the tail, the remaining 20% of the weight acts at the rear foot. Using the principle of moments, we can set up the equation: (80% of the weight) * (distance from front foot to center of gravity) = (20% of the weight) * (distance from rear foot to center of gravity). Plugging in the given values, we have (0.8) * (4.0 - x) = (0.2) * x. Solving this equation, we find x = 3.2 meters. Therefore, the hippo's center of gravity is located 3.2 meters from its tail.
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The current through a 12 Ω resistor in an electric circuit is 1.5 A. Calculate the potential difference across the resistor.
Hello!
We can use Ohm's Law to solve for the potential difference across a resistor given the current and resistance:
\(V = iR\)
V = Potential Difference (? V)
i = Current (1.5 A)
R = Resistance (12 Ω)
Plug in the known values and solve.
\(V = (1.5)(12) = \boxed{18 V}\)
How many grams of aluminum sulfate must be dissolved in 650. mL of water to make 84.0% (m/v) aluminum sulfate solution?
3415.2 grams
Explanation
to solve this we can use a rule of three
Step 1
Let
water= 100-84%= 16%
so,
\(\text{ 16 \%=650 mL}\)for the water , 1 mL = 1 gram , so
\(\text{ 16\% =650 grams}\)now, let represents the mass of the aluminiu, so
\(\text{ 84 \%= x}\)a) the ratio is the same, so we have a proportion
\(\frac{16}{650}=\frac{84}{x}\)Step 2
finally, solve for x
\(\begin{gathered} \frac{16}{650}=\frac{84}{x} \\ \text{cross multiply } \\ 16\cdot x=84\cdot650 \\ 16x=54600 \\ \text{divide both sides by 16} \\ \frac{16x}{16}=\frac{54600}{16} \\ x=3412.5 \end{gathered}\)so, the mass of the aluminum is
3415.2 grams
What is 38.5 celsius to Fahrenheit?
Answer: (38.5°C × 9/5) 32 = 101.3°F
Explanation:
A block starting from rest slides down the length of an 18 m plank with a uniform acceleration of 4. 0 m/s2. How long does the block take to reach the bottom?.
Starting at rest, a block accelerates at 4.0 meters per second square and slides down an 18-meter plank. The block needs three seconds to get to the bottom.
What is acceleration?
Acceleration is the term used to describe how quickly an object changes its velocity. A vector quantity is an acceleration. An object is said to be accelerating if its velocity is changing; an item with a steady velocity is not accelerating.
The velocity of a moving object refers to how quickly it is moving in that direction. Consider the speed of a car driving north on a highway or the speed at which a rocket takes off as an example.
Given that in the question block slides down an 18 m plank length with an acceleration of 4.0 meters per second square when it begins at rest.
Using the equation of motion,
S = ut + (1/2)at²
s is distance, s = 18 m
u is initial velocity, u = 0
a is acceleration, a = 4 m/sec²
t is time
18 = 0*t + (1/2)*4*t
solving we get t = 3 sec.
Hence, the time taken by the block to reach the bottom is 3 sec.
To learn more about acceleration the link is given below:
https://brainly.com/question/14704010?
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